← Session 24 — ii′-2…4: swaps, (4.10) design, contour + website roadmap fixes
thinking (8911 chars)
Issues:
1. **Line 497** (hI1): integral_congr_ae unify failure: the LHS set is `Set.Ioi ↑1` (Nat cast) vs RHS `Set.Ioi 1` — same cast mismatch as before. Fix: my hI1 statement uses `Set.Ioi ((1 : ℕ) : ℝ)` on the left and `Set.Ioi (1:ℝ)` on the right — the riemannZeta0_apply form has `Ioi ((1:ℕ):ℝ)`? hmm actually the issue is that the rw [← integral_neg] turned the RHS into −∫...(Ioi 1) but... The cleanest: state hI1 with matching sets and let the cast go through `Nat.cast_one`:
Change hI1's statement: left side `Set.Ioi ((1:ℕ):ℝ)` — after `rw [Nat.cast_one]` becomes Ioi 1. And the integral_congr_ae then has matching sets. Let me restructure: state hI1 with both sides on Ioi (1:ℝ), and when applying `rw [Nat.cast_one, hI1, ...]` in the main proof the cast handles the ζ₀ side. So:
```lean
have hI1 : (∫ x in Set.Ioi (1:ℝ), (⌊x⌋ + 1 / 2 - x) * (x : ℂ) ^ (-(s + 1)))
= -∫ x in Set.Ioi (1:ℝ), (B1 x : ℂ) * (x : ℂ) ^ (-s - 1) := by
```
and in the main rw: the ζ₀ form after riemannZeta0_apply has ∫ x in Ioi (↑1)... — rw [Nat.cast_one] before hI1 — I already have `rw [Nat.cast_one, hI1, integral_b1_cpow_eq hs]` — Nat.cast_one rewrites ↑(1:ℕ) → 1 in the goal ✓ then hI1 matches ✓. So just change hI1's statement to use (1:ℝ).
2. **Line 485** (the final algebra): after rw [hsum, Nat.cast_one, hI1, integral_b1_cpow_eq hs], the goal has `1 ^ (1 - s)` and `1 ^ (-s)` terms left (the ζ₀ boundary terms (−1^(1−s))/(1−s) etc.) — my field_simp; ring left a mess: the `1 ^ (1 - s)` and `1 ^ (-s)` need one_cpow simplification! Add `Complex.one_cpow` simp:
```lean
rw [hsum, Nat.cast_one, hI1, integral_b1_cpow_eq hs]
simp only [Complex.one_cpow] -- 1^(1−s) = 1, 1^(−s) = 1
field_simp
ring
```
Hmm — the mess shows `s * 1 ^ (1 - s) * 2` etc. — after one_cpow those become s·1·2 = 2s. Then field_simp + ring should close. Let me also look at the actual goal shape — the ζ₀ form: 1 + (−1^(1−s))/(1−s) + (−1^(−s))/2 + s·(−∫B̃₁...) — wait — after the rewrites the goal is: 1 + (−1^(1−s))/(1−s) + (−1^(−s))/2 − s·((s+1)·∫B̃₂...) = 1/2 + 1/(s−1) − s(s+1)∫B̃₂. With one_cpow: −1/(1−s) = 1/(s−1) ✓ field_simp [show s ≠ 1...] + ring. Need s−1 ≠ 0 for field_simp: hs1. Let me write:
```lean
rw [hsum, Nat.cast_one, hI1, integral_b1_cpow_eq hs]
simp only [Complex.one_cpow]
field_simp [sub_ne_zero.mpr hs1]
ring
```
Hmm — field_simp might mangle; alternative pure:
```lean
have e1 : (-(1 : ℂ) ^ (1 - s)) / (1 - s) = 1 / (s - 1) := by
rw [Complex.one_cpow]
field_simp [sub_ne_zero.mpr hs1]
ring -- −1/(1−s) = 1/(s−1)
have e2 : (-(1 : ℂ) ^ (-s)) / 2 = -1 / 2 := by rw [Complex.one_cpow]
rw [e1, e2]
ring
```
Wait — the goal after all rewrites: `1 + (−1^(1−s))/(1−s) + (−1^(−s))/2 − s·((s+1)·∫B̃₂) = 1/2 + 1/(s−1) − s(s+1)∫B̃₂`: with e1, e2: 1 + 1/(s−1) − 1/2 − s(s+1)∫ = 1/2 + 1/(s−1) − s(s+1)∫ ✓ ring closes (treating ∫ as atom). But CAREFUL: the LHS integral form after hI1 + integral_b1_cpow_eq: hI1 turned ζ₀'s integral into −∫B̃₁; then the term is `s * (−∫B̃₁)` — wait the ζ₀ expression has `s * ∫(⌊x⌋+1/2−x)·x^(−(s+1))` and hI1 says that integral = −∫B̃₁·x^(−s−1): so the term = s·(−∫B̃₁·x^(−s−1)) = −s·(s+1)∫B̃₂ via integral_b1_cpow_eq: rw [integral_b1_cpow_eq hs] rewrites ∫B̃₁·x^(−s−1) → (s+1)∫B̃₂·x^(−s−2) ✓. Then ring with the integral atom ✓. But the displayed error goal shows `↑(b2Fun x) * ↑x ^ (-2 - s)` — exponent `−2 − s` vs my `−s − 2` — different syntactic forms (ring-normalized differently)! The integral's exponent in the goal got normalized to (−2−s) while my statement has (−s−2) — the integrals are SYNTACTICALLY different atoms — ring treats them as different! Ugh. That's because the goal went through field_simp which ring-normalized the exponent. Fix: don't field_simp; use the e1/e2 route with ring only (ring might also normalize exponents differently on each side — but if both sides undergo the same normalization, the atoms match ✓). The error came from field_simp; ring — let me use ONLY ring after e1/e2 rewrites. Both sides' exponents get... ring doesn't rewrite inside atoms — it treats `∫ x, ↑b2Fun x·↑x^(−s−2)` as an atom ONLY IF both sides have syntactically identical integrals. My statement's integral: `↑(b2Fun x) * ↑x ^ (-s - 2)`; the goal's after the rewrites: from integral_b1_cpow_eq's RHS: `(s + 1) * ∫ x in Ioi 1, ↑(b2Fun x) * ↑x ^ (-s - 2)` — same form ✓ (the lemma's own statement). So as long as NO field_simp/ring_nf normalizes the exponent, the atoms match and ring closes ✓. So: e1/e2 + ring only.
3. **Line 515** variable z warning — minor, fix by naming _z? The `intro z hz` in hf_an's mono — the z IS used (rw [h1] at hz...). Warning says "not explicitly referenced" at 515 — the hg_an intro? Let me see — it's a warning only; skip for now.
4. **Line 539** hg_an's structure: `apply AnalyticAt.sub _ (analyticOnNhd_b2Integral z hz.1)` failed to unify — because the function form: my goal function: fun s => (1/2 + 1/(s−1)) − s*(s+1)*∫... — AnalyticAt.sub (hf : AnalyticAt f) (hg : AnalyticAt g) : AnalyticAt (f − g) — the (f − g) is pointwise Pi.sub — my goal's lambda fun s => A s − B s — vs f − g — defeq but apply's unification of `?f − ?g` with `fun s => A s − B s` — needs higher-order matching — sometimes works, sometimes not. Standard fix: `apply AnalyticAt.sub` FIRST without args, letting the goal drive f, g; the second goal is AnalyticAt (fun s => s*(s+1)*∫...) z which I then prove via .mul... So:
```lean
intro z hz
apply AnalyticAt.sub
· apply AnalyticAt.add analyticAt_const
apply AnalyticAt.div analyticAt_const (analyticAt_id.sub analyticAt_const)
intro h
...
· apply AnalyticAt.mul
· exact analyticAt_id.mul (analyticAt_id.add analyticAt_const)
· exact analyticOnNhd_b2Integral z hz.1
```
Hmm wait — I did have `apply AnalyticAt.sub _ (analyticOnNhd_b2Integral z hz.1)` — the explicit second arg forces ?g := the integral function — but then the FIRST function ?f must satisfy ?f − ?g = goal-lambda: with both args fixed the pointwise sub f − g vs fun s => A s − B s: f := fun s => 1/2+1/(s−1) must be inferred — the apply created ?f as a metavariable and unified (fun s => ?f s − ∫...s) with the goal — higher-order pattern — usually works (?f s .−. ...)? The error says it could NOT unify — the issue: `AnalyticAt.sub ?m (?integral)`'s type: AnalyticAt ℂ (?m − fun s => ∫...) z vs goal AnalyticAt ℂ (fun s => 1/2 + 1/(s−1) − s*(s+1)*∫...) z — unify ?m − (fun s => ∫) =?= fun s => (1/2+1/(s−1)) − (s*(s+1)*∫): ?m := fun s => 1/2+1/(s−1) requires inverting the subtraction pointwise — the lambda structure: Pi.sub ?m g = fun s => ?m s − g s — unify with fun s => A s − B s: ?m s = A s ✓ pattern... should work. But the error shows it failing — because the goal lambda has `s * (s + 1) * ∫ ...` as the SUBTRAHEND and ?g was fixed to just `fun s => ∫...` (without the s(s+1) factor)! I passed analyticOnNhd_b2Integral z hz.1 : AnalyticAt (fun s => ∫...) — that's only the integral factor, not s(s+1)·∫. Mismatch. So: apply AnalyticAt.sub (no args) then build the pieces:
```lean
intro z hz
apply AnalyticAt.sub
· apply AnalyticAt.add analyticAt_const
apply AnalyticAt.div analyticAt_const (analyticAt_id.sub analyticAt_const)
intro h
have hz1 : z = 1 := by rwa [sub_eq_zero] at h
have hz2 := hz.2
rw [hz1, Complex.one_im] at hz2
norm_num at hz2
· apply AnalyticAt.mul
· exact analyticAt_id.mul (analyticAt_id.add analyticAt_const)
· exact analyticOnNhd_b2Integral z hz.1
```
The AnalyticAt.div for 1/(s−1): the goal after add: AnalyticAt (fun s => 1 / (s − 1)) z: AnalyticAt.div (hf : AnalyticAt f) (hg : AnalyticAt g) (hg0 : g z ≠ 0) : AnalyticAt (fun x => f x / g x) ✓ f = const 1, g = s−1 ✓.
Also the `intro h; have hz1 : z = 1 := by rwa [sub_eq_zero] at h` — h : (z − 1) ≠ ... wait the div's side goal: g z ≠ 0 i.e. (fun s => s − 1) z ≠ 0 = z − 1 ≠ 0: intro h: h : z − 1 = 0?? no — the side goal is `(fun s => s - 1) z ≠ 0` = `z - 1 ≠ 0` — I need to PROVE it (not intro into False): `intro h` turns ¬P into P → False ✓ fine: h : z − 1 = 0; hz1 : z = 1 via sub_eq_zero.mp h ✓ (rwa does mp then... `rwa [sub_eq_zero] at h` — rewrites h : z − 1 = 0 into z = 1 via the iff ✓ hmm rwa [iff] at h — sub_eq_zero : a − b = 0 ↔ a = b — rwa rewrites the PROP h using the iff ✓). Then hz2 := hz.2 : 5 < z.im; rw [hz1, Complex.one_im] at hz2 : 5 < 1.im → 5 < 0 → norm_num at hz2 closes (False) ✓.
5. The hf_an's `show z ≠ 1; intro h1; ...` — similar ✓ already there.
Also the 515 warning about unused z — it's in hf_an's mono lambda: `fun z hz => by show z ≠ 1; intro h1; have hz2 := hz.2; rw [h1, Complex.one_im] at hz2; norm_num at hz2` — z used in hz/h1 ✓ — hmm the warning was at 515:9 — might be the hV's `constructor` block... skip, it's a warning. Actually wait — it could become an issue if it's an `intro z hz` where z unused — linter only. Fine.
Let me apply the fixes.
Applying fixes: cast-normalize hI1's set, the one_cpow simplifications in the algebra step, and restructuring hg_an's apply chain.
tool: Edit
input
{
"replace_all": false,
"file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiRBound.lean",
"old_string": " have hI1 : (\u222b x in Set.Ioi ((1 : \u2115) : \u211d), (\u230ax\u230b + 1 / 2 - x) * (x : \u2102) ^ (-(s + 1)))\n = -\u222b x in Set.Ioi (1:\u211d), (B1 x : \u2102) * (x : \u2102) ^ (-s - 1) := by\n rw [\u2190 integral_neg]\n apply integral_congr_ae\n filter_upwards [self_mem_ae_restrict measurableSet_Ioi] with x hx\n have hx0 : (0:\u211d) \u2264 x := zero_le_one.trans (Set.mem_Ioi.mp hx).le\n rw [b1_eq_fract_sub_half hx0, Int.fract]\n have e : (-(s + 1) : \u2102) = -s - 1 := by ring\n rw [e]\n push_cast\n ring\n rw [Nat.cast_one, hI1, integral_b1_cpow_eq hs]\n field_simp\n ring",
"new_string": " have hI1 : (\u222b x in Set.Ioi (1:\u211d), (\u230ax\u230b + 1 / 2 - x) * (x : \u2102) ^ (-(s + 1)))\n = -\u222b x in Set.Ioi (1:\u211d), (B1 x : \u2102) * (x : \u2102) ^ (-s - 1) := by\n rw [\u2190 integral_neg]\n apply integral_congr_ae\n filter_upwards [self_mem_ae_restrict measurableSet_Ioi] with x hx\n have hx0 : (0:\u211d) \u2264 x := zero_le_one.trans (Set.mem_Ioi.mp hx).le\n rw [b1_eq_fract_sub_half hx0, Int.fract]\n have e : (-(s + 1) : \u2102) = -s - 1 := by ring\n rw [e]\n push_cast\n ring\n rw [Nat.cast_one, hI1, integral_b1_cpow_eq hs]\n have e1 : (-(1 : \u2102) ^ (1 - s)) / (1 - s) = 1 / (s - 1) := by\n rw [Complex.one_cpow]\n field_simp [sub_ne_zero.mpr hs1]\n have e2 : (-(1 : \u2102) ^ (-s)) / 2 = -1 / 2 := by\n rw [Complex.one_cpow]\n rw [e1, e2]\n ring"
}
raw content_json (database row)
[{"type":"thinking","thinking":"Issues:\n\n1. **Line 497** (hI1): integral_congr_ae unify failure: the LHS set is `Set.Ioi ↑1` (Nat cast) vs RHS `Set.Ioi 1` — same cast mismatch as before. Fix: my hI1 statement uses `Set.Ioi ((1 : ℕ) : ℝ)` on the left and `Set.Ioi (1:ℝ)` on the right — the riemannZeta0_apply form has `Ioi ((1:ℕ):ℝ)`? hmm actually the issue is that the rw [← integral_neg] turned the RHS into −∫...(Ioi 1) but... The cleanest: state hI1 with matching sets and let the cast go through `Nat.cast_one`:\n Change hI1's statement: left side `Set.Ioi ((1:ℕ):ℝ)` — after `rw [Nat.cast_one]` becomes Ioi 1. And the integral_congr_ae then has matching sets. Let me restructure: state hI1 with both sides on Ioi (1:ℝ), and when applying `rw [Nat.cast_one, hI1, ...]` in the main proof the cast handles the ζ₀ side. So:\n ```lean\n have hI1 : (∫ x in Set.Ioi (1:ℝ), (⌊x⌋ + 1 / 2 - x) * (x : ℂ) ^ (-(s + 1)))\n = -∫ x in Set.Ioi (1:ℝ), (B1 x : ℂ) * (x : ℂ) ^ (-s - 1) := by\n ```\n and in the main rw: the ζ₀ form after riemannZeta0_apply has ∫ x in Ioi (↑1)... — rw [Nat.cast_one] before hI1 — I already have `rw [Nat.cast_one, hI1, integral_b1_cpow_eq hs]` — Nat.cast_one rewrites ↑(1:ℕ) → 1 in the goal ✓ then hI1 matches ✓. So just change hI1's statement to use (1:ℝ).\n\n2. **Line 485** (the final algebra): after rw [hsum, Nat.cast_one, hI1, integral_b1_cpow_eq hs], the goal has `1 ^ (1 - s)` and `1 ^ (-s)` terms left (the ζ₀ boundary terms (−1^(1−s))/(1−s) etc.) — my field_simp; ring left a mess: the `1 ^ (1 - s)` and `1 ^ (-s)` need one_cpow simplification! Add `Complex.one_cpow` simp: \n```lean\n rw [hsum, Nat.cast_one, hI1, integral_b1_cpow_eq hs]\n simp only [Complex.one_cpow] -- 1^(1−s) = 1, 1^(−s) = 1\n field_simp\n ring\n```\nHmm — the mess shows `s * 1 ^ (1 - s) * 2` etc. — after one_cpow those become s·1·2 = 2s. Then field_simp + ring should close. Let me also look at the actual goal shape — the ζ₀ form: 1 + (−1^(1−s))/(1−s) + (−1^(−s))/2 + s·(−∫B̃₁...) — wait — after the rewrites the goal is: 1 + (−1^(1−s))/(1−s) + (−1^(−s))/2 − s·((s+1)·∫B̃₂...) = 1/2 + 1/(s−1) − s(s+1)∫B̃₂. With one_cpow: −1/(1−s) = 1/(s−1) ✓ field_simp [show s ≠ 1...] + ring. Need s−1 ≠ 0 for field_simp: hs1. Let me write:\n```lean\n rw [hsum, Nat.cast_one, hI1, integral_b1_cpow_eq hs]\n simp only [Complex.one_cpow]\n field_simp [sub_ne_zero.mpr hs1]\n ring\n```\nHmm — field_simp might mangle; alternative pure: \n```lean\n have e1 : (-(1 : ℂ) ^ (1 - s)) / (1 - s) = 1 / (s - 1) := by\n rw [Complex.one_cpow]\n field_simp [sub_ne_zero.mpr hs1]\n ring -- −1/(1−s) = 1/(s−1)\n have e2 : (-(1 : ℂ) ^ (-s)) / 2 = -1 / 2 := by rw [Complex.one_cpow]\n rw [e1, e2]\n ring\n```\nWait — the goal after all rewrites: `1 + (−1^(1−s))/(1−s) + (−1^(−s))/2 − s·((s+1)·∫B̃₂) = 1/2 + 1/(s−1) − s(s+1)∫B̃₂`: with e1, e2: 1 + 1/(s−1) − 1/2 − s(s+1)∫ = 1/2 + 1/(s−1) − s(s+1)∫ ✓ ring closes (treating ∫ as atom). But CAREFUL: the LHS integral form after hI1 + integral_b1_cpow_eq: hI1 turned ζ₀'s integral into −∫B̃₁; then the term is `s * (−∫B̃₁)` — wait the ζ₀ expression has `s * ∫(⌊x⌋+1/2−x)·x^(−(s+1))` and hI1 says that integral = −∫B̃₁·x^(−s−1): so the term = s·(−∫B̃₁·x^(−s−1)) = −s·(s+1)∫B̃₂ via integral_b1_cpow_eq: rw [integral_b1_cpow_eq hs] rewrites ∫B̃₁·x^(−s−1) → (s+1)∫B̃₂·x^(−s−2) ✓. Then ring with the integral atom ✓. But the displayed error goal shows `↑(b2Fun x) * ↑x ^ (-2 - s)` — exponent `−2 − s` vs my `−s − 2` — different syntactic forms (ring-normalized differently)! The integral's exponent in the goal got normalized to (−2−s) while my statement has (−s−2) — the integrals are SYNTACTICALLY different atoms — ring treats them as different! Ugh. That's because the goal went through field_simp which ring-normalized the exponent. Fix: don't field_simp; use the e1/e2 route with ring only (ring might also normalize exponents differently on each side — but if both sides undergo the same normalization, the atoms match ✓). The error came from field_simp; ring — let me use ONLY ring after e1/e2 rewrites. Both sides' exponents get... ring doesn't rewrite inside atoms — it treats `∫ x, ↑b2Fun x·↑x^(−s−2)` as an atom ONLY IF both sides have syntactically identical integrals. My statement's integral: `↑(b2Fun x) * ↑x ^ (-s - 2)`; the goal's after the rewrites: from integral_b1_cpow_eq's RHS: `(s + 1) * ∫ x in Ioi 1, ↑(b2Fun x) * ↑x ^ (-s - 2)` — same form ✓ (the lemma's own statement). So as long as NO field_simp/ring_nf normalizes the exponent, the atoms match and ring closes ✓. So: e1/e2 + ring only.\n\n3. **Line 515** variable z warning — minor, fix by naming _z? The `intro z hz` in hf_an's mono — the z IS used (rw [h1] at hz...). Warning says \"not explicitly referenced\" at 515 — the hg_an intro? Let me see — it's a warning only; skip for now.\n\n4. **Line 539** hg_an's structure: `apply AnalyticAt.sub _ (analyticOnNhd_b2Integral z hz.1)` failed to unify — because the function form: my goal function: fun s => (1/2 + 1/(s−1)) − s*(s+1)*∫... — AnalyticAt.sub (hf : AnalyticAt f) (hg : AnalyticAt g) : AnalyticAt (f − g) — the (f − g) is pointwise Pi.sub — my goal's lambda fun s => A s − B s — vs f − g — defeq but apply's unification of `?f − ?g` with `fun s => A s − B s` — needs higher-order matching — sometimes works, sometimes not. Standard fix: `apply AnalyticAt.sub` FIRST without args, letting the goal drive f, g; the second goal is AnalyticAt (fun s => s*(s+1)*∫...) z which I then prove via .mul... So:\n```lean\n intro z hz\n apply AnalyticAt.sub\n · apply AnalyticAt.add analyticAt_const\n apply AnalyticAt.div analyticAt_const (analyticAt_id.sub analyticAt_const)\n intro h\n ...\n · apply AnalyticAt.mul\n · exact analyticAt_id.mul (analyticAt_id.add analyticAt_const)\n · exact analyticOnNhd_b2Integral z hz.1\n```\nHmm wait — I did have `apply AnalyticAt.sub _ (analyticOnNhd_b2Integral z hz.1)` — the explicit second arg forces ?g := the integral function — but then the FIRST function ?f must satisfy ?f − ?g = goal-lambda: with both args fixed the pointwise sub f − g vs fun s => A s − B s: f := fun s => 1/2+1/(s−1) must be inferred — the apply created ?f as a metavariable and unified (fun s => ?f s − ∫...s) with the goal — higher-order pattern — usually works (?f s .−. ...)? The error says it could NOT unify — the issue: `AnalyticAt.sub ?m (?integral)`'s type: AnalyticAt ℂ (?m − fun s => ∫...) z vs goal AnalyticAt ℂ (fun s => 1/2 + 1/(s−1) − s*(s+1)*∫...) z — unify ?m − (fun s => ∫) =?= fun s => (1/2+1/(s−1)) − (s*(s+1)*∫): ?m := fun s => 1/2+1/(s−1) requires inverting the subtraction pointwise — the lambda structure: Pi.sub ?m g = fun s => ?m s − g s — unify with fun s => A s − B s: ?m s = A s ✓ pattern... should work. But the error shows it failing — because the goal lambda has `s * (s + 1) * ∫ ...` as the SUBTRAHEND and ?g was fixed to just `fun s => ∫...` (without the s(s+1) factor)! I passed analyticOnNhd_b2Integral z hz.1 : AnalyticAt (fun s => ∫...) — that's only the integral factor, not s(s+1)·∫. Mismatch. So: apply AnalyticAt.sub (no args) then build the pieces:\n```lean\n intro z hz\n apply AnalyticAt.sub\n · apply AnalyticAt.add analyticAt_const\n apply AnalyticAt.div analyticAt_const (analyticAt_id.sub analyticAt_const)\n intro h\n have hz1 : z = 1 := by rwa [sub_eq_zero] at h\n have hz2 := hz.2\n rw [hz1, Complex.one_im] at hz2\n norm_num at hz2\n · apply AnalyticAt.mul\n · exact analyticAt_id.mul (analyticAt_id.add analyticAt_const)\n · exact analyticOnNhd_b2Integral z hz.1\n```\nThe AnalyticAt.div for 1/(s−1): the goal after add: AnalyticAt (fun s => 1 / (s − 1)) z: AnalyticAt.div (hf : AnalyticAt f) (hg : AnalyticAt g) (hg0 : g z ≠ 0) : AnalyticAt (fun x => f x / g x) ✓ f = const 1, g = s−1 ✓.\n\nAlso the `intro h; have hz1 : z = 1 := by rwa [sub_eq_zero] at h` — h : (z − 1) ≠ ... wait the div's side goal: g z ≠ 0 i.e. (fun s => s − 1) z ≠ 0 = z − 1 ≠ 0: intro h: h : z − 1 = 0?? no — the side goal is `(fun s => s - 1) z ≠ 0` = `z - 1 ≠ 0` — I need to PROVE it (not intro into False): `intro h` turns ¬P into P → False ✓ fine: h : z − 1 = 0; hz1 : z = 1 via sub_eq_zero.mp h ✓ (rwa does mp then... `rwa [sub_eq_zero] at h` — rewrites h : z − 1 = 0 into z = 1 via the iff ✓ hmm rwa [iff] at h — sub_eq_zero : a − b = 0 ↔ a = b — rwa rewrites the PROP h using the iff ✓). Then hz2 := hz.2 : 5 < z.im; rw [hz1, Complex.one_im] at hz2 : 5 < 1.im → 5 < 0 → norm_num at hz2 closes (False) ✓.\n\n5. The hf_an's `show z ≠ 1; intro h1; ...` — similar ✓ already there.\n\nAlso the 515 warning about unused z — it's in hf_an's mono lambda: `fun z hz => by show z ≠ 1; intro h1; have hz2 := hz.2; rw [h1, Complex.one_im] at hz2; norm_num at hz2` — z used in hz/h1 ✓ — hmm the warning was at 515:9 — might be the hV's `constructor` block... skip, it's a warning. Actually wait — it could become an issue if it's an `intro z hz` where z unused — linter only. Fine.\n\nLet me apply the fixes.","signature":""},{"type":"text","text":"Applying fixes: cast-normalize hI1's set, the one_cpow simplifications in the algebra step, and restructuring hg_an's apply chain."},{"type":"tool_use","id":"Edit_284","name":"Edit","input":{"replace_all":false,"file_path":"D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiRBound.lean","old_string":" have hI1 : (∫ x in Set.Ioi ((1 : ℕ) : ℝ), (⌊x⌋ + 1 / 2 - x) * (x : ℂ) ^ (-(s + 1)))\n = -∫ x in Set.Ioi (1:ℝ), (B1 x : ℂ) * (x : ℂ) ^ (-s - 1) := by\n rw [← integral_neg]\n apply integral_congr_ae\n filter_upwards [self_mem_ae_restrict measurableSet_Ioi] with x hx\n have hx0 : (0:ℝ) ≤ x := zero_le_one.trans (Set.mem_Ioi.mp hx).le\n rw [b1_eq_fract_sub_half hx0, Int.fract]\n have e : (-(s + 1) : ℂ) = -s - 1 := by ring\n rw [e]\n push_cast\n ring\n rw [Nat.cast_one, hI1, integral_b1_cpow_eq hs]\n field_simp\n ring","new_string":" have hI1 : (∫ x in Set.Ioi (1:ℝ), (⌊x⌋ + 1 / 2 - x) * (x : ℂ) ^ (-(s + 1)))\n = -∫ x in Set.Ioi (1:ℝ), (B1 x : ℂ) * (x : ℂ) ^ (-s - 1) := by\n rw [← integral_neg]\n apply integral_congr_ae\n filter_upwards [self_mem_ae_restrict measurableSet_Ioi] with x hx\n have hx0 : (0:ℝ) ≤ x := zero_le_one.trans (Set.mem_Ioi.mp hx).le\n rw [b1_eq_fract_sub_half hx0, Int.fract]\n have e : (-(s + 1) : ℂ) = -s - 1 := by ring\n rw [e]\n push_cast\n ring\n rw [Nat.cast_one, hI1, integral_b1_cpow_eq hs]\n have e1 : (-(1 : ℂ) ^ (1 - s)) / (1 - s) = 1 / (s - 1) := by\n rw [Complex.one_cpow]\n field_simp [sub_ne_zero.mpr hs1]\n have e2 : (-(1 : ℂ) ^ (-s)) / 2 = -1 / 2 := by\n rw [Complex.one_cpow]\n rw [e1, e2]\n ring"},"extra_content":null}]