← Session 28 — ii′-5e: partial-fraction identity (zero series + F entire)
thinking (4408 chars)
With hle1 stubbed by sorry, the parse works AND we reach the real final goal — the parse error was INSIDE hle1's proof (the calc block structure). And now the final linarith fails to close the goal — a REAL error to fix:
Goal: ↑(Ncount a (a+↑N)) + ↑(Ncount (a+↑N)(a+↑N+1)) ≤ A₀(↑N+1)·log(|a|+(↑N+1)+3), with:
- ih : ↑(Ncount a (a+↑N)) ≤ A₀·↑N·log(|a|+↑N+3)
- hwin : ↑(Ncount (a+↑N)(a+↑N+1)) ≤ A₀·log(|a+↑N|+3)
- hle1 : A₀·↑N·log(|a|+↑N+3) ≤ A₀·(↑N+1)·log(|a|+(↑N+1)+3)
- hle2 : A₀·log(|a+↑N|+3) ≤ A₀·log(|a|+(↑N+1)+3)
linarith treats A₀·↑N·log(...) as products of TWO unknowns times... — A₀·↑N·log X is a product of THREE atoms (A₀, ↑N, log X) — linarith only handles LINEAR terms: products of atoms are treated as single atoms IF they appear identically. LHS: ↑(Ncount...) + ↑(Ncount...) — atoms ↑(...) fine. The products: A₀*↑N*log A vs A₀*(↑N+1)*log C — DIFFERENT monomials — linarith CAN'T derive the combination because it needs: A₀·N·logA ≤ A₀·N·logC (hle1-component) etc. — linarith does NOT multiply hypotheses. The chain I need: LHS ≤ A₀·N·logA + A₀·logB ≤ A₀·N·logC + A₀·logC = A₀(N+1)·logC. The last step A₀·N·logC + A₀·logC = A₀(N+1)·logC is ring (linear in the monomial atoms (A₀·logC)·N + A₀·logC·1... — as monomials: N·(A₀·logC) vs (A₀(N+1))·logC — ring_nf normalizes: A₀·N·logC + A₀·logC vs A₀·(N+1)·logC: the difference: A₀·logC·(N+1 − N − 1) = 0 ✓ ring_nf proves the equality of these polynomials in atoms {A₀, N, logC} ✓ so linarith with the monomial-atoms should work IF it normalizes. The failure says the atom-matching broke somewhere: hle1's RHS `A0count * (↑N + 1) * Real.log (|a| + (↑N + 1) + 3)` vs the goal's RHS — same string ✓. hle2's RHS `A0count * Real.log (|a| + (↑N + 1) + 3)` — the goal has `A0count * (↑N + 1) * Real.log (...)` — the combinations: goal-RHS − [N·(A₀·logC) + 1·(A₀·logC)] — linarith's ring normalization should handle. Why did it fail? Maybe because hwin's LHS and the goal's `↑(Ncount (a + ↑N) (a + ↑N + 1))` match ✓, ih's match ✓... The failure "linarith failed to find a contradiction" on the negated goal — let me just feed it more explicitly: provide hsum : ↑(Ncount a (a+↑N)) + ↑(Ncount (a+↑N)(a+↑N+1)) ≤ A₀·↑N·log(|a|+↑N+3) + A₀·log(|a+↑N|+3) := add_le_add ih hwin — then nlinarith/linarith [hsum, hle1, hle2]:
goal: LHS ≤ A₀(N+1)logC: from hsum: LHS ≤ A₀N·logA + A₀·logB; hle1: A₀N·logA ≤ A₀(N+1)logC; hle2: A₀·logB ≤ A₀·logC — sum: LHS ≤ A₀(N+1)logC + A₀·logC — that's A₀(N+2)logC — TOO MUCH by A₀·logC!! My hle1 was too generous. Redo the arithmetic properly:
A₀·N·logA + A₀·logB ≤ A₀·N·logC + A₀·logC = A₀·(N+1)·logC ✓ — I need A₀·N·logA ≤ A₀·N·logC (not the (N+1) version!). So hle1 should be: A₀·N·log(|a|+N+3) ≤ A₀·N·log(|a|+(N+1)+3) (mul_le_mul_of_nonneg_left (log-le) (A₀N ≥ 0)) and hle2: A₀·logB ≤ A₀·logC ✓ then add: A₀N·logC + A₀·logC = A₀(N+1)·logC ✓ ring-equal. So the assembly:
```lean
have h1 : ↑(Ncount a (a + ↑N)) + ↑(Ncount (a + ↑N) (a + ↑N + 1))
≤ A0count * ↑N * Real.log (|a| + ↑N + 3) + A0count * Real.log (|a + ↑N| + 3) :=
add_le_add ih hwin
have h2 : A0count * ↑N * Real.log (|a| + ↑N + 3)
≤ A0count * ↑N * Real.log (|a| + (↑N + 1) + 3) :=
mul_le_mul_of_nonneg_left hlogC (mul_nonneg A0count_pos.le hN0) -- hlogC : log(|a|+N+3) ≤ log(|a|+(N+1)+3)
have h3 : A0count * Real.log (|a + ↑N| + 3)
≤ A0count * Real.log (|a| + (↑N + 1) + 3) := hle2 (keep)
-- final: linarith [h1, h2, h3] — atoms: A₀·N·logA, A₀·logB, A₀·N·logC, A₀·logC, A₀(N+1)logC:
-- from h1,h2,h3: LHS ≤ A₀N·logC + A₀·logC; goal RHS = A₀(N+1)·logC: the equality A₀N·logC + A₀·logC = A₀(N+1)·logC needs ring-normalization across the products: linarith's preprocessing ring_nf should manage (atoms A₀, N, logC: LHS-combo A₀*N*logC + A₀*logC vs RHS A₀*(N+1)*logC — both normalize to the same polynomial ✓ linarith closes).
linarith [h1, h2, h3]
```
where hlogC : Real.log (|a| + ↑N + 3) ≤ Real.log (|a| + (↑N+1) + 3) := Real.log_le_log (by positivity) (by linarith) — that's h2's inner fact (h2 in the old hle1) ✓.
So hle1's whole calc was unnecessary (I over-proved A₀(N+1)logC bound) — replace hle1 with the direct h2. AND the parse error was inside hle1's calc — with it removed, parse is fine. What WAS the parse error? Probably the calc's `:= by` inner block at indent-12 inside the case — whatever; removing it entirely is the fix. Let me restore the backup and rewrite the succ-case tail cleanly.
Found it — hle1's nested `calc ... := by` block broke the parse, and the final linarith needs the tighter `A₀·N·logC` step anyway. Rewriting the succ-case tail.
tool: Bash
input
{
"command": "cd D:/Python/Quantum/research/lean/NguyenRH1 && cp /tmp/LiCircleBound.bak NguyenRH1/LiCircleBound.lean && python - << 'PYEOF'\np = 'NguyenRH1/LiCircleBound.lean'\nsrc = open(p, encoding='utf-8').read()\nstart = src.index(' have hle1 :')\nend = src.index(' linarith [ih, hwin, hle1, hle2]') + len(' linarith [ih, hwin, hle1, hle2]')\nnew_tail = ''' have hlogC : Real.log (|a| + (N : \u211d) + 3)\n \u2264 Real.log (|a| + ((N : \u211d) + 1) + 3) :=\n Real.log_le_log (by positivity) (by linarith)\n have hle1 : A0count * (N : \u211d) * Real.log (|a| + (N : \u211d) + 3)\n \u2264 A0count * (N : \u211d) * Real.log (|a| + ((N : \u211d) + 1) + 3) :=\n mul_le_mul_of_nonneg_left hlogC (mul_nonneg A0count_pos.le hN0)\n have hle2 : A0count * Real.log (|a + (N : \u211d)| + 3)\n \u2264 A0count * Real.log (|a| + ((N : \u211d) + 1) + 3) := by\n apply mul_le_mul_of_nonneg_left _ A0count_pos.le\n apply Real.log_le_log (by positivity)\n have h1 : |a + (N : \u211d)| \u2264 |a| + (N : \u211d) :=\n (abs_add_le _ _).trans (by rw [abs_of_nonneg (show (0 : \u211d) \u2264 (N : \u211d) from Nat.cast_nonneg N)])\n linarith\n have hsum : \u2191(Zeta23.Ncount a (a + (N : \u211d))) + \u2191(Zeta23.Ncount (a + (N : \u211d)) (a + (N : \u211d) + 1))\n \u2264 A0count * (N : \u211d) * Real.log (|a| + (N : \u211d) + 3)\n + A0count * Real.log (|a + (N : \u211d)| + 3) :=\n add_le_add ih hwin\n linarith [hsum, hle1, hle2]'''\nsrc = src[:start] + new_tail + src[end:]\nopen(p, 'w', encoding='utf-8').write(src)\nprint('rewritten')\nPYEOF\nexport PATH=\"$HOME/.elan/bin:$PATH\" && lake env lean NguyenRH1/LiCircleBound.lean 2>&1 | head -30",
"description": "Rewrite the succ-case tail and compile",
"timeout": 600000
}
raw content_json (database row)
[{"type":"thinking","thinking":"With hle1 stubbed by sorry, the parse works AND we reach the real final goal — the parse error was INSIDE hle1's proof (the calc block structure). And now the final linarith fails to close the goal — a REAL error to fix:\n\nGoal: ↑(Ncount a (a+↑N)) + ↑(Ncount (a+↑N)(a+↑N+1)) ≤ A₀(↑N+1)·log(|a|+(↑N+1)+3), with:\n- ih : ↑(Ncount a (a+↑N)) ≤ A₀·↑N·log(|a|+↑N+3)\n- hwin : ↑(Ncount (a+↑N)(a+↑N+1)) ≤ A₀·log(|a+↑N|+3)\n- hle1 : A₀·↑N·log(|a|+↑N+3) ≤ A₀·(↑N+1)·log(|a|+(↑N+1)+3)\n- hle2 : A₀·log(|a+↑N|+3) ≤ A₀·log(|a|+(↑N+1)+3)\n\nlinarith treats A₀·↑N·log(...) as products of TWO unknowns times... — A₀·↑N·log X is a product of THREE atoms (A₀, ↑N, log X) — linarith only handles LINEAR terms: products of atoms are treated as single atoms IF they appear identically. LHS: ↑(Ncount...) + ↑(Ncount...) — atoms ↑(...) fine. The products: A₀*↑N*log A vs A₀*(↑N+1)*log C — DIFFERENT monomials — linarith CAN'T derive the combination because it needs: A₀·N·logA ≤ A₀·N·logC (hle1-component) etc. — linarith does NOT multiply hypotheses. The chain I need: LHS ≤ A₀·N·logA + A₀·logB ≤ A₀·N·logC + A₀·logC = A₀(N+1)·logC. The last step A₀·N·logC + A₀·logC = A₀(N+1)·logC is ring (linear in the monomial atoms (A₀·logC)·N + A₀·logC·1... — as monomials: N·(A₀·logC) vs (A₀(N+1))·logC — ring_nf normalizes: A₀·N·logC + A₀·logC vs A₀·(N+1)·logC: the difference: A₀·logC·(N+1 − N − 1) = 0 ✓ ring_nf proves the equality of these polynomials in atoms {A₀, N, logC} ✓ so linarith with the monomial-atoms should work IF it normalizes. The failure says the atom-matching broke somewhere: hle1's RHS `A0count * (↑N + 1) * Real.log (|a| + (↑N + 1) + 3)` vs the goal's RHS — same string ✓. hle2's RHS `A0count * Real.log (|a| + (↑N + 1) + 3)` — the goal has `A0count * (↑N + 1) * Real.log (...)` — the combinations: goal-RHS − [N·(A₀·logC) + 1·(A₀·logC)] — linarith's ring normalization should handle. Why did it fail? Maybe because hwin's LHS and the goal's `↑(Ncount (a + ↑N) (a + ↑N + 1))` match ✓, ih's match ✓... The failure \"linarith failed to find a contradiction\" on the negated goal — let me just feed it more explicitly: provide hsum : ↑(Ncount a (a+↑N)) + ↑(Ncount (a+↑N)(a+↑N+1)) ≤ A₀·↑N·log(|a|+↑N+3) + A₀·log(|a+↑N|+3) := add_le_add ih hwin — then nlinarith/linarith [hsum, hle1, hle2]:\ngoal: LHS ≤ A₀(N+1)logC: from hsum: LHS ≤ A₀N·logA + A₀·logB; hle1: A₀N·logA ≤ A₀(N+1)logC; hle2: A₀·logB ≤ A₀·logC — sum: LHS ≤ A₀(N+1)logC + A₀·logC — that's A₀(N+2)logC — TOO MUCH by A₀·logC!! My hle1 was too generous. Redo the arithmetic properly:\nA₀·N·logA + A₀·logB ≤ A₀·N·logC + A₀·logC = A₀·(N+1)·logC ✓ — I need A₀·N·logA ≤ A₀·N·logC (not the (N+1) version!). So hle1 should be: A₀·N·log(|a|+N+3) ≤ A₀·N·log(|a|+(N+1)+3) (mul_le_mul_of_nonneg_left (log-le) (A₀N ≥ 0)) and hle2: A₀·logB ≤ A₀·logC ✓ then add: A₀N·logC + A₀·logC = A₀(N+1)·logC ✓ ring-equal. So the assembly: \n```lean\n have h1 : ↑(Ncount a (a + ↑N)) + ↑(Ncount (a + ↑N) (a + ↑N + 1))\n ≤ A0count * ↑N * Real.log (|a| + ↑N + 3) + A0count * Real.log (|a + ↑N| + 3) :=\n add_le_add ih hwin\n have h2 : A0count * ↑N * Real.log (|a| + ↑N + 3)\n ≤ A0count * ↑N * Real.log (|a| + (↑N + 1) + 3) :=\n mul_le_mul_of_nonneg_left hlogC (mul_nonneg A0count_pos.le hN0) -- hlogC : log(|a|+N+3) ≤ log(|a|+(N+1)+3)\n have h3 : A0count * Real.log (|a + ↑N| + 3)\n ≤ A0count * Real.log (|a| + (↑N + 1) + 3) := hle2 (keep)\n -- final: linarith [h1, h2, h3] — atoms: A₀·N·logA, A₀·logB, A₀·N·logC, A₀·logC, A₀(N+1)logC:\n -- from h1,h2,h3: LHS ≤ A₀N·logC + A₀·logC; goal RHS = A₀(N+1)·logC: the equality A₀N·logC + A₀·logC = A₀(N+1)·logC needs ring-normalization across the products: linarith's preprocessing ring_nf should manage (atoms A₀, N, logC: LHS-combo A₀*N*logC + A₀*logC vs RHS A₀*(N+1)*logC — both normalize to the same polynomial ✓ linarith closes).\n linarith [h1, h2, h3]\n```\nwhere hlogC : Real.log (|a| + ↑N + 3) ≤ Real.log (|a| + (↑N+1) + 3) := Real.log_le_log (by positivity) (by linarith) — that's h2's inner fact (h2 in the old hle1) ✓.\n\nSo hle1's whole calc was unnecessary (I over-proved A₀(N+1)logC bound) — replace hle1 with the direct h2. AND the parse error was inside hle1's calc — with it removed, parse is fine. What WAS the parse error? Probably the calc's `:= by` inner block at indent-12 inside the case — whatever; removing it entirely is the fix. Let me restore the backup and rewrite the succ-case tail cleanly.","signature":""},{"type":"text","text":"Found it — hle1's nested `calc ... := by` block broke the parse, and the final linarith needs the tighter `A₀·N·logC` step anyway. Rewriting the succ-case tail."},{"type":"tool_use","id":"Bash_295","name":"Bash","input":{"command":"cd D:/Python/Quantum/research/lean/NguyenRH1 && cp /tmp/LiCircleBound.bak NguyenRH1/LiCircleBound.lean && python - << 'PYEOF'\np = 'NguyenRH1/LiCircleBound.lean'\nsrc = open(p, encoding='utf-8').read()\nstart = src.index(' have hle1 :')\nend = src.index(' linarith [ih, hwin, hle1, hle2]') + len(' linarith [ih, hwin, hle1, hle2]')\nnew_tail = ''' have hlogC : Real.log (|a| + (N : ℝ) + 3)\n ≤ Real.log (|a| + ((N : ℝ) + 1) + 3) :=\n Real.log_le_log (by positivity) (by linarith)\n have hle1 : A0count * (N : ℝ) * Real.log (|a| + (N : ℝ) + 3)\n ≤ A0count * (N : ℝ) * Real.log (|a| + ((N : ℝ) + 1) + 3) :=\n mul_le_mul_of_nonneg_left hlogC (mul_nonneg A0count_pos.le hN0)\n have hle2 : A0count * Real.log (|a + (N : ℝ)| + 3)\n ≤ A0count * Real.log (|a| + ((N : ℝ) + 1) + 3) := by\n apply mul_le_mul_of_nonneg_left _ A0count_pos.le\n apply Real.log_le_log (by positivity)\n have h1 : |a + (N : ℝ)| ≤ |a| + (N : ℝ) :=\n (abs_add_le _ _).trans (by rw [abs_of_nonneg (show (0 : ℝ) ≤ (N : ℝ) from Nat.cast_nonneg N)])\n linarith\n have hsum : ↑(Zeta23.Ncount a (a + (N : ℝ))) + ↑(Zeta23.Ncount (a + (N : ℝ)) (a + (N : ℝ) + 1))\n ≤ A0count * (N : ℝ) * Real.log (|a| + (N : ℝ) + 3)\n + A0count * Real.log (|a + (N : ℝ)| + 3) :=\n add_le_add ih hwin\n linarith [hsum, hle1, hle2]'''\nsrc = src[:start] + new_tail + src[end:]\nopen(p, 'w', encoding='utf-8').write(src)\nprint('rewritten')\nPYEOF\nexport PATH=\"$HOME/.elan/bin:$PATH\" && lake env lean NguyenRH1/LiCircleBound.lean 2>&1 | head -30","description":"Rewrite the succ-case tail and compile","timeout":600000},"extra_content":null}]