← Session 35 — ii′-6-R: Lagarias 6.1 right-tail re-proof (E-032/D-073)
thinking (7358 chars)
Cherry-pick committed (e11ad95). Now ii′-6-a2-i: the Bn/marginTilde/marginExpanded/mK dog-leg redefinition.
The new Bn (D-074's DogLegRight at the DL-5 quarter-charge constants):
```
Bn(F, n) := 4F(T) + 4T[(2/3)Z2(T) + 10.5 log(T+2) + 48] + 40·1.3352
+ 2(e⁴+1)(7Ĥ(T)) + 2·DogLegRight(n) + IIMaj(n) + 1, T = √n+1
DogLegRight(n) = ((√n+1)/2)(e^{5/2}+1)/2 + 8.38 + IIMaj(n)/4
```
Expanded: 2·DogLegRight = (√n+1)(e^{5/2}+1)/2 + 16.76 + IIMaj(n)/2.
Total IIMaj: 1 (I_I) + 1/2 (dog-leg) = 1.5·IIMaj ✓.
vs session-038 honest Bn: `... + 2(e⁴+1)(7Ĥ + 3.3) + IIMaj + 1`. Changes:
- horizontal share: 2(e⁴+1)(7Ĥ + 3.3) → 2(e⁴+1)(7Ĥ) + 2·DogLegRight.
- So Bn_new = Bn_old − 2(e⁴+1)·3.3 + (√n+1)(e^{5/2}+1)/2 + 16.76 + IIMaj(n)/2.
Wait — 2·DogLegRight = (√n+1)(e^{5/2}+1)/2 + 16.76 + IIMaj/2, and the I_I piece is IIMaj. So:
Bn_new = 4F + 4T[...] + 40·1.3352 + 2(e⁴+1)(7Ĥ) + [(√n+1)(e^{5/2}+1)/2 + 16.76 + IIMaj/2] + IIMaj + 1.
Total IIMaj coefficient: 1/2 + 1 = 1.5 ✓.
For the margin blocks (marginExpanded):
- The √n-linear part (√n+1)(e^{5/2}+1)/2: merges with mIdb: coefficient −((8/3)·2.7+192) = −199.2 → −[199.2 + (e^{5/2}+1)/2] = −[199.2 + 6.591] = −205.791. Note: (√n+1)(e^{5/2}+1)/2 = (√n+1)·(e^{5/2}+1)/2 — as a function of m: ((√m+1)·(e^{5/2}+1)/2) — the mIdb block is (−coef)·(√m+1) with coef = 199.2: new coef = 199.2 + (e^{5/2}+1)/2.
- The 16.76: merges with mK: mK := −40·1.3352 − 2(e⁴+1)(7(3·2.9²+48) + 3.3) − 1 + 1 → −40·1.3352 − 2(e⁴+1)(7(3·2.9²+48)) − 16.76 − 1 + 1. (The 3.3 inside the (e⁴+1) bracket is REMOVED and the 16.76 appears raw.)
- mIIM: (−1)·IIMaj → (−1.5)·IIMaj.
- Everything else unchanged (the Ĥ log-blocks mL1sqb/mL1L2b/mL2sqb/mL1b/mL2b with the 2(e⁴+1)·7Ĥ expansion — the Ĥ inside is UNCHANGED: Hhat = 3Ĉ₀² + 10.5 log + 48 ✓ so the log-block coefficients 42·0.433²·(e⁴+1) etc. are UNCHANGED ✓).
Wait — let me double check the Ĥ-block expansion: 2(e⁴+1)·7Ĥ = 2(e⁴+1)·7·(3Ĉ₀² + 10.5 log(T+2) + 48) = 42(e⁴+1)Ĉ₀² + 147(e⁴+1)log(T+2) + 336(e⁴+1). The blocks:
- mL1sqb: −(42·0.433²·(e⁴+1))·log²(T+2) ✓ unchanged
- mL1L2b: −(42·2·0.433·0.886·(e⁴+1))·log·loglog ✓ unchanged
- mL2sqb: −(42·0.886²·(e⁴+1))·loglog² ✓ unchanged
- mL1b: −((42·2·0.433·2.9 + 147)·(e⁴+1))·log ✓ unchanged
- mL2b: −(42·2·0.886·2.9·(e⁴+1))·loglog ✓ unchanged
- mK: the constants −40·1.3352 − 336(e⁴+1) − 2(e⁴+1)·7·3·2.9²·... — wait, the old mK = −40·1.3352 − 2(e⁴+1)(7(3·2.9² + 48) + 3.3) − 1 + 1 — that has the Ĉ₀ constant part 3·2.9² = 25.23·... and the 3.3. New mK = −40·1.3352 − 2(e⁴+1)(7(3·2.9² + 48)) − 16.76 − 1 + 1 — the (7(3·2.9²+48)) = 7·(25.23+48) = 7·73.23 = 512.61 — that's the constant part of 2(e⁴+1)·7Ĥ's Ĉ₀-constant + 48 ✓ — and NO 3.3 (moved to the dog-leg R form) + 16.76 (the 2·8.38).
Now the Bn def itself:
```
def Bn (F : ℝ → ℝ) (n : ℝ) : ℝ :=
let T := Real.sqrt n + 1
4 * F T + 4 * T * ((2 / 3) * Z2hat T + 10.5 * Real.log (T + 2) + 48) +
40 * 1.3352 + 2 * (Real.exp 4 + 1) * (7 * Hhat T) +
2 * DogLegRight n + IIMaj n + 1
```
with a new def DogLegRight:
```
def DogLegRight (n : ℝ) : ℝ :=
((Real.sqrt n + 1) / 2) * (Real.exp (5 / 2) + 1) / 2 + 8.38 + IIMaj n / 4
```
And 2·DogLegRight = (√n+1)(e^{5/2}+1)/2 + 16.76 + IIMaj/2.
Hmm — for the marginExpanded bookkeeping (marginTilde_eq_expanded's ring check), the blocks must sum to exactly marginTilde = sInfty − Bn + 1. The mIdb new coefficient (199.2 + (e^{5/2}+1)/2) and mIIM (−1.5) and mK (−16.76, no 3.3). Let me write the new forms:
```
private def mIdb : ℝ → ℝ := fun m => (-(((8/3)*2.7 + 192) + (Real.exp (5/2) + 1) / 2)) *
((1.5 * Real.sqrt m + 1) ...
```
WAIT — the mIdb block's function: (−coef)·(√m+1) — the dog-leg's √n-linear part is (√n+1)(e^{5/2}+1)/2 — and mIdb's (−coef)·id(√m+1) — the id block: (−((8/3)·2.7+192))·(Real.sqrt m + 1) — the dog-leg part is ((√m+1)·(e^{5/2}+1)/2) = (e^{5/2}+1)/2·(√m+1) — so the TOTAL coefficient of (√m+1) in margiñ is −((8/3)·2.7+192) [from I_III] − (e^{5/2}+1)/2 [from dog-leg] ✓ — so mIdb_new = (−(((8/3)*2.7 + 192) + (Real.exp (5/2) + 1) / 2))·(Real.sqrt m + 1) ✓ — NOT the 1.5-scaled form (the dog-leg keeps T = √n+1!! — no k-shift — the inner function stays √m+1 ✓✓).
And the I_I majorant IIMaj: the Bn's I_I piece is IIMaj(n) [coefficient 1] + dog-leg IIMaj/4 ×2 = IIMaj/2: total 1.5. mIIM = (−1.5)·IIMaj m ✓.
And the DogLegRight def + the Bn def. Also marginTilde's def (lockstep with Bn via marginTilde_eq_sub's simp only).
Let me also double-check marginTilde_eq_sub: marginTilde F n = sInftyLower n − Bn F n + 1 — marginTilde's def is literally (sInfty-expression) − (Bn-expression) + 1 — so if I change BOTH consistently, the simp only [marginTilde, Bn, sInftyLower] proof stays ✓.
And marginTilde_eq_expanded: the blocks sum to the marginTilde form via ring — the mIdb/mIIM/mK changes are consistent on both sides ✓ ring verifies.
And contDiffOn_mIdb: `contDiffOn_const.mul contDiffOn_sqrt_shift` — the block's constant changed (now a sum-of-constants including e^{5/2}) — contDiffOn_const.mul works for any constant ✓ no change needed.
And contDiffOn_mIIM: mIIM = (−1.5)·IIMaj — the unfold + contDiffOn_const.mul ✓ unchanged (constant-agnostic).
And marginTilde_convex's v-blocks: vId (mIdb's deriv) — the coefficient changed: vId's value = (−new-coef)·(psiOf id (√n+1)/(4n)) — the chain_rule_sqrt_shift_on form ✓ unchanged (constant-agnostic) — just the literal updates. vIIM: (−1.5)·IIMaj″ — the final assembly: 1/(2n) + nonnegs + (−1.5)·IIMaj″ ≥ 1/(2n) − 1.5·IIMaj″ > 0 ⟸ IIMaj″ < 1/(3n) ✓ lt_three + the bridge 1.5·(1/(3n)) = 1/(2n) (field_simp — hmm, the bridge `1.5·(1/(3n)) = 1/(2n)` — field_simp [hn0.ne'] closed it earlier ✓ or div_eq_div_iff).
And the mK constant block deriv2_const_val ✓ unchanged (constant).
So the a2-i edits:
1. `DogLegRight` def (new).
2. `Bn` def: horizontal share → 2(e⁴+1)(7Ĥ) + 2·DogLegRight n.
3. `marginTilde` def: lockstep.
4. `marginExpanded` blocks: mIdb (new coefficient), mIIM (−1.5), mK (new).
5. marginTilde_eq_expanded/eq_sub (should be ring/simp-clean).
6. contDiffOn_mIdb/mIIM (probably fine as-is).
7. marginTilde_convex's vId/vIIM literals + final linarith (the 1.5 bridge).
Then a2-ii: base points (LiBasePoints rebuild at the new Bn — targets margin(8e4) ≈ 13 160, margin(10⁵) ≈ 88 911 — vs E-034's margins computed with Bn_DL: 13 160.089 / 88 910.825 — hmm — E-034's Bn_DL used 2·DogLegRight with VRightBound = IIMaj/4 ✓ same as the new Bn ✓ margins match ✓) + endpoint margins.
Wait — one nuance: E-034's Bn_DL has `2 * (e^4 + 1) * (7 * Hhat(T))` (no +3.3, replaced by DogLegRight) ✓ matches the new Bn's structure ✓. And E-034's margins (13 160.089 / 88 910.825 / 2.458e26) are computed with the certified-constant form (e^{5/2}+1 ≤ 13.19 charged as E52P1 = 13.19 ✓ same as Lean's (Real.exp (5/2)+1)/2 with the true exp value ✓ — hmm — the Lean Bn uses Real.exp (5/2) (the TRUE exp) while E-034 charges 13.19 ≥ e^{5/2}+1 = 13.182 — the Lean Bn uses the TRUE exp (5/2)+1 = 13.182+1 = 14.182?? — wait: Real.exp (5/2) = 12.1825, +1 = 13.1825 — E-034's E52P1 = 13.19 (charged upper) — so E-034's Bn_DL is SLIGHTLY bigger (13.19 vs 13.1825) than the Lean Bn (true 13.1825) — the margins differ by ~2·(13.19−13.1825)/2·(√n+1)·... ≈ 2·0.00375·(√n+1) ≈ 2 units at 8e4 — negligible ✓. So E-034's margins ≈ the Lean margins to within a few units ✓ targets fine.
Let me start the a2-i edits. First the DogLegRight + Bn defs.
Cherry-pick committed (`e11ad95`). Now **ii′-6-a2-i**: the Bn dog-leg redefinition. Starting with the `DogLegRight` def and the Bn/marginTilde/block updates.
tool: TodoWrite ok
input
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"content": "ii\u2032-6-a2-i: DogLegRight def + Bn/marginTilde/marginExpanded/mK dog-leg redefinition + eq_expanded/eq_sub + contDiffOn + convexity literals",
"status": "in_progress",
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"content": "Full build + axiom audit + commit ii\u2032-6-a2; then ii\u2032-6-c per the return map",
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result 2026-08-26 11:48:53Z → 2026-08-26 11:48:53Z
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tool: Read ok
input
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result 2026-08-26 11:48:53Z → 2026-08-26 11:48:53Z
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"content": "term \u2212(log 2\u03c0e/2\u03c0)\u00b7T DROPPED, so FAlt \u2265 F + S_b pointwise for T \u2265 0 and\nany literature bound N(T) \u2264 F(T) + S_b(T) upgrades to N(T) \u2264 FAlt(T).\nThe swap is needed because \u03c8[F + S_b] crosses POSITIVE on [5.47, ~16]\n(the dropped term has negative weight against a negative-\u03c8 block), while\nevery FAlt block has provably negative \u03c8 (D-057 rows #1/#3/#4). Margin\ncost: 2\u00b7(log 2\u03c0e/2\u03c0)\u00b7T \u2248 0.9\u221an, negligible vs margin\u0303(8\u00d710\u2074) \u2248 1.6\u00d710\u2074\n(E-028). Domain note: smooth only on (1, \u221e) (log log needs T > 1); the\nmargin composition hits only T = \u221an + 1 \u2265 \u221a20 + 1 > 1. -/\ndef FAlt (T : \u211d) : \u211d :=\n (1 / (2 * Real.pi)) * (T * Real.log T) + 0.137 * Real.log T +\n 0.443 * Real.log (Real.log T) + (7 / 8 + 1.588)\n\n/-- The explicit finite-part bound B(n) (D-037 (4.1) CORRECTED per D-071,\nuser-approved session 038; constants A = 10.5, B\u2080 = 48 from D-056;\n\u0108\u2080/H\u0302/Z\u2082 closed forms; M\u2080 = 1.3352 from E-023; IIMaj the I_I majorant),\nwith the zero-count majorant F as a parameter:\nB(n) = 4F(T) + 4T[(2/3)Z\u2082(T) + 10.5\u00b7log(T+2) + 48] + 40\u00b71.3352\n + 2(e\u2074+1)\u00b7[7H\u0302(T) + 3.3] + IIMaj(n) + 1, T = \u221an + 1.\nThe correction (D-071 F-A/F-B): the bridge is 4F \u2014 the residue sum\n\u03bb_n(T) runs over BOTH signs of \u03b3 (D-036/D-037's 2N(T) was a factor-2\naccounting slip; R-004's theorem is unaffected, see E-030); the I_III\nnear-sum uses the two-unit count (2/3)Z\u2082 (D-069 Finding 2 made exact). -/\ndef Bn (F : \u211d \u2192 \u211d) (n : \u211d) : \u211d :=\n let T := Real.sqrt n + 1\n 4 * F T + 4 * T * ((2 / 3) * Z2hat T + 10.5 * Real.log (T + 2) + 48) +\n 40 * 1.3352 + 2 * (Real.exp 4 + 1) * (7 * Hhat T + 3.3) + IIMaj n + 1\n\n/-- [PROVED session 012] The margin IS sInftyLower \u2212 Bn + 1 (pure\nbookkeeping; same constants as `marginTilde_eq_expanded`). -/\ntheorem marginTilde_eq_sub (F : \u211d \u2192 \u211d) (n : \u211d) :\n marginTilde F n = sInftyLower n - Bn F n + 1 := by\n simp only [marginTilde, Bn, sInftyLower]\n\n/-- The finite part S_f(n) of the Bombieri\u2013Lagarias decomposition\n\u03bb_n = S_\u221e(n) \u2212 S_f(n) + 1 (BL 1999 Thm 2, D-037 P1), here DEFINED by the\nidentity rearranged (\u03bb_n is real by conjugate symmetry, so taking the\nreal part is no loss \u2014 see `LiVerifiedUpTo`). The analytic content \u2014 that\nthis quantity is bounded by B(n) \u2014 is isolated in `SfBoundProp`. -/\ndef Sf (n : \u2115) : \u211d := SInfty n + 1 - (liCoeff n).re\n\n/-- \u2b50 THE named analytic hypothesis of tier (ii): the finite part is\nbounded by the explicit traced B(n) on the whole margin range\n10\u2075 \u2264 n \u2264 N\u2081 = (T\u2080\u22121)\u00b2, T\u2080 = 3\u00d710\u00b9\u00b2.\nProof content (triage D-062): the D-036/D-056 contour estimate \u2014 kernel\nbounds + reference-point R-bound (Mathlib-tractable complex analysis),",
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raw content_json (database row)
[{"type":"thinking","thinking":"Cherry-pick committed (e11ad95). Now ii′-6-a2-i: the Bn/marginTilde/marginExpanded/mK dog-leg redefinition.\n\nThe new Bn (D-074's DogLegRight at the DL-5 quarter-charge constants):\n```\nBn(F, n) := 4F(T) + 4T[(2/3)Z2(T) + 10.5 log(T+2) + 48] + 40·1.3352\n + 2(e⁴+1)(7Ĥ(T)) + 2·DogLegRight(n) + IIMaj(n) + 1, T = √n+1\nDogLegRight(n) = ((√n+1)/2)(e^{5/2}+1)/2 + 8.38 + IIMaj(n)/4\n```\nExpanded: 2·DogLegRight = (√n+1)(e^{5/2}+1)/2 + 16.76 + IIMaj(n)/2.\nTotal IIMaj: 1 (I_I) + 1/2 (dog-leg) = 1.5·IIMaj ✓.\n\nvs session-038 honest Bn: `... + 2(e⁴+1)(7Ĥ + 3.3) + IIMaj + 1`. Changes:\n- horizontal share: 2(e⁴+1)(7Ĥ + 3.3) → 2(e⁴+1)(7Ĥ) + 2·DogLegRight.\n- So Bn_new = Bn_old − 2(e⁴+1)·3.3 + (√n+1)(e^{5/2}+1)/2 + 16.76 + IIMaj(n)/2.\n\nWait — 2·DogLegRight = (√n+1)(e^{5/2}+1)/2 + 16.76 + IIMaj/2, and the I_I piece is IIMaj. So:\nBn_new = 4F + 4T[...] + 40·1.3352 + 2(e⁴+1)(7Ĥ) + [(√n+1)(e^{5/2}+1)/2 + 16.76 + IIMaj/2] + IIMaj + 1.\n\nTotal IIMaj coefficient: 1/2 + 1 = 1.5 ✓.\n\nFor the margin blocks (marginExpanded):\n- The √n-linear part (√n+1)(e^{5/2}+1)/2: merges with mIdb: coefficient −((8/3)·2.7+192) = −199.2 → −[199.2 + (e^{5/2}+1)/2] = −[199.2 + 6.591] = −205.791. Note: (√n+1)(e^{5/2}+1)/2 = (√n+1)·(e^{5/2}+1)/2 — as a function of m: ((√m+1)·(e^{5/2}+1)/2) — the mIdb block is (−coef)·(√m+1) with coef = 199.2: new coef = 199.2 + (e^{5/2}+1)/2.\n- The 16.76: merges with mK: mK := −40·1.3352 − 2(e⁴+1)(7(3·2.9²+48) + 3.3) − 1 + 1 → −40·1.3352 − 2(e⁴+1)(7(3·2.9²+48)) − 16.76 − 1 + 1. (The 3.3 inside the (e⁴+1) bracket is REMOVED and the 16.76 appears raw.)\n- mIIM: (−1)·IIMaj → (−1.5)·IIMaj.\n- Everything else unchanged (the Ĥ log-blocks mL1sqb/mL1L2b/mL2sqb/mL1b/mL2b with the 2(e⁴+1)·7Ĥ expansion — the Ĥ inside is UNCHANGED: Hhat = 3Ĉ₀² + 10.5 log + 48 ✓ so the log-block coefficients 42·0.433²·(e⁴+1) etc. are UNCHANGED ✓).\n\nWait — let me double check the Ĥ-block expansion: 2(e⁴+1)·7Ĥ = 2(e⁴+1)·7·(3Ĉ₀² + 10.5 log(T+2) + 48) = 42(e⁴+1)Ĉ₀² + 147(e⁴+1)log(T+2) + 336(e⁴+1). The blocks:\n- mL1sqb: −(42·0.433²·(e⁴+1))·log²(T+2) ✓ unchanged\n- mL1L2b: −(42·2·0.433·0.886·(e⁴+1))·log·loglog ✓ unchanged\n- mL2sqb: −(42·0.886²·(e⁴+1))·loglog² ✓ unchanged\n- mL1b: −((42·2·0.433·2.9 + 147)·(e⁴+1))·log ✓ unchanged\n- mL2b: −(42·2·0.886·2.9·(e⁴+1))·loglog ✓ unchanged\n- mK: the constants −40·1.3352 − 336(e⁴+1) − 2(e⁴+1)·7·3·2.9²·... — wait, the old mK = −40·1.3352 − 2(e⁴+1)(7(3·2.9² + 48) + 3.3) − 1 + 1 — that has the Ĉ₀ constant part 3·2.9² = 25.23·... and the 3.3. New mK = −40·1.3352 − 2(e⁴+1)(7(3·2.9² + 48)) − 16.76 − 1 + 1 — the (7(3·2.9²+48)) = 7·(25.23+48) = 7·73.23 = 512.61 — that's the constant part of 2(e⁴+1)·7Ĥ's Ĉ₀-constant + 48 ✓ — and NO 3.3 (moved to the dog-leg R form) + 16.76 (the 2·8.38).\n\nNow the Bn def itself:\n```\ndef Bn (F : ℝ → ℝ) (n : ℝ) : ℝ :=\n let T := Real.sqrt n + 1\n 4 * F T + 4 * T * ((2 / 3) * Z2hat T + 10.5 * Real.log (T + 2) + 48) +\n 40 * 1.3352 + 2 * (Real.exp 4 + 1) * (7 * Hhat T) +\n 2 * DogLegRight n + IIMaj n + 1\n```\nwith a new def DogLegRight:\n```\ndef DogLegRight (n : ℝ) : ℝ :=\n ((Real.sqrt n + 1) / 2) * (Real.exp (5 / 2) + 1) / 2 + 8.38 + IIMaj n / 4\n```\nAnd 2·DogLegRight = (√n+1)(e^{5/2}+1)/2 + 16.76 + IIMaj/2.\n\nHmm — for the marginExpanded bookkeeping (marginTilde_eq_expanded's ring check), the blocks must sum to exactly marginTilde = sInfty − Bn + 1. The mIdb new coefficient (199.2 + (e^{5/2}+1)/2) and mIIM (−1.5) and mK (−16.76, no 3.3). Let me write the new forms:\n\n```\nprivate def mIdb : ℝ → ℝ := fun m => (-(((8/3)*2.7 + 192) + (Real.exp (5/2) + 1) / 2)) *\n ((1.5 * Real.sqrt m + 1) ... \n```\nWAIT — the mIdb block's function: (−coef)·(√m+1) — the dog-leg's √n-linear part is (√n+1)(e^{5/2}+1)/2 — and mIdb's (−coef)·id(√m+1) — the id block: (−((8/3)·2.7+192))·(Real.sqrt m + 1) — the dog-leg part is ((√m+1)·(e^{5/2}+1)/2) = (e^{5/2}+1)/2·(√m+1) — so the TOTAL coefficient of (√m+1) in margiñ is −((8/3)·2.7+192) [from I_III] − (e^{5/2}+1)/2 [from dog-leg] ✓ — so mIdb_new = (−(((8/3)*2.7 + 192) + (Real.exp (5/2) + 1) / 2))·(Real.sqrt m + 1) ✓ — NOT the 1.5-scaled form (the dog-leg keeps T = √n+1!! — no k-shift — the inner function stays √m+1 ✓✓).\n\nAnd the I_I majorant IIMaj: the Bn's I_I piece is IIMaj(n) [coefficient 1] + dog-leg IIMaj/4 ×2 = IIMaj/2: total 1.5. mIIM = (−1.5)·IIMaj m ✓.\n\nAnd the DogLegRight def + the Bn def. Also marginTilde's def (lockstep with Bn via marginTilde_eq_sub's simp only).\n\nLet me also double-check marginTilde_eq_sub: marginTilde F n = sInftyLower n − Bn F n + 1 — marginTilde's def is literally (sInfty-expression) − (Bn-expression) + 1 — so if I change BOTH consistently, the simp only [marginTilde, Bn, sInftyLower] proof stays ✓.\n\nAnd marginTilde_eq_expanded: the blocks sum to the marginTilde form via ring — the mIdb/mIIM/mK changes are consistent on both sides ✓ ring verifies.\n\nAnd contDiffOn_mIdb: `contDiffOn_const.mul contDiffOn_sqrt_shift` — the block's constant changed (now a sum-of-constants including e^{5/2}) — contDiffOn_const.mul works for any constant ✓ no change needed.\n\nAnd contDiffOn_mIIM: mIIM = (−1.5)·IIMaj — the unfold + contDiffOn_const.mul ✓ unchanged (constant-agnostic).\n\nAnd marginTilde_convex's v-blocks: vId (mIdb's deriv) — the coefficient changed: vId's value = (−new-coef)·(psiOf id (√n+1)/(4n)) — the chain_rule_sqrt_shift_on form ✓ unchanged (constant-agnostic) — just the literal updates. vIIM: (−1.5)·IIMaj″ — the final assembly: 1/(2n) + nonnegs + (−1.5)·IIMaj″ ≥ 1/(2n) − 1.5·IIMaj″ > 0 ⟸ IIMaj″ < 1/(3n) ✓ lt_three + the bridge 1.5·(1/(3n)) = 1/(2n) (field_simp — hmm, the bridge `1.5·(1/(3n)) = 1/(2n)` — field_simp [hn0.ne'] closed it earlier ✓ or div_eq_div_iff).\n\nAnd the mK constant block deriv2_const_val ✓ unchanged (constant).\n\nSo the a2-i edits:\n1. `DogLegRight` def (new).\n2. `Bn` def: horizontal share → 2(e⁴+1)(7Ĥ) + 2·DogLegRight n.\n3. `marginTilde` def: lockstep.\n4. `marginExpanded` blocks: mIdb (new coefficient), mIIM (−1.5), mK (new).\n5. marginTilde_eq_expanded/eq_sub (should be ring/simp-clean).\n6. contDiffOn_mIdb/mIIM (probably fine as-is).\n7. marginTilde_convex's vId/vIIM literals + final linarith (the 1.5 bridge).\n\nThen a2-ii: base points (LiBasePoints rebuild at the new Bn — targets margin(8e4) ≈ 13 160, margin(10⁵) ≈ 88 911 — vs E-034's margins computed with Bn_DL: 13 160.089 / 88 910.825 — hmm — E-034's Bn_DL used 2·DogLegRight with VRightBound = IIMaj/4 ✓ same as the new Bn ✓ margins match ✓) + endpoint margins.\n\nWait — one nuance: E-034's Bn_DL has `2 * (e^4 + 1) * (7 * Hhat(T))` (no +3.3, replaced by DogLegRight) ✓ matches the new Bn's structure ✓. And E-034's margins (13 160.089 / 88 910.825 / 2.458e26) are computed with the certified-constant form (e^{5/2}+1 ≤ 13.19 charged as E52P1 = 13.19 ✓ same as Lean's (Real.exp (5/2)+1)/2 with the true exp value ✓ — hmm — the Lean Bn uses Real.exp (5/2) (the TRUE exp) while E-034 charges 13.19 ≥ e^{5/2}+1 = 13.182 — the Lean Bn uses the TRUE exp (5/2)+1 = 13.182+1 = 14.182?? — wait: Real.exp (5/2) = 12.1825, +1 = 13.1825 — E-034's E52P1 = 13.19 (charged upper) — so E-034's Bn_DL is SLIGHTLY bigger (13.19 vs 13.1825) than the Lean Bn (true 13.1825) — the margins differ by ~2·(13.19−13.1825)/2·(√n+1)·... ≈ 2·0.00375·(√n+1) ≈ 2 units at 8e4 — negligible ✓. So E-034's margins ≈ the Lean margins to within a few units ✓ targets fine.\n\nLet me start the a2-i edits. First the DogLegRight + Bn defs.","signature":""},{"type":"text","text":"Cherry-pick committed (`e11ad95`). Now **ii′-6-a2-i**: the Bn dog-leg redefinition. Starting with the `DogLegRight` def and the Bn/marginTilde/block updates."},{"type":"tool_use","id":"TodoWrite_591","name":"TodoWrite","input":{"todos":[{"content":"Cherry-pick bracket < 4/3 + IIMaj_deriv2_lt_three onto master (committed e11ad95)","status":"completed","activeForm":"Cherry-picking the bracket strengthening"},{"content":"ii′-6-a2-i: DogLegRight def + Bn/marginTilde/marginExpanded/mK dog-leg redefinition + eq_expanded/eq_sub + contDiffOn + convexity literals","status":"in_progress","activeForm":"Redefining Bn at the dog-leg constants"},{"content":"ii′-6-a2-ii: base-point re-certification (LiBasePoints at the new Bn) + endpoint margins","status":"pending","activeForm":"Re-certifying base points"},{"content":"Full build + axiom audit + commit ii′-6-a2; then ii′-6-c per the return map","status":"pending","activeForm":"Closing ii′-6-a2"}]},"extra_content":null},{"type":"tool_use","id":"Read_592","name":"Read","input":{"file_path":"D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiSkeleton.lean","offset":2421,"limit":45},"extra_content":null}]