← Session 31 — ii′-5f: tight R-bound 10.5/48 (piece 3 + pinch)
thinking (17855 chars)
- `zeroMult ρ := (analyticOrderAt riemannZeta ρ).toNat` (Zeta23 Statement.lean) ✓.
- `AnalyticAt.deriv : AnalyticAt 𝕜 f x → AnalyticAt 𝕜 (deriv f) x` ✓ — so AnalyticAt (iteratedDeriv n f) via iteration or there might be AnalyticAt.iteratedDeriv: let me just use induction: analyticAt_riemannZeta hz, .deriv, .deriv.deriv... via a recursive have:
```
have han : ∀ n : ℕ, AnalyticAt ℂ (iteratedDeriv n riemannZeta) z := by
intro n
induction n with
| zero => exact analyticAt_riemannZeta hz
| succ n ih =>
rw [iteratedDeriv_succ]
exact ih.deriv
```
Need analyticAt_riemannZeta : z ≠ 1 → AnalyticAt ℂ riemannZeta z — used in LiContour's one_le_zeroMult as `analyticAt_riemannZeta hρ1` ✓.
- The conj-deriv lemma: I need for f = iteratedDeriv n ζ: DifferentiableAt ℂ f z and the conj identity. The differentiability: AnalyticAt.differentiableAt ✓.
Now — the conj-deriv lemma's tendsto composition. Let me write it carefully:
```
lemma hasDerivAt_conj_of_conj_eq {f : ℂ → ℂ} {z : ℂ}
(hconj : ∀ s : ℂ, f ((starRingEnd ℂ) s) = (starRingEnd ℂ) (f s))
(hdiff : DifferentiableAt ℂ f z) :
HasDerivAt f ((starRingEnd ℂ) (deriv f z)) ((starRingEnd ℂ) z) := by
rw [hasDerivAt_iff_tendsto] at hdiff ⊢
-- hdiff.hasDerivAt : HasDerivAt f (deriv f z) z — DifferentiableAt.hasDerivAt ✓
have h1 : Filter.Tendsto (fun x : ℂ => (f x - f z) / (x - z)) (𝓝[≠] z)
(𝓝 (deriv f z)) :=
hasDerivAt_iff_tendsto.mp hdiff.hasDerivAt
have h2 : Filter.Tendsto (fun x : ℂ =>
(starRingEnd ℂ) ((f ((starRingEnd ℂ) x) - f z) / (((starRingEnd ℂ) x) - z)))
(𝓝[≠] ((starRingEnd ℂ) z)) (𝓝 ((starRingEnd ℂ) (deriv f z))) := by
have hconjcont : Filter.Tendsto (starRingEnd ℂ) (𝓝 (deriv f z))
(𝓝 ((starRingEnd ℂ) (deriv f z))) :=
(starRingEnd_continuous).tendsto _
have hmap : Filter.Tendsto (starRingEnd ℂ) (𝓝[≠] ((starRingEnd ℂ) z)) (𝓝[≠] z) := by
apply (starRingEnd_continuous).tendsto_nhdsWithin_punctured? ...
exact hconjcont.comp (h1.comp hmap)
-- the function in h2 equals the slope of f at conj z
...
```
Concerns:
- `DifferentiableAt.hasDerivAt : DifferentiableAt f z → HasDerivAt f (deriv f z) z` ✓ exists.
- `hasDerivAt_iff_tendsto : HasDerivAt f f' x ↔ Tendsto (fun x' => (f x' − f x)/(x'−x)) (𝓝[≠] x) (𝓝 f')` — check name: might be `hasDerivAt_iff_tendsto : HasDerivAt f f' x ↔ Tendsto (fun x' => x' − x ... )` — there are variants (slope vs difference quotient): `hasDerivAt_iff_tendsto : HasDerivAt f f' x ↔ Tendsto (fun x' => (f x' - f x) / (x' - x)) (𝓝[≠] x) (𝓝 f')` — I believe this exists with that exact form.
- Tendsto of conj into 𝓝[≠]: `(starRingEnd_continuous).tendsto z : Tendsto conj (𝓝 z) (𝓝 (conj z))`; for punctured: `Tendsto.inf` with the mapsTo: conj maps {x : x ≠ conj z} into {u : u ≠ z} (conj x ≠ z ⟺ x ≠ conj z: (starRingEnd ℂ).injective.ne_iff + conj_conj). There's `ContinuousAt.tendsto_punctured_nhds`? Let me search: `tendsto_nhdsWithin_of_tendsto`? The punctured version: Tendsto f (𝓝[≠] a) (𝓝[≠] b) from Tendsto f (𝓝 a) (𝓝 b) + (∀ x ≠ a, f x ≠ b):
```
have hmap : Filter.Tendsto (starRingEnd ℂ) (𝓝[≠] ((starRingEnd ℂ) z)) (𝓝[≠] z) := by
rw [Filter.tendsto_nhdsWithin_iff]
refine ⟨(starRingEndContinuous.tendsto _).mono_left nhdsWithin_le_nhds, ?_⟩
rw [Filter.eventually_nhdsWithin_iff]
exact Filter.Eventually.of_forall (fun x hx => by
intro hbad
-- conj x = z ⟹ x = conj z (apply conj, conj_conj) — contradiction with hx
have : x = (starRingEnd ℂ) z := by
have h3 := congrArg (starRingEnd ℂ) hbad
rwa [RingHom.apply_apply, ...] at h3 -- conj (conj x) = x
exact hx this)
```
starRingEnd_continuous: `starRingEnd_continuous : Continuous (starRingEnd ℂ)`? There's `Complex.continuous_conj : Continuous conj` — and (starRingEnd ℂ) as a function: continuous_starRingEnd? The name: `continuous_starRingEnd`? Hmm — safer: `Complex.continuous_conj : Continuous Complex.conj` and (starRingEnd ℂ) x = conj x by rfl (starRingEnd_apply: (starRingEnd ℂ) x = conj x ✓ simp lemma). Use Complex.conj directly?? — the isNontrivialZero_conj and other lemmas use (starRingEnd ℂ). The statement of riemannZeta_conj: `riemannZeta ((starRingEnd ℂ) s) = (starRingEnd ℂ) (riemannZeta s)` — from the isNontrivialZero_conj usage: `rw [_root_.riemannZeta_conj, hρ.1, map_zero]` — map_zero applies to the starRingEnd — so the identity is with (starRingEnd ℂ). And (starRingEnd ℂ) x = Complex.conj x — `starRingEnd_apply` simp.
For continuity: `continuous_starRingEnd`? Let me just use: (Complex.continuous_conj : Continuous conj) with the starRingEnd_apply bridges, or check `starRingEnd_continuous` exists — grep later.
The injectivity: (starRingEnd ℂ).injective : Function.Injective (starRingEnd ℂ) — RingHom.injective? For ring equivs: `(starRingEnd ℂ).injective` should work (it's a RingEquiv — `(starRingEnd ℂ) : ℂ ≃+* ℂ`? starRingEnd : R ≃+* R for commutative R ✓ so .injective ✓). And conj_conj: `(starRingEnd ℂ) ((starRingEnd ℂ) x) = x` — `starRingEnd_self_apply` simp lemma ✓.
- The final slope identity: the function in h2 at x (≠ conj z): conj((f(conj x) − f z)/((conj x) − z)) — via hconj: f(conj x) = conj(f x): = conj((conj(f x) − f z)/((conj x) − z)) = conj(conj((f x − f (conj z))/(x − conj z)))·... let me redo: (f(conj x) − f z)/((conj x) − z) where the OUTER conj is applied after: conj([f(conj x) − f z]/[(conj x) − z]) = [conj(f(conj x)) − conj(f z)]/[conj(conj x) − conj z] (conj_div, conj_sub) = [f x − f(conj z)]/[x − conj z] (hconj: conj(f(conj x)) = f x? — from hconj: f(conj s) = conj(f s) ⟹ conj(f(conj x)) = conj(conj(f x)) = f x ✓; conj(f z) = f(conj z) ✓ by hconj at z; conj(conj x) = x ✓; conj z = conj z ✓). So the h2-function = the slope of f at conj z ✓ pointwise on 𝓝[≠] (conj z).
Then h2 + the pointwise identity (eventually near conj z — actually EVERYWHERE ✓) ⟹ Tendsto (slope at conj z) (𝓝[≠] (conj z)) (𝓝 (conj (deriv f z))) ⟹ HasDerivAt via hasDerivAt_iff_tendsto.mpr — with the function equality: the slope-function might differ SYNTACTICALLY from h2's function — need EventuallyEq: show the two functions equal at all x (any x, no neighborhood needed):
```
have h3 : (fun x : ℂ => (starRingEnd ℂ) ((f ((starRingEnd ℂ) x) - f z) / (((starRingEnd ℂ) x) - z)))
= fun x : ℂ => (f x - f ((starRingEnd ℂ) z)) / (x - (starRingEnd ℂ) z) := by
funext x
rw [hconj x, hconj z]
simp [map_sub, map_div₀, starRingEnd_self_apply, map_zero...]
rw [h3] at h2
exact hasDerivAt_iff_tendsto.mpr h2
```
The simp: conj((conj(f x) − conj(f z))/(conj(conj x) − conj z)): conj_div: conj(a/b) = conj a/conj b (map_div₀ (starRingEnd ℂ)); conj_sub (map_sub); starRingEnd_self_apply: conj(conj x) = x. Result: (f x − f(conj z))/(x − conj z) ✓ — as long as hconj x rewrites f(conj x) → conj(f x) first. Order: rw [hconj x, hconj z] turns f(conj x) → conj(f x) and f(conj z) → conj(f z)?? WAIT — the h2-function has f((starRingEnd ℂ) x) — rw [hconj x] : f((starRingEnd ℂ) x) → (starRingEnd ℂ)(f x) ✓. But it ALSO has f z and f((starRingEnd ℂ) z)... only in the OUTER target. The h2 function: conj((f(conj x) − f z)/((conj x) − z)): inner f(conj x) → conj(f x) via hconj x ✓. Then conj((conj(f x) − f z)/(conj x − z)): map_div₀, map_sub: (conj(conj(f x)) − conj(f z))/(conj(conj x) − conj z) = (f x − conj(f z))/(x − conj z) — then conj(f z) = f(conj z) via hconj z reversed: hconj z : f(conj z) = conj(f z) — rw [← hconj z]: conj(f z) → f(conj z) ✓. So: funext x; rw [hconj x]; simp only [map_div₀, map_sub, starRingEnd_self_apply]; rw [← hconj z]. Hmm — map_div₀ needs the RingHom form: (starRingEnd ℂ) (a/b) = (starRingEnd ℂ) a / (starRingEnd ℂ) b — `map_div₀ (starRingEnd ℂ)`? or `map_div (starRingEnd ℂ)`? — simp should have these tagged for RingHom: map_div₀, map_sub, map_zero are simp lemmas for ring homs ✓; starRingEnd_self_apply is simp ✓. So: funext x; rw [hconj x, ← hconj z]; simp [map_div₀, map_sub, starRingEnd_self_apply]. Careful: after rw [hconj x, ← hconj z], the function is conj((conj(f x) − f(conj z))/(conj x − conj z))... wait the ← hconj z rewrites conj(f z) → f(conj z) — but at this point the term conj(f z) hasn't appeared yet (it's inside the outer conj). Order: rw [hconj x] first: f(conj x) → conj(f x). Now: conj((conj(f x) − f z)/(conj x − z)). simp [map_div₀, map_sub, starRingEnd_self_apply]: conj(a/b) → conj(a)/conj(b); conj(a−b) → conj(a)−conj(b); conj(conj u) → u: gives (f x − conj(f z))/(x − conj z). Then rw [← hconj z]: conj(f z) → f(conj z) ✓ final (f x − f(conj z))/(x − conj z) ✓.
OK. And the induction lemma:
```
lemma iteratedDeriv_riemannZeta_conj (n : ℕ) {z : ℂ} (hz : z ≠ 1) :
iteratedDeriv n riemannZeta ((starRingEnd ℂ) z)
= (starRingEnd ℂ) (iteratedDeriv n riemannZeta z) := by
induction n generalizing z with
| zero =>
rw [iteratedDeriv_zero, iteratedDeriv_zero]
exact riemannZeta_conj z
| succ n ih =>
rw [iteratedDeriv_succ, iteratedDeriv_succ]
-- deriv (itD n ζ) (conj z) = conj (deriv (itD n ζ) z)
have hconj : ∀ s : ℂ, iteratedDeriv n riemannZeta ((starRingEnd ℂ) s)
= (starRingEnd ℂ) (iteratedDeriv n riemannZeta s) := by
intro s
by_cases hs : s = 1
· rw [hs]
simp -- at s = 1: conj 1 = 1; itD n ζ 1 vs conj (itD n ζ 1): both junk?
· exact ih hs
have hd : DifferentiableAt ℂ (iteratedDeriv n riemannZeta) z :=
(analyticAt_iteratedDeriv n hz).differentiableAt
exact (hasDerivAt_conj_of_conj_eq hconj hd).deriv
```
The s = 1 case of hconj: iteratedDeriv n ζ (conj 1) = conj (iteratedDeriv n ζ 1): conj 1 = 1 (map_one): both sides = itD n ζ 1: LHS itD n ζ 1, RHS conj(itD n ζ 1) — is conj(itD n ζ 1) = itD n ζ 1?? NOT unless it's real! Hmm — itD n ζ 1 is junk (deriv of non-differentiable = 0): deriv _ 1 = 0? itD n ζ = deriv (itD (n−1) ζ) — at 1: if itD (n−1) ζ is not differentiable at 1, deriv = 0. So both sides 0: conj 0 = 0 ✓. But proving ¬DifferentiableAt (itD m ζ) 1 — hard. AVOID: don't need hconj globally! The hasDerivAt_conj_of_conj_eq needs hconj only EVENTUALLY near z (z ≠ 1): make hconj's hypothesis `∀ᶠ s in 𝓝 z, f (conj s) = conj (f s)`:
```
lemma hasDerivAt_conj_of_conj_eq {f : ℂ → ℂ} {z : ℂ}
(hconj : ∀ᶠ s in 𝓝 z, f ((starRingEnd ℂ) s) = (starRingEnd ℂ) (f s))
(hdiff : DifferentiableAt ℂ f z) :
HasDerivAt f ((starRingEnd ℂ) (deriv f z)) ((starRingEnd ℂ) z)
```
— the slope-quotient rewrite needs hconj at the points near z (x near conj z ⟹ conj x near z ✓ — hconj x in the funext: the funext is pointwise so needs hconj at the specific x = each point near conj z — the final h3 function-equality is used inside a Tendsto over 𝓝[≠] (conj z) — so an EventuallyEq suffices: f₁ =ᶠ[𝓝[≠] (conj z)] f₂: for x near conj z, conj x near z (continuous conj) so hconj holds at conj x: f(conj(conj x)) = conj(f(conj x)) — wait I need f(conj x) = conj(f x) at the point x: hconj holds at x (for x near conj z — the hconj nhd is around z, and x is near conj z — hconj x needs x near z!! x is near conj z, not z!). Hmm — the identity I need at x (near conj z): f(conj x) = conj(f x): that's hconj at x — but x is near conj z. So I need hconj in a neighborhood of CONJ z, i.e. at the points f is evaluated. Let me re-set: the slope at conj z evaluates f at x near conj z: I need f(conj x) = conj(f x) — hconj at x, x near conj z. So the hypothesis should be: ∀ᶠ s in 𝓝 (conj z), f(conj s) = conj(f s). But in the INDUCTIVE use, the identity itD n ζ (conj s) = conj(itD n ζ s) holds for s ≠ 1 — near conj z (z ≠ 1 ⟹ conj z ≠ 1): eventually s ≠ 1 ✓ (conj z ≠ 1 has a neighborhood avoiding 1 ✓). So state:
```
(hconj : ∀ᶠ s in 𝓝 ((starRingEnd ℂ) z), f ((starRingEnd ℂ) s) = (starRingEnd ℂ) (f s))
```
Then in the proof, the slope at conj z: for x near conj z: hconj x gives f(conj x) = conj(f x) ✓. The EventuallyEq of the two slope functions on 𝓝[≠] (conj z) ✓. Then Tendsto.congr' or HasDerivAt.congr_of_eventuallyEq? — `HasDerivAt.congr_of_eventuallyEq (h : HasDerivAt f f' x) (hl : f₁ =ᶠ[𝓝 x] f)`?? no that's for the FUNCTION f not the slope. The tendsto level: Filter.Tendsto.congr' (hl : f₁ =ᶠ[l] f₂) : Tendsto f₁ l n → Tendsto f₂ l n — direction: h2 has the conj-form function tending; I want the standard-slope function tending: standard =ᶠ conj-form (EventuallyEq) then Tendsto.congr' (the Eq) h2 ✓.
And the derivative value: HasDerivAt f (conj (deriv f z)) (conj z) — the value conj(deriv f z) ✓.
Then for the induction at z ≠ 1: hconj eventually at conj z: (conj z) ≠ 1 (z ≠ 1) ⟹ ∃ nhd avoiding 1: `eventually_ne` — nhds has no 1: (conj z) ∈ {s | s ≠ 1} open: (isOpen_compl_singleton.mem_nhds ?) — `isOpen_compl_singleton` ✓: ∀ᶠ s in 𝓝 (conj z), s ≠ 1: `eventually_ne_nhds (conj z) 1`? — there's `eventually_ne_nhds (hx : x ≠ a) : ∀ᶠ y in 𝓝 x, y ≠ a` ✓. Then filter_upwards with ih.
The AnalyticAt.iteratedDeriv: I didn't find it; use the induction with .deriv:
```
have han : ∀ n : ℕ, AnalyticAt ℂ (iteratedDeriv n riemannZeta) z := by
intro n
induction n with
| zero => exact analyticAt_riemannZeta hz
| succ n ih =>
rw [iteratedDeriv_succ]
exact ih.deriv
```
Hmm — iteratedDeriv (n+1) f = deriv (iteratedDeriv n f) — ih : AnalyticAt (itD n ζ) z: ih.deriv : AnalyticAt (deriv (itD n ζ)) z ✓ rw closes ✓.
Wait — actually is there `AnalyticAt.iteratedDeriv`? Let me just use the induction; it's robust.
Now the analyticOrderAt equality:
```
lemma analyticOrderAt_riemannZeta_conj {z : ℂ} (hz : z ≠ 1) :
analyticOrderAt riemannZeta ((starRingEnd ℂ) z) = analyticOrderAt riemannZeta z := by
have hzconj : ((starRingEnd ℂ) z) ≠ 1 := by
intro h
apply hz
have h2 : (starRingEnd ℂ) ((starRingEnd ℂ) z) = (starRingEnd ℂ) 1 := congrArg _ h
rwa [starRingEnd_self_apply, map_one] at h2
have htop : analyticOrderAt riemannZeta z ≠ ⊤ := zeta_order_ne_top_of_ne hz
have htopc : analyticOrderAt riemannZeta ((starRingEnd ℂ) z) ≠ ⊤ :=
zeta_order_ne_top_of_ne hzconj
set n := analyticOrderNatAt riemannZeta z with hn
have hzn : analyticOrderAt riemannZeta z = (n : ℕ∞) :=
(Nat.cast_analyticOrderNatAt htop).symm
have hkey : analyticOrderAt riemannZeta ((starRingEnd ℂ) z) = (n : ℕ∞) := by
rw [(analyticAt_riemannZeta hzconj).analyticOrderAt_eq_nat_iff_iteratedDeriv_eq_zero]
rw [hzn, (analyticAt_riemannZeta hz).analyticOrderAt_eq_nat_iff_iteratedDeriv_eq_zero] at hzn
obtain ⟨hz1, hz2⟩ := hzn
refine ⟨?_, ?_⟩
· intro k hk
rw [iteratedDeriv_riemannZeta_conj k hz]
rw [hz1 k hk, map_zero]
· rw [iteratedDeriv_riemannZeta_conj n hz]
intro hbad
apply hz2
-- conj x = 0 ⟹ x = 0
have : iteratedDeriv n riemannZeta z = 0 := by
have h3 := congrArg (starRingEnd ℂ) hbad
rwa [starRingEnd_self_apply, map_zero] at h3
exact this
rw [hzn, hkey]
```
Hmm — the structure: after rw [hzn, ...] at hzn — hzn becomes the iff RHS. Let me restructure:
```
obtain ⟨hz1, hz2⟩ := (analyticAt_riemannZeta hz).analyticOrderAt_eq_nat_iff_iteratedDeriv_eq_zero.mp hzn
have hkey : analyticOrderAt riemannZeta ((starRingEnd ℂ) z) = (n : ℕ∞) :=
(analyticAt_riemannZeta hzconj).analyticOrderAt_eq_nat_iff_iteratedDeriv_eq_zero.mpr
⟨fun k hk => by rw [iteratedDeriv_riemannZeta_conj k hz, hz1 k hk, map_zero],
by rw [iteratedDeriv_riemannZeta_conj n hz];
intro hbad; apply hz2;
have h3 := congrArg (starRingEnd ℂ) hbad;
rwa [starRingEnd_self_apply, map_zero] at h3⟩
rw [hzn, hkey]
```
Wait — the iff: analyticOrderAt f z₀ = n ↔ (∀ k < n, itD k = 0) ∧ itD n ≠ 0 — the .mp of hzn (order z = n) gives the conjuncts ✓. Note `starRingEnd_self_apply` direction: (starRingEnd ℂ) ((starRingEnd ℂ) x) = x ✓.
Then zeroMult_conj:
```
lemma zeroMult_conj {ρ : ℂ} (hρ : IsNontrivialZero ρ) :
zeroMult ((starRingEnd ℂ) ρ) = zeroMult ρ := by
rw [zeroMult, zeroMult, analyticOrderAt_riemannZeta_conj hρ.ne_one?]
```
— need ρ ≠ 1: from hρ : IsNontrivialZero ρ := (ζ ρ = 0) ∧ (0 < re ρ) ∧ (re ρ < 1): ρ ≠ 1 since re ρ < 1 (re 1 = 1): intro h; rw [h] at hρ.2.2; exact lt_irrefl 1 hρ.2.2 — the hρ structure: hρ.1 : ζ ρ = 0, hρ.2.1 : 0 < ρ.re, hρ.2.2 : ρ.re < 1 ✓.
And `zeroMult` is Zeta23's def — in the NguyenRH1 namespace it resolves to Zeta23's? The files use zeroMult directly ✓ (open Zeta23). zeroMult ρ := (analyticOrderAt riemannZeta ρ).toNat — so:
```
show (analyticOrderAt riemannZeta ((starRingEnd ℂ) ρ)).toNat
= (analyticOrderAt riemannZeta ρ).toNat
rw [analyticOrderAt_riemannZeta_conj hρ1]
```
where hρ1 : ρ ≠ 1. Whether zeroMult unfolds by rfl — `show ... := rfl`-ish; safer: rw [zeroMult, zeroMult] first (Zeta23.zeroMult? or _root_.zeroMult?). Let me check how it's referenced: in LiSides `(zeroMult ρ : ℂ) = (analyticOrderNatAt riemannZeta ρ : ℂ) := rfl` — interesting: zeroMult = analyticOrderNatAt definitionally (not just toNat of the same — analyticOrderNatAt IS (analyticOrderAt).toNat by def ✓ consistent). So zeroMult ρ is DEF-EQUAL to analyticOrderNatAt riemannZeta ρ — the Zeta23 def says (analyticOrderAt riemannZeta ρ).toNat and analyticOrderNatAt is defined as the same — defeq ✓. So:
```
lemma zeroMult_conj {ρ : ℂ} (hρ : IsNontrivialZero ρ) :
zeroMult ((starRingEnd ℂ) ρ) = zeroMult ρ := by
have hρ1 : ρ ≠ 1 := by
rintro rfl
have h := hρ.2.2
rw [Complex.one_re] at h
exact (lt_irrefl (1 : ℝ)) h
show (analyticOrderAt riemannZeta ((starRingEnd ℂ) ρ)).toNat
= (analyticOrderAt riemannZeta ρ).toNat
rw [analyticOrderAt_riemannZeta_conj hρ1]
```
The `show` — zeroMult ρ vs (analyticOrderAt riemannZeta ρ).toNat — defeq so show should accept (it's `zeroMult` from Zeta23 — the show must match definitionally: zeroMult ρ := (analyticOrderAt ζ ρ).toNat by def ✓ defeq ✓).
Now let me also write the C0hat bridges. And check `zeta_order_ne_top_of_ne` exists (used in LiContour's one_le_zeroMult ✓).
One more check — `hasDerivAt_iff_tendsto`: the exact form in this Mathlib.
API details confirmed. Let me verify `hasDerivAt_iff_tendsto` and `starRingEnd` continuity lemmas, then write §13–14.
tool: Bash
input
{
"command": "grep -rn \"theorem hasDerivAt_iff_tendsto\\b\\|lemma hasDerivAt_iff_tendsto\\b\" D:/Python/Quantum/zeta-23-lean/.lake/packages/mathlib/Mathlib/ --include=\"*.lean\" 2>/dev/null | head -3; grep -rn \"continuous_starRingEnd\\|starRingEnd_continuous\" D:/Python/Quantum/zeta-23-lean/.lake/packages/mathlib/Mathlib/ --include=\"*.lean\" 2>/dev/null | grep \"theorem\\|lemma\" | head -4; grep -rn \"theorem.*Tendsto.congr'\\|protected theorem Tendsto.congr'\" D:/Python/Quantum/zeta-23-lean/.lake/packages/mathlib/Mathlib/Order/ --include=\"*.lean\" 2>/dev/null | head -3",
"description": "Verify tendsto/conj API names"
}
raw content_json (database row)
[{"type":"thinking","thinking":"- `zeroMult ρ := (analyticOrderAt riemannZeta ρ).toNat` (Zeta23 Statement.lean) ✓.\n- `AnalyticAt.deriv : AnalyticAt 𝕜 f x → AnalyticAt 𝕜 (deriv f) x` ✓ — so AnalyticAt (iteratedDeriv n f) via iteration or there might be AnalyticAt.iteratedDeriv: let me just use induction: analyticAt_riemannZeta hz, .deriv, .deriv.deriv... via a recursive have: \n ```\n have han : ∀ n : ℕ, AnalyticAt ℂ (iteratedDeriv n riemannZeta) z := by\n intro n\n induction n with\n | zero => exact analyticAt_riemannZeta hz\n | succ n ih => \n rw [iteratedDeriv_succ]\n exact ih.deriv\n ```\n Need analyticAt_riemannZeta : z ≠ 1 → AnalyticAt ℂ riemannZeta z — used in LiContour's one_le_zeroMult as `analyticAt_riemannZeta hρ1` ✓.\n\n- The conj-deriv lemma: I need for f = iteratedDeriv n ζ: DifferentiableAt ℂ f z and the conj identity. The differentiability: AnalyticAt.differentiableAt ✓.\n\nNow — the conj-deriv lemma's tendsto composition. Let me write it carefully:\n\n```\nlemma hasDerivAt_conj_of_conj_eq {f : ℂ → ℂ} {z : ℂ}\n (hconj : ∀ s : ℂ, f ((starRingEnd ℂ) s) = (starRingEnd ℂ) (f s))\n (hdiff : DifferentiableAt ℂ f z) :\n HasDerivAt f ((starRingEnd ℂ) (deriv f z)) ((starRingEnd ℂ) z) := by\n rw [hasDerivAt_iff_tendsto] at hdiff ⊢\n -- hdiff.hasDerivAt : HasDerivAt f (deriv f z) z — DifferentiableAt.hasDerivAt ✓\n have h1 : Filter.Tendsto (fun x : ℂ => (f x - f z) / (x - z)) (𝓝[≠] z)\n (𝓝 (deriv f z)) :=\n hasDerivAt_iff_tendsto.mp hdiff.hasDerivAt\n have h2 : Filter.Tendsto (fun x : ℂ =>\n (starRingEnd ℂ) ((f ((starRingEnd ℂ) x) - f z) / (((starRingEnd ℂ) x) - z)))\n (𝓝[≠] ((starRingEnd ℂ) z)) (𝓝 ((starRingEnd ℂ) (deriv f z))) := by\n have hconjcont : Filter.Tendsto (starRingEnd ℂ) (𝓝 (deriv f z))\n (𝓝 ((starRingEnd ℂ) (deriv f z))) :=\n (starRingEnd_continuous).tendsto _\n have hmap : Filter.Tendsto (starRingEnd ℂ) (𝓝[≠] ((starRingEnd ℂ) z)) (𝓝[≠] z) := by\n apply (starRingEnd_continuous).tendsto_nhdsWithin_punctured? ...\n exact hconjcont.comp (h1.comp hmap)\n -- the function in h2 equals the slope of f at conj z\n ...\n```\nConcerns:\n- `DifferentiableAt.hasDerivAt : DifferentiableAt f z → HasDerivAt f (deriv f z) z` ✓ exists.\n- `hasDerivAt_iff_tendsto : HasDerivAt f f' x ↔ Tendsto (fun x' => (f x' − f x)/(x'−x)) (𝓝[≠] x) (𝓝 f')` — check name: might be `hasDerivAt_iff_tendsto : HasDerivAt f f' x ↔ Tendsto (fun x' => x' − x ... )` — there are variants (slope vs difference quotient): `hasDerivAt_iff_tendsto : HasDerivAt f f' x ↔ Tendsto (fun x' => (f x' - f x) / (x' - x)) (𝓝[≠] x) (𝓝 f')` — I believe this exists with that exact form.\n- Tendsto of conj into 𝓝[≠]: `(starRingEnd_continuous).tendsto z : Tendsto conj (𝓝 z) (𝓝 (conj z))`; for punctured: `Tendsto.inf` with the mapsTo: conj maps {x : x ≠ conj z} into {u : u ≠ z} (conj x ≠ z ⟺ x ≠ conj z: (starRingEnd ℂ).injective.ne_iff + conj_conj). There's `ContinuousAt.tendsto_punctured_nhds`? Let me search: `tendsto_nhdsWithin_of_tendsto`? The punctured version: Tendsto f (𝓝[≠] a) (𝓝[≠] b) from Tendsto f (𝓝 a) (𝓝 b) + (∀ x ≠ a, f x ≠ b): \n ```\n have hmap : Filter.Tendsto (starRingEnd ℂ) (𝓝[≠] ((starRingEnd ℂ) z)) (𝓝[≠] z) := by\n rw [Filter.tendsto_nhdsWithin_iff]\n refine ⟨(starRingEndContinuous.tendsto _).mono_left nhdsWithin_le_nhds, ?_⟩\n rw [Filter.eventually_nhdsWithin_iff]\n exact Filter.Eventually.of_forall (fun x hx => by\n intro hbad\n -- conj x = z ⟹ x = conj z (apply conj, conj_conj) — contradiction with hx\n have : x = (starRingEnd ℂ) z := by\n have h3 := congrArg (starRingEnd ℂ) hbad\n rwa [RingHom.apply_apply, ...] at h3 -- conj (conj x) = x\n exact hx this)\n ```\n starRingEnd_continuous: `starRingEnd_continuous : Continuous (starRingEnd ℂ)`? There's `Complex.continuous_conj : Continuous conj` — and (starRingEnd ℂ) as a function: continuous_starRingEnd? The name: `continuous_starRingEnd`? Hmm — safer: `Complex.continuous_conj : Continuous Complex.conj` and (starRingEnd ℂ) x = conj x by rfl (starRingEnd_apply: (starRingEnd ℂ) x = conj x ✓ simp lemma). Use Complex.conj directly?? — the isNontrivialZero_conj and other lemmas use (starRingEnd ℂ). The statement of riemannZeta_conj: `riemannZeta ((starRingEnd ℂ) s) = (starRingEnd ℂ) (riemannZeta s)` — from the isNontrivialZero_conj usage: `rw [_root_.riemannZeta_conj, hρ.1, map_zero]` — map_zero applies to the starRingEnd — so the identity is with (starRingEnd ℂ). And (starRingEnd ℂ) x = Complex.conj x — `starRingEnd_apply` simp.\n For continuity: `continuous_starRingEnd`? Let me just use: (Complex.continuous_conj : Continuous conj) with the starRingEnd_apply bridges, or check `starRingEnd_continuous` exists — grep later.\n The injectivity: (starRingEnd ℂ).injective : Function.Injective (starRingEnd ℂ) — RingHom.injective? For ring equivs: `(starRingEnd ℂ).injective` should work (it's a RingEquiv — `(starRingEnd ℂ) : ℂ ≃+* ℂ`? starRingEnd : R ≃+* R for commutative R ✓ so .injective ✓). And conj_conj: `(starRingEnd ℂ) ((starRingEnd ℂ) x) = x` — `starRingEnd_self_apply` simp lemma ✓.\n\n- The final slope identity: the function in h2 at x (≠ conj z): conj((f(conj x) − f z)/((conj x) − z)) — via hconj: f(conj x) = conj(f x): = conj((conj(f x) − f z)/((conj x) − z)) = conj(conj((f x − f (conj z))/(x − conj z)))·... let me redo: (f(conj x) − f z)/((conj x) − z) where the OUTER conj is applied after: conj([f(conj x) − f z]/[(conj x) − z]) = [conj(f(conj x)) − conj(f z)]/[conj(conj x) − conj z] (conj_div, conj_sub) = [f x − f(conj z)]/[x − conj z] (hconj: conj(f(conj x)) = f x? — from hconj: f(conj s) = conj(f s) ⟹ conj(f(conj x)) = conj(conj(f x)) = f x ✓; conj(f z) = f(conj z) ✓ by hconj at z; conj(conj x) = x ✓; conj z = conj z ✓). So the h2-function = the slope of f at conj z ✓ pointwise on 𝓝[≠] (conj z).\n Then h2 + the pointwise identity (eventually near conj z — actually EVERYWHERE ✓) ⟹ Tendsto (slope at conj z) (𝓝[≠] (conj z)) (𝓝 (conj (deriv f z))) ⟹ HasDerivAt via hasDerivAt_iff_tendsto.mpr — with the function equality: the slope-function might differ SYNTACTICALLY from h2's function — need EventuallyEq: show the two functions equal at all x (any x, no neighborhood needed):\n ```\n have h3 : (fun x : ℂ => (starRingEnd ℂ) ((f ((starRingEnd ℂ) x) - f z) / (((starRingEnd ℂ) x) - z)))\n = fun x : ℂ => (f x - f ((starRingEnd ℂ) z)) / (x - (starRingEnd ℂ) z) := by\n funext x\n rw [hconj x, hconj z]\n simp [map_sub, map_div₀, starRingEnd_self_apply, map_zero...]\n rw [h3] at h2\n exact hasDerivAt_iff_tendsto.mpr h2\n ```\n The simp: conj((conj(f x) − conj(f z))/(conj(conj x) − conj z)): conj_div: conj(a/b) = conj a/conj b (map_div₀ (starRingEnd ℂ)); conj_sub (map_sub); starRingEnd_self_apply: conj(conj x) = x. Result: (f x − f(conj z))/(x − conj z) ✓ — as long as hconj x rewrites f(conj x) → conj(f x) first. Order: rw [hconj x, hconj z] turns f(conj x) → conj(f x) and f(conj z) → conj(f z)?? WAIT — the h2-function has f((starRingEnd ℂ) x) — rw [hconj x] : f((starRingEnd ℂ) x) → (starRingEnd ℂ)(f x) ✓. But it ALSO has f z and f((starRingEnd ℂ) z)... only in the OUTER target. The h2 function: conj((f(conj x) − f z)/((conj x) − z)): inner f(conj x) → conj(f x) via hconj x ✓. Then conj((conj(f x) − f z)/(conj x − z)): map_div₀, map_sub: (conj(conj(f x)) − conj(f z))/(conj(conj x) − conj z) = (f x − conj(f z))/(x − conj z) — then conj(f z) = f(conj z) via hconj z reversed: hconj z : f(conj z) = conj(f z) — rw [← hconj z]: conj(f z) → f(conj z) ✓. So: funext x; rw [hconj x]; simp only [map_div₀, map_sub, starRingEnd_self_apply]; rw [← hconj z]. Hmm — map_div₀ needs the RingHom form: (starRingEnd ℂ) (a/b) = (starRingEnd ℂ) a / (starRingEnd ℂ) b — `map_div₀ (starRingEnd ℂ)`? or `map_div (starRingEnd ℂ)`? — simp should have these tagged for RingHom: map_div₀, map_sub, map_zero are simp lemmas for ring homs ✓; starRingEnd_self_apply is simp ✓. So: funext x; rw [hconj x, ← hconj z]; simp [map_div₀, map_sub, starRingEnd_self_apply]. Careful: after rw [hconj x, ← hconj z], the function is conj((conj(f x) − f(conj z))/(conj x − conj z))... wait the ← hconj z rewrites conj(f z) → f(conj z) — but at this point the term conj(f z) hasn't appeared yet (it's inside the outer conj). Order: rw [hconj x] first: f(conj x) → conj(f x). Now: conj((conj(f x) − f z)/(conj x − z)). simp [map_div₀, map_sub, starRingEnd_self_apply]: conj(a/b) → conj(a)/conj(b); conj(a−b) → conj(a)−conj(b); conj(conj u) → u: gives (f x − conj(f z))/(x − conj z). Then rw [← hconj z]: conj(f z) → f(conj z) ✓ final (f x − f(conj z))/(x − conj z) ✓.\n\nOK. And the induction lemma:\n```\nlemma iteratedDeriv_riemannZeta_conj (n : ℕ) {z : ℂ} (hz : z ≠ 1) :\n iteratedDeriv n riemannZeta ((starRingEnd ℂ) z)\n = (starRingEnd ℂ) (iteratedDeriv n riemannZeta z) := by\n induction n generalizing z with\n | zero =>\n rw [iteratedDeriv_zero, iteratedDeriv_zero]\n exact riemannZeta_conj z\n | succ n ih =>\n rw [iteratedDeriv_succ, iteratedDeriv_succ]\n -- deriv (itD n ζ) (conj z) = conj (deriv (itD n ζ) z)\n have hconj : ∀ s : ℂ, iteratedDeriv n riemannZeta ((starRingEnd ℂ) s)\n = (starRingEnd ℂ) (iteratedDeriv n riemannZeta s) := by\n intro s\n by_cases hs : s = 1\n · rw [hs]\n simp -- at s = 1: conj 1 = 1; itD n ζ 1 vs conj (itD n ζ 1): both junk?\n · exact ih hs\n have hd : DifferentiableAt ℂ (iteratedDeriv n riemannZeta) z :=\n (analyticAt_iteratedDeriv n hz).differentiableAt\n exact (hasDerivAt_conj_of_conj_eq hconj hd).deriv\n```\nThe s = 1 case of hconj: iteratedDeriv n ζ (conj 1) = conj (iteratedDeriv n ζ 1): conj 1 = 1 (map_one): both sides = itD n ζ 1: LHS itD n ζ 1, RHS conj(itD n ζ 1) — is conj(itD n ζ 1) = itD n ζ 1?? NOT unless it's real! Hmm — itD n ζ 1 is junk (deriv of non-differentiable = 0): deriv _ 1 = 0? itD n ζ = deriv (itD (n−1) ζ) — at 1: if itD (n−1) ζ is not differentiable at 1, deriv = 0. So both sides 0: conj 0 = 0 ✓. But proving ¬DifferentiableAt (itD m ζ) 1 — hard. AVOID: don't need hconj globally! The hasDerivAt_conj_of_conj_eq needs hconj only EVENTUALLY near z (z ≠ 1): make hconj's hypothesis `∀ᶠ s in 𝓝 z, f (conj s) = conj (f s)`:\n```\nlemma hasDerivAt_conj_of_conj_eq {f : ℂ → ℂ} {z : ℂ}\n (hconj : ∀ᶠ s in 𝓝 z, f ((starRingEnd ℂ) s) = (starRingEnd ℂ) (f s))\n (hdiff : DifferentiableAt ℂ f z) :\n HasDerivAt f ((starRingEnd ℂ) (deriv f z)) ((starRingEnd ℂ) z)\n```\n— the slope-quotient rewrite needs hconj at the points near z (x near conj z ⟹ conj x near z ✓ — hconj x in the funext: the funext is pointwise so needs hconj at the specific x = each point near conj z — the final h3 function-equality is used inside a Tendsto over 𝓝[≠] (conj z) — so an EventuallyEq suffices: f₁ =ᶠ[𝓝[≠] (conj z)] f₂: for x near conj z, conj x near z (continuous conj) so hconj holds at conj x: f(conj(conj x)) = conj(f(conj x)) — wait I need f(conj x) = conj(f x) at the point x: hconj holds at x (for x near conj z — the hconj nhd is around z, and x is near conj z — hconj x needs x near z!! x is near conj z, not z!). Hmm — the identity I need at x (near conj z): f(conj x) = conj(f x): that's hconj at x — but x is near conj z. So I need hconj in a neighborhood of CONJ z, i.e. at the points f is evaluated. Let me re-set: the slope at conj z evaluates f at x near conj z: I need f(conj x) = conj(f x) — hconj at x, x near conj z. So the hypothesis should be: ∀ᶠ s in 𝓝 (conj z), f(conj s) = conj(f s). But in the INDUCTIVE use, the identity itD n ζ (conj s) = conj(itD n ζ s) holds for s ≠ 1 — near conj z (z ≠ 1 ⟹ conj z ≠ 1): eventually s ≠ 1 ✓ (conj z ≠ 1 has a neighborhood avoiding 1 ✓). So state:\n```\n(hconj : ∀ᶠ s in 𝓝 ((starRingEnd ℂ) z), f ((starRingEnd ℂ) s) = (starRingEnd ℂ) (f s))\n```\nThen in the proof, the slope at conj z: for x near conj z: hconj x gives f(conj x) = conj(f x) ✓. The EventuallyEq of the two slope functions on 𝓝[≠] (conj z) ✓. Then Tendsto.congr' or HasDerivAt.congr_of_eventuallyEq? — `HasDerivAt.congr_of_eventuallyEq (h : HasDerivAt f f' x) (hl : f₁ =ᶠ[𝓝 x] f)`?? no that's for the FUNCTION f not the slope. The tendsto level: Filter.Tendsto.congr' (hl : f₁ =ᶠ[l] f₂) : Tendsto f₁ l n → Tendsto f₂ l n — direction: h2 has the conj-form function tending; I want the standard-slope function tending: standard =ᶠ conj-form (EventuallyEq) then Tendsto.congr' (the Eq) h2 ✓.\n\nAnd the derivative value: HasDerivAt f (conj (deriv f z)) (conj z) — the value conj(deriv f z) ✓.\n\nThen for the induction at z ≠ 1: hconj eventually at conj z: (conj z) ≠ 1 (z ≠ 1) ⟹ ∃ nhd avoiding 1: `eventually_ne` — nhds has no 1: (conj z) ∈ {s | s ≠ 1} open: (isOpen_compl_singleton.mem_nhds ?) — `isOpen_compl_singleton` ✓: ∀ᶠ s in 𝓝 (conj z), s ≠ 1: `eventually_ne_nhds (conj z) 1`? — there's `eventually_ne_nhds (hx : x ≠ a) : ∀ᶠ y in 𝓝 x, y ≠ a` ✓. Then filter_upwards with ih.\n\nThe AnalyticAt.iteratedDeriv: I didn't find it; use the induction with .deriv:\n```\nhave han : ∀ n : ℕ, AnalyticAt ℂ (iteratedDeriv n riemannZeta) z := by\n intro n\n induction n with\n | zero => exact analyticAt_riemannZeta hz\n | succ n ih =>\n rw [iteratedDeriv_succ]\n exact ih.deriv\n```\nHmm — iteratedDeriv (n+1) f = deriv (iteratedDeriv n f) — ih : AnalyticAt (itD n ζ) z: ih.deriv : AnalyticAt (deriv (itD n ζ)) z ✓ rw closes ✓.\n\nWait — actually is there `AnalyticAt.iteratedDeriv`? Let me just use the induction; it's robust.\n\nNow the analyticOrderAt equality:\n```\nlemma analyticOrderAt_riemannZeta_conj {z : ℂ} (hz : z ≠ 1) :\n analyticOrderAt riemannZeta ((starRingEnd ℂ) z) = analyticOrderAt riemannZeta z := by\n have hzconj : ((starRingEnd ℂ) z) ≠ 1 := by\n intro h\n apply hz\n have h2 : (starRingEnd ℂ) ((starRingEnd ℂ) z) = (starRingEnd ℂ) 1 := congrArg _ h\n rwa [starRingEnd_self_apply, map_one] at h2\n have htop : analyticOrderAt riemannZeta z ≠ ⊤ := zeta_order_ne_top_of_ne hz\n have htopc : analyticOrderAt riemannZeta ((starRingEnd ℂ) z) ≠ ⊤ :=\n zeta_order_ne_top_of_ne hzconj\n set n := analyticOrderNatAt riemannZeta z with hn\n have hzn : analyticOrderAt riemannZeta z = (n : ℕ∞) :=\n (Nat.cast_analyticOrderNatAt htop).symm\n have hkey : analyticOrderAt riemannZeta ((starRingEnd ℂ) z) = (n : ℕ∞) := by\n rw [(analyticAt_riemannZeta hzconj).analyticOrderAt_eq_nat_iff_iteratedDeriv_eq_zero]\n rw [hzn, (analyticAt_riemannZeta hz).analyticOrderAt_eq_nat_iff_iteratedDeriv_eq_zero] at hzn\n obtain ⟨hz1, hz2⟩ := hzn\n refine ⟨?_, ?_⟩\n · intro k hk\n rw [iteratedDeriv_riemannZeta_conj k hz]\n rw [hz1 k hk, map_zero]\n · rw [iteratedDeriv_riemannZeta_conj n hz]\n intro hbad\n apply hz2\n -- conj x = 0 ⟹ x = 0\n have : iteratedDeriv n riemannZeta z = 0 := by\n have h3 := congrArg (starRingEnd ℂ) hbad\n rwa [starRingEnd_self_apply, map_zero] at h3\n exact this\n rw [hzn, hkey]\n```\nHmm — the structure: after rw [hzn, ...] at hzn — hzn becomes the iff RHS. Let me restructure: \n```\n obtain ⟨hz1, hz2⟩ := (analyticAt_riemannZeta hz).analyticOrderAt_eq_nat_iff_iteratedDeriv_eq_zero.mp hzn\n have hkey : analyticOrderAt riemannZeta ((starRingEnd ℂ) z) = (n : ℕ∞) :=\n (analyticAt_riemannZeta hzconj).analyticOrderAt_eq_nat_iff_iteratedDeriv_eq_zero.mpr\n ⟨fun k hk => by rw [iteratedDeriv_riemannZeta_conj k hz, hz1 k hk, map_zero],\n by rw [iteratedDeriv_riemannZeta_conj n hz]; \n intro hbad; apply hz2;\n have h3 := congrArg (starRingEnd ℂ) hbad;\n rwa [starRingEnd_self_apply, map_zero] at h3⟩\n rw [hzn, hkey]\n```\nWait — the iff: analyticOrderAt f z₀ = n ↔ (∀ k < n, itD k = 0) ∧ itD n ≠ 0 — the .mp of hzn (order z = n) gives the conjuncts ✓. Note `starRingEnd_self_apply` direction: (starRingEnd ℂ) ((starRingEnd ℂ) x) = x ✓.\n\nThen zeroMult_conj:\n```\nlemma zeroMult_conj {ρ : ℂ} (hρ : IsNontrivialZero ρ) :\n zeroMult ((starRingEnd ℂ) ρ) = zeroMult ρ := by\n rw [zeroMult, zeroMult, analyticOrderAt_riemannZeta_conj hρ.ne_one?]\n```\n— need ρ ≠ 1: from hρ : IsNontrivialZero ρ := (ζ ρ = 0) ∧ (0 < re ρ) ∧ (re ρ < 1): ρ ≠ 1 since re ρ < 1 (re 1 = 1): intro h; rw [h] at hρ.2.2; exact lt_irrefl 1 hρ.2.2 — the hρ structure: hρ.1 : ζ ρ = 0, hρ.2.1 : 0 < ρ.re, hρ.2.2 : ρ.re < 1 ✓.\nAnd `zeroMult` is Zeta23's def — in the NguyenRH1 namespace it resolves to Zeta23's? The files use zeroMult directly ✓ (open Zeta23). zeroMult ρ := (analyticOrderAt riemannZeta ρ).toNat — so:\n```\n show (analyticOrderAt riemannZeta ((starRingEnd ℂ) ρ)).toNat\n = (analyticOrderAt riemannZeta ρ).toNat\n rw [analyticOrderAt_riemannZeta_conj hρ1]\n```\nwhere hρ1 : ρ ≠ 1. Whether zeroMult unfolds by rfl — `show ... := rfl`-ish; safer: rw [zeroMult, zeroMult] first (Zeta23.zeroMult? or _root_.zeroMult?). Let me check how it's referenced: in LiSides `(zeroMult ρ : ℂ) = (analyticOrderNatAt riemannZeta ρ : ℂ) := rfl` — interesting: zeroMult = analyticOrderNatAt definitionally (not just toNat of the same — analyticOrderNatAt IS (analyticOrderAt).toNat by def ✓ consistent). So zeroMult ρ is DEF-EQUAL to analyticOrderNatAt riemannZeta ρ — the Zeta23 def says (analyticOrderAt riemannZeta ρ).toNat and analyticOrderNatAt is defined as the same — defeq ✓. So:\n```\nlemma zeroMult_conj {ρ : ℂ} (hρ : IsNontrivialZero ρ) :\n zeroMult ((starRingEnd ℂ) ρ) = zeroMult ρ := by\n have hρ1 : ρ ≠ 1 := by\n rintro rfl\n have h := hρ.2.2\n rw [Complex.one_re] at h\n exact (lt_irrefl (1 : ℝ)) h\n show (analyticOrderAt riemannZeta ((starRingEnd ℂ) ρ)).toNat\n = (analyticOrderAt riemannZeta ρ).toNat\n rw [analyticOrderAt_riemannZeta_conj hρ1]\n```\nThe `show` — zeroMult ρ vs (analyticOrderAt riemannZeta ρ).toNat — defeq so show should accept (it's `zeroMult` from Zeta23 — the show must match definitionally: zeroMult ρ := (analyticOrderAt ζ ρ).toNat by def ✓ defeq ✓).\n\nNow let me also write the C0hat bridges. And check `zeta_order_ne_top_of_ne` exists (used in LiContour's one_le_zeroMult ✓).\n\nOne more check — `hasDerivAt_iff_tendsto`: the exact form in this Mathlib.","signature":""},{"type":"text","text":"API details confirmed. Let me verify `hasDerivAt_iff_tendsto` and `starRingEnd` continuity lemmas, then write §13–14."},{"type":"tool_use","id":"Bash_130","name":"Bash","input":{"command":"grep -rn \"theorem hasDerivAt_iff_tendsto\\b\\|lemma hasDerivAt_iff_tendsto\\b\" D:/Python/Quantum/zeta-23-lean/.lake/packages/mathlib/Mathlib/ --include=\"*.lean\" 2>/dev/null | head -3; grep -rn \"continuous_starRingEnd\\|starRingEnd_continuous\" D:/Python/Quantum/zeta-23-lean/.lake/packages/mathlib/Mathlib/ --include=\"*.lean\" 2>/dev/null | grep \"theorem\\|lemma\" | head -4; grep -rn \"theorem.*Tendsto.congr'\\|protected theorem Tendsto.congr'\" D:/Python/Quantum/zeta-23-lean/.lake/packages/mathlib/Mathlib/Order/ --include=\"*.lean\" 2>/dev/null | head -3","description":"Verify tendsto/conj API names"},"extra_content":null}]