← Session 14 — Phase 5 kickoff: paper draft + honesty audit
thinking (1300 chars)
`ContDiff.deriv' (h : ContDiff 𝕜 (n + 1) f) : ContDiff 𝕜 n (deriv f)`. So for ContDiff ℝ 2 φ with 2 = 1+1: hφ.deriv' : ContDiff ℝ 1 (deriv φ), then `.differentiable le_rfl`... ContDiff.differentiable needs (1 ≤ n): ContDiff ℝ 1 (deriv φ) → .differentiable le_rfl gives Differentiable ℝ (deriv φ) ✓.
Fixes:
- hφ2 := (hφ.deriv' (n := 1)).differentiable le_rfl — need 2 = 1 + 1 syntactically? ContDiff ℝ 2 φ with 2 : ℕ∞... The statement hφ : ContDiff ℝ 2 φ — here 2 : WithTop ℕ (ContDiff order). deriv' expects ContDiff 𝕜 (n+1) f. Need to show ContDiff ℝ ((1:WithTop ℕ)+1) φ from ContDiff ℝ 2 φ — defeq of (1:ℕ∞)+1 = 2? Might need `show` or norm_num conversion. Try: `(ContDiff.deriv' (n := 1) (by simpa using hφ))`? Or simply hφ.deriv' might unify 2 with ↑1 + 1 via norm_num1... uncertain. Alternative more robust: use `hφ.differentiable_iteratedDeriv`? Or avoid: get DifferentiableAt (deriv φ) via `ContDiffAt`... Let me just try `(hφ.deriv' ).differentiable (by norm_num)` variants in the compile loop.
- Add `open Topology` for 𝓝.
Also `ContDiff.differentiable (by norm_num)` for hφ1 worked? The error list only flagged line 19 (hφ.deriv) — wait no, 19:8 was flagged with Exists.deriv — that IS the hφ.deriv' line... Line 19 in file = `have hφ2...`? Whatever — fix both.
Update the scratch file.
`ContDiff.deriv'` it is. Fixing both errors.
tool: Edit
input
{
"file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\Scratch.lean",
"old_string": "open Real Filter",
"new_string": "open Real Filter Topology"
}
tool: Edit
input
{
"file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\Scratch.lean",
"old_string": " have h\u03c62 : Differentiable \u211d (deriv \u03c6) :=\n (h\u03c6.deriv (by norm_num : (1 : \u2115\u221e) + 1 \u2264 2)).differentiable le_rfl",
"new_string": " have h\u03c62 : Differentiable \u211d (deriv \u03c6) :=\n (h\u03c6.deriv' (n := 1)).differentiable le_rfl"
}
raw content_json (database row)
[{"type":"thinking","thinking":"`ContDiff.deriv' (h : ContDiff 𝕜 (n + 1) f) : ContDiff 𝕜 n (deriv f)`. So for ContDiff ℝ 2 φ with 2 = 1+1: hφ.deriv' : ContDiff ℝ 1 (deriv φ), then `.differentiable le_rfl`... ContDiff.differentiable needs (1 ≤ n): ContDiff ℝ 1 (deriv φ) → .differentiable le_rfl gives Differentiable ℝ (deriv φ) ✓.\n\nFixes:\n- hφ2 := (hφ.deriv' (n := 1)).differentiable le_rfl — need 2 = 1 + 1 syntactically? ContDiff ℝ 2 φ with 2 : ℕ∞... The statement hφ : ContDiff ℝ 2 φ — here 2 : WithTop ℕ (ContDiff order). deriv' expects ContDiff 𝕜 (n+1) f. Need to show ContDiff ℝ ((1:WithTop ℕ)+1) φ from ContDiff ℝ 2 φ — defeq of (1:ℕ∞)+1 = 2? Might need `show` or norm_num conversion. Try: `(ContDiff.deriv' (n := 1) (by simpa using hφ))`? Or simply hφ.deriv' might unify 2 with ↑1 + 1 via norm_num1... uncertain. Alternative more robust: use `hφ.differentiable_iteratedDeriv`? Or avoid: get DifferentiableAt (deriv φ) via `ContDiffAt`... Let me just try `(hφ.deriv' ).differentiable (by norm_num)` variants in the compile loop.\n\n- Add `open Topology` for 𝓝.\n\nAlso `ContDiff.differentiable (by norm_num)` for hφ1 worked? The error list only flagged line 19 (hφ.deriv) — wait no, 19:8 was flagged with Exists.deriv — that IS the hφ.deriv' line... Line 19 in file = `have hφ2...`? Whatever — fix both.\n\nUpdate the scratch file.","signature":""},{"type":"text","text":"`ContDiff.deriv'` it is. Fixing both errors."},{"type":"tool_use","id":"Edit_166","name":"Edit","input":{"file_path":"D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\Scratch.lean","old_string":"open Real Filter","new_string":"open Real Filter Topology"},"extra_content":null},{"type":"tool_use","id":"Edit_167","name":"Edit","input":{"file_path":"D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\Scratch.lean","old_string":" have hφ2 : Differentiable ℝ (deriv φ) :=\n (hφ.deriv (by norm_num : (1 : ℕ∞) + 1 ≤ 2)).differentiable le_rfl","new_string":" have hφ2 : Differentiable ℝ (deriv φ) :=\n (hφ.deriv' (n := 1)).differentiable le_rfl"},"extra_content":null}]