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← Session 17 — Lean tier (i): elementary proofs (after crash)

#668 assistant 2026-08-20 06:09:50.925 UTC · 1020→3390 tok open ⤢
thinking (7887 chars)
Now I see the a✝: goal IS in the right form: `4.56 * ((s+1)(b²(eA+eB)) + (s+1)(b(eA+eB)/s)) < 4.56 * ((s+1)(a²eA+b²eB) + (s+1)((aeA+beB)/s))` — and m1+m2 SHOULD contradict... m1 : (s+1)(a²eA+b²eB) ≤ (s+1)(b²(eA+eB)); m2 : (s+1)((aeA+beB)/s) ≤ (s+1)(b(eA+eB)/s). Sum: RHS ≤ LHS-components... a✝ says L' < R' where R' = m1's LHS-sum + m2's LHS-sum and L' = the two RHS-sums: m1+m2 give R' ≤ L' → contradiction with L' < R'?? wait: a✝ : [b-side] < [a-side]; m1: a-side-part1 ≤ b-side-part1; m2: a-side-part2 ≤ b-side-part2 → a-side ≤ b-side — contradicts a✝ (b-side < a-side) ✓ linarith SHOULD find this. The monomials: (s+1)*(a²eA+b²eB) — ring_nf: (s+1)a²eA + (s+1)a²eB... and in m1: same ✓. Why fail?? The a✝ has `4.56 * (X + Y)` where X = (s+1)*(b²*(eA+eB)) — m1's RHS is (s+1)*(b²*(eA+eB)) — SAME ✓... Hmm — is it possible linarith's ring_nf normalization chokes on `4.56` (a decimal literal = OfNat.ofNat with floating rational)? 4.56 is a rational literal — ring handles ✓. OR — the `set` variables! eA, eB are `set` variables (let-bound) — linarith/ring treat them fine as atoms... Wait — actually let me look VERY carefully at a✝: `4.56 * ((s + 1) * (b ^ 2 * (eA + eB)) + (s + 1) * (b * (eA + eB) / s)) < 4.56 * ((s + 1) * (a ^ 2 * eA + b ^ 2 * eB) + (s + 1) * (a * eA + b * eB) / s)`. m2's LHS: `(s + 1) * ((a * eA + b * eB) / s)`; a✝'s corresponding: `(s + 1) * (a * eA + b * eB) / s` — PARSING DIFFERENCE! `(s + 1) * (a * eA + b * eB) / s` parses as `((s+1)*(aeA+beB))/s` — division applied to the WHOLE product, while m2 has `(s+1) * ((aeA+beB)/s)`. These are equal by ring (mul_div_assoc) but DIFFERENT atoms for linarith's ring_nf?? ring_nf normalizes both to... ((s+1)(aeA+beB))·s⁻¹ — same ✓ should normalize identically. I'm stuck on why linarith fails — maybe it IS the set-variables: `set` replaces eA with a local definition — ring_nf might unfold?? no... Alternative: skip linarith, use direct term: exact add_le_add m1 m2 |>.trans_eq'?? hmm: goal: 4.56*(A1+A2) ≤ 4.56*(B1+B2) — via mul_le_mul_of_nonneg_left (add_le_add m1 m2) (by norm_num : (0:ℝ) ≤ 4.56) : 4.56 * ((s+1)X + (s+1)Y) ≤ 4.56 * ((s+1)X' + (s+1)Y') ✓ EXACTLY the goal shape (a✝ confirms the goal is 4.56*(sum) ≤ 4.56*(sum))! So: exact mul_le_mul_of_nonneg_left (add_le_add m1 m2) (by norm_num) The add_le_add m1 m2 : (s+1)X + (s+1)Y ≤ (s+1)X' + (s+1)Y' where the sums match the goal's inner sums ✓ syntactically? goal inner LHS: (s + 1) * (a ^ 2 * eA + b ^ 2 * eB) + (s + 1) * (a * eA + b * eB) / s — note the `/s` binds to the whole second product! add_le_add m1 m2's LHS: (s+1)X + (s+1)Y with Y = ((aeA+beB)/s) — the goal's second summand is ((s+1)(aeA+beB))/s ≠ (s+1)((aeA+beB)/s) syntactically!! THAT's the mismatch — and linarith's ring_nf apparently did NOT unify them (surprising but fine). Fix m2's statement to ((s+1)*(aeA+beB))/s form: m2 : (s + 1) * (a * eA + b * eB) / s ≤ (s + 1) * (b * (eA + eB)) / s — from h2 by mul_le_mul_of_nonneg_left then massage: (s+1)*(X/s) = ((s+1)*X)/s: mul_div_assoc ✓: (s+1)*(b*(eA+eB)/s) = ((s+1)*(b*(eA+eB)))/s by (mul_div_assoc).symm. So: have m2 : (s + 1) * (a * eA + b * eB) / s ≤ (s + 1) * (b * (eA + eB)) / s := by have h3 := mul_le_mul_of_nonneg_left h2 (show (0:ℝ) ≤ s + 1 by linarith) rwa [mul_div_assoc, mul_div_assoc] at h3 Then exact mul_le_mul_of_nonneg_left (add_le_add m1 m2) (by norm_num : (0:ℝ) ≤ 4.56). Also fix e3's RHS form to match: e3 : 4.56 * (s + 1) * (b ^ 2 + b / s) * (eA + eB) = 4.56 * ((s + 1) * (b ^ 2 * (eA + eB)) + (s + 1) * (b * (eA + eB)) / s) — second summand with /s outside ✓ field_simp;ring... field_simp closed it before (remove ring). Other errors: - 1193: simp no progress — hu2der's `simp only [Pi.mul_apply] at h` — made no progress (h's function has no Pi.mul applications?? hp.mul he's output: maybe it IS pointwise already: `fun x => f x * g x`?? HasDerivAt.mul : HasDerivAt (fun y => f y * g y)?? Let me check: earlier in psiTilde work, Pi.add_apply WAS needed (hva.add hvb showed Pi.add form). For .mul — hp.mul he: conclusion HasDerivAt (fun x => f x * g x)? or (f * g)? From the earlier error print in psiOf_log_sq_shift: `fun y => 2 * ((fun t => ...) * fun t => ...) y` — that was const_mul of a MUL — the mul there produced Pi.mul ((f) * (g)) y. So .mul DOES produce Pi.mul. But here simp says no progress — maybe because I already have h in the right form... If simp made no progress it's an ERROR regardless. Remove the simp; but then exact h needs the function match — try `exact h` alone; if mismatch, convert. Actually — difference: here hp = ((hasDerivAt_id' x).const_mul (b²)).add_const b — the OUTER op is .add_const (value-add), then hp.mul he: Pi.mul of (fun t => b²*t+b) and (fun t => exp(−a*t)): h's function: fun y => ((fun t => b²*t+b) * (fun t => exp(−a*t))) y — Pi.mul_apply should rewrite... "no progress" means no (f * g) y pattern — maybe the elaborator already beta/iota-reduced? The goal u2: set var — the exact h will need u2 ≡ h's function — set-local-def defeq ✓. Just do rw [e] at h; exact h and see. - 1203: my ContDiff.differentiable application got mangled — `ContDiff.differentiable (hn : n ≠ 0)`: I wrote `.differentiable (by norm_num).differentiableOn.mono interior_subset` — parsed as differentiable applied to (by norm_num) AND interior_subset?? The error shows ContDiff.differentiable ... ?m.3922 interior_subset — so differentiable takes TWO args?? `ContDiff.differentiable (h : ContDiff 𝕜 n f) (hn : n ≠ 0)` — hn implicit? apparently explicit-ish... The error "argument interior_subset has type interior ?m ⊆ ?m of sort Prop but expected ℝ" — it's feeding interior_subset as the n ≠ 0 proof?? no — expected ℝ... confusing. Let me restructure: have hCD : ContDiff ℝ 2 u2 := by simp only [hu2def] exact ((contDiff_const.mul contDiff_id).add contDiff_const).mul ((contDiff_const.mul contDiff_id).exp) then hCD.continuous.continuousOn, hCD.differentiable (by norm_num)).differentiableOn.mono interior_subset. Wait — but u2 is a `set` variable: simp only [hu2def] unfolds it in the goal ✓. Hmm — but the contDiff proof's resulting function must match u2's body: u2 := fun t => (b²*t+b)*exp(−a*t) ✓ the term I give matches ✓. Note: `ContDiff.differentiable (by norm_num)` worked in psiTilde_contDiff context? I didn't use differentiable there. In chain_rule_sqrt_shift_on I used `hφ.differentiableOn (by norm_num)` ✓ that worked. So ContDiff.differentiable (h) (hn : n ≠ 0)? — from usage `hψ.differentiable (by norm_num)` in chain_rule_sqrt (global) — worked ✓. The 1203 error is really about my `.mono interior_subset` — "expected ℝ" — the .differentiableOn might need the set argument first? DifferentiableOn ℝ f s — .mono (h : s' ⊆ s)?? DifferentiableOn.mono : DifferentiableOn ℝ f s → s' ⊆ s → DifferentiableOn ℝ f s' ✓. "expected type ℝ sort Type" — the parser read `.differentiable\n (by norm_num).differentiableOn.mono interior_subset` weirdly — the newline broke it? I wrote: (by norm_num).differentiableOn.mono interior_subset Hmm "(by norm_num).differentiableOn.mono interior_subset" — elaborates (by norm_num) with expected type from .differentiableOn — the expected type of (by norm_num) is `2 ≠ 0`?? but the error says "invalid 'by' tactic, expected type has not been provided" — the (by norm_num) lacks expected type — meaning .differentiable's argument is IMPLICIT and (by norm_num) got parsed as the target of .differentiableOn! i.e. ContDiff.differentiable's hn is implicit/instance? In chain_rule_sqrt I wrote `hψ.differentiable (by norm_num)` and it worked... that's ContDiff.differentiable (h) (hn : n ≠ 0)?? — apparently hn explicit there. Here the dot-completion may differ. Honestly the whole line is fragile — restructure with have hCD. - 1213:12 timeout at whnf — in hu2anti's ≤0 section probably `rw [(hu2der x).deriv]` — or the contDiff line. The restructure may fix. Let me apply all these fixes.
Multiple small issues. The root cause of the linarith failure: `/s` binds differently in `m2` vs the goal. Fixing all.
tool: Edit
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiSkeleton.lean",
  "old_string": "    have m1 : (s + 1) * (a ^ 2 * eA + b ^ 2 * eB) \u2264 (s + 1) * (b ^ 2 * (eA + eB)) :=\n      mul_le_mul_of_nonneg_left h1 (by linarith)\n    have m2 : (s + 1) * ((a * eA + b * eB) / s) \u2264 (s + 1) * (b * (eA + eB) / s) :=\n      mul_le_mul_of_nonneg_left h2 (by linarith)\n    have e3 : 4.56 * (s + 1) * (b ^ 2 + b / s) * (eA + eB) =\n        4.56 * ((s + 1) * (b ^ 2 * (eA + eB)) + (s + 1) * (b * (eA + eB) / s)) := by\n      field_simp [hs0.ne']\n      ring\n    rw [e3]\n    linarith [m1, m2]",
  "new_string": "    have m1 : (s + 1) * (a ^ 2 * eA + b ^ 2 * eB) \u2264 (s + 1) * (b ^ 2 * (eA + eB)) :=\n      mul_le_mul_of_nonneg_left h1 (by linarith)\n    have m2 : (s + 1) * (a * eA + b * eB) / s \u2264 (s + 1) * (b * (eA + eB)) / s := by\n      have h3 := mul_le_mul_of_nonneg_left h2 (show (0 : \u211d) \u2264 s + 1 by linarith)\n      rwa [mul_div_assoc, mul_div_assoc] at h3\n    have e3 : 4.56 * (s + 1) * (b ^ 2 + b / s) * (eA + eB) =\n        4.56 * ((s + 1) * (b ^ 2 * (eA + eB)) + (s + 1) * (b * (eA + eB)) / s) := by\n      field_simp [hs0.ne']\n    rw [e3]\n    exact mul_le_mul_of_nonneg_left (add_le_add m1 m2) (by norm_num)"
}
raw content_json (database row)
[{"type":"thinking","thinking":"Now I see the a✝: goal IS in the right form: `4.56 * ((s+1)(b²(eA+eB)) + (s+1)(b(eA+eB)/s)) < 4.56 * ((s+1)(a²eA+b²eB) + (s+1)((aeA+beB)/s))` — and m1+m2 SHOULD contradict... m1 : (s+1)(a²eA+b²eB) ≤ (s+1)(b²(eA+eB)); m2 : (s+1)((aeA+beB)/s) ≤ (s+1)(b(eA+eB)/s). Sum: RHS ≤ LHS-components... a✝ says L' < R' where R' = m1's LHS-sum + m2's LHS-sum and L' = the two RHS-sums: m1+m2 give R' ≤ L' → contradiction with L' < R'?? wait: a✝ : [b-side] < [a-side]; m1: a-side-part1 ≤ b-side-part1; m2: a-side-part2 ≤ b-side-part2 → a-side ≤ b-side — contradicts a✝ (b-side < a-side) ✓ linarith SHOULD find this. The monomials: (s+1)*(a²eA+b²eB) — ring_nf: (s+1)a²eA + (s+1)a²eB... and in m1: same ✓. Why fail?? The a✝ has `4.56 * (X + Y)` where X = (s+1)*(b²*(eA+eB)) — m1's RHS is (s+1)*(b²*(eA+eB)) — SAME ✓...\n\nHmm — is it possible linarith's ring_nf normalization chokes on `4.56` (a decimal literal = OfNat.ofNat with floating rational)? 4.56 is a rational literal — ring handles ✓.\n\nOR — the `set` variables! eA, eB are `set` variables (let-bound) — linarith/ring treat them fine as atoms...\n\nWait — actually let me look VERY carefully at a✝: `4.56 * ((s + 1) * (b ^ 2 * (eA + eB)) + (s + 1) * (b * (eA + eB) / s)) < 4.56 * ((s + 1) * (a ^ 2 * eA + b ^ 2 * eB) + (s + 1) * (a * eA + b * eB) / s)`. m2's LHS: `(s + 1) * ((a * eA + b * eB) / s)`; a✝'s corresponding: `(s + 1) * (a * eA + b * eB) / s` — PARSING DIFFERENCE! `(s + 1) * (a * eA + b * eB) / s` parses as `((s+1)*(aeA+beB))/s` — division applied to the WHOLE product, while m2 has `(s+1) * ((aeA+beB)/s)`. These are equal by ring (mul_div_assoc) but DIFFERENT atoms for linarith's ring_nf?? ring_nf normalizes both to... ((s+1)(aeA+beB))·s⁻¹ — same ✓ should normalize identically.\n\nI'm stuck on why linarith fails — maybe it IS the set-variables: `set` replaces eA with a local definition — ring_nf might unfold?? no...\n\nAlternative: skip linarith, use direct term: \nexact add_le_add m1 m2 |>.trans_eq'?? hmm: goal: 4.56*(A1+A2) ≤ 4.56*(B1+B2) — via mul_le_mul_of_nonneg_left (add_le_add m1 m2) (by norm_num : (0:ℝ) ≤ 4.56) : 4.56 * ((s+1)X + (s+1)Y) ≤ 4.56 * ((s+1)X' + (s+1)Y') ✓ EXACTLY the goal shape (a✝ confirms the goal is 4.56*(sum) ≤ 4.56*(sum))! So:\nexact mul_le_mul_of_nonneg_left (add_le_add m1 m2) (by norm_num)\n\nThe add_le_add m1 m2 : (s+1)X + (s+1)Y ≤ (s+1)X' + (s+1)Y' where the sums match the goal's inner sums ✓ syntactically? goal inner LHS: (s + 1) * (a ^ 2 * eA + b ^ 2 * eB) + (s + 1) * (a * eA + b * eB) / s — note the `/s` binds to the whole second product! add_le_add m1 m2's LHS: (s+1)X + (s+1)Y with Y = ((aeA+beB)/s) — the goal's second summand is ((s+1)(aeA+beB))/s ≠ (s+1)((aeA+beB)/s) syntactically!! THAT's the mismatch — and linarith's ring_nf apparently did NOT unify them (surprising but fine). Fix m2's statement to ((s+1)*(aeA+beB))/s form: m2 : (s + 1) * (a * eA + b * eB) / s ≤ (s + 1) * (b * (eA + eB)) / s — from h2 by mul_le_mul_of_nonneg_left then massage: (s+1)*(X/s) = ((s+1)*X)/s: mul_div_assoc ✓: (s+1)*(b*(eA+eB)/s) = ((s+1)*(b*(eA+eB)))/s by (mul_div_assoc).symm. So:\n  have m2 : (s + 1) * (a * eA + b * eB) / s ≤ (s + 1) * (b * (eA + eB)) / s := by\n    have h3 := mul_le_mul_of_nonneg_left h2 (show (0:ℝ) ≤ s + 1 by linarith)\n    rwa [mul_div_assoc, mul_div_assoc] at h3\nThen exact mul_le_mul_of_nonneg_left (add_le_add m1 m2) (by norm_num : (0:ℝ) ≤ 4.56).\n\nAlso fix e3's RHS form to match: e3 : 4.56 * (s + 1) * (b ^ 2 + b / s) * (eA + eB) = 4.56 * ((s + 1) * (b ^ 2 * (eA + eB)) + (s + 1) * (b * (eA + eB)) / s) — second summand with /s outside ✓ field_simp;ring... field_simp closed it before (remove ring).\n\nOther errors:\n- 1193: simp no progress — hu2der's `simp only [Pi.mul_apply] at h` — made no progress (h's function has no Pi.mul applications?? hp.mul he's output: maybe it IS pointwise already: `fun x => f x * g x`?? HasDerivAt.mul : HasDerivAt (fun y => f y * g y)?? Let me check: earlier in psiTilde work, Pi.add_apply WAS needed (hva.add hvb showed Pi.add form). For .mul — hp.mul he: conclusion HasDerivAt (fun x => f x * g x)? or (f * g)? From the earlier error print in psiOf_log_sq_shift: `fun y => 2 * ((fun t => ...) * fun t => ...) y` — that was const_mul of a MUL — the mul there produced Pi.mul ((f) * (g)) y. So .mul DOES produce Pi.mul. But here simp says no progress — maybe because I already have h in the right form... If simp made no progress it's an ERROR regardless. Remove the simp; but then exact h needs the function match — try `exact h` alone; if mismatch, convert.\n  Actually — difference: here hp = ((hasDerivAt_id' x).const_mul (b²)).add_const b — the OUTER op is .add_const (value-add), then hp.mul he: Pi.mul of (fun t => b²*t+b) and (fun t => exp(−a*t)): h's function: fun y => ((fun t => b²*t+b) * (fun t => exp(−a*t))) y — Pi.mul_apply should rewrite... \"no progress\" means no (f * g) y pattern — maybe the elaborator already beta/iota-reduced? The goal u2: set var — the exact h will need u2 ≡ h's function — set-local-def defeq ✓. Just do rw [e] at h; exact h and see.\n- 1203: my ContDiff.differentiable application got mangled — `ContDiff.differentiable (hn : n ≠ 0)`: I wrote `.differentiable (by norm_num).differentiableOn.mono interior_subset` — parsed as differentiable applied to (by norm_num) AND interior_subset?? The error shows ContDiff.differentiable ... ?m.3922 interior_subset — so differentiable takes TWO args?? `ContDiff.differentiable (h : ContDiff 𝕜 n f) (hn : n ≠ 0)` — hn implicit? apparently explicit-ish... The error \"argument interior_subset has type interior ?m ⊆ ?m of sort Prop but expected ℝ\" — it's feeding interior_subset as the n ≠ 0 proof?? no — expected ℝ... confusing. Let me restructure: \n  have hCD : ContDiff ℝ 2 u2 := by\n    simp only [hu2def]\n    exact ((contDiff_const.mul contDiff_id).add contDiff_const).mul\n      ((contDiff_const.mul contDiff_id).exp)\n  then hCD.continuous.continuousOn, hCD.differentiable (by norm_num)).differentiableOn.mono interior_subset.\n  Wait — but u2 is a `set` variable: simp only [hu2def] unfolds it in the goal ✓. Hmm — but the contDiff proof's resulting function must match u2's body: u2 := fun t => (b²*t+b)*exp(−a*t) ✓ the term I give matches ✓.\n  Note: `ContDiff.differentiable (by norm_num)` worked in psiTilde_contDiff context? I didn't use differentiable there. In chain_rule_sqrt_shift_on I used `hφ.differentiableOn (by norm_num)` ✓ that worked. So ContDiff.differentiable (h) (hn : n ≠ 0)? — from usage `hψ.differentiable (by norm_num)` in chain_rule_sqrt (global) — worked ✓. The 1203 error is really about my `.mono interior_subset` — \"expected ℝ\" — the .differentiableOn might need the set argument first? DifferentiableOn ℝ f s — .mono (h : s' ⊆ s)?? DifferentiableOn.mono : DifferentiableOn ℝ f s → s' ⊆ s → DifferentiableOn ℝ f s' ✓. \"expected type ℝ sort Type\" — the parser read `.differentiable\\n (by norm_num).differentiableOn.mono interior_subset` weirdly — the newline broke it? I wrote:\n          (by norm_num).differentiableOn.mono interior_subset\n  Hmm \"(by norm_num).differentiableOn.mono interior_subset\" — elaborates (by norm_num) with expected type from .differentiableOn — the expected type of (by norm_num) is `2 ≠ 0`?? but the error says \"invalid 'by' tactic, expected type has not been provided\" — the (by norm_num) lacks expected type — meaning .differentiable's argument is IMPLICIT and (by norm_num) got parsed as the target of .differentiableOn! i.e. ContDiff.differentiable's hn is implicit/instance? In chain_rule_sqrt I wrote `hψ.differentiable (by norm_num)` and it worked... that's ContDiff.differentiable (h) (hn : n ≠ 0)?? — apparently hn explicit there. Here the dot-completion may differ. Honestly the whole line is fragile — restructure with have hCD.\n- 1213:12 timeout at whnf — in hu2anti's ≤0 section probably `rw [(hu2der x).deriv]` — or the contDiff line. The restructure may fix.\n\nLet me apply all these fixes.","signature":""},{"type":"text","text":"Multiple small issues. The root cause of the linarith failure: `/s` binds differently in `m2` vs the goal. Fixing all."},{"type":"tool_use","id":"Edit_207","name":"Edit","input":{"file_path":"D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiSkeleton.lean","old_string":"    have m1 : (s + 1) * (a ^ 2 * eA + b ^ 2 * eB) ≤ (s + 1) * (b ^ 2 * (eA + eB)) :=\n      mul_le_mul_of_nonneg_left h1 (by linarith)\n    have m2 : (s + 1) * ((a * eA + b * eB) / s) ≤ (s + 1) * (b * (eA + eB) / s) :=\n      mul_le_mul_of_nonneg_left h2 (by linarith)\n    have e3 : 4.56 * (s + 1) * (b ^ 2 + b / s) * (eA + eB) =\n        4.56 * ((s + 1) * (b ^ 2 * (eA + eB)) + (s + 1) * (b * (eA + eB) / s)) := by\n      field_simp [hs0.ne']\n      ring\n    rw [e3]\n    linarith [m1, m2]","new_string":"    have m1 : (s + 1) * (a ^ 2 * eA + b ^ 2 * eB) ≤ (s + 1) * (b ^ 2 * (eA + eB)) :=\n      mul_le_mul_of_nonneg_left h1 (by linarith)\n    have m2 : (s + 1) * (a * eA + b * eB) / s ≤ (s + 1) * (b * (eA + eB)) / s := by\n      have h3 := mul_le_mul_of_nonneg_left h2 (show (0 : ℝ) ≤ s + 1 by linarith)\n      rwa [mul_div_assoc, mul_div_assoc] at h3\n    have e3 : 4.56 * (s + 1) * (b ^ 2 + b / s) * (eA + eB) =\n        4.56 * ((s + 1) * (b ^ 2 * (eA + eB)) + (s + 1) * (b * (eA + eB)) / s) := by\n      field_simp [hs0.ne']\n    rw [e3]\n    exact mul_le_mul_of_nonneg_left (add_le_add m1 m2) (by norm_num)"},"extra_content":null}]