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← Session 27 — ii′-5c/5d: Davenport disc + FE-reflection bounds

#1362 assistant 2026-08-23 04:40:11.547 UTC · 506→1575 tok open ⤢
thinking (3688 chars)
Excellent. Zeta23 has everything: - `analyticOrderAt_zeta_one_sub` (order transport through FE for 0 < re < 1) - `zeta_mult_reflect`: zeroMult (reflect ρ) = zeroMult ρ for nontrivial zeros, where `reflect ρ = 1 - conj ρ`. Hmm — note: `reflect ρ = 1 - conj ρ`. The FE symmetry I need for ii′-5d is ρ′ = 1 − ρ (not 1 − conj ρ). Let me think about what exactly the zero-sum cancellation needs. The two sums in D-067 §3: - Σ_{|γ−t|<1} m/(s−ρ) (the nearZeros(t) sum at s) - Σ_{|γ′+t|<1} m′/(1−s−ρ′) (the nearZeros(−t) sum at 1−s) Claim: these cancel exactly. The map is ρ ↦ 1 − ρ. If ρ is a nontrivial zero with im ρ near t, then 1 − ρ is a zero with im(1−ρ) = −im ρ near −t. And 1−s−(1−ρ) = −(s−ρ), so m/(1−s−ρ′) = −m/(s−ρ). So the needed map is ρ ↦ 1 − ρ (NOT the conjugated reflect). Does Zeta23 have zeroMult (1 − ρ) = zeroMult ρ? From `analyticOrderAt_zeta_one_sub`: for 0 < re w < 1, analyticOrderAt ζ (1−w) = analyticOrderAt ζ w. That directly gives zeroMult (1−ρ) = zeroMult ρ for nontrivial zeros ρ (0 < re ρ < 1). Let me check the exact statement at line 224. Also, is 1−ρ a nontrivial zero when ρ is? If ρ = β+iγ is a zero with 0<β<1, then 1−ρ = (1−β)−iγ: ζ(1−ρ) = 0 by the order transport (order ≥ 1 preserved), 0 < 1−β < 1. So yes — IsNontrivialZero (1−ρ). Let me check: the nearZeros finset is defined via `zeroDiscFinset t` filtered by |ρ.im − t| < 1. What is zeroDiscFinset? From journal-023: "zeroDiscFinset + zeroDisc_isNontrivial (re ≥ 1 via Mathlib's one_le_re nonvanishing; re ≤ 0 via ΓR-pole/FE)". So zeroDiscFinset t contains the zeros of ζ in the disc B(2+it, 5/2)... wait actually let me re-read. From the journal: zeroDiscFinset — the zeros in the scaled disc. Let me look at LiDisc.lean more carefully. Actually, `nearZeros t = (zeroDiscFinset t).filter (|ρ.im − t| < 1)`. And zeroDisc_isNontrivial says elements are nontrivial zeros. So for the reflection cancellation, I need: 1. A finset map: nearZeros(−t) is in bijection with nearZeros(t) via ρ ↦ 1−ρ. Wait — but careful: nearZeros(t) elements have im near t; 1−ρ has im = −im(ρ) near −t. So ρ′ = 1−ρ ∈ nearZeros(−t)? We need ρ′ ∈ zeroDiscFinset(−t) AND |im(ρ′) − (−t)| < 1. zeroDiscFinset(−t) = zeros in disc B(2−it, 5/2) presumably (discCenter (−t) = 2 − it). If ρ ∈ B(2+it, 5/2), is 1−ρ ∈ B(2−it, 5/2)? |1−ρ − (2−it)| = |−1−ρ+it| = |ρ + 1 − it|. Hmm, |ρ − (2+it)| vs |ρ + 1 − it|. These aren't equal in general. E.g., ρ = 0.5 + it: |ρ−(2+it)| = 1.5; |1−ρ−(2−it)| = |−1.5| wait: 1−ρ = 0.5−it, 1−ρ−(2−it) = −1.5. |−1.5| = 1.5. OK equal in that case. In general: |1−ρ−(2−it)|² = |(−1−re ρ) + i(t − im ρ)|² = (1+re ρ)² + (t−im ρ)². And |ρ−(2+it)|² = (re ρ −2)² + (im ρ − t)². Difference: (1+re)² − (re−2)² = (1 + 2re + re²) − (re² −4re + 4) = 6re − 3. For re ∈ (0,1), this ranges in (−3, 3). So 1−ρ may NOT be in the disc B(2−it, 5/2) even if ρ ∈ B(2+it, 5/2). E.g., ρ with re ≈ 1, im = t: |ρ−center|² = 1, |1−ρ−center'|² = 4 > 1. Still < 6.25 so inside the disc of radius 2.5? (1+1)² = 4 < 6.25. Hmm, actually max: (1+re ρ)² + (t−im ρ)² with re ≤ 1, |t − im ρ|... For nearZeros, |im ρ − t| < 1, so |1−ρ−(2−it)|² ≤ 4 + 1 = 5 < 6.25. OK so the nearZeros elements DO land in zeroDiscFinset(−t) after reflection, IF zeroDiscFinset(−t) contains ALL zeros in B(2−it, 5/2) (radius squared 6.25 ≥ 5 ✓). But wait — is zeroDiscFinset(t) = ALL zeros of ζ in the closed/open disc B(2+it, 5/2)? I need to check its definition. Let me look at LiDisc.lean around line 970 and the zeroDiscFinset definition. Actually, let me now read the relevant sections of LiDisc.lean in detail. The file is 1361 lines. Let me read the key parts: header/imports, zeroDiscFinset definition, nearZeros, and the capstone theorem.
Zeta23 has all the reflection seams. Now let me read the key parts of LiDisc.lean.
tool: Read
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[{"type":"thinking","thinking":"Excellent. Zeta23 has everything:\n- `analyticOrderAt_zeta_one_sub` (order transport through FE for 0 < re < 1)\n- `zeta_mult_reflect`: zeroMult (reflect ρ) = zeroMult ρ for nontrivial zeros, where `reflect ρ = 1 - conj ρ`.\n\nHmm — note: `reflect ρ = 1 - conj ρ`. The FE symmetry I need for ii′-5d is ρ′ = 1 − ρ (not 1 − conj ρ). Let me think about what exactly the zero-sum cancellation needs.\n\nThe two sums in D-067 §3:\n- Σ_{|γ−t|<1} m/(s−ρ) (the nearZeros(t) sum at s)\n- Σ_{|γ′+t|<1} m′/(1−s−ρ′) (the nearZeros(−t) sum at 1−s)\n\nClaim: these cancel exactly. The map is ρ ↦ 1 − ρ. If ρ is a nontrivial zero with im ρ near t, then 1 − ρ is a zero with im(1−ρ) = −im ρ near −t. And 1−s−(1−ρ) = −(s−ρ), so m/(1−s−ρ′) = −m/(s−ρ).\n\nSo the needed map is ρ ↦ 1 − ρ (NOT the conjugated reflect). Does Zeta23 have zeroMult (1 − ρ) = zeroMult ρ? \n\nFrom `analyticOrderAt_zeta_one_sub`: for 0 < re w < 1, analyticOrderAt ζ (1−w) = analyticOrderAt ζ w. That directly gives zeroMult (1−ρ) = zeroMult ρ for nontrivial zeros ρ (0 < re ρ < 1). Let me check the exact statement at line 224.\n\nAlso, is 1−ρ a nontrivial zero when ρ is? If ρ = β+iγ is a zero with 0<β<1, then 1−ρ = (1−β)−iγ: ζ(1−ρ) = 0 by the order transport (order ≥ 1 preserved), 0 < 1−β < 1. So yes — IsNontrivialZero (1−ρ).\n\nLet me check: the nearZeros finset is defined via `zeroDiscFinset t` filtered by |ρ.im − t| < 1. What is zeroDiscFinset? From journal-023: \"zeroDiscFinset + zeroDisc_isNontrivial (re ≥ 1 via Mathlib's one_le_re nonvanishing; re ≤ 0 via ΓR-pole/FE)\". So zeroDiscFinset t contains the zeros of ζ in the disc B(2+it, 5/2)... wait actually let me re-read.\n\nFrom the journal: zeroDiscFinset — the zeros in the scaled disc. Let me look at LiDisc.lean more carefully. Actually, `nearZeros t = (zeroDiscFinset t).filter (|ρ.im − t| < 1)`. And zeroDisc_isNontrivial says elements are nontrivial zeros.\n\nSo for the reflection cancellation, I need:\n1. A finset map: nearZeros(−t) is in bijection with nearZeros(t) via ρ ↦ 1−ρ. \n\nWait — but careful: nearZeros(t) elements have im near t; 1−ρ has im = −im(ρ) near −t. So ρ′ = 1−ρ ∈ nearZeros(−t)? We need ρ′ ∈ zeroDiscFinset(−t) AND |im(ρ′) − (−t)| < 1.\n\nzeroDiscFinset(−t) = zeros in disc B(2−it, 5/2) presumably (discCenter (−t) = 2 − it). If ρ ∈ B(2+it, 5/2), is 1−ρ ∈ B(2−it, 5/2)? |1−ρ − (2−it)| = |−1−ρ+it| = |ρ + 1 − it|. Hmm, |ρ − (2+it)| vs |ρ + 1 − it|. These aren't equal in general. E.g., ρ = 0.5 + it: |ρ−(2+it)| = 1.5; |1−ρ−(2−it)| = |−1.5| wait: 1−ρ = 0.5−it, 1−ρ−(2−it) = −1.5. |−1.5| = 1.5. OK equal in that case. In general: |1−ρ−(2−it)|² = |(−1−re ρ) + i(t − im ρ)|² = (1+re ρ)² + (t−im ρ)². And |ρ−(2+it)|² = (re ρ −2)² + (im ρ − t)². Difference: (1+re)² − (re−2)² = (1 + 2re + re²) − (re² −4re + 4) = 6re − 3. For re ∈ (0,1), this ranges in (−3, 3). So 1−ρ may NOT be in the disc B(2−it, 5/2) even if ρ ∈ B(2+it, 5/2). E.g., ρ with re ≈ 1, im = t: |ρ−center|² = 1, |1−ρ−center'|² = 4 > 1. Still < 6.25 so inside the disc of radius 2.5? (1+1)² = 4 < 6.25. Hmm, actually max: (1+re ρ)² + (t−im ρ)² with re ≤ 1, |t − im ρ|... For nearZeros, |im ρ − t| < 1, so |1−ρ−(2−it)|² ≤ 4 + 1 = 5 < 6.25. OK so the nearZeros elements DO land in zeroDiscFinset(−t) after reflection, IF zeroDiscFinset(−t) contains ALL zeros in B(2−it, 5/2) (radius squared 6.25 ≥ 5 ✓).\n\nBut wait — is zeroDiscFinset(t) = ALL zeros of ζ in the closed/open disc B(2+it, 5/2)? I need to check its definition. Let me look at LiDisc.lean around line 970 and the zeroDiscFinset definition.\n\nActually, let me now read the relevant sections of LiDisc.lean in detail. The file is 1361 lines. Let me read the key parts: header/imports, zeroDiscFinset definition, nearZeros, and the capstone theorem.","signature":""},{"type":"text","text":"Zeta23 has all the reflection seams. Now let me read the key parts of LiDisc.lean."},{"type":"tool_use","id":"Read_16","name":"Read","input":{"file_path":"D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiDisc.lean","limit":120},"extra_content":null}]