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← Session 33 — ii′-3b/3c crux + F-D finding; Lagarias letter package

#1966 assistant 2026-08-25 05:31:21.112 UTC · 1752→5013 tok open ⤢
thinking (11922 chars)
I have the full pigeonhole pattern. Now build ii′-6-b. Plan the file layout — new file `LiAssembly.lean`: Contents: 1. **Perimeter Props** (LiContour.lean — append, since that's where ZeroCountProp2/NoLowZeros live; the freeze protocol exception was approved for these additions): - `zeroGlobalWindow (T : ℝ) : Set ℂ := {ρ | IsNontrivialZero ρ ∧ 0 < ρ.im ∧ ρ.im ≤ T}` + finiteness. - `ZeroCountGlobalProp : Prop := ∀ T : ℝ, 2 ≤ T → (((zeroGlobalWindow_finite T).toFinset.sum fun ρ => zeroMult ρ) : ℝ) ≤ FAlt T` - `MZeroProp : Prop := ∀ t : ℝ, |t| ≤ 10 → ‖logDeriv riemannZeta (-(5/2) + t * Complex.I)‖ ≤ 1.3352` Wait — MZeroProp uses logDeriv ζ at −5/2 + t·I. Note: at t = 0: ζ(−5/2) ≠ 0 ✓ (zeros are nontrivial ∪ {0} ∪ {−2n}; −5/2 not one). The M₀ bound is for the logDeriv. Fine. FAlt is defined in LiSkeleton; LiContour imports LiSkeleton? Let me check LiContour's imports. (ZeroCountProp uses C0hat from LiSkeleton ✓ so it imports LiSkeleton ✓ FAlt available ✓.) 2. **Extended pigeonhole** `exists_zero_avoiding_T_wide` (LiContour.lean — after exists_zero_avoiding_T): ```lean theorem exists_zero_avoiding_T_wide (hZC : ZeroCountProp) {a : ℝ} (ha : 3 ≤ a) : ∃ T : ℝ, a ≤ T ∧ T ≤ a + 1 ∧ ∀ ρ : ℂ, IsNontrivialZero ρ → a - 1 < ρ.im → ρ.im < a + 2 → 1 / (9 * C0hat (a + 2)) ≤ |ρ.im - T| ``` Proof: the 3-unit window (a−1, a+2) — hmm, the zeroWindow def is {IsNontrivialZero ∧ a ≤ im ∧ im ≤ a+1} (closed). For the wide window, define a local finset: zeros with a−1 ≤ im ≤ a+2? The count: zeros with a−1 ≤ im ≤ a+2 ⊆ zeroWindow (a−1) ∪ zeroWindow a ∪ zeroWindow (a+1) — each ≤ C0hat(a), C0hat(a+1), C0hat(a+2) via hZC (a−1 ≥ 2 ✓). Total ≤ C0hat(a) + C0hat(a+1) + C0hat(a+2) ≤ 3·C0hat(a+2) (C0hat monotone — check C0hat_mono exists ✓ used in LiGapCircles). Then the midpoint pigeonhole with k = the wide finset's card: T with clearance 1/(2(k+1)) ≥ 1/(2·(3·C0hat(a+2))) — hmm: 2(k+1) ≤ 2·(3C0hat) = 6·C0hat: clearance ≥ 1/(6·C0hat(a+2))?? But D-071 said 1/(9·C0hat(a+2)). The D-071 form c = 1/(9·C0hat(a+2)) came from "3·C3 with C3 = 3·C0hat(a+2)" — the exists_zero_avoiding_T pattern's clearance is 1/(3·count): 2(k+1) ≤ 3·C0hat for the unit window (using C0hat ≥ 2). For the wide: 2(k+1) ≤ 3·(3·C0hat(a+2))·... let me redo: hT3 gives 1/(2·(card+1)) ≤ |x−T|; card ≤ 3·C0hat(a+2); 2·(card+1) ≤ 2·(3·C0hat + 1) ≤ 2·(3·C0hat + C0hat/2·... hmm — C0hat ≥ 2 so 1 ≤ C0hat/2: 2·(3C0hat+1) ≤ 2·(3.5·C0hat) = 7·C0hat. So clearance ≥ 1/(7·C0hat(a+2)). D-071's 1/(9·C0hat) is satisfied if I show 2(card+1) ≤ 9·C0hat(a+2): 2·(3·C0hat + 1) ≤ 6·C0hat + C0hat = 7·C0hat ≤ 9·C0hat ✓ (using 1 ≤ C0hat, even 2·1 ≤ C0hat since C0hat ≥ 2). Even 7·C0hat works but D-071 said 9 — keep 9 (looser, fine, and matches D-071/E-030's c = 1/(9·C0hat(a+2))). The wide window's zeros: im ∈ (a−1, a+2) — strict or closed? D-071 says (a−1, a+2) — I'll use the closed form for the finset (a−1 ≤ im ≤ a+2) which is a superset — the statement with < follows. Structure the window: `zeroWindowWide (a : ℝ) : Set ℂ := {ρ | IsNontrivialZero ρ ∧ a - 1 ≤ ρ.im ∧ ρ.im ≤ a + 2}` + finiteness (subset of zerosIn_finite) + the card bound via the three unit windows. The union decomposition: zeroWindowWide a ⊆ zeroWindow (a−1) ∪ zeroWindow a ∪ zeroWindow (a+1) — membership by cases on im (linarith). The mult-count over the wide window ≤ Σ over the three unit windows (finset sum over union via Set.Finite.toFinset subset + sum_le_sum_of_subset? or bound the wide finset's sum via the union's sum: sum over subset ≤ sum over superset for nonneg terms ✓ Finset.sum_le_sum_of_subset_of_nonneg). And each unit window's sum ≤ C0hat(t+1) via hZC. So Σ wide ≤ C0hat(a) + C0hat(a+1) + C0hat(a+2) ≤ 3·C0hat(a+2) (monotone). Then card ≤ Σ mult ✓ same as before. Then exists_avoiding_midpoint with S = wide.image im. 3. **Sides identity + bridge** (new file LiAssembly.lean): ```lean theorem sides_identity (n : ℕ) (hn : 1 ≤ n) {T : ℝ} (hT : √n ≤ T ∧ T ≤ √n + 1) (hTavoid : ∀ ρ, IsNontrivialZero ρ → √n - 1 < ρ.im → ρ.im < √n + 2 → 0 < |ρ.im - T|) : |Sf n| ≤ ‖RectangleIntegral' (Jlag n) (-(5/2) - T * I) (2 * √n + T * I)‖ + ‖∑ ρ ∈ Sz, (zeroMult ρ : ℂ) * (1 - (ρ / (ρ - 1)) ^ n)‖ ``` Hmm — wait, |Sf n| = |(ResW1 n).re| ≤ ‖ResW1 n‖ = ‖RectInt − Σ‖ ≤ ‖RectInt‖ + ‖Σ‖. So: ```lean theorem sf_abs_le_rectInt_add_sum (hZC : ZeroCountProp) (n : ℕ) {T : ℝ} ... : |Sf n| ≤ ‖RectangleIntegral' (Jlag n) z w‖ + ‖∑ ρ ∈ Sz, ...‖ ``` via sf_eq_resW1 (hZC) hn : (ResW1 n).re = Sf n; |Sf n| = |(ResW1 n).re| ≤ ‖ResW1 n‖ (Complex.abs_re_le_norm — banked: abs_re_le_norm exists per journal-029 ✓); ResW1 = RectInt − Σ via rectInt'_Jlag (needs 1 interior + border-zero-free + Sz characterization). The rectangle: z = ⟨−5/2, −T⟩, w = ⟨2√n, T⟩. In ℂ: z = -5/2 - T*I? Hmm — Rectangle z w with z.re ≤ w.re, z.im ≤ w.im. Take z := (-5/2 : ℝ) - T * I? (-(5/2) : ℂ) - (T : ℝ) * Complex.I has re = −5/2, im = −T ✓. w := (2 * Real.sqrt n : ℝ) + (T : ℝ) * I? re = 2√n, im = T ✓... wait — need w.re = 2√n as a real: (2 * √n : ℂ) — write w := ((2 * Real.sqrt n : ℝ) : ℂ) + (T : ℝ) * Complex.I. re = 2√n ✓ im = T ✓. - hre : z.re ≤ w.re: −5/2 ≤ 2√n ✓ (norm_num + sqrt nonneg). - him : z.im ≤ w.im: −T ≤ T ✓ (T ≥ √n > 0). - h1 : Rectangle z w ∈ 𝓝 1: 1 ∈ interior: re: −5/2 < 1 < 2√n (need 1 < 2√n: n ≥ 1 ✓ √n ≥ 1); im: −T < 0 < T ✓. Rectangle_mem_nhds: there's a lemma `rectangle_mem_nhds_of_mem_not_border` and h1 in rectInt'_Jlag is `Rectangle z w ∈ 𝓝 (1:ℂ)` — need to prove it: Rectangle z w = [z.re, w.re] × [z.im, w.im] as a set? There must be a lemma like `Rectangle_mem_nhds` (iff: z.re < x.re < w.re ∧ z.im < x.im < w.im?). Let me check how h1 is discharged elsewhere... rectInt'_Jlag is only used... it's the capstone of ii′-1b — was it ever instantiated? Probably not yet. Check for `Rectangle.*mem_nhds` lemmas in Zeta23. - hborder : ∀ s ∈ RectangleBorder z w, riemannZeta s ≠ 0: The border = {re ∈ {−5/2, 2√n}, im ∈ [−T,T]} ∪ {re ∈ [−5/2, 2√n], im ∈ {−T, T}}. - On re = −5/2: zeros classification: zeros = nontrivial ∪ {0} ∪ {−2n}. re(ρ) = −5/2: nontrivial have re ∈ (0,1) ✗; 0 ✗; −2n: re = −2n = −5/2 ⟹ n = 5/4 ✗ not nat. So no zeros on re = −5/2 ✓ — via zeta_zero_classification (LiFEntire ✓). - On re = 2√n: re > 1 (2√n ≥ 2): ζ ≠ 0 via Mathlib `riemannZeta_ne_zero_of_one_le_re` (takes ONLY re per banked note: riemannZeta_ne_zero_of_one_le_re (h : 1 ≤ s.re) — check). - On im = ±T: ζ(s) = 0 with im s = ±T: zeros with |im| = T: nontrivial (re ∈ (0,1)) with γ = ±T — excluded by the wide pigeonhole (|T − γ| ≥ 1/(9·C0hat) > 0 for γ ∈ (√n−1, √n+2); zeros outside that window have |im − T| ≥ 1 > 0 hmm — im = T exactly: γ = T ∈ [√n, √n+1] ⊂ (√n−1, √n+2) ✓ covered by the pigeonhole ⟹ γ ≠ T ✓; and γ = −T: by conj symmetry or directly: the wide window covers only positive... γ = −T: is that excluded? The pigeonhole is about positive ordinates (im ∈ (a−1, a+2)). For im = −T: a zero with γ = −T — conj gives a zero with γ = T ✓ excluded via isNontrivialZero_conj. Or use: zeros with im = −T ⟹ conj-zero with im = T ∈ [√n, √n+1] ✓ excluded. Also trivial zeros on im = ±T: trivial zeros have im = 0 ✓ not on im = ±T (T > 0). And 0: im = 0 ✗. So hborder via the classification + the pigeonhole + conj. - Sz: the finset of zeros of zetaA inside: Sz = (the zeros inside) — from zeta_zero_classification: zetaA s = 0 ⟺ ζ s = 0 (off 1) ⟺ nontrivial ∨ s = 0 ∨ s = −2n. Inside the rectangle: nontrivial with |im| ≤ T (and re ∈ (0,1) ⊂ (−5/2, 2√n) ✓ — all nontrivial zeros with |im| ≤ T are inside: re ∈ (0,1): −5/2 < re < 2√n ✓ (2√n ≥ 2 > 1); im: |im| ≤ T hmm — inside needs z.re ≤ re ≤ w.re and z.im ≤ im ≤ w.im: |im| ≤ T ⟺ −T ≤ im ≤ T ✓) + {0}? ζ(0) = −1/2 ≠ 0 but zetaA 0 = (0−1)·ζ(0) = 1/2 ≠ 0 — wait zetaA s = 0 ⟺ (s−1)·ζ(s) = 0 (s ≠ 1) ⟺ ζ s = 0 for s ≠ 1. zetaA 0 = update ... 0 ≠ 1 so zetaA 0 = (0−1)·ζ(0) = (−1)·(−1/2) = 1/2 ≠ 0 ✓ so 0 ∉ Sz. −2n: zetaA(−2n) = 0 for n ≥ 1; inside: −2 ∈ (−5/2, 2√n) ✓ im = 0 ∈ (−T, T) ✓ so −2 ∈ Sz; −4: re = −4 < −5/2 ✗ not inside; −6, ... ✗. So Sz = {nontrivial, |im| ≤ T} ∪ {−2}. For the identity I don't need the EXACT Sz — rectInt'_Jlag takes Sz + the characterization. I need to CONSTRUCT the finset: Sz := (finite set of nontrivial zeros with |im| ≤ T) ∪ {−2}. Finiteness via zerosIn_finite. The characterization `s ∈ Sz ↔ s ∈ Rectangle z w ∧ zetaA s = 0`: prove via the classification. Then: ```lean theorem sf_abs_le (hZC) (n) (hn : 1 ≤ n) {T} (hT : √n ≤ T ≤ √n+1) (hTwide : ...) : |Sf n| ≤ ‖RectangleIntegral' (Jlag n) z w‖ + ‖∑ ρ ∈ Sz, mult * (1 - (ρ/(ρ-1))^n)‖ ``` Proof: |Sf n| = |(ResW1 n).re| (sf_eq_resW1 hZC hn ▸ abs) ≤ ‖ResW1 n‖ (abs_re_le_norm) = ‖RectInt − Σ‖ (rectInt'_Jlag ▸) ≤ ‖RectInt‖ + ‖Σ‖ (norm_sub_le). Wait — rectInt'_Jlag gives RectInt = ResW1 + Σ, so ResW1 = RectInt − Σ ✓ norm_sub_le ✓. 4. **The bridge**: ```lean theorem zeroTerm_norm_le_four_FAlt (hRH : RHUpTo (3*10^12)) (hZCG : ZeroCountGlobalProp) (n : ℕ) {T : ℝ} (hT : T ≤ 3*10^12 - 1) : ‖∑ ρ ∈ Sz, (zeroMult ρ : ℂ) * (1 - (ρ / (ρ - 1)) ^ n)‖ ≤ 4 * FAlt T + 1 ``` Hmm — the triv is inside Sz ({−2}): separate: Σ = Σ_{nontriv} + term(−2); |term(−2)| = |1 − ((−2)/(−3))ⁿ| = 1 − (2/3)ⁿ ≤ 1 ✓. The nontriv part: Σ_{|γ|≤T} mult·|1−(ρ/(ρ−1))ⁿ| ≤ Σ mult·2: - on the line via hRH: |ρ.im| ≤ T ≤ 3×10¹² ⟹ re = 1/2 ⟹ |ρ/(ρ−1)| = 1 (norm computation: |ρ|² = (1/2)²+γ², |ρ−1|² = (−1/2)²+γ² ✓ equal). - so |1−(ρ/(ρ−1))ⁿ| ≤ 1 + 1 = 2 ✓. - Σ mult·2 = 2·Σ mult over both-signs = 2·(2·Σ_{one-sign} mult) ≤ 4·FAlt T (the conj bijection: {0 < γ ≤ T} and {−T ≤ γ < 0} — no zeros with γ = 0 (nontrivial have im ≠ 0? IsNontrivialZero: 0 < re < 1 and... im could be 0? A nontrivial zero with im = 0: possible by the def? IsNontrivialZero ρ := ζ ρ = 0 ∧ 0 < re ρ ∧ re ρ < 1 — wait let me check: from LiMoments usage, IsNontrivialZero ρ has .1 (ζ = 0), .2.1 (0 < re), .2.2 (re < 1). im = 0 not excluded by def — but NoLowZeros says |γ| ≥ 14! With hNLZ... hmm — do we have NoLowZeros in the bridge? It's a perimeter Prop (5f's hNLZ). For the bridge, zeros with γ = 0: nontrivial zeros with im = 0 — the wide-window/pigeonhole doesn't need it, but the both-signs decomposition needs: {nontrivial, |im| ≤ T} = {0 < im ≤ T} ∪ {im = 0} ∪ {−T ≤ im < 0}. im = 0 nontrivial zeros: exist? A real zero in (0,1)? ζ on (0,1): ζ(0) = −1/2, ζ has no real zeros in (0,1) (ζ(x) < 0 for 0 ≤ x < 1 — classical; Mathlib: riemannZeta_ne_zero_of_one_le_re for re ≥ 1; for (0,1)... hmm. Is there a Lean proof ζ ≠ 0 on (0,1)? Via NoLowZeros (|γ| ≥ 14) — that's the Platt-class certificate ✓ in the perimeter. So the bridge takes hNLZ too: im = 0 ⟹ |im| = 0 < 14 ⟹ no zeros (hNLZ). So {nontrivial, |im| ≤ T} = {0 < im ≤ T} ∪ {−T ≤ im < 0} and the conj bijection (zeroMult_conj : zeroMult (conj ρ) = zeroMult ρ — from LiTightR §? — zeroMult_conj exists ✓ used in LiMoments' tsum_mult_inv_pow_conj). So bridge: ‖Σ_nontriv‖ ≤ 2·Σ_{both} mult = 2·(2·Σ_{0<γ≤T} mult) ≤ 4·FAlt T; plus triv ≤ 1. Total ≤ 4·FAlt T + 1. Hmm wait — Bn charges 4·FAlt T for the bridge and +1 for triv separately ✓ consistent: |λ_n(T)| ≤ 4·FAlt T, |triv| ≤ 1. Layout decision: perimeter Props + extended pigeonhole → LiContour.lean (append; it's the natural home, already has ZeroCountProp2/NoLowZeros and the pigeonhole machine). Sides identity + bridge → new LiAssembly.lean (imports LiSides, LiCrux (sf_eq_resW1), LiContour, LiTightR (zeroMult_conj?), LiSkeleton (FAlt, Sf)). Where's zeroMult_conj? Used in LiMoments (tsum_mult_inv_pow_conj) — grep: it's in LiTightR (the conj machinery from 5f piece 3: zeroMult_conj). LiMoments imports LiTightR ✓. LiAssembly can import LiMoments or LiTightR. Let me check zeroMult_conj's exact form and zeta_zero_classification + riemannZeta_ne_zero_of_one_le_re + Rectangle mem_nhds lemmas. Then write.
The pattern is fully clear. Checking the last few signatures (zeroMult_conj, zeta_zero_classification, Rectangle mem_nhds, one_le_re nonvanishing).
tool: Grep ok
input
{
  "pattern": "theorem zeroMult_conj|lemma zeroMult_conj|theorem zeta_zero_classification|lemma zeta_zero_classification|rectangle_mem_nhds_of_mem_not_border|theorem Rectangle.*mem_nhds|riemannZeta_ne_zero_of_one_le_re",
  "path": "D:\\Python\\Quantum\\research\\lean",
  "output_mode": "content",
  "-n": true,
  "-A": 5,
  "head_limit": 50
}
result 2026-08-25 05:31:21Z → 2026-08-25 05:31:21Z
mode='content' num_files=0 filenames=[] content="research\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean:2294:lemma zeroMult_conj {ρ : ℂ} (hρ : IsNontrivialZero ρ) :\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean-2295-    zeroMult ((starRingEnd ℂ) ρ) = zeroMult ρ:= by\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean-2296-  have hρ1: ρ ≠ 1 := by\nD:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean-2297-    rintro rfl\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean-2298-    have h:= hρ.2.2\nD:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean-2299-    rw [Complex.one_re] at h\n--\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean:4324:    apply riemannZeta_ne_zero_of_one_le_re\nD:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean-4325-    rw [hs₀def]\nD:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean-4326-    simp\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean-4327-  have hs₀0: s₀ ≠ 0 := by\nD:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean-4328-    intro h\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean-4329-    have h1: s₀.re = (0 : ℂ).re := by rw [h]\n--\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiSides.lean:143:lemma rectangle_mem_nhds_of_mem_not_border {z w p : ℂ} (hre : z.re ≤ w.re) (him : z.im ≤ w.im)\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiSides.lean-144-    (hmem: p ∈ Rectangle z w) (hb : p ∉ RectangleBorder z w) :\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiSides.lean-145-    Rectangle z w ∈ 𝓝 p:= by\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiSides.lean-146-  obtain ⟨h1, h2⟩:= hmem\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiSides.lean-147-  have h1': z.re ≤ p.re ∧ p.re ≤ w.re := by simpa [Set.uIcc_of_le hre] using h1\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiSides.lean-148-  have h2': z.im ≤ p.im ∧ p.im ≤ w.im := by simpa [Set.uIcc_of_le him] using h2\n--\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiSides.lean:457:    exact rectangle_mem_nhds_of_mem_not_border hre him ((hSz ρ).mp hρ).1\nD:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiSides.lean-458-      (fun hb => hborder ρ hb (hSz_zeta ρ hρ))\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiSides.lean-459-  set A: ℂ → ℂ := fun p => if p = 1 then 0 else (zeroMult p : ℂ) * (1 - (p / (p - 1)) ^ n)\nD:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiSides.lean-460-    with hAdef\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiSides.lean-461-  have fHolo: HolomorphicOn (Rfun n) (Rectangle z w \\ ↑(insert (1 : ℂ) Sz)) := by\nD:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiSides.lean-462-    intro s hs\n--\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiDisc.lean:54:`riemannZeta_ne_zero_of_one_le_re`; re ≤ 0 excluded by the FE since the\nD:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiDisc.lean-55-disc avoids {−2n} and 0). -/\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiDisc.lean-56-theorem zeroDisc_isNontrivial {t: ℝ} {ρ : ℂ} (hρ : ρ ∈ zeroDiscFinset t) :\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiDisc.lean-57-    IsNontrivialZero ρ:= by\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiDisc.lean-58-  have h2:= (mem_zeroDiscFinset.mp hρ).2\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiDisc.lean-59-  have hball:= (mem_zeroDiscFinset.mp hρ).1\n--\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiDisc.lean:73:    exact riemannZeta_ne_zero_of_one_le_re h h2\nD:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiDisc.lean-74-  -- re ρ ≤ 0 excluded (would force ρ ∈ {−2n} ∪ {0}, all outside the disc)\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiDisc.lean-75-  have hpos: 0 < ρ.re := by\nD:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiDisc.lean-76-    by_contra h\nD:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiDisc.lean-77-    push Not at h\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiDisc.lean-78-    by_cases hG: Complex.Gammaℝ ρ = 0\n--\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiFEntire.lean:166:split; `riemannZeta_ne_zero_of_one_le_re` excludes re ≥ 1). -/\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiFEntire.lean:167:lemma zeta_zero_classification {s : ℂ} (hs : riemannZeta s = 0) :\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiFEntire.lean-168-    IsNontrivialZero s ∨ s = 0 ∨ ∃ n: ℕ, 1 ≤ n ∧ s = -2 * (n : ℂ) := by\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiFEntire.lean-169-  by_cases h1: 1 ≤ s.re\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiFEntire.lean:170:  · exact absurd hs (riemannZeta_ne_zero_of_one_le_re h1)\nD:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiFEntire.lean-171-  · push Not at h1\nresearch\\lean\\NguyenRH1\\NguyenRH1\\LiFEntire.lean-172-    by_cases h0: 0 < s.re\nD:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiFEntire.lean-173-    · exact Or.inl ⟨hs, h0, h1⟩" num_lines=50 num_matches=None applied_limit=50 applied_offset=None
raw content_json (database row)
[{"type":"thinking","thinking":"I have the full pigeonhole pattern. Now build ii′-6-b. Plan the file layout — new file `LiAssembly.lean`:\n\nContents:\n1. **Perimeter Props** (LiContour.lean — append, since that's where ZeroCountProp2/NoLowZeros live; the freeze protocol exception was approved for these additions):\n   - `zeroGlobalWindow (T : ℝ) : Set ℂ := {ρ | IsNontrivialZero ρ ∧ 0 < ρ.im ∧ ρ.im ≤ T}` + finiteness.\n   - `ZeroCountGlobalProp : Prop := ∀ T : ℝ, 2 ≤ T → (((zeroGlobalWindow_finite T).toFinset.sum fun ρ => zeroMult ρ) : ℝ) ≤ FAlt T`\n   - `MZeroProp : Prop := ∀ t : ℝ, |t| ≤ 10 → ‖logDeriv riemannZeta (-(5/2) + t * Complex.I)‖ ≤ 1.3352`\n   \n   Wait — MZeroProp uses logDeriv ζ at −5/2 + t·I. Note: at t = 0: ζ(−5/2) ≠ 0 ✓ (zeros are nontrivial ∪ {0} ∪ {−2n}; −5/2 not one). The M₀ bound is for the logDeriv. Fine.\n   \n   FAlt is defined in LiSkeleton; LiContour imports LiSkeleton? Let me check LiContour's imports. (ZeroCountProp uses C0hat from LiSkeleton ✓ so it imports LiSkeleton ✓ FAlt available ✓.)\n\n2. **Extended pigeonhole** `exists_zero_avoiding_T_wide` (LiContour.lean — after exists_zero_avoiding_T):\n   ```lean\n   theorem exists_zero_avoiding_T_wide (hZC : ZeroCountProp) {a : ℝ} (ha : 3 ≤ a) :\n       ∃ T : ℝ, a ≤ T ∧ T ≤ a + 1 ∧\n         ∀ ρ : ℂ, IsNontrivialZero ρ → a - 1 < ρ.im → ρ.im < a + 2 →\n           1 / (9 * C0hat (a + 2)) ≤ |ρ.im - T|\n   ```\n   Proof: the 3-unit window (a−1, a+2) — hmm, the zeroWindow def is {IsNontrivialZero ∧ a ≤ im ∧ im ≤ a+1} (closed). For the wide window, define a local finset: zeros with a−1 ≤ im ≤ a+2? The count: zeros with a−1 ≤ im ≤ a+2 ⊆ zeroWindow (a−1) ∪ zeroWindow a ∪ zeroWindow (a+1) — each ≤ C0hat(a), C0hat(a+1), C0hat(a+2) via hZC (a−1 ≥ 2 ✓). Total ≤ C0hat(a) + C0hat(a+1) + C0hat(a+2) ≤ 3·C0hat(a+2) (C0hat monotone — check C0hat_mono exists ✓ used in LiGapCircles).\n   \n   Then the midpoint pigeonhole with k = the wide finset's card: T with clearance 1/(2(k+1)) ≥ 1/(2·(3·C0hat(a+2))) — hmm: 2(k+1) ≤ 2·(3C0hat) = 6·C0hat: clearance ≥ 1/(6·C0hat(a+2))?? But D-071 said 1/(9·C0hat(a+2)). The D-071 form c = 1/(9·C0hat(a+2)) came from \"3·C3 with C3 = 3·C0hat(a+2)\" — the exists_zero_avoiding_T pattern's clearance is 1/(3·count): 2(k+1) ≤ 3·C0hat for the unit window (using C0hat ≥ 2). For the wide: 2(k+1) ≤ 3·(3·C0hat(a+2))·... let me redo: hT3 gives 1/(2·(card+1)) ≤ |x−T|; card ≤ 3·C0hat(a+2); 2·(card+1) ≤ 2·(3·C0hat + 1) ≤ 2·(3·C0hat + C0hat/2·... hmm — C0hat ≥ 2 so 1 ≤ C0hat/2: 2·(3C0hat+1) ≤ 2·(3.5·C0hat) = 7·C0hat. So clearance ≥ 1/(7·C0hat(a+2)). D-071's 1/(9·C0hat) is satisfied if I show 2(card+1) ≤ 9·C0hat(a+2): 2·(3·C0hat + 1) ≤ 6·C0hat + C0hat = 7·C0hat ≤ 9·C0hat ✓ (using 1 ≤ C0hat, even 2·1 ≤ C0hat since C0hat ≥ 2). Even 7·C0hat works but D-071 said 9 — keep 9 (looser, fine, and matches D-071/E-030's c = 1/(9·C0hat(a+2))).\n   \n   The wide window's zeros: im ∈ (a−1, a+2) — strict or closed? D-071 says (a−1, a+2) — I'll use the closed form for the finset (a−1 ≤ im ≤ a+2) which is a superset — the statement with < follows.\n   \n   Structure the window: `zeroWindowWide (a : ℝ) : Set ℂ := {ρ | IsNontrivialZero ρ ∧ a - 1 ≤ ρ.im ∧ ρ.im ≤ a + 2}` + finiteness (subset of zerosIn_finite) + the card bound via the three unit windows. The union decomposition: zeroWindowWide a ⊆ zeroWindow (a−1) ∪ zeroWindow a ∪ zeroWindow (a+1) — membership by cases on im (linarith).\n   \n   The mult-count over the wide window ≤ Σ over the three unit windows (finset sum over union via Set.Finite.toFinset subset + sum_le_sum_of_subset? or bound the wide finset's sum via the union's sum: sum over subset ≤ sum over superset for nonneg terms ✓ Finset.sum_le_sum_of_subset_of_nonneg). And each unit window's sum ≤ C0hat(t+1) via hZC. So Σ wide ≤ C0hat(a) + C0hat(a+1) + C0hat(a+2) ≤ 3·C0hat(a+2) (monotone). Then card ≤ Σ mult ✓ same as before.\n   \n   Then exists_avoiding_midpoint with S = wide.image im.\n\n3. **Sides identity + bridge** (new file LiAssembly.lean):\n   ```lean\n   theorem sides_identity (n : ℕ) (hn : 1 ≤ n) {T : ℝ} (hT : √n ≤ T ∧ T ≤ √n + 1)\n       (hTavoid : ∀ ρ, IsNontrivialZero ρ → √n - 1 < ρ.im → ρ.im < √n + 2 → 0 < |ρ.im - T|) :\n       |Sf n| ≤ ‖RectangleIntegral' (Jlag n) (-(5/2) - T * I) (2 * √n + T * I)‖ +\n         ‖∑ ρ ∈ Sz, (zeroMult ρ : ℂ) * (1 - (ρ / (ρ - 1)) ^ n)‖\n   ```\n   Hmm — wait, |Sf n| = |(ResW1 n).re| ≤ ‖ResW1 n‖ = ‖RectInt − Σ‖ ≤ ‖RectInt‖ + ‖Σ‖. So:\n   ```lean\n   theorem sf_abs_le_rectInt_add_sum (hZC : ZeroCountProp) (n : ℕ) {T : ℝ} ... :\n       |Sf n| ≤ ‖RectangleIntegral' (Jlag n) z w‖ + ‖∑ ρ ∈ Sz, ...‖\n   ```\n   via sf_eq_resW1 (hZC) hn : (ResW1 n).re = Sf n; |Sf n| = |(ResW1 n).re| ≤ ‖ResW1 n‖ (Complex.abs_re_le_norm — banked: abs_re_le_norm exists per journal-029 ✓); ResW1 = RectInt − Σ via rectInt'_Jlag (needs 1 interior + border-zero-free + Sz characterization).\n   \n   The rectangle: z = ⟨−5/2, −T⟩, w = ⟨2√n, T⟩. In ℂ: z = -5/2 - T*I? Hmm — Rectangle z w with z.re ≤ w.re, z.im ≤ w.im. Take z := (-5/2 : ℝ) - T * I? (-(5/2) : ℂ) - (T : ℝ) * Complex.I has re = −5/2, im = −T ✓. w := (2 * Real.sqrt n : ℝ) + (T : ℝ) * I? re = 2√n, im = T ✓... wait — need w.re = 2√n as a real: (2 * √n : ℂ) — write w := ((2 * Real.sqrt n : ℝ) : ℂ) + (T : ℝ) * Complex.I. re = 2√n ✓ im = T ✓.\n   \n   - hre : z.re ≤ w.re: −5/2 ≤ 2√n ✓ (norm_num + sqrt nonneg).\n   - him : z.im ≤ w.im: −T ≤ T ✓ (T ≥ √n > 0).\n   - h1 : Rectangle z w ∈ 𝓝 1: 1 ∈ interior: re: −5/2 < 1 < 2√n (need 1 < 2√n: n ≥ 1 ✓ √n ≥ 1); im: −T < 0 < T ✓. Rectangle_mem_nhds: there's a lemma `rectangle_mem_nhds_of_mem_not_border` and h1 in rectInt'_Jlag is `Rectangle z w ∈ 𝓝 (1:ℂ)` — need to prove it: Rectangle z w = [z.re, w.re] × [z.im, w.im] as a set? There must be a lemma like `Rectangle_mem_nhds` (iff: z.re < x.re < w.re ∧ z.im < x.im < w.im?). Let me check how h1 is discharged elsewhere... rectInt'_Jlag is only used... it's the capstone of ii′-1b — was it ever instantiated? Probably not yet. Check for `Rectangle.*mem_nhds` lemmas in Zeta23.\n   - hborder : ∀ s ∈ RectangleBorder z w, riemannZeta s ≠ 0:\n     The border = {re ∈ {−5/2, 2√n}, im ∈ [−T,T]} ∪ {re ∈ [−5/2, 2√n], im ∈ {−T, T}}.\n     - On re = −5/2: zeros classification: zeros = nontrivial ∪ {0} ∪ {−2n}. re(ρ) = −5/2: nontrivial have re ∈ (0,1) ✗; 0 ✗; −2n: re = −2n = −5/2 ⟹ n = 5/4 ✗ not nat. So no zeros on re = −5/2 ✓ — via zeta_zero_classification (LiFEntire ✓).\n     - On re = 2√n: re > 1 (2√n ≥ 2): ζ ≠ 0 via Mathlib `riemannZeta_ne_zero_of_one_le_re` (takes ONLY re per banked note: riemannZeta_ne_zero_of_one_le_re (h : 1 ≤ s.re) — check).\n     - On im = ±T: ζ(s) = 0 with im s = ±T: zeros with |im| = T: nontrivial (re ∈ (0,1)) with γ = ±T — excluded by the wide pigeonhole (|T − γ| ≥ 1/(9·C0hat) > 0 for γ ∈ (√n−1, √n+2); zeros outside that window have |im − T| ≥ 1 > 0 hmm — im = T exactly: γ = T ∈ [√n, √n+1] ⊂ (√n−1, √n+2) ✓ covered by the pigeonhole ⟹ γ ≠ T ✓; and γ = −T: by conj symmetry or directly: the wide window covers only positive... γ = −T: is that excluded? The pigeonhole is about positive ordinates (im ∈ (a−1, a+2)). For im = −T: a zero with γ = −T — conj gives a zero with γ = T ✓ excluded via isNontrivialZero_conj. Or use: zeros with im = −T ⟹ conj-zero with im = T ∈ [√n, √n+1] ✓ excluded.\n       Also trivial zeros on im = ±T: trivial zeros have im = 0 ✓ not on im = ±T (T > 0).\n       And 0: im = 0 ✗.\n     So hborder via the classification + the pigeonhole + conj.\n   - Sz: the finset of zeros of zetaA inside: Sz = (the zeros inside) — from zeta_zero_classification: zetaA s = 0 ⟺ ζ s = 0 (off 1) ⟺ nontrivial ∨ s = 0 ∨ s = −2n. Inside the rectangle: nontrivial with |im| ≤ T (and re ∈ (0,1) ⊂ (−5/2, 2√n) ✓ — all nontrivial zeros with |im| ≤ T are inside: re ∈ (0,1): −5/2 < re < 2√n ✓ (2√n ≥ 2 > 1); im: |im| ≤ T hmm — inside needs z.re ≤ re ≤ w.re and z.im ≤ im ≤ w.im: |im| ≤ T ⟺ −T ≤ im ≤ T ✓) + {0}? ζ(0) = −1/2 ≠ 0 but zetaA 0 = (0−1)·ζ(0) = 1/2 ≠ 0 — wait zetaA s = 0 ⟺ (s−1)·ζ(s) = 0 (s ≠ 1) ⟺ ζ s = 0 for s ≠ 1. zetaA 0 = update ... 0 ≠ 1 so zetaA 0 = (0−1)·ζ(0) = (−1)·(−1/2) = 1/2 ≠ 0 ✓ so 0 ∉ Sz. −2n: zetaA(−2n) = 0 for n ≥ 1; inside: −2 ∈ (−5/2, 2√n) ✓ im = 0 ∈ (−T, T) ✓ so −2 ∈ Sz; −4: re = −4 < −5/2 ✗ not inside; −6, ... ✗. So Sz = {nontrivial, |im| ≤ T} ∪ {−2}.\n   \n   For the identity I don't need the EXACT Sz — rectInt'_Jlag takes Sz + the characterization. I need to CONSTRUCT the finset: Sz := (finite set of nontrivial zeros with |im| ≤ T) ∪ {−2}. Finiteness via zerosIn_finite. The characterization `s ∈ Sz ↔ s ∈ Rectangle z w ∧ zetaA s = 0`: prove via the classification.\n   \n   Then:\n   ```lean\n   theorem sf_abs_le (hZC) (n) (hn : 1 ≤ n) {T} (hT : √n ≤ T ≤ √n+1) (hTwide : ...) :\n       |Sf n| ≤ ‖RectangleIntegral' (Jlag n) z w‖ + ‖∑ ρ ∈ Sz, mult * (1 - (ρ/(ρ-1))^n)‖\n   ```\n   Proof: |Sf n| = |(ResW1 n).re| (sf_eq_resW1 hZC hn ▸ abs) ≤ ‖ResW1 n‖ (abs_re_le_norm) = ‖RectInt − Σ‖ (rectInt'_Jlag ▸) ≤ ‖RectInt‖ + ‖Σ‖ (norm_sub_le).\n   \n   Wait — rectInt'_Jlag gives RectInt = ResW1 + Σ, so ResW1 = RectInt − Σ ✓ norm_sub_le ✓.\n\n4. **The bridge**:\n   ```lean\n   theorem zeroTerm_norm_le_four_FAlt (hRH : RHUpTo (3*10^12)) (hZCG : ZeroCountGlobalProp)\n       (n : ℕ) {T : ℝ} (hT : T ≤ 3*10^12 - 1) :\n       ‖∑ ρ ∈ Sz, (zeroMult ρ : ℂ) * (1 - (ρ / (ρ - 1)) ^ n)‖ ≤ 4 * FAlt T + 1\n   ```\n   Hmm — the triv is inside Sz ({−2}): separate: Σ = Σ_{nontriv} + term(−2); |term(−2)| = |1 − ((−2)/(−3))ⁿ| = 1 − (2/3)ⁿ ≤ 1 ✓.\n   The nontriv part: Σ_{|γ|≤T} mult·|1−(ρ/(ρ−1))ⁿ| ≤ Σ mult·2:\n   - on the line via hRH: |ρ.im| ≤ T ≤ 3×10¹² ⟹ re = 1/2 ⟹ |ρ/(ρ−1)| = 1 (norm computation: |ρ|² = (1/2)²+γ², |ρ−1|² = (−1/2)²+γ² ✓ equal).\n   - so |1−(ρ/(ρ−1))ⁿ| ≤ 1 + 1 = 2 ✓.\n   - Σ mult·2 = 2·Σ mult over both-signs = 2·(2·Σ_{one-sign} mult) ≤ 4·FAlt T (the conj bijection: {0 < γ ≤ T} and {−T ≤ γ < 0} — no zeros with γ = 0 (nontrivial have im ≠ 0? IsNontrivialZero: 0 < re < 1 and... im could be 0? A nontrivial zero with im = 0: possible by the def? IsNontrivialZero ρ := ζ ρ = 0 ∧ 0 < re ρ ∧ re ρ < 1 — wait let me check: from LiMoments usage, IsNontrivialZero ρ has .1 (ζ = 0), .2.1 (0 < re), .2.2 (re < 1). im = 0 not excluded by def — but NoLowZeros says |γ| ≥ 14! With hNLZ... hmm — do we have NoLowZeros in the bridge? It's a perimeter Prop (5f's hNLZ). For the bridge, zeros with γ = 0: nontrivial zeros with im = 0 — the wide-window/pigeonhole doesn't need it, but the both-signs decomposition needs: {nontrivial, |im| ≤ T} = {0 < im ≤ T} ∪ {im = 0} ∪ {−T ≤ im < 0}. im = 0 nontrivial zeros: exist? A real zero in (0,1)? ζ on (0,1): ζ(0) = −1/2, ζ has no real zeros in (0,1) (ζ(x) < 0 for 0 ≤ x < 1 — classical; Mathlib: riemannZeta_ne_zero_of_one_le_re for re ≥ 1; for (0,1)... hmm. Is there a Lean proof ζ ≠ 0 on (0,1)? Via NoLowZeros (|γ| ≥ 14) — that's the Platt-class certificate ✓ in the perimeter. So the bridge takes hNLZ too: im = 0 ⟹ |im| = 0 < 14 ⟹ no zeros (hNLZ). So {nontrivial, |im| ≤ T} = {0 < im ≤ T} ∪ {−T ≤ im < 0} and the conj bijection (zeroMult_conj : zeroMult (conj ρ) = zeroMult ρ — from LiTightR §? — zeroMult_conj exists ✓ used in LiMoments' tsum_mult_inv_pow_conj).\n   \n   So bridge: ‖Σ_nontriv‖ ≤ 2·Σ_{both} mult = 2·(2·Σ_{0<γ≤T} mult) ≤ 4·FAlt T; plus triv ≤ 1. Total ≤ 4·FAlt T + 1.\n   \n   Hmm wait — Bn charges 4·FAlt T for the bridge and +1 for triv separately ✓ consistent: |λ_n(T)| ≤ 4·FAlt T, |triv| ≤ 1.\n\nLayout decision: perimeter Props + extended pigeonhole → LiContour.lean (append; it's the natural home, already has ZeroCountProp2/NoLowZeros and the pigeonhole machine). Sides identity + bridge → new LiAssembly.lean (imports LiSides, LiCrux (sf_eq_resW1), LiContour, LiTightR (zeroMult_conj?), LiSkeleton (FAlt, Sf)).\n\nWhere's zeroMult_conj? Used in LiMoments (tsum_mult_inv_pow_conj) — grep: it's in LiTightR (the conj machinery from 5f piece 3: zeroMult_conj). LiMoments imports LiTightR ✓. LiAssembly can import LiMoments or LiTightR.\n\nLet me check zeroMult_conj's exact form and zeta_zero_classification + riemannZeta_ne_zero_of_one_le_re + Rectangle mem_nhds lemmas. Then write.","signature":""},{"type":"text","text":"The pattern is fully clear. Checking the last few signatures (zeroMult_conj, zeta_zero_classification, Rectangle mem_nhds, one_le_re nonvanishing)."},{"type":"tool_use","id":"Grep_243","name":"Grep","input":{"pattern":"theorem zeroMult_conj|lemma zeroMult_conj|theorem zeta_zero_classification|lemma zeta_zero_classification|rectangle_mem_nhds_of_mem_not_border|theorem Rectangle.*mem_nhds|riemannZeta_ne_zero_of_one_le_re","path":"D:\\Python\\Quantum\\research\\lean","output_mode":"content","-n":true,"-A":5,"head_limit":50},"extra_content":null}]