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Session 30 — ii′-5e squeeze capstone + 5f perimeter repair

08-24-2026 → 08-24-2026 · kimi-k3 · 99 messages · 1641.0k tokens · $39.0712

Summary

Focus: ii′-5e capstone + ii′-5f start (research sessions 034–035).

What happened:

  • 5e-v-d: the Schwarz squeeze ⟹ partialFraction_identity PROVED (ζ′/ζ = B + series − 1/s − 1/(s−1) + ½log π − ½ψ(s/2)), modulo only the declared perimeter.
  • 5f-0: ZeroCountProp strengthened to the mult-weighted form (second encoding-defect repair); perimeter additions ZeroCountProp2 + NoLowZeros approved.
  • 5f-i/ii: pieces 1, 2, 4, 5, 6 of the tight-constant decomposition.

Outcome: the partial-fraction identity — the analytic heart of the R-bound — was machine-proved.

99 message(s) shown — click any card's “open ⤢” for line-by-line navigation
#1673 user 2026-08-24 05:31:42.028 UTC open ⤢
check where we are with the NGUYEN-RH-1 project
#1674 assistant 2026-08-24 05:31:51.447 UTC · 43731→117 tok open ⤢
thinking (197 chars)
The user wants a status check on the NGUYEN-RH-1 project. Per the session START protocol (§8.3): Read STATE.md first, then skim latest journal entry + results/index.md. Let me read STATE.md first.
Reading the resume point per session protocol.
tool: Read
input
{
  "file_path": "D:\\Python\\Quantum\\STATE.md"
}
#1675 assistant 2026-08-24 05:32:34.290 UTC · 7985→1321 tok open ⤢
thinking (2360 chars)
The user asked where we are with the project. STATE.md gives the full picture. Let me also quickly verify the git state and check the latest journal entry exists. Actually, STATE.md is comprehensive and was just updated (session 033 closure is the most recent commit per git status). The git status snapshot shows some untracked LaTeX build artifacts (draft.bbl, paperA.pdf etc.) but the last commit is "Session 033 closure" — so the archive is in a clean committed state. I should give a concise status summary. Key points: 1. **Big picture**: Phases 0, 1, 3, 4 COMPLETE. Phase 2 (Track B spectral) mapped to exhaustion at current technology. Phase 5 (Verification & Write-up) in progress — paper written, honesty audit done, Lean formalization deep in progress. 2. **Current focus**: Phase 5B / Tier ii′ — closing `SfBoundProp` in Lean before Paper A submission (user directive). This is the last non-perimeter hypothesis in the finite-height Li theorem (R-004). 3. **Where exactly**: ii′-5e-v-c COMPLETE (session 033, today per the git log). Next is ii′-5e-v-d: the Schwarz squeeze ⟹ capstone `partialFraction_identity`. Then ii′-5f (tight constants), ii′-3b/3c (moments + crux), ii′-6 (L0 assembly), ii′-7 (closure). 4. **Build state**: green, 8766 jobs (need to verify LiCircleBound isn't root-imported yet — STATE says not yet root-imported). 5. **Paper A**: submission-ready, frozen under the freeze protocol. 6. **No blockers.** Untracked files in git status: LaTeX build artifacts (.bbl, .blg, .fdb_latexmk, .fls, .pdf) and research/paper/submit/ — these are build artifacts, probably fine to leave untracked (draft.pdf is gitignored per handoff notes; interesting that the pdfs show as untracked — maybe only draft.pdf is gitignored). Let me keep the response concise. Maybe I should also verify the working tree state quickly with git log to confirm session 033 is committed. The gitStatus snapshot at conversation start already shows: last commit df4e083 "Session 033 closure: journal + STATE + NGUYEN + db (ii'-5e-v-c COMPLETE: the Fexpr circle bound)". So everything is committed except untracked LaTeX build artifacts. I'll give a status summary organized by: where we are (headline), the active thread (tier ii′ progress bar), what just finished (session 033), what's next (session 034: ii′-5e-v-d), and standing items. Keep it tight.
**NGUYEN-RH-1 status — Session 033 committed clean, no blockers.** ## Big picture - **Phases 0, 1, 3, 4 — COMPLETE.** Track A (certificates) hit its documented ceiling (D-013, monitoring mode); Track C produced **R-004**: the explicit finite-height Li theorem (λ_n > 0 for all n ≤ N₁ ≈ 9×10²⁴), ledger #6. - **Phase 2 (Track B spectral)** — mapped to exhaustion at current technology (tasks 2.6–2.13 all answered; parked). - **Phase 5 (write-up/verification)** — paper written (5.3 ✔), honesty audit done (5.4 ✔), Lean skeleton + tier (i) + tier (ii) steps 1–2 PROVED. ## The headline result's Lean status `lambda_pos_finite_height_verified` is proved modulo exactly **3 hypotheses**: `RHUpTo 3×10¹²`, `LiVerifiedUpTo 5×10⁵` (declared computational perimeter), and `SfBoundProp`. PrintAxioms = 3 standard axioms only. ## Active thread: Tier ii′ (Phase 5B) Per your directive, `SfBoundProp` is being closed in Lean **before** Paper A submission (Paper A frozen but submission-ready throughout). Progress through the sub-stage map: - ii′-0 through ii′-4 ✔ (design, liCoeff defect repair, residue machinery, swaps, (4.10) pieces A+B, contour/kernel lemmas) - ii′-5a→5d ✔ (loose R-bound ≤ 10⁵(log|t|)² right half-plane, ≤ 2×10⁵(log|t|)² left, via Davenport disc + Blaschke + Borel–Carathéodory + FE reflection) - ii′-5e (partial-fraction identity) — **0, i, ii, iii, iv, v-a/b/c all ✔**; session 033 just landed `Fexpr_circle_le` (the Fexpr circle bound). Build green, all audits 3 standard axioms only. ## Next action (Session 034) **ii′-5e-v-d** — the Schwarz squeeze: `Fexpr_circle_le` + max-modulus + Schwarz lemma ⟹ the growth of the entire function `Gentire` is sub-linear ⟹ `Gentire ≡ const =: B` ⟹ the capstone `partialFraction_identity` under `ZeroCountProp`. All inputs are in hand; the design is spelled out step-by-step in STATE.md (§NEXT ACTION). Then: ii′-5f (tight constants A=10.5, B₀=48) → ii′-3b (moments) → ii′-3c (crux Sf = Res₁) → ii′-6 (L0 assembly) → ii′-7 (closure + paper Appendix B + tag upgrade). Standing items: your read-through of paperA.pdf (nothing blocks it), repo-publication prep, Paper B Task 1 (R-003 bookkeeping, renumbered D-065) queued after ii′. Ready to start ii′-5e-v-d whenever you are.
#1676 user 2026-08-24 05:43:35.416 UTC open ⤢
Let's start ii′-5e-v-d
#1677 assistant 2026-08-24 05:44:55.529 UTC · 1397→2209 tok open ⤢
thinking (5127 chars)
The user wants to start ii′-5e-v-d — the Schwarz squeeze ⟹ the ∃ B capstone `partialFraction_identity`. Per STATE.md, the design is: 1. **Every circle point is good** (¬badPoint s: not nontrivial (3a), ≠ 0/1 (norms), ≠ −2n (R/2 ∉ ℤ by hgapInt)) ⟹ Gentire s = Fexpr s (5e-iv's gentire_eq_Fexpr) ⟹ ‖Gentire‖ ≤ the same bound on the sphere. 2. **MapsTo**: Gentire differentiable on ball 0 R (from gentire_analyticAt_and_eq.1) + Zeta23's AnalyticOn.norm_le_of_norm_le_on_sphere ⟹ MapsTo (ball 0 R) into closedBall (Gentire 0) (R₂(R) + 1) with R₂(R) := 2·lowZeroConst + dirichletC2 + 400000·A₀·Ĉ₀(R+2)·(log R)² + ‖Gentire 0‖. 3. **Schwarz**: Complex.dist_le_div_mul_dist_of_mapsTo_ball (ball-form; bridge via ball ⊆ closedBall and R₂ < R₂+1): dist (Gentire z₀) (Gentire 0) ≤ (R₂(R)+1)/R·‖z₀‖ for ‖z₀‖ < R. 4. **The ratio → 0**: Ĉ₀(R+2) ≤ 5·log R (log(R+4) ≤ 2·log R for R ≥ 3; loglog ≤ 1+log; L ≥ 9) ⟹ R₂(R)+1 ≤ C₀' + 2.01·10⁶·A₀·(log R)³ (symbolic C₀') ⟹ (R₂+1)/R ≤ (C₀'+64·2.01·10⁶·A₀)·R^{−1/4} via log R ≤ 4·R^{1/4} (Real.log_le_rpow — CHECK exists: 1 ≤ x, 0 < r ⟹ log x ≤ r⁻¹·x^r) ⟹ (log R)³ ≤ 64·R^{3/4} (rpow arithmetic). For fixed z₀: pick k with 4k+5/2 > max(‖z₀‖, (C·‖z₀‖/ε)⁴) ⟹ dist < ε ⟹ dist (Gentire z₀) (Gentire 0) = 0 ⟹ **Gentire ≡ Gentire 0 =: B**. 5. **Capstone** (D-068 §5): `partialFraction_identity (hZC : ZeroCountProp) : ∃ B : ℂ, ∀ s, riemannZeta s ≠ 0 → s ≠ 0 → s ≠ 1 → (∀ n ≥ 1, s ≠ −2n) → logDeriv riemannZeta s = B + seriesFun s − 1/s − 1/(s−1) + (Real.log Real.pi)/2 − Complex.digamma (s/2)/2` — from Gentire s = Fexpr s at good points (5e-iv) + Gentire ≡ B: Fexpr unfolds to exactly this. Per session protocol: 1. First read journal-033 for the gotchas + exact statement of Fexpr_circle_le, and journal-030/032 as referenced. 2. Look at the current LiCircleBound.lean structure to see where to add things (§13 or new file LiSqueeze.lean). 3. Check key Mathlib/Zeta23 lemmas exist: AnalyticOn.norm_le_of_norm_le_on_sphere, Complex.dist_le_div_mul_dist_of_mapsTo_ball, Real.log_le_rpow. Let me set up a task list and start. First reads: - research/journal/session-033.md (gotchas + state) - The end of LiCircleBound.lean (Fexpr_circle_le statement + what's around it) - LiFEntire.lean capstone statement (gentire_analyticAt_and_eq) Let me plan the work: **Sub-stage plan for 5e-v-d:** 1. Read journals (033 for latest gotchas), D-068 §5 (capstone design), tail of LiCircleBound.lean, relevant parts of LiFEntire.lean. 2. Verify Mathlib lemma names: `Complex.dist_le_div_mul_dist_of_mapsTo_ball` (the Schwarz lemma for ball maps), `Real.log_le_rpow` or similar (log x ≤ r⁻¹ x^r). 3. Build the steps: - Step 1: `gentire_circle_le`: on the gap circle, ‖Gentire s‖ ≤ R₂bound (from Fexpr_circle_le + gentire_eq_Fexpr + every circle point good). - Step 2: MapsTo from norm_le_of_norm_le_on_sphere (need to check the exact Zeta23 name — it might be `DifferentiableOn.norm_le_of_norm_le_on_sphere` or in Zeta23). - Step 3: Schwarz bound. - Step 4: ratio → 0, constancy via picking k large. - Step 5: capstone partialFraction_identity. 4. Build, audit, commit at clean boundaries. Note the ZeroCountProp hypothesis: the gap circles exist under ZeroCountProp (perimeter). The capstone takes (hZC : ZeroCountProp). Also note: Gentire 0 — what's its value? At s=0, Gentire is the punctured limit. We don't need to evaluate it; B := Gentire 0. Wait — actually in the capstone statement, the identity is logDeriv ζ s = B + seriesFun s − 1/s − 1/(s−1) + (log π)/2 − ψ(s/2)/2. Fexpr s = logDeriv ζ s − seriesFun s + 1/s + 1/(s−1) − (log π)/2 + ψ(s/2)/2. So Fexpr s = B ⟹ logDeriv ζ s = B + seriesFun s − 1/s − 1/(s−1) + (log π)/2 − ψ(s/2)/2. Yes exactly. Good. Note B is known to be γ + (log 4π)/2... wait, actually the constant in the partial fraction identity: ζ′/ζ(s) = B + Σ_ρ (1/(s−ρ) + 1/ρ) − 1/s − 1/(s−1) + (log π)/2 − (1/2)ψ(s/2) where B = −1 − γ/2 + log(4π)/2... Actually in Lagarias' convention, ζ′/ζ(s) = log 2π − 1 − γ/2 − 1/(s−1) ... let me not worry; the capstone just says ∃ B. The tight-constant stage (5f) might need B's value, but that's for later. Actually for the moment identity ii′-3b we may need B = −1 − γ/2 + log(4π)... wait no — the D-068 design says capstone is ∃ B. Fine. Actually hold on — one nuance: is it known that Gentire 0 is the right B? The identity at good points: Fexpr s = Gentire s = Gentire 0 = B for all good s. So B := Gentire 0. Fine, no evaluation needed. Let me start. First, read the journals and files. I'll read: - research/journal/session-033.md - research/derivations/D-068-*.md (find the file) - The tail of research/lean/NguyenRH1/NguyenRH1/LiCircleBound.lean - LiFEntire.lean capstone region Let me find files first. LiCircleBound.lean is at research/lean/NguyenRH1/NguyenRH1/LiCircleBound.lean presumably (package NguyenRH1 with root NguyenRH1). Let me glob. Also create the task list with TaskCreate... wait, the tools available: TaskCreate is deferred. I have TodoWrite available directly. Actually looking at the tools: TodoWrite is available. TaskCreate is deferred. I'll use TodoWrite. Let me start by reading key files in parallel.
Starting ii′-5e-v-d. Per STATE.md, all inputs are in hand; the design has 5 steps. Let me set up the task list and read the latest state first.
tool: TodoWrite
input
{
  "todos": [
    {
      "content": "Read journal-033 + D-068 \u00a75 + tails of LiCircleBound/LiFEntire",
      "status": "in_progress",
      "activeForm": "Reading journals and Lean file state"
    },
    {
      "content": "Verify Mathlib/Zeta23 lemma names (Schwarz ball-form, log_rpow, norm_le_on_sphere)",
      "status": "pending",
      "activeForm": "Verifying lemma names"
    },
    {
      "content": "Step 1: gentire_circle_le (circle points good \u27f9 Gentire = Fexpr bound)",
      "status": "pending",
      "activeForm": "Building gentire_circle_le"
    },
    {
      "content": "Step 2: MapsTo (ball 0 R) into closedBall (Gentire 0) (R\u2082+1)",
      "status": "pending",
      "activeForm": "Building MapsTo step"
    },
    {
      "content": "Step 3: Schwarz dist bound for fixed z\u2080",
      "status": "pending",
      "activeForm": "Building Schwarz step"
    },
    {
      "content": "Step 4: ratio \u2192 0 \u27f9 Gentire \u2261 Gentire 0 =: B",
      "status": "pending",
      "activeForm": "Building constancy argument"
    },
    {
      "content": "Step 5: capstone partialFraction_identity (hZC : ZeroCountProp)",
      "status": "pending",
      "activeForm": "Building the capstone"
    },
    {
      "content": "Build green + axiom audit + commit + session 034 journal",
      "status": "pending",
      "activeForm": "Building, auditing, committing"
    }
  ]
}
#1678 assistant 2026-08-24 05:45:29.638 UTC · 7400→346 tok open ⤢
thinking (139 chars)
Now let me read the tail of LiCircleBound.lean to see the Fexpr_circle_le statement and its hypotheses, and the capstone of LiFEntire.lean.
Now the tail of LiCircleBound.lean (the `Fexpr_circle_le` signature + hypotheses) and the LiFEntire capstone.
tool: Bash
input
{
  "command": "grep -n \"theorem Fexpr_circle_le\\|theorem gentire\\|def Fexpr\\|def Gentire\\|def badPoint\\|gentire_eq_Fexpr\\|gentire_analyticAt_and_eq\\|section\\|^end\" D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1/LiCircleBound.lean | tail -40",
  "description": "Find Fexpr_circle_le signature and section structure in LiCircleBound"
}
tool: Bash
input
{
  "command": "grep -n \"theorem gentire_analyticAt_and_eq\\|theorem gentire_eq_Fexpr\\|def Gentire\\|def Fexpr\\|def badPoint\\|noncomputable\" D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1/LiFEntire.lean",
  "description": "Find Gentire/Fexpr capstone declarations in LiFEntire"
}
#1679 assistant 2026-08-24 05:47:21.129 UTC · 856→297 tok open ⤢
thinking (343 chars)
Both exist: - `Complex.dist_le_div_mul_dist_of_mapsTo_ball (hd : DifferentiableOn ℂ f (ball c R₁)) ...` at Schwarz.lean:190. Let me read its full signature. - `Real.log_le_rpow_div {x ε : ℝ} (hx : 0 ≤ x) (hε : 0 < ε) : log x ≤ x ^ ε / ε` — so log x ≤ x^ε / ε. With ε = 1/4: log x ≤ 4·x^{1/4}. Let me read the Schwarz lemma signature in full.
Both exist. Reading the exact Schwarz signature and the Zeta23 sphere lemma.
tool: Bash
input
{
  "command": "M=D:/Python/Quantum/zeta-23-lean/.lake/packages/mathlib/Mathlib; sed -n '180,215p' $M/Analysis/Complex/Schwarz.lean; echo ===; sed -n '25,60p' D:/Python/Quantum/zeta-23-lean/Zeta23/FromPNTPlus/StrongPNTPrefix.lean",
  "description": "Read Schwarz lemma and sphere lemma signatures"
}
#1680 assistant 2026-08-24 05:51:53.248 UTC · 1528→7858 tok open ⤢
thinking (18169 chars)
All three key lemmas verified: 1. **`Complex.dist_le_div_mul_dist_of_mapsTo_ball`** (Mathlib Schwarz.lean:190): ```lean theorem dist_le_div_mul_dist_of_mapsTo_ball (hd : DifferentiableOn ℂ f (ball c R₁)) (h_maps : MapsTo f (ball c R₁) (closedBall (f c) R₂)) (hz : z ∈ ball c R₁) : dist (f z) (f c) ≤ R₂ / R₁ * dist z c ``` 2. **`AnalyticOn.norm_le_of_norm_le_on_sphere`** (Zeta23 StrongPNTPrefix.lean:33): ```lean lemma AnalyticOn.norm_le_of_norm_le_on_sphere {C r R : ℝ} {f : ℂ → ℂ} {w : ℂ} (hyp_r : r ≤ R) (analytic : AnalyticOn ℂ f (Metric.closedBall 0 R)) (cond : ∀ z ∈ Metric.sphere 0 r, ‖f z‖ ≤ C) (wInS : w ∈ Metric.closedBall 0 r) : ‖f w‖ ≤ C ``` 3. **`Real.log_le_rpow_div {x ε : ℝ} (hx : 0 ≤ x) (hε : 0 < ε) : log x ≤ x ^ ε / ε`** — with ε = 1/4: log x ≤ 4·x^{1/4}. Now the plan for 5e-v-d. Design (STATE.md §NEXT ACTION): **Step 1** `gentire_circle_le`: for k ≥ 4000, R gap circle, ‖s‖ = R ⟹ ‖Gentire s‖ ≤ RB R where RB R := 2·lowZeroConst + dirichletC2 + 400000·A0count·C0hat (R+2)·(log R)². To get this: Gentire s = Fexpr s needs ¬ badPoint s: - ¬ IsNontrivialZero s: from `not_isNontrivialZero_on_gapCircle hk hRlo hgap hs` (already used in Fexpr_circle_le). - s ≠ 0: ‖s‖ = R ≥ 16002 > 0. - s ≠ 1: ‖s‖ = R ≠ ‖1‖ = 1. - ¬ ∃ n ≥ 1, s = −2n: if s = −2·(n:ℂ), then s.re = −2n, so R/2 = ‖s‖/2 = |re s|... hmm wait. ‖s‖ = R and s = −2n gives R = ‖−2n‖ = 2n, so R/2 = n ∈ ℤ, contradicting hgapInt with m = n: |R/2 − n| = 0 < 1/4. Good — need hgapInt here. **Step 2** MapsTo: Gentire differentiable on ball 0 R. From gentire_analyticAt_and_eq.1: ∀ s, AnalyticAt ℂ Gentire s. So DifferentiableOn ℂ Gentire (ball 0 R) — via fun s hs => (gentire_analyticAt_and_eq.1 s).differentiableAt.differentiableWithinAt. Actually AnalyticAt.differentiableAt : AnalyticAt ℂ f s → DifferentiableAt ℂ f s. Then DifferentiableOn. Then: for w ∈ ball 0 R, ‖w‖ < R. Use the sphere lemma with r := ‖w‖... hmm wait. Actually the standard approach: we want MapsTo Gentire (ball 0 R) (closedBall (Gentire 0) (R₂+1)) where R₂ := RB R + ‖Gentire 0‖. Wait, actually the sphere lemma gives ‖Gentire w‖ ≤ C for w ∈ closedBall 0 r where the bound C holds on sphere 0 r. For w with ‖w‖ < R: take r := max ‖w‖ something... hmm, simpler: for each w ∈ ball 0 R, choose r := (‖w‖ + R)/2 ∈ (‖w‖, R)? But then the circle bound on sphere 0 r requires r to be a GAP circle radius — which it isn't in general! The bound ‖Fexpr‖ ≤ RB only holds on the special gap circles. Hmm wait. Let me re-think. The circle bound holds only on gap circles R_k. But R_k ∈ [4k+5/2, 4k+3] for each k. For a FIXED z₀, we pick k large enough that 4k+5/2 > ‖z₀‖, i.e., z₀ ∈ ball 0 R_k, and then: - Gentire analytic on closedBall 0 R_k (entire). - On sphere 0 R_k: ‖Gentire‖ ≤ RB R_k (step 1, using the gap-circle properties of R_k from exists_gapCircle_radius). - By sphere lemma (max modulus): ‖Gentire z₀‖ ≤ RB R_k as well. So actually we don't need MapsTo on every ball — only on the gap-circle balls. Then: dist (Gentire z₀) (Gentire 0) ≤ ‖Gentire z₀‖ + ‖Gentire 0‖ ≤ RB R_k + ‖Gentire 0‖. That's the naive triangle bound, which doesn't give → 0. We need the Schwarz lemma: apply Schwarz to f = Gentire on ball 0 R_k mapping into closedBall (Gentire 0) (RB R_k + ‖Gentire 0‖): MapsTo Gentire (ball 0 R_k) (closedBall (Gentire 0) (RB R_k + ‖Gentire 0‖)): for z ∈ ball 0 R_k, ‖Gentire z‖ ≤ RB R_k (max modulus on ball from sphere bound — using AnalyticOn.norm_le_of_norm_le_on_sphere with r = R_k, R = R_k, w ∈ closedBall 0 R_k) and dist (Gentire z) (Gentire 0) ≤ ‖Gentire z‖ + ‖Gentire 0‖ ≤ RB R_k + ‖Gentire 0‖. ✓. Then Schwarz: dist (Gentire z₀) (Gentire 0) ≤ (RB R_k + ‖Gentire 0‖)/R_k · dist z₀ 0 = (RB R_k + ‖Gentire 0‖)/R_k · ‖z₀‖. **Step 4**: (RB R_k + ‖Gentire 0‖)/R_k → 0 as k → ∞. RB R = 2·lowZeroConst + dirichletC2 + 400000·A₀·Ĉ₀(R+2)·(log R)². Need: Ĉ₀(R+2) growth bound. What is C0hat? Let me check its definition. From STATE.md: "Ĉ₀(R+2) ≤ 5·log R (log(R+4) ≤ 2·log R for R ≥ 3; loglog ≤ 1+log; L ≥ 9)". Let me check the actual definition of C0hat. Then (RB R_k + ‖Gentire 0‖)/R_k ≤ (C + C'·(log R_k)³)/R_k with (log R)³ ≤ 64·R^{3/4} via Real.log_le_rpow_div with ε=1/4: log R ≤ R^{1/4}/(1/4) = 4·R^{1/4}, so (log R)³ ≤ 64 R^{3/4}. And R^{3/4}/R = R^{-1/4} → 0... but we don't need a limit — we do the direct argument: for fixed z₀ and ε > 0, choose k so large that (C + 64·C'·R_k^{3/4})/R_k < ε/‖z₀‖... Actually the cleanest: show dist (Gentire z₀) (Gentire 0) < ε for all ε > 0, hence = 0 (dist_eq_zero / eq_of_dist_eq_zero... the lemma: dist_lt_of... we use `dist_eq_zero` after showing ∀ ε>0, dist < ε — there's a lemma like `dist_le_zero`... The pattern: by_contra h; set ε := dist/2 > 0; get dist < ε contradiction. Or `eq_of_forall_dist_le` hmm. There's `dist_eq_zero : dist x y = 0 ↔ x = y`. And to show dist = 0: le_antisymm (le_of_forall_pos_le_add or le_of_forall_lt...) nonneg. There's the standard `le_of_forall_pos_le_add : (∀ ε > 0, a ≤ b + ε) → a ≤ b`? Hmm, or `le_of_forall_lt'`... Let me think: we show ∀ ε > 0, dist (Gentire z₀) (Gentire 0) ≤ ε. Then by `le_of_forall_le_of...`? Standard: `le_of_forall_pos_le_add` gives dist ≤ 0 from dist ≤ 0 + ε. Actually there's `le_of_forall_lt_imp_le_of_dense`... The cleanest known forms: - `le_of_forall_pos_le_add : (∀ ε : α, 0 < ε → a ≤ b + ε) → a ≤ b` (exists in ordered fields). So show ∀ ε > 0, dist ≤ 0 + ε, i.e., dist ≤ ε. For that: given ε > 0, we need k with (RB R_k + ‖Gentire 0‖)·‖z₀‖/R_k ≤ ε. Bound: (RB R + G)/R ≤ (C₀' + C₁·(log R)³)/R where C₀' = 2·lowZeroConst + dirichletC2 + ‖Gentire 0‖ + ... wait plus we need Ĉ₀(R+2) ≤ 5 log R. Let me check C0hat's definition first. Then (C₀' + C₁·64·R^{3/4})/R = C₀'/R + 64·C₁·R^{-1/4}. To make this ≤ ε: choose R ≥ max((2C₀'/ε), (128·C₁/ε)⁴)... then C₀'/R ≤ ε/2 and 64 C₁ R^{-1/4} ≤ 64 C₁/(128 C₁/ε) = ε/2. ✓ (needs R^{-1/4} manipulation via rpow; R ≥ (128 C₁/ε)⁴ ⟹ R^{1/4} ≥ 128 C₁/ε ⟹ R^{-1/4} ≤ ε/(128 C₁). rpow arithmetic: (R^{1/4})... Let me handle with Real.rpow: R^{3/4}/R = R^{3/4 − 1} = R^{-1/4}. Hmm, dealing with negative rpow in Lean: Real.rpow_neg etc. Alternative cleaner: avoid rpow-negatives by writing: want (C₀' + 64·C₁·R^{3/4}) ≤ ε·R. Since R^{3/4} ≤ R... hmm. Alternative: use log R ≤ R^{1/4}·4 and demand: C₀' ≤ εR/2 AND 64·C₁·R^{3/4} ≤ εR/2. The second: 128·C₁·R^{3/4} ≤ ε·R ⟺ 128·C₁/ε ≤ R^{1/4} ⟺ (128 C₁/ε)⁴ ≤ R. With rpow: R^{3/4} = R^{(3/4:ℝ)} via rpow. Need (R⁴)^{1/4} = R for R ≥ 0: Real.rpow_nat_inv_pow... Actually `Real.rpow_natCast`, `Real.rpow_mul`... There's `Real.rpow_nat_inv_pow_nat (hx : 0 ≤ x) : (x ^ n) ^ ((n:ℝ)⁻¹) = x`? Something like Real.rpow_inv_natCast_pow? Let me just recall: `Real.rpow_natCast`, and the key identity: `Real.rpow_nat_inv_pow_nat {x : ℝ} (hx : 0 ≤ x) {n : ℕ} (hn : n ≠ 0)? : (x ^ n) ^ (n⁻¹ : ℝ) = x`. I believe there's `Real.rpow_inv_natCast_pow (hx : 0 ≤ x) (hn : n ≠ 0) : (x ^ (n:ℝ)) ^ (n:ℝ)⁻¹ = x`? I'll check in Mathlib when building. Alternatively avoid fourth roots: (log R)³ ≤ 64·R^{3/4} and R^{3/4}/R: note R^{3/4} ≤ R is wrong direction... Cleaner approach avoiding rpow division gymnastics: log R ≤ 4·R^{1/4} gives log R ≤ 4·R^{1/4}. Cube: (log R)³ ≤ 64·(R^{1/4})³ = 64·R^{3/4}. Now I want: 64·C₁·(log R)³·.../R ≤ ε/2. Write R = (R^{1/4})⁴: then R^{3/4}/R = 1/R^{1/4}. So need 64·C₁/R^{1/4} ≤ ε/2, i.e., R^{1/4} ≥ 128·C₁/ε, i.e., R ≥ (128·C₁/ε)⁴. In Lean: set Q := R^{(1/4 : ℝ)} (rpow). Then Q⁴ = R? `Real.rpow_nat_inv_pow_nat`: hmm. Let me instead set the choice directly in terms of a real M := max(‖z₀‖+1, (2C₀'/ε), (128 C₁/ε)⁴, 16002...) and pick k with 4k+5/2 ≥ M (exists by Archimedean: ∃ k:ℕ, M ≤ 4k — exists_nat_ge style). Then R_k ≥ 4k+5/2 ≥ M. Then: - C₀'/R ≤ C₀'/M ≤ ε/2 if M ≥ 2C₀'/ε (need C₀' ≥ 0 for the division monotonicity). - For the rpow part: R ≥ (128C₁/ε)⁴ ⟹ R^{1/4} ≥ ((128C₁/ε)⁴)^{1/4} = 128C₁/ε (using rpow monotonicity Real.rpow_le_rpow with 0 ≤ base and exponent 1/4 ≥ 0, and the identity (x⁴)^{1/4} = x). Then 64·C₁·R^{3/4}/R = 64·C₁·(R^{1/4})³/(R^{1/4})⁴ = 64·C₁/R^{1/4} ≤ 64·C₁·ε/(128·C₁) = ε/2. To do this cleanly in Lean I need R = (R^{1/4})⁴: `Real.rpow_nat_inv_pow_nat`? Let me search Mathlib for the exact lemma name later. Options: `Real.rpow_mul (hx : 0 ≤ x) (y z : ℝ) : x ^ (y * z) = (x ^ y) ^ z`. So R = R^1 = R^{(1/4)·4} = (R^{1/4})⁴ = ((R^{1/4}))^((4:ℕ):ℝ) = (R^{1/4})^4 via rpow_natCast. That works: R^(1/4 * 4) = R^1 = R. So set Q := R^(1/4:ℝ); R = Q^4. Then (log R)³ ≤ 64·Q³. And (C₀' + 64·C₁·Q³·... hmm wait I need to redo: RB R + ‖Gentire 0‖ ≤ C₀' + C₁·(log R)³ where C₁ = 400000·A₀·5 = 2·10⁶·A₀ (if Ĉ₀(R+2) ≤ 5 log R). Then numerator ≤ C₀' + C₁·64·Q³. Then numerator/R ≤ ε: suffices C₀' ≤ ε/2·Q⁴/... hmm — I set it up as: C₀'/R ≤ ε/2 and 64 C₁ Q³/Q⁴ ≤ ε/2. OK this is all standard real-number grinding. The nlinarith/linear tools won't handle rpow, so I'll convert: once Q ≥ max(128·C₁/ε, (2C₀'/ε)^{1/4}...)... Actually simpler to put both conditions in terms of Q: want C₀' ≤ (ε/2)·Q⁴ and 64·C₁ ≤ (ε/2)·Q. Two conditions: Q ≥ 128·C₁/ε and Q⁴ ≥ 2·C₀'/ε. Take Q ≥ max(128C₁/ε, (2C₀'/ε)^{1/4})... ugh, fourth root of C₀' — instead: Q ≥ max(128 C₁/ε, 2C₀'/ε) hmm no: if Q ≥ 2C₀'/ε and Q ≥ 1 then Q⁴ ≥ Q ≥ 2C₀'/ε ✓. So: Q ≥ max(1, 128·C₁/ε, 2·C₀'/ε). Then: - 64·C₁ ≤ (ε/2)·Q ⟹ 64·C₁·Q³ ≤ (ε/2)·Q⁴ ✓ (multiply by Q³ ≥ 0). - C₀' ≤ (ε/2)·Q ≤ (ε/2)·Q⁴ ✓ (Q ≥ 1 ⟹ Q ≤ Q⁴). Sum: C₀' + 64·C₁·Q³ ≤ ε·Q⁴ = ε·R ✓. So the condition is Q := R^{1/4} ≥ max(1, (128·C₁ + 2·C₀')/ε)-ish. And R = Q⁴ ≥ ((...)/ε)⁴. So choose M := max(‖z₀‖ + 1, 16002, ((128·C₁ + 2·C₀' + 1)/ε)⁴) — then R ≥ M gives Q = R^{1/4} ≥ M^{1/4} ≥ (128 C₁ + 2 C₀' + 1)/ε via rpow monotonicity + (x⁴)^{1/4} = x. The rpow identity needed: (M^{1/4})⁴... I need M^{1/4} ≥ c where M ≥ c⁴: Real.rpow_le_rpow (0 ≤ c⁴... base monotonicity: c⁴ ≤ M, exponent 1/4 ≥ 0 ⟹ (c⁴)^{1/4} ≤ M^{1/4}; and (c⁴)^{1/4} = c for c ≥ 0: via Real.rpow_nat_inv_pow_nat or rpow_mul: (c⁴)^{1/4} = c^{4·(1/4)} = c^1 = c. rpow_mul needs 0 ≤ c: c^(4*1/4) = (c^4)^(1/4)... the direction: `Real.rpow_mul (hx : 0 ≤ x) (y z : ℝ) : x ^ (y * z) = (x ^ y) ^ z`. So (c^4)^((1/4):ℝ) hmm: c^((4:ℝ)·(1/4)) = (c^(4:ℝ))^(1/4). And c^(4:ℝ) = c^4 (rpow_natCast). 4·(1/4) = 1, c^1 = c (rpow_one). So (c^4)^(1/4:ℝ) = c after rewriting 4*(1/4)=1 — but rw inside exponent: `show c ^ (((4:ℝ) * (4:ℝ)⁻¹)) = ...`; the arithmetic 4 * (1/4) = 1 needs norm_num inside the exponent position — doable via `congr` or `rw [show (4:ℝ)*(1/4) = 1 by norm_num]`? The term is `c ^ ((4:ℝ) * (1/4))` — `rw [mul_inv_cancel₀]`? hmm (1/4) is 4⁻¹ defeq? (1/4 : ℝ) = 4⁻¹ is defeq (OneDiv). Might be easier to use exponent (0.25) no... Let me just use `Real.rpow_nat_inv_pow_nat`: searching memory — I believe Mathlib has `Real.rpow_nat_inv_pow_nat {x : ℝ} (hx : 0 ≤ x) {n : ℕ} (hn : n ≠ 0)? : (x ^ n) ^ ((n : ℝ)⁻¹) = x`? There's definitely `Real.rpow_inv_natCast_pow`? I'll grep Mathlib when writing the code. And (1/4 : ℝ) = (4:ℝ)⁻¹ by norm_num1 or `one_div`. Fine — details at build time. Also need: (log R)³ ≤ 64·R^{3/4}: from log R ≤ R^{1/4}/(1/4) = 4·Q. Cube both sides (log R ≥ 9 ≥ 0, so pow monotone): (log R)³ ≤ (4Q)³ = 64 Q³. And R^{3/4} = Q³: (Q^4)^{3/4} = Q^3 — same rpow juggling: R^{(3/4:ℝ)} = (Q^4)^{3/4}... Alternatively skip R^{3/4} entirely: work wholly in Q: numerator bound C₀' + 64·C₁·Q³, denominator R = Q⁴. Never mention R^{3/4}. Now — the Ĉ₀(R+2) ≤ 5·log R bound. Need C0hat's definition. Let me grep. From the R-chain: C0hat is presumably defined in LiContour.lean or LiSkeleton as something like 3·log(x)·log(log x) or the Trudgian shape. STATE.md says: "Ĉ₀(R+2) ≤ 5·log R (log(R+4) ≤ 2·log R for R ≥ 3; loglog ≤ 1+log; L ≥ 9)". So C0hat(x) involves log·loglog presumably. Let me check. Also `lowZeroConst`, `dirichletC2`, `A0count` are the constants. C₀' := 2·lowZeroConst + dirichletC2 + ‖Gentire 0‖ and C₁ := 400000·A0count·5 = 2·10⁶·A0count. Wait, careful: the Schwarz application: h_maps : MapsTo Gentire (ball 0 R_k) (closedBall (Gentire 0) R₂) with R₂ := (RB R_k + ‖Gentire 0‖). For z ∈ ball: dist (Gentire z) (Gentire 0) ≤ ‖Gentire z − Gentire 0‖ ≤ ‖Gentire z‖ + ‖Gentire 0‖ ≤ RB R_k + ‖Gentire 0‖ where ‖Gentire z‖ ≤ RB R_k comes from the sphere lemma applied at radius... hmm — z ∈ ball 0 R_k, and the sphere bound is on sphere 0 R_k. AnalyticOn.norm_le_of_norm_le_on_sphere with r = R := R_k, analytic on closedBall 0 R_k, w ∈ closedBall 0 R_k (z ∈ ball ⊂ closedBall). Wait the signature: (hyp_r : r ≤ R) (analytic : AnalyticOn ℂ f (closedBall 0 R)) (cond : ∀ z ∈ sphere 0 r, ‖f z‖ ≤ C) (wInS : w ∈ closedBall 0 r). With r = R = R_k: analytic: AnalyticOn ℂ Gentire (closedBall 0 R_k) — from ∀ s, AnalyticAt ℂ Gentire s: AnalyticOnNhd, then .analyticOn. AnalyticOnNhd ℂ Gentire (closedBall 0 R_k) := fun s _ => gentire_analyticAt_and_eq.1 s. Then AnalyticOnNhd.analyticOn. Hmm wait, but actually is the sphere 0 R_k in Metric vs the ‖s‖ = R hypothesis — sphere 0 R = {s : ‖s‖ = R}? Metric.sphere (0:ℂ) R = {s | dist s 0 = R} = {s | ‖s‖ = R} (dist_eq_norm, sub_zero). Fine — a mem-sphere to ‖·‖=R bridge: `Metric.mem_sphere`, dist_eq_norm, norm_sub... s - 0 = s (sub_zero). Standard. So cond: ∀ z ∈ Metric.sphere 0 R_k, ‖Gentire z‖ ≤ RB R_k — from step 1 (gentire_circle_le) applied to each z on the sphere (using the gap properties of R_k from exists_gapCircle_radius hZC (k large)). Then the max-modulus gives: ∀ z ∈ closedBall 0 R_k, ‖Gentire z‖ ≤ RB R_k. Then MapsTo: z ∈ ball 0 R_k ⟹ dist (Gentire z) (Gentire 0) = ‖Gentire z − Gentire 0‖ ≤ ‖Gentire z‖ + ‖Gentire 0‖ ≤ RB R_k + ‖Gentire 0‖ =: R₂. mem_closedBall: dist z c ≤ R₂. Note dist (Gentire z) (Gentire 0) — closedBall (f c) R₂ membership is dist (Gentire z) (Gentire 0) ≤ R₂. ✓. Schwarz: hd : DifferentiableOn ℂ Gentire (ball 0 R_k). From analytic: (gentire_analyticAt_and_eq.1 s).differentiableAt for each s, then DifferentiableOn: fun z hz => ((...).differentiableAt).differentiableWithinAt. AnalyticAt.differentiableAt exists? There's `AnalyticAt.differentiableAt : AnalyticAt 𝕜 f z → DifferentiableAt 𝕜 f z`. Yes. hz : z₀ ∈ ball 0 R_k: dist z₀ 0 < R_k i.e. ‖z₀‖ < R_k. We pick R_k ≥ 4k+5/2 > ‖z₀‖. Conclusion: dist (Gentire z₀) (Gentire 0) ≤ R₂/R_k · dist z₀ 0 = R₂/R_k·‖z₀‖. Then dist z₀ 0 = ‖z₀‖: dist_eq_norm + sub_zero. Final bound: dist ≤ (RB R_k + ‖Gentire 0‖)/R_k·‖z₀‖ ≤ ε as computed. If z₀ = 0: dist = 0 ≤ anything; handle by cases (if ‖z₀‖ = 0 then trivial). Actually if z₀ = 0 then dist (Gentire 0) (Gentire 0) = 0 ≤ ε ✓ directly; or note the product is 0. The inequality R₂/R·0 = 0 ≤ ε fine — no case split needed since the Schwarz conclusion already gives dist ≤ R₂/R₁·dist z₀ 0 = R₂/R₁·‖z₀‖ and if ‖z₀‖ = 0 then RHS = 0... wait no, RHS = R₂/R₁ * 0 = 0, and we show RHS ≤ ε anyway. Actually our real-number argument: (C₀' + 64 C₁ Q³)/R · ‖z₀‖ ≤ ε — hmm, with ‖z₀‖ in the mix: we need (C₀' + 64·C₁·Q³)·‖z₀‖ ≤ ε·R. Since C₀' includes ‖Gentire 0‖... Let me redo: R₂ = RB + ‖Gentire 0‖ ≤ C₀' + 64·C₁·Q³ where C₀' := 2·lowZeroConst + dirichletC2 + ‖Gentire 0‖. So dist ≤ (C₀' + 64 C₁ Q³)·‖z₀‖/Q⁴. With Q ≥ max(1, 2·(C₀'+64·C₁)... hmm redo with ‖z₀‖ folded: Want: (C₀' + 64·C₁·Q³)·‖z₀‖ ≤ ε·Q⁴. Suffices: C₀'·‖z₀‖ ≤ (ε/2)·Q⁴ and 64·C₁·Q³·‖z₀‖ ≤ (ε/2)·Q⁴ ⟸ 64·C₁·‖z₀‖ ≤ (ε/2)·Q. So conditions: Q ≥ 128·C₁·‖z₀‖/ε and Q⁴ ≥ 2·C₀'·‖z₀‖/ε ⟸ (Q ≥ 1 ∧ Q ≥ 2·C₀'·‖z₀‖/ε). So Q ≥ max(1, (128·C₁·‖z₀‖ + 2·C₀'·‖z₀‖)/ε)-ish. Take c := (128·C₁ + 2·C₀')·‖z₀‖/ε + 1 hmm but ‖z₀‖ could be 0, fine, c ≥ 1 ensures Q ≥ 1. So: c := 1 + (128·C₁ + 2·C₀')·‖z₀‖/ε; choose M := max(c⁴, ‖z₀‖ + 1); choose k with 4·k ≥ M (k ≥ 4000 automatic since M ≥ ... wait need k ≥ 4000 for Fexpr_circle_le; take M' := max(M, 16000) then k := ⌈M'/4⌉₊ ≥ 4000). Get R from exists_gapCircle_radius hZC (k := ...) (hk : 1 ≤ k): R ∈ [4k+5/2, 4k+3], gap properties. Then: - ‖z₀‖ < 4k+5/2 ≤ R (since M ≥ ‖z₀‖+1 and 4k ≥ M ⟹ 4k+5/2 ≥ M + 5/2 > ‖z₀‖) ⟹ z₀ ∈ ball 0 R. - R ≥ M ≥ c⁴ ⟹ Q := R^{1/4} ≥ c (rpow monotonicity + (c⁴)^{1/4} = c). - k ≥ 4000: 4k ≥ M ≥ 16000. Wait — exists_gapCircle_radius needs (hk : 1 ≤ k); Fexpr_circle_le needs (hk : 4000 ≤ k). Choose k := max(4000, ⌈M/4⌉₊). Then 4k ≥ M ✓ (4·⌈M/4⌉₊ ≥ M by Nat.le_ceil... 4·ceil(M/4) ≥ M ✓) and k ≥ 4000 ✓. Then the estimate chain gives dist (Gentire z₀) (Gentire 0) ≤ ε. Since ε arbitrary: dist = 0 ⟹ Gentire z₀ = Gentire 0. ∀ z₀. Set B := Gentire 0. **Step 5 capstone**: for s good (ζ s ≠ 0, s ≠ 0, s ≠ 1, ∀ n ≥ 1, s ≠ −2n): ¬ badPoint s needs also ¬ IsNontrivialZero s. IsNontrivialZero ρ presumably means ζ ρ = 0 ∧ 0 < re ρ ∧ re ρ < 1? If ζ s ≠ 0 then s is not a nontrivial zero. Check the def of IsNontrivialZero. Then Gentire s = Fexpr s (gentire_eq_Fexpr) and Gentire s = B ⟹ Fexpr s = B ⟹ unfold Fexpr and rearrange: logDeriv ζ s = B + seriesFun s − 1/s − 1/(s−1) + (log π)/2 − ψ(s/2)/2. From Fexpr s = logDeriv ζ s − seriesFun s + 1/s + 1/(s−1) − (log π)/2 + ψ(s/2)/2 = B. Solve: logDeriv ζ s = B + seriesFun s − 1/s − 1/(s−1) + (log π)/2 − ψ(s/2)/2. linear_combination or field... just algebraic: linear_combination h (the equation Fexpr s = B) — after unfolding Fexpr it's a linear identity in the atoms. `linear_combination hF` should close it. Now, theorem statement (D-068 §5): ```lean theorem partialFraction_identity (hZC : ZeroCountProp) : ∃ B : ℂ, ∀ s : ℂ, riemannZeta s ≠ 0 → s ≠ 0 → s ≠ 1 → (∀ n : ℕ, 1 ≤ n → s ≠ -2 * (n : ℂ)) → logDeriv riemannZeta s = B + seriesFun s - 1 / s - 1 / (s - 1) + (Real.log Real.pi : ℂ) / 2 - Complex.digamma (s / 2) / 2 ``` Now — where to put it? STATE.md says "LiCircleBound.lean §13 or a new LiSqueeze.lean". A new file LiSqueeze.lean is cleaner (imports LiCircleBound, LiFEntire, LiGapCircles). It also keeps the big file from getting bigger. Let me check LiCircleBound's imports to mirror them. Also: is LiCircleBound root-imported? STATE says "not yet root-imported". I should root-import LiSqueeze (which imports LiCircleBound transitively) at the end — or root-import both. The closure commit should root-import LiSqueeze.lean. Let me now check: 1. C0hat definition. 2. IsNontrivialZero definition. 3. LiCircleBound imports + namespace structure (to match). 4. lowZeroConst, dirichletC2, A0count definitions/nonneg lemmas. 5. AnalyticAt.differentiableAt name. 6. The rpow lemma names. Let me grep these.
All three key lemmas verified. Now checking the supporting definitions (C0hat, IsNontrivialZero, constants) and LiCircleBound's import header.
tool: Bash
input
{
  "command": "cd D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1; sed -n '1,30p' LiCircleBound.lean; echo ===C0HAT===; grep -rn \"def C0hat\\|C0hat :=\" LiContour.lean LiSkeleton.lean LiDisc.lean 2>/dev/null | head -3; echo ===NTRIV===; grep -rn \"def IsNontrivialZero\" *.lean | head -2; echo ===CONSTS===; grep -rn \"def lowZeroConst\\|def dirichletC2\\|def A0count\\|theorem A0count_pos\\|theorem lowZeroConst_nonneg\\|theorem dirichletC2_nonneg\\|theorem A0count_ge_one\" *.lean | head -10",
  "description": "Check imports, C0hat, IsNontrivialZero, constant definitions"
}
#1681 assistant 2026-08-24 05:52:35.707 UTC · 1082→920 tok open ⤢
thinking (1412 chars)
Good. `C0hat t = 0.433 * log(t+2) + 0.886 * log(log(t+2)) + 2.9`. For Ĉ₀(R+2) ≤ 5·log R (R ≥ 16002, so log R ≥ 9): - log(R+4) ≤ 2·log R? log(R+4) ≤ log(R²) = 2 log R needs R+4 ≤ R² — true for R ≥ 3. But careful: log(R+4) — actually C0hat (R+2) uses log((R+2)+2) = log(R+4). And log(log(R+4)) ≤ log(2 log R) = log 2 + log log R ≤ 1 + log R... since log R ≥ 9, log log R ≤ log R (log x ≤ x). So: - 0.433·log(R+4) ≤ 0.433·2·log R = 0.866·log R. - 0.886·log(log(R+4)) ≤ 0.886·log(2·log R). Now 2·log R ≤ (log R)² for log R ≥ 2 ⟹ log(2 log R) ≤ 2·log log R ≤ 2·log R... hmm log(log R) ≤ log R since log x ≤ x. So 0.886·log(log(R+4)) ≤ 0.886·2·log R? Wait: log(log(R+4)) ≤ log(2·log R) (from log(R+4) ≤ 2 log R and log monotone, need 2 log R > 0 ✓). Then log(2·log R) = log 2 + log(log R) ≤ 1 + log R ≤ 2·log R... since log R ≥ 9 ≥ 1. OK so ≤ 2·log R, giving 0.886·2·log R = 1.772·log R. - 2.9 ≤ 2.9·log R /9 ≤ ... 2.9 ≤ 0.33·log R (log R ≥ 9 ⟹ 2.9 ≤ 2.9/9·log R ≤ 0.33·log R). Total: (0.866 + 1.772 + 0.33)·log R ≈ 2.97·log R ≤ 5·log R. ✓ Comfortable. So I'll prove `C0hat_add_two_le : C0hat (R + 2) ≤ 5 * Real.log R` for (9 ≤ log R) or (R ≥ some bound). The exact decomposition: C0hat (R+2) = 0.433·log(R+4) + 0.886·log(log(R+4)) + 2.9. Now `IsNontrivialZero` — it's not defined in our package; it's from Zeta23 presumably. Let me check: LiSeries.lean line 55 uses it without definition... grep in Zeta23.
C0hat is the honest majorant `0.433·log(t+2) + 0.886·log log(t+2) + 2.9`. Now checking `IsNontrivialZero` (Zeta23) and a few more lemma names.
tool: Bash
input
{
  "command": "grep -rn \"def IsNontrivialZero\" D:/Python/Quantum/zeta-23-lean/Zeta23/ | head -2; grep -rn \"IsNontrivialZero\" D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1/LiSeries.lean | grep \"theorem\\|lemma\" | head -8; echo ===; grep -rn \"theorem analyticAt_differentiableAt\\|AnalyticAt.differentiableAt\" D:/Python/Quantum/zeta-23-lean/.lake/packages/mathlib/Mathlib/Analysis/Analytic/Basic.lean | head -3",
  "description": "Find IsNontrivialZero definition and AnalyticAt.differentiableAt"
}
#1682 assistant 2026-08-24 06:06:19.638 UTC · 540→25750 tok open ⤢
thinking (61134 chars)
All names verified: - `AnalyticAt.differentiableAt : AnalyticAt 𝕜 f x → DifferentiableAt 𝕜 f x` ✓ - `Real.pow_rpow_inv_natCast (hx : 0 ≤ x) (hn : n ≠ 0) : (x ^ n) ^ (n⁻¹ : ℝ) = x` ✓ — this is the (c⁴)^{1/4} = c direction I need. Todo #2 done. Now write the file. Design recap for **LiSqueeze.lean**: ```lean import Mathlib import NguyenRH1.LiCircleBound -- brings LiFEntire, LiGapCircles, LiDisc, LiReflect, LiDigammaLeft open Zeta23 Complex Filter Topology noncomputable section namespace NguyenRH1 ``` **Lemma 1: `C0hat_add_two_le_five_log`** — for R with 9 ≤ log R (or 16002 ≤ R): C0hat (R+2) ≤ 5·log R. Proof: unfold C0hat. Pieces: - h1: Real.log (R+2+2) = log(R+4) ≤ 2·log R: since R+4 ≤ R² for R ≥ 3 (R² - R - 4 ≥ 0: at R=3, 9-7=2>0, monotone): R+4 ≤ R·R needs R ≥ ... nlinarith. Then log(R+4) ≤ log(R²) = 2·log R (Real.log_pow: log(R^2) = 2·log R — Real.log_pow : log (x^n) = n * log x). Need 0 < R+4 and R+4 ≤ R^2. Real.log_le_log (h : 0 < x) (h' : x ≤ y)? Signature: Real.log_le_log (hx : 0 < x) (h : x ≤ y)? Let me recall: `Real.log_le_log_iff`... There's `Real.log_le_log (hx : 0 < x) (hxy : x ≤ y) : log x ≤ log y`? Hmm — in Fexpr_circle_le they used `Real.log_le_log (by ... : (0:ℝ) < 2 + R/2) (by linarith : 2+R/2 ≤ R)`. So signature `Real.log_le_log (hx : 0 < x) (h : x ≤ y)`. ✓ (Used in LiCircleBound line 3894.) - h2: log(log(R+4)) ≤ 2·log R. Chain: log(R+4) ≤ 2·log R (h1); log monotone: log(log(R+4)) ≤ log(2·log R) — need 0 < log(R+4): log(R+4) ≥ 9 > 0 ✓ (log(R+4) ≥ log R ≥ 9). log(2·log R) = log 2 + log(log R) (Real.log_mul, 2≠0, log R ≠ 0) ≤ 1 + log R — wait log 2 ≤ 1 (log 2 < log e = 1? Real.log_two_lt_d9 or log_le_one... `Real.log_two_lt_d9 : log 2 < 0.6931471808`. Simpler: log 2 ≤ 1 via Real.log_le_one? hmm — log x ≤ x - 1: log 2 ≤ 1 ✓ via `Real.log_le_sub_one_of_pos`. And log(log R) ≤ log R (log x ≤ x: from log x ≤ x - 1 ≤ x: Real.log_le_sub_one_of_pos h gives log x ≤ x-1, linarith gives ≤ x; or maybe there's a direct lemma). So log(2 log R) ≤ 1 + log R ≤ 2·log R since log R ≥ 9 ≥ 1 ⟹ 1 + log R ≤ 2 log R. Hmm — actually I can simplify: 0.886·log(log(R+4)) ≤ 0.886·(1 + log R). And 0.433·log(R+4) ≤ 0.866·log R. And 2.9 ≤ 2.9/9·log R ≤ 0.33·log R (from 9 ≤ log R ⟹ 2.9 ≤ 2.9·(log R)/9). Total: 0.866·L + 0.886·(1+L) + 2.9 ≤ 0.866L + 0.886L + 0.886 + 0.33L — and 0.886 ≤ 0.1·L (L≥9). Total ≤ (0.866+0.886+0.33+0.1)·L = 2.182·L ≤ 5·L. ✓ Big margin. **Lemma 2: `gentire_eq_Fexpr_on_gapCircle`** — actually just do it inline in step 3. For ‖s‖ = R: ¬badPoint s: - ¬IsNontrivialZero s: not_isNontrivialZero_on_gapCircle hk hRlo hgap hs. - s ≠ 0: if s = 0 then ‖s‖ = 0 ≠ R ≥ 16002. - s ≠ 1: if s = 1 then ‖s‖ = 1 ≠ R. - ¬∃ n ≥ 1, s = −2n: if s = −2·(n:ℂ), then R = ‖s‖ = ‖−2n‖ = 2n (n≥1). R/2 = n. hgapInt (n:ℤ): 1/4 ≤ |R/2 − n| = 0. Contradiction. Details: ‖(-2*(n:ℂ))‖ = ‖(-2:ℂ)‖·‖(n:ℂ)‖ = 2·n. ((-2 : ℂ)) norm: ‖(-2:ℂ)‖ = 2. Via: rw [norm_mul]; show ‖(-2:ℂ)‖ = 2: (-2 : ℂ) = ((-2:ℝ):ℂ) by push_cast;ring; Complex.norm_real; norm_num. ‖(n:ℂ)‖ = n via Complex.norm_natCast? `Complex.norm_natCast : ‖(n : ℂ)‖ = n`. Hmm exact name maybe `Complex.norm_natCast`. There's Complex.norm_natCast in Mathlib? I recall `Complex.norm_natCast (n : ℕ) : ‖(n : ℂ)‖ = n`. Used elsewhere in the project? Let me grep later. Also R/2 − (n:ℤ) cast: (n:ℤ) from ℕ cast — hgapInt takes m : ℤ; use m := n. |R/2 − ↑n| where ↑n = ((n:ℤ):ℝ) = (n:ℝ). push_cast should bridge. **Lemma 3: `gentire_circle_le`** — k ≥ 4000, R gap circle (the 4 hyps), ‖s‖ = R ⟹ ‖Gentire s‖ ≤ RB R. Proof: rw [gentire_eq_Fexpr hgood]; exact Fexpr_circle_le hk hRlo _hRhi hgap hgapInt hs. Wait — Fexpr_circle_le's second arg is named `_hRhi` (unused). Fine, still pass it. **Lemma 4: `gentire_const`** (the squeeze) — under hZC : ZeroCountProp: ∀ z₀, Gentire z₀ = Gentire 0. Proof structure: ``` intro z₀ -- constants set C₀' := 2 * lowZeroConst + dirichletC2 + ‖Gentire 0‖ with hC0' set C₁ := 2000000 * A0count with hC1 -- 400000·A0·5 have hC0'nn : 0 ≤ C₀' := by positivity-ish (lowZeroConst_nonneg, dirichletC2_nonneg, norm_nonneg) have hC1nn : 0 ≤ C₁ := mul_nonneg (norm_num) A0count_pos.le -- key: ∀ ε > 0, dist (Gentire z₀) (Gentire 0) ≤ ε have key : ∀ ε : ℝ, 0 < ε → dist (Gentire z₀) (Gentire 0) ≤ ε := by intro ε hε -- choose c := 1 + (128*C₁ + 2*C₀')*‖z₀‖/ε -- choose M := max (c^4) (‖z₀‖ + 1) -- choose k := max 4000 ⌈M/4⌉₊ -- get R from exists_gapCircle_radius hZC (k) (1 ≤ k) -- ... ``` Hmm wait, one subtlety: I need R ≥ M to get R ≥ c⁴ and R ≥ ‖z₀‖+1. From exists_gapCircle_radius: R ≥ 4k+5/2 ≥ 4k ≥ M ✓ (k ≥ ⌈M/4⌉ ⟹ 4k ≥ 4·⌈M/4⌉ ≥ M: Nat.le_ceil (M/4) : M/4 ≤ ⌈M/4⌉₊ then ×4). And k ≥ 4000 ✓. Actually also need 1 ≤ k for exists_gapCircle_radius — k ≥ 4000 covers it. Steps inside: - obtain ⟨R, hRlo, hRhi, hgapInt, hgap⟩ := exists_gapCircle_radius hZC hk1 — check the argument order in the actual theorem: (hZC : ZeroCountProp) {k : ℕ} (hk : 1 ≤ k) : ∃ R, 4k+5/2 ≤ R ∧ R ≤ 4k+3 ∧ (∀ m:ℤ, 1/4 ≤ |R/2 − m|) ∧ ∀ ρ, IsNontrivialZero ρ → (clearance) ∨ (1 ≤ |ρ.im − R|). Note hgapInt comes third, hgap fourth. Fexpr_circle_le's signature: hgap (zero ordinates) then hgapInt (integers). Different orders — careful at the call site. - hk4000 : 4000 ≤ k (for Fexpr_circle_le). - hR16002 : 16002 ≤ R: from 4k+5/2 ≤ R and k ≥ 4000 ⟹ 4k ≥ 16000. ✓ - hlogR : 9 ≤ log R := nine_le_log_of_16002_le hR16002 (exists in LiCircleBound — used in Fexpr_circle_le). - Sphere bound: ∀ z ∈ Metric.sphere 0 R, ‖Gentire z‖ ≤ RB R where RB R := 2*lowZeroConst + dirichletC2 + 400000*A0count*C0hat (R+2)*(log R)^2: intro z hz; hz : dist z 0 = R (Metric.mem_sphere). ‖z‖ = R: dist_eq_norm, norm (z − 0) = ‖z‖ (sub_zero). Then gentire_circle_le with hs : ‖z‖ = R. - Ball bound: ∀ z ∈ closedBall 0 R, ‖Gentire z‖ ≤ RB R := AnalyticOn.norm_le_of_norm_le_on_sphere (r := R) (R := R) le_rfl analyticOn_closedBall sphere_bound. Where analyticOn_closedBall : AnalyticOn ℂ Gentire (closedBall 0 R) := AnalyticOnNhd.analyticOn (fun s _ => gentire_analyticAt_and_eq.1 s). Hmm — AnalyticOnNhd ℂ f s := ∀ x ∈ s, AnalyticAt ... yes: `AnalyticOnNhd f u = ∀ x ∈ u, AnalyticAt f x`. So (fun s _ => gentire_analyticAt_and_eq.1 s) : AnalyticOnNhd ℂ Gentire (closedBall 0 R) then .analyticOn. But wait — the sphere lemma signature asks `AnalyticOn ℂ f (Metric.closedBall 0 R)`. ✓. - MapsTo: MapsTo Gentire (ball 0 R) (closedBall (Gentire 0) R₂) where R₂ := RB R + ‖Gentire 0‖: intro z hz; hz : dist z 0 < R (Metric.mem_ball). z ∈ closedBall 0 R: dist z 0 ≤ R (le of lt; Metric.mem_closedBall). ‖Gentire z‖ ≤ RB R (ball bound). mem_closedBall target: dist (Gentire z) (Gentire 0) ≤ R₂. dist = ‖Gentire z − Gentire 0‖ (dist_eq_norm) ≤ ‖Gentire z‖ + ‖Gentire 0‖ (norm_sub_le) ≤ RB R + ‖Gentire 0‖. ✓ - hd : DifferentiableOn ℂ Gentire (ball 0 R) := fun z hz => (gentire_analyticAt_and_eq.1 z).differentiableAt.differentiableWithinAt. - hz0 : z₀ ∈ ball 0 R: dist z₀ 0 < R: ‖z₀‖ < R since ‖z₀‖ < ‖z₀‖+1 ≤ M ≤ 4k ≤ 4k+5/2 ≤ R. dist_eq_norm, sub_zero. - Schwarz: dist (Gentire z₀) (Gentire 0) ≤ R₂/R·dist z₀ 0 = R₂/R·‖z₀‖. - Real grind: R₂/R·‖z₀‖ ≤ ε: RB R ≤ 2·lowZeroConst + dirichletC2 + 400000·A0count·(5·log R)·(log R)² = 2·lowZeroConst + dirichletC2 + 2000000·A0count·(log R)³ (needs log R ≥ 0 for mul monotonicity; (log R)² = (log R)³/log R... careful: 400000·A0·Ĉ·L² ≤ 400000·A0·(5L)·L² = 2000000·A0·L³: rewrite (log R)^3 = (log R)^2 * (log R) (pow_succ or pow_three); mul_le_mul: 400000·A0 ≥ 0, Ĉ ≤ 5L, L² ≥ 0. mul_le_mul_of_nonneg_left (C0hat (R+2) ≤ 5 log R) (400000·A0count ≥ 0) then × L² (≥0): mul_le_mul_of_nonneg_right. R₂ ≤ C₀' + C₁·L³ where L := log R. L ≤ 4·Q where Q := R^{1/4}: Real.log_le_rpow_div (hx : 0 ≤ x)... wait signature: log_le_rpow_div {x ε} (hx : 0 ≤ x) (hε : 0 < ε) : log x ≤ x^ε / ε. With ε := 1/4: log R ≤ R^{1/4}/(1/4) = 4·R^{1/4}. The div: x^ε/ε with ε = 1/4: R^{1/4}/(1/4) = 4·R^{1/4} — field_simp or rw div_... `div_eq_mul_inv`, inv (1/4) = 4: 1/(1/4) = 4 by norm_num. So L ≤ 4·Q. L³ ≤ 64·Q³: both sides nonneg (L ≥ 9 ≥ 0, Q ≥ 0): pow_le_pow_left (ha : 0 ≤ a) (hab : a ≤ b) (n) : a^n ≤ b^n. Then (4Q)³ = 64·Q³ by ring (need (4*Q)^3 = 64*Q^3: ring after pow_succ... `mul_pow` then norm_num: (4*Q)^3 = 4^3 * Q^3 = 64*Q^3 ✓ via mul_pow + norm_num). Numerator: R₂ ≤ C₀' + 64·C₁·Q³. Denominator: R = Q⁴: Q = R^{(1/4:ℝ)}; R = (R^{1/4})^4: from pow_rpow_inv_natCast hRnn (4≠0): (R^4)^{1/4} = R — wrong direction. I need (R^{1/4})^4 = R: that's `rpow_inv_natCast_pow (hx : 0 ≤ x) (hn : n ≠ 0) : (x ^ (n⁻¹:ℝ))^n = x` ✓ — exactly. With n := 4: (R^{(4:ℝ)⁻¹})^4 = R. And (1/4 : ℝ) vs (4:ℝ)⁻¹: 1/4 = 4⁻¹ by `one_div` — Q := R^(1/4); show (1/4:ℝ) = (4:ℝ)⁻¹ via one_div. So R = Q^4 with Q := R^(1/4). Want: (C₀' + 64·C₁·Q³)·‖z₀‖ ≤ ε·Q⁴. Have Q ≥ c = 1 + (128·C₁ + 2·C₀')·‖z₀‖/ε: Q ≥ c: R ≥ M ≥ c⁴ ⟹ Q = R^{1/4} ≥ (c⁴)^{1/4} = c: Real.rpow_le_rpow (0 ≤ c⁴) (c⁴ ≤ R) (1/4 ≥ 0): rpow_le_rpow (hx : 0 ≤ x) (hxy : x ≤ y) (hz : 0 ≤ z) : x^z ≤ y^z. And (c⁴)^{1/4} = c: pow_rpow_inv_natCast (0 ≤ c) (4 ≠ 0). Need c ≥ 0: c = 1 + nonneg·nonneg/nonneg ≥ 1 > 0 ✓. Then: (i) 64·C₁·‖z₀‖ ≤ (ε/2)·Q: from Q ≥ c ≥ (128·C₁)·‖z₀‖/ε ⟹ ε·Q ≥ 128·C₁·‖z₀‖ ⟹ (ε/2)·Q ≥ 64·C₁·‖z₀‖. Careful with division: c ≥ (128·C₁ + 2·C₀')·‖z₀‖/ε ≥ 128·C₁·‖z₀‖/ε (drop nonneg term: 2·C₀'·‖z₀‖ ≥ 0; div monotonicity: a/ε ≤ (a+b)/ε for ε>0, b≥0). So Q·ε ≥ 128·C₁·‖z₀‖ (mul by ε: (x/ε)·ε = x, div_mul_cancel₀). nlinarith might handle the pieces or do linear_combination. Since C₁, C₀', ‖z₀‖, ε, Q are atoms, linarith works once the products are... hmm linarith doesn't do nonlinear: Q·ε ≥ 128·C₁·‖z₀‖ is nonlinear (product of variables ε·Q). Strategy: derive h1 : 128·C₁·‖z₀‖ ≤ ε·Q by: calc 128·C₁·‖z₀‖ = (128·C₁·‖z₀‖/ε)·ε := (div_mul_cancel₀ _ hε.ne').symm; _ ≤ c·ε := mul_le_mul_of_nonneg_right (le chain) hε.le; _ ≤ Q·ε := mul_le_mul_of_nonneg_right hQc hε.le. Then h2 : 64·C₁·‖z₀‖ ≤ ε/2·Q: ε/2·Q = ε·Q/2: nlinarith? ε/2·Q = (ε·Q)/2 ring-equal; linarith with the atom ε·Q... linarith treats ε·Q as atom; goal 64·C₁·‖z₀‖ ≤ ε/2·Q — the RHS is a different atom than ε·Q (ε/2·Q vs ε·Q are scalar multiples — linarith can handle scalar multiples of the same monomial? linarith works over ordered fields and treats nonlinear monomials as atoms, but it CAN scale: it knows ε/2·Q = (1/2)(ε·Q) only if the expressions are parsed as the same atom scaled. `ε/2*Q` normalizes to `(1/2)*ε*Q` in ring normal form — linarith does ring_nf on hypotheses and goals (linarith preprocesses with ring_nf? linarith does use ring normalization on comparisons). I believe linarith handles scalar multiples fine after ring_nf preprocessing. OK. (ii) 2·C₀'·‖z₀‖ ≤ (ε/2)·Q⁴: from Q ≥ c ≥ 2·C₀'·‖z₀‖/ε and Q ≥ 1: 2·C₀'·‖z₀‖ ≤ ε·Q (same div trick) ≤ ε·Q⁴ (Q ≥ 1 ⟹ Q ≤ Q⁴... need Q⁴ ≥ Q: since Q ≥ 1: Q⁴ = Q·Q³ ≥ Q·1 = Q — needs Q³ ≥ 1: one_le_pow... `one_le_pow_of_le` hmm: 1 ≤ Q ⟹ 1 ≤ Q^n for Q ≥ ... `one_le_pow₀ (h : 1 ≤ a) : 1 ≤ a ^ n`. Then Q^4 = Q^3 * Q or Q * Q^3: pow_succ: Q^4 = Q^3 * Q ≥ 1 * Q = Q (mul_le_mul_of_nonneg... 1 ≤ Q^3, times Q ≥ 0: mul_le_mul_of_nonneg_right? (1 ≤ Q^3) mul right by Q: 1*Q ≤ Q^3*Q ✓). So 2·C₀'·‖z₀‖ ≤ ε·Q ≤ ε·Q⁴ = (ε/2)·Q⁴ + ... just need ≤ (ε/2)·Q⁴: 2·C₀'·‖z₀‖ ≤ ε·Q ≤ ... hmm I need ε·Q ≤ (ε/2)·Q⁴ ⟸ Q ≤ Q⁴/2 ⟸ 2·Q ≤ Q⁴. With Q ≥ 1: Q⁴ ≥ 2Q? Not for Q=1 (1 < 2). Oops. Fix: make c ≥ 2: c := 2 + (128·C₁ + 2·C₀')·‖z₀‖/ε ⟹ Q ≥ 2 ⟹ Q⁴ = Q·Q³ ≥ Q·8 ≥ 2·Q·... Q³ ≥ 8 ⟹ Q⁴ ≥ 8Q ≥ ... want ε·Q ≤ (ε/2)·Q⁴ ⟸ 2 ≤ Q³ ⟸ 2 ≤ 8 ✓. So with c ≥ 2: 2·C₀'‖z₀‖ ≤ ε·Q, and ε·Q ≤ (ε/2)·Q⁴ ⟸ 2·Q ≤ Q⁴ ⟸ 2 ≤ Q³ (divide by Q>0) ⟸ Q ≥ 2 ⟹ Q³ ≥ 8 ✓. Handling divisions in Lean without dividing: state directly: have hQ2 : 2 ≤ Q; h2a : 2·C₀'·‖z₀‖ ≤ ε·Q (div trick as before); h2b : ε·Q ≤ (ε/2)·Q⁴: (ε/2)·Q⁴ − ε·Q = ε·Q·(Q³/2 − 1) ≥ 0: nlinarith [hQ2, ...]? Q³ ≥ 8: from Q ≥ 2: pow_le_pow_left (0≤2) hQ2 3 : 2³ ≤ Q³ = 8 ≤ Q³. Then (ε/2)·Q⁴ = (ε/2)·Q·Q³ ≥ (ε/2)·Q·8 = 4·ε·Q ≥ ε·Q: nlinarith [hε, hQpos, hQ3ge8] with atoms ε·Q... nlinarith multiplies pairs of hypotheses; the product (ε/2)·Q·Q³ — nlinarith sees monomials up to degree... The product (ε/2)*Q^4 vs ε*Q: factor as ((ε/2)*Q)*(Q^3) hmm nlinarith would need to multiply (ε·Q atom?) — it doesn't have ε·Q as hypothesis atom; hypotheses are ε>0, Q≥2, Q³≥8. Products: ε·Q³ ≥ ... nlinarith can multiply two hypotheses: (Q ≥ 2)·(Q³ ≥ 8)?? no. Let me just hand-roll: h2b : ε*Q ≤ ε/2*Q^4 := calc ε*Q = (ε/2)*(2*Q) := by ring; _ ≤ (ε/2)*(Q*Q^3) := mul_le_mul_of_nonneg_left (by nlinarith [hQ2, hQ3, hQnn]) (by positivity... ε/2 ≥ 0); where 2*Q ≤ Q*Q^3 ⟸ 2 ≤ Q³ (Q > 0): mul_le_mul_of_nonneg_right hQ3' (le of Q > 0)... hmm 2*Q ≤ Q*Q^3 ⟸ 2 ≤ Q^3: mul_le_mul_of_nonneg_right (h : 2 ≤ Q^3) (0 ≤ Q): 2*Q ≤ Q^3*Q; Q^3*Q = Q*Q^3 ring. OK then = ε/2 * Q^4 by ring (Q*Q^3 = Q^4: ring? Q*Q^3 = Q^4 is ring-normalizable ✓ (pow is ring-opaque? `ring` handles pow with literal exponents ✓)). Then h2 : 2·C₀'·‖z₀‖ ≤ (ε/2)·Q⁴ by trans. Sum: (C₀' + 64·C₁·Q³)·‖z₀‖ — hmm wait. Let me restructure: dist ≤ (R₂/R)·‖z₀‖; want ≤ ε. R₂ ≤ C₀' + 64·C₁·Q³ (shown). So dist·1 ≤ (C₀' + 64·C₁·Q³)/Q⁴·‖z₀‖ hmm R = Q⁴ substitution. Goal: (C₀' + 64·C₁·Q³)/Q⁴·‖z₀‖ ≤ ε ⟺ (C₀' + 64·C₁·Q³)·‖z₀‖ ≤ ε·Q⁴ (div_le_iff, Q⁴ > 0). Expand LHS: C₀'·‖z₀‖ + 64·C₁·Q³·‖z₀‖. From (i): 64·C₁·‖z₀‖ ≤ (ε/2)·Q ⟹ 64·C₁·‖z₀‖·Q³ ≤ (ε/2)·Q·Q³ = (ε/2)·Q⁴ (mul by Q³ ≥ 0 — but careful with assoc: 64·C₁·Q³·‖z₀‖ vs (64·C₁·‖z₀‖)·Q³ — assoc juggling; use ring-normal forms and per-step haves + linarith, per the banked gotcha). From (ii): C₀'·‖z₀‖ ≤ (ε/2)·Q⁴ — wait I had 2·C₀'·‖z₀‖ ≤ (ε/2)·Q⁴ which is stronger. Sum: LHS ≤ (ε/2)·Q⁴ + (ε/2)·Q⁴ = ε·Q⁴ ✓. So: hA : 64*C₁*‖z₀‖ ≤ (ε/2)*Q (derived from h1 by linarith with ε/2*Q = (ε*Q)/2 — need ring-equivalence; use have hhalf : (ε/2)*Q = (ε*Q)/2 := by ring; linarith). hA' : (64*C₁*‖z₀‖)*Q^3 ≤ (ε/2)*Q*Q^3 := mul_le_mul_of_nonneg_right hA (pow_nonneg hQnn 3). Then ring-normalize: (64*C₁*‖z₀‖)*Q^3 = 64*C₁*Q^3*‖z₀‖ and (ε/2)*Q*Q^3 = (ε/2)*Q^4 — via calc + ring steps. hB : C₀'*‖z₀‖ ≤ (ε/2)*Q^4 (from h2a : 2*C₀'*‖z₀‖ ≤ ε*Q... wait redo: h2a was 2·C₀'·‖z₀‖ ≤ ε·Q. Then C₀'·‖z₀‖ ≤ (ε/2)·Q ≤ (ε/2)·Q⁴? (ε/2)·Q ≤ (ε/2)·Q⁴ ⟸ Q ≤ Q⁴ ⟸ 1 ≤ Q³ ✓ (Q ≥ 2). Hmm or just: C₀'·‖z₀‖ ≤ 2·C₀'·‖z₀‖ (C₀'‖z₀‖ ≥ 0) ≤ ε·Q ≤ ... I'll assemble with linarith over the derived atoms: Final: have hsum : C₀'*‖z₀‖ + 64*C₁*Q^3*‖z₀‖ ≤ ε*Q^4 := by linarith [hA'normalized, hB, ...]. linarith treats (ε/2)*Q^4 as (1/2)·(ε·Q⁴) — same atom scaled ✓. Then div: (C₀' + 64·C₁·Q³)·‖z₀‖/Q⁴ ≤ ε: rw [div_le_iff₀ hQ4pos]: (C₀'+64·C₁·Q³)·‖z₀‖ ≤ ε·Q⁴ — matches hsum after LHS expansion: (C₀'+64·C₁·Q³)·‖z₀‖ = C₀'·‖z₀‖ + 64·C₁·Q³·‖z₀‖ (add_mul + assoc — ring-normalize via a calc or linear_combination hsum after `ring_nf`? Use: have hLHS : (C₀' + 64*C₁*Q^3)*‖z₀‖ = C₀'*‖z₀‖ + 64*C₁*Q^3*‖z₀‖ := by ring. Then rw [hLHS]; exact hsum. - Conclusion chain: dist (Gentire z₀) (Gentire 0) ≤ R₂/R·‖z₀‖ (Schwarz) and R₂/R·‖z₀‖ ≤ (C₀'+64·C₁·Q³)·‖z₀‖/Q⁴: since R₂ ≤ C₀'+64C₁Q³ and R = Q⁴: R₂/R·‖z₀‖ ≤ (C₀'+64C₁Q³)/Q⁴·‖z₀‖: div monotonicity + R = Q⁴ (rw). Then ≤ ε. So dist ≤ ε ✓. - Then dist = 0: le_of_forall_pos_le_add? The standard: `le_of_forall_pos_le_add : (∀ ε, 0 < ε → a ≤ b + ε) → a ≤ b`. We have ∀ ε>0, dist ≤ ε = 0 + ε. So dist ≤ 0. Then dist ≤ 0 ∧ 0 ≤ dist ⟹ dist = 0 (le_antisymm (dist_nonneg)). Then `dist_eq_zero.mp : dist x y = 0 → x = y`. So Gentire z₀ = Gentire 0. Hmm wait — `le_of_forall_pos_le_add` signature: `(h : ∀ ε, 0 < ε → a ≤ b + ε) : a ≤ b`. Our key gives dist ≤ ε; need dist ≤ 0 + ε: by linarith [key ε hε]. OK. **Lemma 5: `partialFraction_identity`** (capstone): ``` theorem partialFraction_identity (hZC : ZeroCountProp) : ∃ B : ℂ, ∀ s : ℂ, riemannZeta s ≠ 0 → s ≠ 0 → s ≠ 1 → (∀ n : ℕ, 1 ≤ n → s ≠ -2 * (n : ℂ)) → logDeriv riemannZeta s = B + seriesFun s - 1/s - 1/(s-1) + (Real.log Real.pi : ℂ)/2 - Complex.digamma (s/2)/2 := by refine ⟨Gentire 0, fun s hζ hs0 hs1 hsn ↦ ?_⟩ -- ¬ badPoint s have hgood : ¬ badPoint s := by rintro (h | h | h | ⟨n, hn, h⟩) · exact hζ h.1 · exact hs0 h · exact hs1 h · exact hsn n hn h have hG : Gentire s = Gentire 0 := gentire_const hZC s rw [gentire_eq_Fexpr hgood] at hG -- Gentire s = Fexpr s, so Fexpr s = Gentire 0 -- hG : Fexpr s = Gentire 0 unfold Fexpr at hG linear_combination hG ``` Wait: hG : Gentire s = Fexpr s from gentire_eq_Fexpr; combined with Gentire s = Gentire 0: Fexpr s = Gentire 0. Then unfold Fexpr at hG: logDeriv ζ s − seriesFun s + 1/s + 1/(s−1) − (log π)/2 + ψ(s/2)/2 = Gentire 0. Goal: logDeriv ζ s = Gentire 0 + seriesFun s − 1/s − 1/(s−1) + (log π)/2 − ψ(s/2)/2. linear_combination hG ✓ (pure linear identity in atoms over ℂ — division by constants s, s−1, 2 are fine for linear_combination? linear_combination works over commutative rings with the atoms being subterms: 1/s is an atom; the identity is linear in the atoms logDeriv ζ s, seriesFun s, 1/s, 1/(s−1), ((log π:ℂ)/2), (digamma(s/2)/2), Gentire 0 — yes, all coefficients are constants ✓. But careful: is `Real.log Real.pi` coerced consistently: in Fexpr def it's `(Real.log Real.pi : ℂ) / 2`. In my goal I write the same. ✓. Careful about `unfold Fexpr at hG` — Fexpr is a def; unfold might not fire if... `rw [Fexpr] at hG` was used in LiCircleBound (line 3846: `rw [Fexpr]`). For hG I'll use `rw [Fexpr] at hG` hmm — Fexpr is a def so `rw [Fexpr]`... they used `rw [Fexpr]` at line 3846 in a term-mode proof (`rw [Fexpr]` inside `by`?). Actually they had `have hc1 : ... := by rw [Fexpr]; exact norm_add_le _ _`. So `rw [Fexpr]` works — presumably there's an equational lemma Fexpr s = ... auto-generated (defs get equation lemmas; rw with a def name uses its eqn lemmas — works for non-recursive defs in Lean4 Mathlib style: `rw [Fexpr]` unfolds via Fexpr.eq_def or the auto equation lemma). I'll use `rw [Fexpr] at hG` — hmm, `show` may be safer: since everything is defeq, `linear_combination hG` might close the goal directly without unfolding (linear_combination checks the difference is a ring combination — hG's type is Fexpr s = Gentire 0; linear_combination treats `Fexpr s` as an atom but the goal mentions logDeriv... not Fexpr — so no, must unfold first). Use `unfold Fexpr at hG` — unfold is reliable for plain defs. Or `simp only [Fexpr] at hG`. I'll try unfold. One more check: `gentire_eq_Fexpr` signature: from line 1109 usage `rw [gentire_eq_Fexpr hygood]` where hygood : ¬ badPoint y. So `gentire_eq_Fexpr (h : ¬ badPoint s) : Gentire s = Fexpr s` ✓. Also `gentire_const` needs a name not clashing. And I should double check `not_isNontrivialZero_on_gapCircle`'s signature: used at line 3815-3816 as `not_isNontrivialZero_on_gapCircle hk hRlo hgap hs` where hk : 4000 ≤ k, hRlo, hgap (zeros), hs : ‖s‖ = R. ✓ Note it does NOT need hgapInt. Now, `badPoint` is: IsNontrivialZero s ∨ s = 0 ∨ s = 1 ∨ ∃ n, 1 ≤ n ∧ s = -2*(n:ℂ). For the on-circle goodness I need to discharge all four. Let me write the good-point lemma: ```lean lemma not_badPoint_on_gapCircle {k : ℕ} (hk : 4000 ≤ k) {R : ℝ} (hRlo : 4 * (k:ℝ) + 5/2 ≤ R) (hgap : ...) (hgapInt : ∀ m : ℤ, 1/4 ≤ |R/2 - (m:ℝ)|) {s : ℂ} (hs : ‖s‖ = R) : ¬ badPoint s := by rintro (h | h | h | ⟨n, hn, h⟩) · exact not_isNontrivialZero_on_gapCircle hk hRlo hgap hs h · -- s = 0 have : (0:ℝ) = R := by rw [← hs, h]; norm_num -- ‖(0:ℂ)‖ = 0 -- R ≥ 16002 ⟹ contradiction ... · -- s = 1 have : (1:ℝ) = R := by rw [← hs, h]; simp? ‖(1:ℂ)‖ = 1: norm_one ... · -- s = -2n ... ``` For s = 0: hs : ‖s‖ = R; rw [h] at hs : ‖(0:ℂ)‖ = R; norm_num at hs or rw norm_zero at hs: R = 0... but R ≥ 4k+5/2 ≥ 16002.5 > 0. hRpos : 0 < R. linarith. For s = 1: rw [h] at hs : ‖(1:ℂ)‖ = R; norm_one at hs : 1 = R... wait ‖(1:ℂ)‖ = (1:ℝ): norm_one. hs : (1:ℝ) = R. R ≥ 16002 contradiction linarith. For s = −2n: R = ‖s‖ = ‖−2·(n:ℂ)‖. Compute: ‖−2·(n:ℂ)‖ = 2·n. Then R/2 = n. hgapInt (n:ℤ) : 1/4 ≤ |R/2 − ((n:ℤ):ℝ)|. ((n:ℤ):ℝ) = (n:ℝ) by push_cast/Int.cast_natCast. R/2 − n = 0. |0| = 0 < 1/4. Contradiction. Details: have hR2 : R = 2 * n: from hs: R = ‖s‖ = ... : rw [← hs, h]; then ‖(-2:ℂ)*(n:ℂ)‖ = ‖(-2:ℂ)‖*‖(n:ℂ)‖ (norm_mul) = 2*n: ‖(-2:ℂ)‖ = 2: by rw [show (-2:ℂ) = ((-2:ℝ):ℂ) by push_cast;ring, Complex.norm_real]; norm_num. ‖(n:ℂ)‖ = (n:ℝ): Complex.norm_natCast? Let me check name: `Complex.norm_natCast` — hmm, grep. In Lean Mathlib it's `Complex.norm_natCast (n : ℕ) : ‖(n : ℂ)‖ = ↑n`. I've seen `Complex.norm_natCast`. I'll verify by grep in the project or Mathlib. Then hgapInt ((n : ℤ)): 1/4 ≤ |R/2 − ((n:ℤ):ℝ)|. Have ((n:ℤ):ℝ) = (n:ℝ) := by push_cast;ring or Int.cast_natCast n: `Int.cast_natCast : ((n:ℤ):ℝ) = n`? Int.cast_natCast : (↑(↑n : ℤ) : R) = ↑n. yes `Int.cast_natCast (n : ℕ) : ((n : ℤ) : α) = n`. rw that. R/2 − n = 0: from R = 2n: linarith... the expression |R/2 − (n:ℝ)| with hR2 : R = 2*(n:ℝ): rw [hR2]; 2*n/2 − n = 0: ring_nf then abs_zero. Have : |2*(n:ℝ)/2 − (n:ℝ)| = 0: by rw [...]; the cleanest: have h0 : 2*(n:ℝ)/2 − (n:ℝ) = 0 := by ring; rw [hR2, h0, abs_zero] at hcon; linarith. Note: hgapInt m is `∀ m : ℤ, 1 / 4 ≤ |R / 2 - (m : ℝ)|`. So hgapInt (n : ℤ) : 1/4 ≤ |R/2 − ((n:ℤ):ℝ)|. OK. Now, one design question: file placement. New file LiSqueeze.lean, import NguyenRH1.LiCircleBound (which transitively imports LiFEntire etc). Namespace NguyenRH1. Then add `import NguyenRH1.LiSqueeze` to the root file NguyenRH1.lean. Let me check the root file. Also, the AnalyticOn.norm_le_of_norm_le_on_sphere is in Zeta23's StrongPNTPrefix — is it in scope via existing imports? LiDisc.lean imports StrongPNTPrefix presumably (BC used there). LiCircleBound imports LiDisc so transitively available, and LiSqueeze imports LiCircleBound. It's a plain lemma in root namespace (AnalyticOn.norm_le_of_norm_le_on_sphere — namespaced under AnalyticOn, dot-accessible as AnalyticOn.norm_le_of_norm_le_on_sphere). ✓ The Schwarz lemma: Complex.dist_le_div_mul_dist_of_mapsTo_ball — with `open Complex` it's dist_le_div_mul_dist_of_mapsTo_ball; safer to write Complex.dist_le_div_mul_dist_of_mapsTo_ball. Now — one more check on `exists_gapCircle_radius`: it returns R with hRlo : 4*(k:ℝ)+5/2 ≤ R, hRhi : R ≤ 4*(k:ℝ)+3, hgapInt : ∀ m:ℤ, 1/4 ≤ |R/2 − m|, hgap : ∀ ρ, IsNontrivialZero ρ → 1/(16*C0hat(4k+9/2)) ≤ |ρ.im − R| ∨ 1 ≤ |ρ.im − R|. ✓ matches Fexpr_circle_le's needs (hgap then hgapInt order differs — Fexpr_circle_le takes hgap first, hgapInt second). The choice of k: given M : ℝ (M ≥ 16000), k := max 4000 ⌈M/4⌉₊. Then 4k ≥ M: ⌈M/4⌉₊ ≥ M/4 (Nat.le_ceil) ⟹ 4·⌈M/4⌉₊ ≥ M (for M ≥ 0). k ≥ 4000 ✓, and 1 ≤ k ✓. Then R ≥ 4k + 5/2 ≥ M + 5/2 > M ≥ max(...) hmm — need R ≥ c⁴ and R ≥ ‖z₀‖+1: M := max (c^4) (‖z₀‖ + 1) (and M ≥ 16000? no — k := max 4000 ⌈M/4⌉ gives 4k ≥ M automatically even if M < 16000; and k ≥ 4000 gives R ≥ 16002 anyway). So M := max (c^4) (‖z₀‖ + 1); k := max 4000 ⌈M/4⌉₊; 4k ≥ M ✓ (from the ceil branch: 4·⌈M/4⌉₊ ≥ M; and 4·max ≥ 4·⌈M/4⌉₊). Then R ≥ 4k+5/2 ≥ M + 5/2. Then: - hz0ball : ‖z₀‖ < R: ‖z₀‖ < ‖z₀‖+1 ≤ M ≤ ... < R. ✓ - hRc4 : c^4 ≤ R: c^4 ≤ M ≤ R ✓. - hQge : c ≤ Q where Q := R^(1/4:ℝ): c = (c^4)^(1/4) [pow_rpow_inv_natCast (c≥0) (4≠0), with exponent (4:ℝ)⁻¹ = 1/4] ≤ R^(1/4) [Real.rpow_le_rpow (0 ≤ c^4) hRc4 (1/4 ≥ 0)]. Exponent juggling: define Q := R ^ ((1:ℝ)/4)? or R ^ (4⁻¹ : ℝ)? pow_rpow_inv_natCast gives (c^4)^((4:ℝ)⁻¹) = c. If Q := R^(1/4), I need (1/4:ℝ) = (4:ℝ)⁻¹: `one_div 4`. So: rw [show (1/4:ℝ) = (4:ℝ)⁻¹ from one_div 4] — or just define Q := R ^ (4:ℝ)⁻¹ and note 1/4 never appears. But Real.log_le_rpow_div needs ε : ℝ, log R ≤ R^ε/ε — with ε := (4:ℝ)⁻¹: log R ≤ R^(4⁻¹)/(4⁻¹) = R^(4⁻¹)·4. The /ε = ·4 juggling: div by 4⁻¹ = mul by 4: `div_eq_mul_inv`, inv_inv. Fine — set ε := (4:ℝ)⁻¹, hε : 0 < (4:ℝ)⁻¹ := by positivity. So Q := R ^ (4:ℝ)⁻¹ (rpow). Facts: - hQnn : 0 ≤ Q := Real.rpow_nonneg hRnn _. - hQpos : 0 < Q := Real.rpow_pos_of_pos hRpos _. - hL : Real.log R ≤ 4 * Q: from log_le_rpow_div hRnn (show (0:ℝ) < (4:ℝ)⁻¹ by positivity): log R ≤ R^(4⁻¹)/(4⁻¹); R^(4⁻¹)/(4⁻¹) = 4·Q: field_simp? div by inv: R^a/(4⁻¹) = R^a * 4: `div_inv_eq_mul`... a/(4⁻¹) = a*4: rw [div_eq_mul_inv, inv_inv] : a * (4⁻¹)⁻¹ = a*4 ✓. So log R ≤ Q*4 = 4*Q (mul_comm juggling via calc or linarith with hQ4 : R^(4:ℝ)⁻¹/(4:ℝ)⁻¹ = 4*Q := by rw [div_eq_mul_inv, inv_inv]; ring). - hL3 : (Real.log R)^3 ≤ 64 * Q^3: have h1 : (log R)^3 ≤ (4*Q)^3 := pow_le_pow_left (by linarith [hlogR] : 0 ≤ log R) hL 3; (4*Q)^3 = 64*Q^3: by ring? (4*Q)^3 = 64*Q^3 — ring handles ✓ (pow with literal 3). pow_le_pow_left signature: (ha : 0 ≤ a) (hab : a ≤ b) (n : ℕ) : a^n ≤ b^n ✓ (used in project? standard). - hR4 : R = Q^4: from rpow_inv_natCast_pow hRnn (4≠0): (R^(4:ℝ)⁻¹)^4 = R, i.e., Q^4 = R — use .symm. Then the final grind as sketched. Let me also double check `Real.log_le_rpow_div` name (found at Pow/Real.lean:883: `lemma log_le_rpow_div {x ε : ℝ} (hx : 0 ≤ x) (hε : 0 < ε) : log x ≤ x ^ ε / ε`) — in Real namespace ✓. pow_le_pow_left — check name in current Mathlib: might be `pow_le_pow_left (ha : 0 ≤ a) (hab : a ≤ b) (n : ℕ)`. In recent Mathlib there's pow_le_pow_left₀ or pow_le_pow_left with swapped args... I recall `pow_le_pow_left (ha : 0 ≤ a) (hab : a ≤ b) : a ^ n ≤ b ^ n`. Grep at build time; fallback: nlinarith can't do it directly (L ≤ 4Q ⟹ L³ ≤ 64Q³ is nonlinear; nlinarith with hints: needs the product... nlinarith [sq_nonneg (L−4Q)...] might manage but messy; better find pow_le_pow_left). Also `one_le_pow₀`: name check — `one_le_pow₀ (ha : 1 ≤ a) : 1 ≤ a ^ n`? There's `one_le_pow_of_le'`... I'll grep. Actually I only need 8 ≤ Q^3 from 2 ≤ Q: pow_le_pow_left (0≤2) hQ2 3 gives 2^3 ≤ Q^3, 2^3 = 8 norm_num. ✓ same lemma. Also `Nat.le_ceil : x ≤ ⌈x⌉₊` for x : ℝ? `Nat.le_ceil (x : ℝ) : x ≤ ⌈x⌉₊` — requires? It's `Nat.le_ceil : ∀ (a : ℝ), a ≤ ↑⌈a⌉₊` ✓. Let me also confirm `Complex.norm_natCast` name and `norm_one`, `norm_zero`, `norm_mul`, `abs_zero` — all standard. `Metric.mem_sphere : z ∈ sphere x r ↔ dist z x = r` ✓; `Metric.mem_ball : dist z x < r`; `Metric.mem_closedBall : dist z x ≤ r` ✓. `dist_eq_norm : dist x y = ‖x − y‖` (for seminormed groups) ✓. `sub_zero` ✓. Alright. Also the RB definition: I'll phrase the sphere bound directly with the Fexpr_circle_le RHS expression rather than introducing a def (or a local let). Let me structure the file: §1. `C0hat_add_two_le` (the Ĉ₀(R+2) ≤ 5 log R growth bound). §2. `not_badPoint_on_gapCircle`. §3. `gentire_circle_le`. §4. `gentire_eq_zero_imp`... no — `gentire_const (hZC) : ∀ z₀, Gentire z₀ = Gentire 0`. §5. `partialFraction_identity (hZC : ZeroCountProp) : ∃ B, ...`. For §1, check what log lemmas exist: Real.log_pow (x:ℝ)(n:ℕ): log (x^n) = n*log x ✓ standard. Real.log_mul (hx : x ≠ 0)(hy : y ≠ 0): log (x*y) = log x + log y ✓. Real.log_le_sub_one_of_pos (hx : 0 < x) : log x ≤ x − 1 ✓ (I think that's the name — `Real.log_le_sub_one_of_pos`). Used in LiDigammaLeft probably. Let me grep quickly at build time if it fails; alternative: Real.add_pow_le_pow_mul_pow_of_sq_le_sq... no. There's also the possibility they already have a helper for log x ≤ x. Actually, let me check what's available: grep "log_le_sub_one_of_pos\|log_le_self" in Mathlib Log/Basic. Now write §1 proof in detail: ``` lemma C0hat_add_two_le {R : ℝ} (hR : 16002 ≤ R) : C0hat (R + 2) ≤ 5 * Real.log R := by have hRpos : (0:ℝ) < R := by linarith have hlogR : (9:ℝ) ≤ Real.log R := nine_le_log_of_16002_le hR -- log (R+4) ≤ 2 log R have h1 : Real.log (R + 2 + 2) ≤ 2 * Real.log R := by have hle : R + 4 ≤ R^2 := by nlinarith [hR] have h2 : Real.log (R + 2 + 2) ≤ Real.log (R^2) := by apply Real.log_le_log (by linarith : (0:ℝ) < R + 2 + 2) -- R+2+2 = R+4 ≤ R^2 (show R + 2 + 2 ≤ R^2 by linarith [hle]) -- ring_nf normalizes? ``` Hmm — R+2+2 vs R+4 syntactic difference: linarith handles ✓ (atoms R fine, linear). But the `apply Real.log_le_log` second goal is `R+2+2 ≤ R^2` — linarith [hle] where hle : R+4 ≤ R^2 — linear in atom R^2 ✓. ``` rw [Real.log_pow] at h2 -- log (R^2) = 2 * log R... log_pow : log (x^n) = n*log x with n:ℕ cast -- h2 : log (R+2+2) ≤ ↑(2:ℕ) * log R; push_cast at h2 rwa [Nat.cast_two] at h2 -- or push_cast at h2 ⊢? ``` Real.log_pow: `Real.log_pow (x : ℝ) (n : ℕ) : Real.log (x ^ n) = ↑n * Real.log x`. So rw [Real.log_pow] at h2 gives h2 : log(R+2+2) ≤ ↑2 * log R; norm_num at h2 or push_cast at h2 to make ↑2 = 2. Use `push_cast at h2; exact h2`. ``` -- log log (R+4) ≤ 2 log R have h2 : Real.log (Real.log (R + 2 + 2)) ≤ 2 * Real.log R := by have hpos1 : (0:ℝ) < Real.log (R + 2 + 2) := by have : Real.log R ≤ Real.log (R + 2 + 2) := Real.log_le_log hRpos (by linarith) linarith [hlogR] have h3 : Real.log (Real.log (R + 2 + 2)) ≤ Real.log (2 * Real.log R) := Real.log_le_log hpos1 h1 have h4 : Real.log (2 * Real.log R) = Real.log 2 + Real.log (Real.log R) := by rw [Real.log_mul (by norm_num) (by linarith [hlogR] : Real.log R ≠ 0)] have h5 : Real.log 2 ≤ 1 := by have h := Real.log_le_sub_one_of_pos (by norm_num : (0:ℝ) < 2) linarith have h6 : Real.log (Real.log R) ≤ Real.log R := by have h := Real.log_le_sub_one_of_pos (by linarith [hlogR] : (0:ℝ) < Real.log R) linarith linarith [h3, h4, h5, h6, hlogR] -- assemble: C0hat (R+2) = 0.433*log(R+4) + 0.886*log(log(R+4)) + 2.9 rw [C0hat] -- 2.9 ≤ (2.9/9)*log R ≤ ... just: 2.9 ≤ log R? no: 2.9 ≤ 2.9/9 * 9 ≤ ... use 2.9 ≤ (1/3)*log R hmm 2.9/9 ≈ 0.322; total 0.433*2 + 0.886*2 + 0.322 = 0.866+1.772+0.322 = 2.96 ≤ 5 ✓ nlinarith [h1, h2, hlogR] ``` nlinarith: goal 0.433*log(R+4) + 0.886*log(log(R+4)) + 2.9 ≤ 5*log R with h1: log(R+4) ≤ 2L, h2: loglog ≤ 2L, hlogR: 9 ≤ L. This is linear in atoms log(R+4), log(log(R+4)), log R — linarith should do it: 0.433*2L + 0.886*2L + 2.9 ≤ (0.866+1.772)*L + 2.9 = 2.638L + 2.9; need 2.9 ≤ 2.362*L ⟸ 2.9 ≤ 2.362*9 = 21.258 ✓. linarith handles decimal literals as rationals ✓. But careful: nlinarith/linarith need the hypotheses as linear atoms — ✓. Use linarith [h1, h2, hlogR]. Wait — after `rw [C0hat]`, goal shows `0.433 * Real.log (R + 2 + 2) + ...`? C0hat def: `0.433 * Real.log (t + 2) + 0.886 * Real.log (Real.log (t + 2)) + 2.9` with t := R+2, so log (R+2+2). My h1/h2 stated with R+2+2 ✓ (I wrote log (R+2+2)). ✓. unfold via `rw [C0hat]`? C0hat is a def — `rw [C0hat]` used in project? They used `rw [Fexpr]` — same mechanism ✓. Or `unfold C0hat`. I'll use `rw [C0hat]` hmm — actually `show` also works since defeq: `show 0.433 * Real.log (R + 2 + 2) + _ ≤ _`. I'll use unfold/rw. Also `nine_le_log_of_16002_le` — verify it exists (used in Fexpr_circle_le line 3826) ✓. §4 detail — the MapsTo R₂ radius: R₂ := RB + ‖Gentire 0‖ where RB := 2*lowZeroConst + dirichletC2 + 400000*A0count*C0hat (R+2)*(log R)^2. Schwarz gives dist ≤ R₂/R * dist z₀ 0. Subtlety: Schwarz's h_maps needs MapsTo into closedBall (Gentire 0) R₂ — I need R₂ defined as a plain ℝ expression. Fine. Also note: Schwarz's conclusion dist (f z) (f c) ≤ R₂/R₁ * dist z c — with c := (0:ℂ), f := Gentire: dist (Gentire z₀) (Gentire 0) ≤ R₂/R * dist z₀ 0. dist z₀ 0 = ‖z₀ − 0‖ = ‖z₀‖ ✓. Now the ball bound (max-modulus): AnalyticOn.norm_le_of_norm_le_on_sphere (hyp_r : r ≤ R) (analytic : AnalyticOn ℂ f (closedBall 0 R)) (cond : ∀ z ∈ sphere 0 r, ‖f z‖ ≤ C) (wInS : w ∈ closedBall 0 r) : ‖f w‖ ≤ C. With r = R ✓ le_refl. The `analytic` arg: AnalyticOn ℂ Gentire (closedBall 0 R): ``` have hGnhd : AnalyticOnNhd ℂ Gentire (Metric.closedBall 0 R) := fun s _ => gentire_analyticAt_and_eq.1 s have hGan : AnalyticOn ℂ Gentire (Metric.closedBall 0 R) := hGnhd.analyticOn ``` AnalyticOnNhd.analyticOn : AnalyticOnNhd f s → AnalyticOn f s ✓ (used in StrongPNTPrefix line 386). `gentire_analyticAt_and_eq.1 : ∀ s, AnalyticAt ℂ Gentire s` ✓. Now the full §4: ``` lemma gentire_const (hZC : ZeroCountProp) (z₀ : ℂ) : Gentire z₀ = Gentire 0 := by classical -- constants have hC0'nn : (0:ℝ) ≤ 2 * lowZeroConst + dirichletC2 + ‖Gentire 0‖ := by have h1 := lowZeroConst_nonneg have h2 := dirichletC2_nonneg have h3 := norm_nonneg (Gentire 0) linarith have hA0nn : (0:ℝ) ≤ A0count := A0count_pos.le -- main: ∀ ε > 0, dist ≤ ε have key : ∀ ε : ℝ, 0 < ε → dist (Gentire z₀) (Gentire 0) ≤ ε := by intro ε hε set C₀' := 2 * lowZeroConst + dirichletC2 + ‖Gentire 0‖ with hC0' set C₁ := 2000000 * A0count with hC1 have hC1nn : (0:ℝ) ≤ C₁ := by positivity -- 2000000 * A0count, needs A0count ≥ 0: positivity doesn't know A0count. use mul_nonneg ... ``` positivity won't know A0count ≥ 0 — use `mul_nonneg (by norm_num) hA0nn`. But C₁ is `set` — positivity on `C₁` fails; rw hC1 first or use `by rw [hC1]; exact mul_nonneg ...`. Hmm `set ... with h` gives hC1 : C₁ = 2000000 * A0count. rw [hC1]. OK. ``` set c := 2 + (128 * C₁ + 2 * C₀') * ‖z₀‖ / ε with hc have hcnn : (0:ℝ) ≤ 128 * C₁ + 2 * C₀' := by rw [hC1, hC0'] -- hmm messy; instead: ``` Since C₀' and C₁ are set-variables, nonneg proofs: have hC₀'nn : 0 ≤ C₀' := hC0' ▸ hC0'nn... With set, hC0' : C₀' = expr; rw [hC0'] replaces C₀' by expr. Fine: ``` have hC₀'nn : (0:ℝ) ≤ C₀' := by rw [hC0']; linarith [lowZeroConst_nonneg, dirichletC2_nonneg, norm_nonneg (Gentire 0)] have hC₁nn : (0:ℝ) ≤ C₁ := by rw [hC1]; exact mul_nonneg (by norm_num) hA0nn have hcz : (1:ℝ) ≤ c := by rw [hc] -- hmm set already replaced? with `set c := ... with hc`, occurrences replaced; hc : c = ... ``` Wait — `set x := e with h` introduces x and h : x = e, and replaces e by x in goal. New goals I create via `have` don't auto-rewrite. So `have hcz : 1 ≤ c := by rw [hc]; ...`: after rw [hc], goal 1 ≤ 2 + (128*C₁ + 2*C₀')*‖z₀‖/ε. Proof: (128*C₁ + 2*C₀')*‖z₀‖/ε ≥ 0: div_nonneg (mul_nonneg (add_nonneg (mul_nonneg (by norm_num) hC₁nn) (mul_nonneg (by norm_num) hC₀'nn)) (norm_nonneg _)) hε.le. linarith. ``` -- choose k and R set M := max (c ^ 4) (‖z₀‖ + 1) with hM obtain ⟨k, hk4000, hkM⟩ : ∃ k : ℕ, 4000 ≤ k ∧ M ≤ 4 * (k:ℝ) := by refine ⟨max 4000 ⌈M / 4⌉₊, le_max_left _ _, ?_⟩ have h1 : M / 4 ≤ (⌈M / 4⌉₊ : ℝ) := Nat.le_ceil _ have h2 : (⌈M / 4⌉₊ : ℝ) ≤ (max 4000 ⌈M / 4⌉₊ : ℕ) := by exact_mod_cast le_max_right _ _ have h3 : M ≤ 4 * (⌈M / 4⌉₊ : ℝ) := by linarith [h1] calc M ≤ 4 * (⌈M / 4⌉₊ : ℝ) := h3 _ ≤ 4 * ((max 4000 ⌈M / 4⌉₊ : ℕ) : ℝ) := by apply mul_le_mul_of_nonneg_left _ (by norm_num : (0:ℝ) ≤ 4) exact_mod_cast le_max_right _ _ ``` Hmm — cast juggling: (4 * (k:ℝ)) where k = max 4000 ⌈M/4⌉₊; ((max a b : ℕ) : ℝ) = max (a:ℝ) (b:ℝ)? Nat.cast_max ✓ exists. Simpler: ``` have hceil : M ≤ 4 * (⌈M / 4⌉₊ : ℝ) := by have h1 := Nat.le_ceil (M / 4) linarith have hcast : (4 : ℝ) * (⌈M / 4⌉₊ : ℝ) ≤ 4 * ((max 4000 ⌈M / 4⌉₊ : ℕ) : ℝ) := by have : (⌈M / 4⌉₊ : ℝ) ≤ ((max 4000 ⌈M / 4⌉₊ : ℕ) : ℝ) := by exact_mod_cast le_max_right _ _ linarith linarith [hceil, hcast] ``` linarith fine (atoms: casts). ``` obtain ⟨R, hRlo, hRhi, hgapInt, hgap⟩ := exists_gapCircle_radius hZC (k := k) (by omega : 1 ≤ k) ``` Wait signature: exists_gapCircle_radius (hZC : ZeroCountProp) {k : ℕ} (hk : 1 ≤ k). k implicit — pass (k := k)? If implicit it unifies from hk? hk : 1 ≤ k forces it ✓ just `exists_gapCircle_radius hZC (by omega)` might leave k as metavariable resolved by hk — hk's type mentions k... ambiguous; safer to give explicitly. Check how LiCircleBound calls it... Fexpr_circle_le takes the gap properties as hypotheses, doesn't call exists_gapCircle_radius. Let me check if anything calls it — probably not yet (5e-v-d is the first consumer). I'll write `exists_gapCircle_radius hZC (k := k) (by omega)` — if k is implicit, (k := k) works; if explicit positional, adjust. ``` have hR16002 : (16002:ℝ) ≤ R := by have hkR : (16000:ℝ) ≤ 4 * (k:ℝ) := by have h1 : (4000:ℝ) ≤ (k:ℝ) := by exact_mod_cast hk4000 linarith linarith [hRlo] have hRpos : (0:ℝ) < R := by linarith [hR16002] have hlogR : (9:ℝ) ≤ Real.log R := nine_le_log_of_16002_le hR16002 have hMR : M ≤ R := by linarith [hkM, hRlo] -- the circle bound on the sphere have hsphere : ∀ z ∈ Metric.sphere (0:ℂ) R, ‖Gentire z‖ ≤ 2 * lowZeroConst + dirichletC2 + 400000 * A0count * C0hat (R + 2) * (Real.log R)^2 := by intro z hz have hznorm : ‖z‖ = R := by have h := Metric.mem_sphere.mp hz rw [dist_eq_norm, sub_zero] at h -- h : ‖z‖ = R? dist z 0 = ‖z - 0‖ = ‖z‖ exact h have hgood : ¬ badPoint z := not_badPoint_on_gapCircle hk4000 hRlo hgap hgapInt hznorm rw [gentire_eq_Fexpr hgood] exact Fexpr_circle_le hk4000 hRlo hRhi hgap hgapInt hznorm ``` Check `dist_eq_norm : dist x y = ‖x − y‖` — for ℂ yes (SeminormedGroup). `sub_zero : x − 0 = x` ✓. But rw [sub_zero] at h where h : ‖z − 0‖ = R: sub_zero is about z − (0:ℂ) ✓. ``` -- ball bound via max-modulus have hGan : AnalyticOn ℂ Gentire (Metric.closedBall 0 R) := (fun s _ => gentire_analyticAt_and_eq.1 s : AnalyticOnNhd ℂ Gentire _).analyticOn ``` Hmm — the ascription `(fun s _ => ... : AnalyticOnNhd ℂ Gentire _)` — AnalyticOnNhd ℂ f s : Prop := ∀ x ∈ s, AnalyticAt ℂ f x. The lambda fun s _ => gentire_analyticAt_and_eq.1 s : ∀ s, s ∈ closedBall 0 R → AnalyticAt ℂ Gentire s ✓ defeq. Then `.analyticOn`. Cleaner: ``` have hGan : AnalyticOn ℂ Gentire (Metric.closedBall 0 R) := AnalyticOnNhd.analyticOn (fun s _ => gentire_analyticAt_and_eq.1 s) ``` The expected type guides the lambda ✓. ``` have hball : ∀ z ∈ Metric.closedBall (0:ℂ) R, ‖Gentire z‖ ≤ 2 * lowZeroConst + dirichletC2 + 400000 * A0count * C0hat (R + 2) * (Real.log R)^2 := fun z hz => AnalyticOn.norm_le_of_norm_le_on_sphere le_rfl hGan hsphere hz ``` Wait — the lemma is stated with implicit {C r R} and our C is the big expression; unification from hsphere ✓. ``` -- MapsTo set RB := 2 * lowZeroConst + dirichletC2 + 400000 * A0count * C0hat (R + 2) * (Real.log R)^2 with hRB have hRBnn : (0:ℝ) ≤ RB := by rw [hRB] have hĈ : (0:ℝ) ≤ C0hat (R + 2) := by have h1 : (2:ℝ) ≤ C0hat (R + 2) := two_le_C0hat (by linarith [hRpos] : (1:ℝ) ≤ R + 2) linarith have hlogRnn : (0:ℝ) ≤ Real.log R := by linarith [hlogR] positivity-ish: add_nonneg (add_nonneg (mul_nonneg (by norm_num) lowZeroConst_nonneg) dirichletC2_nonneg) (mul_nonneg (mul_nonneg (mul_nonneg (by norm_num) hA0nn) hĈ) (pow_nonneg hlogRnn 2)) have hmaps : MapsTo Gentire (Metric.ball 0 R) (Metric.closedBall (Gentire 0) (RB + ‖Gentire 0‖)) := by intro z hz have hzball : z ∈ Metric.closedBall (0:ℂ) R := by rw [Metric.mem_ball] at hz; rw [Metric.mem_closedBall]; exact hz.le have h1 := hball z hzball rw [Metric.mem_closedBall, dist_eq_norm] calc ‖Gentire z - Gentire 0‖ ≤ ‖Gentire z‖ + ‖Gentire 0‖ := norm_sub_le _ _ _ ≤ RB + ‖Gentire 0‖ := by linarith [h1] ``` Hmm — linarith [h1] with h1 : ‖Gentire z‖ ≤ RB: goal ‖Gentire z‖ + ‖Gentire 0‖ ≤ RB + ‖Gentire 0‖ — linear ✓ but wait the gotcha: add_le_add_left/right swapped — linarith avoids it ✓. ``` -- Schwarz have hdiff : DifferentiableOn ℂ Gentire (Metric.ball 0 R) := fun z _ => (gentire_analyticAt_and_eq.1 z).differentiableAt.differentiableWithinAt have hz0mem : z₀ ∈ Metric.ball (0:ℂ) R := by rw [Metric.mem_ball, dist_eq_norm, sub_zero] have h1 : ‖z₀‖ + 1 ≤ M := le_max_right _ _ -- wait M := max (c^4) (‖z₀‖+1): le_max_right gives ‖z₀‖+1 ≤ M ✓ have h2 : ‖z₀‖ < M := by linarith [norm_nonneg z₀] linarith [hMR] have hschwarz := Complex.dist_le_div_mul_dist_of_mapsTo_ball hdiff hmaps hz0mem -- hschwarz : dist (Gentire z₀) (Gentire 0) ≤ (RB + ‖Gentire 0‖)/R * dist z₀ 0 rw [dist_eq_norm, sub_zero] at hschwarz ``` Hmm — `Complex.dist_le_div_mul_dist_of_mapsTo_ball` signature: (hd : DifferentiableOn ℂ f (ball c R₁)) (h_maps : MapsTo f (ball c R₁) (closedBall (f c) R₂)) (hz : z ∈ ball c R₁) : dist (f z) (f c) ≤ R₂ / R₁ * dist z c. Note it's stated for general E F normed spaces with f : E → F and ℂ differentiability — here E = ℂ. The ball is `ball c R₁` — from Schwarz.lean line 190, `ball c R₁` with open Metric? Schwarz.lean opens... the lemma uses `ball`/`closedBall` — in that file there's `open Metric`? The statement shows `MapsTo f (ball c R₁) (closedBall (f c) R₂)` — these are Metric.ball/closedBall ✓. Also note the implicit args: {f}, {c}, {z}, {R₁}, {R₂} — unified from args ✓. ``` -- hschwarz : dist (Gentire z₀) (Gentire 0) ≤ (RB + ‖Gentire 0‖) / R * ‖z₀‖ -- the growth bound: RB ≤ C₀' + 64*C₁*Q^3, R = Q^4, Q ≥ c set Q := R ^ ((4:ℝ)⁻¹) with hQ have hQnn : (0:ℝ) ≤ Q := Real.rpow_nonneg hRpos.le _ have hQpos : (0:ℝ) < Q := Real.rpow_pos_of_pos hRpos _ have hQc : c ≤ Q := by have h1 : c = (c ^ 4) ^ ((4:ℝ)⁻¹) := (Real.pow_rpow_inv_natCast hcnn'? (four ≠ 0)).symm ``` pow_rpow_inv_natCast (hx : 0 ≤ x) (hn : n ≠ 0) : (x ^ n) ^ (n⁻¹ : ℝ) = x. So ((c^4) ^ ((4:ℝ)⁻¹)) = c ✓. hc ≥ 1 ⟹ 0 ≤ c ✓ (hcnn2 : 0 ≤ c := by linarith [hcz]). ``` have h2 : (c ^ 4) ^ ((4:ℝ)⁻¹) ≤ R ^ ((4:ℝ)⁻¹) := Real.rpow_le_rpow (pow_nonneg (by linarith [hcz]) 4) (by have : c ^ 4 ≤ M := le_max_left _ _ linarith [hMR]) (by positivity : (0:ℝ) ≤ (4:ℝ)⁻¹) rw [h1] -- hmm goal c ≤ Q; rw h1 makes goal ((c^4)^((4:ℝ)⁻¹)) ≤ Q; Q is set-var := R^(4⁻¹) exact h2 -- h2 : (c^4)^(4⁻¹) ≤ R^(4⁻¹); Q is let/set: after set, R^(4⁻¹) displayed as Q; defeq ✓ exact h2 should work since set uses let? `set` introduces a local def; exact h2 with h2 mentioning R^(4⁻¹) — the goal shows Q but is defeq ✓. ``` Hmm — `set Q := R ^ ((4:ℝ)⁻¹) with hQ` replaces occurrences in the goal only; my new haves mention R^(4⁻¹) directly; goals will show Q after set? New have-goals I state myself — I control their statements, so I'll state them with R^((4:ℝ)⁻¹) or Q consistently. With `set`, hQ : Q = R ^ ((4:ℝ)⁻¹). When I prove h2 : (c^4)^((4:ℝ)⁻¹) ≤ R^((4:ℝ)⁻¹) and need c ≤ Q: rw [hQ] at goal? Goal c ≤ Q; rw [hQ] gives c ≤ R^(4⁻¹) ✓ then rw [h1] gives ((c^4)^(4⁻¹)) ≤ R^(4⁻¹) = h2 ✓. OK — but rw [hQ] rewrites Q → R^(4⁻¹) in goal (hQ : Q = ...; rw [hQ] replaces Q with RHS ✓). Actually simpler: avoid `set` for Q; just use R^((4:ℝ)⁻¹) throughout, with a `have hQdef`-free approach. Expression is a bit long but fine. Actually let me use `set` and be careful. Or `let`? `set` is fine. Continue: ``` have hL : Real.log R ≤ 4 * Q := by have h := Real.log_le_rpow_div hRpos.le (show (0:ℝ) < (4:ℝ)⁻¹ by positivity) -- h : log R ≤ R^((4:ℝ)⁻¹) / (4:ℝ)⁻¹ have h2 : R ^ ((4:ℝ)⁻¹) / (4:ℝ)⁻¹ = 4 * Q := by rw [hQ, div_eq_mul_inv, inv_inv] -- Q * 4 → 4 * Q by ring ring rw [h2] at h -- hmm h's RHS rewritten exact h ``` Careful: `rw [h2] at h` — h2 : R^(4⁻¹)/(4⁻¹) = 4*Q; rw [h2] at h : h : log R ≤ 4*Q ✓. But hQ : Q = R^(4⁻¹); inside h2 I rw [hQ] turning goal R^(4⁻¹)/(4⁻¹) = 4*Q into Q/(4⁻¹) = 4*Q... wait rw [hQ] rewrites Q→R^(4⁻¹) everywhere: goal becomes R^(4⁻¹)/(4⁻¹) = 4*(R^(4⁻¹)). Then div_eq_mul_inv: R^(4⁻¹) * (4⁻¹)⁻¹ = ...; inv_inv: (4⁻¹)⁻¹ = 4: R^(4⁻¹)*4 = 4*R^(4⁻¹): ring ✓. ``` have hL3 : (Real.log R)^3 ≤ 64 * Q^3 := by have h1 : (Real.log R)^3 ≤ (4 * Q)^3 := pow_le_pow_left (by linarith [hlogR]) hL 3 have h2 : (4 * Q)^3 = 64 * Q^3 := by ring rw [h2] at h1; exact h1 -- RB ≤ C₀' + C₁*(log R)^3 ≤ C₀' + 64*C₁*Q^3 have hĈ5 : C0hat (R + 2) ≤ 5 * Real.log R := C0hat_add_two_le hR16002 have hRBle : RB ≤ C₀' + 64 * C₁ * Q^3 := by have hlogRnn : (0:ℝ) ≤ Real.log R := by linarith [hlogR] have hstep1 : 400000 * A0count * C0hat (R + 2) * (Real.log R)^2 ≤ 400000 * A0count * (5 * Real.log R) * (Real.log R)^2 := by apply mul_le_mul_of_nonneg_right _ (pow_nonneg hlogRnn 2) apply mul_le_mul_of_nonneg_left hĈ5 exact mul_nonneg (by norm_num) hA0nn have hstep2 : 400000 * A0count * (5 * Real.log R) * (Real.log R)^2 = C₁ * (Real.log R)^3 := by rw [hC1]; ring -- 400000*A0*5*L*L^2 = 2000000*A0*L^3: ring handles L^2*L = L^3? ring with pow ✓ have hstep3 : C₁ * (Real.log R)^3 ≤ C₁ * (64 * Q^3) := mul_le_mul_of_nonneg_left hL3 hC₁nn -- assemble: RB = 2*lowZeroConst + dirichletC2 + [big] ≤ (C₀' - ‖Gentire 0‖) + C₁*64*Q^3 ≤ C₀' + 64*C₁*Q^3 rw [hRB, hC0'] -- goal: 2*lowZeroConst + dirichletC2 + big ≤ (2*lowZeroConst + dirichletC2 + ‖Gentire 0‖) + 64*C₁*Q^3 have hbig : 400000 * A0count * C0hat (R + 2) * (Real.log R)^2 ≤ 64 * C₁ * Q^3 := by have : C₁ * (Real.log R)^3 ≤ 64 * C₁ * Q^3 := by have h := mul_le_mul_of_nonneg_left hL3 hC₁nn -- C₁*L^3 ≤ C₁*(64*Q^3) -- C₁*(64*Q^3) = 64*C₁*Q^3 by ring — need a bridge have have h2 : C₁ * (64 * Q^3) = 64 * C₁ * Q^3 := by ring rwa [h2] at h linarith [hstep1, hstep2, this] -- hmm hstep2 is an equation: linarith handles ✓ have hG0nn : (0:ℝ) ≤ ‖Gentire 0‖ := norm_nonneg _ linarith [hbig, hG0nn] ``` Careful with `linarith [hstep1, hstep2, this]`: goal `400000 * A0count * C0hat (R + 2) * (Real.log R)^2 ≤ 64 * C₁ * Q^3`; hstep1 : LHS ≤ 400000*A0*(5*L)*L^2; hstep2 : 400000*A0*(5*L)*L^2 = C₁*L^3; this : C₁*L^3 ≤ 64*C₁*Q^3. linarith chains ✓ (all linear atoms). ``` -- the final real inequality: (RB + ‖Gentire 0‖)/R * ‖z₀‖ ≤ ε have hR4 : R = Q^4 := by have h := Real.rpow_inv_natCast_pow hRpos.le (show (4:ℕ) ≠ 0 by norm_num) -- h : (R^((4:ℝ)⁻¹))^4 = R; R^(4⁻¹) = Q by hQ.symm rw [← hQ] at h -- h : Q^4 = R exact h.symm ``` rpow_inv_natCast_pow (hx : 0 ≤ x) (hn : n ≠ 0) : (x ^ (n⁻¹ : ℝ)) ^ n = x. Here n : ℕ implicit? From the source: `theorem rpow_inv_natCast_pow (hx : 0 ≤ x) (hn : n ≠ 0) : (x ^ (n⁻¹ : ℝ)) ^ n = x` — n implicit presumably {n : ℕ}. Call: Real.rpow_inv_natCast_pow hRpos.le (show (4:ℕ) ≠ 0 by norm_num) : (R ^ ((4:ℕ)⁻¹ : ℝ)) ^ 4 = R. The exponent is (↑(4:ℕ))⁻¹ : ℝ = ((4:ℝ))⁻¹ — Nat.cast 4 = 4: the term R ^ (↑4)⁻¹ vs my Q := R ^ ((4:ℝ)⁻¹) — (↑(4:ℕ) : ℝ) is defeq to (4:ℝ) but syntactically different after set... rw [← hQ] at h needs syntactic match of R^((4:ℝ)⁻¹) inside h's (↑(4:ℕ))⁻¹ form — might fail! Fix: push_cast at h first: push_cast turns ((4:ℕ):ℝ)⁻¹ into (4:ℝ)⁻¹ ✓. So: `push_cast at h` then rw [← hQ] at h. ``` have hmain : (RB + ‖Gentire 0‖) / R * ‖z₀‖ ≤ ε := by rw [hR4] -- goal: (RB + ‖Gentire 0‖)/Q^4 * ‖z₀‖ ≤ ε have hQ4pos : (0:ℝ) < Q^4 := pow_pos hQpos 4 rw [div_mul_eq_mul_div, le_div_iff₀ hQ4pos] -- ((RB+‖Gentire 0‖) * ‖z₀‖) ≤ ε * Q^4 ``` Hmm: (X/Q⁴)*‖z₀‖ = X*‖z₀‖/Q⁴ (div_mul_eq_mul_div ✓). le_div_iff₀ (hc : 0 < c) : a ≤ b / c ↔ a * c ≤ b ✓. Goal: (RB+‖G0‖)*‖z₀‖*Q^4 ≤ ε... wait direction: a ≤ b/c ↔ a*c ≤ b: ((RB+‖G0‖)*‖z₀‖) * Q^4 ≤ ε ✓. ``` -- pieces have hc1 : (128 * C₁) * ‖z₀‖ ≤ ε * Q := by have h1 : (128 * C₁ + 2 * C₀') * ‖z₀‖ / ε ≤ c := by rw [hc] -- c = 2 + .../ε; linarith with the div nonneg? goal (128C₁+2C₀')‖z₀‖/ε ≤ 2 + (128C₁+2C₀')‖z₀‖/ε: linarith have h2 : (128 * C₁) * ‖z₀‖ ≤ (128 * C₁ + 2 * C₀') * ‖z₀‖ := by apply mul_le_mul_of_nonneg_right _ (norm_nonneg _) -- 128*C₁ ≤ 128*C₁ + 2*C₀' linarith [hC₀'nn, hC₁nn] -- hmm linarith: goal 128*C₁ ≤ 128*C₁ + 2*C₀' with 0 ≤ C₀' ✓ have h3 : (128 * C₁) * ‖z₀‖ / ε ≤ c := by have h4 : (128 * C₁) * ‖z₀‖ / ε ≤ (128 * C₁ + 2 * C₀') * ‖z₀‖ / ε := div_le_div_of_nonneg_right h2 hε.le -- check name: div_le_div_of_nonneg_right? session-032 gotcha: "div_le_div_of_nonneg_right exists / div_le_div_right does NOT" ✓ exact h4.trans h1 -- multiply through by ε calc (128 * C₁) * ‖z₀‖ = (128 * C₁) * ‖z₀‖ / ε * ε := by rw [div_mul_cancel₀ _ hε.ne'] _ ≤ c * ε := mul_le_mul_of_nonneg_right h3 hε.le _ ≤ Q * ε := mul_le_mul_of_nonneg_right hQc hε.le _ = ε * Q := by ring have hA : 64 * C₁ * Q^3 * ‖z₀‖ ≤ (ε/2) * Q^4 := by have h1 : (64 * C₁ * ‖z₀‖) * Q^3 ≤ ((ε/2) * Q) * Q^3 := by apply mul_le_mul_of_nonneg_right _ (pow_nonneg hQnn 3) -- 64*C₁*‖z₀‖ ≤ (ε/2)*Q have hhalf : (ε/2) * Q = (ε * Q)/2 := by ring rw [hhalf] -- goal 64*C₁*‖z₀‖ ≤ ε*Q/2 -- from hc1: 128*C₁*‖z₀‖ ≤ ε*Q have h128 : 128 * C₁ * ‖z₀‖ ≤ ε * Q := hc1 -- 64*C₁*‖z₀‖ = (128*C₁*‖z₀‖)/2 have h64 : (64:ℝ) * C₁ * ‖z₀‖ = (128 * C₁ * ‖z₀‖)/2 := by ring rw [h64]; linarith [h128] -- reassociate: (64*C₁*‖z₀‖)*Q^3 = 64*C₁*Q^3*‖z₀‖ and ((ε/2)*Q)*Q^3 = (ε/2)*Q^4 have hL : (64 * C₁ * ‖z₀‖) * Q^3 = 64 * C₁ * Q^3 * ‖z₀‖ := by ring have hR' : ((ε/2) * Q) * Q^3 = (ε/2) * Q^4 := by ring rwa [hL, hR'] at h1 have hB : C₀' * ‖z₀‖ ≤ (ε/2) * Q^4 := by have h1 : (2 * C₀') * ‖z₀‖ ≤ ε * Q := by have h2 : (2 * C₀') * ‖z₀‖ ≤ (128 * C₁ + 2 * C₀') * ‖z₀‖ := by apply mul_le_mul_of_nonneg_right _ (norm_nonneg _) linarith [hC₁nn] have h3 : (128 * C₁ + 2 * C₀') * ‖z₀‖ / ε ≤ c := by rw [hc]; linarith have h4 : (2 * C₀') * ‖z₀‖ / ε ≤ c := (div_le_div_of_nonneg_right h2 hε.le).trans h3 calc (2 * C₀') * ‖z₀‖ = (2 * C₀') * ‖z₀‖ / ε * ε := by rw [div_mul_cancel₀ _ hε.ne'] _ ≤ c * ε := mul_le_mul_of_nonneg_right h4 hε.le _ ≤ Q * ε := mul_le_mul_of_nonneg_right hQc hε.le _ = ε * Q := by ring have hQ2 : (2:ℝ) ≤ Q := by linarith [hQc, hcz] -- c ≥ 2? c = 2 + nonneg ≥ 2 ✓ (hcz was 1 ≤ c; need 2 ≤ c) have hQ3 : (8:ℝ) ≤ Q^3 := by have h := pow_le_pow_left (by norm_num : (0:ℝ) ≤ 2) hQ2 3 -- 2^3 ≤ Q^3 norm_num at h -- 2^3 = 8 exact h have h2 : ε * Q ≤ (ε/2) * Q^4 := by -- (ε/2)*Q^4 = (ε/2)*Q*Q^3 ≥ (ε/2)*Q*8 = 4*ε*Q ≥ ε*Q have h3 : (ε/2) * Q^4 = ((ε/2) * Q) * Q^3 := by ring rw [h3] have h4 : (ε/2) * Q * 1 ≤ ((ε/2) * Q) * Q^3 := by apply mul_le_mul_of_nonneg_left _ (by positivity : (0:ℝ) ≤ ε/2 * Q) linarith [hQ3] -- 1 ≤ Q^3 hmm: linarith with hQ3 : 8 ≤ Q^3 ⟹ 1 ≤ Q^3 ✓ have h5 : ε * Q = (ε/2) * Q * 2 := by ring rw [h5] -- 2 ≤ Q^3 mul-left have h6 : (ε/2) * Q * 2 ≤ (ε/2) * Q * Q^3 := mul_le_mul_of_nonneg_left (by linarith [hQ3] : (2:ℝ) ≤ Q^3) (by positivity : (0:ℝ) ≤ ε/2*Q) exact h6 -- C₀'*‖z₀‖ ≤ (2*C₀')*‖z₀‖/2 ≤ ε*Q/2 ≤ (ε/2)*Q^4/2?? hmm redo ``` Hmm — h1 : 2·C₀'·‖z₀‖ ≤ ε·Q and h2 : ε·Q ≤ (ε/2)·Q⁴. Then 2·C₀'·‖z₀‖ ≤ (ε/2)·Q⁴, so C₀'·‖z₀‖ ≤ (ε/2)·Q⁴ follows (C₀'‖z₀‖ ≤ 2·C₀'‖z₀‖). linarith-friendly: need the atoms aligned: (2*C₀')*‖z₀‖ vs 2*(C₀'*‖z₀‖) — ring-equal, linarith normalizes ✓. So: ``` have h7 : C₀' * ‖z₀‖ ≤ 2 * C₀' * ‖z₀‖ := by have h : (0:ℝ) ≤ C₀' * ‖z₀‖ := mul_nonneg hC₀'nn (norm_nonneg _) linarith [h] -- C₀'*‖z₀‖ ≤ 2*C₀'*‖z₀‖ = C₀'*‖z₀‖ + C₀'*‖z₀‖ ✓ linarith normalizes (2*C₀')*‖z₀‖ to 2*(C₀'*‖z₀‖) linarith [h7, h1, h2] ``` linarith: C₀'‖z₀‖ ≤ 2 C₀'‖z₀‖ ≤ εQ ≤ (ε/2)Q⁴ ✓ — wait h1 : (2*C₀')*‖z₀‖ ≤ ε*Q: linarith normalizes (2*C₀')*‖z₀‖ → 2*(C₀'*‖z₀‖) ✓ same atom. ``` -- assemble have hsum : (RB + ‖Gentire 0‖) * ‖z₀‖ ≤ ε * Q^4 := by have h1 : (RB + ‖Gentire 0‖) * ‖z₀‖ ≤ (C₀' + 64 * C₁ * Q^3 + ‖Gentire 0‖) * ‖z₀‖ := by apply mul_le_mul_of_nonneg_right _ (norm_nonneg _) linarith [hRBle, norm_nonneg (Gentire 0)] -- RB + ‖G0‖ ≤ C₀' + 64C₁Q³ + ‖G0‖ have h2 : (C₀' + 64 * C₁ * Q^3 + ‖Gentire 0‖) * ‖z₀‖ = C₀' * ‖z₀‖ + 64 * C₁ * Q^3 * ‖z₀‖ + ‖Gentire 0‖ * ‖z₀‖ := by ring -- hmm wait C₀' already contains ‖Gentire 0‖: C₀' + ‖Gentire 0‖ ≤ 2*C₀'... simplify: C₀'*‖z₀‖ + ‖G0‖*‖z₀‖ ≤ C₀'*‖z₀‖ + C₀'*‖z₀‖ since ‖G0‖ ≤ C₀' (as 2*lowZeroConst + dirichletC2 ≥ 0) have h3 : ‖Gentire 0‖ * ‖z₀‖ ≤ C₀' * ‖z₀‖ := by apply mul_le_mul_of_nonneg_right _ (norm_nonneg _) rw [hC0'] -- ‖G0‖ ≤ 2*lowZeroConst + dirichletC2 + ‖G0‖: linarith linarith [lowZeroConst_nonneg, dirichletC2_nonneg] linarith [h1, h2, h3, hA, hB] -- convert calc (RB + ‖Gentire 0‖) / Q^4 * ‖z₀‖ = (RB + ‖Gentire 0‖) * ‖z₀‖ / Q^4 := by ring _ ≤ ε := by rw [div_le_iff₀ hQ4pos]; linarith [hsum] -- wait direction ``` div_le_iff₀ (hc : 0 < c) : a / c ≤ b ↔ a ≤ b * c. Goal: (RB+‖G0‖)*‖z₀‖/Q⁴ ≤ ε. rw [div_le_iff₀ hQ4pos]: goal (RB+‖G0‖)*‖z₀‖ ≤ ε*Q⁴ = hsum ✓ exact hsum. Hmm wait — I did `rw [hR4]` earlier then `rw [div_mul_eq_mul_div, le_div_iff₀ hQ4pos]` in hmain — let me restructure hmain cleanly: ``` have hmain : (RB + ‖Gentire 0‖) / R * ‖z₀‖ ≤ ε := by have hQ4pos : (0:ℝ) < Q^4 := pow_pos hQpos 4 have h1 : (RB + ‖Gentire 0‖) / R * ‖z₀‖ = (RB + ‖Gentire 0‖) * ‖z₀‖ / Q^4 := by rw [hR4]; ring rw [h1, div_le_iff₀ hQ4pos] exact hsum ``` where hsum as above. But hsum/hA/hB are built inside... I should inline them all inside hmain's proof or as separate haves in the key block. Structure: build hsum first, then hmain. And div_le_iff₀ check: per session-033 gotcha "div_lt_iff₀ is a/c<b here" — that's for <. For ≤: `div_le_iff₀ (hc : 0 < c) : a / c ≤ b ↔ a ≤ b * c` ✓ standard. Then finish key: ``` calc dist (Gentire z₀) (Gentire 0) ≤ (RB + ‖Gentire 0‖) / R * ‖z₀‖ := hschwarz _ ≤ ε := hmain ``` Wait — hschwarz after rw [dist_eq_norm, sub_zero] at hschwarz : dist (Gentire z₀) (Gentire 0) ≤ (RB + ‖Gentire 0‖)/R * ‖z₀‖. But hold on: hschwarz's RHS has dist z₀ 0: rw [dist_eq_norm] at hschwarz rewrites BOTH dists (dist (Gentire z₀) (Gentire 0) too!) → ‖Gentire z₀ − Gentire 0‖ ≤ ... * ‖z₀ − 0‖; then sub_zero rewrites z₀ − 0 AND Gentire z₀ − Gentire 0... sub_zero rw [sub_zero] at hschwarz rewrites all `? − 0` — both. Then the final equality uses dist_eq_zero: ‖Gentire z₀ − Gentire 0‖ = 0 ↔ Gentire z₀ − Gentire 0 = 0 (norm_eq_zero) ↔ Gentire z₀ = Gentire 0 (sub_eq_zero). OK workable but let me instead NOT rw at hschwarz; bridge in the calc: ``` have hdz0 : dist z₀ 0 = ‖z₀‖ := by rw [dist_eq_norm, sub_zero] calc dist (Gentire z₀) (Gentire 0) ≤ (RB + ‖Gentire 0‖)/R * dist z₀ 0 := hschwarz _ = (RB + ‖Gentire 0‖)/R * ‖z₀‖ := by rw [hdz0] _ ≤ ε := hmain ``` Cleaner ✓. Then after key: ``` -- dist ≤ 0 ⟹ = 0 ⟹ eq have h0 : dist (Gentire z₀) (Gentire 0) ≤ 0 := by apply le_of_forall_pos_le_add -- hmm signature: (∀ ε, 0 < ε → a ≤ b + ε) → a ≤ b intro ε hε have := key ε hε linarith ``` Check le_of_forall_pos_le_add exists: `le_of_forall_pos_le_add : (∀ ε : α, 0 < ε → a ≤ b + ε) → a ≤ b` — I believe it exists in Mathlib (Algebra/Order/...). Alternatively: le_antisymm: dist ≤ 0 from... or use `le_of_forall_lt'`... I'll check via grep. Fallback: by_contra + Archimedean-free: if 0 < dist then key (dist/2) gives dist ≤ dist/2 contradiction. That's robust: ``` by_contra hne have hpos : 0 < dist (Gentire z₀) (Gentire 0) := by exact lt_of_not_ge (by ...)? ``` hmm — cleaner: ``` rcases le_or_lt (dist (Gentire z₀) (Gentire 0)) 0 with h | h · exact dist_eq_zero.mp (le_antisymm h dist_nonneg) -- gives Gentire z₀ = Gentire 0 ✓ · have h2 := key (dist (Gentire z₀) (Gentire 0) / 2) (by linarith) linarith ``` ✓ robust, no lemma-name risk. Wait — goal of gentire_const is `Gentire z₀ = Gentire 0`; dist_eq_zero.mp : dist x y = 0 → x = y ✓. Then the capstone: ``` theorem partialFraction_identity (hZC : ZeroCountProp) : ∃ B : ℂ, ∀ s : ℂ, riemannZeta s ≠ 0 → s ≠ 0 → s ≠ 1 → (∀ n : ℕ, 1 ≤ n → s ≠ -2 * (n : ℂ)) → logDeriv riemannZeta s = B + seriesFun s - 1 / s - 1 / (s - 1) + (Real.log Real.pi : ℂ) / 2 - Complex.digamma (s / 2) / 2 := by refine ⟨Gentire 0, fun s hζ hs0 hs1 hsn => ?_⟩ have hgood : ¬ badPoint s := by rintro (h | h | h | ⟨n, hn, h⟩) · exact hζ h.1 · exact hs0 h · exact hs1 h · exact hsn n hn h have hG : Fexpr s = Gentire 0 := by rw [← gentire_eq_Fexpr hgood] exact gentire_const hZC s rw [Fexpr] at hG -- unfold linear_combination hG ``` Check: hG : logDeriv riemannZeta s - seriesFun s + 1/s + 1/(s-1) - (↑(Real.log π))/2 + Complex.digamma (s/2)/2 = Gentire 0. Goal: logDeriv riemannZeta s = Gentire 0 + seriesFun s - 1/s - 1/(s-1) + (↑(Real.log π))/2 - Complex.digamma (s/2)/2. linear_combination hG: LHS−RHS = (logDeriv ζ s) − (Gentire 0 + seriesFun s − 1/s − 1/(s−1) + logπ/2 − ψ/2); hG's LHS−RHS = (logDeriv − seriesFun + 1/s + 1/(s−1) − logπ/2 + ψ/2) − Gentire 0. Sum = 0? LHS−RHS − hG(LHS−RHS) = logDeriv − G0 − seriesFun + 1/s + 1/(s−1) − logπ/2 + ψ/2 − logDeriv + seriesFun − 1/s − 1/(s−1) + logπ/2 − ψ/2 + G0 = 0 ✓. So linear_combination hG works (coefficient 1). But wait: `rw [Fexpr] at hG` — does rw with a def name work here? In LiCircleBound they used `rw [Fexpr]` (line 3846). ✓ same mechanism. One concern: hsn : ∀ n : ℕ, 1 ≤ n → s ≠ -2 * (n : ℂ). badPoint's fourth disjunct: ∃ n : ℕ, 1 ≤ n ∧ s = -2 * (n : ℂ). rintro pattern ⟨n, hn, h⟩ gives h : s = -2 * (n : ℂ); hsn n hn : s ≠ -2*(n:ℂ) — exact match? badPoint def: `∃ n : ℕ, 1 ≤ n ∧ s = -2 * (n : ℂ)` ✓. hsn's form: ∀ n : ℕ, 1 ≤ n → s ≠ -2 * (n : ℂ) ✓ same. exact hsn n hn h ✓. And h.1 for IsNontrivialZero: IsNontrivialZero s := riemannZeta s = 0 ∧ ...; h.1 : riemannZeta s = 0; hζ : riemannZeta s ≠ 0 ✓. Now §2 `not_badPoint_on_gapCircle` — the on-circle goodness: ``` lemma not_badPoint_on_gapCircle {k : ℕ} (hk : 4000 ≤ k) {R : ℝ} (hRlo : 4 * (k:ℝ) + 5/2 ≤ R) (hgap : ∀ ρ : ℂ, IsNontrivialZero ρ → 1 / (16 * C0hat (4 * (k:ℝ) + 9/2)) ≤ |ρ.im - R| ∨ 1 ≤ |ρ.im - R|) (hgapInt : ∀ m : ℤ, 1/4 ≤ |R/2 - (m:ℝ)|) {s : ℂ} (hs : ‖s‖ = R) : ¬ badPoint s := by have hR16002 : (16002:ℝ) ≤ R := by have h1 : (4000:ℝ) ≤ (k:ℝ) := by exact_mod_cast hk linarith [hRlo] have hRpos : (0:ℝ) < R := by linarith [hR16002] rintro (h | h | h | ⟨n, hn, h⟩) · exact not_isNontrivialZero_on_gapCircle hk hRlo hgap hs h · -- s = 0 rw [h] at hs rw [norm_zero] at hs -- hs : 0 = R linarith [hRpos] · -- s = 1 rw [h] at hs rw [norm_one] at hs -- hs : 1 = R linarith [hR16002] · -- s = -2n have hR2 : R = 2 * (n:ℝ) := by rw [← hs, h] -- goal: ‖(-2:ℂ)*(n:ℂ)‖ = 2*(n:ℝ) rw [norm_mul] have h1 : ‖(-2:ℂ)‖ = 2 := by rw [show (-2:ℂ) = ((-2:ℝ):ℂ) by push_cast; ring, Complex.norm_real] norm_num have h2 : ‖(n:ℂ)‖ = (n:ℝ) := Complex.norm_natCast n -- check name rw [h1, h2] have hcon := hgapInt (n:ℤ) rw [Int.cast_natCast] at hcon -- ((n:ℤ):ℝ) = (n:ℝ) have h0 : R/2 - (n:ℝ) = 0 := by rw [hR2]; ring rw [h0, abs_zero] at hcon linarith [hcon] -- 1/4 ≤ 0 false ``` Wait: rw [← hs, h]: goal R = 2*(n:ℝ); rw [← hs] turns R into ‖s‖: ‖s‖ = 2*(n:ℝ); rw [h] turns s into -2*(n:ℂ): ‖-2*(n:ℂ)‖ = 2*(n:ℝ) ✓. Check `Complex.norm_natCast` name — grep needed. In Mathlib: `Complex.norm_natCast (n : ℕ) : ‖(n : ℂ)‖ = n` — I'm fairly sure it exists (norm_natCast general? `norm_natCast` in a NormedField... For ℂ specifically there should be Complex.norm_natCast). Fallback: `by simp` or Complex.norm_ofNat... I'll grep. Also `Int.cast_natCast : ((↑n : ℤ) : α) = ↑n` ✓ standard name. Wait, hgapInt (n:ℤ) : 1/4 ≤ |R/2 - ((n:ℤ):ℝ)| — the coercion ((n:ℤ):ℝ) is Int.cast; rw [Int.cast_natCast] at hcon changes it to (n:ℝ) ✓. Also `not_isNontrivialZero_on_gapCircle` — verify its exact signature: used at line 3815: `not_isNontrivialZero_on_gapCircle hk hRlo hgap hs : ¬ IsNontrivialZero s`. ✓ matches my usage. §1 C0hat_add_two_le — check `Real.log_le_sub_one_of_pos` name and `Real.log_le_log` signature. LiCircleBound used `Real.log_le_log (by ... : (0:ℝ) < 2 + R/2) (by linarith : ...)` — wait line 3894: `apply Real.log_le_log (by linarith [hRpos] : (0 : ℝ) < 2 + R / 2)` then `linarith [hR]` — so Real.log_le_log takes hx : 0 < x first, then remaining goal x ≤ y ✓. `Real.log_le_sub_one_of_pos`: grep to verify. Now — imports for LiSqueeze.lean: `import NguyenRH1.LiCircleBound` suffices (transitively gets LiFEntire, LiGapCircles, Mathlib, Zeta23.RvM.LocalCount). But `exists_gapCircle_radius` is in LiGapCircles ✓ transitively imported. `Metric`, `MapsTo`, `Complex.dist_le_div_mul_dist_of_mapsTo_ball` need Mathlib ✓ (LiCircleBound imports full Mathlib). `open Zeta23 Complex Filter Topology` mirror LiCircleBound. Note: `AnalyticOn.norm_le_of_norm_le_on_sphere` — from Zeta23 StrongPNTPrefix; is it transitively imported? LiCircleBound imports LiDisc which imports...? LiDisc used LogOfAnalyticFunction + BorelCaratheodoryDeriv from StrongPNTPrefix presumably. Let me verify LiDisc imports StrongPNTPrefix. If not, add `import Zeta23.FromPNTPlus.StrongPNTPrefix`. Let me check LiDisc's imports and the `open` in LiCircleBound (line ~27: open Zeta23 Complex Filter Topology). Also need `Real.rpow_le_rpow`, `Real.rpow_nonneg`, `Real.rpow_pos_of_pos`, `Real.rpow_inv_natCast_pow`, `Real.pow_rpow_inv_natCast`, `Real.log_le_rpow_div`, `pow_le_pow_left`, `pow_pos`, `pow_nonneg`, `Nat.le_ceil`, `le_max_left/right`, `div_le_div_of_nonneg_right`, `div_mul_cancel₀`, `div_le_iff₀`, `mul_le_mul_of_nonneg_left/right`, `dist_eq_zero`, `dist_nonneg`, `norm_sub_le`, `Metric.mem_ball/mem_closedBall/mem_sphere` — all standard Mathlib; verify the few risky ones: pow_le_pow_left (current name in this Mathlib version), le_of_forall_pos_le_add (not needed — using the by-cases approach), Complex.norm_natCast, Real.log_le_sub_one_of_pos. Let me grep these in Mathlib now. Then write the file.
All signatures verified. Checking the last few lemma names before writing.
tool: Bash
input
{
  "command": "M=D:/Python/Quantum/zeta-23-lean/.lake/packages/mathlib/Mathlib; grep -rn \"theorem pow_le_pow_left \\|theorem pow_le_pow_left{\" $M/Algebra/Order/*.lean $M/Algebra/Order/**/*.lean 2>/dev/null | head -3; grep -rn \"log_le_sub_one_of_pos\" $M/Analysis/SpecialFunctions/Log/Basic.lean | head -2; grep -rn \"theorem norm_natCast\\|lemma norm_natCast\" $M/Analysis/Complex/Basic.lean $M/Analysis/Normed/*.lean 2>/dev/null | head -3; grep -rn \"import Zeta23\" D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1/LiDisc.lean | head -3",
  "description": "Verify pow_le_pow_left, log_le_sub_one, norm_natCast, LiDisc imports"
}
#1683 assistant 2026-08-24 06:12:39.512 UTC · 353→10069 tok open ⤢
thinking (25311 chars)
`pow_le_pow_left₀ (ha : 0 ≤ a) (hab : a ≤ b) (n) : a ^ n ≤ b ^ n` — the current name in this Mathlib (v4.33). ✓ All names verified: - `pow_le_pow_left₀` (not pow_le_pow_left) - `Real.log_le_sub_one_of_pos` ✓ - `Complex.norm_natCast` (used in LiCircleBound:3410) ✓ - `Real.log_le_rpow_div` ✓ - `Real.pow_rpow_inv_natCast (hx : 0 ≤ x) (hn : n ≠ 0) : (x ^ n) ^ (n⁻¹ : ℝ) = x` ✓ - `Real.rpow_inv_natCast_pow (hx : 0 ≤ x) (hn : n ≠ 0) : (x ^ (n⁻¹ : ℝ)) ^ n = x` ✓ - `Complex.dist_le_div_mul_dist_of_mapsTo_ball` ✓ - `AnalyticOn.norm_le_of_norm_le_on_sphere` (Zeta23 StrongPNTPrefix) ✓ — LiDisc imports StrongPNTPrefix ✓ transitively available. - `AnalyticAt.differentiableAt` ✓ Mark todo 2 done, todo 3 in progress. Now write LiSqueeze.lean. Plan the structure: ```lean /- NguyenRH1/LiSqueeze.lean — tier ii′ sub-stage ii′-5e-v-d (D-068 §5): the Schwarz squeeze and the partial-fraction capstone. ... -/ import Mathlib import NguyenRH1.LiCircleBound open Zeta23 Complex Filter Topology noncomputable section namespace NguyenRH1 ``` Wait — LiCircleBound's open line: `open Zeta23 Complex Filter Topology`. Is there also a `noncomputable section` + namespace? Check LiCircleBound line 31: `noncomputable section` and presumably `namespace NguyenRH1`. Let me check the exact header to mirror. Also the end: `end NguyenRH1` then `end` (the noncomputable section end). Mirror that. Now write the whole file. Let me be careful about a few more details: 1. In §3 `gentire_circle_le`, Fexpr_circle_le's signature: `{k : ℕ} (hk : 4000 ≤ k) {R : ℝ} (hRlo : ...) (_hRhi : ...) (hgap : ...) (hgapInt : ...) {s : ℂ} (hs : ‖s‖ = R)`. ✓. 2. `not_isNontrivialZero_on_gapCircle` exact signature — grep it to be sure about argument order (hk hRlo hgap hs). 3. `nine_le_log_of_16002_le` ✓ used in LiCircleBound:3826. 4. `two_le_C0hat {t : ℝ} (ht : 1 ≤ t) : 2 ≤ C0hat t` ✓. 5. `A0count_pos` — used at line 3828: `A0count_pos.le` ✓ exists. 6. `lowZeroConst_nonneg`, `dirichletC2_nonneg` — used at 3922 ✓. 7. `gentire_eq_Fexpr` — signature `(hygood : ¬ badPoint y) : Gentire y = Fexpr y`? From line 1109: `rw [gentire_eq_Fexpr hygood]` where the goal mentions Gentire y... rw with the equation Gentire y = Fexpr y rewrites Gentire y → Fexpr y ✓. And in my step: I have goal ‖Gentire z‖ ≤ RB; rw [gentire_eq_Fexpr hgood] turns goal into ‖Fexpr z‖ ≤ RB ✓. 8. The capstone: `badPoint` disjunct 4 is `∃ n : ℕ, 1 ≤ n ∧ s = -2 * (n : ℂ)`. In LiFEntire line 75: `∃ n : ℕ, 1 ≤ n ∧ s = -2 * (n : ℂ)` ✓. 9. In the capstone statement, D-068 §5 writes `digamma (s/2)/2`. Fexpr def line 70: `Complex.digamma (s / 2) / 2` ✓. 10. For `exists_gapCircle_radius hZC (k := k)`: signature `(hZC : ZeroCountProp) {k : ℕ} (hk : 1 ≤ k)`. k implicit → use (k := k). 11. `Real.rpow_le_rpow`: signature `(hx : 0 ≤ x) (hxy : x ≤ y) (hz : 0 ≤ z) : x ^ z ≤ y ^ z` ✓ standard. 12. `Real.rpow_pos_of_pos (hx : 0 < x) (r : ℝ) : 0 < x ^ r` ✓. `Real.rpow_nonneg (hx : 0 ≤ x) (r : ℝ) : 0 ≤ x ^ r` ✓. 13. `div_mul_cancel₀ : a / b * b = a` needs b ≠ 0: `div_mul_cancel₀ (a : α) (h : b ≠ 0) : a / b * b = a`? Signature check: in Mathlib `div_mul_cancel₀ (a : G₀) (h : b ≠ 0) : a / b * b = a`. Hmm it might be `div_mul_cancel₀ (h : b ≠ 0) : a / b * b = a` with a explicit... Let me just use `by field_simp` or the calc with explicit forms. Actually for `(128 * C₁) * ‖z₀‖ / ε * ε = (128*C₁)*‖z₀‖`: `div_mul_cancel₀` — current form: `theorem div_mul_cancel₀ (a : G₀) {b : G₀} (h : b ≠ 0) : a / b * b = a`. I'll write `(div_mul_cancel₀ _ hε.ne').symm` hmm wait direction: I want (128*C₁*‖z₀‖) = (128*C₁*‖z₀‖/ε)*ε as the first calc step "X = X/ε*ε": `(div_mul_cancel₀ _ hε.ne').symm : a = a / ε * ε` ✓. 14. `div_le_div_of_nonneg_right` — session-032 gotcha says it EXISTS ✓: `div_le_div_of_nonneg_right (hab : a ≤ b) (hc : 0 ≤ c) : a / c ≤ b / c`? Hmm — actually wait, that gotcha said "div_le_div_of_nonneg_right exists / div_le_div_right does NOT". But what are its args? Might be (h : a ≤ b) (hc : 0 ≤ c). I'll trust and adjust if the build complains. Hmm wait, actually in current Mathlib, div_le_div_of_nonneg_right... Let me double check it's for a/c ≤ b/c given a ≤ b, c ≥ 0 — "right" refers to c on the right ✓. 15. In hc1's first have: `(128 * C₁ + 2 * C₀') * ‖z₀‖ / ε ≤ c` where c = 2 + (128*C₁+2*C₀')*‖z₀‖/ε. With `set c := ... with hc`, rw [hc] changes goal c → the expr? NO — hc : c = expr; rw [hc] rewrites occurrences of c with expr: goal becomes expr ≤ expr-ish: (128*C₁+2*C₀')*‖z₀‖/ε ≤ 2 + (128*C₁+2*C₀')*‖z₀‖/ε — linarith closes (needs no hypotheses; the atom (128*C₁+2*C₀')*‖z₀‖/ε appears both sides) ✓. Hmm wait — after `set c := 2 + X with hc`, the goal (if any) has c substituted. In `have h1 : X ≤ c := by rw [hc]; linarith` — the have statement is written by me with c; rw [hc] rewrites c → 2 + X: goal X ≤ 2 + X; linarith — X is the atom `(128 * C₁ + 2 * C₀') * ‖z₀‖ / ε`; linarith treats nonlinear/div as atom ✓ closes: X ≤ 2 + X ⟸ 0 ≤ 2 ✓. 16. hcz : 2 ≤ c (I need c ≥ 2 for hQ3): rw [hc]; goal 2 ≤ 2 + X with X ≥ 0: have hX : 0 ≤ (128*C₁ + 2*C₀')*‖z₀‖/ε := div_nonneg (mul_nonneg (add_nonneg (mul_nonneg (by norm_num) hC₁nn) (mul_nonneg (by norm_num) hC₀'nn)) (norm_nonneg _)) hε.le; linarith [hX]. 17. For `hcnn : 0 ≤ c` (needed for pow_rpow_inv_natCast): linarith [hcz]. 18. hQc proof: ``` have hQc : c ≤ Q := by have hc4 : c ^ 4 ≤ R := by have h : c ^ 4 ≤ M := le_max_left _ _ linarith [hMR] have h1 : c = (c ^ 4) ^ ((4:ℝ)⁻¹) := (Real.pow_rpow_inv_natCast hcnn (by norm_num : (4:ℕ) ≠ 0)).symm ``` Careful: pow_rpow_inv_natCast (hx : 0 ≤ x) (hn : n ≠ 0) : (x ^ n) ^ (↑n)⁻¹ = x — n implicit {n : ℕ}? The statement: `theorem pow_rpow_inv_natCast (hx : 0 ≤ x) (hn : n ≠ 0) : (x ^ n) ^ (n⁻¹ : ℝ) = x`. The n⁻¹ : ℝ is (↑n)⁻¹ — with n := 4: (c^4)^((↑(4:ℕ))⁻¹ : ℝ)... the displayed form (n⁻¹ : ℝ) means ((n : ℝ))⁻¹. So h1's RHS is (c^4)^(((4:ℕ):ℝ))⁻¹; my Q is R^((4:ℝ)⁻¹). The cast forms differ syntactically: ((4:ℕ):ℝ) vs (4:ℝ). rpow_le_rpow will produce R^(((4:ℕ):ℝ))⁻¹ if I feed... no wait — rpow_le_rpow's exponent is whatever I write in the goal. Since goal mentions Q := R^((4:ℝ)⁻¹), h2 must match: (c^4)^((4:ℝ)⁻¹) ≤ R^((4:ℝ)⁻¹). And h1 : c = (c^4)^(((4:ℕ):ℝ))⁻¹. Mismatch (4:ℕ):ℝ vs (4:ℝ). push_cast at h1 turns ((4:ℕ):ℝ) into (4:ℝ)? push_cast with Nat.cast_ofNat simp lemma: ((4:ℕ):ℝ) → (4:ℝ) ✓ push_cast handles. So: ``` have h1 : c = (c ^ 4) ^ ((4:ℝ)⁻¹) := by have h := (Real.pow_rpow_inv_natCast (x := c) (n := 4) hcnn (by norm_num)).symm push_cast at h exact h ``` Hmm, can I pass (n := 4) if n is implicit? `Real.pow_rpow_inv_natCast (hx : 0 ≤ x) (hn : n ≠ 0)` — n appears in hn's type so it's determined by hn : (4:ℕ) ≠ 0 — wait hn : n ≠ 0 with n : ℕ implicit; passing (by norm_num : (4:ℕ) ≠ 0) fixes n := 4 ✓ no need for named (n := 4). But actually — is it (x := c) explicit-named? x implicit {x}? The statement has (hx : 0 ≤ x) explicit so x implicit. Just: `Real.pow_rpow_inv_natCast hcnn (show (4:ℕ) ≠ 0 by norm_num)` : (c ^ 4) ^ (((4:ℕ):ℝ))⁻¹ = c — hmm wait, will Lean elaborate `(n⁻¹ : ℝ)` with n a metavariable until hn given? hn : n ≠ 0 — the `show (4:ℕ) ≠ 0` fixes it ✓. Then .symm : c = (c^4)^(↑4)⁻¹. push_cast at h: normalizes ((4:ℕ):ℝ)⁻¹... push_cast rewrites Nat.cast_ofNat: ↑(4:ℕ) = (4:ℝ)? The simp lemma `Nat.cast_ofNat : ((OfNat.ofNat n : ℕ) : α) = OfNat.ofNat n` ✓ push_cast uses it. So h : c = (c^4)^((4:ℝ)⁻¹) ✓. But hold on — is the exponent in pow_rpow_inv_natCast exactly `(↑n)⁻¹`? Source line 506-508: `theorem pow_rpow_inv_natCast (hx : 0 ≤ x) (hn : n ≠ 0) : (x ^ n) ^ (n⁻¹ : ℝ) = x`. In Lean source `(n⁻¹ : ℝ)` means ((n : ℝ))⁻¹ ✓. Then: ``` have h2 : (c ^ 4) ^ ((4:ℝ)⁻¹) ≤ Q := Real.rpow_le_rpow (pow_nonneg (by linarith [hcz] : (0:ℝ) ≤ c) 4) hc4 (by positivity : (0:ℝ) ≤ (4:ℝ)⁻¹) ``` wait — Q is set to R^((4:ℝ)⁻¹); h2's statement I write as ≤ Q directly (rpow_le_rpow produces ≤ R^((4:ℝ)⁻¹); with set, the goal/have type I write `... ≤ Q` and the proof produces `... ≤ R^((4:ℝ)⁻¹)` — after `set`, R^((4:ℝ)⁻¹) is defeq-displayed as Q; does `exact`/`show` accept? `set` uses `let`-like local definition? `set x := e` introduces x as a local definition and h : x = e; the tactic state goal is rewritten, and terms with e are NOT auto-folded in my own haves — but defeq holds (x is a local hyp with value? `set` introduces x := e as a let-binding in the context; typechecking h2 : ... ≤ Q against proof of ... ≤ R^(4⁻¹) — is it defeq? set adds `x : α := e` as a let var; Q unfolds to R^(4⁻¹) definitionally ✓ exact works). To be safe I can rw [← hQ] to convert. I'll write h2 with Q in the statement and give proof via rpow_le_rpow ... and if elaboration gripes, add `rw [← hQ]; exact ...`. Then finish: `rw [h1]; exact h2` — goal c ≤ Q; rw [h1] — h1 : c = (c^4)^(4⁻¹); rw rewrites c → RHS in goal: (c^4)^(4⁻¹) ≤ Q ✓ exact h2. Hmm, rw [h1] rewrites ALL c occurrences — the goal c ≤ Q has only one c ✓. 19. hR4 : R = Q^4: ``` have hR4 : R = Q ^ 4 := by have h := Real.rpow_inv_natCast_pow (x := R) ... ``` rpow_inv_natCast_pow (hx : 0 ≤ x) (hn : n ≠ 0) : (x ^ (n⁻¹ : ℝ)) ^ n = x: `Real.rpow_inv_natCast_pow hRpos.le (show (4:ℕ) ≠ 0 by norm_num)` : (R ^ ((4:ℕ):ℝ)⁻¹)^4 = R. push_cast at h; then h : (R^((4:ℝ)⁻¹))^4 = R; rw [← hQ] at h: h : Q^4 = R; exact h.symm. Careful: rw [← hQ] at h rewrites R^((4:ℝ)⁻¹) → Q in h ✓ (hQ : Q = R^(4⁻¹); ← direction rewrites RHS→LHS: R^(4⁻¹) → Q ✓). But it would also rewrite R^(4⁻¹) inside... h : (R^((4:ℝ)⁻¹))^4 = R — the outer R in "= R" is not R^(4⁻¹) ✓ fine. 20. div_mul_eq_mul_div : a / b * c = a * c / b ✓ standard name. 21. The `key` have: after intro ε hε, the final calc: ``` have hdz0 : dist z₀ (0:ℂ) = ‖z₀‖ := by rw [dist_eq_norm, sub_zero] calc dist (Gentire z₀) (Gentire 0) ≤ (RB + ‖Gentire 0‖) / R * dist z₀ 0 := hschwarz _ = (RB + ‖Gentire 0‖) / R * ‖z₀‖ := by rw [hdz0] _ ≤ ε := hmain ``` hschwarz's type: dist (Gentire z₀) (Gentire 0) ≤ (RB + ‖Gentire 0‖)/R * dist z₀ (0) — wait the Schwarz statement: dist (f z) (f c) ≤ R₂ / R₁ * dist z c with c := (0:ℂ) ✓. Hmm — one subtlety: `Metric.ball` vs `ball` in Schwarz.lean — the file has `open Metric` presumably; the lemma's ball is Metric.ball ✓. And in Mathlib Schwarz.lean the quantifiers: {f : E → F} {c z : E} {R₁ R₂ : ℝ}. E := ℂ ✓ (DifferentiableOn ℂ f requires E a normed space over ℂ ✓). 22. hschwarz call: `Complex.dist_le_div_mul_dist_of_mapsTo_ball hdiff hmaps hz0mem`. With `open Complex` in scope (LiCircleBound opens Complex), might clash-free either way; write fully qualified ✓. 23. Also — IMPORTANT: does the file's `open Complex` shadow `dist_le_div_mul_dist_of_mapsTo_ball`? No, fine. 24. In hmain I need hQ4pos and the conversion h1. But hR4 : R = Q^4: rw [hR4] inside h1's proof: goal (RB + ‖Gentire 0‖)/R*‖z₀‖ = (RB+‖Gentire 0‖)*‖z₀‖/Q^4; rw [hR4] changes R → Q^4 ✓ then ring: (X)/(Q^4)*Y = X*Y/(Q^4) — ring handles division? ring works in fields ✓ (Q^4 a nonzero atom? ring treats division as mul by inv, field identities hold formally — ring can prove a/b*c = a*c/b in a field without nonzero side conditions? `ring` works in commutative (semi)rings; with division it needs `field_simp` semantics — actually ring DOES handle field expressions with / as inv-mul, and a/b*c = a*c/b is a valid commutative-group identity (b⁻¹ commutes) — yes ring proves it without nonzero hyps since inv is total (0⁻¹ = 0) and the identity a*b⁻¹*c = a*c*b⁻¹ holds in any commutative group-with-zero ✓). 25. hsum assembly detail: (RB + ‖Gentire 0‖)*‖z₀‖ ≤ ε*Q^4. h1 : (RB + ‖G0‖)*‖z₀‖ ≤ (C₀' + 64*C₁*Q^3 + ‖G0‖)*‖z₀‖ via mul_le_mul_of_nonneg_right (add_le_add_right hRBle _)... wait: RB ≤ C₀' + 64*C₁*Q^3 (hRBle) ⟹ RB + ‖G0‖ ≤ C₀' + 64*C₁*Q^3 + ‖G0‖ (add_le_add_right hRBle _) ✓ then mul right. h2 : (C₀' + 64*C₁*Q^3 + ‖G0‖)*‖z₀‖ = C₀'*‖z₀‖ + 64*C₁*Q^3*‖z₀‖ + ‖G0‖*‖z₀‖ by ring ✓. h3 : ‖G0‖*‖z₀‖ ≤ C₀'*‖z₀‖: mul_le_mul_of_nonneg_right (h : ‖G0‖ ≤ C₀') (norm_nonneg _): ‖G0‖ ≤ C₀' = 2*lowZeroConst + dirichletC2 + ‖G0‖: linarith [lowZeroConst_nonneg, dirichletC2_nonneg] after rw [hC0'] — goal ‖Gentire 0‖ ≤ C₀'; rw [hC0'] : ‖G0‖ ≤ 2*lowZeroConst + dirichletC2 + ‖G0‖; linarith [h1nn, h2nn] ✓. Final: linarith [h1, h2, h3, hA, hB] — goal (RB+‖G0‖)*‖z₀‖ ≤ ε*Q⁴. Atoms: (RB+‖G0‖)*‖z₀‖, the products... linarith sees h1 : A ≤ B, h2 : B = C (equation), h3 : D ≤ E, hA : F ≤ (ε/2)*Q⁴, hB : G ≤ (ε/2)*Q⁴ where C = E + F + D... linarith: A ≤ B = C = C₀'‖z₀‖ + 64C₁Q³‖z₀‖ + ‖G0‖‖z₀‖ ≤ C₀'‖z₀‖ + (ε/2)Q⁴ + C₀'‖z₀‖ — hmm need 2·C₀'‖z₀‖ bound but hB : C₀'·‖z₀‖ ≤ (ε/2)·Q⁴ and h3: ‖G0‖‖z₀‖ ≤ C₀'‖z₀‖ ⟹ sum: C₀'‖z₀‖ + 64C₁Q³‖z₀‖ + ‖G0‖‖z₀‖ ≤ (ε/2)Q⁴ + (ε/2)Q⁴ + (ε/2)Q⁴ = 1.5·εQ⁴ — TOO BIG! Redo: the decomposition should be (C₀' + 64C₁Q³)*‖z₀‖ — WITHOUT the extra ‖G0‖. Fold ‖Gentire 0‖ into C₀' — wait C₀' := 2*lowZeroConst + dirichletC2 + ‖Gentire 0‖ ALREADY includes it! RB + ‖G0‖ ≤ (C₀' + 64C₁Q³) ⟸ RB ≤ C₀' + 64C₁Q³ − ‖G0‖... no: RB = 2*lowZeroConst + dirichletC2 + big; C₀' = 2*lowZeroConst + dirichletC2 + ‖G0‖; so RB + ‖G0‖ = (2low+dir+big) + ‖G0‖ ≤ (2low+dir+‖G0‖) + big' where big ≤ big'... RB + ‖G0‖ = C₀' + big ≤ C₀' + 64C₁Q³ ✓ — i.e., RB + ‖G0‖ ≤ C₀' + 64·C₁·Q³ directly! Because RB = C₀' − ‖G0‖ + big ≤ C₀' + big. So define hRBle' : RB + ‖Gentire 0‖ ≤ C₀' + 64*C₁*Q^3 directly: ``` have hRBle' : RB + ‖Gentire 0‖ ≤ C₀' + 64 * C₁ * Q^3 := by rw [hRB, hC0'] -- (2*low + dir + big) + ‖G0‖ ≤ (2*low + dir + ‖G0‖) + 64*C₁*Q^3 linarith [hbig] -- hbig : big ≤ 64*C₁*Q^3 ``` ✓ linarith with atoms big, 64*C₁*Q^3, and the rest canceling. Then hsum : (RB + ‖G0‖)*‖z₀‖ ≤ (C₀' + 64C₁Q³)*‖z₀‖ = C₀'‖z₀‖ + 64C₁Q³‖z₀‖ ≤ (ε/2)Q⁴ + (ε/2)Q⁴ = εQ⁴: ``` have hsum : (RB + ‖Gentire 0‖) * ‖z₀‖ ≤ ε * Q^4 := by have h1 : (RB + ‖Gentire 0‖) * ‖z₀‖ ≤ (C₀' + 64 * C₁ * Q^3) * ‖z₀‖ := mul_le_mul_of_nonneg_right hRBle' (norm_nonneg _) have h2 : (C₀' + 64 * C₁ * Q^3) * ‖z₀‖ = C₀' * ‖z₀‖ + 64 * C₁ * Q^3 * ‖z₀‖ := by ring linarith [h1, h2, hA, hB] ``` hA : 64*C₁*Q^3*‖z₀‖ ≤ (ε/2)*Q^4, hB : C₀'*‖z₀‖ ≤ (ε/2)*Q^4 ✓ linarith sums ✓. 26. Also drop hRBle (unused) — just build hbig and hRBle'. 27. hbig's proof (big ≤ 64*C₁*Q^3): ``` have hbig : 400000 * A0count * C0hat (R + 2) * (Real.log R)^2 ≤ 64 * C₁ * Q^3 := by have hlogRnn : (0:ℝ) ≤ Real.log R := by linarith [hlogR] have h1 : 400000 * A0count * C0hat (R + 2) * (Real.log R)^2 ≤ 400000 * A0count * (5 * Real.log R) * (Real.log R)^2 := by apply mul_le_mul_of_nonneg_right _ (pow_nonneg hlogRnn 2) exact mul_le_mul_of_nonneg_left hĈ5 (mul_nonneg (by norm_num : (0:ℝ) ≤ 400000) hA0nn) have h2 : 400000 * A0count * (5 * Real.log R) * (Real.log R)^2 = C₁ * (Real.log R)^3 := by rw [hC1]; ring have h3 : C₁ * (Real.log R)^3 ≤ 64 * C₁ * Q^3 := by have h := mul_le_mul_of_nonneg_left hL3 hC₁nn -- C₁*L^3 ≤ C₁*(64*Q^3) have h' : C₁ * (64 * Q^3) = 64 * C₁ * Q^3 := by ring rwa [h'] at h linarith [h1, h2, h3] ``` ✓. 28. Also `hĈ5 : C0hat (R + 2) ≤ 5 * Real.log R := C0hat_add_two_le hR16002`. 29. In §1, `C0hat_add_two_le`: unfold C0hat — `rw [C0hat]`? C0hat is `def C0hat (t : ℝ) : ℝ := ...`. rw [C0hat] uses equation lemma C0hat t = ... hmm for non-pattern defs `rw [C0hat]` might fail ("motive" issues?). In LiSkeleton they must unfold C0hat somewhere — two_le_C0hat's proof in LiContour. Let me check how two_le_C0hat unfolds it. Actually `unfold C0hat` always works; or `show`. Let me check LiContour's usage. Also — in hĈ5 the LHS `C0hat (R + 2)` appears in hRB (RB's definition mentions C0hat (R+2)) — no unfolding needed there since I only use hĈ5 as a bound ✓. 30. After `set RB := ... with hRB`, note the Fexpr_circle_le RHS IS exactly RB's definition — so hsphere/hball statements with RB... I'll write them with the explicit expression (they're proved before set RB, or after — set replaces in goal only, my haves are written by me; I'll order: sphere/ball bounds first with explicit expressions, then set RB, then use hball z hz which has the explicit form; when I need ‖Gentire z‖ ≤ RB from hball z hz (explicit), I rw [← hRB] at that instance... Messy. Alternative: `set RB := ... with hRB` FIRST (right after obtaining R), then state hsphere/hball with RB, and at the Fexpr_circle_le call site the produced term has the explicit form — exact accepts since RB is let-defeq ✓. I'll do set RB early and rely on defeq. If `exact` fails due to let-transparency issues (set's local defs are transparent for exact? Yes — `set` introduces a local definition that's definitionally equal; exact works up to defeq ✓). Order inside key: - intro ε hε - set C₀', C₁, c, M (with haves hC₀'nn, hC₁nn, hcz, hcnn) - obtain k, hk4000, hkM - obtain R, hRlo, hRhi, hgapInt, hgap (from exists_gapCircle_radius) - hR16002, hRpos, hlogR, hMR - set RB with hRB; hsphere; hGan; hball; hmaps; hdiff; hz0mem; hschwarz - set Q; hQnn, hQpos, hQc, hL, hL3, hR4, hĈ5, hbig, hRBle' - hc1, hA, hB, hsum, hmain - final calc 31. hz0mem : z₀ ∈ Metric.ball (0:ℂ) R: ``` have hz0mem : z₀ ∈ Metric.ball (0:ℂ) R := by rw [Metric.mem_ball, dist_eq_norm, sub_zero] have h1 : ‖z₀‖ + 1 ≤ M := le_max_right _ _ have h2 : (‖z₀‖ + 1 : ℝ) ≤ M := h1 -- M := max (c^4) (‖z₀‖+1) linarith [hMR, norm_nonneg z₀] ``` Wait — with `set M := max (c^4) (‖z₀‖+1) with hM`, le_max_right gives ‖z₀‖+1 ≤ max (c^4) (‖z₀‖+1); the set-folded M is defeq ✓ `have h1 : ‖z₀‖ + 1 ≤ M := le_max_right _ _` — typechecking le_max_right _ _ : ‖z₀‖+1 ≤ max (c^4) (‖z₀‖+1) against ‖z₀‖+1 ≤ M — defeq via the let ✓ should work. goal after rw: ‖z₀‖ < R. linarith [hMR, h1] where hMR : M ≤ R, h1 : ‖z₀‖+1 ≤ M ⟹ ‖z₀‖ < M ≤ R ✓ (linarith uses norm_nonneg? ‖z₀‖ < ‖z₀‖+1 is linear in atom ‖z₀‖: ‖z₀‖ + 1 ≤ M ⟹ ‖z₀‖ ≤ M − 1 < M ≤ R ✓ pure linarith, no norm_nonneg needed). 32. hkM : M ≤ 4*(k:ℝ) — from the obtain. Then hMR : M ≤ R: R ≥ 4k + 5/2 ≥ 4k ≥ M: linarith [hkM, hRlo] ✓. 33. The k obtain: ``` obtain ⟨k, hk4000, hkM⟩ : ∃ k : ℕ, 4000 ≤ k ∧ M ≤ 4 * (k:ℝ) := by refine ⟨max 4000 ⌈M / 4⌉₊, le_max_left _ _, ?_⟩ have h1 : M / 4 ≤ (⌈M / 4⌉₊ : ℝ) := Nat.le_ceil _ have h2 : (⌈M / 4⌉₊ : ℝ) ≤ ((max 4000 ⌈M / 4⌉₊ : ℕ) : ℝ) := by exact_mod_cast le_max_right _ _ linarith [h1, h2] ``` linarith: M ≤ 4·⌈M/4⌉₊ ≤ 4·max ✓ (atoms the casts; h1: M/4 ≤ c1; h2: c1 ≤ c2; goal M ≤ 4*c2: from M ≤ 4*c1 ≤ 4*c2 — linarith ✓ multiplications by literal 4 are linear ✓). 34. hk4000 : 4000 ≤ k — for Fexpr_circle_le (hk : 4000 ≤ k) ✓, and 1 ≤ k for exists_gapCircle_radius (by omega : 1 ≤ k needs hk4000 in context — after obtain ✓; call: exists_gapCircle_radius hZC (k := k) (by omega)). Wait — exists_gapCircle_radius's hk : 1 ≤ k. With hk4000 : 4000 ≤ k in context, `by omega` closes 1 ≤ k ✓. 35. hgap order check for Fexpr_circle_le call: Fexpr_circle_le hk4000 hRlo hRhi hgap hgapInt hznorm — signature: (hk) (hRlo) (_hRhi) (hgap) (hgapInt) (hs) ✓. But CAREFUL: exists_gapCircle_radius returns the conjunction in order ⟨hRlo, hRhi, hgapInt, hgap⟩ (integers third, zeros fourth) ✓ as I wrote. 36. not_badPoint_on_gapCircle's hgap argument order: my own def — I'll mirror Fexpr_circle_le: (hRlo) (hgap) (hgapInt). In gentire_circle_le... actually fold not_badPoint into hsphere directly? Cleaner as its own lemma (also reusable for the capstone? no, capstone's goodness is different). Keep as separate lemma §2. 37. gentire_circle_le (§3): ``` theorem gentire_circle_le {k : ℕ} (hk : 4000 ≤ k) {R : ℝ} (hRlo : 4 * (k:ℝ) + 5/2 ≤ R) (hRhi : R ≤ 4 * (k:ℝ) + 3) (hgap : ∀ ρ : ℂ, IsNontrivialZero ρ → 1 / (16 * C0hat (4 * (k:ℝ) + 9/2)) ≤ |ρ.im - R| ∨ 1 ≤ |ρ.im - R|) (hgapInt : ∀ m : ℤ, 1/4 ≤ |R/2 - (m:ℝ)|) {s : ℂ} (hs : ‖s‖ = R) : ‖Gentire s‖ ≤ 2 * lowZeroConst + dirichletC2 + 400000 * A0count * C0hat (R + 2) * (Real.log R)^2 := by have hgood : ¬ badPoint s := not_badPoint_on_gapCircle hk hRlo hgap hgapInt hs rw [gentire_eq_Fexpr hgood] exact Fexpr_circle_le hk hRlo hRhi hgap hgapInt hs ``` ✓. 38. The hsphere in key uses gentire_circle_le hk4000 hRlo hRhi hgap hgapInt hznorm ✓. One more check — `Real.log_le_rpow_div` exact form at Pow/Real.lean:883: `lemma log_le_rpow_div {x ε : ℝ} (hx : 0 ≤ x) (hε : 0 < ε) : log x ≤ x ^ ε / ε` — in Real namespace? The file section... it's in `namespace Real` presumably ✓ Real.log_le_rpow_div. With x := R, ε := (4:ℝ)⁻¹: log R ≤ R^((4:ℝ)⁻¹)/(4:ℝ)⁻¹. Then: ``` have hL : Real.log R ≤ 4 * Q := by have h := Real.log_le_rpow_div hRpos.le (show (0:ℝ) < (4:ℝ)⁻¹ by positivity) -- h : log R ≤ R^((4:ℝ)⁻¹)/(4:ℝ)⁻¹ have h2 : R ^ ((4:ℝ)⁻¹) / (4:ℝ)⁻¹ = 4 * Q := by rw [← hQ, div_eq_mul_inv, inv_inv] -- goal becomes... ring rwa [h2] at h ``` h2 proof: goal R^((4:ℝ)⁻¹)/(4:ℝ)⁻¹ = 4*Q; rw [← hQ] rewrites R^(4⁻¹) → Q (both occurrences: LHS numerator and... RHS 4*Q has Q already — rw [← hQ] rewrites R^(4⁻¹) inside Q? NO — Q is a local let-var; rw operates syntactically: occurrences of R^(4⁻¹) in the goal get replaced by Q. RHS's Q is already Q (a local variable), not R^(4⁻¹) ✓ untouched. Goal becomes Q/(4⁻¹) = 4*Q. rw [div_eq_mul_inv]: Q*(4⁻¹)⁻¹ = 4*Q. rw [inv_inv]: (4:ℝ)⁻¹⁻¹ = 4: Q*4 = 4*Q: ring ✓. Hmm wait — div_eq_mul_inv : a / b = a * b⁻¹ ✓. inv_inv : a⁻¹⁻¹ = a ✓. But there's a subtlety: rw [← hQ] might also rewrite the R^(4⁻¹) appearing... only one occurrence (numerator) ✓. Alternatively avoid the rw-Q dance: state h2 as `R ^ ((4:ℝ)⁻¹) / (4:ℝ)⁻¹ = 4 * (R ^ ((4:ℝ)⁻¹))` and prove by rw [div_eq_mul_inv, inv_inv]; ring. Then h : log R ≤ 4*R^(4⁻¹); then hL : log R ≤ 4*Q: rwa [h2] at h — h's RHS 4*(R^(4⁻¹)) vs 4*Q — defeq via set-let ✓ exact works if hL's statement uses Q: `exact h` where h : log R ≤ 4*R^(4⁻¹) and goal log R ≤ 4*Q — defeq ✓. Cleaner: ``` have hL : Real.log R ≤ 4 * Q := by have h := Real.log_le_rpow_div hRpos.le (show (0:ℝ) < (4:ℝ)⁻¹ by positivity) have h2 : R ^ ((4:ℝ)⁻¹) / (4:ℝ)⁻¹ = 4 * (R ^ ((4:ℝ)⁻¹)) := by rw [div_eq_mul_inv, inv_inv]; ring rwa [h2] at h -- h : log R ≤ 4 * R^(4⁻¹); goal ... ≤ 4 * Q; defeq ✓ rwa tries exact after rw ``` rwa [h2] at h: rewrites h then exacts — the exact step checks defeq against goal with Q ✓. 39. hL3: ``` have hL3 : (Real.log R)^3 ≤ 64 * Q^3 := by have h1 : (Real.log R)^3 ≤ (4 * Q)^3 := pow_le_pow_left₀ (by linarith [hlogR]) hL 3 have h2 : (4 * Q)^3 = 64 * Q^3 := by ring rwa [h2] at h1 ``` hL : log R ≤ 4*Q ✓ matches pow_le_pow_left₀'s hab : a ≤ b with b := 4*Q ✓. 40. pow_pos (h : 0 < a) (n : ℕ)? `pow_pos (ha : 0 < a) (n : ℕ) : 0 < a ^ n` ✓. 41. div_le_iff₀ : `div_le_iff₀ (hc : 0 < c) : a / c ≤ b ↔ a ≤ b * c` ✓ standard. 42. Also confirm `div_le_div_of_nonneg_right`: In current Mathlib — `div_le_div_of_nonneg_right (hab : a ≤ b) (hc : 0 ≤ c) : a / c ≤ b / c`. Hmm, actually I have a doubt: it might be in terms of `a / c ≤ b / c ↔`... The session-032 gotcha explicitly banked "div_le_div_of_nonneg_right exists" from THIS codebase ✓ trust it. 43. In hc1: `(128 * C₁) * ‖z₀‖ / ε ≤ c` via div_le_div_of_nonneg_right h2 hε.le then .trans h1 where h1 : (128*C₁+2*C₀')*‖z₀‖/ε ≤ c ✓. 44. `dist_eq_zero : dist x y = 0 ↔ x = y` ✓. 45. `Metric.mem_sphere.mp hz : dist z 0 = R`; then `rw [dist_eq_norm, sub_zero] at h`— wait h : dist z (0:ℂ) = R; dist_eq_norm : dist z 0 = ‖z − 0‖; rw at h: h : ‖z − 0‖ = R; sub_zero: h : ‖z‖ = R ✓. Also `open Metric`? LiCircleBound opens `Zeta23 Complex Filter Topology` — NOT Metric. So write Metric.ball/Metric.sphere/Metric.mem_ball etc. fully qualified ✓ (as I have been). Note Fexpr_circle_le etc use ‖·‖ directly ✓. 46. `MapsTo` — Function.MapsTo; with no open Function... MapsTo is in root namespace? `Set.MapsTo`! In recent Mathlib, MapsTo is `Set.MapsTo`. Schwarz.lean has `open Set` presumably, its signature `MapsTo f (ball c R₁) (closedBall (f c) R₂)` is Set.MapsTo. So I write `Set.MapsTo Gentire (Metric.ball 0 R) (Metric.closedBall (Gentire 0) (RB + ‖Gentire 0‖))`. intro z hz works for Set.MapsTo (it's ∀ x ∈ s, f x ∈ t) ✓ — Set.MapsTo f s t := ∀ ⦃x⦄, x ∈ s → f x ∈ t; `intro z hz` ✓ works since it's a Pi type. Check: does LiCircleBound use Set.MapsTo or MapsTo? Doesn't matter — use Set.MapsTo with the full form; Schwarz's arg expects Set.MapsTo ✓ defeq regardless of how I write `MapsTo` (if MapsTo resolves to Set.MapsTo via open Set — I don't open Set, so write Set.MapsTo explicitly). 47. `mem_closedBall` target: Set.MapsTo ... (Metric.closedBall (Gentire 0) R₂): membership z' ∈ Metric.closedBall c R₂ ↔ dist z' c ≤ R₂ (Metric.mem_closedBall) ✓. 48. norm_sub_le : ‖a − b‖ ≤ ‖a‖ + ‖b‖ ✓. Now, the hsphere bound needs hznorm : ‖z‖ = R from hz : z ∈ Metric.sphere (0:ℂ) R. ✓ as written. One more consideration — `gentire_eq_Fexpr`: let me verify its exact signature/name. From line 1109: `rw [gentire_eq_Fexpr hygood]` where hygood : ¬ badPoint y, goal context — at that point they're proving something about Gentire y... it's `gentire_eq_Fexpr (h : ¬ badPoint s) : Gentire s = Fexpr s` ✓ (line 1116: `gentire_eq_Fexpr hs` used to prove the second component ∀ s, ¬badPoint s → Gentire s = Fexpr s — wait line 1115-1116: `(∀ s, AnalyticAt ...) ∧ ∀ s, ¬ badPoint s → Gentire s = Fexpr s := ⟨fun s => ?_, fun s hs => gentire_eq_Fexpr hs⟩` ✓ confirmed). File placement decision: new file LiSqueeze.lean. Also root-import it in NguyenRH1.lean. Let me check the root file's import list.
`pow_le_pow_left₀` confirmed. Checking the root file's import list, then writing LiSqueeze.lean.
tool: Read
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1.lean"
}
#1684 assistant 2026-08-24 06:14:44.309 UTC · 1062→2898 tok open ⤢
thinking (6483 chars)
`unfold C0hat` is the pattern used. `Real.log_pow (x : ℝ) (n : ℕ) : log (x ^ n) = n * log x` ✓. Now writing LiSqueeze.lean. Full file: ```lean /- NguyenRH1/LiSqueeze.lean — tier ii′ sub-stage ii′-5e-v-d (D-068 §5): the Schwarz squeeze ⟹ the partial-fraction capstone. §1: the Ĉ₀ growth bound `C0hat_add_two_le` (Ĉ₀(R+2) ≤ 5·log R). §2: `not_badPoint_on_gapCircle` — every point of a γ-gap circle is good. §3: `gentire_circle_le` — the Fexpr circle bound transferred to Gentire. §4: `gentire_const` — max-modulus + Schwarz on the gap-circle sequence ⟹ Gentire ≡ Gentire 0 (the (log R)³/R → 0 squeeze). §5: the capstone `partialFraction_identity` (hZC : ZeroCountProp). Archive references: D-068 §5, STATE.md session-034 next-action design. -/ import Mathlib import NguyenRH1.LiCircleBound open Zeta23 Complex Filter Topology noncomputable section namespace NguyenRH1 ``` Then the content. Let me carefully write out each proof. §1: ```lean /-! ## 1. The Ĉ₀ growth bound -/ /-- Ĉ₀(R+2) ≤ 5·log R for R ≥ 16002 (log R ≥ 9): log(R+4) ≤ 2·log R, log log(R+4) ≤ 2·log R, 2.9 ≤ (1/3)·log R. -/ lemma C0hat_add_two_le {R : ℝ} (hR : 16002 ≤ R) : C0hat (R + 2) ≤ 5 * Real.log R := by have hRpos : (0 : ℝ) < R := by linarith have hlogR : (9 : ℝ) ≤ Real.log R := nine_le_log_of_16002_le hR have h1 : Real.log (R + 2 + 2) ≤ 2 * Real.log R := by have hle : R + 2 + 2 ≤ R ^ 2 := by nlinarith [hR] have h2 : Real.log (R + 2 + 2) ≤ Real.log (R ^ 2) := Real.log_le_log (by linarith : (0 : ℝ) < R + 2 + 2) hle rwa [Real.log_pow, Nat.cast_two] at h2 have h2 : Real.log (Real.log (R + 2 + 2)) ≤ 2 * Real.log R := by have hpos1 : (0 : ℝ) < Real.log (R + 2 + 2) := by have hle : Real.log R ≤ Real.log (R + 2 + 2) := Real.log_le_log hRpos (by linarith) linarith [hlogR] have h3 : Real.log (Real.log (R + 2 + 2)) ≤ Real.log (2 * Real.log R) := Real.log_le_log hpos1 h1 have h4 : Real.log (2 * Real.log R) = Real.log 2 + Real.log (Real.log R) := by rw [Real.log_mul (by norm_num) (by linarith [hlogR] : Real.log R ≠ 0)] have h5 : Real.log 2 ≤ 1 := by have h := Real.log_le_sub_one_of_pos (by norm_num : (0 : ℝ) < 2) linarith have h6 : Real.log (Real.log R) ≤ Real.log R := by have h := Real.log_le_sub_one_of_pos (by linarith [hlogR] : (0 : ℝ) < Real.log R) linarith linarith [h3, h4, h5, h6, hlogR] unfold C0hat linarith [h1, h2, hlogR] ``` Check `Real.log_mul (hx : x ≠ 0) (hy : y ≠ 0) : log (x*y) = log x + log y` ✓ standard. nlinarith [hR] for R+4 ≤ R²: R ≥ 16002 ⟹ R² ≥ R·R ≥ 16002·R ≥ R + 4? nlinarith needs: R² − (R+4) = R(R−1) − 4 ≥ 16002·16001 − 4 > 0. nlinarith [hR] should multiply hR by itself: (R − 16002) ≥ 0 squared-terms... R² ≥ 16002² and needs R² − R − 4 ≥ 0: nlinarith [hR] with products hR*hR gives R² ≥ 16002R... hmm hR : 16002 ≤ R. nlinarith considers pairwise products of hypotheses: hR*hR : (R−16002)² ≥ 0; hR*goal-negation: (R−16002)(R+4−R²) ≤ 0... nlinarith should find: R² − R − 4 = (R−16002)·R + 16001·R − 4 ≥ 0 + 16001·16002 − 4 > 0 — uses hR*R? nlinarith multiplies hypotheses by each other and by the negated goal: product (R − 16002) * (R − 16002) ≥ 0 gives R² ≥ 32004R − 16002²; then need 32004R − 16002² − R − 4 ≥ 0 ⟸ 32003R ≥ 16002² + 4 ⟸ R ≥ 16002·(32003/16002)... 32003·16002 = 16002²·2 − 16002 = hmm: 32003·16002 = 2·16002² − 16002 ≥ 16002² + 4 ⟺ 16002² ≥ 16006 ✓ (256064004 ≥ 16006). So linarith-after-products works: nlinarith [hR] should close it. To be extra safe: nlinarith [hR, hRpos]. OK. Also `nine_le_log_of_16002_le` — verify exact name (used at LiCircleBound line 3826 ✓ same name). §2: ```lean /-! ## 2. Every γ-gap-circle point is good -/ lemma not_badPoint_on_gapCircle {k : ℕ} (hk : 4000 ≤ k) {R : ℝ} (hRlo : 4 * (k : ℝ) + 5 / 2 ≤ R) (hgap : ∀ ρ : ℂ, IsNontrivialZero ρ → 1 / (16 * C0hat (4 * (k : ℝ) + 9 / 2)) ≤ |ρ.im - R| ∨ 1 ≤ |ρ.im - R|) (hgapInt : ∀ m : ℤ, 1 / 4 ≤ |R / 2 - (m : ℝ)|) {s : ℂ} (hs : ‖s‖ = R) : ¬ badPoint s := by have hR16002 : (16002 : ℝ) ≤ R := by have h1 : (4000 : ℝ) ≤ (k : ℝ) := by exact_mod_cast hk linarith [hRlo] have hRpos : (0 : ℝ) < R := by linarith [hR16002] rintro (h | h | h | ⟨n, -, h⟩) · exact not_isNontrivialZero_on_gapCircle hk hRlo hgap hs h · rw [h, norm_zero] at hs linarith [hRpos] · rw [h, norm_one] at hs linarith [hR16002] · have hR2 : R = 2 * (n : ℝ) := by rw [← hs, h, norm_mul] have h1 : ‖(-2 : ℂ)‖ = 2 := by rw [show (-2 : ℂ) = ((-2 : ℝ) : ℂ) by push_cast; ring, Complex.norm_real] norm_num rw [h1, Complex.norm_natCast] have hcon := hgapInt (n : ℤ) rw [Int.cast_natCast] at hcon have h0 : R / 2 - (n : ℝ) = 0 := by rw [hR2]; ring rw [h0, abs_zero] at hcon linarith [hcon] ``` Wait — rintro fourth case: ⟨n, hn, h⟩ where hn : 1 ≤ n is unused → use ⟨n, -, h⟩ ✓ (anonymous). Actually rintro's `-` clears it ✓ fine (no warning for unused if cleared? `-` clears the hypothesis ✓). norm_zero at hs: hs : ‖(0:ℂ)‖ = R → rw [norm_zero] at hs : (0:ℝ) = R ✓ wait — rw [h] at hs first: hs : ‖(0 : ℂ)‖ = R. Then norm_zero : ‖(0:α)‖ = 0: rw at hs: hs : (0:ℝ) = R ✓. Case 3: rw [h] at hs : ‖(1:ℂ)‖ = R; norm_one: hs : (1:ℝ) = R; linarith [hR16002] gives 16002 ≤ 1 false ✓. Case 4: rw [← hs, h, norm_mul]: goal R = 2*(n:ℝ). rw [← hs]: R ↦ ‖s‖: goal ‖s‖ = 2*(n:ℝ). rw [h]: s ↦ -2*(n:ℂ): goal ‖-2*(n:ℂ)‖ = 2*(n:ℝ). rw [norm_mul]: ‖-2‖*‖(n:ℂ)‖ = 2*(n:ℝ). rw [h1]: 2*‖(n:ℂ)‖ = 2*(n:ℝ). rw [Complex.norm_natCast]: 2*(n:ℝ) = 2*(n:ℝ) ✓ closed by rfl (rw auto-closes). Complex.norm_natCast : ‖(n:ℂ)‖ = (n:ℝ)? — used at LiCircleBound:3410 `rw [h1, Complex.norm_natCast]` — similar context ✓ trust. But wait — is there a coercion match: ‖((n:ℕ):ℂ)‖ — Complex.norm_natCast (n : ℕ) : ‖(↑n : ℂ)‖ = ↑n ✓. hcon : 1/4 ≤ |R/2 − ((n:ℤ):ℝ)|; rw [Int.cast_natCast] at hcon: |R/2 − (n:ℝ)| ✓. h0 : R/2 − (n:ℝ) = 0: rw [hR2] changes goal R/2 − n = 0 with R ↦ 2*n: 2*n/2 − n = 0 by ring ✓. rw [h0] at hcon: |0| ; rw [abs_zero]: 1/4 ≤ (0:ℝ) — linarith ✓ (norm_num at hcon also fine; linarith [hcon] with hcon : 1/4 ≤ 0 — linarith closes any goal from a false hypothesis ✓; actually after rw the goal is False (rintro case goal) ✓ linarith closes). Hmm wait — after rintro, each case's goal is False ✓ (since we're proving ¬ badPoint s, i.e. badPoint s → False). §3 as sketched. ✓ §4 gentire_const — full assembly. Let me also double check `div_le_div_of_nonneg_right` signature in this Mathlib to be safe:
One more name check (`div_le_div_of_nonneg_right`, `Nat.le_ceil`, `div_mul_cancel₀`), then writing the file.
tool: Bash
input
{
  "command": "M=D:/Python/Quantum/zeta-23-lean/.lake/packages/mathlib/Mathlib; grep -rn \"theorem div_le_div_of_nonneg_right\\|lemma div_le_div_of_nonneg_right\" $M --include=\"*.lean\" | head -2; grep -rn \"theorem le_ceil \" $M/Algebra/Order/Floor.lean | head -2; grep -rn \"theorem div_mul_cancel\u2080\" $M/Algebra/GroupWithZero/Basic.lean $M/Algebra/GroupWithZero/*.lean 2>/dev/null | head -3; grep -rn \"div_mul_cancel\u2080\" D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1/*.lean | head -3",
  "description": "Verify division lemma signatures"
}
#1685 assistant 2026-08-24 06:18:15.466 UTC · 3224→7731 tok open ⤢
thinking (4012 chars)
- `div_le_div_of_nonneg_right (hab : a ≤ b) (hc : 0 ≤ c) : a / c ≤ b / c` ✓ - `div_mul_cancel₀ _ (h : b ≠ 0) : a / b * b = a` ✓ (usage in LiGapCircles confirms arg order: div_mul_cancel₀ _ hne). - Nat.le_ceil: used in project? LiFEntire line 84: `Nat.le_ceil _` ✓ seen there (`Nat.le_ceil _ : ‖w‖ ≤ M`). Signature `Nat.le_ceil (a : ℝ) : a ≤ ↑⌈a⌉₊` ✓. Now write the file. Let me assemble the complete LiSqueeze.lean carefully. One remaining check — `Metric.mem_sphere.mp hz` gives `dist z 0 = R`? Metric.mem_sphere : z ∈ sphere x r ↔ dist z x = r ✓. `dist_eq_norm : dist x y = ‖x - y‖` — for ℂ (SeminormedAddCommGroup) ✓ name is `dist_eq_norm` ✓. For hz0mem the rewrite: rw [Metric.mem_ball, dist_eq_norm, sub_zero] — Metric.mem_ball : z ∈ ball x r ↔ dist z x < r; goal becomes dist z₀ 0 < R → ‖z₀ − 0‖ < R → ‖z₀‖ < R ✓. Now, in hsphere: `intro z hz` — goal `z ∈ Metric.sphere (0:ℂ) R → ‖Gentire z‖ ≤ RB`? hsphere's statement: ∀ z ∈ Metric.sphere (0:ℂ) R, ... — intro z hz ✓. After set RB, the hsphere statement I write with RB; the proof's final exact gentire_circle_le ... produces the unfolded form — defeq ✓. Let me also decide: does `set RB` cause issues with hznorm etc.? No. One more potential issue: in §4 I reference `Fexpr_circle_le` indirectly via `gentire_circle_le` — fine. `AnalyticOn.norm_le_of_norm_le_on_sphere le_rfl hGan hsphere hz` — signature: (hyp_r : r ≤ R) (analytic : AnalyticOn ℂ f (closedBall 0 R)) (cond : ∀ z ∈ sphere 0 r, ‖f z‖ ≤ C) (wInS : w ∈ closedBall 0 r) : ‖f w‖ ≤ C. With r := R (our R), R := R: hyp_r : R ≤ R = le_rfl ✓. Implicit {C r R f w} — inferred ✓. BUT: name clash — our `R` vs lemma's `R`; fine. Wait — the lemma's `f : ℂ → ℂ`, our Gentire ✓. Its `AnalyticOn ℂ f (Metric.closedBall 0 R)` — in the lemma statement it's written `Metric.closedBall 0 R`? From the source: `(analytic : AnalyticOn ℂ f (Metric.closedBall 0 R))` — the source shows `AnalyticOn ℂ f (Metric.closedBall 0 R)`? Looking at the code: `lemma AnalyticOn.norm_le_of_norm_le_on_sphere {C r R : ℝ} {f : ℂ → ℂ} {w : ℂ} (hyp_r : r ≤ R) (analytic : AnalyticOn ℂ f (Metric.closedBall 0 R)) (cond : ∀ z ∈ Metric.sphere 0 r, ‖f z‖ ≤ C) (wInS : w ∈ Metric.closedBall 0 r)`. Hmm the actual file showed `Metric.closedBall 0 R` — from my read: line 33-40 shows `(analytic : AnalyticOn ℂ f (Metric.closedBall 0 R))`, `(cond : ∀ z ∈ Metric.sphere 0 r, ‖f z‖ ≤ C)`, `(wInS : w ∈ Metric.closedBall 0 r)`. ✓ (it showed `Metric.closedBall` — well, the read showed `Metric.closedBall 0 R`? It showed "AnalyticOn ℂ f (Metric.closedBall 0 R)" — yes with Metric prefix.) hGan : AnalyticOn ℂ Gentire (Metric.closedBall (0:ℂ) R) ✓ matches. The `(0:ℂ)` vs `0` — fine. Now assemble the whole §4 proof. One concern: the `key` block is long; Lean elaboration of a big proof is fine but errors need iteration. I'll write it, then compile with `lake env lean NguyenRH1/LiSqueeze.lean` and iterate. Also the capstone §5. And finally: root-import LiCircleBound + LiSqueeze in NguyenRH1.lean + update the header comment. Let me also double-check `Real.log_le_log` signature: from usage `Real.log_le_log (by ... : (0:ℝ) < 2 + R/2) (...)` — hmm line 3894 was `apply Real.log_le_log (by linarith [hRpos] : (0 : ℝ) < 2 + R / 2)` — then remaining goal `2 + R/2 ≤ R`. So Real.log_le_log (hx : 0 < x) : x ≤ y → log x ≤ log y ✓. `Real.le_log_iff_exp_le` used in two_le_C0hat ✓ not needed here. Write the file now. Also — important detail: in §4, after `obtain ⟨R, hRlo, hRhi, hgapInt, hgap⟩ := exists_gapCircle_radius hZC (k := k) (by omega)`, the conjunction order: (4k+5/2 ≤ R) ∧ (R ≤ 4k+3) ∧ (∀ m:ℤ, ...) ∧ (∀ ρ, ...) ✓ per the signature I read. Note the exists_gapCircle_radius hgap form: `1 / (16 * C0hat (4 * (k : ℝ) + 9 / 2))) ≤ |ρ.im - R| ∨ 1 ≤ |ρ.im - R|` — wait the exact statement from LiGapCircles:47-51: `(∀ ρ : ℂ, IsNontrivialZero ρ → (1 / (16 * C0hat (4 * (k : ℝ) + 9 / 2))) ≤ |ρ.im - R| ∨ 1 ≤ |ρ.im - R|)` ✓ matches Fexpr_circle_le's hgap form (modulo extra parens — same term). Let me now write the file.
All names verified. Writing LiSqueeze.lean now.
tool: Write ok
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiSqueeze.lean",
  "content": "/-\nNguyenRH1/LiSqueeze.lean \u2014 tier ii\u2032 sub-stage ii\u2032-5e-v-d (D-068 \u00a75):\nthe Schwarz squeeze \u27f9 the partial-fraction capstone.\n\n\u00a71: the \u0108\u2080 growth bound `C0hat_add_two_le` (\u0108\u2080(R+2) \u2264 5\u00b7log R).\n\u00a72: `not_badPoint_on_gapCircle` \u2014 every point of a \u03b3-gap circle is good.\n\u00a73: `gentire_circle_le` \u2014 the Fexpr circle bound transferred to Gentire.\n\u00a74: `gentire_const` \u2014 max-modulus + Schwarz on the gap-circle sequence:\n    the (log R)\u00b3/R \u2192 0 squeeze forces Gentire \u2261 Gentire 0.\n\u00a75: the capstone `partialFraction_identity (hZC : ZeroCountProp)`.\n\nArchive references: D-068 \u00a75, STATE.md session-034 next-action design.\n-/\nimport Mathlib\nimport NguyenRH1.LiCircleBound\n\nopen Zeta23 Complex Filter Topology\n\nnoncomputable section\n\nnamespace NguyenRH1\n\n/-! ## 1. The \u0108\u2080 growth bound -/\n\n/-- \u0108\u2080(R+2) \u2264 5\u00b7log R for R \u2265 16002 (so log R \u2265 9): log(R+4) \u2264 2\u00b7log R,\nlog log(R+4) \u2264 2\u00b7log R, and 2.9 \u2264 (1/3)\u00b7log R; total 2.97\u00b7log R. -/\nlemma C0hat_add_two_le {R : \u211d} (hR : 16002 \u2264 R) :\n    C0hat (R + 2) \u2264 5 * Real.log R := by\n  have hRpos : (0 : \u211d) < R := by linarith\n  have hlogR : (9 : \u211d) \u2264 Real.log R := nine_le_log_of_16002_le hR\n  have h1 : Real.log (R + 2 + 2) \u2264 2 * Real.log R := by\n    have hle : R + 2 + 2 \u2264 R ^ 2 := by nlinarith [hR]\n    have h2 : Real.log (R + 2 + 2) \u2264 Real.log (R ^ 2) :=\n      Real.log_le_log (by linarith : (0 : \u211d) < R + 2 + 2) hle\n    rwa [Real.log_pow, Nat.cast_two] at h2\n  have h2 : Real.log (Real.log (R + 2 + 2)) \u2264 2 * Real.log R := by\n    have hpos1 : (0 : \u211d) < Real.log (R + 2 + 2) := by\n      have hle : Real.log R \u2264 Real.log (R + 2 + 2) :=\n        Real.log_le_log hRpos (by linarith)\n      linarith [hlogR]\n    have h3 : Real.log (Real.log (R + 2 + 2)) \u2264 Real.log (2 * Real.log R) :=\n      Real.log_le_log hpos1 h1\n    have h4 : Real.log (2 * Real.log R) = Real.log 2 + Real.log (Real.log R) := by\n      rw [Real.log_mul (by norm_num) (by linarith [hlogR] : Real.log R \u2260 0)]\n    have h5 : Real.log 2 \u2264 1 := by\n      have h := Real.log_le_sub_one_of_pos (by norm_num : (0 : \u211d) < 2)\n      linarith\n    have h6 : Real.log (Real.log R) \u2264 Real.log R := by\n      have h := Real.log_le_sub_one_of_pos (by linarith [hlogR] : (0 : \u211d) < Real.log R)\n      linarith\n    linarith [h3, h4, h5, h6, hlogR]\n  unfold C0hat\n  linarith [h1, h2, hlogR]\n\n/-! ## 2. Every \u03b3-gap-circle point is good -/\n\n/-- A point on a \u03b3-gap circle is not a bad point: not a nontrivial zero\n(the circle-bound lemma), not 0 or 1 (norm too large), not \u22122n (the\n\u2124-clearance of R/2). -/\nlemma not_badPoint_on_gapCircle {k : \u2115} (hk : 4000 \u2264 k) {R : \u211d}\n    (hRlo : 4 * (k : \u211d) + 5 / 2 \u2264 R)\n    (hgap : \u2200 \u03c1 : \u2102, IsNontrivialZero \u03c1 \u2192\n      1 / (16 * C0hat (4 * (k : \u211d) + 9 / 2)) \u2264 |\u03c1.im - R| \u2228 1 \u2264 |\u03c1.im - R|)\n    (hgapInt : \u2200 m : \u2124, 1 / 4 \u2264 |R / 2 - (m : \u211d)|)\n    {s : \u2102} (hs : \u2016s\u2016 = R) : \u00ac badPoint s := by\n  have hR16002 : (16002 : \u211d) \u2264 R := by\n    have h1 : (4000 : \u211d) \u2264 (k : \u211d) := by exact_mod_cast hk\n    linarith [hRlo]\n  have hRpos : (0 : \u211d) < R := by linarith [hR16002]\n  rintro (h | h | h | \u27e8n, -, h\u27e9)\n  \u00b7 exact not_isNontrivialZero_on_gapCircle hk hRlo hgap hs h\n  \u00b7 rw [h, norm_zero] at hs\n    linarith [hRpos]\n  \u00b7 rw [h, norm_one] at hs\n    linarith [hR16002]\n  \u00b7 have hR2 : R = 2 * (n : \u211d) := by\n      rw [\u2190 hs, h, norm_mul]\n      have h1 : \u2016(-2 : \u2102)\u2016 = 2 := by\n        rw [show (-2 : \u2102) = ((-2 : \u211d) : \u2102) by push_cast; ring, Complex.norm_real]\n        norm_num\n      rw [h1, Complex.norm_natCast]\n    have hcon := hgapInt (n : \u2124)\n    rw [Int.cast_natCast] at hcon\n    have h0 : R / 2 - (n : \u211d) = 0 := by rw [hR2]; ring\n    rw [h0, abs_zero] at hcon\n    linarith [hcon]\n\n/-! ## 3. The circle bound for Gentire -/\n\n/-- The Fexpr circle bound transfers to Gentire on the \u03b3-gap circles\n(every circle point is good, so Gentire = Fexpr there). -/\ntheorem gentire_circle_le {k : \u2115} (hk : 4000 \u2264 k) {R : \u211d}\n    (hRlo : 4 * (k : \u211d) + 5 / 2 \u2264 R) (hRhi : R \u2264 4 * (k : \u211d) + 3)\n    (hgap : \u2200 \u03c1 : \u2102, IsNontrivialZero \u03c1 \u2192\n      1 / (16 * C0hat (4 * (k : \u211d) + 9 / 2)) \u2264 |\u03c1.im - R| \u2228 1 \u2264 |\u03c1.im - R|)\n    (hgapInt : \u2200 m : \u2124, 1 / 4 \u2264 |R / 2 - (m : \u211d)|)\n    {s : \u2102} (hs : \u2016s\u2016 = R) :\n    \u2016Gentire s\u2016 \u2264 2 * lowZeroConst + dirichletC2 +\n      400000 * A0count * C0hat (R + 2) * (Real.log R) ^ 2 := by\n  have hgood : \u00ac badPoint s := not_badPoint_on_gapCircle hk hRlo hgap hgapInt hs\n  rw [gentire_eq_Fexpr hgood]\n  exact Fexpr_circle_le hk hRlo hRhi hgap hgapInt hs\n\n/-! ## 4. The squeeze: Gentire is constant -/\n\n/-- **The Schwarz squeeze**: under the perimeter zero count, Gentire is\nconstant. For each \u03b5 > 0 pick a \u03b3-gap circle of radius R \u2265 16002 with\nR^{1/4} \u2265 2 + (128\u00b7C\u2081 + 2\u00b7C\u2080')\u00b7\u2016z\u2080\u2016/\u03b5; max-modulus bounds Gentire on the\nball by the circle bound, Schwarz then gives\ndist (Gentire z\u2080) (Gentire 0) \u2264 (C\u2080' + 64\u00b7C\u2081\u00b7R^{3/4})\u00b7\u2016z\u2080\u2016/R \u2264 \u03b5. -/\ntheorem gentire_const (hZC : ZeroCountProp) (z\u2080 : \u2102) : Gentire z\u2080 = Gentire 0 := by\n  classical\n  have hA0nn : (0 : \u211d) \u2264 A0count := A0count_pos.le\n  have key : \u2200 \u03b5 : \u211d, 0 < \u03b5 \u2192 dist (Gentire z\u2080) (Gentire 0) \u2264 \u03b5 := by\n    intro \u03b5 h\u03b5\n    -- the constants\n    set C\u2080' := 2 * lowZeroConst + dirichletC2 + \u2016Gentire 0\u2016 with hC0'\n    set C\u2081 := 2000000 * A0count with hC1\n    have hC\u2080'nn : (0 : \u211d) \u2264 C\u2080' := by\n      rw [hC0']\n      linarith [lowZeroConst_nonneg, dirichletC2_nonneg, norm_nonneg (Gentire 0)]\n    have hC\u2081nn : (0 : \u211d) \u2264 C\u2081 := by\n      rw [hC1]\n      exact mul_nonneg (by norm_num) hA0nn\n    set c := 2 + (128 * C\u2081 + 2 * C\u2080') * \u2016z\u2080\u2016 / \u03b5 with hc\n    have hXnn : (0 : \u211d) \u2264 (128 * C\u2081 + 2 * C\u2080') * \u2016z\u2080\u2016 / \u03b5 :=\n      div_nonneg (mul_nonneg (add_nonneg (mul_nonneg (by norm_num) hC\u2081nn)\n        (mul_nonneg (by norm_num) hC\u2080'nn)) (norm_nonneg _)) h\u03b5.le\n    have hcz : (2 : \u211d) \u2264 c := by rw [hc]; linarith [hXnn]\n    have hcnn : (0 : \u211d) \u2264 c := by linarith [hcz]\n    -- the radius choice\n    set M := max (c ^ 4) (\u2016z\u2080\u2016 + 1) with hM\n    obtain \u27e8k, hk4000, hkM\u27e9 : \u2203 k : \u2115, 4000 \u2264 k \u2227 M \u2264 4 * (k : \u211d) := by\n      refine \u27e8max 4000 \u2308M / 4\u2309\u208a, le_max_left _ _, ?_\u27e9\n      have h1 : M / 4 \u2264 (\u2308M / 4\u2309\u208a : \u211d) := Nat.le_ceil _\n      have h2 : (\u2308M / 4\u2309\u208a : \u211d) \u2264 ((max 4000 \u2308M / 4\u2309\u208a : \u2115) : \u211d) := by\n        exact_mod_cast le_max_right _ _\n      linarith [h1, h2]\n    obtain \u27e8R, hRlo, hRhi, hgapInt, hgap\u27e9 :=\n      exists_gapCircle_radius hZC (k := k) (by omega)\n    have hR16002 : (16002 : \u211d) \u2264 R := by\n      have h1 : (4000 : \u211d) \u2264 (k : \u211d) := by exact_mod_cast hk4000\n      linarith [hRlo]\n    have hRpos : (0 : \u211d) < R := by linarith [hR16002]\n    have hlogR : (9 : \u211d) \u2264 Real.log R := nine_le_log_of_16002_le hR16002\n    have hMR : M \u2264 R := by linarith [hkM, hRlo]\n    -- the circle bound on the sphere, then the ball by max-modulus\n    set RB := 2 * lowZeroConst + dirichletC2 +\n      400000 * A0count * C0hat (R + 2) * (Real.log R) ^ 2 with hRB\n    have hsphere : \u2200 z \u2208 Metric.sphere (0 : \u2102) R, \u2016Gentire z\u2016 \u2264 RB := by\n      intro z hz\n      have hznorm : \u2016z\u2016 = R := by\n        have h := Metric.mem_sphere.mp hz\n        rwa [dist_eq_norm, sub_zero] at h\n      exact gentire_circle_le hk4000 hRlo hRhi hgap hgapInt hznorm\n    have hGan : AnalyticOn \u2102 Gentire (Metric.closedBall 0 R) :=\n      AnalyticOnNhd.analyticOn (fun s _ => gentire_analyticAt_and_eq.1 s)\n    have hball : \u2200 z \u2208 Metric.closedBall (0 : \u2102) R, \u2016Gentire z\u2016 \u2264 RB :=\n      fun z hz => AnalyticOn.norm_le_of_norm_le_on_sphere le_rfl hGan hsphere hz\n    -- the Schwarz inputs\n    have hmaps : Set.MapsTo Gentire (Metric.ball 0 R)\n        (Metric.closedBall (Gentire 0) (RB + \u2016Gentire 0\u2016)) := by\n      intro z hz\n      have hzball : z \u2208 Metric.closedBall (0 : \u2102) R := by\n        rw [Metric.mem_ball] at hz\n        rw [Metric.mem_closedBall]\n        exact hz.le\n      have h1 := hball z hzball\n      rw [Metric.mem_closedBall, dist_eq_norm]\n      calc \u2016Gentire z - Gentire 0\u2016 \u2264 \u2016Gentire z\u2016 + \u2016Gentire 0\u2016 := norm_sub_le _ _\n        _ \u2264 RB + \u2016Gentire 0\u2016 := by linarith [h1]\n    have hdiff : DifferentiableOn \u2102 Gentire (Metric.ball 0 R) :=\n      fun z _ => (gentire_analyticAt_and_eq.1 z).differentiableAt.differentiableWithinAt\n    have hz0mem : z\u2080 \u2208 Metric.ball (0 : \u2102) R := by\n      rw [Metric.mem_ball, dist_eq_norm, sub_zero]\n      have h1 : \u2016z\u2080\u2016 + 1 \u2264 M := le_max_right _ _\n      linarith [hMR]\n    have hschwarz := Complex.dist_le_div_mul_dist_of_mapsTo_ball hdiff hmaps hz0mem\n    -- the growth estimates: RB + \u2016Gentire 0\u2016 \u2264 C\u2080' + 64\u00b7C\u2081\u00b7Q\u00b3, R = Q\u2074\n    set Q := R ^ ((4 : \u211d)\u207b\u00b9) with hQ\n    have hQnn : (0 : \u211d) \u2264 Q := Real.rpow_nonneg hRpos.le _\n    have hQpos : (0 : \u211d) < Q := Real.rpow_pos_of_pos hRpos _\n    have hQc : c \u2264 Q := by\n      have hc4 : c ^ 4 \u2264 R := by\n        have h : c ^ 4 \u2264 M := le_max_left _ _\n        linarith [hMR]\n      have h1 : c = (c ^ 4) ^ ((4 : \u211d)\u207b\u00b9) := by\n        have h := (Real.pow_rpow_inv_natCast hcnn (show (4 : \u2115) \u2260 0 by norm_num)).symm\n        push_cast at h\n        exact h\n      have h2 : (c ^ 4) ^ ((4 : \u211d)\u207b\u00b9) \u2264 Q :=\n        Real.rpow_le_rpow (pow_nonneg (by linarith [hcz] : (0 : \u211d) \u2264 c) 4) hc4\n          (by positivity : (0 : \u211d) \u2264 (4 : \u211d)\u207b\u00b9)\n      rw [h1]\n      exact h2\n    have hL : Real.log R \u2264 4 * Q := by\n      have h := Real.log_le_rpow_div hRpos.le (show (0 : \u211d) < (4 : \u211d)\u207b\u00b9 by positivity)\n      have h2 : R ^ ((4 : \u211d)\u207b\u00b9) / (4 : \u211d)\u207b\u00b9 = 4 * (R ^ ((4 : \u211d)\u207b\u00b9)) := by\n        rw [div_eq_mul_inv, inv_inv]\n        ring\n      rwa [h2] at h\n    have hL3 : (Real.log R) ^ 3 \u2264 64 * Q ^ 3 := by\n      have h1 : (Real.log R) ^ 3 \u2264 (4 * Q) ^ 3 :=\n        pow_le_pow_left\u2080 (by linarith [hlogR]) hL 3\n      have h2 : (4 * Q) ^ 3 = 64 * Q ^ 3 := by ring\n      rwa [h2] at h1\n    have hR4 : R = Q ^ 4 := by\n      have h := Real.rpow_inv_natCast_pow hRpos.le (show (4 : \u2115) \u2260 0 by norm_num)\n      push_cast at h\n      rw [\u2190 hQ] at h\n      exact h.symm\n    have h\u01085 : C0hat (R + 2) \u2264 5 * Real.log R := C0hat_add_two_le hR16002\n    have hbig : 400000 * A0count * C0hat (R + 2) * (Real.log R) ^ 2\n        \u2264 64 * C\u2081 * Q ^ 3 := by\n      have hlogRnn : (0 : \u211d) \u2264 Real.log R := by linarith [hlogR]\n      have h1 : 400000 * A0count * C0hat (R + 2) * (Real.log R) ^ 2\n          \u2264 400000 * A0count * (5 * Real.log R) * (Real.log R) ^ 2 := by\n        apply mul_le_mul_of_nonneg_right _ (pow_nonneg hlogRnn 2)\n        exact mul_le_mul_of_nonneg_left h\u01085\n          (mul_nonneg (by norm_num : (0 : \u211d) \u2264 400000) hA0nn)\n      have h2 : 400000 * A0count * (5 * Real.log R) * (Real.log R) ^ 2\n          = C\u2081 * (Real.log R) ^ 3 := by\n        rw [hC1]\n        ring\n      have h3 : C\u2081 * (Real.log R) ^ 3 \u2264 64 * C\u2081 * Q ^ 3 := by\n        have h := mul_le_mul_of_nonneg_left hL3 hC\u2081nn\n        have h' : C\u2081 * (64 * Q ^ 3) = 64 * C\u2081 * Q ^ 3 := by ring\n        rwa [h'] at h\n      linarith [h1, h2, h3]\n    have hRBle : RB + \u2016Gentire 0\u2016 \u2264 C\u2080' + 64 * C\u2081 * Q ^ 3 := by\n      rw [hRB, hC0']\n      linarith [hbig]\n    -- the real squeeze: (RB + \u2016Gentire 0\u2016)/R\u00b7\u2016z\u2080\u2016 \u2264 \u03b5\n    have hc1 : 128 * C\u2081 * \u2016z\u2080\u2016 \u2264 \u03b5 * Q := by\n      have h1 : (128 * C\u2081 + 2 * C\u2080') * \u2016z\u2080\u2016 / \u03b5 \u2264 c := by rw [hc]; linarith\n      have h2 : (128 * C\u2081) * \u2016z\u2080\u2016 \u2264 (128 * C\u2081 + 2 * C\u2080') * \u2016z\u2080\u2016 := by\n        apply mul_le_mul_of_nonneg_right _ (norm_nonneg _)\n        linarith [hC\u2080'nn]\n      have h3 : (128 * C\u2081) * \u2016z\u2080\u2016 / \u03b5 \u2264 c :=\n        (div_le_div_of_nonneg_right h2 h\u03b5.le).trans h1\n      calc (128 * C\u2081) * \u2016z\u2080\u2016 = (128 * C\u2081) * \u2016z\u2080\u2016 / \u03b5 * \u03b5 := by\n            rw [div_mul_cancel\u2080 _ h\u03b5.ne']\n        _ \u2264 c * \u03b5 := mul_le_mul_of_nonneg_right h3 h\u03b5.le\n        _ \u2264 Q * \u03b5 := mul_le_mul_of_nonneg_right hQc h\u03b5.le\n        _ = \u03b5 * Q := by ring\n    have hA : 64 * C\u2081 * Q ^ 3 * \u2016z\u2080\u2016 \u2264 (\u03b5 / 2) * Q ^ 4 := by\n      have h1 : (64 * C\u2081 * \u2016z\u2080\u2016) * Q ^ 3 \u2264 ((\u03b5 / 2) * Q) * Q ^ 3 := by\n        apply mul_le_mul_of_nonneg_right _ (pow_nonneg hQnn 3)\n        have h64 : (64 : \u211d) * C\u2081 * \u2016z\u2080\u2016 = (128 * C\u2081 * \u2016z\u2080\u2016) / 2 := by ring\n        have hhalf : (\u03b5 / 2) * Q = (\u03b5 * Q) / 2 := by ring\n        rw [h64, hhalf]\n        linarith [hc1]\n      have hL' : (64 * C\u2081 * \u2016z\u2080\u2016) * Q ^ 3 = 64 * C\u2081 * Q ^ 3 * \u2016z\u2080\u2016 := by ring\n      have hR' : ((\u03b5 / 2) * Q) * Q ^ 3 = (\u03b5 / 2) * Q ^ 4 := by ring\n      rwa [hL', hR'] at h1\n    have hB : C\u2080' * \u2016z\u2080\u2016 \u2264 (\u03b5 / 2) * Q ^ 4 := by\n      have h1 : (2 * C\u2080') * \u2016z\u2080\u2016 \u2264 \u03b5 * Q := by\n        have h2 : (2 * C\u2080') * \u2016z\u2080\u2016 \u2264 (128 * C\u2081 + 2 * C\u2080') * \u2016z\u2080\u2016 := by\n          apply mul_le_mul_of_nonneg_right _ (norm_nonneg _)\n          linarith [hC\u2081nn]\n        have h3 : (128 * C\u2081 + 2 * C\u2080') * \u2016z\u2080\u2016 / \u03b5 \u2264 c := by rw [hc]; linarith\n        have h4 : (2 * C\u2080') * \u2016z\u2080\u2016 / \u03b5 \u2264 c :=\n          (div_le_div_of_nonneg_right h2 h\u03b5.le).trans h3\n        calc (2 * C\u2080') * \u2016z\u2080\u2016 = (2 * C\u2080') * \u2016z\u2080\u2016 / \u03b5 * \u03b5 := by\n              rw [div_mul_cancel\u2080 _ h\u03b5.ne']\n          _ \u2264 c * \u03b5 := mul_le_mul_of_nonneg_right h4 h\u03b5.le\n          _ \u2264 Q * \u03b5 := mul_le_mul_of_nonneg_right hQc h\u03b5.le\n          _ = \u03b5 * Q := by ring\n      have hQ2 : (2 : \u211d) \u2264 Q := by linarith [hQc, hcz]\n      have hQ3 : (2 : \u211d) \u2264 Q ^ 3 := by\n        have h := pow_le_pow_left\u2080 (by norm_num : (0 : \u211d) \u2264 2) hQ2 3\n        norm_num at h\n        linarith [h]\n      have h2 : \u03b5 * Q \u2264 (\u03b5 / 2) * Q ^ 4 := by\n        have h3 : (\u03b5 / 2) * Q ^ 4 = ((\u03b5 / 2) * Q) * Q ^ 3 := by ring\n        rw [h3]\n        have h6 : (\u03b5 / 2) * Q * 2 \u2264 (\u03b5 / 2) * Q * Q ^ 3 :=\n          mul_le_mul_of_nonneg_left hQ3 (by positivity)\n        have h5 : \u03b5 * Q = (\u03b5 / 2) * Q * 2 := by ring\n        rw [h5]\n        exact h6\n      have h7 : C\u2080' * \u2016z\u2080\u2016 \u2264 2 * C\u2080' * \u2016z\u2080\u2016 := by\n        have h : (0 : \u211d) \u2264 C\u2080' * \u2016z\u2080\u2016 := mul_nonneg hC\u2080'nn (norm_nonneg _)\n        linarith [h]\n      linarith [h7, h1, h2]\n    have hsum : (RB + \u2016Gentire 0\u2016) * \u2016z\u2080\u2016 \u2264 \u03b5 * Q ^ 4 := by\n      have h1 : (RB + \u2016Gentire 0\u2016) * \u2016z\u2080\u2016 \u2264 (C\u2080' + 64 * C\u2081 * Q ^ 3) * \u2016z\u2080\u2016 :=\n        mul_le_mul_of_nonneg_right hRBle (norm_nonneg _)\n      have h2 : (C\u2080' + 64 * C\u2081 * Q ^ 3) * \u2016z\u2080\u2016\n          = C\u2080' * \u2016z\u2080\u2016 + 64 * C\u2081 * Q ^ 3 * \u2016z\u2080\u2016 := by ring\n      linarith [h1, h2, hA, hB]\n    have hmain : (RB + \u2016Gentire 0\u2016) / R * \u2016z\u2080\u2016 \u2264 \u03b5 := by\n      have hQ4pos : (0 : \u211d) < Q ^ 4 := pow_pos hQpos 4\n      have h1 : (RB + \u2016Gentire 0\u2016) / R * \u2016z\u2080\u2016 = (RB + \u2016Gentire 0\u2016) * \u2016z\u2080\u2016 / Q ^ 4 := by\n        rw [hR4]\n        ring\n      rw [h1, div_le_iff\u2080 hQ4pos]\n      exact hsum\n    -- assemble\n    have hdz0 : dist z\u2080 (0 : \u2102) = \u2016z\u2080\u2016 := by rw [dist_eq_norm, sub_zero]\n    calc dist (Gentire z\u2080) (Gentire 0)\n        \u2264 (RB + \u2016Gentire 0\u2016) / R * dist z\u2080 0 := hschwarz\n      _ = (RB + \u2016Gentire 0\u2016) / R * \u2016z\u2080\u2016 := by rw [hdz0]\n      _ \u2264 \u03b5 := hmain\n  -- dist < every \u03b5 \u27f9 dist = 0\n  rcases le_or_lt (dist (Gentire z\u2080) (Gentire 0)) 0 with h | h\n  \u00b7 exact dist_eq_zero.mp (le_antisymm h dist_nonneg)\n  \u00b7 have h2 := key (dist (Gentire z\u2080) (Gentire 0) / 2) (by linarith)\n    linarith\n\n/-! ## 5. The capstone: the partial-fraction identity -/\n\n/-- **The ii\u2032-5e capstone** (D-068 \u00a75): under the perimeter zero count\n`ZeroCountProp`, the completed partial-fraction identity\n\u03b6\u2032/\u03b6(s) = B + \u03a3_\u03c1 m_\u03c1(1/(s\u2212\u03c1) + 1/\u03c1) \u2212 1/s \u2212 1/(s\u22121) + \u00bdlog \u03c0 \u2212 \u00bd\u03c8(s/2)\nholds at every s off the excluded set. Proof: the difference Fexpr is\nentire (5e-iv) and O((log R)\u00b2\u00b7\u0108\u2080) = o(R) on the \u03b3-gap circles\n(`Fexpr_circle_le`), so the max-modulus + Schwarz squeeze (`gentire_const`)\nforces it constant. -/\ntheorem partialFraction_identity (hZC : ZeroCountProp) :\n    \u2203 B : \u2102, \u2200 s : \u2102, riemannZeta s \u2260 0 \u2192 s \u2260 0 \u2192 s \u2260 1 \u2192\n      (\u2200 n : \u2115, 1 \u2264 n \u2192 s \u2260 -2 * (n : \u2102)) \u2192\n      logDeriv riemannZeta s\n        = B + seriesFun s - 1 / s - 1 / (s - 1) + (Real.log Real.pi : \u2102) / 2\n          - Complex.digamma (s / 2) / 2 := by\n  refine \u27e8Gentire 0, fun s h\u03b6 hs0 hs1 hsn => ?_\u27e9\n  have hgood : \u00ac badPoint s := by\n    rintro (h | h | h | \u27e8n, hn, h\u27e9)\n    \u00b7 exact h\u03b6 h.1\n    \u00b7 exact hs0 h\n    \u00b7 exact hs1 h\n    \u00b7 exact hsn n hn h\n  have hG : Fexpr s = Gentire 0 := by\n    rw [\u2190 gentire_eq_Fexpr hgood]\n    exact gentire_const hZC s\n  rw [Fexpr] at hG\n  linear_combination hG\n\nend NguyenRH1\n\nend\n"
}
result 2026-08-24 06:18:15Z → 2026-08-24 06:18:15Z
{
  "type": "create",
  "filePath": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiSqueeze.lean",
  "content": "/-\nNguyenRH1/LiSqueeze.lean \u2014 tier ii\u2032 sub-stage ii\u2032-5e-v-d (D-068 \u00a75):\nthe Schwarz squeeze \u27f9 the partial-fraction capstone.\n\n\u00a71: the \u0108\u2080 growth bound `C0hat_add_two_le` (\u0108\u2080(R+2) \u2264 5\u00b7log R).\n\u00a72: `not_badPoint_on_gapCircle` \u2014 every point of a \u03b3-gap circle is good.\n\u00a73: `gentire_circle_le` \u2014 the Fexpr circle bound transferred to Gentire.\n\u00a74: `gentire_const` \u2014 max-modulus + Schwarz on the gap-circle sequence:\n    the (log R)\u00b3/R \u2192 0 squeeze forces Gentire \u2261 Gentire 0.\n\u00a75: the capstone `partialFraction_identity (hZC : ZeroCountProp)`.\n\nArchive references: D-068 \u00a75, STATE.md session-034 next-action design.\n-/\nimport Mathlib\nimport NguyenRH1.LiCircleBound\n\nopen Zeta23 Complex Filter Topology\n\nnoncomputable section\n\nnamespace NguyenRH1\n\n/-! ## 1. The \u0108\u2080 growth bound -/\n\n/-- \u0108\u2080(R+2) \u2264 5\u00b7log R for R \u2265 16002 (so log R \u2265 9): log(R+4) \u2264 2\u00b7log R,\nlog log(R+4) \u2264 2\u00b7log R, and 2.9 \u2264 (1/3)\u00b7log R; total 2.97\u00b7log R. -/\nlemma C0hat_add_two_le {R : \u211d} (hR : 16002 \u2264 R) :\n    C0hat (R + 2) \u2264 5 * Real.log R := by\n  have hRpos : (0 : \u211d) < R := by linarith\n  have hlogR : (9 : \u211d) \u2264 Real.log R := nine_le_log_of_16002_le hR\n  have h1 : Real.log (R + 2 + 2) \u2264 2 * Real.log R := by\n    have hle : R + 2 + 2 \u2264 R ^ 2 := by nlinarith [hR]\n    have h2 : Real.log (R + 2 + 2) \u2264 Real.log (R ^ 2) :=\n      Real.log_le_log (by linarith : (0 : \u211d) < R + 2 + 2) hle\n    rwa [Real.log_pow, Nat.cast_two] at h2\n  have h2 : Real.log (Real.log (R + 2 + 2)) \u2264 2 * Real.log R := by\n    have hpos1 : (0 : \u211d) < Real.log (R + 2 + 2) := by\n      have hle : Real.log R \u2264 Real.log (R + 2 + 2) :=\n        Real.log_le_log hRpos (by linarith)\n      linarith [hlogR]\n    have h3 : Real.log (Real.log (R + 2 + 2)) \u2264 Real.log (2 * Real.log R) :=\n      Real.log_le_log hpos1 h1\n    have h4 : Real.log (2 * Real.log R) = Real.log 2 + Real.log (Real.log R) := by\n      rw [Real.log_mul (by norm_num) (by linarith [hlogR] : Real.log R \u2260 0)]\n    have h5 : Real.log 2 \u2264 1 := by\n      have h := Real.log_le_sub_one_of_pos (by norm_num : (0 : \u211d) < 2)\n      linarith\n    have h6 : Real.log (Real.log R) \u2264 Real.log R := by\n      have h := Real.log_le_sub_one_of_pos (by linarith [hlogR] : (0 : \u211d) < Real.log R)\n      linarith\n    linarith [h3, h4, h5, h6, hlogR]\n  unfold C0hat\n  linarith [h1, h2, hlogR]\n\n/-! ## 2. Every \u03b3-gap-circle point is good -/\n\n/-- A point on a \u03b3-gap circle is not a bad point: not a nontrivial zero\n(the circle-bound lemma), not 0 or 1 (norm too large), not \u22122n (the\n\u2124-clearance of R/2). -/\nlemma not_badPoint_on_gapCircle {k : \u2115} (hk : 4000 \u2264 k) {R : \u211d}\n    (hRlo : 4 * (k : \u211d) + 5 / 2 \u2264 R)\n    (hgap : \u2200 \u03c1 : \u2102, IsNontrivialZero \u03c1 \u2192\n      1 / (16 * C0hat (4 * (k : \u211d) + 9 / 2)) \u2264 |\u03c1.im - R| \u2228 1 \u2264 |\u03c1.im - R|)\n    (hgapInt : \u2200 m : \u2124, 1 / 4 \u2264 |R / 2 - (m : \u211d)|)\n    {s : \u2102} (hs : \u2016s\u2016 = R) : \u00ac badPoint s := by\n  have hR16002 : (16002 : \u211d) \u2264 R := by\n    have h1 : (4000 : \u211d) \u2264 (k : \u211d) := by exact_mod_cast hk\n    linarith [hRlo]\n  have hRpos : (0 : \u211d) < R := by linarith [hR16002]\n  rintro (h | h | h | \u27e8n, -, h\u27e9)\n  \u00b7 exact not_isNontrivialZero_on_gapCircle hk hRlo hgap hs h\n  \u00b7 rw [h, norm_zero] at hs\n    linarith [hRpos]\n  \u00b7 rw [h, norm_one] at hs\n    linarith [hR16002]\n  \u00b7 have hR2 : R = 2 * (n : \u211d) := by\n      rw [\u2190 hs, h, norm_mul]\n      have h1 : \u2016(-2 : \u2102)\u2016 = 2 := by\n        rw [show (-2 : \u2102) = ((-2 : \u211d) : \u2102) by push_cast; ring, Complex.norm_real]\n        norm_num\n      rw [h1, Complex.norm_natCast]\n    have hcon := hgapInt (n : \u2124)\n    rw [Int.cast_natCast] at hcon\n    have h0 : R / 2 - (n : \u211d) = 0 := by rw [hR2]; ring\n    rw [h0, abs_zero] at hcon\n    linarith [hcon]\n\n/-! ## 3. The circle bound for Gentire -/\n\n/-- The Fexpr circle bound transfers to Gentire on the \u03b3-gap circles\n(every circle point is good, so Gentire = Fexpr there). -/\ntheorem gentire_circle_le {k : \u2115} (hk : 4000 \u2264 k) {R : \u211d}\n    (hRlo : 4 * (k : \u211d) + 5 / 2 \u2264 R) (hRhi : R \u2264 4 * (k : \u211d) + 3)\n    (hgap : \u2200 \u03c1 : \u2102, IsNontrivialZero \u03c1 \u2192\n      1 / (16 * C0hat (4 * (k : \u211d) + 9 / 2)) \u2264 |\u03c1.im - R| \u2228 1 \u2264 |\u03c1.im - R|)\n    (hgapInt : \u2200 m : \u2124, 1 / 4 \u2264 |R / 2 - (m : \u211d)|)\n    {s : \u2102} (hs : \u2016s\u2016 = R) :\n    \u2016Gentire s\u2016 \u2264 2 * lowZeroConst + dirichletC2 +\n      400000 * A0count * C0hat (R + 2) * (Real.log R) ^ 2 := by\n  have hgood : \u00ac badPoint s := not_badPoint_on_gapCircle hk hRlo hgap hgapInt hs\n  rw [gentire_eq_Fexpr hgood]\n  exact Fexpr_circle_le hk hRlo hRhi hgap hgapInt hs\n\n/-! ## 4. The squeeze: Gentire is constant -/\n\n/-- **The Schwarz squeeze**: under the perimeter zero count, Gentire is\nconstant. For each \u03b5 > 0 pick a \u03b3-gap circle of radius R \u2265 16002 with\nR^{1/4} \u2265 2 + (128\u00b7C\u2081 + 2\u00b7C\u2080')\u00b7\u2016z\u2080\u2016/\u03b5; max-modulus bounds Gentire on the\nball by the circle bound, Schwarz then gives\ndist (Gentire z\u2080) (Gentire 0) \u2264 (C\u2080' + 64\u00b7C\u2081\u00b7R^{3/4})\u00b7\u2016z\u2080\u2016/R \u2264 \u03b5. -/\ntheorem gentire_const (hZC : ZeroCountProp) (z\u2080 : \u2102) : Gentire z\u2080 = Gentire 0 := by\n  classical\n  have hA0nn : (0 : \u211d) \u2264 A0count := A0count_pos.le\n  have key : \u2200 \u03b5 : \u211d, 0 < \u03b5 \u2192 dist (Gentire z\u2080) (Gentire 0) \u2264 \u03b5 := by\n    intro \u03b5 h\u03b5\n    -- the constants\n    set C\u2080' := 2 * lowZeroConst + dirichletC2 + \u2016Gentire 0\u2016 with hC0'\n    set C\u2081 := 2000000 * A0count with hC1\n    have hC\u2080'nn : (0 : \u211d) \u2264 C\u2080' := by\n      rw [hC0']\n      linarith [lowZeroConst_nonneg, dirichletC2_nonneg, norm_nonneg (Gentire 0)]\n    have hC\u2081nn : (0 : \u211d) \u2264 C\u2081 := by\n      rw [hC1]\n      exact mul_nonneg (by norm_num) hA0nn\n    set c := 2 + (128 * C\u2081 + 2 * C\u2080') * \u2016z\u2080\u2016 / \u03b5 with hc\n    have hXnn : (0 : \u211d) \u2264 (128 * C\u2081 + 2 * C\u2080') * \u2016z\u2080\u2016 / \u03b5 :=\n      div_nonneg (mul_nonneg (add_nonneg (mul_nonneg (by norm_num) hC\u2081nn)\n        (mul_nonneg (by norm_num) hC\u2080'nn)) (norm_nonneg _)) h\u03b5.le\n    have hcz : (2 : \u211d) \u2264 c := by rw [hc]; linarith [hXnn]\n    have hcnn : (0 : \u211d) \u2264 c := by linarith [hcz]\n    -- the radius choice\n    set M := max (c ^ 4) (\u2016z\u2080\u2016 + 1) with hM\n    obtain \u27e8k, hk4000, hkM\u27e9 : \u2203 k : \u2115, 4000 \u2264 k \u2227 M \u2264 4 * (k : \u211d) := by\n      refine \u27e8max 4000 \u2308M / 4\u2309\u208a, le_max_left _ _, ?_\u27e9\n      have h1 : M / 4 \u2264 (\u2308M / 4\u2309\u208a : \u211d) := Nat.le_ceil _\n      have h2 : (\u2308M / 4\u2309\u208a : \u211d) \u2264 ((max 4000 \u2308M / 4\u2309\u208a : \u2115) : \u211d) := by\n        exact_mod_cast le_max_right _ _\n      linarith [h1, h2]\n    obtain \u27e8R, hRlo, hRhi, hgapInt, hgap\u27e9 :=\n      exists_gapCircle_radius hZC (k := k) (by omega)\n    have hR16002 : (16002 : \u211d) \u2264 R := by\n      have h1 : (4000 : \u211d) \u2264 (k : \u211d) := by exact_mod_cast hk4000\n      linarith [hRlo]\n    have hRpos : (0 : \u211d) < R := by linarith [hR16002]\n    have hlogR : (9 : \u211d) \u2264 Real.log R := nine_le_log_of_16002_le hR16002\n    have hMR : M \u2264 R := by linarith [hkM, hRlo]\n    -- the circle bound on the sphere, then the ball by max-modulus\n    set RB := 2 * lowZeroConst + dirichletC2 +\n      400000 * A0count * C0hat (R + 2) * (Real.log R) ^ 2 with hRB\n    have hsphere : \u2200 z \u2208 Metric.sphere (0 : \u2102) R, \u2016Gentire z\u2016 \u2264 RB := by\n      intro z hz\n      have hznorm : \u2016z\u2016 = R := by\n        have h := Metric.mem_sphere.mp hz\n        rwa [dist_eq_norm, sub_zero] at h\n      exact gentire_circle_le hk4000 hRlo hRhi hgap hgapInt hznorm\n    have hGan : AnalyticOn \u2102 Gentire (Metric.closedBall 0 R) :=\n      AnalyticOnNhd.analyticOn (fun s _ => gentire_analyticAt_and_eq.1 s)\n    have hball : \u2200 z \u2208 Metric.closedBall (0 : \u2102) R, \u2016Gentire z\u2016 \u2264 RB :=\n      fun z hz => AnalyticOn.norm_le_of_norm_le_on_sphere le_rfl hGan hsphere hz\n    -- the Schwarz inputs\n    have hmaps : Set.MapsTo Gentire (Metric.ball 0 R)\n        (Metric.closedBall (Gentire 0) (RB + \u2016Gentire 0\u2016)) := by\n      intro z hz\n      have hzball : z \u2208 Metric.closedBall (0 : \u2102) R := by\n        rw [Metric.mem_ball] at hz\n        rw [Metric.mem_closedBall]\n        exact hz.le\n      have h1 := hball z hzball\n      rw [Metric.mem_closedBall, dist_eq_norm]\n      calc \u2016Gentire z - Gentire 0\u2016 \u2264 \u2016Gentire z\u2016 + \u2016Gentire 0\u2016 := norm_sub_le _ _\n        _ \u2264 RB + \u2016Gentire 0\u2016 := by linarith [h1]\n    have hdiff : DifferentiableOn \u2102 Gentire (Metric.ball 0 R) :=\n      fun z _ => (gentire_analyticAt_and_eq.1 z).differentiableAt.differentiableWithinAt\n    have hz0mem : z\u2080 \u2208 Metric.ball (0 : \u2102) R := by\n      rw [Metric.mem_ball, dist_eq_norm, sub_zero]\n      have h1 : \u2016z\u2080\u2016 + 1 \u2264 M := le_max_right _ _\n      linarith [hMR]\n    have hschwarz := Complex.dist_le_div_mul_dist_of_mapsTo_ball hdiff hmaps hz0mem\n    -- the growth estimates: RB + \u2016Gentire 0\u2016 \u2264 C\u2080' + 64\u00b7C\u2081\u00b7Q\u00b3, R = Q\u2074\n    set Q := R ^ ((4 : \u211d)\u207b\u00b9) with hQ\n    have hQnn : (0 : \u211d) \u2264 Q := Real.rpow_nonneg hRpos.le _\n    have hQpos : (0 : \u211d) < Q := Real.rpow_pos_of_pos hRpos _\n    have hQc : c \u2264 Q := by\n      have hc4 : c ^ 4 \u2264 R := by\n        have h : c ^ 4 \u2264 M := le_max_left _ _\n        linarith [hMR]\n      have h1 : c = (c ^ 4) ^ ((4 : \u211d)\u207b\u00b9) := by\n        have h := (Real.pow_rpow_inv_natCast hcnn (show (4 : \u2115) \u2260 0 by norm_num)).symm\n        push_cast at h\n        exact h\n      have h2 : (c ^ 4) ^ ((4 : \u211d)\u207b\u00b9) \u2264 Q :=\n        Real.rpow_le_rpow (pow_nonneg (by linarith [hcz] : (0 : \u211d) \u2264 c) 4) hc4\n          (by positivity : (0 : \u211d) \u2264 (4 : \u211d)\u207b\u00b9)\n      rw [h1]\n      exact h2\n    have hL : Real.log R \u2264 4 * Q := by\n      have h := Real.log_le_rpow_div hRpos.le (show (0 : \u211d) < (4 : \u211d)\u207b\u00b9 by positivity)\n      have h2 : R ^ ((4 : \u211d)\u207b\u00b9) / (4 : \u211d)\u207b\u00b9 = 4 * (R ^ ((4 : \u211d)\u207b\u00b9)) := by\n        rw [div_eq_mul_inv, inv_inv]\n        ring\n      rwa [h2] at h\n    have hL3 : (Real.log R) ^ 3 \u2264 64 * Q ^ 3 := by\n      have h1 : (Real.log R) ^ 3 \u2264 (4 * Q) ^ 3 :=\n        pow_le_pow_left\u2080 (by linarith [hlogR]) hL 3\n      have h2 : (4 * Q) ^ 3 = 64 * Q ^ 3 := by ring\n      rwa [h2] at h1\n    have hR4 : R = Q ^ 4 := by\n      have h := Real.rpow_inv_natCast_pow hRpos.le (show (4 : \u2115) \u2260 0 by norm_num)\n      push_cast at h\n      rw [\u2190 hQ] at h\n      exact h.symm\n    have h\u01085 : C0hat (R + 2) \u2264 5 * Real.log R := C0hat_add_two_le hR16002\n    have hbig : 400000 * A0count * C0hat (R + 2) * (Real.log R) ^ 2\n        \u2264 64 * C\u2081 * Q ^ 3 := by\n      have hlogRnn : (0 : \u211d) \u2264 Real.log R := by linarith [hlogR]\n      have h1 : 400000 * A0count * C0hat (R + 2) * (Real.log R) ^ 2\n          \u2264 400000 * A0count * (5 * Real.log R) * (Real.log R) ^ 2 := by\n        apply mul_le_mul_of_nonneg_right _ (pow_nonneg hlogRnn 2)\n        exact mul_le_mul_of_nonneg_left h\u01085\n          (mul_nonneg (by norm_num : (0 : \u211d) \u2264 400000) hA0nn)\n      have h2 : 400000 * A0count * (5 * Real.log R) * (Real.log R) ^ 2\n          = C\u2081 * (Real.log R) ^ 3 := by\n        rw [hC1]\n        ring\n      have h3 : C\u2081 * (Real.log R) ^ 3 \u2264 64 * C\u2081 * Q ^ 3 := by\n        have h := mul_le_mul_of_nonneg_left hL3 hC\u2081nn\n        have h' : C\u2081 * (64 * Q ^ 3) = 64 * C\u2081 * Q ^ 3 := by ring\n        rwa [h'] at h\n      linarith [h1, h2, h3]\n    have hRBle : RB + \u2016Gentire 0\u2016 \u2264 C\u2080' + 64 * C\u2081 * Q ^ 3 := by\n      rw [hRB, hC0']\n      linarith [hbig]\n    -- the real squeeze: (RB + \u2016Gentire 0\u2016)/R\u00b7\u2016z\u2080\u2016 \u2264 \u03b5\n    have hc1 : 128 * C\u2081 * \u2016z\u2080\u2016 \u2264 \u03b5 * Q := by\n      have h1 : (128 * C\u2081 + 2 * C\u2080') * \u2016z\u2080\u2016 / \u03b5 \u2264 c := by rw [hc]; linarith\n      have h2 : (128 * C\u2081) * \u2016z\u2080\u2016 \u2264 (128 * C\u2081 + 2 * C\u2080') * \u2016z\u2080\u2016 := by\n        apply mul_le_mul_of_nonneg_right _ (norm_nonneg _)\n        linarith [hC\u2080'nn]\n      have h3 : (128 * C\u2081) * \u2016z\u2080\u2016 / \u03b5 \u2264 c :=\n        (div_le_div_of_nonneg_right h2 h\u03b5.le).trans h1\n      calc (128 * C\u2081) * \u2016z\u2080\u2016 = (128 * C\u2081) * \u2016z\u2080\u2016 / \u03b5 * \u03b5 := by\n            rw [div_mul_cancel\u2080 _ h\u03b5.ne']\n        _ \u2264 c * \u03b5 := mul_le_mul_of_nonneg_right h3 h\u03b5.le\n        _ \u2264 Q * \u03b5 := mul_le_mul_of_nonneg_right hQc h\u03b5.le\n        _ = \u03b5 * Q := by ring\n    have hA : 64 * C\u2081 * Q ^ 3 * \u2016z\u2080\u2016 \u2264 (\u03b5 / 2) * Q ^ 4 := by\n      have h1 : (64 * C\u2081 * \u2016z\u2080\u2016) * Q ^ 3 \u2264 ((\u03b5 / 2) * Q) * Q ^ 3 := by\n        apply mul_le_mul_of_nonneg_right _ (pow_nonneg hQnn 3)\n        have h64 : (64 : \u211d) * C\u2081 * \u2016z\u2080\u2016 = (128 * C\u2081 * \u2016z\u2080\u2016) / 2 := by ring\n        have hhalf : (\u03b5 / 2) * Q = (\u03b5 * Q) / 2 := by ring\n        rw [h64, hhalf]\n        linarith [hc1]\n      have hL' : (64 * C\u2081 * \u2016z\u2080\u2016) * Q ^ 3 = 64 * C\u2081 * Q ^ 3 * \u2016z\u2080\u2016 := by ring\n      have hR' : ((\u03b5 / 2) * Q) * Q ^ 3 = (\u03b5 / 2) * Q ^ 4 := by ring\n      rwa [hL', hR'] at h1\n    have hB : C\u2080' * \u2016z\u2080\u2016 \u2264 (\u03b5 / 2) * Q ^ 4 := by\n      have h1 : (2 * C\u2080') * \u2016z\u2080\u2016 \u2264 \u03b5 * Q := by\n        have h2 : (2 * C\u2080') * \u2016z\u2080\u2016 \u2264 (128 * C\u2081 + 2 * C\u2080') * \u2016z\u2080\u2016 := by\n          apply mul_le_mul_of_nonneg_right _ (norm_nonneg _)\n          linarith [hC\u2081nn]\n        have h3 : (128 * C\u2081 + 2 * C\u2080') * \u2016z\u2080\u2016 / \u03b5 \u2264 c := by rw [hc]; linarith\n        have h4 : (2 * C\u2080') * \u2016z\u2080\u2016 / \u03b5 \u2264 c :=\n          (div_le_div_of_nonneg_right h2 h\u03b5.le).trans h3\n        calc (2 * C\u2080') * \u2016z\u2080\u2016 = (2 * C\u2080') * \u2016z\u2080\u2016 / \u03b5 * \u03b5 := by\n              rw [div_mul_cancel\u2080 _ h\u03b5.ne']\n          _ \u2264 c * \u03b5 := mul_le_mul_of_nonneg_right h4 h\u03b5.le\n          _ \u2264 Q * \u03b5 := mul_le_mul_of_nonneg_right hQc h\u03b5.le\n          _ = \u03b5 * Q := by ring\n      have hQ2 : (2 : \u211d) \u2264 Q := by linarith [hQc, hcz]\n      have hQ3 : (2 : \u211d) \u2264 Q ^ 3 := by\n        have h := pow_le_pow_left\u2080 (by norm_num : (0 : \u211d) \u2264 2) hQ2 3\n        norm_num at h\n        linarith [h]\n      have h2 : \u03b5 * Q \u2264 (\u03b5 / 2) * Q ^ 4 := by\n        have h3 : (\u03b5 / 2) * Q ^ 4 = ((\u03b5 / 2) * Q) * Q ^ 3 := by ring\n        rw [h3]\n        have h6 : (\u03b5 / 2) * Q * 2 \u2264 (\u03b5 / 2) * Q * Q ^ 3 :=\n          mul_le_mul_of_nonneg_left hQ3 (by positivity)\n        have h5 : \u03b5 * Q = (\u03b5 / 2) * Q * 2 := by ring\n        rw [h5]\n        exact h6\n      have h7 : C\u2080' * \u2016z\u2080\u2016 \u2264 2 * C\u2080' * \u2016z\u2080\u2016 := by\n        have h : (0 : \u211d) \u2264 C\u2080' * \u2016z\u2080\u2016 := mul_nonneg hC\u2080'nn (norm_nonneg _)\n        linarith [h]\n      linarith [h7, h1, h2]\n    have hsum : (RB + \u2016Gentire 0\u2016) * \u2016z\u2080\u2016 \u2264 \u03b5 * Q ^ 4 := by\n      have h1 : (RB + \u2016Gentire 0\u2016) * \u2016z\u2080\u2016 \u2264 (C\u2080' + 64 * C\u2081 * Q ^ 3) * \u2016z\u2080\u2016 :=\n        mul_le_mul_of_nonneg_right hRBle (norm_nonneg _)\n      have h2 : (C\u2080' + 64 * C\u2081 * Q ^ 3) * \u2016z\u2080\u2016\n          = C\u2080' * \u2016z\u2080\u2016 + 64 * C\u2081 * Q ^ 3 * \u2016z\u2080\u2016 := by ring\n      linarith [h1, h2, hA, hB]\n    have hmain : (RB + \u2016Gentire 0\u2016) / R * \u2016z\u2080\u2016 \u2264 \u03b5 := by\n      have hQ4pos : (0 : \u211d) < Q ^ 4 := pow_pos hQpos 4\n      have h1 : (RB + \u2016Gentire 0\u2016) / R * \u2016z\u2080\u2016 = (RB + \u2016Gentire 0\u2016) * \u2016z\u2080\u2016 / Q ^ 4 := by\n        rw [hR4]\n        ring\n      rw [h1, div_le_iff\u2080 hQ4pos]\n      exact hsum\n    -- assemble\n    have hdz0 : dist z\u2080 (0 : \u2102) = \u2016z\u2080\u2016 := by rw [dist_eq_norm, sub_zero]\n    calc dist (Gentire z\u2080) (Gentire 0)\n        \u2264 (RB + \u2016Gentire 0\u2016) / R * dist z\u2080 0 := hschwarz\n      _ = (RB + \u2016Gentire 0\u2016) / R * \u2016z\u2080\u2016 := by rw [hdz0]\n      _ \u2264 \u03b5 := hmain\n  -- dist < every \u03b5 \u27f9 dist = 0\n  rcases le_or_lt (dist (Gentire z\u2080) (Gentire 0)) 0 with h | h\n  \u00b7 exact dist_eq_zero.mp (le_antisymm h dist_nonneg)\n  \u00b7 have h2 := key (dist (Gentire z\u2080) (Gentire 0) / 2) (by linarith)\n    linarith\n\n/-! ## 5. The capstone: the partial-fraction identity -/\n\n/-- **The ii\u2032-5e capstone** (D-068 \u00a75): under the perimeter zero count\n`ZeroCountProp`, the completed partial-fraction identity\n\u03b6\u2032/\u03b6(s) = B + \u03a3_\u03c1 m_\u03c1(1/(s\u2212\u03c1) + 1/\u03c1) \u2212 1/s \u2212 1/(s\u22121) + \u00bdlog \u03c0 \u2212 \u00bd\u03c8(s/2)\nholds at every s off the excluded set. Proof: the difference Fexpr is\nentire (5e-iv) and O((log R)\u00b2\u00b7\u0108\u2080) = o(R) on the \u03b3-gap circles\n(`Fexpr_circle_le`), so the max-modulus + Schwarz squeeze (`gentire_const`)\nforces it constant. -/\ntheorem partialFraction_identity (hZC : ZeroCountProp) :\n    \u2203 B : \u2102, \u2200 s : \u2102, riemannZeta s \u2260 0 \u2192 s \u2260 0 \u2192 s \u2260 1 \u2192\n      (\u2200 n : \u2115, 1 \u2264 n \u2192 s \u2260 -2 * (n : \u2102)) \u2192\n      logDeriv riemannZeta s\n        = B + seriesFun s - 1 / s - 1 / (s - 1) + (Real.log Real.pi : \u2102) / 2\n          - Complex.digamma (s / 2) / 2 := by\n  refine \u27e8Gentire 0, fun s h\u03b6 hs0 hs1 hsn => ?_\u27e9\n  have hgood : \u00ac badPoint s := by\n    rintro (h | h | h | \u27e8n, hn, h\u27e9)\n    \u00b7 exact h\u03b6 h.1\n    \u00b7 exact hs0 h\n    \u00b7 exact hs1 h\n    \u00b7 exact hsn n hn h\n  have hG : Fexpr s = Gentire 0 := by\n    rw [\u2190 gentire_eq_Fexpr hgood]\n    exact gentire_const hZC s\n  rw [Fexpr] at hG\n  linear_combination hG\n\nend NguyenRH1\n\nend\n",
  "structuredPatch": [],
  "originalFile": null
}
#1686 assistant 2026-08-24 06:18:57.555 UTC · 673→197 tok open ⤢
thinking (227 chars)
The todo rewrite consolidated the steps — fine (the step detail lives in the file). Now compile. From the handoff notes: iterate single-file with `lake env lean NguyenRH1/LiSqueeze.lean` from the package dir, with elan on PATH.
Compiling the new file.
tool: Bash
input
{
  "command": "cd D:/Python/Quantum/research/lean/NguyenRH1 && export PATH=\"$HOME/.elan/bin:$PATH\" && lake env lean NguyenRH1/LiSqueeze.lean 2>&1 | head -60",
  "description": "Compile LiSqueeze.lean single-file",
  "timeout": 300000
}
#1687 assistant 2026-08-24 06:19:47.442 UTC · 451→250 tok open ⤢
thinking (351 chars)
LiCircleBound hasn't been built (it's not root-imported, so the build never compiled it). Build it first: `lake build NguyenRH1.LiCircleBound` (will compile the file into olean), then compile LiSqueeze. Or just `lake build NguyenRH1.LiSqueeze` which will build the dependency LiCircleBound first. That's the cleanest: `lake build NguyenRH1.LiSqueeze`.
LiCircleBound's olean doesn't exist yet (never root-imported/built). Building the target with its dependency.
tool: Bash
input
{
  "command": "cd D:/Python/Quantum/research/lean/NguyenRH1 && export PATH=\"$HOME/.elan/bin:$PATH\" && lake build NguyenRH1.LiSqueeze 2>&1 | tail -40",
  "description": "Build LiSqueeze (builds LiCircleBound first)",
  "timeout": 600000
}
#1688 assistant 2026-08-24 06:21:25.072 UTC · 1797→379 tok open ⤢
thinking (517 chars)
LiCircleBound built clean (51s). LiSqueeze has one error: `le_or_lt` unknown identifier — session-030 gotcha banked: "le_or_gt (le_or_lt absent)". So use `le_or_gt`... wait the gotcha says "le_or_gt (le_or_lt absent)" — meaning use `le_or_gt` instead. `le_or_gt : a ≤ b ∨ b < a`? Let me check: `le_or_gt (a b : α) : a ≤ b ∨ a > b` ✓. So `rcases le_or_gt (dist (Gentire z₀) (Gentire 0)) 0 with h | h` — hmm le_or_gt a b : a ≤ b ∨ a > b. With a := dist, b := 0: dist ≤ 0 ∨ dist > 0 ✓ exactly what I want. Fix line 306.
One error: `le_or_lt` doesn't exist in this Mathlib (banked gotcha: use `le_or_gt`). Fixing.
tool: Edit
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiSqueeze.lean",
  "old_string": "  rcases le_or_lt (dist (Gentire z\u2080) (Gentire 0)) 0 with h | h",
  "new_string": "  rcases le_or_gt (dist (Gentire z\u2080) (Gentire 0)) 0 with h | h"
}
#1689 assistant 2026-08-24 06:23:48.486 UTC · 467→306 tok open ⤢
thinking (437 chars)
Full build green — the only warnings are the 5 intended skeleton sorryAx declarations (SuzukiSkeleton + 4 ValleySkeleton) and pre-existing variable-name warnings in ValleySkeleton. No errors, no warnings in LiSqueeze. Now the axiom audit. Check partialFraction_identity, gentire_const, gentire_circle_le, not_badPoint_on_gapCircle, C0hat_add_two_le — should show only [propext, Classical.choice, Quot.sound]. Write a small audit script.
Full build green (only the 5 intended skeleton sorries + pre-existing warnings). Now the axiom audit.
tool: Write
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\AuditSession034.lean",
  "content": "/-\nAuditSession034.lean \u2014 axiom audit for ii\u2032-5e-v-d (session 034).\nExpected: [propext, Classical.choice, Quot.sound] on every declaration.\n-/\nimport NguyenRH1.LiSqueeze\n\nopen NguyenRH1\n\n#print axioms C0hat_add_two_le\n#print axioms not_badPoint_on_gapCircle\n#print axioms gentire_circle_le\n#print axioms gentire_const\n#print axioms partialFraction_identity\n"
}
#1690 assistant 2026-08-24 06:26:32.843 UTC · 1233→2497 tok open ⤢
thinking (812 chars)
Milestone committed. Now the session-end artifacts: 1. journal/session-034.md 2. STATE.md update (NEXT ACTION → ii′-5f) 3. NGUYEN.md §5 checklist (ii′-5e entry) + session log 4. db registration (session + derivation? — the Lean sub-stages get journal + STATE; check how previous sessions registered. From handoff: "Session registration via direct sqlite3 insert (journal_file column)".) Let me check how session 033 did the db registration to mirror. Actually the commits show "journal + STATE + NGUYEN + db". Let me look at the db.py CLI quickly and the session table pattern. From handoff notes: `db.py: init, log-experiment, add-result, add-derivation, add-graveyard, list`. Session registration via direct sqlite3 insert. Let me write the journal first, then STATE, then NGUYEN, then db, then final commit.
Milestone committed. Now the session-end archive artifacts (journal, STATE, NGUYEN, db).
tool: Write
input
{
  "file_path": "D:\\Python\\Quantum\\research\\journal\\session-034.md",
  "content": "# Session 034 \u2014 2026-08-23 \u2014 ii\u2032-5e-v-d COMPLETE: the Schwarz squeeze \u27f9\n# the partial-fraction capstone\n\n## Directive\nContinue ii\u2032-5e-v per STATE.md: chunk 5e-v-d \u2014 the Schwarz squeeze \u27f9\nthe \u2203 B capstone `partialFraction_identity` (LiCircleBound.lean \u00a713 or a\nnew LiSqueeze.lean). User: \"Let's start ii\u2032-5e-v-d\".\n\n## Outcome: 5e-v-d COMPLETE (commit 5a262a1; new file LiSqueeze.lean,\n~330 lines, clean elaboration, zero warnings; LiCircleBound + LiSqueeze\nroot-imported; full build GREEN; audit-session034-axioms.txt: 5 decls,\n3 standard axioms only)\n\nNew file **LiSqueeze.lean** (imports LiCircleBound; LiCircleBound built\nfor the first time \u2014 51 s \u2014 and both now root-imported):\n\n- **\u00a71 `C0hat_add_two_le`**: \u0108\u2080(R+2) \u2264 5\u00b7log R for R \u2265 16002. Via\n  log(R+4) \u2264 2\u00b7log R (R+4 \u2264 R\u00b2, Real.log_pow), log log(R+4) \u2264\n  log(2\u00b7log R) = log 2 + log log R \u2264 1 + log R \u2264 2\u00b7log R\n  (Real.log_le_sub_one_of_pos twice), 2.9 \u2264 (1/3)\u00b7log R; total\n  0.433\u00b72 + 0.886\u00b72 + 1/3 \u2248 2.97 \u2264 5.\n- **\u00a72 `not_badPoint_on_gapCircle`**: the four-way badness split \u2014\n  not nontrivial (session-032's `not_isNontrivialZero_on_gapCircle`),\n  \u2260 0/1 (norms: \u2016s\u2016 = R \u2265 16002), \u2260 \u22122n (else R/2 = n \u2208 \u2124 against\n  hgapInt with m := n; `Int.cast_natCast` bridge, `Complex.norm_natCast`).\n- **\u00a73 `gentire_circle_le`**: Gentire s = Fexpr s on the circle (\u00a72 +\n  5e-iv's `gentire_eq_Fexpr`) \u27f9 the Fexpr_circle_le bound transfers.\n- **\u00a74 `gentire_const (hZC : ZeroCountProp)` : Gentire z\u2080 = Gentire 0**.\n  The squeeze: for \u03b5 > 0, set C\u2080' := 2\u00b7lowZeroConst + dirichletC2 +\n  \u2016Gentire 0\u2016, C\u2081 := 2\u00b710\u2076\u00b7A\u2080 ( = 400000\u00b7A\u2080\u00b75), c := 2 +\n  (128\u00b7C\u2081 + 2\u00b7C\u2080')\u00b7\u2016z\u2080\u2016/\u03b5, M := max (c\u2074) (\u2016z\u2080\u2016+1), k := max 4000 \u2308M/4\u2309\u208a;\n  the perimeter gap circle R \u2208 [4k+5/2, 4k+3] (exists_gapCircle_radius)\n  has R \u2265 M. Max-modulus (Zeta23\n  `AnalyticOn.norm_le_of_norm_le_on_sphere`, r = R, analytic from\n  `gentire_analyticAt_and_eq.1`) lifts the sphere bound to the ball;\n  MapsTo into closedBall (Gentire 0) (RB + \u2016Gentire 0\u2016) by norm_sub_le;\n  the ball-form Schwarz lemma\n  (`Complex.dist_le_div_mul_dist_of_mapsTo_ball`) gives\n  dist \u2264 (RB + \u2016Gentire 0\u2016)/R\u00b7\u2016z\u2080\u2016. Growth: RB \u2264 C\u2080' + 64\u00b7C\u2081\u00b7Q\u00b3 with\n  Q := R^{1/4} (Real.log_le_rpow_div at \u03b5 = 1/4 \u27f9 log R \u2264 4Q;\n  pow_le_pow_left\u2080 \u27f9 (log R)\u00b3 \u2264 64Q\u00b3; \u0108\u2080(R+2) \u2264 5\u00b7log R by \u00a71) and\n  R = Q\u2074 (Real.rpow_inv_natCast_pow); Q \u2265 c \u27f9 the two branches\n  64\u00b7C\u2081\u00b7Q\u00b3\u00b7\u2016z\u2080\u2016 \u2264 (\u03b5/2)\u00b7Q\u2074 (from 128\u00b7C\u2081\u00b7\u2016z\u2080\u2016 \u2264 \u03b5\u00b7Q) and C\u2080'\u00b7\u2016z\u2080\u2016 \u2264\n  (\u03b5/2)\u00b7Q\u2074 (from 2\u00b7C\u2080'\u00b7\u2016z\u2080\u2016 \u2264 \u03b5\u00b7Q and \u03b5\u00b7Q \u2264 (\u03b5/2)\u00b7Q\u2074 via Q\u00b3 \u2265 8);\n  sum \u27f9 (RB + \u2016Gentire 0\u2016)\u00b7\u2016z\u2080\u2016 \u2264 \u03b5\u00b7Q\u2074 = \u03b5\u00b7R. Then dist \u2264 \u03b5 for all\n  \u03b5 \u27f9 dist = 0 (le_or_gt rcases + the \u03b5 := dist/2 contradiction) \u27f9\n  Gentire z\u2080 = Gentire 0.\n- **\u00a75 `partialFraction_identity (hZC : ZeroCountProp)`**: \u2203 B : \u2102,\n  \u2200 s, riemannZeta s \u2260 0 \u2192 s \u2260 0 \u2192 s \u2260 1 \u2192 (\u2200 n \u2265 1, s \u2260 \u22122n) \u2192\n  logDeriv riemannZeta s = B + seriesFun s \u2212 1/s \u2212 1/(s\u22121) +\n  (Real.log Real.pi : \u2102)/2 \u2212 Complex.digamma (s/2)/2. Proof: \u03b6 s \u2260 0\n  kills the nontrivial-zero disjunct (IsNontrivialZero.1) \u27f9 \u00ac badPoint s\n  \u27f9 Gentire s = Fexpr s (5e-iv) and Gentire s = Gentire 0 (\u00a74) \u27f9\n  Fexpr s = Gentire 0; unfold Fexpr; linear_combination. B := Gentire 0\n  (no evaluation needed \u2014 D-068 \u00a70: B cancels in 5f's two-point\n  analysis).\n\n**This is the first use of the perimeter in the 5e chain** (the gap\ncircles need ZeroCountProp; 5c/5d/5e-i..iv were Jensen/unconditional).\nThe capstone is exactly the D-068 \u00a75 target statement.\n\n## Inventory verification (all live-checked before writing)\n- `Complex.dist_le_div_mul_dist_of_mapsTo_ball` (Mathlib Schwarz.lean):\n  (hd : DifferentiableOn \u2102 f (ball c R\u2081)) (MapsTo f (ball c R\u2081)\n  (closedBall (f c) R\u2082)) (z \u2208 ball) \u27f9 dist (f z) (f c) \u2264 R\u2082/R\u2081\u00b7dist z c.\n- `AnalyticOn.norm_le_of_norm_le_on_sphere` (Zeta23 StrongPNTPrefix):\n  r \u2264 R, AnalyticOn (closedBall 0 R), sphere-r bound, w \u2208 closedBall 0 r\n  \u27f9 \u2016f w\u2016 \u2264 C.\n- `Real.log_le_rpow_div (0 \u2264 x) (0 < \u03b5) : log x \u2264 x^\u03b5/\u03b5` (Pow/Real).\n- `Real.pow_rpow_inv_natCast_pow` / `Real.rpow_inv_natCast_pow` (the\n  (c\u2074)^{1/4} = c / (R^{1/4})\u2074 = R directions).\n- `pow_le_pow_left\u2080` (the \u2080-suffixed form in this Mathlib;\n  pow_le_pow_left is the preorder one WITHOUT the 0 \u2264 a).\n\n## Banked gotchas (session 034)\n- **`le_or_lt` does NOT exist** (recurrence of the session-030/032\n  gotcha \u2014 now banked here too): use `le_or_gt (a b) : a \u2264 b \u2228 a > b`.\n  The dist-squeeze close: rcases le_or_gt d 0; the d > 0 branch dies\n  by key (d/2).\n- `set Q := R ^ ((4:\u211d)\u207b\u00b9) with hQ` + `rw [\u2190 hQ] at h` after push_cast\n  is the clean (R^{1/4})\u2074 = R bridge; write haves with Q in the\n  statement and give R^{1/4} proofs \u2014 the set-let defeq makes `exact`\n  accept them.\n- `Real.log_le_rpow_div` wants the rpow EXPONENT as the \u03b5 hypothesis:\n  (4:\u211d)\u207b\u00b9 with positivity; the x^\u03b5/\u03b5 \u2192 4\u00b7x^\u03b5 conversion is\n  div_eq_mul_inv + inv_inv + ring.\n- push_cast turns rpow_inv_natCast_pow's ((4:\u2115):\u211d)\u207b\u00b9 exponent into\n  (4:\u211d)\u207b\u00b9 BEFORE the rw [\u2190 hQ] match (cast-mismatch rw failure\n  otherwise).\n- linarith closes every \u2264-chain once the products are pre-formed\n  (div_mul_cancel\u2080 for the /\u03b5\u00b7\u03b5 round trips; mul_le_mul_of_nonneg_right\n  for the single-factor lifts); the banked \"no add_le_add_left/right\"\n  rule kept.\n- lake build of a NON-root-imported file's importer fails with a stale\n  \"object file does not exist\" \u2014 `lake build NguyenRH1.LiSqueeze`\n  builds the dependency chain (LiCircleBound 51 s first time).\n\n## Status / next\n**ii\u2032-5e COMPLETE** (5e-0, i, ii, iii, iv, v-a/b/c/d all done). The\npartial-fraction identity is now Lean-proved modulo ONLY the declared\nperimeter (ZeroCountProp \u2014 Trudgian N(T)/S(T), D-062 \u00a74). Remaining\nmap: **ii\u2032-5f** (D-056's tight constants A = 10.5, B\u2080 = 48 from the\nidentity \u2014 the partial-fraction R-bound, ~1 session) \u2192 ii\u2032-3b (moments)\n\u2192 ii\u2032-3c (crux assembly Sf = Res\u2081) \u2192 ii\u2032-6 (L0) \u2192 ii\u2032-7 (closure +\npaper Appendix B + tag upgrade).\n"
}
#1691 assistant 2026-08-24 06:31:00.881 UTC · 561→1152 tok open ⤢
thinking (157 chars)
Now update NGUYEN.md §5 checklist (the ii′-5e entry) and add the session-034 entry to §8.6 session log. Let me look at the current ii′-5e entry in NGUYEN.md.
Now NGUYEN.md: the ii′-5e checklist entry + the session log.
tool: Edit
input
{
  "file_path": "D:\\Python\\Quantum\\NGUYEN.md",
  "old_string": "      **5e-v-b + 5e-v-c COMPLETE (sessions 030\u2013033)**:\n      LiCircleBound.lean (~3928 lines) \u2014 count bridges (A0count from\n      Zeta23's RvM local count, mult-weighted, all t, unconditional),\n      the Dirichlet bound \u2016\u03b6\u2032/\u03b6\u2016 \u2264 dirichletC2 (re \u2265 2),\n      tsum_split_finset, lowZeroConst, the far-tail bound\n      zero_tail_inv_sq_le (\u03a3_{|\u03b3|>X} m/(1+\u03b3\u00b2) \u2264 16\u00b7A\u2080\u00b7log X/X,\n      X \u2265 200 \u2014 the dyadic fiber machine + ENNReal.tsum_fiberwise),\n      **the series circle bound seriesFun_norm_le_gapCircle**\n      (\u2016seriesFun s\u2016 \u2264 2\u00b7lowZeroConst + 2900\u00b7A\u2080\u00b7\u0108\u2080(4k+9/2)\u00b7(log R)\u00b2\n      on the \u03b3-gap circle, k \u2265 4000), and **the Fexpr circle bound\n      Fexpr_circle_le** (\u2016Fexpr s\u2016 \u2264 2\u00b7lowZeroConst + dirichletC2 +\n      400000\u00b7A\u2080\u00b7\u0108\u2080(R+2)\u00b7(log R)\u00b2): three-region logDeriv assembly\n      (Dirichlet / 5c+5d capstones + the near sum via gapCircle_sep /\n      FE + \u0393R bracket), digamma_circle_le (uniform \u03c8 bound, left\n      near-axis via the \u2124-clearance), and\n      **logDeriv_Gamma\u211d_eq_of_not_neg_nat** (the (G) formula at any\n      non-pole point incl. s = \u2212R \u2014 direct logDeriv_mul, no\n      continuity). Remaining: 5e-v-d Schwarz squeeze \u27f9 capstone \u2203 B.",
  "new_string": "      **5e-v-b + 5e-v-c COMPLETE (sessions 030\u2013033)**:\n      LiCircleBound.lean (~3928 lines) \u2014 count bridges (A0count from\n      Zeta23's RvM local count, mult-weighted, all t, unconditional),\n      the Dirichlet bound \u2016\u03b6\u2032/\u03b6\u2016 \u2264 dirichletC2 (re \u2265 2),\n      tsum_split_finset, lowZeroConst, the far-tail bound\n      zero_tail_inv_sq_le (\u03a3_{|\u03b3|>X} m/(1+\u03b3\u00b2) \u2264 16\u00b7A\u2080\u00b7log X/X,\n      X \u2265 200 \u2014 the dyadic fiber machine + ENNReal.tsum_fiberwise),\n      **the series circle bound seriesFun_norm_le_gapCircle**\n      (\u2016seriesFun s\u2016 \u2264 2\u00b7lowZeroConst + 2900\u00b7A\u2080\u00b7\u0108\u2080(4k+9/2)\u00b7(log R)\u00b2\n      on the \u03b3-gap circle, k \u2265 4000), and **the Fexpr circle bound\n      Fexpr_circle_le** (\u2016Fexpr s\u2016 \u2264 2\u00b7lowZeroConst + dirichletC2 +\n      400000\u00b7A\u2080\u00b7\u0108\u2080(R+2)\u00b7(log R)\u00b2): three-region logDeriv assembly\n      (Dirichlet / 5c+5d capstones + the near sum via gapCircle_sep /\n      FE + \u0393R bracket), digamma_circle_le (uniform \u03c8 bound, left\n      near-axis via the \u2124-clearance), and\n      **logDeriv_Gamma\u211d_eq_of_not_neg_nat** (the (G) formula at any\n      non-pole point incl. s = \u2212R \u2014 direct logDeriv_mul, no\n      continuity). **5e-v-d COMPLETE (session 034) \u2014 ii\u2032-5e DONE**:\n      LiSqueeze.lean (~330 lines, 5 decls audited clean; LiCircleBound\n      + LiSqueeze root-imported) \u2014 the Schwarz squeeze\n      (`gentire_const`: max-modulus + ball-form Schwarz on the \u03b3-gap\n      circles, growth (log R)\u00b3/R \u2192 0 via Q := R^{1/4} \u27f9 Gentire \u2261\n      Gentire 0 =: B) and **THE CAPSTONE `partialFraction_identity`\n      (hZC : ZeroCountProp)**: \u2203 B : \u2102, \u03b6\u2032/\u03b6(s) = B + seriesFun s \u2212\n      1/s \u2212 1/(s\u22121) + \u00bdlog \u03c0 \u2212 \u00bd\u03c8(s/2) off the excluded set \u2014 the\n      partial-fraction identity Lean-proved modulo ONLY the declared\n      perimeter. Remaining: 5f (tight constants 10.5/48 from D-056's\n      two-point analysis of the identity)."
}
#1692 assistant 2026-08-24 06:33:31.371 UTC · 966→222 tok open ⤢
thinking (232 chars)
Now the db registration. From the handoff notes: "Session registration via direct sqlite3 insert (journal_file column)." Let me check how session 033 was registered — look at the db.py CLI and mimic. Let me check the sessions table.
Now the db session registration (mirroring session 033's pattern).
tool: Bash
input
{
  "command": "cd D:/Python/Quantum/research && ./../.venv/Scripts/python.exe -c \"\nimport sqlite3\ncon = sqlite3.connect('research.db')\nrow = con.execute(\\\"SELECT * FROM sessions ORDER BY rowid DESC LIMIT 1\\\").fetchone()\ncols = [d[0] for d in con.execute('SELECT * FROM sessions LIMIT 1').description]\nprint(cols)\nprint(row)\n\"",
  "description": "Inspect sessions table schema and last row"
}
#1693 assistant 2026-08-24 06:35:06.326 UTC · 541→684 tok open ⤢
**ii′-5e-v-d COMPLETE — and with it, ii′-5e is DONE.** Two commits: `5a262a1` (milestone) + `0b5d2bc` (closure). ## What was built — LiSqueeze.lean (~330 lines, 5 decls, all audited: 3 standard axioms only) 1. **`C0hat_add_two_le`** — Ĉ₀(R+2) ≤ 5·log R for R ≥ 16002 (the growth bound). 2. **`not_badPoint_on_gapCircle`** — every γ-gap-circle point is good (norm excludes 0/1; the ℤ-clearance dist(R/2,ℤ) ≥ 1/4 excludes −2n; session-032's lemma excludes nontrivial zeros). 3. **`gentire_circle_le`** — the Fexpr circle bound transfers to Gentire on the circles. 4. **`gentire_const`** — the squeeze: max-modulus (Zeta23's sphere lemma) lifts the circle bound to the ball; the ball-form Schwarz lemma gives `dist (Gentire z₀) (Gentire 0) ≤ (RB + ‖Gentire 0‖)/R · ‖z₀‖`; with Q := R^{1/4}, the bound is ≤ (C₀′ + 64·C₁·Q³)·‖z₀‖/Q⁴, and choosing the perimeter gap circle with Q ≥ 2 + (128·C₁ + 2·C₀′)·‖z₀‖/ε forces it ≤ ε — for all ε, so Gentire ≡ Gentire 0. 5. **THE CAPSTONE `partialFraction_identity (hZC : ZeroCountProp)`** — ∃ B : ℂ, for all s with ζ s ≠ 0, s ≠ 0, s ≠ 1, s ≠ −2n: `ζ′/ζ(s) = B + Σ_ρ m_ρ(1/(s−ρ) + 1/ρ) − 1/s − 1/(s−1) + ½log π − ½ψ(s/2)` The partial-fraction identity is now **Lean-proved modulo only the declared perimeter** (ZeroCountProp — Trudgian N(T)/S(T), D-062 §4). This is the first perimeter use in the 5e chain (the gap circles need it); everything else was unconditional. Build: full green, LiCircleBound + LiSqueeze root-imported; sorryAx remains only on the 5 intended skeletons. One build hiccup: `le_or_lt` doesn't exist in this Mathlib (banked gotcha — `le_or_gt` + the dist/2 contradiction closes the squeeze). **Next (session 035): ii′-5f** — the tight constants A = 10.5, B₀ = 48 from D-056's two-point analysis of the identity (B cancels — no evaluation needed), ~1 session. Then ii′-3b (moments) → ii′-3c (crux) → ii′-6 → ii′-7 closure.
#1694 user 2026-08-24 06:36:30.610 UTC open ⤢
Let's work on session 035
#1695 assistant 2026-08-24 06:37:21.206 UTC · 737→1294 tok open ⤢
thinking (3074 chars)
Session 035: ii′-5f — the tight R-bound from the partial-fraction identity. Per STATE.md NEXT ACTION: > Session 035: **ii′-5f** — the tight R-bound from the identity: D-056's six-piece analysis on `partialFraction_identity` at s vs the reference point s₀ = 2+it ⟹ |R(s)| ≤ 13.73·C₀(t) + 7.97 ≤ 10.5·log(|t|+2) + 48 EXACTLY (the baked LiSkeleton constants; D-068 §6 preview: near sum ≤ C₀(t) via the perimeter ZeroCountProp, far difference ≤ 12.73·C₀ + 7.06 via Σ 1/(k(k+1)) = 1, Z₂ ≤ 0.65 certified, ψ-difference via digamma_stirling; B := Gentire 0 cancels in the two-point difference — no evaluation needed). ~1 session. First, per the session START protocol: read STATE.md (done implicitly — I just updated it, but let me follow protocol properly; I know the state), skim latest journal (session-034, just written). The key input now is **D-056** — the reference-point R-bound proof with A = 10.5, B₀ = 48. I need to read D-056 carefully to understand the six-piece analysis, and D-068 §6 (the preview of what 5f consumes). Also look at what "the R-bound" means in the LiSkeleton context — SfBoundProp is the target eventually, and the R-bound is |ζ′/ζ(s) − Σ_near...| ≤ A log|t| + B₀ on the contour? Let me recall from NGUYEN.md: - D-056 (session 009): "reference-point R-bound PROVED (A = 10.5, B₀ = 48, honest C₀ incl. log log term — D-036 §0 erratum) + digamma remainder |r| ≤ 1.2/|w|² PROVED + I_I housekeeping." - D-036: explicit |ξ′/ξ| / |L′/L| contour bounds. The R-bound in the D-036/D-037/R-004 context: R(s) = ζ′/ζ(s) − Σ_{|γ−t|<1} m_ρ/(s−ρ) is the "R" in the R-bound |R(s)| ≤ A log(|t|+2) + B₀ used for the contour estimates (I_II/I_III integrals in the Lagarias Thm 6.1 bridge). Hmm — actually let me not guess. Let me read D-056 and D-068 §6 first. Also need to understand what the Lean deliverable for 5f should be. The SfBoundProp proof (ii′-6) needs: |Sf n| ≤ Bn FAlt n on [10⁵, N₁], via the contour assembly: |Sf| ≤ |λ_n(T)| + |sides| + |triv| where the sides integrals need the R-bound with the tight constants 10.5/48 (the constants baked into LiSkeleton's Hhat/marginTilde: Hhat T = 3·C0hat² + 10.5·log(T+2) + 48). So 5f's deliverable: a Lean theorem stating the tight R-bound, presumably: ‖logDeriv ζ s − Σ_{ρ ∈ nearZeros t} m_ρ/(s−ρ)‖ ≤ 10.5·log(|t|+2) + 48 for s on the relevant contour (σ ∈ [−1, 2]? |t| ≥ T₀-something), proved from partialFraction_identity + ZeroCountProp. Let me read D-056 first — it's the analytic content. Also D-068 §6 preview. And check what LiSkeleton expects (where does 10.5/48 appear — Hhat). Plan: 1. Read D-056 (the proof to formalize). 2. Read D-068 §6 (already read — the preview says: near sum ≤ C₀(t) (perimeter ZeroCountProp), far difference ≤ 12.73 C₀ + 7.06 (Σ 1/(k(k+1)) = 1), Z₂ ≤ 0.65 certified, ψ-difference via digamma_stirling ⟹ |R| ≤ 13.73·C₀(t) + 7.97 ≤ 10.5·log(|t|+2) + 48 EXACTLY). 3. Check what nearZeros is in Lean (LiDisc/LiReflect define nearZeros t as a finset). 4. Design the 5f statement + proof decomposition. 5. Build it. Let me start reading. D-056 is in research/derivations/.
Starting session 035 — ii′-5f. Per protocol, reading the design inputs first: D-056 (the tight-constant proof to formalize) and the relevant Lean context (nearZeros, Hhat).
tool: TodoWrite
input
{
  "todos": [
    {
      "content": "Read D-056 (six-piece analysis) + D-068 \u00a76 + nearZeros/Hhat Lean context",
      "status": "in_progress",
      "activeForm": "Reading D-056 and Lean context"
    },
    {
      "content": "Design 5f statement + proof decomposition (D-069)",
      "status": "pending",
      "activeForm": "Designing 5f"
    },
    {
      "content": "Build 5f pieces in Lean",
      "status": "pending",
      "activeForm": "Building 5f"
    },
    {
      "content": "Build green + axiom audit + commit + journal/STATE/NGUYEN/db",
      "status": "pending",
      "activeForm": "Closing session 035"
    }
  ]
}
#1696 assistant 2026-08-24 06:39:56.687 UTC · 3920→3766 tok open ⤢
thinking (10398 chars)
Now I understand the D-056 theorem to formalize: **Theorem R.** For s = σ + it, σ ∈ [−5/2, 3], |t| ≥ 10: R(s) := ζ′/ζ(s) − Σ_{|γ−t|<1} 1/(s−ρ) |R(s)| ≤ 10.5·log(|t|+2) + 48. Wait — one important detail: D-056's R(s) has the near sum WITHOUT multiplicity weights: Σ_{|γ−t|<1} 1/(s−ρ). But the partial-fraction identity in Lean has Σ m_ρ(1/(s−ρ) + 1/ρ) over the zero subtype (with zeroMult). The D-036/D-056 paper convention writes the sum over zeros "counted with multiplicity" implicitly as Σ_ρ where each ρ appears m_ρ times, or without multiplicities if RH-simplicity... Actually in D-056, the near sum Σ_{|γ−t|<1} 1/(s−ρ) — since the R-bound is used in the contour assembly for the Li theorem, and zeros could have multiplicity in principle... In the paper world (D-036 §1), the sum runs over zeros counted with multiplicity (standard convention). In Lean, nearZeros t is a finset of the subtype with zeroMult weights — from LiDisc: `logDeriv_riemannZeta_sub_nearZeros_le`: ‖ζ′/ζ(s) − Σ_{|γ−t|<1} m/(s−ρ)‖ ≤ 100000·(log|t|)². So the near sum in the LiDisc capstone is mult-weighted: Σ_{ρ ∈ nearZeros t} (zeroMult ρ)/(s−ρ). For 5f, the deliverable should be the tight version of the same shape: ‖logDeriv ζ s − Σ_{ρ ∈ nearZeros t} (zeroMult ρ : ℂ)/(s−ρ)‖ ≤ 10.5·log(|t|+2) + 48 for σ ∈ [−5/2, 3], |t| ≥ 10, ζ s ≠ 0 (and off the trivial zeros etc.). Wait — but actually, hmm: what does the assembly (ii′-6) actually need? Let me check how D-037/D-062 use the R-bound. In D-037, the contour bounds for the Lagarias bridge use H = ζ′/ζ split into near sum + R-bound on the sides of the rectangle at height T(n) = √n+1... The R-bound enters the I_II/I_III estimates. The Lean marginTilde already encodes the CONSTANTS 10.5/48 via Hhat and the margin formula (see LiSkeleton: `2 * F T + 4 * T * ((2/3) * C0hat T + 10.5 * Real.log (T + 2) + 48) + ...`). So 5f's deliverable must produce exactly the bound shape used in D-037's assembly: the R-bound |ζ′/ζ(s) − Σ_near m/(s−ρ)| ≤ 10.5 log(|t|+2) + 48 for s on the contour (σ ∈ [−1,2]-ish, t = T ≥ ...). Wait, in D-056 it's σ ∈ [−5/2, 3], |t| ≥ 10. The contour for ii′-6 (from D-037): the rectangle with corners... at height T = √n+1, σ from −(something) to 2. Anyway — σ ∈ [−5/2, 3] covers it (the contour's vertical range is within [−1, 2] per D-037? Hmm, actually the Lagarias kernel contour: from D-062's layer map, the sides are at re = −1/2...? I don't remember exactly. D-056 says σ ∈ [−5/2, 3] which should cover whatever the contour needs.) Now — the Lean proof plan. From the partial-fraction identity: logDeriv ζ s = B + seriesFun s − 1/s − 1/(s−1) + (log π)/2 − ψ(s/2)/2 Take the difference between s and s₀ = 2+it: logDeriv ζ s − logDeriv ζ s₀ = seriesFun s − seriesFun s₀ − (1/s − 1/s₀) − (1/(s−1) − 1/(s₀−1)) − (ψ(s/2) − ψ(s₀/2))/2 (B cancels; (log π)/2 cancels.) seriesFun s − seriesFun s₀ = Σ_ρ m_ρ [1/(s−ρ) + 1/ρ − 1/(s₀−ρ) − 1/ρ] = Σ_ρ m_ρ (1/(s−ρ) − 1/(s₀−ρ)) = Σ_ρ m_ρ (s₀−s)/((s−ρ)(s₀−ρ)). So: logDeriv ζ s = logDeriv ζ s₀ + Σ_ρ m_ρ(s₀−s)/((s−ρ)(s₀−ρ)) − (1/s − 1/s₀) − (1/(s−1) − 1/(s₀−1)) − (ψ(s/2) − ψ(s₀/2))/2. Split the series into near (|γ−t| < 1) and far (|γ−t| ≥ 1): Σ_near m_ρ(s₀−s)/((s−ρ)(s₀−ρ)) + Σ_far m_ρ(s₀−s)/((s−ρ)(s₀−ρ)). R(s) = logDeriv ζ s − Σ_near m_ρ/(s−ρ). Note the near part of the difference series is Σ_near m_ρ[(s₀−s)/((s−ρ)(s₀−ρ))] = Σ_near m_ρ[1/(s−ρ) − 1/(s₀−ρ)]. So: R(s) = logDeriv ζ s₀ − Σ_near m_ρ/(s₀−ρ) + Σ_far m_ρ(s₀−s)/((s−ρ)(s₀−ρ)) − (1/s − 1/s₀) − (1/(s−1) − 1/(s₀−1)) − (ψ(s/2) − ψ(s₀/2))/2. This matches D-056's display (with multiplicities). Six pieces: 1. |ζ′/ζ(s₀)| ≤ Z₂ ≤ 0.57 (Dirichlet bound at re 2 — in Lean: norm_logDeriv_zeta_le_dirichlet gives ≤ dirichletC2 — what is dirichletC2's value? It's defined in LiCircleBound line 203. If dirichletC2 ≤ 0.57 exactly... it's presumably defined as −ζ′/ζ(2) = Σ Λ(n)/n² ≈ 0.56996 or the majorant with some slack. Let me check the def.) 2. Near at s₀: |s₀−ρ| ≥ 1 (since re ρ ≤ 1... wait β < 1 strictly? For nontrivial zeros re ρ < 1 so |s₀−ρ| ≥ 2 − re ρ > 1. In Lean, IsNontrivialZero gives re < 1, so |s₀−ρ| ≥ |re(s₀−ρ)| = 2 − re ρ > 1 ≥ 1) ⟹ Σ_near m_ρ/|s₀−ρ| ≤ Σ_near m_ρ ≤ (count) ≤ C₀(t) — via the perimeter ZeroCountProp. In Lean: the count input is ZeroCountProp: ∀ t ≥ 2, (Nat.card (zeroWindow t) : ℝ) ≤ C0hat (t+1) where zeroWindow t = zeros with im in (t, t+1]? Need to check the exact def in LiContour.lean. The near sum Σ_{|γ−t|<1} m_ρ needs bounding by C0hat-ish via covering the window |γ−t| < 1 by two unit windows. In LiCircleBound there are Ncount bridges (Ncount_le_of_interval etc.) — mult-weighted counts. nearZeros_count_le (session 033): "the near-window mult-count ≤ 3·A₀·log(3·max|t−1||t+1|+5), single zerosIn window" — that's the unconditional Jensen-flavored count, NOT the perimeter one. For the TIGHT bound we need the perimeter version: Σ_near m ≤ 2·C0hat(t+2)-ish. Hmm, D-056 says ≤ C₀(t) where C₀(t) := F(t+1)−F(t) + S_b(t+1) + S_b(t) ≤ 0.433 log(t+2) + 0.886 loglog(t+2) + 2.9 = C0hat(t)... wait C0hat t = 0.433 log(t+2) + 0.886 log log(t+2) + 2.9 — and C₀(t) ≤ that. And Lean's ZeroCountProp: (Nat.card (zeroWindow t) : ℝ) ≤ C0hat (t+1). So the mult-count over |γ−t|<1 ⊂ (t−1, t+1) ⊂ two unit windows (t−1, t] and (t, t+1): each ≤ C0hat(t+1)... hmm: zeroWindow t covers (t, t+1]? Let me check the def. If zeroWindow t = {zeros with im ∈ (t, t+1]}, then |γ−t|<1 means γ ∈ (t−1, t+1) ⊂ (t−1, t] ∪ (t, t+1] = zeroWindow(t−1) ∪ zeroWindow(t). Each card ≤ C0hat(t) and C0hat(t+1) resp. (ZeroCountProp at t−1 gives ≤ C0hat(t); at t gives ≤ C0hat(t+1)). So Σ_near m ≤ C0hat(t) + C0hat(t+1) ≤ 2·C0hat(t+1)... but D-056 claims ≤ C₀(t) ≤ C0hat(t)!? Hmm — D-056's C₀(t) is DEFINED as the honest unit-interval count majorant F(t+1)−F(t) + S_b(t+1) + S_b(t), i.e., it ALREADY includes two window contributions (the F-difference plus two S_b slacks) — it's the count for the DOUBLE window (t, t+1] plus slacks, and |γ−t|<1 needs... hmm wait. Actually D-036's C₀(t) counts zeros in |γ−t| ≤ 1 (the unit-neighborhood count, not the unit-interval count). The Lean ZeroCountProp encodes C0hat (t+1) as the bound for zeroWindow t — what window exactly? Let me check LiContour.lean's zeroWindow def. Whatever the exact form, the tight 5f needs the mult-count of nearZeros t ≤ something like 2·C0hat(t+2) and then the assembly constant folds as 13.73·(count bound) + 7.97 ≤ 10.5·log(|t|+2) + 48. The exact constant bookkeeping will need care: D-056's "C₀(t)" must map to the Lean-available count. Hmm wait — actually, hold on. Is the ZeroCountProp's zeroWindow mult-weighted? "Nat.card (zeroWindow t)" — if zeroWindow is a SET of zeros (subtype), the card is NOT mult-weighted. But D-036's count F(t+1)−F(t)+S_b... counts WITH multiplicity (N(T) counts with multiplicity). For the near sum Σ m_ρ/(s₀−ρ) we need the mult-weighted count. If zeroWindow is a set (not multiset), Nat.card undercounts multiplicities. Hmm — but in LiCircleBound there are mult-weighted bridges from ZeroCountProp? The count bridges there were from Zeta23's RvM count (A0count, unconditional). Let me check: does LiContour/LiCircleBound have a mult-weighted window count from ZeroCountProp? `nearZeros_count_le` (session 033) is ≤ 3·A₀·log(...) — unconditional (A0count). For 5f we need the TIGHT count from ZeroCountProp — is there a mult-weighted version? Let me look at zeroWindow's definition and whether multiplicity matters. Key question: is zeroWindow t a finset/set of zeros with Nat.card, and if so how does the mult-weight enter? In D-062 §4 the perimeter was declared as "Trudgian N(T)/S(T) in Ĉ₀ form" — the ZeroCountProp def: ∀ t ≥ 2, (Nat.card (zeroWindow t) : ℝ) ≤ C0hat (t+1). If zeroWindow is the SET of zeros (subtype elements) in the window, multiplicities are NOT counted. Then Σ_{ρ ∈ window} m_ρ could exceed card if some zero is multiple. BUT: zeroMult ρ ≥ 1, and Σ m_ρ = card only if all simple. Hmm — is there a multiplicity-vs-card bridge? In LiDisc there's the analyticOrderNatAt machinery (multiplicity = order). For the SET of zeros with multiplicities, Σ_{ρ ∈ S} m_ρ = Nat.card of the multiset... Wait — actually, let me reconsider. Zeta23's zero_sum_inv_sq — is that mult-weighted? From ii′-1a: "Zeta23 zero_sum_inv_sq comparison" with the mult-weighted dominator (9/2)n²·mult/(1+‖γ‖²) — so liSummable handles mult via zero_sum_inv_sq which sums over the subtype with zeroMult weights? Let me check Zeta23's zero_sum_inv_sq statement — if it's Σ_ρ (mult ρ)/(1+γ²) < ∞ over the subtype, then... hmm. For the tight count, maybe the cleanest: Σ_{ρ ∈ nearZeros t} zeroMult ρ ≤ C0hat-something requires a mult-weighted window count from the perimeter. If the perimeter only gives plain card bounds, we need a mult bridge: Σ m_ρ over a window ≤ mult-weighted count... The honest Trudgian N(T) DOES count with multiplicity, so the intended perimeter semantic is mult-weighted. Let me check the actual zeroWindow definition in LiContour.lean — maybe zeroWindow t is defined as a multiset or with multiplicity baked in. Let me read. Also need to see how the D-062 perimeter was declared in the paper: "Trudgian N(T)/S(T)" — N(T) counts with multiplicity. Let me read LiContour.lean's ZeroCountProp region. Also piece 3 (far difference) needs the two-sided interval counts with multiplicity — D-056's grouping by unit intervals uses C₀(t) (the mult-weighted unit-neighborhood count) for the left side (k intervals below t), C₀(2t) for the right side, and the k > t tail. In Lean this becomes a sum over dyadic/unit intervals of the mult-weighted count — again needs the mult-weighted window count from ZeroCountProp. So the CRITICAL first question: what mult-weighted count machinery exists from ZeroCountProp? Let me look at LiContour.lean (zeroWindow def) and LiCircleBound.lean's count bridges (A0count was the unconditional one; is there a ZeroCountProp-fed bridge? gapCircle construction used ZeroCountProp via zeroWindow_finite + C0hat — the exists_gapCircle_radius proof used "the perimeter ZeroCountProp on the two unit windows" per D-068 §2. Let me read LiGapCircles to see how the count was used — that shows the available bridge. Let me read: 1. LiContour.lean ZeroCountProp + zeroWindow definitions. 2. LiGapCircles.lean exists_gapCircle_radius's use of ZeroCountProp (how card → C0hat was applied). 3. LiCircleBound's nearZeros def + nearZeros_count_le. 4. dirichletC2 def (piece 1 constant).
D-056 read. Now the Lean-side count machinery — critical question: how `ZeroCountProp` feeds mult-weighted window counts. Checking LiContour (ZeroCountProp/zeroWindow defs), LiGapCircles (how the perimeter count is consumed), and LiCircleBound (nearZeros + dirichletC2).
tool: Bash
input
{
  "command": "cd D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1; sed -n '40,80p' LiContour.lean; echo ===GAP-USE===; grep -n \"hZC\\|ZeroCountProp\\|zeroWindow\\|C0hat\" LiGapCircles.lean | head -25",
  "description": "Read ZeroCountProp, zeroWindow, and gap-circle count usage"
}
#1697 assistant 2026-08-24 06:42:18.009 UTC · 5280→3709 tok open ⤢
thinking (12948 chars)
Key finding: **`ZeroCountProp` counts the SET-card of zeroWindow — NOT mult-weighted.** `zeroWindow a := {ρ | IsNontrivialZero ρ ∧ a ≤ ρ.im ∧ ρ.im ≤ a+1}` and `Nat.card (zeroWindow t)`. So the perimeter gives plain (unweighted) window counts. For the mult-weighted near sum Σ m_ρ/(s−ρ), we need Σ_{ρ ∈ window} zeroMult ρ ≤ (mult-weighted count). Is there a bridge from unweighted card to mult-weighted? Hmm — actually, wait. Is there? In LiDisc/LiCircleBound, the mult-weighted counts came from Zeta23's RvM `zeta_local_zero_count` (A0count) — mult-weighted, unconditional. The `nearZeros_count_le` (session 033) gives near-window mult-count ≤ 3·A₀·log(3·max|t−1||t+1|+5) — UNCONDITIONAL but with the A0count constant (loose, ~3·A₀ vs tight C0hat). For the TIGHT bound 13.73·C₀(t) + 7.97 ≤ 10.5 log + 48 we need the count to be C0hat-shaped (0.433 log + 0.886 loglog + 2.9), not 3·A₀·log. A₀ is the RvM constant — probably something like 5 or larger (loose). If we used the unconditional mult-count, the folded constants would be much bigger than 10.5/48 and the margin (already computed with 10.5/48 baked in) would break. So the question: **how do we get mult-weighted counts from the unweighted perimeter?** Options: (a) The multiplicity: Σ_{ρ ∈ W} zeroMult ρ vs Nat.card W. Since zeroMult ρ ≥ 1 for zeros, Σ ≥ card, wrong direction. We need Σ ≤ C·card-ish — no, multiplicities can be arbitrarily large a priori... BUT: the mult-weighted count IS what Trudgian's N(T) bounds. The declared perimeter semantic (D-062 §4: "Trudgian N(T)/S(T)") counts WITH multiplicity. The Lean ZeroCountProp as encoded uses Nat.card of the SET — which undercounts multiplicities! Hmm wait — is that a perimeter-encoding issue like the liCoeff defect? Let me think. For N(T)-style counts, the mult-weighted window count = N(t+1)−N(t) + O(log t) counts with multiplicity. If ZeroCountProp only bounds the SET card, then Σ_{ρ ∈ W} m_ρ could exceed C0hat(t+1) if there are multiple zeros. But hold on — can multiplicities be bounded by the set-card of a slightly bigger window? No local argument gives that... Actually there IS a standard trick: the multiplicity of a zero ρ is bounded by the count in a small neighborhood... no, that gives m_ρ ≤ count(ball) which is still ≥ m_ρ. Circular. Hmm, wait. Let me reconsider. Does 5f actually NEED the mult-weighted count? The near sum in R(s): Σ_{|γ−t|<1} m_ρ/(s−ρ) — this comes from the partial-fraction identity's series which IS mult-weighted (seriesFun uses zeroMult). So yes, the R-bound's near sum is mult-weighted, and D-056's C₀(t) bounds the mult-weighted count (Trudgian N(T) is mult-weighted). So there's a genuine mismatch: ZeroCountProp (as encoded) bounds the UNWEIGHTED card. UNLESS: zeroMult can be folded into the card via... hmm. Wait — let me check how LiCircleBound's capstones used nearZeros + ZeroCountProp... no, they used A0count (unconditional) for mult-weighted counts, and ZeroCountProp only via exists_gapCircle_radius (which only needs the unweighted card for the pigeonhole). So for 5f we need either: (a) A mult-weighted window count from ZeroCountProp + something else; or (b) Reformulate the perimeter: strengthen ZeroCountProp to the mult-weighted form. But ZeroCountProp is part of the DECLARED PERIMETER (D-062 §4) — changing its statement changes the trusted input. Is the mult-weighted form the honest Trudgian content? YES — Trudgian's N(T) counts with multiplicity. The set-card form is actually the WEAKER (less honest) encoding. D-062 §4 declared "Trudgian N(T)/S(T)" — the mult-weighted window count IS the Trudgian content. The set-card encoding under-declares. Hmm wait, actually — is that right? Let me think again. N(T) = #{ρ : 0 < γ ≤ T} counted WITH multiplicity. Trudgian's bound |N(T) − F(T)| ≤ S_b(T) is for the mult-weighted count. So the window count (mult-weighted) ≤ F(t+1)−F(t) + S_b(t+1) + S_b(t) ≤ C0hat-ish. The SET-card ≤ mult-weighted count always (m ≥ 1). So ZeroCountProp as encoded (set card ≤ C0hat) is IMPLIED BY the mult-weighted Trudgian bound. It's a true, weaker statement. But it's NOT sufficient for the mult-weighted near sum. Can we derive the mult-weighted window bound from the set-card version + other proved facts? In general no — you'd need to know multiplicities are bounded, which requires... hmm, actually there IS a way: the mult-weighted count in window W equals the set-card of W "with multiplicity" — alternatively, Σ_{ρ∈W} m_ρ = ∫... no. Hmm, hold on. Actually, is there a bridge via A0count RATIO? No — A₀ is loose. Alternative: bound the multiplicities directly. m_ρ ≤ C·log|γ| (standard: multiplicity at height T is O(log T)) — provable from Jensen (LiDisc machinery!). Indeed, in LiDisc, scaledZeta_jensen_count gives the mult-weighted count in a DISC ≤ log((9/4)|t|²)/log(33/32) — the Jensen count IS mult-weighted (ZerosBound with analyticOrderNatAt multiplicities). So mult-weighted window counts ARE available unconditionally via Jensen/A0count — but with loose constants. The tight Trudgian constants need the mult-weighted perimeter. So the honest fix: **strengthen ZeroCountProp to the mult-weighted form** — it's the same declared literature input (Trudgian 2014 N(T)/S(T) IS mult-weighted), just encoded correctly. This parallels the ii′-1a liCoeff defect: the encoding didn't match the intended mathematical content, and the fix is to the ENCODING (declaration), not new mathematics. But wait — the freeze protocol: "no edits to existing Lean proofs except the liCoeff correctness fix". Changing ZeroCountProp's statement is a freeze-sensitive edit. Hmm. But it's the PERIMETER declaration — the point of the perimeter is to declare the trusted computational/literature inputs. The question is whether the mult-weighted form is what's consumed downstream and whether it changes the audit surface. Actually — hold on. Let me first check whether the mult-weight is really needed, or whether the 5f near sum can be handled unweighted. The near sum Σ_{|γ−t|<1} m_ρ/(s−ρ): bound ≤ Σ m_ρ (since |s−ρ| ≥ 1). If multiplicities... in the paper R-004 world, the sum over |γ−t|<1 of 1/(s−ρ) is over zeros "counted with multiplicity" (standard convention Σ_ρ ranges over the multiset). D-056's C₀(t) is mult-weighted. Alternatively — could 5f's near sum be restructured to the unweighted sum? The series in partialFraction_identity is mult-weighted (zeroMult), intrinsically. The near part of the difference R(s) inherits that. No way around mult-weighting for the identity-based R-bound. OK here's the thing though. Let me check whether Zeta23 or our LiDisc has a MULT-WEIGHTED window count bound with TIGHT-ish constants that could feed 5f WITHOUT changing the perimeter... The RvM count A0count: what is its value? Let me check the magnitude. A0count is Classical.choose of zeta_local_zero_count — an existential, symbolic. The folded constant would be 13.73·(A₀-shaped bound) which blows past 48. So no. So the options for 5f: (A) Strengthen ZeroCountProp to mult-weighted (freeze-sensitive but correct-honest; needs user sign-off? It's within the declared perimeter content — Trudgian N(T) is mult-weighted — so the change makes the declaration match the declared source. I should flag this to the user.) (B) Prove mult-weighted ≤ C₀ · set-card... impossible locally. (C) Keep ZeroCountProp and DERIVE the mult-weighted window bound from it + a multiplicity bound. Multiplicity bound: m_ρ for ρ in window W is at most the mult-weighted count in a slightly bigger window... circular without a mult-weighted input. Hmm wait — actually, hmm, is there an unconditional bridge: m_ρ ≤ (set-card of a tiny window around ρ)? No: a double zero is one set element with m=2; tiny window card = 1 but m = 2. No. What about deriving mult-weighted counts from the mult-weighted DISC count (Jensen, LiDisc — unconditional) intersected smartly? The Jensen count at radius r around 2+it: Σ_{disc} m ≤ log((9/4)t²)/log(33/32) ≈ 66·log t. That's the A₀-flavored loose count — the folded R-bound would be ~13.73·66·log t ≈ 900·log t, way over 10.5. The margin was computed with 10.5/48 baked in; a 900 log t R-bound would need margin recomputation — the whole R-004 assembly constants change. NOT acceptable for 5f (the point of 5f is the tight constants). So the honest path is (A): the perimeter's ZeroCountProp should be the mult-weighted form. This is a DECLARATION correction (matching the declared Trudgian source), exactly parallel to ii′-1a's liCoeff encoding fix (which was freeze-excepted by the user directive). Wait wait wait. Hold on. Let me re-examine. Maybe I'm wrong about ZeroCountProp being unweighted-in-effect. Let me look at how the mult enters the WINDOW count more carefully. zeroWindow t is a SET of ℂ (the zeros themselves, with IsNontrivialZero predicate). Nat.card of the set = number of DISTINCT zeros. Multiple zero = 1 element. So yes, unweighted. Hmm, but actually — let me reconsider the actual near-sum structure in LiDisc. In LiDisc, `nearZeros t` — let me check its definition. It's probably a FINSET of the subtype {ρ // IsNontrivialZero ρ} with zeroMult weights in the sum. The LiDisc capstone: ‖logDeriv ζ s − Σ_{ρ ∈ nearZeros t} (zeroMult ρ)/(s−ρ)‖ ≤ 100000·(log|t|)². And `nearZeros_count_le`: Σ_{ρ ∈ nearZeros t} zeroMult ρ ≤ 3·A₀·log(...) — mult-weighted via A0count (unconditional). So for 5f's tight near count Σ_{nearZeros t} m_ρ ≤ C₀(t)-ish, we need mult-weighted window input. Now, is there possibly a clean derivation of the mult-weighted TIGHT window count from ZeroCountProp (unweighted) + the LOOSE mult-weighted count? NO — the loose count doesn't imply the tight one. Hmm, unless... the multiplicities sum over a window can be related to set-cards of the window at multiple "levels"? No. OK so decision: 5f needs a mult-weighted perimeter count. Options: (A-i) CHANGE ZeroCountProp to the mult-weighted form: ∀ t ≥ 2, Σ_{ρ ∈ zeroWindow-finset} zeroMult ρ ≤ C0hat(t+1). This matches Trudgian N(T) exactly (mult-weighted window count). Downstream consumers: exists_gapCircle_radius (uses the card for the pigeonhole — mult-weighted bound implies unweighted card bound since card ≤ Σ m — so it still works, via Σ m ≤ C0hat and card ≤ Σ m... wait need card ≤ Σ m: each m_ρ ≥ 1 ⟹ card ≤ Σ m ✓ so the unweighted card bound FOLLOWS from the mult-weighted one — exists_gapCircle_radius's proof would need a small adaptation: card ≤ Σ m ≤ C0hat ✓). (A-ii) ADD a second perimeter hypothesis ZeroCountPropMult, keeping ZeroCountProp. More additive, less disruptive to freeze; but grows the declared perimeter surface by one item — actually it SHOULDN'T grow the audit surface: it's the same Trudgian input. Which is better? The freeze protocol says no edits to existing Lean proofs except ii′-1a — but that was about PROOFS; the perimeter declarations are the trusted-input surface and D-062 §4 explicitly designs the perimeter. Changing ZeroCountProp's statement is a design decision affecting the paper's appendix declaration. This is exactly the kind of thing to flag + decide carefully, and per §8.4a/fork rules and the general "ask before risky" — I should consult the user? Hmm — actually, wait. Let me first double-check that 5f truly needs the mult-weighted form, by checking what ii′-6 (the actual consumer) needs. The margin/Bn were computed with the R-bound 10.5 log + 48 where the near sum is mult-weighted (D-056 convention). So yes. Hmm, hold on, let me reconsider once more whether multiplicity can be avoided entirely. Alternative approach to the R-bound without mult-weighting: bound Σ_{nearZeros} m_ρ/(s−ρ) by (max mult) × (unweighted harmonic sum)? No bound on max mult. OK here's yet another thought — is the multiplicity of nontrivial zeros ACTUALLY bounded by something we can prove tightly? m_ρ ≤ A₀·log-ish via Jensen (LiDisc): m_ρ ≤ count in unit disc ≤ 66 log t — loose. So: 5f requires the mult-weighted window count ≤ C0hat-shaped bound. The Trudgian declaration IS mult-weighted mathematically. The current ZeroCountProp encoding captures only the set-card. **This is a second perimeter-encoding defect** (parallel to the ii′-1a liCoeff defect — encoding weaker than the declared literature content). The repair: strengthen ZeroCountProp to the mult-weighted form, which (i) matches the declared Trudgian N(T)/S(T) input, (ii) still serves the gap-circle pigeonhole (card ≤ Σ m), (iii) enables 5f. Per the freeze protocol and the significance of touching a PERIMETER declaration, I should present this to the user before implementing. Actually — let me first verify the claim that the set-card form is what's encoded, and check precisely how exists_gapCircle_radius consumes it, and whether there's any existing mult-weighted ZeroCountProp variant elsewhere in the package. Also check the D-062 §4 perimeter doc to see the declared form (maybe D-062 already specifies mult-weighted and the Lean encoding drifted). Let me read D-062 §4.
Key discovery: `ZeroCountProp` is encoded with `Nat.card (zeroWindow t)` — the **unweighted set-card**. But 5f's near sum is **mult-weighted** (Σ m_ρ/(s−ρ) from `seriesFun`'s `zeroMult`), and D-056's C₀(t) is the mult-weighted Trudgian count. Let me check the D-062 §4 perimeter declaration to see the intended form before concluding.
tool: Bash
input
{
  "command": "grep -n \"mult\\|multiplicity\\|ZeroCountProp\\|zeroWindow\" D:/Python/Quantum/research/derivations/D-062*.md | head -20; echo ===; grep -n \"nearZeros\" D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1/LiDisc.lean | head -8; echo ===; grep -n \"def nearZeros\\|nearZeros_count_le\" D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1/*.lean | head -6",
  "description": "Check D-062 perimeter form and nearZeros definitions"
}
#1698 assistant 2026-08-24 06:45:05.117 UTC · 1400→2566 tok open ⤢
thinking (8792 chars)
D-062 §4 says "Trudgian 2014's explicit N(T)/S(T) bounds go INSIDE the trusted perimeter". Trudgian's N(T) counts zeros **with multiplicity** (standard). So the mult-weighted window count IS the declared perimeter content — the current `ZeroCountProp` encoding (set-card) under-encodes it. Hmm, wait. Actually, let me think about whether the set-card form vs mult-weighted form really differ in the Trudgian content. Trudgian 2014: |N(T) − F(T)| ≤ S_b(T) for T ≥ e, where N(T) = #{ρ = β+iγ : 0 < γ ≤ T} counted with multiplicity (if a zero has multiplicity m, it contributes m). So the mult-weighted window count Σ_{ρ: t<γ≤t+1} m_ρ = N(t+1) − N(t) ≤ F(t+1) − F(t) + S_b(t+1) + S_b(t) ≤ C0hat-ish. The set-card of the window ≤ the mult-weighted count. So: - Declared source: Trudgian N(T)/S(T) — mult-weighted. - Encoded ZeroCountProp: set-card — WEAKER (implied by the source). - 5f needs: mult-weighted — the FULL source content. So the fix is to strengthen ZeroCountProp to the mult-weighted form, which is exactly the declared Trudgian input. This is a legitimate perimeter-encoding repair (like ii′-1a). But it touches a declaration used by exists_gapCircle_radius (which would need the card ≤ Σ m bridge). Actually — wait. Before proposing a change to the perimeter, let me double-check whether the mult-weighted window count can be DERIVED from things already proved + ZeroCountProp as-is. The mult-weighted window count Σ_{ρ∈W} m_ρ... Hmm, is there any way? In LiDisc, the Jensen count is mult-weighted over a DISC — could we bound the window mult-count by a JENSEN count with the right constants? The Jensen count bound was log((9/4)|t|²)/log(33/32) ≈ 66 log t — far looser than C0hat ≈ 0.433 log t + ... The fold 13.73·(66 log t) breaks the 10.5 coefficient by ~100×. The margin B(n) was computed with the 10.5/48 constants; the leading coefficient of the √n log n term is 4·(0.1443 + 10.5/2) ≈ 21.6 (D-056 §3). If the R-bound's A became ~900, the margin would go NEGATIVE — R-004 would collapse. So no: 5f genuinely needs the tight mult-weighted count, which is only available from the perimeter. Alternatively — hmm, one more thought — could the R-bound's near sum be bounded via the UNWEIGHTED count + a multiplicity bound? mult(ρ) ≤ C₀(t)-ish? No tight unconditional multiplicity bound exists either (multiplicity at height T is O(log T) via Jensen — same looseness). So the decision point: strengthen ZeroCountProp to the mult-weighted form. Options: (A) Edit ZeroCountProp in LiContour.lean: ```lean def ZeroCountProp : Prop := ∀ t : ℝ, 2 ≤ t → ((zeroWindow_finite t).toFinset.sum (fun ρ => zeroMult ρ) : ℝ) ≤ C0hat (t + 1) ``` Then exists_gapCircle_radius needs the bridge: W.card ≤ Σ zeroMult ≤ C0hat (since 1 ≤ zeroMult ρ for each zero: zeroMult ρ = analyticOrderNatAt... is 1 ≤ zeroMult ρ for IsNontrivialZero ρ already proved? In LiSeries/LiContour — zeroMult is defined as the order (nat) of the zero; for a zero it's ≥ 1. There should be a lemma `one_le_zeroMult` — used in ii′-1a/5c. Let me check.) (B) Add a second def ZeroCountPropMult and have 5f take both. This grows the declared perimeter from 4 items to 5 — and the paper's appendix declaration lists "Trudgian 2014 (published explicit bounds)" as one item. (A) keeps it as one item with the correct (stronger, source-faithful) content. (A) is cleaner and honest: the declared source (Trudgian N(T)) IS mult-weighted; the encoding should match. But it's a freeze-sensitive edit to a perimeter declaration — exactly the kind of thing the freeze protocol covers ("no edits to existing Lean proofs except the liCoeff correctness fix"). Editing ZeroCountProp's statement requires touching exists_gapCircle_radius's proof (a card→Σm bridge lemma + adapting three hW-card steps). Per the project's careful-governance norms (perimeter = trusted surface; freeze protocol in force; this is exactly a "fork/decision" moment), I should surface this to the user with a crisp recommendation BEFORE editing. Actually — the user directive for tier ii′ said "option (a) — close SfBoundProp in Lean BEFORE submission" and the freeze has the ii′-1a exception for encoding defects. This is arguably the same CLASS: a perimeter encoding defect discovered at the point of consumption. The ii′-1a precedent: the user was informed via the design doc (D-064) and the fix was folded into the plan as ii′-1a. Given the significance, let me use AskUserQuestion to confirm the approach. Options: 1. Strengthen ZeroCountProp to mult-weighted (recommended — matches declared Trudgian source; one-line card≤Σm bridge fixes the gap-circle consumer). 2. Add ZeroCountPropMult as a second perimeter hypothesis (keeps existing decl untouched; grows perimeter surface). 3. Don't touch the perimeter; investigate deriving the mult-count another way (I'm confident it's impossible with tight constants, but could spend time confirming). Actually, wait. Before asking, let me double-check the claim that 5f really needs the mult-weighted NEAR count, by looking at how ii′-6 will consume the R-bound. Let me check what shape the R-bound takes in LiSkeleton's Bn/margin — is the near sum even present in the assembled contour estimate? In D-037, the contour integrals bound |ζ′/ζ| by (near sum + R-bound): the sides of the rectangle. The near sum Σ m/(s−ρ) on the zero-avoiding contour |s−ρ| ≥ c/log... uses the mult-weighted count. So yes, both the R-bound AND the near-sum-on-contour bounds are mult-weighted. And L3's pigeonhole (ii′-4, exists_zero_avoiding_T) used ZeroCountProp's card — for the CONTOUR avoidance, the number of candidate midpoints must exceed the number of zeros (set-card suffices for avoidance? avoidance: each zero disqualifies intervals... with multiplicity m, a zero's excluded set is the same regardless of m — avoidance uses the SET of ordinates, so set-card is right there ✓). But the near-sum bound on the contour IS mult-weighted (Σ m/|s−ρ| ≤ m-total/(clearance)). Hmm wait — did ii′-4's L3 or the contour bound use a mult-weighted count anywhere already? `sum_zeroMult_le_of_im_band` (session 032, LiCircleBound): "band [a,b] + sign-separation c ⟹ 3·A₀·(b−a+2)·log(3·max|a||b|+5)" — that's A₀-based (unconditional). So all existing mult-weighted counts use A₀ (loose). 5f is the first place needing the TIGHT mult-weighted count. And ii′-6's assembly will need the tight mult-weighted count too (for the near-sum on the contour: D-037's I_II bounds). Actually wait — will it? D-037's assembly: the sides bound |ζ′/ζ(s)| ≤ (near sum) + |R| where near sum ≤ C₀(T)·(1/clearance)-ish. Yes, mult-weighted tight count needed in ii′-6 too. So the mult-weighted perimeter is unavoidable for the whole 5f→ii′-6 arc. Hmm, actually hold on — let me reconsider. In ii′-4, L1's kernel bounds and L3's zero-avoiding T were built with ZeroCountProp (unweighted card). If ii′-6's contour assembly needs the mult-weighted count, then this encoding question would have surfaced in the D-062/D-064 designs... D-064 §4 R3 says "R-bound (D-056, A = 10.5, B₀ = 48) via LOCAL route" and D-062 lists L0–L3 layers. Did any design doc flag the mult-vs-card issue? The D-068 §6 preview says "near sum ≤ C₀(t) (perimeter ZeroCountProp — FIRST use of the perimeter in the R-chain...)" — it assumed ZeroCountProp directly gives the mult-weighted C₀(t) bound. So the design DID intend ZeroCountProp to serve the mult-weighted near sum — the encoding (set-card) doesn't match the design intent. This strengthens the case that the ZeroCountProp encoding should be mult-weighted (matching both the Trudgian source AND the design intent), and the set-card form was an under-encoding oversight (not caught until now because gap-circle pigeonhole only needs card, and card ≤ Σm... wait — actually the gap-circle proof uses hZC to bound W.card where W = zeroWindow's finset: with the mult form, card ≤ Σ zeroMult ≤ C0hat — a tiny bridge). So the repair is a genuine encoding defect fix of the ii′-1a class. Given its freeze-sensitivity (perimeter declaration edit), I'll present it to the user with the analysis and options. Actually — the user's standing directive for tier ii′ is to CLOSE SfBoundProp; the freeze's purpose is protecting paper/proof integrity, and the freeze already has the encoding-fix exception precedent (ii′-1a was created exactly for the liCoeff encoding defect). This new defect is the same class and BLOCKS the mandated work. The cleanest is option (A). But the freeze protocol says the ONLY exception is ii′-1a. A second encoding fix is a plan change — the user should decide. Per §4A/§8.4a norms and "executing actions with care", I'll ask. Let me prepare the question with full context. Actually, let me first verify `one_le_zeroMult`-style lemma exists (for the card ≤ Σm bridge), so my options are concrete.
D-062 §4 declares Trudgian's N(T)/S(T) as the perimeter — and Trudgian's N(T) counts zeros **with multiplicity**. But the encoded `ZeroCountProp` uses `Nat.card (zeroWindow t)` (unweighted set-card). 5f's near sum (and ii′-6's contour near sum) are mult-weighted. Let me verify the bridge lemma situation before presenting options.
tool: Bash
input
{
  "command": "cd D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1; grep -rn \"one_le_zeroMult\\|zeroMult_pos\\|1 \u2264 zeroMult\\|zeroMult_nonneg\" *.lean | head -8; echo ===; grep -n \"def zeroMult\" *.lean | head -3",
  "description": "Check zeroMult lower-bound lemmas"
}
#1699 assistant 2026-08-24 06:48:03.148 UTC · 804→1573 tok open ⤢
thinking (2930 chars)
The pattern exists (`one_le_analyticOrderNatAt_scaledZeta` in LiDisc). A `one_le_zeroMult` for IsNontrivialZero is easy: ```lean theorem one_le_zeroMult {ρ : ℂ} (hρ : IsNontrivialZero ρ) : 1 ≤ zeroMult ρ := by have htop := zeta_order_ne_top_of_ne (ρ := ρ) (by ... : ρ ≠ 1) -- re < 1 ⟹ ρ ≠ 1 have hne : analyticOrderAt riemannZeta ρ ≠ 0 := (analyticAt).analyticOrderAt_ne_zero.mpr hρ.1 exact ENat.toNat_pos hne htop ``` Wait zeroMult := (analyticOrderAt riemannZeta ρ).toNat — and analyticOrderNatAt := (analyticOrderAt f z).toNat presumably. ENat.toNat_pos (hne : n ≠ 0) (htop : n ≠ ⊤) : 0 < n.toNat. OK so the bridge is feasible. Now the decision. The situation: **Discovery (5f-blocking, session 035):** `ZeroCountProp` as encoded (LiContour.lean) bounds the UNWEIGHTED set-card `Nat.card (zeroWindow t) ≤ C0hat (t+1)`. But: - The declared perimeter source (Trudgian 2014 N(T)/S(T), D-062 §4) counts zeros WITH multiplicity (N(T) is mult-weighted). - The D-068 §6 design intended ZeroCountProp to serve the mult-weighted near sum ("near sum ≤ C₀(t) (perimeter ZeroCountProp)"). - 5f's R-bound near sum Σ m_ρ/(s−ρ) and ii′-6's contour near sum are mult-weighted (zeroMult in seriesFun). - The gap-circle pigeonhole (exists_gapCircle_radius) only needs the unweighted card, which FOLLOWS from the mult-weighted form (card ≤ Σ m since m ≥ 1). So the encoding should be strengthened to the mult-weighted form — this is the ii′-1a class of repair (encoding weaker than the declared literature content). Options: (A) Strengthen ZeroCountProp in place: `∀ t ≥ 2, (Σ ρ ∈ (zeroWindow_finite t).toFinset, zeroMult ρ : ℝ) ≤ C0hat (t+1)`. Fix exists_gapCircle_radius's three card steps via card ≤ Σ m (needs `one_le_zeroMult` — new 5-line lemma). ~0.5 sub-session. Freeze-sensitive: touches the perimeter declaration + one existing proof (adaptation, not math change). (B) Add a parallel `ZeroCountPropMult` def, leave ZeroCountProp untouched; 5f/ii′-6 consume the mult one. Zero edits to existing code; but TWO perimeter count declarations for ONE declared literature input, and the unweighted one stays as dead weight (still used by gap circles). Slightly larger audit surface. (C) Attempt to derive the mult-weighted tight count from ZeroCountProp + proved results. I'm confident this is impossible (multiplicity is invisible to set-card; the only unconditional mult-weighted counts are Jensen/A₀-based with ~100× looser constants that would collapse the margin). Documenting the impossibility would still leave 5f blocked. Recommendation: (A) — it makes the encoding match the declared source (Trudgian N(T) IS mult-weighted), unblocks 5f and ii′-6, and the consumer repair is mechanical. It's the ii′-1a precedent: encoding defect found at consumption time, fixed at the declaration. This is a plan-level decision (perimeter declaration change under the freeze protocol). I must ask the user. Let me use AskUserQuestion.
The 5f design has hit a genuine blocker that needs your decision. Here's the situation: **Discovery (encoding defect, ii′-1a class):** `ZeroCountProp` (LiContour.lean:60) is encoded as ```lean ∀ t : ℝ, 2 ≤ t → (Nat.card (zeroWindow t) : ℝ) ≤ C0hat (t + 1) ``` — the **unweighted set-card**. But: 1. **The declared perimeter source is mult-weighted.** D-062 §4 puts Trudgian 2014's N(T)/S(T) in the perimeter, and N(T) counts zeros *with multiplicity*. The set-card form is strictly weaker than the declared input. 2. **5f needs the mult-weighted form.** D-056's near sum Σ_{|γ−t|<1} m_ρ/(s−ρ) (zeroMult-weighted, from `seriesFun`) is bounded by C₀(t) — the Trudgian mult-weighted count. The unconditional mult-weighted counts we have (Jensen/A₀, LiDisc) are ~100× looser (≈ 66·log t) and would collapse the R-004 margin (the 10.5/48 constants are baked into `marginTilde`/`Hhat`). 3. **D-068 §6 already assumed** ZeroCountProp would serve the mult-weighted near sum ("near sum ≤ C₀(t) (perimeter ZeroCountProp)"). 4. **The one existing consumer is safe under strengthening:** `exists_gapCircle_radius` uses only the set-card, and card ≤ Σ m_ρ since m_ρ ≥ 1 (a ~5-line `one_le_zeroMult` bridge via the LiDisc `ENat.toNat_pos` pattern). So the encoding under-captures the declared Trudgian input, exactly parallel to the ii′-1a liCoeff defect (found, like that one, at the point of consumption).
tool: AskUserQuestion
input
{
  "questions": [
    {
      "question": "ZeroCountProp is encoded unweighted (Nat.card of the zero set), but the declared Trudgian N(T)/S(T) perimeter is mult-weighted, and 5f/ii\u2032-6 need the mult-weighted window count. How should I repair it?",
      "header": "Perimeter fix",
      "options": [
        {
          "label": "Strengthen in place (Recommended)",
          "description": "Edit ZeroCountProp to the mult-weighted form (\u03a3 zeroMult over the window finset \u2264 C0hat(t+1)) \u2014 matching the declared Trudgian source. Add a one_le_zeroMult lemma and adapt exists_gapCircle_radius's three card steps (card \u2264 \u03a3 m). One perimeter item, source-faithful; small freeze-protocol exception like ii\u2032-1a."
        },
        {
          "label": "Add ZeroCountPropMult alongside",
          "description": "Leave ZeroCountProp untouched; add a second mult-weighted perimeter declaration consumed by 5f/ii\u2032-6. Zero edits to existing proofs, but two count declarations for one declared literature input and a slightly larger audit surface."
        },
        {
          "label": "Investigate derivation first",
          "description": "Spend time confirming whether the tight mult-weighted count can be derived from the unweighted perimeter + proved results before touching any declaration. (My assessment: impossible \u2014 multiplicity is invisible to set-card; only loose Jensen counts are derivable.)"
        }
      ]
    }
  ]
}
#1700 assistant 2026-08-24 07:07:27.029 UTC · 657→1723 tok open ⤢
thinking (4734 chars)
User chose (A): strengthen ZeroCountProp in place. Plan: 1. Add `one_le_zeroMult` lemma (IsNontrivialZero ρ → 1 ≤ zeroMult ρ) — where? LiContour.lean near ZeroCountProp, or LiDisc? zeroMult is Zeta23's def. The lemma needs: analyticOrderAt ζ ρ ≠ 0 (from ζ ρ = 0 + analyticity) and ≠ ⊤ (zeta_order_ne_top_of_ne from LiSides, needs ρ ≠ 1). LiContour imports what? Let me check LiContour's imports — if it doesn't import LiSides, put the lemma where the deps are available. Actually LiContour defines ZeroCountProp and the gap circles; let me check its imports. 2. Edit ZeroCountProp in LiContour.lean to the mult-weighted form: ```lean def ZeroCountProp : Prop := ∀ t : ℝ, 2 ≤ t → (((zeroWindow_finite t).toFinset.sum fun ρ => zeroMult ρ) : ℝ) ≤ C0hat (t + 1) ``` Hmm — the sum over the toFinset of zeroWindow. zeroWindow_finite t : (zeroWindow t).Finite; .toFinset : Finset ℂ. Then Σ ρ ∈ that, (zeroMult ρ : ℕ) — as a ℕ sum then cast, or cast each. Better: `((zeroWindow_finite t).toFinset.sum (fun ρ => zeroMult ρ) : ℝ) ≤ C0hat (t + 1)` — sum in ℕ, cast to ℝ. 3. Adapt exists_gapCircle_radius in LiGapCircles.lean: currently hW1card : (W1.card : ℝ) ≤ C0hat (...) from hZC. With the new form, hZC gives (Σ zeroMult : ℝ) ≤ C0hat; need W.card ≤ Σ zeroMult: Finset.card_le_sum... `Finset.card_le_sum (hs : ∀ i ∈ s, 1 ≤ f i) : s.card ≤ Σ i ∈ s, f i`? There's `Finset.card_le_sum`? Something like that exists: Finset.card_le_sum (hf : ∀ i ∈ s, 1 ≤ f i)? Let me check the exact name: `Finset.card_le_sum` — I believe there's `Finset.card_le_sum (hs : ∀ i ∈ s, 1 ≤ f i) : s.card ≤ ∑ i ∈ s, f i`? Or one can use `Finset.sum_le_sum` with f := 1. Standard: `Finset.card_le_sum` exists in Mathlib as: theorem Finset.card_le_sum (hs : ∀ i ∈ s, 1 ≤ f i) : s.card ≤ ∑ i ∈ s, f i — actually I recall `Finset.card_le_sum` might not exist; there is `Finset.card_nsmul_le_sum`... Let me grep. Alternatively: s.card = Σ i ∈ s, 1 (Finset.card_eq_sum_ones) ≤ Σ zeroMult by Finset.sum_le_sum (fun ρ hρ => one_le_zeroMult ...). The membership: ρ ∈ (zeroWindow_finite t).toFinset → ρ ∈ zeroWindow t → IsNontrivialZero ρ. Set.Finite.mem_toFinset. So: ```lean have hcard_le : W1.card ≤ W1.sum (fun ρ => zeroMult ρ) := by rw [Finset.card_eq_sum_ones] exact Finset.sum_le_sum (fun ρ hρ => one_le_zeroMult ((Set.Finite.mem_toFinset _ _).mp hρ).1) ``` Wait — zeroWindow t := {ρ | IsNontrivialZero ρ ∧ ...}, so membership gives .1 : IsNontrivialZero ρ ✓. Then cast: (W1.card : ℝ) ≤ (W1.sum zeroMult : ℝ) via Nat.cast_le.mpr, then trans with hZC. 4. Then rebuild everything downstream (LiGapCircles → LiCircleBound → LiSqueeze) and fix breakages. 5. Also — importantly — the paper's declaration: freeze protocol says paper files untouched until ii′-7. The perimeter declaration in paperA.tex's appendix says "Trudgian 2014 (published explicit bounds)" — the mult-weighted strengthening matches the declared source, so the paper text remains accurate (N(T) IS mult-weighted). No paper edit needed (and forbidden anyway). At ii′-7 the appendix's Lean-declaration description should match — note this in the journal. 6. Also should record this in D-064's lineage — the encoding-defect log. D-064 documented the liCoeff defect. This is a second encoding defect found in session 035. The journal + NGUYEN checklist entry should note it. Where to put one_le_zeroMult? It needs: - zeroMult def (Zeta23.Statement, open via Zeta23 namespace? In our files zeroMult is used unqualified — open Zeta23). - zeta_order_ne_top_of_ne (LiSides, line 121): {ρ : ℂ} (hρ : ρ ≠ 1) : analyticOrderAt riemannZeta ρ ≠ ⊤. - analyticity of riemannZeta at ρ (ρ ≠ 1: riemannZeta is analytic off 1 — Mathlib: analyticAt_riemannZeta? There should be `analyticAt_riemannZeta` or via differentiability. In LiSides, zeta_order_ne_top_of_ne used analyticity. Let me look at how LiDisc's one_le_analyticOrderNatAt_scaledZeta does it: `han : AnalyticAt ℂ (scaledZeta t) w`, `hne : analyticOrderAt (scaledZeta t) w ≠ 0 := han.analyticOrderAt_ne_zero.mpr hw0`. AnalyticAt.analyticOrderAt_ne_zero : AnalyticAt 𝕜 f z → (analyticOrderAt f z = 0 ↔ f z ≠ 0)? .mpr hw0 with hw0 : f w = 0 gives analyticOrderAt ≠ 0 ✓. - For riemannZeta at a nontrivial zero ρ: analytic — Mathlib name? `analyticAt_riemannZeta`? grep. There's `differentiableAt_riemannZeta` maybe. LiSides line ~121 area proves zeta_order_ne_top_of_ne — let me read it to copy the analyticity step. LiContour imports: let me check. If LiContour doesn't import LiSides, I'll place one_le_zeroMult in LiContour only if deps are there; otherwise place it in LiGapCircles (which imports LiContour + ?). Actually simplest: place it right before its use in LiGapCircles.lean, or in LiContour if deps allow. Let me check both files' imports.
User approved option (A) — strengthen in place. Executing: `one_le_zeroMult` bridge lemma + mult-weighted `ZeroCountProp` + gap-circle consumer adaptation.
tool: TodoWrite ok
input
{
  "todos": [
    {
      "content": "Read D-056 + D-068 \u00a76 + nearZeros/Hhat Lean context",
      "status": "completed",
      "activeForm": "Reading D-056 and Lean context"
    },
    {
      "content": "Perimeter repair: one_le_zeroMult + mult-weighted ZeroCountProp + gap-circle adaptation",
      "status": "in_progress",
      "activeForm": "Repairing ZeroCountProp encoding (user-approved)"
    },
    {
      "content": "Rebuild downstream (LiGapCircles \u2192 LiCircleBound \u2192 LiSqueeze) green",
      "status": "pending",
      "activeForm": "Rebuilding downstream"
    },
    {
      "content": "Design 5f statement + proof decomposition (D-069)",
      "status": "pending",
      "activeForm": "Designing 5f"
    },
    {
      "content": "Build 5f pieces in Lean",
      "status": "pending",
      "activeForm": "Building 5f"
    },
    {
      "content": "Build green + axiom audit + commit + journal/STATE/NGUYEN/db",
      "status": "pending",
      "activeForm": "Closing session 035"
    }
  ]
}
result 2026-08-24 07:07:27Z → 2026-08-26 18:10:59Z
{
  "oldTodos": [
    "content='6-c-ii: I_III left-vertical bound vIntegral_Jlag_left_norm_le' status='completed' active_form='Proving 6-c-ii I_III left-vertical bound'",
    "content='6-c-iii: I_I right-vertical bound (F-E form)' status='in_progress' active_form='Proving 6-c-iii I_I bound'",
    "content='6-c-iv: mid-horizontal segment machine' status='pending' active_form='Proving 6-c-iv mid-horizontal machine'",
    "content='6-c-v: horizontal assembly (mid + DL-5 tails)' status='pending' active_form='Assembling 6-c-v horizontal bound'",
    "content='6-d: fold \u27f9 sfBoundProp (then commit, update archive)' status='pending' active_form='Proving 6-d fold to sfBoundProp'"
  ],
  "newTodos": [
    "content='6-c-ii: I_III left-vertical bound vIntegral_Jlag_left_norm_le' status='completed' active_form='Proving 6-c-ii I_III left-vertical bound'",
    "content='6-c-iii: I_I right-vertical bound (F-E form)' status='completed' active_form='Proving 6-c-iii I_I bound'",
    "content='6-c-iv: mid-horizontal segment machine' status='in_progress' active_form='Proving 6-c-iv mid-horizontal machine'",
    "content='6-c-v: horizontal assembly (mid + DL-5 tails)' status='pending' active_form='Assembling 6-c-v horizontal bound'",
    "content='6-d: fold \u27f9 sfBoundProp (then commit, update archive)' status='pending' active_form='Proving 6-d fold to sfBoundProp'"
  ],
  "cleared": false
}
#1701 assistant 2026-08-24 07:09:13.769 UTC · 778→2753 tok open ⤢
thinking (7904 chars)
LiContour imports LiSides — so `zeta_order_ne_top_of_ne` is available in LiContour. And `analyticAt_riemannZeta (hρ : ρ ≠ 1)` exists (used at LiSides line ~131). So `one_le_zeroMult` can go in LiContour right before ZeroCountProp: ```lean /-- A nontrivial zero has multiplicity ≥ 1. -/ theorem one_le_zeroMult {ρ : ℂ} (hρ : IsNontrivialZero ρ) : 1 ≤ zeroMult ρ := by have hρ1 : ρ ≠ 1 := by intro h rw [h] at hρ -- IsNontrivialZero 1: re 1 < 1 false exact (lt_irrefl (1 : ℝ)) (by ... ) ``` hmm — IsNontrivialZero ρ gives ρ.re < 1; if ρ = 1 then ρ.re = 1: 1 < 1 false. `IsNontrivialZero (1:ℂ)`: (1:ℂ).re = 1 (Complex.one_re). So: ```lean have hρ1 : ρ ≠ 1 := by rintro rfl have := hρ.2.2 -- (1:ℂ).re < 1 rw [Complex.one_re] at this exact lt_irrefl _ this have htop := zeta_order_ne_top_of_ne hρ1 have hne : analyticOrderAt riemannZeta ρ ≠ 0 := (analyticAt_riemannZeta hρ1).analyticOrderAt_ne_zero.mpr hρ.1 exact ENat.toNat_pos hne htop ``` Wait — zeroMult ρ := (analyticOrderAt riemannZeta ρ).toNat. ENat.toNat_pos (hne : n ≠ 0) (htop : n ≠ ⊤)? Check the signature: in LiDisc line 453: `ENat.toNat_pos hne htop : 0 < (analyticOrderAt ...).toNat` — wait actually the usage at line 445-455: `have h := ENat.toNat_pos hne htop` then `exact h` where goal `1 ≤ analyticOrderNatAt (scaledZeta t) w`. analyticOrderNatAt f z := (analyticOrderAt f z).toNat presumably. So ENat.toNat_pos : n ≠ 0 → n ≠ ⊤ → 0 < n.toNat. Goal 1 ≤ zeroMult ρ: unfold zeroMult → 1 ≤ (analyticOrderAt riemannZeta ρ).toNat ↔ 0 < ...toNat. ENat.toNat_pos hne htop : 0 < ...toNat — the goal 1 ≤ X vs 0 < X for ℕ: exact h works? 0 < n ↔ 1 ≤ n for ℕ — defeq? In Lean, Nat.lt is defined as n+1 ≤ m: 0 < X is 0+1 ≤ X = 1 ≤ X — is `0 + 1 ≤ X` syntactically `1 ≤ X`? Nat.lt n m := n+1 ≤ m, so 0 < X is 0+1 ≤ X; 0+1 reduces to 1 definitionally. `exact h` should work (defeq). In LiDisc they did `have h := ENat.toNat_pos hne htop; exact h` with goal `1 ≤ analyticOrderNatAt ...` — wait that goal shows `1 ≤ analyticOrderNatAt (scaledZeta t) w` and analyticOrderNatAt is a def for (analyticOrderAt ...).toNat? If analyticOrderNatAt is a def, exact h needs defeq through the def — worked in LiDisc ✓. For zeroMult — a Zeta23 def — same defeq should hold. But hmm — `analyticOrderAt_ne_zero`: signature AnalyticAt.analyticOrderAt_ne_zero : AnalyticAt 𝕜 f z → (analyticOrderAt f z = 0 ↔ f z ≠ 0)? From LiDisc: `han.analyticOrderAt_ne_zero.mpr hw0` where hw0 : scaledZeta t w = 0 — so .mpr takes f w = 0 and produces analyticOrderAt ≠ 0 — so the iff is `analyticOrderAt f z = 0 ↔ f z ≠ 0` and .mpr : f z ≠ 0 → ... wait .mpr takes the RHS: f z ≠ 0? But hw0 : f w = 0... Let me re-read: `have hne : analyticOrderAt (scaledZeta t) w ≠ 0 := han.analyticOrderAt_ne_zero.mpr hw0`. If the iff were (= 0 ↔ f z ≠ 0), .mpr would take f z ≠ 0. hw0 : scaledZeta t w = 0 — so the iff must be `analyticOrderAt f z ≠ 0 ↔ f z = 0`! i.e. AnalyticAt.analyticOrderAt_ne_zero : AnalyticAt 𝕜 f z → (analyticOrderAt f z ≠ 0 ↔ f z = 0). Yes — that makes sense: order ≥ 1 iff vanishes. So `.mpr hρ.1` with hρ.1 : riemannZeta ρ = 0 ✓. Check name: `AnalyticAt.analyticOrderAt_ne_zero` — from LiDisc usage ✓ exists. Now the ZeroCountProp edit: ```lean /-- [PERIMETER — Trudgian 2014 N(T)/S(T), D-062 §4] The unit-window zero-count bound: the multiplicity-weighted count of nontrivial zeros with ordinates in [t, t+1] is at most Ĉ₀(t+1) (t ≥ 2). Declared counting input; Ĉ₀ = `C0hat` is D-056 §2's honest majorant (LiSkeleton). [Erratum 2026-08-23 (session 035): strengthened from the unweighted set-card form to the mult-weighted form — Trudgian's N(T) counts with multiplicity; the set-card form under-encoded the declared source and could not serve 5f/ii′-6's mult-weighted near sums. The set-card bound follows from this form (card ≤ Σ mult).] -/ def ZeroCountProp : Prop := ∀ t : ℝ, 2 ≤ t → (((zeroWindow_finite t).toFinset.sum fun ρ => zeroMult ρ) : ℝ) ≤ C0hat (t + 1) ``` Hmm — `zeroWindow_finite t` is a theorem (proof); using it inside the def makes the def depend on a proof term — fine in Lean (it's a Finset-valued construction via Set.Finite.toFinset which is noncomputable but fine). Alternatively define the sum via a function: `zeroWindowFinset t := (zeroWindow_finite t).toFinset` then sum over it. Cleaner: add a def: ```lean /-- The unit ordinate window as a finset. -/ noncomputable def zeroWindowFinset (t : ℝ) : Finset ℂ := (zeroWindow_finite t).toFinset ``` and ZeroCountProp: `∀ t : ℝ, 2 ≤ t → ((zeroWindowFinset t).sum (fun ρ => zeroMult ρ) : ℝ) ≤ C0hat (t + 1)`. Wait — LiContour is already in `noncomputable section`? Line 36 open, and the section — LiContour line ~30s: import then open... does LiContour have `noncomputable section`? zeroWindow_finite is a theorem (proof of .Finite); toFinset needs noncomputable. Let me check. Actually the grep showed no "noncomputable" line in the first 40 lines... line 40 is `namespace NguyenRH1`? Let me check the structure. From the earlier read: line 40 namespace... Actually the first read of LiContour showed lines 40-80 starting "namespace NguyenRH1" at line 40. And imports at 30-34, open at 36-37. No noncomputable section visible — but maybe it's between 37 and 40. zeroWindow (a Set) doesn't need noncomputable; zeroWindow_finite is a proof. exists_avoiding_midpoint etc. are theorems. If there's no noncomputable section, adding `noncomputable def` explicitly is fine anyway. Now the gap-circle adaptation in LiGapCircles.lean. Current code (lines 55-90): ```lean set W1 := (zeroWindow_finite (4 * (k : ℝ) + 3 / 2)).toFinset ... have hW1card : (W1.card : ℝ) ≤ C0hat (4 * (k : ℝ) + 3 / 2 + 1) := by have h1 := hZC _ h2t1 have h2 : Nat.card (zeroWindow (4 * (k : ℝ) + 3 / 2)) = W1.card := by ... ``` After the change, hZC _ h2t1 : ((W1.sum fun ρ => zeroMult ρ) : ℝ) ≤ C0hat (4k+3/2+1) — wait, (zeroWindow_finite _).toFinset vs W1 := (zeroWindow_finite _).toFinset — same thing syntactically ✓ (set W1 := that exact term). Then: ```lean have hW1card : (W1.card : ℝ) ≤ C0hat (4 * (k : ℝ) + 3 / 2 + 1) := by have h1 := hZC _ h2t1 -- ((W1.sum fun ρ => zeroMult ρ) : ℝ) ≤ C0hat (...) have h2 : W1.card ≤ W1.sum (fun ρ => zeroMult ρ) := by rw [Finset.card_eq_sum_ones] apply Finset.sum_le_sum intro ρ hρ exact one_le_zeroMult ((Set.Finite.mem_toFinset _ _).mp hρ).1 have h3 : (W1.card : ℝ) ≤ ((W1.sum fun ρ => zeroMult ρ) : ℝ) := Nat.cast_le.mpr h2 exact h3.trans h1 ``` Check `Set.Finite.mem_toFinset (hs : s.Finite) : a ∈ hs.toFinset ↔ a ∈ s` — signature: Set.Finite.mem_toFinset (hs : s.Finite)? or (h : ...)? It's `Set.Finite.mem_toFinset (hs : s.Finite) : a ∈ hs.toFinset ↔ a ∈ s`. In LiGapCircles they must already convert membership somewhere — but h2's hρ : ρ ∈ W1; W1 is let-defined as (zeroWindow_finite _).toFinset; membership conversion needs the unfold — with `set`, W1 is the let var; `Set.Finite.mem_toFinset _ _` — hmm the implicit s... After set, hρ : ρ ∈ W1 where W1 := (zeroWindow_finite (4k+3/2)).toFinset. To convert: rw [show W1 = (zeroWindow_finite (4*(k:ℝ)+3/2)).toFinset from rfl] at hρ? With `set ... with hW1def`, hW1def : W1 = .... Hmm, actually `set` introduces the definition and hW1def. Let me instead obtain membership via: have hρ' : ρ ∈ zeroWindow (4*(k:ℝ)+3/2) := by have := (Set.Finite.mem_toFinset _ _).mp (by rwa [...]) — messy with set. Simpler: in LiGapCircles, W1 is defined via `set W1 := (zeroWindow_finite (4 * (k : ℝ) + 3 / 2)).toFinset` — there might be a `with hW1` clause. Let me read the actual proof text around lines 55-100 to see the exact forms (also how they prove `Nat.card (zeroWindow ...) = W1.card` — probably via Set.Finite.toFinset + Nat.card_eq_finsetCard or similar; and whether membership bridging lemmas already exist there). Also — the exact same pattern is used for W2 and W3. Let me read LiGapCircles.lean lines 44-130.
LiContour imports LiSides — all deps available. Reading the gap-circle card steps to plan the exact adaptation.
tool: Read
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiGapCircles.lean",
  "offset": 44,
  "limit": 75
}
#1702 assistant 2026-08-24 07:10:49.775 UTC · 4615→2709 tok open ⤢
thinking (7795 chars)
Now I see the exact consumer pattern. The three card steps use: ```lean have h1 := hZC _ h2t1 -- currently : (Nat.card (zeroWindow _) : ℝ) ≤ C0hat _ have h2 : Nat.card (zeroWindow (4 * (k : ℝ) + 3 / 2)) = W1.card := ... rw [h2] at h1 ``` After the ZeroCountProp change, `hZC _ h2t1 : (((zeroWindow_finite (4*(k:ℝ)+3/2)).toFinset.sum fun ρ => zeroMult ρ) : ℝ) ≤ C0hat (4*(k:ℝ)+3/2+1)`. W1 is set to exactly `(zeroWindow_finite (4 * (k : ℝ) + 3 / 2)).toFinset` — so the sum's finset is syntactically W1's definition. Since `set` folds occurrences, `hZC _ h2t1`'s type will display with W1 folded (set rewrites the goal and NEW terms from hZC? No — set only rewrites the goal at the time of set; new hypotheses introduced later have the unfolded form. But defeq holds either way.) Adaptation per window: ```lean have hW1card : (W1.card : ℝ) ≤ C0hat (4 * (k : ℝ) + 3 / 2 + 1) := by have h1 := hZC _ h2t1 -- h1 : (((zeroWindow_finite _).toFinset.sum fun ρ => zeroMult ρ) : ℝ) ≤ C0hat _ have h2 : W1.card ≤ W1.sum (fun ρ => zeroMult ρ) := by rw [Finset.card_eq_sum_ones] apply Finset.sum_le_sum intro ρ hρ -- hρ : ρ ∈ W1 — with set, W1 is the toFinset; membership: exact one_le_zeroMult (hρ' : IsNontrivialZero ρ) ``` For membership: ρ ∈ W1 where W1 := (zeroWindow_finite _).toFinset. `Set.Finite.mem_toFinset : a ∈ hs.toFinset ↔ a ∈ s`. With set, W1 is a local definition; `Set.Finite.mem_toFinset` expects the literal toFinset term. Since set introduces W1 as a let with value, hρ : ρ ∈ W1. Convert: `have hρW : ρ ∈ zeroWindow (4*(k:ℝ)+3/2) := by have := (Set.Finite.mem_toFinset _ _).mp hρ; exact this` — type mismatch: mem_toFinset.mp expects hρ : ρ ∈ (zeroWindow_finite _).toFinset but hρ : ρ ∈ W1 — defeq ✓ exact-style should accept since W1 unfolds. With `set`, the local context has W1 := ... as a let-variable; defeq checking unfolds it ✓. Then `(Set.Finite.mem_toFinset _ _).mp hρ : ρ ∈ zeroWindow _` — zeroWindow is a set-builder {ρ | IsNontrivialZero ρ ∧ ...}, so membership is the conjunction ✓ `.1` gives IsNontrivialZero ρ. Actually — signature check: Set.Finite.mem_toFinset (hs : s.Finite)? The existing code uses `Set.ncard_eq_toFinset_card _ _` — takes both args explicit-ish. `Set.Finite.mem_toFinset` — in current Mathlib: `theorem Set.Finite.mem_toFinset (hs : s.Finite) : a ∈ hs.toFinset ↔ a ∈ s` — hmm, might have {s} implicit and (hs) explicit; the `_ _` in the existing code for ncard_eq_toFinset_card suggests two explicit args (s and hs). For mem_toFinset: probably `Set.Finite.mem_toFinset (hs : s.Finite) : ...` with s implicit, a implicit... The usage `(Set.Finite.mem_toFinset _ _).mp hρ` — if only one explicit arg (hs), then `_ _` would be wrong. Let me check Mathlib. Alternatively avoid membership entirely: `one_le_zeroMult` needs IsNontrivialZero ρ. Finset.sum_le_sum with f := fun _ => 1, g := zeroMult: need ∀ ρ ∈ W1, (1:ℕ) ≤ zeroMult ρ. Let me check the exact signature of Set.Finite.mem_toFinset via grep. Also `Finset.card_eq_sum_ones : s.card = ∑ _ ∈ s, 1` ✓ standard. Then: ```lean have h3 : (W1.card : ℝ) ≤ ((W1.sum fun ρ => zeroMult ρ) : ℝ) := Nat.cast_le.mpr h2 exact h3.trans h1 ``` Wait — h1's LHS is ((zeroWindow_finite ...).toFinset.sum fun ρ => zeroMult ρ : ℝ) — displayed via set-folding as (W1.sum ... : ℝ)? The set tactic rewrites the goal at set-time; h1 is introduced after, its type mentions the un-folded term. h3.trans h1 : needs h1 : (W1.sum ... : ℝ) ≤ C0hat — defeq with the unfolded form ✓ `exact` accepts. But `h3.trans h1` — trans is term-mode, checks defeq ✓ should be fine. Also — do I even need to change the three steps' final form? The hW-card results are used at line 100-102: `linarith [hW1card, hW2card, hW3card, hm1, hm2, hm3]` for hcard3 — unchanged signatures ✓. Now — the `one_le_zeroMult` lemma placement: LiContour.lean right after zeroWindow_finite (before ZeroCountProp). It needs zeta_order_ne_top_of_ne (LiSides ✓ imported) and analyticAt_riemannZeta (Mathlib, used in LiSides ✓). Let me also double check `analyticAt_riemannZeta` exact name — from LiSides line 131: `(analyticAt_riemannZeta hρ)` ✓. And AnalyticAt.analyticOrderAt_ne_zero — from LiDisc line ~452: `han.analyticOrderAt_ne_zero.mpr hw0`. The iff form: `AnalyticAt.analyticOrderAt_ne_zero (hf : AnalyticAt 𝕜 f z) : analyticOrderAt f z ≠ 0 ↔ f z = 0`? .mpr hw0 with hw0 : f z = 0 ⟹ analyticOrderAt ≠ 0 ✓. And ENat.toNat_pos — LiDisc line 453: `ENat.toNat_pos hne htop` where hne : analyticOrderAt ... ≠ 0, htop : ... ≠ ⊤. Returns 0 < (...).toNat ✓. zeroMult def: `(analyticOrderAt riemannZeta ρ).toNat` — so goal 1 ≤ zeroMult ρ unfolds to 1 ≤ (analyticOrderAt riemannZeta ρ).toNat. ENat.toNat_pos gives 0 < .toNat — exact needs 1 ≤ X from 0 < X: for ℕ, Nat.lt def: 0 < x ↔ 0+1 ≤ x; 0+1 = 1 defeq ✓ (LiDisc's exact h worked the same way ✓). Write: ```lean /-- A nontrivial zero has multiplicity ≥ 1 (zeroMult is the analytic order). Used to bridge the mult-weighted perimeter count to the plain window cardinality. -/ theorem one_le_zeroMult {ρ : ℂ} (hρ : IsNontrivialZero ρ) : 1 ≤ zeroMult ρ := by have hρ1 : ρ ≠ 1 := by rintro rfl rw [Complex.one_re] at hρ exact absurd hρ.2.2 (lt_irrefl 1) -- hmm: hρ.2.2 : (1:ℂ).re < 1 → after rw: (1:ℝ) < 1 have htop := zeta_order_ne_top_of_ne hρ1 have hne : analyticOrderAt riemannZeta ρ ≠ 0 := (analyticAt_riemannZeta hρ1).analyticOrderAt_ne_zero.mpr hρ.1 have h := ENat.toNat_pos hne htop exact h ``` Wait `rw [Complex.one_re] at hρ` — hρ : IsNontrivialZero 1 which is a def (riemannZeta 1 = 0 ∧ ...). rw at hρ with Complex.one_re : (1:ℂ).re = 1 — rewriting inside a def-typed hypothesis: hρ's type is IsNontrivialZero 1 — is it reducible for rw to see (1:ℂ).re? rw works up to syntactic matching after unfolding? rw doesn't unfold defs. Better: ```lean have hρ1 : ρ ≠ 1 := by rintro rfl have h := hρ.2.2 -- hmm hρ : IsNontrivialZero 1; .2.2 needs the def unfolded? ``` IsNontrivialZero ρ := riemannZeta ρ = 0 ∧ 0 < ρ.re ∧ ρ.re < 1 — a def; hρ.2.2 : (1:ℂ).re < 1 — anonymous projection through the def: `.2.2` works if the def is reducible for projection notation? The `.2` anonymous projection unfolds the def? For a def that reduces to an And, `h.2` works via whnf ✓ (this pattern is used all over — e.g. LiGapCircles uses hρ.1 from zeroWindow membership). So h := hρ.2.2 : (1 : ℂ).re < 1. Then `rw [Complex.one_re] at h` : h : (1:ℝ) < 1. Then exact lt_irrefl _ h — lt_irrefl (a) : ¬ a < a; so (lt_irrefl 1) h : False? lt_irrefl : ∀ a, ¬ a < a — (lt_irrefl 1) : ¬ (1 < 1) : 1 < 1 → False; applied to h gives False; goal is False (after rintro rfl in a proof of ρ ≠ 1 = (ρ = 1 → False)) ✓ `exact (lt_irrefl 1) h` — hmm lt_irrefl's argument explicit? `lt_irrefl (a : α) : ¬a < a` — a explicit in Mathlib? It's usually explicit: lt_irrefl a. Or `exact absurd h (lt_irrefl 1)`. Or simply `exact lt_self_iff_false...` no. Or `norm_num at h`. I'll use `exact absurd h (lt_irrefl _)`. Hmm — absurd h (lt_irrefl 1) : False ✓ robust. Actually simplest: `simpa using h` — no. `exact (lt_irrefl (1:ℝ) h).elim`? For False goal, `exact (lt_irrefl (1:ℝ)) h` works (¬P is P → False) ✓. Now the ZeroCountProp edit + erratum docstring, and LiGapCircles three-step adaptation. Also — CHECK: does anything else use ZeroCountProp? grep: exists_gapCircle_radius (LiGapCircles) and... LiSqueeze's gentire_const uses exists_gapCircle_radius (not hZC directly — wait it does: `exists_gapCircle_radius hZC (k := k) (by omega)` — passes hZC through, type unchanged ✓). LiContour's exists_zero_avoiding_T uses ZeroCountProp? From ii′-4: "L3 exists_zero_avoiding_T — clearance 1/(3·C0hat(a+1)) in any unit window [a, a+1], a ≥ 2, from the perimeter ZeroCountProp" — yes LiContour itself uses it. Let me grep all uses.
Now checking all consumers of `ZeroCountProp` before editing.
tool: Bash
input
{
  "command": "cd D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1; grep -rn \"hZC\\|ZeroCountProp\" *.lean | grep -v \"^LiGapCircles\\|def ZeroCountProp\\|PERIMETER\" | head -20; echo ===; grep -n \"hZC\\|ZeroCountProp\" LiContour.lean | head -10",
  "description": "Find all ZeroCountProp consumers"
}
#1703 assistant 2026-08-24 07:11:08.653 UTC · 3145→248 tok open ⤢
thinking (354 chars)
Two direct consumers: 1. `exists_zero_avoiding_T` (LiContour.lean:167) — line 179: `have h1 := hZC a ha` — currently gets (Nat.card (zeroWindow a) : ℝ) ≤ C0hat (a+1). Needs adaptation to card ≤ Σ mult. 2. `exists_gapCircle_radius` (LiGapCircles.lean:47) — the three window steps. Let me read LiContour's exists_zero_avoiding_T proof around line 164-200.
Two direct consumers: `exists_zero_avoiding_T` (LiContour:167) and `exists_gapCircle_radius`. Reading the LiContour consumer.
tool: Read
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiContour.lean",
  "offset": 160,
  "limit": 55
}
#1704 assistant 2026-08-24 07:12:34.304 UTC · 1441→2315 tok open ⤢
thinking (6842 chars)
I see the membership bridge pattern: `Set.Finite.mem_toFinset hfin : ρ ∈ hfin.toFinset ↔ ρ ∈ zeroWindow a` — takes just hfin (one explicit arg). ✓ Now make the edits: **Edit 1 — LiContour.lean**: add `one_le_zeroMult` + strengthen `ZeroCountProp`. For the def: ```lean /-- [PERIMETER — Trudgian 2014 N(T)/S(T), D-062 §4] The unit-window zero-count bound: the multiplicity-weighted count of nontrivial zeros with ordinates in [t, t+1] is at most Ĉ₀(t+1) (t ≥ 2). Declared counting input; Ĉ₀ = `C0hat` is D-056 §2's honest majorant (LiSkeleton). [Erratum 2026-08-23 (session 035): strengthened from the unweighted set-card form `Nat.card (zeroWindow t) ≤ Ĉ₀(t+1)` to the mult-weighted form — Trudgian's N(T) counts zeros with multiplicity, and the mult-weighted form is what 5f/ii′-6's near sums (zeroMult-weighted) consume. The set-card bound follows (card ≤ Σ mult); both consumers adapted (exists_zero_avoiding_T, exists_gapCircle_radius).] -/ def ZeroCountProp : Prop := ∀ t : ℝ, 2 ≤ t → (((zeroWindow_finite t).toFinset.sum fun ρ => zeroMult ρ) : ℝ) ≤ C0hat (t + 1) ``` **Edit 2 — exists_zero_avoiding_T's hWFcard**: ```lean have hWFcard : (WF.card : ℝ) ≤ C0hat (a + 1) := by have h1 := hZC a ha -- h1 : ((hfin.toFinset.sum fun ρ => zeroMult ρ) : ℝ) ≤ C0hat (a+1) have h2 : WF.card ≤ WF.sum (fun ρ => zeroMult ρ) := by rw [Finset.card_eq_sum_ones] apply Finset.sum_le_sum intro ρ hρ exact one_le_zeroMult ((hWFmem ρ).mp hρ).1 have h3 : (WF.card : ℝ) ≤ ((WF.sum fun ρ => zeroMult ρ) : ℝ) := Nat.cast_le.mpr h2 exact h3.trans h1 ``` Careful: hZC a ha gives `((zeroWindow_finite a).toFinset.sum ... : ℝ) ≤ ...` and WF := hfin.toFinset where hfin := zeroWindow_finite a. WF is `set ... with hWF_def` — so WF's definition is hfin.toFinset = (zeroWindow_finite a).toFinset. h1's finset: (zeroWindow_finite a).toFinset — the SAME proof term hfin? `hfin := zeroWindow_finite a` (a have, so hfin is a local hyp of type (zeroWindow a).Finite; hfin.toFinset). hZC's term uses (zeroWindow_finite a).toFinset — with the proof `zeroWindow_finite a` vs the local `hfin`. Are they syntactically equal? hfin is a local variable of type (zeroWindow a).Finite; (zeroWindow_finite a) is the proof term. hfin ≠ proof term syntactically. BUT Set.Finite.toFinset — is it proof-irrelevant-dependent? Set.Finite.toFinset {s} (h : s.Finite) : Finset ℂ — the VALUE depends on the proof h only up to proof irrelevance — two different proofs of the same s.Finite give EQUAL finsets by proof irrelevance (the content is determined by s). But Lean's defeq: toFinset uses Classical.choice internally; hfin.toFinset vs (zeroWindow_finite a).toFinset — these are different TERMS but equal by proof irrelevance (propext/choice): actually `Set.Finite.toFinset` is defined via `hs.some`... For the terms to be defeq: toFinset hfin vs toFinset (zeroWindow_finite a) — h : Finite proofs are Props, and any two proofs of the same Prop are defeq (proof irrelevance is DEFINITIONAL in Lean 4? Proof irrelevance is definitional for terms in Prop: any two proofs of the same proposition are definitionally equal ✓). So hfin.toFinset ≡ (zeroWindow_finite a).toFinset definitionally ✓ — and with set, WF := hfin.toFinset, so the h1 term is defeq to the WF version. `h3.trans h1` typechecks up to defeq ✓. Also `.mp hρ` with hWFmem's iff — hρ : ρ ∈ WF; hWFmem ρ : ρ ∈ WF ↔ ρ ∈ zeroWindow a — wait hWFmem is stated about hfin.toFinset; WF is set to that; the iff displays with WF folded? hWFmem := fun ρ => Set.Finite.mem_toFinset hfin : ∀ ρ, ρ ∈ hfin.toFinset ↔ ... With set WF := hfin.toFinset, occurrences fold — my hWFmem definition was written by them AFTER set, so it's stated with WF? No — it's written `∀ ρ : ℂ, ρ ∈ WF ↔ ρ ∈ zeroWindow a` and proved by `fun ρ => Set.Finite.mem_toFinset hfin` — defeq ✓ (this is existing code, works). So in my h2: (hWFmem ρ).mp hρ : ρ ∈ zeroWindow a; .1 : IsNontrivialZero ρ ✓. For `Finset.card_eq_sum_ones : s.card = ∑ x ∈ s, 1` ✓ standard name. Then h3.trans h1 — h3 : (WF.card:ℝ) ≤ ((WF.sum fun ρ => zeroMult ρ):ℝ); h1 : (((zeroWindow_finite a).toFinset.sum ...) : ℝ) ≤ C0hat (a+1) — the middle terms must be defeq: WF.sum f vs (zeroWindow_finite a).toFinset.sum f — WF ≡ hfin.toFinset ≡ (zeroWindow_finite a).toFinset by proof-irrel ✓. `exact h3.trans h1` — trans elaborates: h3 : a ≤ b, h1 : b' ≤ c, needs b ≡ b' defeq ✓ should unify. **Edit 3 — LiGapCircles three steps** (same pattern): ```lean have hW1card : (W1.card : ℝ) ≤ C0hat (4 * (k : ℝ) + 3 / 2 + 1) := by have h1 := hZC _ h2t1 have h2 : W1.card ≤ W1.sum (fun ρ => zeroMult ρ) := by rw [Finset.card_eq_sum_ones] apply Finset.sum_le_sum intro ρ hρ exact one_le_zeroMult ((Set.Finite.mem_toFinset _ _).mp hρ |>.1) ``` Hmm — membership for W1: hρ : ρ ∈ W1 where W1 := (zeroWindow_finite (4*(k:ℝ)+3/2)).toFinset. `(Set.Finite.mem_toFinset _ _).mp hρ` — signature: the existing code used `Set.ncard_eq_toFinset_card _ _` with two args (s and the finite proof). For mem_toFinset: Mathlib's `Set.Finite.mem_toFinset` signature? In LiContour line 175: `Set.Finite.mem_toFinset hfin` — ONE explicit arg (hfin). So mem_toFinset takes hs only (s implicit). Then `(Set.Finite.mem_toFinset _).mp hρ`? But the _ must be inferred from hρ's type ρ ∈ W1 — W1 is set-folded; unification ρ ∈ ?hs.toFinset =?= ρ ∈ W1 requires unfolding W1's let-value — unification may fail with set (the local def might not unfold during typechecking of `_`). Safer in LiGapCircles: provide the proof term explicitly: `(Set.Finite.mem_toFinset (zeroWindow_finite (4 * (k : ℝ) + 3 / 2))).mp hρ` — but hρ : ρ ∈ W1 vs expected ρ ∈ (zeroWindow_finite ...).toFinset — defeq via the set-let ✓ usually accepted (set variables are let-bound, defeq transparent). Hmm, actually with `set`, the occurrences in the goal are replaced and a definitional equality is registered; typechecking `.mp hρ` against expected type ρ ∈ (proof).toFinset: Lean must unify W1 ≡ (zeroWindow_finite _).toFinset — since W1 is a let-variable with that value, whnf unfolds ✓ works. Let me write it with explicit finite proofs: ```lean exact one_le_zeroMult (((Set.Finite.mem_toFinset (zeroWindow_finite (4 * (k : ℝ) + 3 / 2))).mp hρ).1) ``` Wait — mem_toFinset's argument: is it (hs : s.Finite) with s implicit? LiContour:175 `Set.Finite.mem_toFinset hfin` ✓ one arg. Good. For W2, W3 the same with their proof terms. Now — after editing ZeroCountProp, ALSO update the docstring references: LiContour.lean line 12 (header comment about ZeroCountProp), and check anywhere else referencing the card form. Also the LiGapCircles header comment (line ~5-16 mentions the perimeter). Also check: does anything else use `Nat.card (zeroWindow ...)`? grep after edits. Let me also check `Finset.card_eq_sum_ones` exists in this Mathlib: grep.
Membership-bridge pattern confirmed (`Set.Finite.mem_toFinset hfin`). Verifying `Finset.card_eq_sum_ones`, then making the edits.
tool: Bash
input
{
  "command": "M=D:/Python/Quantum/zeta-23-lean/.lake/packages/mathlib/Mathlib; grep -rn \"theorem card_eq_sum_ones\" $M/Algebra/BigOperators/*.lean $M/Algebra/BigOperators/**/*.lean 2>/dev/null | head -2; grep -rn \"theorem analyticOrderAt_ne_zero\\|AnalyticAt.analyticOrderAt_ne_zero\" $M/Analysis/Analytic/*.lean | head -3; grep -rn \"theorem ENat.toNat_pos\\|lemma toNat_pos\" $M/Data/ENat/*.lean $M/Mathlib/Data/ENat*.lean 2>/dev/null | head -3",
  "description": "Verify card_eq_sum_ones, analyticOrderAt_ne_zero, ENat.toNat_pos"
}
#1705 assistant 2026-08-24 07:13:52.836 UTC · 485→1204 tok open ⤢
thinking (1209 chars)
All verified: - `Finset.card_eq_sum_ones (s : Finset ι) : #s = ∑ _ ∈ s, 1` ✓ (in a Group namespace? It's in Algebra/BigOperators/Group/Finset/Basic — might be in a namespace. Line 958: `lemma card_eq_sum_ones (s : Finset ι) : #s = ∑ _ ∈ s, 1` — probably `Finset.card_eq_sum_ones`. The `#s` notation = s.card. It's in namespace Finset presumably ✓. - `AnalyticAt.analyticOrderAt_ne_zero` ✓. - `ENat.toNat_pos (hn0 : n ≠ 0) (hxt : n ≠ ⊤) : 0 < n.toNat` at Data/ENat/Basic.lean:192 ✓ (namespace ENat). Now make the edits. Edit 1: LiContour.lean — add one_le_zeroMult before ZeroCountProp and change the def. The def is at line 56-61 (from earlier read: lines 44-61 show zeroWindow def, zeroWindow_finite, ZeroCountProp def at 56-61 with docstring at 53-55... let me get exact text). From the earlier read: ``` /-- [PERIMETER — Trudgian 2014 N(T)/S(T), D-062 §4] The unit-window zero-count bound: at most Ĉ₀(t+1) nontrivial zeros have ordinates in [t, t+1] (t ≥ 2). Declared counting input for the L3 pigeonhole; Ĉ₀ = `C0hat` is D-056 §2's honest majorant (LiSkeleton). -/ def ZeroCountProp : Prop := ∀ t : ℝ, 2 ≤ t → (Nat.card (zeroWindow t) : ℝ) ≤ C0hat (t + 1) ``` Replace with one_le_zeroMult + new def.
All verified. Making the three edits: `one_le_zeroMult` + strengthened `ZeroCountProp` in LiContour, then the two consumer adaptations.
tool: Edit
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiContour.lean",
  "old_string": "/-- [PERIMETER \u2014 Trudgian 2014 N(T)/S(T), D-062 \u00a74] The unit-window\nzero-count bound: at most \u0108\u2080(t+1) nontrivial zeros have ordinates in\n[t, t+1] (t \u2265 2). Declared counting input for the L3 pigeonhole;\n\u0108\u2080 = `C0hat` is D-056 \u00a72's honest majorant (LiSkeleton). -/\ndef ZeroCountProp : Prop :=\n  \u2200 t : \u211d, 2 \u2264 t \u2192 (Nat.card (zeroWindow t) : \u211d) \u2264 C0hat (t + 1)",
  "new_string": "/-- A nontrivial zero has multiplicity \u2265 1 (zeroMult is the analytic\norder). Bridges the mult-weighted perimeter count to the plain window\ncardinality (card \u2264 \u03a3 mult). -/\ntheorem one_le_zeroMult {\u03c1 : \u2102} (h\u03c1 : IsNontrivialZero \u03c1) : 1 \u2264 zeroMult \u03c1 := by\n  have h\u03c11 : \u03c1 \u2260 1 := by\n    rintro rfl\n    have h := h\u03c1.2.2\n    rw [Complex.one_re] at h\n    exact (lt_irrefl (1 : \u211d)) h\n  have htop := zeta_order_ne_top_of_ne h\u03c11\n  have hne : analyticOrderAt riemannZeta \u03c1 \u2260 0 :=\n    (analyticAt_riemannZeta h\u03c11).analyticOrderAt_ne_zero.mpr h\u03c1.1\n  exact ENat.toNat_pos hne htop\n\n/-- [PERIMETER \u2014 Trudgian 2014 N(T)/S(T), D-062 \u00a74] The unit-window\nzero-count bound: the multiplicity-weighted count of nontrivial zeros\nwith ordinates in [t, t+1] is at most \u0108\u2080(t+1) (t \u2265 2). Declared\ncounting input for the L3 pigeonhole and the tight R-bound; \u0108\u2080 =\n`C0hat` is D-056 \u00a72's honest majorant (LiSkeleton).\n[Erratum 2026-08-23 (session 035): strengthened from the unweighted\nset-card form `(Nat.card (zeroWindow t) : \u211d) \u2264 \u0108\u2080(t+1)` to the\nmult-weighted form \u2014 Trudgian's N(T) counts zeros with multiplicity,\nand the mult-weighted form is what the 5f/ii\u2032-6 near sums\n(zeroMult-weighted, from `seriesFun`) consume; the set-card encoding\nunder-captured the declared source (a second ii\u2032-1a-class encoding\ndefect, found at the point of consumption). The set-card bound follows\nfrom this form via `one_le_zeroMult` (card \u2264 \u03a3 mult); the two\nconsumers (exists_zero_avoiding_T, exists_gapCircle_radius) adapted.] -/\ndef ZeroCountProp : Prop :=\n  \u2200 t : \u211d, 2 \u2264 t \u2192\n    (((zeroWindow_finite t).toFinset.sum fun \u03c1 => zeroMult \u03c1) : \u211d) \u2264 C0hat (t + 1)"
}
#1706 assistant 2026-08-24 07:14:57.623 UTC · 1017→382 tok open ⤢
Now the `exists_zero_avoiding_T` adaptation in the same file.
tool: Edit
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiContour.lean",
  "old_string": "  have hWFcard : (WF.card : \u211d) \u2264 C0hat (a + 1) := by\n    have h1 := hZC a ha\n    have h2 : Nat.card (zeroWindow a) = WF.card := by\n      rw [Nat.card_coe_set_eq, hWF_def]\n      exact Set.ncard_eq_toFinset_card _ hfin\n    rw [h2] at h1\n    exact h1",
  "new_string": "  have hWFcard : (WF.card : \u211d) \u2264 C0hat (a + 1) := by\n    have h1 := hZC a ha\n    -- h1 : ((hfin.toFinset.sum fun \u03c1 => zeroMult \u03c1) : \u211d) \u2264 C0hat (a + 1)\n    have h2 : WF.card \u2264 WF.sum (fun \u03c1 => zeroMult \u03c1) := by\n      rw [Finset.card_eq_sum_ones]\n      apply Finset.sum_le_sum\n      intro \u03c1 h\u03c1\n      exact one_le_zeroMult ((hWFmem \u03c1).mp h\u03c1).1\n    have h3 : (WF.card : \u211d) \u2264 ((WF.sum fun \u03c1 => zeroMult \u03c1) : \u211d) := Nat.cast_le.mpr h2\n    exact h3.trans h1"
}
#1707 assistant 2026-08-24 07:15:54.622 UTC · 688→1659 tok open ⤢
thinking (2207 chars)
Wait — in exists_zero_avoiding_T, the hWFmem is defined AFTER `set WF := hfin.toFinset with hWF_def`: ```lean set WF : Finset ℂ := hfin.toFinset with hWF_def have hWFmem : ∀ ρ : ℂ, ρ ∈ WF ↔ ρ ∈ zeroWindow a := fun ρ => Set.Finite.mem_toFinset hfin ``` And hWFcard comes after hWFmem (line 178) ✓ so hWFmem is available. But there's an ordering issue: `h1 := hZC a ha` gives the sum over `(zeroWindow_finite a).toFinset` — while WF := hfin.toFinset where hfin := zeroWindow_finite a (a local have). hfin is a local hypothesis (proof term). The two toFinset applications use different proof terms (hfin vs zeroWindow_finite a) — defeq by proof irrelevance? Set.Finite.toFinset's value: it's defined as `(hs : s.Finite)` → uses Classical... the finset's elements are determined by s, and two proofs of the same s.Finite give equal finsets by proof irrelevance (Lean 4: any two proofs of a Prop are DEFINITIONALLY equal — proof irrelevance is definitional in Lean's kernel ✓). So hfin.toFinset ≡ (zeroWindow_finite a).toFinset definitionally ✓. But h3.trans h1: h3 : (WF.card:ℝ) ≤ ((WF.sum fun ρ => zeroMult ρ):ℝ); h1 : (((zeroWindow_finite a).toFinset.sum fun ρ => zeroMult ρ):ℝ) ≤ C0hat (a+1). trans needs the middle terms to be syntactically-unifiable up to defeq: (WF.sum f : ℝ) vs ((zeroWindow_finite a).toFinset.sum f : ℝ) — Nat.cast of both; defeq: WF ≡ hfin.toFinset ≡ (zeroWindow_finite a).toFinset ✓ (proof irrelevance makes hfin ≡ zeroWindow_finite a? hfin is a local hypothesis introduced by `have hfin := zeroWindow_finite a` — hfin is a free variable of type (zeroWindow a).Finite, NOT the proof term zeroWindow_finite a. Proof irrelevance: any two terms of the same Prop type are definitionally equal — this is a kernel rule: `hfin` and `zeroWindow_finite a` both have type `(zeroWindow a).Finite` (a Prop), so they're defeq ✓. And Set.Finite.toFinset is a function of s and the proof — congruence gives toFinset hfin ≡ toFinset (zeroWindow_finite a) ✓.) In LiGapCircles, W1 := (zeroWindow_finite (4*(k:ℝ)+3/2)).toFinset directly (not via a local have) — so the sum's finset is syntactically the same proof application ✓ even simpler. Now the LiGapCircles edits — the three card steps.
Now the three card steps in LiGapCircles.
tool: Edit
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiGapCircles.lean",
  "old_string": "  have hW1card : (W1.card : \u211d) \u2264 C0hat (4 * (k : \u211d) + 3 / 2 + 1) := by\n    have h1 := hZC _ h2t1\n    have h2 : Nat.card (zeroWindow (4 * (k : \u211d) + 3 / 2)) = W1.card := by\n      rw [Nat.card_coe_set_eq]\n      exact Set.ncard_eq_toFinset_card _ _\n    rw [h2] at h1\n    exact h1\n  have hW2card : (W2.card : \u211d) \u2264 C0hat (4 * (k : \u211d) + 5 / 2 + 1) := by\n    have h1 := hZC _ h2t2\n    have h2 : Nat.card (zeroWindow (4 * (k : \u211d) + 5 / 2)) = W2.card := by\n      rw [Nat.card_coe_set_eq]\n      exact Set.ncard_eq_toFinset_card _ _\n    rw [h2] at h1\n    exact h1\n  have hW3card : (W3.card : \u211d) \u2264 C0hat (4 * (k : \u211d) + 7 / 2 + 1) := by\n    have h1 := hZC _ h2t3\n    have h2 : Nat.card (zeroWindow (4 * (k : \u211d) + 7 / 2)) = W3.card := by\n      rw [Nat.card_coe_set_eq]\n      exact Set.ncard_eq_toFinset_card _ _\n    rw [h2] at h1\n    exact h1",
  "new_string": "  have hW1card : (W1.card : \u211d) \u2264 C0hat (4 * (k : \u211d) + 3 / 2 + 1) := by\n    have h1 := hZC _ h2t1\n    -- h1 : ((W1.sum fun \u03c1 => zeroMult \u03c1) : \u211d) \u2264 C0hat _; card \u2264 \u03a3 mult\n    have h2 : W1.card \u2264 W1.sum (fun \u03c1 => zeroMult \u03c1) := by\n      rw [Finset.card_eq_sum_ones]\n      apply Finset.sum_le_sum\n      intro \u03c1 h\u03c1\n      exact one_le_zeroMult\n        (((Set.Finite.mem_toFinset (zeroWindow_finite (4 * (k : \u211d) + 3 / 2))).mp h\u03c1).1)\n    have h3 : (W1.card : \u211d) \u2264 ((W1.sum fun \u03c1 => zeroMult \u03c1) : \u211d) := Nat.cast_le.mpr h2\n    exact h3.trans h1\n  have hW2card : (W2.card : \u211d) \u2264 C0hat (4 * (k : \u211d) + 5 / 2 + 1) := by\n    have h1 := hZC _ h2t2\n    have h2 : W2.card \u2264 W2.sum (fun \u03c1 => zeroMult \u03c1) := by\n      rw [Finset.card_eq_sum_ones]\n      apply Finset.sum_le_sum\n      intro \u03c1 h\u03c1\n      exact one_le_zeroMult\n        (((Set.Finite.mem_toFinset (zeroWindow_finite (4 * (k : \u211d) + 5 / 2))).mp h\u03c1).1)\n    have h3 : (W2.card : \u211d) \u2264 ((W2.sum fun \u03c1 => zeroMult \u03c1) : \u211d) := Nat.cast_le.mpr h2\n    exact h3.trans h1\n  have hW3card : (W3.card : \u211d) \u2264 C0hat (4 * (k : \u211d) + 7 / 2 + 1) := by\n    have h1 := hZC _ h2t3\n    have h2 : W3.card \u2264 W3.sum (fun \u03c1 => zeroMult \u03c1) := by\n      rw [Finset.card_eq_sum_ones]\n      apply Finset.sum_le_sum\n      intro \u03c1 h\u03c1\n      exact one_le_zeroMult\n        (((Set.Finite.mem_toFinset (zeroWindow_finite (4 * (k : \u211d) + 7 / 2))).mp h\u03c1).1)\n    have h3 : (W3.card : \u211d) \u2264 ((W3.sum fun \u03c1 => zeroMult \u03c1) : \u211d) := Nat.cast_le.mpr h2\n    exact h3.trans h1"
}
#1708 assistant 2026-08-24 07:16:18.891 UTC · 1894→365 tok open ⤢
thinking (860 chars)
Wait — in LiGapCircles, the `hρ` from `Finset.sum_le_sum`'s intro has type `ρ ∈ W1` where W1 is a `set` variable. `(Set.Finite.mem_toFinset (zeroWindow_finite ...)).mp hρ` expects `ρ ∈ (zeroWindow_finite ...).toFinset`. With `set`, W1 is a let-bound local; defeq should handle it... but `Finset.sum_le_sum`'s intro — hρ's type is `ρ ∈ W1` displayed; the underlying term is the set-variable. The `.mp` application needs hρ : ρ ∈ (zeroWindow_finite (4*(k:ℝ)+3/2)).toFinset — the elaborator will try to unify W1 with the toFinset term. `set` uses `let` in the local context — when elaborating `.mp hρ`, Lean infers hρ's type as ρ ∈ W1 (a let-var application), and the expected type is ρ ∈ (zeroWindow_finite ...).toFinset; isDefEq unfolds the let ✓ should work. Also update the header comment of LiContour (line 12) mentioning ZeroCountProp — check what it says.
Also updating the LiContour header reference, then rebuilding.
tool: Read
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiContour.lean",
  "offset": 1,
  "limit": 40
}
#1709 assistant 2026-08-24 07:18:50.491 UTC · 453→1328 tok open ⤢
thinking (2726 chars)
The cast shape: my ZeroCountProp def sums in ℕ then casts: `((...toFinset.sum fun ρ => zeroMult ρ) : ℝ)`. But the error shows the expected type is `∑ ρ ∈ WF, ↑(zeroMult ρ)` — i.e., the def's `((sum ...) : ℝ)` gets NORMALIZED by push_cast-style coercion insertion to `∑ ρ ∈ _, ↑(zeroMult ρ)`? Interesting — the elaborator inserted the cast inside. Actually what happened: in my def I wrote `(((zeroWindow_finite t).toFinset.sum fun ρ => zeroMult ρ) : ℝ)` — the sum is in ℕ (zeroMult : ℂ → ℕ), then cast to ℝ. But the error says h1 has type `... ≤ ∑ ρ ∈ WF, ↑(zeroMult ρ)` — so h1's LHS got elaborated as a REAL sum of casts. That means the def's `(sum ... : ℝ)` with the expected real type pushed the coercion inside? No wait — the ERROR is at line 213: `Nat.cast_le.mpr h2` where h2 : WF.card ≤ WF.sum (fun ρ => zeroMult ρ) (ℕ inequality), so Nat.cast_le.mpr h2 : (↑WF.card : ℝ) ≤ ↑(WF.sum ...) — a cast of a ℕ-sum. But h1's LHS is `∑ ρ ∈ WF, ↑(zeroMult ρ)` — a sum of casts (the elaborator of my def unified `(sum fun ρ => zeroMult ρ : ℝ)` by inserting the cast per-term because the ascription ((...) : ℝ) coerces the whole... hmm no — apparently when I wrote `((Finset.sum ... fun ρ => zeroMult ρ) : ℝ)`, Lean elaborated `Finset.sum` at type ℝ directly (the expected type ℝ propagates INTO the sum, making each term cast: zeroMult ρ gets coerced ℕ → ℂ? no → ℝ). So the sum is the ℝ-sum of `(zeroMult ρ : ℝ)` terms. So h1 : (∑ ρ ∈ toFinset, (zeroMult ρ : ℝ)) ≤ C0hat (a+1) — sum of real casts. And my h3 : ↑WF.card ≤ ↑(∑ ...) — cast of a ℕ-sum. These are equal by Nat.cast_sum but not syntactically. Fix: make h2 produce the ℝ-valued sum directly: use Finset.card_le_sum... or push_cast at h3, or state h2 with the cast sum: ```lean have h3 : (WF.card : ℝ) ≤ ((WF.sum fun ρ => zeroMult ρ) : ℝ) := Nat.cast_le.mpr h2 rw [Nat.cast_sum] at h3 -- cast of sum = sum of casts exact h3.trans h1 ``` Nat.cast_sum : ↑(∑ i ∈ s, f i) = ∑ i ∈ s, ↑(f i) ✓ standard (Nat.cast_sum (s) (f)). Add the rw. Or simpler: change h2 to work over ℝ directly: ```lean have h2 : (WF.card : ℝ) ≤ ∑ ρ ∈ WF, (zeroMult ρ : ℝ) := by rw [show (WF.card : ℝ) = ∑ ρ ∈ WF, (1 : ℝ) by simp] apply Finset.sum_le_sum intro ρ hρ exact_mod_cast one_le_zeroMult (((hWFmem ρ).mp hρ).1) ``` `(WF.card : ℝ) = ∑ ρ ∈ WF, (1:ℝ)` — via Finset.card_eq_sum_ones + cast, or `by simp` (Finset.sum_const, nsmul... simp should close: ∑ _ ∈ s, (1:ℝ) = s.card • 1 = card). Then Finset.sum_le_sum over ℝ with (1:ℝ) ≤ (zeroMult ρ : ℝ) via exact_mod_cast of one_le_zeroMult (1 ≤ zeroMult ρ in ℕ → (1:ℝ) ≤ (zeroMult ρ:ℝ) via Nat.cast_le... exact_mod_cast handles). Cleaner. Let me rewrite that step in LiContour, and similarly in LiGapCircles.
The def's ascription pushed the cast inside the sum (real sum of casts), while my bridge produced a cast of a ℕ-sum. Fixing by working over ℝ directly in the card step.
tool: Edit
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiContour.lean",
  "old_string": "  have hWFcard : (WF.card : \u211d) \u2264 C0hat (a + 1) := by\n    have h1 := hZC a ha\n    -- h1 : ((hfin.toFinset.sum fun \u03c1 => zeroMult \u03c1) : \u211d) \u2264 C0hat (a + 1)\n    have h2 : WF.card \u2264 WF.sum (fun \u03c1 => zeroMult \u03c1) := by\n      rw [Finset.card_eq_sum_ones]\n      apply Finset.sum_le_sum\n      intro \u03c1 h\u03c1\n      exact one_le_zeroMult ((hWFmem \u03c1).mp h\u03c1).1\n    have h3 : (WF.card : \u211d) \u2264 ((WF.sum fun \u03c1 => zeroMult \u03c1) : \u211d) := Nat.cast_le.mpr h2\n    exact h3.trans h1",
  "new_string": "  have hWFcard : (WF.card : \u211d) \u2264 C0hat (a + 1) := by\n    have h1 := hZC a ha\n    -- h1 : (\u2211 \u03c1 \u2208 WF, (zeroMult \u03c1 : \u211d)) \u2264 C0hat (a + 1); card \u2264 \u03a3 mult\n    have h2 : (WF.card : \u211d) \u2264 \u2211 \u03c1 \u2208 WF, (zeroMult \u03c1 : \u211d) := by\n      rw [show (WF.card : \u211d) = \u2211 _\u03c1 \u2208 WF, (1 : \u211d) by simp]\n      apply Finset.sum_le_sum\n      intro \u03c1 h\u03c1\n      exact_mod_cast one_le_zeroMult ((hWFmem \u03c1).mp h\u03c1).1\n    exact h2.trans h1"
}
#1710 assistant 2026-08-24 07:21:33.482 UTC · 774→163 tok open ⤢
thinking (91 chars)
Both build successfully. Now rebuild the whole downstream (LiCircleBound, LiSqueeze, root).
Both green. Now the full build (LiCircleBound → LiSqueeze → root).
tool: Bash
input
{
  "command": "cd D:/Python/Quantum/research/lean/NguyenRH1 && export PATH=\"$HOME/.elan/bin:$PATH\" && lake build 2>&1 | tail -4",
  "description": "Full build after ZeroCountProp strengthening",
  "timeout": 600000
}
#1711 assistant 2026-08-24 07:24:55.400 UTC · 263→286 tok open ⤢
thinking (355 chars)
Full build GREEN (8768 jobs). The perimeter strengthening is complete and everything downstream rebuilds. Axiom-audit the changed declarations (one_le_zeroMult, exists_zero_avoiding_T, exists_gapCircle_radius, partialFraction_identity) to confirm 3 standard axioms only. Then commit this perimeter repair as a sub-stage commit before moving to 5f design.
Full build green (8768 jobs). Axiom-audit the affected declarations, then commit the perimeter repair.
tool: Write
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\AuditSession035.lean",
  "content": "/-\nAuditSession035.lean \u2014 axiom audit for the session-035 perimeter repair\n(ZeroCountProp mult-weighted strengthening) + the 5e capstone chain.\nExpected: [propext, Classical.choice, Quot.sound] on every declaration.\n-/\nimport NguyenRH1\n\nopen NguyenRH1\n\n#print axioms one_le_zeroMult\n#print axioms exists_zero_avoiding_T\n#print axioms exists_gapCircle_radius\n#print axioms gentire_const\n#print axioms partialFraction_identity\n"
}
#1712 assistant 2026-08-24 07:27:16.066 UTC · 845→2048 tok open ⤢
thinking (4364 chars)
Perimeter repair committed. Now the 5f design. Let me now carefully design 5f — the tight R-bound: **Target statement** (matching D-056 Theorem R + the LiDisc capstone shape): ```lean theorem logDeriv_riemannZeta_sub_nearZeros_le_tight (hZC : ZeroCountProp) {t : ℝ} (ht : 10 ≤ |t|) {s : ℂ} (hσ : -5/2 ≤ s.re ∧ s.re ≤ 3) (him : s.im = t) (hζ : riemannZeta s ≠ 0) ... : ‖logDeriv riemannZeta s - ∑ ρ ∈ nearZeros t, (zeroMult ρ : ℂ) / (s - ρ)‖ ≤ 10.5 * Real.log (|t| + 2) + 48 ``` Wait — what are the exact hypotheses needed? D-056: σ ∈ [−5/2, 3], |t| ≥ 10. The six pieces: 1. |ζ′/ζ(s₀)| ≤ Z₂ ≤ 0.57 where s₀ = 2+it: Dirichlet bound. In Lean: `norm_logDeriv_zeta_le_dirichlet` gives ‖logDeriv ζ (2+it)‖ ≤ dirichletC2 for re ≥ 2. What is dirichletC2's value? Let me check LiCircleBound line 203. It was defined as... need to look. If dirichletC2 ≤ 0.57-ish or a bit more — D-056 uses Z₂ ≤ 0.57. If dirichletC2 is defined as exactly the Dirichlet majorant Σ Λ(n)/n² = −ζ′/ζ(2) ≈ 0.56996..., then the tight fold 0.57 works. Let me check. 2. Near at s₀: Σ_{|γ−t|<1} m_ρ/|s₀−ρ| ≤ Σ m_ρ ≤ (mult count) ≤ C0hat-ish. The window |γ−t|<1 ⊂ (t−1, t+1) ⊂ [t−1, t] ∪ [t, t+1]... zeroWindow a covers [a, a+1]. |γ−t| < 1 means γ ∈ (t−1, t+1) ⊂ zeroWindow (t−1) ∪ zeroWindow t? zeroWindow (t−1) covers [t−1, t] ✓ and zeroWindow t covers [t, t+1] ✓ — union covers [t−1, t+1] ⊃ (t−1, t+1) ✓. So Σ_near m ≤ Σ_{W(t−1)} m + Σ_{W(t)} m ≤ C0hat(t) + C0hat(t+1) ≤ 2·C0hat(t+1) by mono. Hmm — but D-056 uses ONE C₀(t) for this. Our perimeter gives 2·C0hat(t+1). The constant fold: D-056's assembly was 13.73·C₀(t) + 7.97 where C₀(t) ≤ C0hat-ish. If our count is 2·C0hat(t+1) everywhere D-056 had C₀(t), the fold becomes 13.73·(2·C0hat(t+1)) + ... — hmm, that doubles the count contribution: 13.73·2·(0.433 log + 0.886 loglog + 2.9) + 7.97 ≈ 11.9 log + 24.3 loglog + 87.6 — vs the target 10.5 log + 48. That BREAKS the constants! Wait — hold on. Let me recheck D-056's C₀(t) definition: "C₀(t) := F(t+1)−F(t) + S_b(t+1) + S_b(t)" — this is the count for the unit interval (t, t+1]... no wait: F(t+1)−F(t) + S_b(t+1) + S_b(t) bounds |N(t+1) − N(t)| = zeros in (t, t+1]. So C₀(t) bounds the unit window (t, t+1]. But D-056's near sum is over |γ−t| < 1 = (t−1, t+1) — TWO unit windows! D-056 piece 2 says "Σ_{|γ−t|<1} 1/|s₀−ρ| ≤ C₀(t)" — using C₀(t) for a TWO-unit window?? Hmm, let me re-read D-056. "2. Near at s₀: |s₀−ρ| ≥ 2 − β ≥ 1 ⟹ Σ_{|γ−t|<1} 1/|s₀−ρ| ≤ C₀(t)." So D-056 uses C₀(t) as the bound for the |γ−t|<1 window. And D-036 §0 erratum defines C₀(t) := F(t+1)−F(t) + S_b(t+1) + S_b(t) as "the HONEST Trudgian form" — hmm, that bounds (t, t+1]. But the near window is (t−1, t+1)... unless C₀(t) is defined as the bound for |γ−t|≤1 which would be (t−1, t+1] = N(t+1)−N(t−1) ≤ F(t+1)−F(t−1) + S_b(t+1)+S_b(t−1). Let me check D-036 §0's exact C₀ definition. Actually from NGUYEN.md/STATE: "C0hat (t : ℝ) := 0.433·log(t+2) + 0.886·log log(t+2) + 2.9" and ZeroCountProp: count in [t, t+1] ≤ C0hat(t+1) = 0.433 log(t+3) + 0.886 loglog(t+3) + 2.9. And D-036's Ĉ₀(t) was designed as the count bound for a unit window [t, t+1]. The LiSkeleton margin uses C0hat T... Let me look at D-036 §0 for C₀(t)'s exact definition to see whether D-056's piece 2 usage (one C₀(t) for the double window) is a genuine accounting or a slip that was absorbed. Actually — D-056's fold: "13.73·C₀(t) + 7.97 ≤ 13.73·(0.433 log(t+2) + 0.886 loglog(t+2) + 2.9) + 7.97 = 5.95 log + 12.16 loglog + 39.8 + 7.97 ≤ (5.95 + 12.16/e) log + 47.8 ≤ 10.5 log + 48". So D-056 used C₀(t) ≤ C0hat(t) — i.e., ONE unit-window majorant for the near window |γ−t| < 1. Hmm wait, is that right? Let me check D-036 §0's C₀ definition — from NGUYEN.md: "margin convexity PROVED (chain-rule reduction φ(T(n))″ = ...)" and "D-036 §0 erratum" is referenced in D-056: "The zero-count input is the HONEST Trudgian form (D-036 §0 erratum): C₀(t) := F(t+1)−F(t) + S_b(t+1) + S_b(t) ≤ 0.433 log(t+2) + 0.886 log log(t+2) + 2.9". So C₀(t) bounds |N(t+1)−N(t)| = count in (t, t+1]. Then piece 2's claim Σ_{|γ−t|<1} ≤ C₀(t) is... using the WRONG window? |γ−t|<1 spans (t−1, t+1) which is two unit intervals. Hmm — but wait: maybe D-036's C₀(t) is defined for the window |γ−t| ≤ 1 directly. Let me read D-036 §0. Actually, let me look at D-036 first. The honest accounting matters for the Lean fold. Let me read D-036 §0-§2.
Perimeter repair committed (`75172e6`). Now the 5f design — first I need D-036's exact C₀ definition to get the near-window accounting right (D-056's piece 2 uses one C₀(t) for the double window |γ−t|<1 — need to check if that's the design or a slip).
tool: Bash
input
{
  "command": "grep -n \"C\u2080(t)\\|C0hat\\|F(t+1)\\|S_b\" D:/Python/Quantum/research/derivations/D-036*.md | head -20",
  "description": "Find C\u2080(t) definition in D-036"
}
#1713 assistant 2026-08-24 07:31:00.286 UTC · 1386→5421 tok open ⤢
thinking (12483 chars)
Now I see the accounting clearly: - D-036 §0: "zeros in a unit interval at height t ≥ 10: n(t) := N(t+1) − N(t) ≤ C₀(t)" — C₀(t) bounds the count in the unit interval (t, t+1]... and "C₀(t) ≤ 0.433 log(t+2) + 0.886 log log(t+2) + 2.9" is the honest form. - D-036 §1's R(s): "Σ_{|γ−t|<1} 1/ρ ≤ C₀(t)/14.13" — again uses ONE C₀(t) for the double window |γ−t| < 1. Hmm — so D-036/D-056 both use one C₀(t) for |γ−t| < 1 = (t−1, t+1). Is that a slip or is C₀(t) defined as the |γ−t|≤1 count? Line 20: "n(t) := N(t+1) − N(t)" — unit interval (t, t+1]. But then the |γ−t|<1 window = (t−1, t+1) needs TWO such counts: n(t−1) + n(t) ≤ C₀(t−1) + C₀(t) ≤ 2·C₀(t) (mono). Hmm, wait — maybe the convention: the |γ−t|<1 sum... D-036 line 37: R(s) := ζ′/ζ(s) − Σ_{|γ−t|<1} 1/(s−ρ). And the near-sum bound |Σ_{|γ−t|<1} 1/ρ| ≤ C₀(t)/14.13 — hmm, that uses |ρ| ≥ |γ|·0.999 or |ρ| ≥ 14.13... wait "≤ C₀(t)/14.13" — the 14.13 is from |ρ| ≥ |γ| ≥ ... hmm, for |γ−t|<1, |γ| ≥ t−1 ≥ 9, and |ρ| ≥ ~|γ| so each term 1/|ρ| ≤ 1/14.13-ish... no — 1/|ρ| ≤ 1/(t−1)... the C₀(t)/14.13 bound = count × (1/14.13)?? For t = 10, |γ| ≥ 9, 1/|ρ| ≤ 1/9-ish, and C₀/14.13 has 14.13 — hmm inconsistent, maybe |ρ| ≥ 14.13 for ALL nontrivial zeros (first zero at 14.13!). So Σ_{|γ−t|<1} 1/|ρ| ≤ count/14.13 where count = #{|γ−t|<1} ≤ C₀(t)?? So the question stands: does the paper convention use C₀(t) for the TWO-unit window (t−1, t+1)? Let me think about what's true mathematically: the count in (t−1, t+1] = N(t+1) − N(t−1) ≤ F(t+1)−F(t−1) + |S(t+1)| + |S(t−1)| ≈ 2·(0.433 log(t+2) + ...) — twice the unit-window bound. If D-056's assembly 13.73·C₀(t) + 7.97 actually needs 2·C₀(t) for the near piece, the constants would be off. Hmm wait — let me recount D-056's piece 2 vs piece 3 more carefully: Piece 2: near at s₀: Σ_{|γ−t|<1} 1/|s₀−ρ| ≤ C₀(t). — count in |γ−t|<1 window × 1 (since |s₀−ρ| ≥ 1). If the window count is really 2·C₀(t)... Piece 3: far difference: |s₀−s| ≤ 4.5; terms 4.5√2/(|t−γ|(1+|t−γ|)); "Group by unit intervals (Σ 1/(k(k+1)) = 1 exactly): left side ≤ C₀(t), right side k ≤ t ≤ C₀(2t) ≤ C₀(t) + 0.58; the k > t tail ≤ 0.53". The grouping: for the far zeros, group by k ≤ |t−γ| < k+1 (k ≥ 1). Left side (γ < t): intervals k = 1..~t: count per interval ≤ C₀(...) each — the sum Σ_k C₀/(k(k+1)) ≤ C₀(t)·Σ1/(k(k+1)) = C₀(t) — hmm this needs per-interval count ≤ C₀(t) for all intervals up to t, i.e., C₀ monotone. Each unit interval's count ≤ C₀(t) ✓ (mono). The left side intervals: k from 1 to ~t — each interval {γ : k ≤ t−γ < k+1} = (t−k−1, t−k] is a unit window with count ≤ C₀(t−k) ≤ C₀(t). Sum over k: Σ_{k≥1} C₀(t)/(k(k+1)) = C₀(t)·1. ✓. Right side: γ ∈ (t+k, t+k+1]: count ≤ C₀(t+k) ≤ C₀(2t) for k ≤ t; Σ_{1≤k≤t} C₀(2t)/(k(k+1)) ≤ C₀(2t)·1. ✓. Tail k > t: Σ_{k>t} C₀(t+k)/(k(k+1)) ≤ ~C₀(2t)/(t+1) + ... ≤ 0.53. ✓. So piece 3's per-interval counts are all single-unit-window counts ✓ consistent with C₀ = unit-interval count. But piece 2's Σ_{|γ−t|<1}: the window (t−1, t+1) — TWO unit intervals! Using ONE C₀(t) there looks like an off-by-two slip... OR the convention |γ−t|<1 vs the count: hmm wait, actually. Hmm, let me recheck: is C₀(t) in D-036 §0 the count of the unit interval at height t — "n(t) := N(t+1) − N(t)" ✓ unit interval (t, t+1]. And piece 2's window |γ−t|<1 = γ ∈ (t−1, t+1) = (t−1, t] ∪ (t, t+1) → count ≤ n(t−1) + n(t) ≤ 2·C₀(t)-ish. So the paper's piece 2 (Σ_{|γ−t|<1} 1/|s₀−ρ| ≤ C₀(t)) appears to undercount by a factor of 2! Unless... hmm wait. Let me recheck D-056's near-sum convention. D-036 §1 line 37: R(s) := ζ′/ζ(s) − Σ_{|γ−t|<1} 1/(s−ρ). Hmm — actually hold on, is it possible that the convention in the paper is |γ − t| ≤ 1 with count C₀(t) where C₀(t) was DEFINED as the |γ−t|≤1 count? D-036 §0 line 19-20: "zeros in a unit interval at height t ≥ 10: n(t) := N(t+1) − N(t) ≤ C₀(t)". So C₀(t) = unit-interval count. The |γ−t|<1 window needs 2 of them. Hmm, so is D-056's assembly wrong by one C₀(t)? Let me recount the total with the honest near count 2C₀(t) instead of C₀(t): D-056 assembly: |R(s)| ≤ Z₂ + C₀(t) + [12.73·C₀(t) + 7.06] + 0.09 + 0.29 with pieces 1..6 = 0.57 + C₀ + 12.73C₀ + 7.06 + 0.045 + 0.045 + 0.29 = 13.73 C₀ + 7.97. If piece 2 is really 2·C₀: total = 0.57 + 2C₀ + 12.73C₀ + 7.97 = 14.73·C₀ + 7.97 ≤ 14.73·(0.433 log + 0.886 loglog + 2.9) + 7.97 = 6.38 log + 13.05 loglog + 42.7 + 7.97 ≤ (6.38 + 13.05/e) log + 50.7 ≤ (6.38 + 4.8) log + 50.7 = 11.18 log + 50.7 — vs the baked 10.5 log + 48. That BREAKS the baked constants (11.18 > 10.5, 50.7 > 48)! Whoa. Wait — is this a REAL slip in D-056 (which would need an erratum + possibly a margin re-derivation), or am I miscounting the window? Let me recompute: |γ − t| < 1 ⟺ γ ∈ (t−1, t+1). Unit intervals: (t−1, t] and (t, t+1). n(t−1) = N(t) − N(t−1) ≤ C₀(t−1) and n(t) ≤ C₀(t). C₀ monotone increasing ⟹ ≤ 2·C₀(t). Hmm. BUT WAIT. Let me look at D-036's R(s) again — hmm, in D-036 the near sum is over |γ−t| < 1 and piece 2 in D-056 says Σ_{|γ−t|<1} 1/|s₀−ρ| ≤ C₀(t). Hmm, unless the C₀ in D-056 is defined differently — D-056 says "C₀(t) := F(t+1)−F(t) + S_b(t+1) + S_b(t)". That bounds |N(t+1) − N(t)| — the count in (t, t+1]... Hmm hold on, actually — wait. Let me reconsider. F(t+1) − F(t) + S(t+1) + S(t): |N(t+1) − N(t)| = |F(t+1)−F(t) + S(t+1) − S(t)| ≤ F(t+1)−F(t) + |S(t+1)| + |S(t)| ✓ that's the (t, t+1] count. So C₀(t) is the (t, t+1] unit count. The |γ−t|<1 window is two units. D-056's piece 2 is off by a factor of 2 on its face. Hmm, but wait — maybe not! Let me look at the near sum in R(s) more carefully. R(s) = ζ′/ζ(s) − Σ_{|γ−t|<1} 1/(s−ρ). In the reference-point difference: R(s) = ζ′/ζ(s₀) − Σ_{|γ−t|<1} 1/(s₀−ρ) + Σ_{|γ−t|≥1} (s₀−s)/((s−ρ)(s₀−ρ)) − ... Hmm wait, actually that's not right. The full difference series is Σ_ρ m(1/(s−ρ) − 1/(s₀−ρ)) over ALL zeros. Split as near (|γ−t|<1) and far. R(s) := ζ′/ζ(s) − Σ_near m/(s−ρ): ζ′/ζ(s) − ζ′/ζ(s₀) = Σ_all m(1/(s−ρ) − 1/(s₀−ρ)) − (1/s−1/s₀) − ... So ζ′/ζ(s) = ζ′/ζ(s₀) + Σ_near m/(s−ρ) − Σ_near m/(s₀−ρ) + Σ_far m(1/(s−ρ) − 1/(s₀−ρ)) − elems. R(s) = ζ′/ζ(s₀) − Σ_near m/(s₀−ρ) + Σ_far m(1/(s−ρ) − 1/(s₀−ρ)) − elems ✓ matches D-056. Piece 2 = |Σ_near m/(s₀−ρ)| ≤ Σ_near m ≤ count(|γ−t|<1). Now — the count of |γ−t|<1. Hmm, is it possible D-056/D-036 intend |γ − t| < 1 to really be a ONE-sided or differently-centered window where one C₀ suffices? |γ−t|<1 is two-sided, two unit intervals. I'm now fairly convinced piece 2 as written costs 2·C₀(t), not C₀(t). Hold on — but wait: E-028 V-R verified the traced bound 10.5 log + 48 NUMERICALLY at 15 sample points with worst ratio 0.039 (26× slack). The numerical verification used the TRUE near sums (computed from actual zeros), so the bound HOLDS numerically with huge slack. The issue is purely the traced/paper assembly accounting. And the Lean margin constants are baked as 10.5/48 in marginTilde/Hhat. So if the honest traced assembly gives 14.73·C₀ + 7.97 ≤ 11.2 log + 51, the baked 10.5/48 would be unprovable from the assembly — the Lean 5f would fail to hit 10.5/48. BUT — the slack is 26×. Can the assembly be honestly tightened to fit 10.5/48? Options: (a) Tighten piece 3's far bound: 12.73·C₀ + 7.06 — the 4.5√2 ≈ 6.36 factor and the two-sided count... D-056's piece 3 already counts each side with per-interval counts — the left side ≤ C₀(t)·1 (Σ 1/(k(k+1)) = 1), right ≤ C₀(2t)·1, tail 0.53 — total ≤ 4.5√2·(2C₀(t) + 0.58 + 0.53) = 6.364·(2C₀ + 1.11) = 12.73·C₀ + 7.06 ✓. (b) Note the near-window count could be taken as C₀(t) EXACTLY if the near window is re-centered: the sum Σ_{|γ−t|<1} — hmm what if we instead define the near window as |γ − t| ≤ 1 vs... no, still two units. Hmm wait, wait. Actually, let me recheck: is the window in D-036's R(s) maybe |γ − t| ≤ 1 where the COUNT convention... D-036 §0: "zeros in a unit interval at height t ≥ 10: n(t) := N(t+1) − N(t) ≤ C₀(t)". Hmm what if C₀(t) is intended as the count of the |γ−t| ≤ 1 neighborhood (a TWO-unit window), i.e., N(t+1) − N(t−1)? Line 20 says N(t+1) − N(t) explicitly. So C₀(t) = one-unit count. Hmm hmm. But then D-036 line 41: "|Σ_{|γ−t|<1} 1/ρ| ≤ C₀(t)/14.13" — with |ρ| ≥ 14.13 (first zero!) and count ≤ C₀(t) — again one C₀ for the two-unit window. Consistent convention across D-036 and D-056 — either both right or both wrong by 2×. Let me compute the true count bound for |γ−t|<1 at t=10..1000 vs C₀(t): C₀(t) ≈ 0.433·log(t+2) + 0.886·loglog(t+2) + 2.9. At t=10: 0.433·2.48 + 0.886·0.907 + 2.9 ≈ 1.07 + 0.80 + 2.9 = 4.78. True count in (9, 11): zeros at 14.13... none! (first zero 14.1347). At t=15: count in (14,16): one zero (14.13). C₀(15) = 0.433·2.83 + 0.886·1.04 + 2.9 ≈ 1.23+0.92+2.9 = 5.05. Fine. The point: C₀(t) ≈ 4.8–6.5 while the true two-unit counts are ~0–3 — the average spacing is 2π/log ≈ 2.5 at these heights, so a two-unit window has ~0.8·2 = 1.6 zeros typically, and C₀ ~ 5–7 has slack ~3–4× per unit window... The honest PROVABLE two-unit bound is 2·C₀ ≈ 10–13 though. The 26× measured slack in E-028 swallows even the honest 2·C₀ accounting? Let me recompute the total with honest 2C₀ for piece 2: Total ≤ 0.57 + 2C₀ + 12.73C₀ + 7.06 + 0.09 + 0.29 = 14.73·C₀ + 7.97. C₀(t) ≈ 5–7 for t ∈ [10, 1000]: 14.73·6 + 8 ≈ 96.4 at t≈50, while the baked bound 10.5·log(52)+48 ≈ 89.5. So 14.73C₀ + 7.97 ≈ 96 > 89.5 — the honest 2C₀ assembly EXCEEDS the baked 10.5/48 at moderate t. But the MEASURED |R| ≤ 4.75 (E-021) — the bound has ~20× slack vs the true value. So the TRACED assembly with honest counting can't hit 10.5/48... unless piece 3 is also honestly re-tightened? Let me not spiral — the key question: what does 5f need to PROVE in Lean, and with what constants? Actually — hold on. Let me step back and reconsider piece 2. Is it REALLY 2·C₀? The near window |γ−t|<1. Note the sum Σ_{|γ−t|<1} 1/|s₀−ρ| with s₀ = 2+it: |s₀−ρ| ≥ 1 since re ρ ≤ 1... hmm wait, actually — we know more: re ρ ∈ (0,1), so |s₀−ρ| = √((2−β)² + (t−γ)²) ≥ 1 with equality possible. Terms ≤ 1 each. Count ≤ 2C₀(t). Hmm, so yes 2·C₀(t). UNLESS the zero count in (t−1, t+1) is bounded by C₀(t) via a DIFFERENT route: N(t+1) − N(t−1) ≤ F(t+1) − F(t−1) + S(t+1) + S(t−1). F(t+1) − F(t−1) ≈ (1/2π)·2·log(t/2π) = (1/π)log — twice the one-unit F-difference. So no, the two-unit count is honestly ≈ 2·C₀(t). OK so this is a REAL accounting question about D-056 (the paper's piece 2). Let me look at what the ASSEMBLED Lean constants need: the margin's B(n) uses 10.5·log(T+2) + 48 (Hhat T = 3·C0hat² + 10.5·log(T+2) + 48). The 3·C0hat² term — where does that come from? Hhat bounds |ζ′/ζ| on the contour including the near sum: |ζ′/ζ(s)| ≤ |R(s)| + Σ_near 1/|s−ρ| ≤ [10.5 log + 48] + (near count)·(1/clearance). The clearance from the L3 pigeonhole is 1/(3·C0hat) and the near count ≤ ...·C0hat ⟹ near sum ≤ 3·C0hat² — THERE's the 3·C0hat² in Hhat! So Hhat = 3·C0hat² + [10.5 log + 48] = near-sum + R-bound. The near sum's count factor: if the honest count is 2·C0hat (two units), the near sum ≤ 3·C0hat·(2·C0hat)?? — hmm wait, no: the L3 pigeonhole gives T in a UNIT window [a, a+1] avoiding zeros by 1/(3·C0hat(a+1)); the zeros within |γ−T|<1 sit in a two-unit window... the near sum Σ_{|γ−T|<1} 1/|s−ρ| ≤ (count)·(3·C0hat) ≤ 2·C0hat·3·C0hat = 6·C0hat². But Hhat has 3·C0hat²! So Hhat's near-sum term ALSO assumes the one-C0hat count for the |γ−T|<1 window?? Hmm wait, let me look at D-037's assembly to see how Hhat was derived. This is getting deep. Let me read D-037 (the R-004 assembly) §sides/Hhat derivation. Actually — hold on. Let me reconsider the pigeonhole geometry. L3: T ∈ [a, a+1] with |T − γ| ≥ 1/(3·C0hat(a+1)) for all γ in [a, a+1]... but the zeros OUTSIDE [a, a+1] (e.g. γ ∈ (a+1, a+2)) could be within |γ − T| < 1 of T! The near sum at height T runs over |γ − T| < 1 ⊂ (a−1, a+2) — THREE unit windows?? Hmm, no: T ∈ [a, a+1]; |γ−T|<1 ⟹ γ ∈ (T−1, T+1) ⊂ (a−1, a+2). The count there ≤ 3·C0hat-ish. And the clearance: does L3's T avoid zeros in (a−1, a) ∪ (a+1, a+2) too? exists_zero_avoiding_T as proved: "∀ ρ, IsNontrivialZero ρ → a ≤ ρ.im → ρ.im ≤ a+1 → 1/(3·C0hat(a+1)) ≤ |ρ.im − T|" — ONLY the window zeros. A zero just outside the window, γ = a + 1 + ε, could be at |γ − T| = ε + (a+1−T) — arbitrarily small! So the near-sum bound Σ_{|γ−T|<1} 1/|s−ρ| has NO clearance control from L3 as stated... unless the contour is chosen at T where the FULL |γ−T|<1 neighborhood is avoided. Hmm — but wait, this is what ii′-4's L3 was designed for (D-036 §2). Let me check D-036 §2's actual statement. Line 54+ of D-036. Let me read.
Important accounting question surfaced. Let me read D-036 §2 (the zero-avoiding T and the Hhat near-sum derivation in D-037) before designing 5f.
tool: Read
input
{
  "file_path": "D:\\Python\\Quantum\\research\\derivations\\D-036-zeta-contour-constants.md",
  "offset": 54,
  "limit": 40
}
#1714 assistant 2026-08-24 07:48:35.128 UTC · 6770→31645 tok open ⤢
thinking (75598 chars)
Now I see the H(T) derivation (D-036 §2): Line 55-60: "Zeros in [√n, √n+1]: ≤ C₀(√n+1). Pigeonhole: some gap ≥ 1/(C₀+1); choose T at a gap center ⟹ d_min ≥ 1/(3C₀(√n+1)). Then on the horizontal segments: |ζ′/ζ(s)| ≤ C₀(T)/d_min + A log(T+2) + B₀ ≤ 3C₀(T)² + A log(T+2) + B₀ =: H(T)." So the near sum at the chosen T is bounded C₀(T)/d_min where d_min = 1/(3C₀(√n+1)) — and C₀(T) is used as the count of |γ−T|<1. This is the SAME convention: one C₀ for the |γ−T|<1 window. Hmm, wait — the pigeonhole as stated: zeros in [√n, √n+1] counted by C₀(√n+1); T chosen in [√n, √n+1] at a gap center with d_min ≥ 1/(3C₀) — but only from zeros IN [√n, √n+1]. A zero at √n+1+ε (just outside the window) is at distance ε from the window boundary — T could be near √n+1 and the zero just outside could be at distance < d_min from T! Hmm, unless the pigeonhole is applied to the LARGER window. Let me look at how ii′-4's L3 (exists_zero_avoiding_T) was actually stated and used: "∃ T ∈ [a, a+1], ∀ ρ zero with a ≤ im ρ ≤ a+1: |ρ.im − T| ≥ 1/(3·C0hat(a+1))". Only window zeros. So the clearance is only guaranteed vs window zeros. But the near sum at height T runs over |γ − T| < 1 which includes zeros in (a−1, a) and (a+1, a+2) — those have NO clearance guarantee! Hmm, wait. But actually — is that a problem in the PAPER's accounting? The near sum Σ_{|γ−T|<1} 1/(s−ρ): for the horizontal contour at height T, s = σ + iT, |s − ρ| ≥ |T − γ| ≥ d_min only for γ in the window. For γ just outside the window (say γ = a+1+ε), |T−γ| could be tiny if T is near a+1... BUT: does the R-bound's near/far split save it? R(s) = ζ′/ζ(s) − Σ_{|γ−T|<1} 1/(s−ρ) — the R-bound |R(s)| ≤ A log + B₀ holds everywhere (no clearance needed). Then |ζ′/ζ(s)| ≤ |R(s)| + Σ_{|γ−T|<1} 1/|s−ρ|. The near sum needs BOTH the count AND the per-term clearance 1/|s−ρ| ≥ ... for s on the horizontal at height T: |s−ρ| ≥ |T−γ|. For γ ∈ window: ≥ 1/(3C₀). For γ outside the window but within |γ−T|<1: γ ∈ (a−1, a) ∪ (a+1, a+2) with T ∈ [a, a+1]: |T − γ| can be arbitrarily small!! Hmm, hold on — but if |T − γ| < 1/(3C₀) for an out-of-window zero, then γ is within 1/(3C₀) of T... T ∈ [a, a+1], γ ∈ (a+1, a+2): |γ−T| ≥ γ − (a+1)... if T is at distance ≥ δ from BOTH endpoints a and a+1, then out-of-window zeros (which are ≥ 0 from the boundary... no — an out-of-window zero can be AT a+1+ε for any ε > 0, so its distance to T ≤ a+1 is ≥ (a+1) − T. If the pigeonhole placed T in the MIDDLE of the window (distance ≥ 1/4 from each endpoint), then out-of-window zeros have |γ − T| ≥ 1/4 − ... hmm: γ > a+1 (outside [a, a+1]) and T ≤ a+1: |γ − T| = γ − T ≥ γ − (a+1) + (a+1) − T ≥ (a+1) − T ≥ (window − midpoint distance). If T ∈ [a+1/4, a+3/4] then |γ−T| ≥ 1/4 for γ ∉ (a−... wait γ could also be in (a−1, a): |γ−T| ≥ T − a ≥ 1/4. And window zeros: ≥ 1/(3C₀) ≤ 1/4-ish. So with T centered, ALL |γ−T|<1 zeros have clearance ≥ min(1/(3C₀), 1/4) = 1/(3C₀) (C₀ ≥ 2). So the near sum ≤ count·3C₀ where count ≤ 3·C₀ (three unit windows) → 9·C₀². But D-036 wrote 3·C₀² — using count ≤ C₀ for the near window. Hmm OK. So there are TWO accounting gaps between the paper sketch (D-036) and a fully honest Lean assembly: (i) the near-window count is really 2–3 unit-window counts, not one; (ii) the pigeonhole clearance only covers window zeros (need T centered or a two-sided pigeonhole). BUT — wait. These are the PAPER-side accounting for ii′-6 (the L0 assembly), not 5f! 5f is just the R-bound: |R(s)| ≤ 10.5 log + 48. The R-bound's D-056 proof has only ONE place where the count enters with a tight constant: piece 2 (the near sum at the reference point s₀). Everything else (pieces 1, 3–6) is count-free or uses the count with room (piece 3's per-interval counts). So for 5f specifically, the question is whether the honest piece-2 count (2·C₀(t) for the two-unit window) breaks the 10.5/48 fold. From my computation: with 2C₀ for piece 2, total = 14.73·C₀(t) + 7.97 ≤ 14.73·(0.433 log + 0.886 loglog + 2.9) + 7.97 = 6.38 log + 13.05 loglog + 42.72 + 7.97 = 6.38 log + 13.05 loglog + 50.69. Fold loglog ≤ log/e: ≤ (6.38 + 13.05/e)·log + 50.69 = (6.38 + 4.80)·log + 50.69 = 11.18 log + 50.69. The baked constants: 10.5/48. 11.18 > 10.5 and 50.69 > 48. BREAKS. Hmm. But wait — is the paper's piece-2 one-C₀ convention actually DEFENSIBLE? Let me think again... |γ − t| < 1. Hmm, what if the near-sum convention in the paper is |γ − t| ≤ 1 with the count C₀(t) being the count of |γ−t| ≤ 1 — i.e., the paper's C₀(t) was ALWAYS meant as the two-unit-window count? D-036 §0 line 20 defines n(t) := N(t+1) − N(t) (one unit) — but maybe D-056's C₀(t) := F(t+1) − F(t) + S_b(t+1) + S_b(t)... that's N(t+1)−N(t) — ONE unit. So no, one unit. Hmm, unless the two-unit count really is ≤ C₀(t) via... N(t+1) − N(t−1) ≤ F(t+1) − F(t−1) + S(t+1) + S(t−1). F(t+1)−F(t−1) ≈ (2/2π)·log(t/2π) + ... ≈ 2 × (one-unit F-difference). So the two-unit count ≈ 2·C₀(t) − adjustments. Definitely 2×. So D-056's assembly has a genuine factor-2 gap at piece 2. What are the options? Option 1: Re-fold with honest constants and check the margin still works. The honest fold gives ≈ 11.2 log + 50.7 — exceeds the baked 10.5/48. The margin would need re-verification with the new constants: B(n)'s leading coefficient 4·(0.1443 + A/2): A = 11.2 → 4·(0.1443+5.6) = 22.97 vs the old 21.6 — a ~6% increase in the leading √n log n coefficient. The margin at N₀ = 80000 had huge slack (margiñ(8×10⁴) ≥ 8001 certified vs the base requirement...) — actually the margin trail: margin(10⁵) ≈ 9.3×10⁴ measured. A 6% increase in the leading coefficient reduces the margin by... at n = 10⁵, √n log n ≈ 316·11.5 ≈ 3634; ×(22.97−21.6) ≈ ×1.37/21.6... the margin is ~9.3×10⁴ and the B-side grows by maybe ~5%: margin shrinks by ~5-10% — still hugely positive. The N₀ crossover might move slightly. This is doable but changes the baked constants everywhere (Hhat, marginTilde, the certified base points margiñ(8×10⁴) ≥ 8001, the paper text). COSTLY + freeze-sensitive (paper edits forbidden until ii′-7... the constants are baked in LiSkeleton which is proof-relevant — margiñ base points were CERTIFIED against the current constants). Option 2: Tighten piece 2's INPUT — the near-window count — via a tighter split: |γ−t| < 1 is (t−1, t+1). Bound N(t+1) − N(t−1) DIRECTLY via Trudgian: F(t+1)−F(t−1) + S(t+1) + S(t−1) — this is the honest 2-unit count ≈ 2·C₀(t) − 2.9-ish? Let me compute: F-difference over 2 units ≈ (1/π)·log(t/2π) ≈ 2·(0.433 log(t+2) − 2.9-ish F-part)... the S-pair: S(t+1)+S(t−1) ≈ 2·(0.137 log + 0.443 loglog + 1.588). The honest 2-unit count = 2·C₀(t) − small. No real savings. Option 3: Sharpen piece 2's PER-TERM bound: |s₀ − ρ| ≥ √(1 + (t−γ)²) (since |re(s₀−ρ)| = 2−β ≥ 1). So 1/|s₀−ρ| ≤ 1/√(1+(t−γ)²) — for the near window, the terms with |t−γ| close to 1 are smaller. Split the near window into sub-intervals: |t−γ| ≤ 1/2 and 1/2 < |t−γ| < 1: the inner ≤ C₀(t)-ish (one unit window!) × 1, the outer ≤ 2·C₀... hmm — inner window |t−γ| ≤ 1/2 ⊂ one unit window ≤ C₀(t); outer (1/2 < |t−γ| < 1): two half-windows, count ≤ 2·C₀... per-term ≤ 1/√(1+1/4) = 2/√5 ≈ 0.894. So piece 2 ≤ C₀(t)·1 + 2·C₀(t)·0.894?? — worse than... no wait, outer count is ≤ 2 unit windows MINUS... ugh, the outer annulus (1/2, 1) around t is contained in (t−1, t+1) — two windows — count ≤ 2C₀(t) − ... this gives ≤ C₀ + 0.894·2C₀ = 2.79·C₀ — worse than 2C₀. No. Hmm, actually: |t−γ|<1 window: count ≤ 2·C₀(t) is the ONLY honest bound (without fancier density input). So piece 2 ≤ 2·C₀(t) honestly. Option 4: Reduce piece 3's coefficient to compensate. Piece 3 currently 12.73·C₀ + 7.06 (from 4.5√2·[2C₀ + 1.11]). Can it be tightened? The 4.5 = |s₀−s| ≤ |2−σ| ≤ 4.5 (σ ∈ [−5/2, 3]). The σ range: why −5/2? D-036's contour has σ₀ = −5/2 (left vertical). For the R-bound used at the CONTOUR (the horizontals at height T), σ ∈ [−5/2, 2√n]... The R-bound is applied on the horizontal segments σ ∈ [−5/2, 2√n] and the left vertical σ = −5/2. Hmm, σ up to 2√n — D-056's σ ≤ 3?! The right part σ ∈ [3, 2√n] uses the stepping argument (D-036 §3 II/IV) not the R-bound... Actually the R-bound for σ ∈ [−5/2, 3] + the stepping for σ > 3. So |s₀−s| ≤ 4.5 is needed at σ = −5/2. Tighten the far-sum per-interval accounting: D-056 used |s₀−ρ| ≥ (1+|t−γ|)/√2 and |s−ρ| ≥ |t−γ|, giving 4.5√2/(k(k+1)). Alternative: |s−ρ| = √((σ−β)²+(t−γ)²) ≥ √((t−γ)²) = |t−γ| ✓; |s₀−ρ| ≥ √(1+(t−γ)²) ✓ (2−β ≥ 1 exactly? β < 1 ⟹ 2−β > 1; β ≤ 1 ⟹ ≥ 1 ✓). Term ≤ 4.5/(|t−γ|·√(1+(t−γ)²)). For k ≤ |t−γ| < k+1: ≤ 4.5/(k·√(1+k²)) ≤ 4.5/(k²). Σ_{k≥1} 4.5·2·C₀/k² = 9·C₀·π²/6 = 14.8·C₀ — WORSE than 12.73. D-056's (1+|t−γ|)/√2 trick is better. Hmm — actually D-056's term: 4.5√2/(|t−γ|(1+|t−γ|)) ≤ 4.5√2/(k(k+1)) for |t−γ| ≥ k ✓ (x(1+x) ≥ k(k+1) for x ≥ k ✓). Sum over intervals: left side intervals k=1..~t, right side k=1..~t plus tail. ≤ 4.5√2·C₀(t)·[Σ_{k≤t} 1/(k(k+1)) + Σ_{k≤t, right} C₀(2t)/C₀(t)/(k(k+1)) + tail] = 4.5√2·[C₀(t)·(1−1/(t+1)) + C₀(2t)·(1−...) + 0.53]. ≈ 6.364·[C₀ + C₀(2t) + 0.53] ≈ 6.364·[2C₀ + 0.58 + 0.53]. To tighten: C₀(2t) ≤ C₀(t) + 0.58 — already used. The 4.5√2 factor: |s₀−s| = 2−σ ≤ 4.5 only at σ = −5/2; could split by σ? The R-bound is needed uniformly on σ ∈ [−5/2, 3]. The extreme σ = −5/2 drives 4.5. If we split the contour usage: on the horizontals σ ∈ [−5/2, 3]... the horizontal integral bounds use sup over the whole segment — need the σ = −5/2 endpoint. Hmm. Alternatively — reduce piece 3 by using |s−ρ| ≥ |t−γ| AND |s₀−ρ| ≥ max(1, |t−γ|)... that's what (1+x)/√2 does. OK this constant-tightening spiral is exactly the kind of thing E-028's 26× slack says is unnecessary. The measured max |R| = 4.75 at t up to 1000 (E-021) vs the bound 10.5·log(1002)+48 ≈ 120. The traced assembly is lossy by ~25×. The honest fix for the factor-2: RE-FOLD the assembly with honest constants and re-verify the margin. But the margin constants are baked in LiSkeleton (10.5/48 in Hhat/marginTilde) with CERTIFIED base points... Hmm wait, actually — hold on. Let me re-examine whether piece 2's 2× is really needed, ONE more time. The near sum Σ_{|γ−t|<1} 1/|s₀−ρ|. |s₀−ρ| ≥ 1... but actually MORE: |s₀−ρ|² = (2−β)² + (t−γ)² ≥ (2−β)² ≥ 1. Yes ≥ 1. And the count of |γ−t|<1... Hmm — actually WAIT. Is the count of |γ − t| < 1 really 2·C₀? The window (t−1, t+1) — 2 units. But C₀(t) as DEFINED in D-056 is F(t+1)−F(t) + S_b(t+1) + S_b(t) — hmm, what if D-056 intended C₀(t) as the count of the TWO-unit window |γ−t|≤1, i.e., N(t+1)−N(t−1) ≤ F(t+1)−F(t−1) + S_b(t+1)+S_b(t−1), and the "F(t+1)−F(t)" in the text is a typo for F(t+1)−F(t−1)? Let me check the numeric value: F(t+1)−F(t−1) at t=10: F(x) = (x/2π)log(x/2π) − x/2π + 7/8. F(11)−F(9): F'(x) ≈ (1/2π)log(x/2π) ≈ 0.159·log(1.6) ≈ 0.075 per unit at x=10... so F(11)−F(9) ≈ 0.15. Plus S_b pair ≈ 2·(0.137·2.3 + 0.443·0.83 + 1.588) ≈ 2·2.27 = 4.54. Total ≈ 4.7 ≈ matches C₀(10) ≈ 4.78 (0.433·2.48+0.886·0.907+2.9 = 4.78). And the ONE-unit version: F(11)−F(10) ≈ 0.075 + S pair 4.54 ≈ 4.6 — nearly the same because the S_b pair dominates!! The F-difference is tiny compared to the S_b slack. So the two-unit count ≈ the one-unit C₀ to within ~0.1! OH. That's the resolution. The C₀(t) majorant is DOMINATED by the S_b pair (2·1.588 = 3.18 of the ~4.7 total), and the F-difference for one vs two units differs by only ~0.075. So C₀(t) as a CLOSED-FORM majorant (0.433 log(t+2) + 0.886 loglog(t+2) + 2.9) can absorb the two-unit window count — IF the closed form honestly majorizes the two-unit Trudgian count. Let me check: two-unit count ≤ F(t+1)−F(t−1) + S_b(t+1) + S_b(t−1). Need ≤ 0.433·log(t+2) + 0.886·loglog(t+2) + 2.9? F(t+1)−F(t−1) = ∫_{t−1}^{t+1} F'(x) dx where F'(x) = (1/2π)log(x/2π). At t=10: ≈ 2·0.159·log(10/6.28) ≈ 0.318·0.466 ≈ 0.148. S_b(t+1)+S_b(t−1) = 0.137·(log 11 + log 9) + 0.443·(loglog 11 + loglog 9) + 2·1.588 = 0.137·(2.398+2.197) + 0.443·(0.874+0.788) + 3.176 = 0.629 + 0.736 + 3.176 = 4.54. Total: 4.69 ≤ 4.78 ✓ (margin 0.09 at t=10). Hmm — TIGHT (2% margin). At larger t it should improve (the closed form's 0.433 log vs the F-part's (1/π)log = 0.318 log... wait: the two-unit F-difference ≈ (1/π)·log(t/2π) ≈ 0.318·log(t)−0.586 and the closed form has 0.433·log(t+2) for the F+log parts... S_b pair: 0.137·2·log t + 0.443·2·loglog t + 3.176 = 0.274 log t + 0.886 loglog t + 3.176 vs closed form 0.433 log(t+2) + 0.886 loglog(t+2) + 2.9. Difference: (0.433−0.318)·log + (0.274·... hmm let me redo: two-unit honest = F-diff + S-pair = (1/π)log(t/2π)-ish + 0.274 log t + 0.886 loglog t + 3.176. Total log coefficient: 0.318+0.274 = 0.592 vs closed form 0.433. The closed form UNDERCOUNTS the two-unit log coefficient (0.433 < 0.592)! At large t, the honest two-unit count EXCEEDS the closed form 0.433 log + ...! Wait, that can't be right — let me recompute the one-unit version: one-unit count ≤ F(t+1)−F(t) + S_b(t+1)+S_b(t) ≈ (1/2π)·log(t/2π)·1 + 0.274 log + 0.886 loglog + 3.176 ≈ 0.159·log + 0.274·log + ... = 0.433·log + 0.886·loglog + 3.176-ish. AH — there it is: 0.433 = 0.159 (one-unit F-difference coefficient) + 0.274 (the S-pair log coefficient). So C₀(t)'s 0.433 log coefficient is exactly the ONE-unit honest count's log coefficient. The TWO-unit honest count has log coefficient ≈ 0.318 + 0.274 = 0.592 > 0.433. So the two-unit window count is NOT ≤ C₀(t) — it exceeds it at large t (break-even when 0.159·log t ≈ the constant slack ~ −0.3...: (0.592−0.433)·log t vs (2.9 − 3.176 − F-consts...) — the closed form's constant 2.9 vs honest 3.176: already negative; so the two-unit count exceeds C₀(t) essentially everywhere). CONCLUSION: D-056's piece 2 (and D-036's §1 near-sum and §2's H(T) count) genuinely need the two-unit window count ≈ 2·C₀(t)−ish, and the one-C₀ convention is an undercount by ~0.16·log t + 0.3 in the count, propagating to ~14.73·C₀+7.97 vs 13.73·C₀+7.97 in the R-bound fold. This is a REAL (if small) accounting slip in D-056's assembly — of the D-054-review class (this is exactly what the adversarial gauntlet is for — and it slipped through). Hmm wait — but E-028 verified the R-bound numerically (26× slack) — so the THEOREM (10.5/48 bound) is true; it's the TRACED PROOF that has a gap. For the Lean 5f, I need a PROOF of the 10.5/48 bound — and the traced assembly with honest counting gives 11.2 log + 50.7, which does NOT imply 10.5 log + 48 (at t=10: 11.18·2.48+50.7 = 78.4 vs 10.5·2.48+48 = 74.0 — exceeds!). So the honest assembly as-is does NOT prove the baked bound. Options: (A) Tighten the assembly to honestly fit 10.5/48. The slack analysis: the far-sum piece 3 (12.73·C₀ + 7.06) dominates. Can it be tightened enough? We need to save ~1·C₀ + 2.7 (to absorb the extra C₀ in piece 2 and the constant growth): target total ≤ 10.5 log + 48 with C₀ ≤ 0.433L + 0.886LL + 2.9: Need 13.73·C₀ + 7.97 + extra-C₀ ≤ A·L + 48... currently 14.73·C₀ + 7.97 ≤ 14.73·(0.433L + 0.886LL + 2.9) + 7.97 = 6.38L + 13.05LL + 50.7. To fit 10.5L + 48: need to save 13.05·LL + 2.7 + (6.38+13.05/e−10.5)·L = 13.05LL + 0.68L + 2.7. From piece 3's 4.5√2·(2C₀+1.11): the per-term bound 4.5√2/(k(k+1)) is lossy: the actual term is 4.5/(x√(1+x²)) with x = |t−γ|; 4.5√2/(x(1+x)) vs 4.5/(x√(1+x²)): ratio √2·√(1+x²)/(1+x) → √2·x/(1+x) → √2 ≈ 1.414 as x→∞. So D-056's far bound is ≤ √2 × the true sum — the loss is up to 41%. Tightening piece 3 to 4.5·Σ C₀/(k·√(1+k²))... per-interval: term ≤ 4.5/(k·√(1+k²)); Σ_{k≥1} 1/(k√(1+k²)) = ? ≈ 1/1.414 + 1/(2·2.236) + 1/(3·3.16) + ... ≈ 0.707 + 0.224 + 0.105 + 0.062 + ... ≈ Σ ≈ 1.32-ish? vs Σ1/(k(k+1)) = 1. Hmm — 1.32 > 1, so the per-interval sharpened sum is BIGGER than the (1+x)/√2 form?? No wait: (1+x)/√2 ≤ √(1+x²)? (1+x)²/2 = (1+2x+x²)/2 vs 1+x²: (1+x)² ≤ 2(1+x²) ⟺ 1+2x+x² ≤ 2+2x² ⟺ 0 ≤ 1−2x+x² = (1−x)² ✓. So (1+x)/√2 ≤ √(1+x²), i.e., 1/√(1+x²) ≤ √2/(1+x) — the sharpened term 4.5/(x√(1+x²)) ≤ 4.5√2/(x(1+x)) ✓ D-056's is an upper bound of the sharpened one. The sharpened sum: Σ_k 4.5·count_k/(k√(1+k²)) where count_k ≤ C₀ for each unit interval (both sides: 2 intervals per k) — ≤ 4.5·C₀·[2·Σ_{k≥1} 1/(k√(1+k²))]·... but the C₀(2t) for the right side... the sum Σ 1/(k√(1+k²)): numerically ≈ let me estimate: k=1: 0.707, k=2: 0.2236, k=3: 0.1054, k=4: 0.0606, k=5: 0.0392, k=6: 0.0277, k=7: 0.0206, k=8: 0.0158, k=9: 0.0125, k=10: 0.0101, tail ≈ Σ_{k>10} 1/k² ≈ 0.1. Total ≈ 0.707+0.224+0.105+0.061+0.039+0.028+0.021+0.016+0.012+0.010+0.10 ≈ 1.32. Hmm so 2-sided: 2·1.32·4.5·C₀ = 11.9·C₀ vs D-056's 12.73·C₀ — saves only 0.8·C₀. Not enough (need ~1.7·C₀ + constants). (B) Accept the honest constants and RE-FOLD the whole margin: A = 11.2, B₀ = 50.7 (say A = 11.5, B₀ = 52 with rounding). This changes Hhat (10.5→11.5, 48→52), marginTilde's baked numbers, and re-runs the base-point certification + the margin convexity (D-057's proof is structural — the constants A/B₀ enter as parameters? Let me check: marginTilde's def has 10.5 and 48 HARDCODED (line: `(2 / 3) * C0hat T + 10.5 * Real.log (T + 2) + 48`). Changing them touches: marginTilde_convex (proved in session 011 — the 8-block ψ-table with specific constants!), sInfty_lower_bound (no), LiBasePoints (the certified interval bounds margiñ(8×10⁴) ≥ 8001, margiñ(10⁵) ≥ 85501 — the CERTIFIED numbers would drop ~5–10% but remain positive), lambda_pos_finite_height_verified (the assembly — constant-agnostic if the hypotheses are about marginTilde). The convexity proof (session 011) used specific numeric constants — its IIMaj″ ≤ 1.316 < 2 bound and the ψ-table blocks — would need re-verification with 11.5/52. The paper's §3 has the 10.5/48 trail in text (margin trail footnote) — frozen until ii′-7, but at ii′-7 the paper's appendix gets updated anyway. The COST: re-verify convexity + re-certify base points + paper text touch at ii′-7. The GAIN: honesty (the current 10.5/48 traced assembly is unprovable as it stands). (C) Hmm — wait. Actually, let me reconsider. Is there a way to keep 10.5/48 by being smarter about the near window in piece 2? The near sum Σ_{|γ−t|<1} 1/|s₀−ρ|: split into |γ−t| ≤ 1/2 and 1/2 < |γ−t| < 1... no — count issue remains. Hmm, actually — WAIT. What about the reference point trick applied differently: instead of bounding Σ_near 1/|s₀−ρ| ≤ count (each term ≤ 1), note that this sum is part of the DIFFERENCE and could be paired with... no, it's a standalone absolute bound. Actually actually actually. Hold on. Let me recompute the two-unit count bound more carefully. The honest two-unit count: N(t+1) − N(t−1) — but for the MULT-weighted near sum we need Σ_{|γ−t|<1} m. Via the perimeter (mult-weighted ZeroCountProp): window counts for (t−1, t] and (t, t+1): Σ ≤ C0hat(t) + C0hat(t+1) ≤ 2·C0hat(t+1). With C0hat(t+1) = 0.433 log(t+3) + 0.886 loglog(t+3) + 2.9. So piece 2 ≤ 2·C0hat(t+1). And piece 3's per-interval counts: left intervals (t−k−1, t−k]: ≤ C0hat(t−k+1) ≤ C0hat(t); right intervals (t+k, t+k+1]: ≤ C0hat(t+k+1) ≤ C0hat(2t+1) for k ≤ t. Etc. The full honest fold will give ≈ 14.73·C0hat(t+1) + 7.97 ≤ 6.38L + 13.05LL + 50.7 (L = log(t+3)-ish). vs target 10.5 log(|t|+2) + 48. At t=10: honest ≈ 6.38·2.56 + 13.05·0.94 + 50.7 = 16.3+12.3+50.7 = 79.3 vs target 74.0. Exceeds. So (A) [tightening] would need to save ~5.3+ at t=10 and the LL/L terms at ∞ — from piece 3's √2 slack (up to 29% of 12.73·C₀ ≈ 3.7·C₀ ≈ 18–25 at these heights) — actually the available slack in piece 3 IS enough if fully harvested: 12.73·C₀+7.06 → ~9.2·C₀+const would save 3.5·C₀ ≈ 17+. But harvesting the √2 slack requires the per-interval sum Σ 1/(k√(1+k²)) ≈ 1.32 vs 1 — wait that's WORSE per unit... I'm confusing myself. Let me just compute D-056's piece-3 exactly vs the sharpened version: D-056: term ≤ 4.5√2/(x(1+x)), x = |t−γ|; per interval k ≤ x < k+1: ≤ 4.5√2/(k(k+1)). Two-sided Σ ≤ 4.5√2·[C₀·Σ_{k=1}^{~t} 1/(k(k+1)) (left) + C₀(2t)·Σ (right) + tail] ≈ 6.364·[C₀·1 + C₀(2t)·1 + 0.53]. Sharpened: term = 4.5/(x√(1+x²)) ≤ 4.5/(k·√(1+k²)) on the interval... but WAIT — x ≥ k gives 1/(x√(1+x²)) ≤ 1/(k√(1+k²)) ✓. Σ_{k≥1} 1/(k√(1+k²)) ≈ 1.32 (computed above) vs Σ 1/(k(k+1)) = 1. So per-interval sharpened: 4.5·1.32 = 5.94 vs D-056's 6.364·1 = 6.364 per side. Saves ~7%. Total piece 3: 5.94·[2C₀ + 1.11] ≈ 11.88·C₀ + 6.6 vs 12.73·C₀ + 7.06. Saves 0.85·C₀ + 0.5 ≈ 5–6.5 at these heights. New total: 0.57 + 2C₀ + 11.88C₀ + 6.6 + 0.38 = 13.88·C₀ + 7.55 ≤ 13.88·(0.433L + 0.886LL + 2.9) + 7.55 = 6.01L + 12.3LL + 40.3 + 7.55 = 6.01L + 12.3LL + 47.8 ≤ (6.01 + 12.3/e)L + 47.8 = (6.01+4.52)L + 47.8 = 10.53L + 47.8. vs 10.5L + 48 — 10.53 > 10.5 STILL breaks (barely!). Hmm. And at t=10: 6.01·2.56+12.3·0.94+47.8 = 15.4+11.6+47.8 = 74.8 vs 74.0 — still barely over. GRRR. More tightening? The per-interval count on the LEFT at interval k is C₀(t−k+1) ≤ C₀(t) — could weight: Σ_k C₀(t−k)/(k√(1+k²)) — for small k (dominant terms), C₀(t−k) ≈ C₀(t); savings negligible. The 4.5 factor (σ = −5/2): if the R-bound's σ range is actually only used on [−5/2, 3]... what if we split: for σ ∈ [−3/2, 3], |s₀−s| ≤ 3.5; the σ ∈ [−5/2, −3/2] strip handled via FE-reflection (5d machinery) with its own constants? That's a different proof structure — D-056 chose the direct route precisely to avoid that. Hmm. Honestly, the cleanest is (B): re-fold with honest constants A = 11.5, B₀ = 52 (round up from 11.18/50.7 with margin) — or even A = 12, B₀ = 55 for comfort — and re-verify the downstream. Let me quantify the downstream impact: The R-bound enters the margin via the H-majorant on the contour: Hhat T = 3·C0hat² + A·log(T+2) + B₀. The margin's B-side: 4T·((2/3)·C0hat + A·log + B₀) + 2(e⁴+1)(7·Hhat + 3.3) + ... The leading √n log n coefficient: from D-056 §3: 4·(0.1443 + A/2). A: 10.5 → 11.5: coefficient 21.6 → 23.6 (+9%). Margin at n = 10⁵: measured margin(10⁵) ≈ 9.3×10⁴ (D-056 §3); the B-side grows by ~4·√n·(ΔA/2)·log n ≈ 4·316·0.5·11.5 ≈ 7272... hmm that's ~8% of 9.3×10⁴. New margin(10⁵) ≈ 8.6×10⁴ — still hugely positive. N₀ crossover: was ~32 871 traced / N₀ adopted 80 000 — with the bigger B-side the crossover moves up maybe 10–20%: ~40 000; adopted N₀ = 80 000 still covers it (and the certified base points margiñ(8×10⁴) ≥ 8001 would become ~... the 8001 was the certified lower bound with the OLD constants; with new constants the margin drops ~8%: ~7300 — still positive ✓ but the CERTIFIED interval proof (LiBasePoints) is constant-specific and would need re-running. The convexity proof (D-057, session 011 Lean) is structural but has baked numeric comparisons (1.316 < 2 etc.) that shift slightly — need re-checking. The paper §3 text has the constants (frozen until ii′-7). Cost estimate for (B): LiSkeleton constant edits + re-run session-011 convexity proof (may need block re-tuning) + LiBasePoints re-certification + paper text at ii′-7. ~1–2 sessions of rework, all mechanical. Cost estimate for (A) [fully tighten to keep 10.5/48]: the piece-3 sharpening to per-interval 1/(k√(1+k²)) sums (the Σ = 1.32 constant needs a Lean-provable closed form — a digamma/trig value or an integral bound) + MORE sharpening elsewhere (~0.03·L + small constants — very tight) — likely fails without a structurally different route (FE-reflection split). Risky, multi-session, and even then 10.53 vs 10.5 is knife-edge — likely impossible with this assembly shape. There's also (D): pick the near window SMARTER — define R(s) with the near sum over |γ−t| < 1 but split the count as C₀(t−1)+C₀(t) ≤ 2C₀(t)... no saving. Hmm — hmm, hold on, wait. Let me reconsider option (A) once more, because there might be more slack in piece 2 itself: Σ_{|γ−t|<1} 1/|s₀−ρ| with |s₀−ρ| = √((2−β)² + (t−γ)²) ≥ √(1 + (t−γ)²). The terms with |t−γ| near 1 contribute ≤ 1/√2. Per-interval sharpening on the NEAR sum: |t−γ| ≤ 1/2: count ≤ C₀(t) (one unit window (t−1/2, t+1/2] ⊂ ... hmm — (t−1/2, t+1/2] is a unit window ✓ count ≤ C₀(t)); per-term ≤ 1. Outer: 1/2 < |t−γ| < 1: two half-unit windows ⊂ two unit windows; count ≤ 2·C₀(t) − [inner overlap]... honestly ≤ 2C₀(t); per-term ≤ 1/√(1.25) = 0.894. Total: C₀ + 0.894·2C₀ = 2.79·C₀ — worse than the straight 2C₀. The straight 2C₀ is better. OK. What about |s₀−ρ| ≥ √(1+x²) per interval in the OUTER annulus: x ∈ (1/2, 1): per-term ≤ 1/√(1+1/4) = 0.894 — same. No. So piece 2 honest = 2·C₀(t) is optimal with the Trudgian input. TOTAL honest minimum ≈ 13.88·C₀ + 7.55 ≈ 10.53·L + 47.8 — JUST over 10.5/48. The 10.5/48 constants are genuinely unprovable from this assembly shape (they were derived FROM the faulty one-C₀ piece 2). Wait, actually — one more idea for (A): the digamma-difference piece 6 (0.29) and pieces 4–5 (0.045 each) and piece 1 (0.57) have slack: piece 1's Z₂ = 0.57 is exact-ish. Constants: 0.57 + 7.06 + 0.09 + 0.29 = 8.01 vs the folded 7.97 + ... The L-side: 13.88·0.433 = 6.01. To hit 10.5: need 6.01 + 12.3/e ≤ 10.5 ⟺ 6.01 + 4.524 = 10.534 > 10.5. Off by 0.034·L. The loglog fold loglog u ≤ (1/e)·log u is lossy for small u... at t=10: loglog(12) = 0.91 vs (1/e)log(12) = 0.914 — nearly tight there. Alternatively fold loglog ≤ c·log with a better constant on a restricted range? loglog u ≤ (1/e) log u is exact-optimal globally (equality at u = e^e). At u = t+2 = 12: LL/L = 0.91/2.48 = 0.367 vs 1/e = 0.368. No gain. Reduce piece 3's per-interval sum constant: Σ 1/(k√(1+k²)) — could push the first interval's exact value: k=1: 1/√2 = 0.7071; the D-056 form gives 1/(1·2) = 0.5 — wait, D-056's per-interval bound 4.5√2/(k(k+1)) at k=1: 4.5·1.414/2 = 3.182; sharpened: 4.5·0.7071 = 3.182 — SAME (equality at k=1: √2/(1·2) = 1/√2 ✓). At k=2: D-056: 4.5√2/6 = 1.0607; sharpened: 4.5/(2√5) = 1.0062. Sum over k of the ratio → the 7% computed. To do better, use the EXACT term 4.5/(x√(1+x²)) with x per-interval lower bound k: already did. Use x·(1+x²)^{1/2} ≥ (k+1)/... no, lower bound is k. Alternatively parametrize intervals by midpoints? Diminishing. The real slack: the right-side intervals use C₀(2t) (count up to height 2t) — C₀(2t) ≈ C₀(t) + 0.433·log 2 ≈ C₀(t) + 0.30. And the tail 0.53. Piece 3 total ≈ 4.5·1.32·(2C₀ + 0.3 + 0.53)-ish. Fine. So: honest best ≈ 10.53L + 47.8 vs baked 10.5L + 48. SO CLOSE. But over. And any further tightening (0.03·L ≈ 0.08 at t=10) is within the rounding noise of these estimates — it might actually fit with fully careful bookkeeping! E.g., piece 3's tail 0.53 → sharper; the C₀(2t) ≤ C₀(t)+0.58 → +0.30 actual; pieces 4–6 exact: 0.045+0.045+0.29 → maybe 0.30 total; Z₂ = 0.57 → 0.56996. Marginal gains ≈ 0.2–0.3 — comparable to the 0.08–0.5 gap. NOT robust. Knife-edge. Not the way. DECISION LEAN: (B) re-fold with honest constants. But this has real downstream cost and touches baked constants — ANOTHER user decision point. OR — actually, wait. Let me reconsider the whole thing once more. Hmm — hold on. Let me re-examine D-056's piece 2 once more. "2. Near at s₀: |s₀−ρ| ≥ 2 − β ≥ 1 ⟹ Σ_{|γ−t|<1} 1/|s₀−ρ| ≤ C₀(t)." Hmm wait — what if the intended reading is that C₀(t) denotes the count of |γ−t|≤1 throughout D-056 (a DIFFERENT C₀ than D-036's)? D-056 says "The zero-count input is the HONEST Trudgian form (D-036 §0 erratum): C₀(t) := F(t+1)−F(t) + S_b(t+1) + S_b(t)". F(t+1)−F(t) is the one-unit F-difference. So C₀(t) is the one-unit count. UNLESS F(t+1)−F(t) is a typo for F(t+1)−F(t−1)... As computed, the closed form 0.433 log + 0.886 loglog + 2.9 matches the ONE-unit honest count (0.159+0.274 = 0.433 ✓). So D-056's C₀ = one-unit count, and piece 2's use for the two-unit window is a genuine gap. CONFIRMED. Also D-036 §2's H(T): "|ζ′/ζ(s)| ≤ C₀(T)/d_min + A log + B₀ ≤ 3C₀(T)² + A log + B₀" — the near sum at height T: count(C₀(T)) × clearance(1/d_min = 3C₀(√n+1)) — TWO gaps: (i) count should be the two/three-unit count (the |γ−T|<1 window with T ∈ [√n, √n+1] spans (T−1, T+1) ⊂ (√n−1, √n+2) — THREE unit windows, or two if T-centered... T ∈ [√n, √n+1] ⟹ (T−1, T+1) ⊂ (√n−1, √n+2) — 3 units! unless the window is |γ−T|<1 ∩ wherever); (ii) the clearance d_min is only against window zeros — zeros in (√n+1, √n+2) have no clearance guarantee. Hmm — but wait: actually the pigeonhole as implemented in ii′-4 (exists_zero_avoiding_T) gives clearance 1/(3·C0hat(a+1)) vs zeros in [a, a+1] only. For the H(T) bound we need clearance vs ALL zeros with |γ−T|<1. A zero at γ = a+1+ε (just above the window): |γ−T| ≥ γ−T > (a+1)−T ≥ 0 — can be < 1/(3C₀)! E.g. T = a+0.9, γ = a+1.05: |γ−T| = 0.15 < 1/(3·5) = 0.067? 0.15 > 0.067 OK — but γ = a+1.02, T = a+0.98: |γ−T| = 0.04 < 0.067. So yes, an out-of-window zero CAN be closer than the clearance. GAP in the D-036 H(T) derivation as well (this is ii′-6 territory, not 5f — but the SAME C0hat²-accounting feeds Hhat which is baked in marginTilde). Hmm — OK wait, but this one has an easy honest fix: apply the pigeonhole to the EXTENDED window [a−1, a+2] (three unit windows, count ≤ 3·C0hat): get T ∈ [a, a+1]... no — the midpoint pigeonhole on [a−1, a+2] with 3·C0hat zeros gives a gap of length ≥ 3/(3C₀+1) — T at the center of a sub-gap within [a, a+1]... the gaps within [a, a+1] that are far from out-of-window zeros: choose T ∈ [a, a+1] avoiding ALL zeros in (a−1, a+2) by 1/(9C₀)-ish (pigeonhole with 3C₀ zeros in the 3-unit window — midpoints in [a, a+1]... need the midpoint grid within [a, a+1] with ≥ 3C₀+1 points ⟹ spacing 1/(3C₀+1) ⟹ clearance 1/(6C₀+2)...). Anyway: honest clearance 1/(c·C₀) vs all |γ−T|<1 zeros, count ≤ 3C₀ ⟹ near sum ≤ 3c·C₀² vs the baked 3·C₀². With c = 6–9: 18–27·C₀² vs baked 3·C₀². Hhat's 3·C0hat² would become ~18–27·C0hat². That's a 6–9× increase in the (log T)⁴-ish term of the margin B-side... The margin's C0hat² term: 2(e⁴+1)·7·3·C0hat² ≈ 2·55.6·7·3·(0.433L+..)² ≈ 2335·(0.433L+0.886LL+2.9)². At n = 10⁵ (T ≈ 317): C0hat ≈ 0.433·5.76+0.886·1.75+2.9 ≈ 2.49+1.55+2.9 = 6.94; C0hat² ≈ 48.2; ×2335 ≈ 112 600 — hmm that's COMPARABLE to the margin 9.3×10⁴! Increasing the C0hat² coefficient 6× would add ~5.6×10⁵ to the B-side — EXCEEDING the margin at 10⁵?! Let me recompute the margin formula: margiñ(n) = S(n) − B̃(n) + 1 where the B-side includes `2 * (Real.exp 4 + 1) * (7 * Hhat T + 3.3)`. Hhat T = 3·C0hat² + 10.5·log(T+2) + 48. At T = √n+1, n = 10⁵: T ≈ 317.2, C0hat(317.2) ≈ 0.433·log(319.2) + 0.886·loglog(319.2) + 2.9 = 0.433·5.766 + 0.886·1.752 + 2.9 = 2.497 + 1.552 + 2.9 = 6.95. 3·C0hat² = 3·48.3 = 144.9. 10.5·log(319.2) = 60.5. Hhat ≈ 144.9+60.5+48 = 253.4. 7·Hhat+3.3 ≈ 1777. ×2·(e⁴+1) = 2·55.6 = 111.2: ≈ 197 600. Hmm — and the margin at 10⁵ is 9.3×10⁴?!? That means the B-side's horizontal-integral term ALONE (197 600) exceeds... wait, margin(10⁵) = S(10⁵) − B(10⁵) + 1 ≈ 9.3×10⁴ requires B(10⁵) ≈ S(10⁵) − 9.3×10⁴. S(n) ≈ (n/2)·log n + (c₁−γ/2)·n − 4 ≈ 0.5·10⁵·11.51 + (0.0231)·10⁵ ≈ 575 650 + 2310 ≈ 578 000. B-side: 2FT + 4T((2/3)C₀ + 10.5 log + 48) + 40·1.3352 + 2(e⁴+1)(7H+3.3) + IIMaj + 1: 2FT ≈ 2·(317/6.28·log(317/6.28))·... F(317) ≈ (317/6.28)·log(50.5) − 50.5 + 0.875 ≈ 50.5·3.92 − 49.6 ≈ 148.4; 2F·T ≈ 2·148.4·317 ≈ 94 100. 4T((2/3)·6.95 + 60.5 + 48) = 4·317·113.1 ≈ 143 400. The (e⁴+1) term ≈ 197 600. 40·1.3352 ≈ 53. IIMaj tiny. Total B ≈ 94 100 + 143 400 + 197 600 + 53 ≈ 435 200. Margin ≈ 578 000 − 435 200 ≈ 142 800. Hmm — I misremembered 9.3×10⁴ (that was margin at a different n or with different constants; D-056 §3 says margin(10⁵) = 9.3×10⁴ — close enough order). Anyway the C0hat²-piece of B at 10⁵ is ~2(e⁴+1)·7·3·48.3 ≈ 111.2·7·144.9/7... let me just: 2(e⁴+1)·(7·Hhat) with Hhat's C0hat² part = 144.9: 111.2·7·144.9 ≈ 112 800. If C0hat²'s coefficient triples (3→18): 111.2·7·869 ≈ 676 000 — EXCEEDS the entire margin! So an 18·C0hat² Hhat would DESTROY the margin at 10⁵ (B-side ≈ 1M > S ≈ 578K). Whoa. Hmm wait, so how did the original assembly survive with 3·C0hat²? Because the near sum's count×clearance = C₀·3C₀ = 3C₀² — the one-unit count convention AND the window-only clearance. The honest accounting (3-unit count 3C₀, full-neighborhood clearance 1/(6–9C₀)) gives 18–27·C₀². The margin survives only if the C0hat² coefficient stays ≤ ~6-ish. Let me see what's actually provable: Near sum ≤ count × clearance. Honest count for |γ−T|<1 with T ∈ [a, a+1]: (T−1, T+1) ⊂ (a−1, a+2): 3 units ⟹ 3·C0hat(a+2). Honest clearance: extend the pigeonhole — the midpoint pigeonhole over [a, a+1] against ALL zeros in (a−1, a+2): ≤ 3C₀ zeros; place ⌈3C₀⌉+1 midpoints in [a+1/4, a+3/4] (say) with spacing ≥ (1/2)/(3C₀) ⟹ clearance ≥ (1/4)/(3C₀+1)-ish ≥ 1/(13·C₀)-ish. Then near sum ≤ 3C₀ · 13C₀ = 39·C₀². vs baked 3·C₀². 13× WORSE. The margin dies (as computed: 13×112 800 ≈ 1.5M > margin). UNLESS the clearance/count split is smarter: Cauchy-Schwarz? Σ 1/|T−γ| over the near zeros — with the pigeonhole giving clearance d vs ALL near zeros, Σ ≤ count/d. Alternatively use the EXPLICIT sum structure: Σ_{|γ−T|<1} 1/|T−γ| — the zeros are 1D points; if T has clearance d from ALL zeros and the count in each unit sub-window is ≤ C₀, then Σ 1/|T−γ| ≤ count(|γ−T|<d... none) + Σ over dyadic shells d ≤ |γ−T| < 1: shell [2^{-j}, 2^{-j+1}) has count ≤ 2·2^{-j+1}-unit windows... Σ ≤ Σ_j C₀·2^j·(shell width 2^{-j+1} → count ≤ C₀·(2 windows per shell...)) — hmm: shell {2^{-j} ≤ |γ−T| < 2^{-j+1}} has width 2^{-j+2}, count ≤ 2^{-j+2}·C₀ per unit... count ≤ C₀·2^{-j+2}/1 = C₀·2^{-j+2} windows?? — no: count per UNIT window ≤ C₀; shell width w = 2^{-j+2} units... for j ≥ 2 the shell is < 1 unit wide: count ≤ C₀ (one window covers it). Σ_j: shells j=1..~log(1/d): count_j ≤ C₀ (each shell ⊂ 1–2 unit windows); per-term ≤ 2^j. So Σ ≤ Σ_{j=1}^{J} C₀·2^j ≈ C₀·2^{J+1} = C₀·(2/d). With d = 1/(3C₀): Σ ≤ 6·C₀². Hmm — 6C₀², better than 39 but still 2× the baked 3C₀². Actually more carefully: Σ_{|γ−T|<1} 1/|T−γ|: split at 1/2: inner |γ−T|<1/2 ⊂ one unit window: count ≤ C₀; terms ≤ 1/d ≤ 3C₀... inner ≤ C₀·3C₀ = 3C₀². Outer 1/2 ≤ |γ−T| < 1: terms ≤ 2; count ≤ 2C₀ (two windows): outer ≤ 4C₀. Total ≤ 3C₀² + 4C₀ — CLOSE to the baked 3C₀²! The extra 4C₀ is lower-order (C₀ vs C₀²). So the near sum ≤ 3·C₀² + 4·C₀ honestly IF the clearance d = 1/(3C₀) holds against ALL zeros within distance 1/2 of T (i.e., the pigeonhole must cover (T−1/2, T+1/2) ⊂ (a−1, a+2)... — extend L3: pigeonhole on the 3-unit window (a−1, a+2) (count ≤ 3C₀) with midpoints in [a, a+1]... hmm, the midpoint spacing: window [a, a+1], 3C₀ forbidden points (the zeros in (a−1, a+2) — wait we only need clearance vs zeros in (T−1/2, T+1/2) ⊂ (a−1/2, a+3/2) since T ∈ [a, a+1]: zeros in (a−1/2, a+3/2): count ≤ 2C₀. Pigeonhole: 2C₀+1 midpoints in [a, a+1] at spacing 1/(2C₀+1), each zero blocks ≤ 1 midpoint ⟹ a midpoint T with clearance ≥ 1/(2(2C₀+1)) ≥ 1/(6C₀) from all zeros within (a−1/2, a+3/2). Then near sum: inner |γ−T| < 1/2 (all such zeros are in the clearance range): count ≤ C₀(2 units... (T−1/2, T+1/2) = 1 unit ✓ ≤ C₀); terms ≤ 6C₀ ⟹ ≤ 6C₀². Outer: 1/2≤|γ−T|<1: count ≤ 2C₀, terms ≤ 2 ⟹ ≤ 4C₀. Total ≤ 6C₀² + 4C₀. vs baked 3C₀²: 2× + lower order. Margin impact: the C0hat² coefficient doubles: 112 800 → 225 600 extra at n=10⁵: B-side +112 800 — margin 142 800 → 30 000 — SURVIVES (barely, and the crossover N₀ moves up, maybe past 80 000?!). Ugh — actually the margin at the certified base point 8×10⁴ was ≥ 8001 with the old constants; doubling the C0hat² term would flip it negative... OK. This is all ii′-6 territory (the H(T)/contour assembly), NOT 5f. Let me SCOPE BACK to 5f: the R-bound |R(s)| ≤ 10.5 log(|t|+2) + 48 for σ ∈ [−5/2, 3], |t| ≥ 10. The ONLY count input is piece 2 (2× gap) + piece 3 (per-interval, honest as written). Honest fold: 14.73·C₀ + 7.97 ≤ 11.18·L + 50.7 (vs baked 10.5/48). With piece-3 sharpening (per-interval 1/(k√(1+k²))): 13.88·C₀ + 7.55 ≤ 10.53·L + 47.8 — STILL barely over 10.5/48. So for 5f, the honest options: (B1) Prove the R-bound with honest constants A = 11.5, B₀ = 52 (comfortable rounding of 11.18/50.7) and re-fold downstream (margin constants change: Hhat's 10.5/48 → 11.5/52; the 3C0hat² stays as-is for now — its own honesty issue is ii′-6's to face). Downstream cost: marginTilde def constants, convexity re-verification, base-point re-certification, paper text at ii′-7. AND the margin at 8×10⁴/10⁵ must be re-checked (impact ~5–8% — survives per my estimates, but the CERTIFIED proofs need re-running). (B2) Prove a sharper assembly that fits 10.5/48 — appears knife-edge/impossible with this shape. Hmm hold on, wait. Before spiraling further, let me double-check the D-056 piece-2 claim by looking at what E-028 actually verified and what the paper's §3 (R-004 assembly) uses. If E-028's V-R verified |R(s)| ≤ 10.5 log + 48 numerically (26× slack), the BOUND is fine — it's the traced PROOF that's gappy. For the Lean 5f, I need a PROOF. The cleanest provable-from-assembly statement has the honest constants. Hmm — actually, WAIT. One more idea for keeping 10.5/48 exactly: the reference-point difference for the NEAR sum doesn't need to bound Σ_near 1/|s₀−ρ| by the count — the near sum at s₀ can be paired with the far difference at the SAME zeros? No — the split is near vs far, disjoint. Alternatively: sharpen piece 2 using the per-term √(1+x²): Σ_{|γ−t|<1} 1/√(1+(t−γ)²): inner |t−γ| ≤ 1/2: ≤ C₀(t)·1; outer 1/2<|t−γ|<1: count ≤ 2C₀ − hmm. ≤ C₀(t) + 0.894·(2C₀(t) − ...) — the outer annulus (1/2,1) count is ≤ 2C₀(t) (two windows) minus nothing provable. 2.79·C₀ — worse. What about THREE-way split: |t−γ| ≤ 1/2 (≤ C₀, ×1), 1/2 < |t−γ| ≤ 3/4... the count of the annulus (1/2, 3/4]: ⊂ (t−3/4, t+3/4] — 1.5 units — count ≤ 2C₀... ugh, the annuli counts don't sharpen below 2C₀ for the two-sided window. FUNDAMENTAL: the two-sided near window count is 2·C₀·(1+o(1))-ish — no, wait, is it? (t−1, t+1] = two unit windows = 2·C₀(t) with C₀(t) ≈ 5. True count ≈ 2·(average density) ≈ 2·(log t)/2π·... the Trudgian bound per unit is C₀ ≈ 5 (vs true ~1.1 at t=50) — the SLACK is in the S_b constants (Trudgian's S bound is uniform, not tight per-window). The two-unit honest count is 2·C₀ − (F-overlap...) ≈ 2·C₀ − 2.6 (the constant 2.9 is per-window... C₀(t) = 0.433L + 0.886LL + 2.9; two-unit = F(t+1)−F(t−1) + S(t+1)+S(t−1) ≤ 0.318L + 0.886LL + (3.176 − ...) hmm: S_b pair for two-unit = S(t+1)+S(t−1) = 0.137(2 log t) + 0.443(2 loglog t) + 3.176 = 0.274L + 0.886LL + 3.176. F-diff-2unit = (1/π)L + c ≈ 0.318L. Total ≈ 0.592L + 0.886LL + 3.176−ish. vs 2·C₀ = 0.866L + 1.772LL + 5.8. So the honest two-unit count (0.592L + 0.886LL + 3.2) is MUCH better than 2·C₀ (0.866L + 1.77LL + 5.8)!! Because the F-difference over 2 units only doubles the 0.159 coefficient, while C₀'s constant 2.9 and LL 0.886 don't double in the honest form!! RECOMPUTE piece 2 with the honest two-unit Trudgian form: piece 2 ≤ N(t+1)−N(t−1) ≤ [F(t+1)−F(t−1)] + S_b(t+1)+S_b(t−1) ≤ (0.318·L + 0.886·LL + 3.176 + small) where L = log(t+2)-ish. Hmm — but our LEAN perimeter is ZeroCountProp with C0hat — the mult-weighted UNIT-window count ≤ C0hat(t+1). The two-unit count via the perimeter = C0hat(t) + C0hat(t+1) ≤ 2·C0hat(t+1) — we DON'T have the honest F/S-pair two-unit form in Lean (the perimeter is the closed-form C0hat, not the F/S-pair). The closed form 2·C0hat(t+1) = 0.866L + 1.77LL + 5.8. Piece 2 ≤ 2·C0hat(t+1). Fold with piece 3 sharpened (11.88·C₀ + 6.6): total = 0.57 + 2C₀ + 11.88C₀ + 6.6 + 0.38 ≈ 13.88·C₀ + 7.55. With C₀ = C0hat(t+1) = 0.433L' + 0.886LL' + 2.9, L' = log(t+3): ≤ 6.01L' + 12.3LL' + 40.3 + 7.55 = 6.01L' + 12.3LL' + 47.85. ≤ (6.01 + 12.3/e)L' + 47.85 = 10.53·L' + 47.85. The target: 10.5·log(|t|+2) + 48. L' = log(t+3) > log(t+2) — slight overshoot both sides. 10.53 > 10.5: BREAKS by 0.03·L + (47.85 + 10.53·log((t+3)/(t+2)) − 48) ≈ 0.03L + 0.1. Knife-edge negative. To close the last 0.03·L + 0.1: piece 3's tail 0.53 → exact ~0.3?; C₀(2t) ≤ C₀+0.58 → +0.3; pieces 4–6: 0.045+0.045+0.29 = 0.38 → could sharpen to ~0.2; Z₂ = 0.57 → 0.56997. Piece 3's Σ constant 1.32 → exact ≈ 1.316? (Σ 1/(k√(1+k²)) — numerically: k=1: 0.70711, k=2: 0.22361, k=3: 0.10541, k=4: 0.06063, k=5: 0.03922, k=6: 0.02774, k=7: 0.02058, k=8: 0.01578, k=9: 0.01249, k=10: 0.01010, Σ_{k>10} ≤ ∫_10^∞ dx/x² = 0.1: total ≈ 1.3225 + ... let me sum: 0.70711+0.22361 = 0.93072; +0.10541 = 1.03613; +0.06063 = 1.09676; +0.03922 = 1.13598; +0.02774 = 1.16372; +0.02058 = 1.18430; +0.01578 = 1.20008; +0.01249 = 1.21257; +0.01010 = 1.22267; tail Σ_{k≥11} 1/(k√(1+k²)) ≤ Σ 1/k² ≤ 1/10 = 0.1 → ≈ 1.32267+... hmm ≈ 1.32. And 4.5·1.32 = 5.94/side. Total constant: 0.56997 + 5.94·(2·0.58+0.53)... this is getting extremely fiddly. The gap is 0.03·L + ~0.15 — honestly too tight to close robustly without redoing the whole assembly at higher precision. And EVEN IF closed, it leaves ii′-6's H(T) near-sum issue (the 3C₀² clearance/count problem — which is a SEPARATE, bigger honesty gap that WILL need facing at ii′-6 and likely moves the constants anyway!). STEPPING BACK. Strategic view: the 10.5/48 constants came from D-056's assembly which has the one-C₀-piece-2 gap. The margin constants baked in LiSkeleton inherit from that. The honest re-fold moves A from 10.5 to ~11.2–11.5 and B₀ from 48 to ~51–52 (or a bit more with room). The margin has ~25× slack at the theorem level (E-028) but the CERTIFIED Lean artifacts (convexity proof, base-point bounds) are constant-specific and will need re-verification. That's the honest cost of a genuine fix — and it SHOULD be done now (at 5f) rather than at ii′-6, because 5f is where the R-bound constants enter Lean. BUT — the ii′-6 H(T) issue (3C₀² → 6C₀²+ clearance coverage) will move the constants AGAIN. If I re-fold now for 5f and again at ii′-6, double rework. ALTERNATIVE: face BOTH issues now — i.e., design 5f + the ii′-6 contour assembly constants together, re-fold ONCE. Hmm, wait — is the ii′-6 issue real? Let me double check the H(T) near-sum against the ii′-4 L3 statement. exists_zero_avoiding_T: T ∈ [a, a+1], clearance 1/(3·C0hat(a+1)) vs zeros with im ∈ [a, a+1]. The horizontal contour at height T: near sum Σ_{|γ−T|<1} 1/|s−ρ|, |s−ρ| ≥ |T−γ|. Zeros with γ ∈ (a+1, a+2) and |γ−T|<1: clearance NOT covered by L3. So the H(T) bound C₀/d_min is NOT justified as stated. The honest version needs clearance vs all |γ−T|<1 zeros: extend the pigeonhole to the 3-unit window (count 3C₀, clearance 1/(9C₀+3)-ish → near sum ≤ 3C₀·(9C₀+3) ≈ 27C₀²) OR the smarter split (≤ 6C₀² + 4C₀ as computed). Either way Hhat's 3·C0hat² is undercounted. Hmm wait, actually — one clean fix for the clearance: choose T in [a+1/4, a+3/4] (the central half) via the pigeonhole on the FULL window [a, a+1]... no: out-of-window zeros sit just outside a or a+1: γ = a − ε or a+1+ε; T ∈ [a+1/4, a+3/4] ⟹ |T−γ| ≥ 1/4 − ... γ > a+1: |T−γ| > (a+1) − T ≥ 1/4. γ < a: |T−γ| > T − a ≥ 1/4. So out-of-window zeros are ≥ 1/4 away if T is in the central half! And in-window zeros: clearance 1/(3C₀) via the pigeonhole (needs the pigeonhole to place T in the central half: use ~2C₀+1 midpoints in [a+1/4, a+3/4]: spacing (1/2)/(2C₀+1)... hmm — the pigeonhole: k zeros in window, k+1 midpoints in [a+1/4, a+3/4] spaced 1/(2(k+1)) apart, each zero blocks ≤ 1 ⟹ T with clearance 1/(4(k+1)) ≥ 1/(4(C₀+1)) ≥ 1/(5C₀)... Combined clearance vs ALL zeros: min(1/(5C₀), 1/4) = 1/(5C₀) (C₀ ≥ 2). Near sum: inner |γ−T| < 1/2: count ≤ C₀ (1 unit); terms ≤ 5C₀ ⟹ ≤ 5C₀². Outer 1/2 ≤ |γ−T| < 1: count ≤ 2C₀, terms ≤ 2 ⟹ ≤ 4C₀. Total ≤ 5C₀² + 4C₀. vs baked 3C₀²: coefficient 5 vs 3 (+67% on the C0hat² term) + 4C₀ lower-order. Margin impact at n = 10⁵: the C0hat² term in B: 2(e⁴+1)·7·(5·48.3) vs (3·48.3): 111.2·7·2·48.3 = +75 200 extra ⟹ margin 142 800 → ~67 600 — SURVIVES. At n = 8×10⁴ (T ≈ 283.8): C0hat(284.8) ≈ 0.433·5.65+0.886·1.73+2.9 ≈ 2.45+1.53+2.9 = 6.88; C0hat² ≈ 47.3; extra 2·47.3·111.2·7 ≈ ... the increment is 2(e⁴+1)·7·2·C0hat² ≈ 1556.8·47.3 ≈ 73 600. Old margiñ(8×10⁴) ≥ 8001 certified (true ~15 764 per the margin trail). 15 764 − 73 600 < 0?!? Hmm wait — that can't be right. Let me recompute the C0hat²-piece at 8×10⁴ with the OLD constants: 111.2·7·3·47.3 ≈ 110 400. But the total B-side at 8×10⁴ was ≈ S − margin ≈ ... margin(8×10⁴) ≈ 15 764 (true) — S(8×10⁴) ≈ 0.5·80000·11.29 + 0.0231·80000 ≈ 451 600 + 1850 ≈ 453 450; B ≈ 437 700. The C0hat² piece 110 400 is 25% of B. Doubling adds 73 600 ⟹ B ≈ 511 300 > S ≈ 453 450 — MARGIN NEGATIVE at 8×10⁴. The crossover moves WAY up (maybe n ~ 2×10⁵?). And N₀ is capped by the finite verification 5×10⁵... margin at 5×10⁵ was 2.0×10⁶ — with the extra ~2·C0hat²·778: at n = 5×10⁵, T ≈ 708: C0hat ≈ 0.433·6.56+0.886·1.88+2.9 ≈ 2.84+1.67+2.9 = 7.41; C0hat² ≈ 54.9; extra ≈ 1556.8·... wait the increment coefficient: 2(e⁴+1)·7·(5−3)·C0hat² = 111.2·14·54.9 ≈ 85 500. margin(5×10⁵) = 2.0×10⁶ − 85 500 ≈ 1.9M ✓ fine. The crossover: where does margin become positive? B's leading √n log n grows by Δ ≈ 1556.8·C0hat²(T)-ish/√n-log-n units... The crossover was ~33 000 (traced). With the C0hat² doubling, the crossover might move to ~60 000–150 000 — DANGEROUSLY close to or past N₀ = 80 000 and the certified base points!! Hmm wait, I should just compute the crossover honestly... this is getting deep into ii′-6 redesign. STOP. Scope discipline: 5f is the R-bound. The H(T) issue is ii′-6's. But the CONSTANTS decision couples them. Given the coupling, the RIGHT move per the fork rule and the careful-governance norms: present the finding to the user NOW — D-056's assembly has a genuine factor-2 gap at piece 2 (one-C₀ for the two-unit window), so the baked 10.5/48 is not provable from that assembly as written; options: (B) re-fold with honest constants (A ≈ 11.5, B₀ ≈ 52) + downstream re-verification, or investigate harder. Also flag the ii′-6 H(T) clearance/count issue discovered in the same review (near sum honestly 5C₀²+4C₀ vs baked 3C₀² — or 6C₀²+4C₀ with the current pigeonhole + window extension). Hmm, wait. Actually — let me reconsider whether E-028's numerical verification already settles these questions in a way the Lean proof could use... no — the Lean proof needs the ASSEMBLY, not numerics (the margin is a uniform statement to N₁ = 9×10²⁴). Hold on, hold on. Let me re-examine the piece-2 gap ONE more time, because everything hinges on it. D-056: "2. Near at s₀: |s₀−ρ| ≥ 2 − β ≥ 1 ⟹ Σ_{|γ−t|<1} 1/|s₀−ρ| ≤ C₀(t)." Hmm — is C₀(t) here possibly the count of |γ−t| ≤ 1 = N(t+1)−N(t−1) ≤ F(t+1)−F(t−1) + S(t+1)+S(t−1), and the "F(t+1)−F(t)" in the C₀ definition line a typo for F(t+1)−F(t−1)? If C₀(t) were DEFINED as the two-unit count, then the closed form 0.433 log(t+2) + 0.886 loglog(t+2) + 2.9 would need to majorize the two-unit honest form 0.592L + 0.886LL + 3.176: 0.433L + 2.9 vs 0.592L + 3.176 — fails for large L (0.433 < 0.592). So no — the closed form matches the one-unit definition. The gap is real. Hmm, although — wait, actually let me redo the two-unit F-difference: F(x) = (x/2π)(log(x/2π) − 1) + 7/8. F(t+1) − F(t−1): F'(x) = (1/2π)log(x/2π). ∫_{t−1}^{t+1} (1/2π)log(x/2π) dx ≈ (2/2π)·log(t/2π) = (1/π)·(L − log(2π))·... = (1/π)·L − (1/π)·1.838 ≈ 0.318L − 0.585. And the closed form's log coefficient is 0.433 with constant 2.9. The honest two-unit: 0.318L − 0.585 + 0.274L + 0.886LL + 3.176 = 0.592L + 0.886LL + 2.59. vs C₀ closed form 0.433L + 0.886LL + 2.9. Crossover: 0.592L + 2.59 vs 0.433L + 2.9 ⟺ 0.159L = 0.31 ⟺ L ≈ 1.95 ⟺ t ≈ 5.2. For t ≥ 10 (L ≥ 2.4): the two-unit honest form EXCEEDS the C₀ closed form. Confirmed: at t=10, honest-2unit ≈ 0.592·2.48+0.886·0.907+2.59 ≈ 1.47+0.80+2.59 = 4.86 vs C₀(10) = 4.78. So piece 2 honestly ≤ 4.86-ish > 4.78. Tiny but real overage, growing as 0.159·L. OK so it's definitively a (small) gap in D-056's traced assembly. The bound is numerically fine (26× slack) but the traced constants 10.5/48 can't be reached from that assembly. The Lean 5f must re-fold. Given the coupling to ii′-6's (bigger) H(T) issue, and that BOTH will move the baked constants, the clean path is: **Re-fold the R-bound AND the H(T)/Hhat accounting honestly NOW, then re-verify the margin artifacts (convexity + base points) with the new constants, then continue.** This is a significant but mechanical rework — and it MUST be done before ii′-6 regardless. Actually — hmm, wait. Let me reconsider the scale of the H(T) fix once more. The central-half trick gives clearance 1/(5C₀) with the SAME pigeonhole count C₀ (window zeros), and near sum ≤ 5C₀² + 4C₀. Even simpler: the L3 statement as PROVED in Lean (exists_zero_avoiding_T) gives T ∈ [a, a+1] with clearance 1/(3·C0hat(a+1)) vs window zeros only. To get the central-half version I'd need a modified pigeonhole (midpoints in [a+1/4, a+3/4]) — the exists_avoiding_midpoint lemma takes (a, S, card bound) and returns a midpoint in [a, a+1]... it could be INSTANTIATED at the sub-window? The zeros to avoid = those in (a−1/4, a+5/4)-ish... Actually exists_avoiding_midpoint a' S' with a' = a+1/4 on window [a+1/4, a+5/4] (width 1): gives T ∈ [a+1/4, a+5/4] avoiding zeros in [a+1/4, a+5/4]... then T could be up to a+5/4 — out-of-[a+1/4,a+5/4] zeros (γ just below a+1/4 or above a+5/4) within |γ−T|<1: γ = a+1/4−ε, T ≤ a+5/4: |γ−T| ≥ (a+1/4−ε) − ... no wait γ < a+1/4 ≤ T: |T−γ| = T−γ ≥ T−(a+1/4) ≥ 0 if T = a+1/4. Hmm — need T in the central half of the AVOIDED window. exists_avoiding_midpoint places T as one of k+1 midpoints spanning the whole window — no centrality guarantee. To force centrality: apply the midpoint pigeonhole on window [a', a'+1] but only to midpoints in the central half... the existing lemma: "k+1 midpoints a + (2j+1)/(2(k+1))" — j spans 0..k — the midpoints span [a + 1/(2(k+1)), a + 1 − 1/(2(k+1))] — nearly the full window. For centrality, need a variant: midpoints in [a+1/4, a+3/4], spacing (1/2)/(k+1), k = card bound on the 1.5-unit window (a−1/4, a+5/4)... count ≤ 2C₀. Then T central ⟹ out-of-(a−1/4, a+5/4) zeros ≥ 1/4 away; in-window zeros ≥ 1/(4(2C₀+1)) ≥ 1/(12C₀)... near sum ≤ C₀·(12C₀) [inner 1 unit] + 2C₀·2 [outer] = 12C₀² + 4C₀. Hmm — 12 vs the earlier 5 estimate: the inner window (T−1/2, T+1/2) count... I conflated. Let me redo cleanly: Goal: bound Σ_{|γ−T|<1} 1/|T−γ|. Given: T ∈ [a+1/4, a+3/4] (central half), clearance d vs ALL zeros with |γ−T| < 5/4 (i.e., in (a−1/2, a+2) ⊂ 3 unit windows, count ≤ 3C₀; pigeonhole with 3C₀+1 midpoints in [a+1/4, a+3/4], spacing (1/2)/(3C₀+1), clearance ≥ (1/4)/(3C₀+1) ≥ 1/(13C₀)). Then: - |γ−T| < 1/4: all such zeros are within the cleared neighborhood ⟹ each term ≤ 13C₀; count ≤ C₀ (one unit window (T−1/4, T+1/4]... width 1/2 ≤ 1 ✓ ≤ C₀). Contribution ≤ 13·C₀². - 1/4 ≤ |γ−T| < 1: terms ≤ 4; count ≤ 2C₀ ⟹ ≤ 8C₀. - Total ≤ 13C₀² + 8C₀. vs the earlier rougher 12C₀²+4C₀ / 5C₀²+4C₀ estimates — depends on the geometry choices. Anyway: the honest H(T) C0hat² coefficient lands ~5–13 vs baked 3. OK — decision time for real. This is a significant finding (a second constants-level gap in the R-004 traced chain — D-056's piece 2 — PLUS the H(T) clearance-coverage gap for ii′-6), and the remediation path (re-fold constants + re-verify margin artifacts) has multiple viable parameter choices. Per the project's governance (fork rule, careful plan changes, user owns the research direction), I should present this to the user with a clear analysis and options before spending sessions on the wrong re-fold. Actually — hmm, wait. Before going to the user, let me make sure the H(T) issue is REAL and not already handled by the D-037 assembly. Let me check D-037's use of H(T). Actually, from LiSkeleton's marginTilde: the B-side has `2 * (Real.exp 4 + 1) * (7 * Hhat T + 3.3)` — the 7·Hhat matches D-036 §3's "|I_II| = |I_IV| ≤ (e⁴+1)·[7H(T) + e·|ζ′/ζ(2)|·2] ≤ (e⁴+1)·[7H(T)+3.3]" — the horizontals use H(T) = 3C₀² + A log + B₀ with the near-sum-at-T inside. And the I_III left-vertical term: `4 * T * ((2 / 3) * C0hat T + 10.5 * Real.log (T + 2) + 48)` — the (2/3)·C0hat(T) is the left-vertical near sum (|σ−β| ≥ 1.5 ⟹ terms ≤ 2/3... Σ_{|γ−T|<1} (2/3) ≤ (2/3)·count — with the ONE-C₀ convention again: (2/3)·C₀(T) — honest would be (2/3)·2C₀ = (4/3)C₀). So the baked constants embed the one-C₀ convention in THREE places (R-bound's A/B₀ via piece 2, Hhat's 3C₀², I_III's (2/3)C₀). So the honest re-fold touches: A/B₀ (R-bound), the C0hat² coefficient (3 → 5–13), the (2/3) → (4/3) C₀ coefficient in I_III. All in marginTilde's baked arithmetic. The margin slack: ~25× at the theorem level but the CERTIFIED crossover/base-points move. This is exactly a D-054-class repair (like 4.5a–d in session 009). Given all this, the honest path forward: 1. File the finding as a documented repair item (D-069: 5f design + the D-056 piece-2 gap + the H(T) clearance-coverage gap). 2. Re-derive the honest constants: A/B₀ for the R-bound; the H(T) near-sum coefficient; I_III's C₀ coefficient. 3. Re-verify the margin (convexity — structural, constants parametric? need to check session-011's proof sensitivity; base points — re-certify by interval bounds; crossover/N₀ — re-run E-023-style numerics to pick N₀... N₀ = 80 000 might no longer have positive margin! Need to recompute. If the new crossover exceeds 80 000, N₀ moves up (≤ 5×10⁵ finite verification cap — actually the finite verification is to 5×10⁵, and N₀ must be ≤ 5×10⁵ AND have positive margin + convexity bridge to N₁). 4. Re-bake LiSkeleton constants + re-run the Lean margin artifacts. This is genuinely a 2–4 session repair arc, and it REPLACES the simple "5f ~1 session" plan. The user should decide: (i) full honest re-fold now (recommended — it's required for ii′-6/7 anyway); or (ii) attempt the knife-edge tightening to keep 10.5/48 (my assessment: fails); or (iii) park 5f and re-scope. Hmm — wait, actually, one more consideration before presenting: maybe I'm wrong about the margin going negative at 8×10⁴. My back-of-envelope B-side recomputations are rough. The clean way: recompute the margin numerically with the honest constants (E-023/E-028 machinery exists — the assembly script). That's a 30-min numerics job that would settle the crossover/margin positivity question EXACTLY before any Lean rework. THAT should be step 1 of the repair arc regardless. Let me now also sanity-check my claim about piece 2 against the ACTUAL near-sum values: at t = 50, near window (49, 51): zeros at 49.77 (4th zero? zeros: 14.13, 21.02, 25.01, 30.42, 32.94, 37.59, 40.92, 43.33, 48.01, 49.77, 52.97, ...) — γ₉ = 48.01, γ₁₀ = 49.77 — in (49, 51): just 49.77: count 1. C₀(50) = 0.433·3.95+0.886·1.37+2.9 = 1.71+1.21+2.9 = 5.83. So 1 ≤ 5.83 hugely — the SLACK per window is ~5×. The honest two-unit Trudgian bound at t=50: 0.592·3.95+0.886·1.37+2.59 ≈ 2.34+1.21+2.59 = 6.14 vs one-unit C₀ 5.83 — overage 0.31. The FOLD impact: piece 2 honest 6.14 vs traced 5.83 — the R-bound total: pieces 1+2+3+4+5+6 = 0.57 + 6.14 + 12.73·5.83·(hmm — piece 3 uses C₀ per interval...). Let me just recompute the honest total at t=50: 0.57 + 6.14 + (12.73·5.83 + 7.06) + 0.38 = 0.57+6.14+74.2+7.06+0.38 = 88.35. Baked bound: 10.5·log(52)+48 = 10.5·3.95+48 = 89.5. 88.35 ≤ 89.5 ✓ FITS at t=50! At t=10: honest: piece2 ≤ 4.86 (computed above), piece 3: 12.73·4.78+7.06 = 60.85+7.06 = 67.91; total: 0.57+4.86+67.91+0.38 = 73.72 vs baked 10.5·2.48+48 = 74.04 ✓ FITS (by 0.3)! At t=1000: piece2: 0.592·6.91+0.886·1.93+2.59 = 4.09+1.71+2.59 = 8.39; C₀(1000) = 0.433·6.91+0.886·1.93+2.9 = 2.99+1.71+2.9 = 7.60; piece 3: 12.73·7.60+7.06 = 96.75+7.06 = 103.8; total: 0.57+8.39+103.8+0.38 = 113.1 vs baked: 10.5·6.91+48 = 120.6 ✓ FITS (by 7.5). At t=10⁶: L = 13.82: piece2: 0.592·13.82+0.886·2.63+2.59 = 8.18+2.33+2.59 = 13.1; C₀ = 0.433·13.82+0.886·2.63+2.9 = 5.98+2.33+2.9 = 11.21; piece3: 12.73·11.21+7.06 = 149.8; total: 0.57+13.1+149.8+0.38 = 163.85; baked: 10.5·13.82+48 = 193.1 ✓ FITS (by 29). WAIT. It FITS?! Let me recheck my earlier "breaks" claim. Earlier I folded piece2 = 2·C₀ (the crude 2× unit count) — but the HONEST two-unit Trudgian form is 0.592L + 0.886LL + 2.59 (NOT 2·C₀!). The key: the two-unit window count via the F-difference has log coefficient 0.318+0.274 = 0.592, NOT 2·0.433 = 0.866 — because the S_b pair does NOT double (it's S(t+1)+S(t−1), still TWO S-terms, same as the one-unit form's S(t+1)+S(t)!). So the honest piece-2 count ≈ C₀(t) + 0.159·L − 0.3 — only slightly MORE than C₀(t). And the fold: |R| ≤ Z₂ + [C₀(t) + 0.159L] + [12.73·C₀(t) + 7.06] + 0.38 = 13.73·C₀(t) + 0.159L + 8.01 ≤ 13.73·(0.433L + 0.886LL + 2.9) + 0.159L + 8.01 = 5.945L + 12.16LL + 39.82 + 0.159L + 8.01 = 6.104L + 12.16LL + 47.83 ≤ (6.104 + 12.16/e)·L + 47.83 = (6.104 + 4.474)·L + 47.83 = 10.578·L + 47.83. vs 10.5L + 48: 10.578 > 10.5 — STILL over by 0.078·L − 0.17. At L = 2.48 (t=10): over by 0.19−0.17 = 0.02. At L = 6.91: over by 0.54−0.17 = 0.37. Hmm — but my per-t computation above said it FITS at t=10/50/1000?! Because I used the exact honest piece-2 (4.86 at t=10) vs the folded 0.159L-term... At t=10: my fold gives 10.578·2.48 + 47.83 = 26.23+47.83 = 74.06 vs baked 74.04 — over by 0.02. The direct computation gave 73.72 (fits by 0.32). The difference: the loglog≤L/e fold is lossy at small t, and my 0.159L+8.01 vs the exact piece-2... The truth is at the knife-edge: ±0.3 at t=10, and the ASYMPTOTIC coefficient 10.578 > 10.5 breaks it for large t... at t=10⁶: fold says 10.578·13.82+47.83 = 146.2+47.8 = 194.0 vs baked 193.1 — over by 0.9. Direct: 163.85 vs 193.1 — fits by 29!! The discrepancy: the direct per-t computation uses the exact LL term (LL(10⁶) = log 13.82 = 2.63, while L/e = 5.08 — the LL≤L/e fold loses 12.16·(5.08−2.63) = 29.8 at t=10⁶!!). So the fold loglog ≤ (1/e)·log is HUGELY lossy for t ≫ e^e ≈ 15.15. The bound 10.5L + 48 might actually hold via the assembly with a BETTER loglog fold! The loglog fold: want c₁L + c₂LL + c₃ ≤ 10.5L + 48 with c₁ = 6.104, c₂ = 12.16, c₃ = 47.83. I.e., need 12.16·LL ≤ (10.5−6.104)·L + (48−47.83) = 4.396·L + 0.17. LL ≤ (4.396/12.16)·L + 0.014 = 0.3615·L + 0.014. Is loglog(t+2) ≤ 0.3615·log(t+2) + 0.014 for t ≥ 10? Let x = log(t+2) ≥ log 12 = 2.485: need log x ≤ 0.3615·x + 0.014. The max of log x / x is 1/e = 0.3679 at x = e — 0.3615 < 0.3679! At x = e (t+2 = e^e = 15.15, t = 13.15): log x = 1, need 1 ≤ 0.3615·e + 0.014 = 0.9825 + 0.014 = 0.9965 — 1 ≤ 0.9965 FALSE! So at t ≈ 13.15, the inequality 12.16LL ≤ 4.396L + 0.17 FAILS by ~0.0035!! KNIFE-EDGE FAILURE at t ≈ 13. The failure is by 0.0035 at exactly one spot (t ≈ 13.15) — the assembly with the honest piece-2 misses 10.5/48 by 0.004 THERE. But wait — my constants are rough (0.159L for the piece-2 overage, the piece-3 constants 12.73/7.06, the 0.38 for pieces 4–6, Z₂ = 0.57). The TRUE assembly values (exact piece-3 interval sums, exact piece-2 two-unit form, exact piece-6) could easily absorb 0.004. E.g., Z₂ = 0.56996 not 0.57 (−0.00004... too small). Piece 3's 12.73 = 4.5√2·2: 4.5√2 = 6.36396; the tail 0.53→?; C₀(2t) ≤ C₀(t)+0.58→0.30 — saves 6.364·0.28 ≈ 1.78 — WAY more than 0.004. So with slightly sharper bookkeeping, 10.5/48 is reachable. BUT the bookkeeping must be Lean-provable — every constant needs a machine-checkable derivation. A knife-edge fit at t ≈ 13.15 (by ~0.01) is fragile but POSSIBLE with exact interval arithmetic (like LiBasePoints' certified bounds). Hmm — but "fragile at one point" for a UNIFORM bound over t ≥ 10... the pointwise near-miss at t ≈ 13 means the proof must be exact there — certified interval evaluation of the assembly at the worst point. Doable (LiBasePoints machinery exists) but delicate. ALTERNATIVELY — change the fold: don't fold LL ≤ L/e globally; keep the honest three-term form 6.104L + 12.16LL + 47.83 and prove THAT ≤ 10.5L + 48 for t ≥ 10... which fails at t ≈ 13 by 0.004 as shown. So the assembly's own constants must improve by ≥ 0.01 at t = 13 before the fold. Options: piece-3 right-side C₀(2t) → C₀(t)+0.433·log 2 exactly (saves 6.364·(0.58−0.30) = 1.8); the piece-3 tail 0.53 → exact (t=13: Σ_{k>t} C₀(2t)/(k(k+1)) + ... ≤ C₀(2t)/(t+1) + 0.433/t ≈ 5.9/14 + 0.03 ≈ 0.45 → saves 0.08); pieces 4–6: 0.38 → 0.36. Piece-2's overage 0.159L−0.31 → exact two-unit F/S form. These save ~1.9 total at t=13 — the 0.004 gap closes 400×. So YES, 10.5/48 is provable with careful bookkeeping — the D-056 assembly was lossy, not wrong-headed. CONCLUSION: 5f is feasible at the baked 10.5/48 constants, but requires a TIGHTER assembly than D-056's text (piece-2 two-unit form, piece-3 sharper right-side/tail accounting), with the t ≈ 13 near-miss discharged by certified interval evaluation (the LiBasePoints pattern). The Lean work: (i) two-unit window count from the mult-weighted ZeroCountProp: Σ_{(t−1,t]} + Σ_{(t,t+1]} ≤ C0hat(t) + C0hat(t+1) — hmm WAIT. The Lean perimeter gives the closed-form C0hat window counts, NOT the F/S-pair Trudgian form! The honest two-unit form 0.592L + 0.886LL + 2.59 was derived from F/S-pair directly. From the Lean perimeter (C0hat per unit window), the two-unit count ≤ C0hat(t) + C0hat(t+1) = 0.433(L₁+L₂) + 0.886(LL₁+LL₂) + 5.8 where L₁ = log(t+1), L₂ = log(t+2)... = 0.866L + 1.772LL + 5.8 — the CRUDE doubling! The F/S-pair refinement (0.592L+...) is NOT available from the perimeter as declared (ZeroCountProp gives per-unit C0hat bounds; the two-unit sum is two applications). Hmm!! So in Lean, piece 2 ≤ C0hat(t) + C0hat(t+1) ≤ 2·C0hat(t+1) = 0.866L' + 1.772LL' + 5.8 (L' = log(t+3)). The fold: 0.57 + 2C₀' + 12.73C₀' + 7.06 + 0.38 where C₀' = C0hat(t+1) — wait no: piece 3's per-interval counts also come from the perimeter: left intervals ≤ C0hat(t−k+1) ≤ C0hat(t); right ≤ C0hat(t+k+1) ≤ C0hat(2t+1). So piece 3 ≤ 4.5√2·[C0hat(t)·1 + C0hat(2t+1)·1 + tail]. C0hat(2t+1) ≤ C0hat(t+1) + 0.433·log 2 + 0.886·(LL(2t+1)−LL(t+1)) ≤ C0hat(t+1) + 0.31+0.27-ish. So the fold in Lean: pieces: 0.57 + 2·Ĉ + 6.364·[Ĉ + Ĉ+0.58 + 0.53] + 0.38 = 0.57 + 2Ĉ + 12.73Ĉ + 7.06 + 0.38 = 14.73·Ĉ + 8.01 where Ĉ = C0hat(t+1) ≈ 0.433L' + 0.886LL' + 2.9. Total = 14.73·(0.433L'+0.886LL'+2.9) + 8.01 = 6.378L' + 13.05LL' + 42.72 + 8.01 = 6.378L' + 13.05LL' + 50.73. Fold LL ≤ L/e: (6.378 + 13.05/e)L' + 50.73 = (6.378+4.80)L' + 50.73 = 11.18L' + 50.73 vs 10.5L + 48. BREAKS (as computed before: at t=10: 11.18·2.56+50.73 = 79.3 vs 74.0). So with the Lean perimeter's per-unit closed-form counts, the assembly CANNOT reach 10.5/48 (breaks by ~5 at t=10 and 0.68·L asymptotically). To keep 10.5/48, the piece-2 two-unit count must use the F/S-pair form (0.592L + 0.886LL + 2.59) — which is a DIFFERENT perimeter declaration (the two-unit Trudgian form), OR ZeroCountProp could be declared with the two-unit form built in... but ZeroCountProp's C0hat IS the one-unit closed form. The F/S-pair form is a genuinely sharper/different declared input. Hmm — OR: strengthen ZeroCountProp's CONTENT: declare the count bound for the two-unit window |γ−t|<1 directly as a C0hat-shaped bound: #{|γ−t|≤1} ≤ Ĉ₀⁽²⁾(t) := 0.6·log(t+2) + 0.886·loglog(t+2) + 2.7 (the honest two-unit closed form: 0.592L + 0.886LL + 2.59 rounded up). This is still Trudgian N(t+1)−N(t−1) + S-pair — same declared source! Just a different specialization. Then piece 2 ≤ Ĉ₀⁽²⁾(t), and the fold: 0.57 + (0.6L + 0.886LL + 2.7) + 12.73·(0.433L + 0.886LL + 2.9) + 7.06 + 0.38 = [0.6 + 12.73·0.433]L + [0.886 + 12.73·0.886]LL + [0.57+2.7+12.73·2.9+7.06+0.38] = [0.6+5.512]L + [0.886+11.28]LL + [47.13] = 6.112L + 12.17LL + 47.13. Fold LL ≤ L/e: (6.112 + 4.478)L + 47.13 = 10.59L + 47.13 vs 10.5L + 48: 10.59 > 10.5 — STILL over asymptotically by 0.09L!! At t=10: 10.59·2.48+47.13 = 73.4 vs 74.04 ✓ fits by 0.6; at t=13.15 (the loglog pinch): L = log 15.15 = 2.718, LL = 1.0: LHS pieces: 6.112·2.718 + 12.17·1.0 + 47.13 = 16.61+12.17+47.13 = 75.91 vs 10.5·2.718+48 = 76.54 — fits by 0.63 ✓; asymptotically: (10.59−10.5)L vs (48−47.13) = 0.87: 0.09L > 0.87 for L > 9.7 ⟺ t > 16 000!! At t = 10⁵: 0.09·11.5 = 1.04 > 0.87 — BREAKS for t ≳ 2×10⁴. And the contour goes to T = √N₁ = 3×10¹²!! So the asymptotic overage 0.09·L is fatal at the top of the range. Hmm!!! So even the two-unit-form piece 2 + piece-3 as-is breaks at large t. The asymptotic log coefficient budget: 10.5 − (piece-2's L-coefficient 0.592 + piece-3's 12.73·0.433 = 5.512 + ...) let me recompute the minimal achievable: pieces: Z₂ (0.57, no L) + piece2 (0.592L + 0.886LL + 2.59) + piece3 (4.5√2·[C₀(t)·1 + C₀(2t)·1 + tail]: L-coefficient 6.364·(0.433+0.433) = 5.512, LL-coefficient 6.364·(0.886+0.886) = 11.28, constants 6.364·(2.9+2.9+0.53·..)...) — the RIGHT side intervals use C₀(t+k+1) — for k up to t — C₀(t+k+1) ≤ C₀(2t+1) — with L-coefficient 0.433. So piece-3 L-coefficient: 6.364·(0.433 + 0.433) = 5.512. TOTAL L-coefficient: 0.592 + 5.512 = 6.104; LL: 0.886 + 11.28 = 12.17. The LL-fold at best gives LL/L ≤ 1/e (equality at t = 13.15): total effective L-coefficient ≤ 6.104 + 12.17/e = 6.104 + 4.478 = 10.582 > 10.5. ASYMPTOTICALLY the assembly's minimum with this structure is 10.582 — over 10.5 by 0.082. For the bound to hold for ALL t ≥ 10 up to 3×10¹², we need the total ≤ 10.5L + 48 at the top: at L = 28.7 (t = 3×10¹²): 10.582·28.7 = 303.7 vs 10.5·28.7+48−... wait the LL fold: at t = 3×10¹², LL = log(28.7) = 3.36, L/e = 10.56 — the LL≤L/e fold loses 12.17·7.2 = 87 there! So the UNFOLDED assembly: 6.104L + 12.17LL + 47.13 at t = 3×10¹²: 6.104·28.7 + 12.17·3.36 + 47.13 = 175.2 + 40.9 + 47.1 = 263.2 vs 10.5·28.7 + 48 = 349.4 — FITS by 86!! The unfolded form fits comfortably at large t; the pinch is only near t ≈ 13 (where LL/L peaks at 1/e). At t = 13.15: 6.104·2.718 + 12.17·1.0 + 47.13 = 16.59 + 12.17 + 47.13 = 75.89 vs 10.5·2.718 + 48 = 76.54 — fits by 0.65 ✓!! So the UNFOLDED honest assembly 6.104L + 12.17LL + 47.13 ≤ 10.5L + 48 holds: need 12.17·LL ≤ 4.396·L + 0.87. At the LL/L max (x = e, LL = 1, L = e): 12.17 ≤ 4.396·2.718 + 0.87 = 11.95 + 0.87 = 12.82 ✓ (by 0.65). For x ≥ e: LL grows slower; the worst point IS x = e. So the two-sided inequality 6.104L + 12.17LL + 47.13 ≤ 10.5L + 48 ⟺ 12.17LL − 4.396L ≤ 0.87 — the LHS max over t ≥ 10: d/dL[12.17 log L − 4.396 L] = 12.17/L − 4.396 = 0 at L = 2.769 (t+2 = 15.97, t = 13.97): value 12.17·1.019 − 4.396·2.769 = 12.40 − 12.17 = 0.23 ≤ 0.87 ✓. And at L = log 12 = 2.485 (t=10): 12.17·0.910 − 4.396·2.485 = 11.07 − 10.92 = 0.15 ✓. So the max of (12.17LL − 4.396L) over t ≥ 10 is ≈ 0.23 ≤ 0.87 ✓✓ COMFORTABLE (4× margin). So the honest assembly DOES prove 10.5 log(|t|+2) + 48 — with: - piece 2 via the honest two-unit Trudgian form (0.592L + 0.886LL + 2.59-ish closed form — call it Ĉ₀⁽²⁾(t)); - piece 3 as in D-056 (12.73·C₀ + 7.06 — maybe slightly sharpened); - the UNFOLDED loglog comparison (NOT LL ≤ L/e — instead prove 12.17·LL + const ≤ 4.396·L + 0.87 by calculus: max at L ≈ 2.77, value 0.23). But the Lean perimeter gives per-UNIT C0hat counts — piece 2's two-unit form 0.592L + 0.886LL + 2.59 is NOT derivable from 2·C0hat (that's 0.866L + 1.77LL + 5.8 — too big). So the perimeter declaration needs a two-unit variant. Options: (i) change ZeroCountProp AGAIN to give the two-unit form (ZeroCountProp2: #{|γ−t|≤1, mult-weighted} ≤ C0hat2(t) := 0.6·log(t+2) + 0.886·loglog(t+2) + 2.7 — needs verification that the honest form 0.592L + 0.886LL + 2.59 ≤ that closed form for t ≥ 9-ish ✓ plausible); the one-unit form follows? NO — one-unit ≤ two-unit form ✓ (one-unit window ⊂ two-unit window... zeroWindow t = [t, t+1] ⊂ |γ−t| ≤ 1? [t, t+1] ⊂ [t−1, t+1] ✓). So declaring the two-unit form SUBSUMES the one-unit form (the gap-circle and L3 consumers use [t, t+1] windows — the two-unit bound applies). Hmm — but the one-unit count ≤ two-unit closed form 0.6L + 0.886LL + 2.7 vs the OLD C0hat(t+1) = 0.433L + 0.886LL + 2.9 — the two-unit form is BIGGER in L-coefficient (0.6 > 0.433) but the existing consumers (gap circles, L3) only use C0hat qualitatively (clearances 1/(16·C0hat), 1/(3·C0hat)) — a bigger C0hat gives SMALLER clearances — do the proofs still go through? exists_zero_avoiding_T: the pigeonhole k = card ≤ C0hat — a bigger bound still works (k+1 midpoints, clearance 1/(2(k+1)) ≥ 1/(3·C0hat) — the constants 2(k+1) vs 3·C0hat: needs 3·C0hat ≥ 2(k+1) ⟸ C0hat ≥ 2, k ≤ C0hat ✓ structural). The gap circles: similar structural use. So swapping C0hat's VALUE to the two-unit form propagates... but wait, C0hat is ALSO used in LiSkeleton's marginTilde/Hhat (the baked margin!) — changing C0hat's value changes the margin computation and all certified artifacts!!! NO — don't touch C0hat. ADD a separate declared form for the two-unit window. So: new perimeter item ZeroCountProp2 (two-unit, mult-weighted, closed form 0.6L + 0.886LL + 2.7 — verify constants) — declared under the SAME Trudgian source (it's literally N(t+1)−N(t−1) + S-pair). This GROWS the declared perimeter by a specialization of an existing item (justified in the journal + ii′-7 paper appendix note). Hmm, hold on — is the two-unit closed form honestly derivable from the one-unit C0hat? NO (shown: 2·C0hat too big). Is it honestly derivable from Trudgian's F/S theorems? YES (N(t+1)−N(t−1) ≤ F(t+1)−F(t−1) + S_b(t+1)+S_b(t−1) — published). But our perimeter doesn't have F and S_b separately — only the C0hat specialization. So declaring the two-unit specialization is declaring ANOTHER consequence of the same published theorem. Honest — but it's a perimeter GROWTH (needs user sign-off). ALTERNATIVE: prove the two-unit closed form from the one-unit perimeter + monotonicity cleverness? #{|γ−t|≤1} = #{(t−1, t]} + #{(t, t+1]} ≤ C0hat(t) + C0hat(t+1) — the only route from the current perimeter. 0.866L + 1.77LL + 5.8. Too big. No. So the choice: (α) Declare the two-unit form (perimeter growth, same Trudgian source) ⟹ 5f provable at 10.5/48 with the unfolded LL treatment (max-at-L≈2.77 calculus lemma + the certified endpoint checks). (β) Keep per-unit perimeter ⟹ honest constants become A ≈ 11.2, B₀ ≈ 51 ⟹ re-bake marginTilde/Hhat + re-verify convexity + re-certify base points + (ii′-6 will face the H(T) clearance issue separately, possibly moving constants AGAIN). (α) is strictly better: keeps ALL baked constants (no downstream rework), same declared source, and the calculus lemma (12.17·LL ≤ 4.396·L + 0.87 for L ≥ log 12) is a clean one-variable real fact (max at an interior point, value comparison — provable via deriv + the two-point method already in Lean). Wait — but I should double-check the (α) fold arithmetic once more, carefully, with the EXACT piece constants, because 5f will need to reproduce them in Lean: Piece 1: ‖logDeriv ζ (2+it)‖ ≤ dirichletC2. What IS dirichletC2 in Lean? Need to check — if it's 0.57-ish ✓. (Check the def.) Piece 2: Σ_near m/|s₀−ρ| ≤ Σ_near m ≤ Ĉ₀⁽²⁾(t) := 0.6·log(t+2) + 0.886·loglog(t+2) + 2.7 — VERIFY this honest form: N(t+1)−N(t−1) ≤ F(t+1)−F(t−1) + S_b(t+1) + S_b(t−1): F(t+1)−F(t−1) = (1/2π)·∫_{t−1}^{t+1} log(x/2π) dx ≤ (2/2π)·log((t+1)/2π) = (1/π)·(log(t+2) − log 2π + log((t+1)/(t+2))·...) ≤ (1/π)·log(t+2) − (1/π)·log(2π) + (1/π)·log((t+1)/(t...)) hmm just ≤ (1/π)·log(t+2) for t+1 ≤ 2π·(t+2)-ish?? (1/π)log((t+1)/2π) ≤ (1/π)log(t+2) ⟺ (t+1)/2π ≤ t+2 ✓ always. But we need to be careful: (1/π)·log((t+1)/(2π)) could be NEGATIVE-small... For t ≥ 10 it's ≥ (1/π)·log(11/6.28) = (1/π)·0.561 = 0.179. Bound: (1/π)·log((t+1)/2π) ≤ (1/π)·log(t+1) − (1/π)·log 2π ≤ (1/π)·log(t+2) − 0.585. So F-part ≤ 0.3183·L − 0.585 where L = log(t+2). S-pair: S_b(t+1)+S_b(t−1) = 0.137·(log(t+1)+log(t−1)) + 0.443·(loglog(t+1)+loglog(t−1)) + 3.176 ≤ 0.274·log(t+2)... hmm log(t−1) < log(t+1) < log(t+2) ✓; loglog similarly (t−1 ≥ 9 > e ✓). So S-pair ≤ 0.274·L + 0.886·LL + 3.176. Total: ≤ (0.3183 + 0.274)·L + 0.886·LL + (3.176 − 0.585) = 0.5923·L + 0.886·LL + 2.591. So Ĉ₀⁽²⁾(t) := 0.6·L + 0.886·LL + 2.7 has slack: 0.0077·L + 0.109 ≥ 0 ✓ (for L ≥ 0). ✓ SAFE closed form. [This is a NEW declared specialization of Trudgian; needs the F(t+1)−F(t−1) + S_b pair bound — from the same Trudgian 2014 Thm 1. Justification: same source, different window.] Piece 3: as D-056: ≤ 4.5√2·[C₀(t)·Σ_left 1/(k(k+1)) + C₀(2t)·Σ_right + tail] ≤ 4.5√2·[C₀(t) + C₀(2t) + 0.53]·... hmm wait — D-056: "left side ≤ C₀(t), right side k ≤ t ≤ C₀(2t) ≤ C₀(t) + 0.58; the k > t tail ≤ C₀(2t)/(t+1) + 0.433/t ≤ 0.53". With C₀ = C0hat: C0hat(2t) ≤ C0hat(t+1) + 0.433·log 2 + 0.886·[LL(2t+2) − LL(t+2)]·... ≤ C0hat(t+1) + 0.31 + 0.886·(log 2)/(L)... eh — D-056's 0.58 covers it. So piece 3 ≤ 4.5√2·[C0hat(t+1) + C0hat(t+1) + 0.58 + 0.53] = 4.5√2·[2·C0hat(t+1) + 1.11] = 12.7279·C0hat(t+1) + 7.063. (4.5√2 = 6.36396; ×2 = 12.7279; ×1.11 = 7.064.) In Lean, the per-interval count: the interval (t−k−1, t−k] for k = 1..⌈t⌉: these are unit windows at heights t−k−1 ≥ ... hmm — for k close to t, the window is at LOW height (t−k−1 could be < 2, where ZeroCountProp doesn't apply!). D-056's left side: intervals down to height ~0... the count C₀(t−k) for windows at height < 2 — ZeroCountProp requires t ≥ 2. The near-window |γ−t|<1 with t ≥ 10: intervals (t−k−1, t−k] for k ≥ 1: heights ≥ t−k−1; for k ≤ t−3: height ≥ 2 ✓; for k > t−3: heights < 2 — the zeros with |γ| < 3-ish: there are NONE (first zero at 14.13!). So for t ≥ 10, the far sum's intervals with k > t − 14 are EMPTY (no zeros below 14.13). In Lean: use the first-zero fact (Zeta23 has a zero-free region to 14.13? or the IsNontrivialZero definition gives 0 < re < 1 only — the 14.13 lower bound on |γ| needs a zero-free input! Does Zeta23/our package have |γ| ≥ 14? Hmm — Zeta23 might have a zero-free disc or the classical |γ| ≥ 14 via... not sure. ALTERNATIVELY: use the A0count-style unconditional count for the low windows? The A0count bridges in LiCircleBound count windows at ALL heights (mult-weighted, unconditional: Ncount_le_of_interval...). Those give ~A₀·log — for the few low intervals the A₀ constant is fine (bounded number of intervals below height 2... actually the intervals (t−k−1, t−k] with t−k−1 < 2 means k > t−3: heights from ~−1 to 2 — but also NEGATIVE heights (γ < 0 symmetric side). The far sum over ALL zeros with |γ−t| ≥ 1: γ ranges over all ordinates — positive and negative. For γ < 0 with t ≥ 10: |γ−t| = t + |γ| ≥ t — those are the "k > t" tail on the negative side. D-056's accounting: "left side ≤ C₀(t)" (γ < t side: intervals k=1..~t, i.e., γ ∈ (0, t−1)), "right side" γ ∈ (t+1, 2t]: k ≤ t, count C₀(2t); "k > t tail": γ > 2t AND the negative side?? D-056's "k > t tail ≤ C₀(2t)/(t+1) + 0.433/t ≤ 0.53" — hmm this doesn't obviously include γ < 0. Actually by the symmetry γ → −γ (conjugate zeros — isNontrivialZero_conj in Lean), the γ < 0 side mirrors... no wait — for t ≥ 10 and γ < 0: |t−γ| = t−γ = t+|γ| which is LARGE — these are in the k > t tail: Σ_{γ<0} 4.5√2/(|t−γ|(1+|t−γ|)) = Σ_{γ' > 0} 4.5√2/((t+γ')(1+t+γ')) ≤ Σ_k C₀(k)/((t+k)(1+t+k))-ish ≤ C₀(∞)... D-056's tail bound "C₀(2t)/(t+1) + 0.433/t" might be exactly this (the far tail dominated by intervals at height ~t+k with count C₀(t+k) ≤ ...). The details need care in Lean — the negative side via conjugation symmetry. OK — the design is getting long but the shape is clear. Let me now also double check piece 3's left-side: "left side ≤ C₀(t)": the intervals (t−k−1, t−k] for k = 1, 2, ... down to height 0: counts C0hat(t−k+1) ≤ C0hat(t) for k ≥ 1 ✓ (mono, needs t−k ≥ 1 for the perimeter's t ≥ 2 — intervals with t−k ∈ [1, 2): partially... ugh, ZeroCountProp requires the window START ≥ 2. For windows starting in [0, 2): no zeros (14.13) — needs the zero-free input OR the A0count bridges. In LiCircleBound, `lowZeroConst` handles exactly this (the low zeros — from session 031: "lowZeroConst" — the finite ball count). Let me check its value: lowZeroConst is presumably 0 (no zeros below 14.13!) or a small finite count. From session-031/032 notes: "lowZeroConst" used in the series bound shell_low (2·lowZeroConst). Let me check its definition. I need to stop designing in my head and check these Lean facts. Let me look at: 1. dirichletC2's definition/value (piece 1). 2. lowZeroConst (the low-zero count — is it 0?). 3. Does the package have a |γ| ≥ 14-ish zero-free fact? 4. A0count's role for low windows. Then write D-069 (the 5f design doc) and present the perimeter-growth decision (the two-unit form declaration) to the user together with the piece-2 gap finding.
The piece-2 accounting question is resolved — but it reveals a real gap. Let me verify the key Lean-side values before finalizing the design: `dirichletC2`, `lowZeroConst`, and any zero-free input.
tool: Bash
input
{
  "command": "cd D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1; sed -n '200,215p' LiCircleBound.lean; echo ===LOW===; sed -n '330,360p' LiCircleBound.lean | grep -n \"lowZero\\|theorem\\|def\\|:=\" | head -12; echo ===ZF===; grep -rn \"14\\|zeroFree\\|zero_free\\|first zero\" LiSkeleton.lean | grep -i \"zero\\|14\" | head -8",
  "description": "Check dirichletC2, lowZeroConst, zero-free inputs"
}
#1715 assistant 2026-08-24 07:56:28.116 UTC · 32594→13507 tok open ⤢
thinking (31872 chars)
Key findings: 1. `dirichletC2 := ∑' n, ‖LSeries.term Λ 2 n‖` — the exact sum Σ Λ(n)/n² = −ζ′/ζ(2) ≈ 0.56996. D-056's piece 1 uses Z₂ ≤ 0.57. For the Lean fold, I need dirichletC2 ≤ 0.57 (a certified numeric bound — the E-028 V5 certification: partial sum to 10⁶ + tail 1.5e-5 = 0.569975 ≤ 0.5700). In Lean, bounding a tsum of LSeries norms ≤ 0.57 requires... hmm. That's a certified numeric computation — partial sums to 10⁶ in Lean?? That's heavy. Alternative: is there a closed form or a coarser bound? Σ Λ(n)/n² = −ζ′(2)/ζ(2). Could bound via ζ(2) = π²/6 and ζ′(2)... Mathlib has ζ(2). ζ′(2) — probably not. A cheaper bound: Σ Λ(n)/n² ≤ Σ (log n)/n² = −ζ′(2) ≈ 0.9375 — too big (the fold needs ≤ 0.57 with the current constants; 0.9375 would add 0.37 to the constant side — the fold had 47.13 + 0.37 = 47.5 ≤ 48 ✓ hmm actually the constant budget has room: total constant 47.13 vs 48 — 0.87 slack; adding 0.37 keeps ≤ 48 ✓!). Wait let me recompute: piece 1 ≤ −ζ′(2) = Σ (log n)/n²·... no: Λ(n) ≤ log n, so Σ Λ(n)/n² ≤ Σ log n/n² = −ζ′(2) = 0.9375. And does Lean/Mathlib have −ζ′(2)?? Unlikely. Σ log n / n² as a tsum bound — also not standard. Hmm. Actually — the cleanest: piece 1's value only needs to fit the constant budget. The fold: Z₂ + [piece2 const 2.7] + [piece3 const 7.06] + [pieces 4–6: 0.38] + [fold slack]. Let me redo the full honest fold with the two-unit perimeter form: - piece 1: Z₂ (need SOME certified bound ≤ ~1) - piece 2: 0.6L + 0.886LL + 2.7 (two-unit form) - piece 3: 12.7279·C0hat(t+1) + 7.064 where C0hat(t+1) = 0.433L' + 0.886LL' + 2.9, L' = log(t+3) - pieces 4–6: ≤ 0.045 + 0.045 + 0.29 = 0.38 L-side: piece2: 0.6L + 0.886LL; piece3: 12.7279·(0.433L' + 0.886LL') = 5.511L' + 11.277LL'. With L' = log(t+3) vs L = log(t+2): L' ≤ L + log((t+3)/(t+2)) ≤ L + 1/(t+2)·... ≤ L + 1/12 (t ≥ 10). Similarly LL' ≤ LL + small. Total L-side: 0.6L + 5.511(L + 1/12) + [0.886LL + 11.277(LL + 1/(12·...))] ≈ 6.111L + 12.163LL + (5.511/12 + 11.277/12·1/L·...) ≈ 6.111L + 12.163LL + 0.5. Constants: 0.57 + 2.7 + 7.064 + 0.38 = 10.714. Total: 6.111L + 12.163LL + 0.5 + 10.714 = 6.111L + 12.163LL + 11.214. Target: 10.5L + 48 ⟺ need 12.163·LL ≤ 4.389·L + 36.786. At the LL/L pinch (L = e, t ≈ 13.15): 12.163·1 ≤ 4.389·2.718 + 36.786 = 11.93 + 36.79 = 48.72 ✓ HUGE margin (36.6!). Wait — why so much room now? Because D-056's fold was ≤ 48 with the constant 47.8 — I mis-added: the constants: Z₂ 0.57 + piece2-const 2.7 + piece3-const 7.064 + pieces4–6 0.38 = 10.714 — and D-056 had 0.57 + [piece2 = ONE C₀: const 2.9] + 7.06 + 0.38 = 10.81?! And D-056's total constant was 47.8?! Let me recheck D-056's assembly: "5.95 log(t+2) + 12.16 log log(t+2) + 39.8 + 7.97" — the 39.8 = 13.73·2.9 = 39.82 (the C₀ constant × 13.73) and 7.97 = the other constants (0.57+7.06+0.09+0.29 = 8.01 ≈ 7.97). So D-056's constant = 13.73·2.9 + 8.01 = 47.84. My honest version: piece2's count is the two-unit form (const 2.7) instead of one C₀ (const 2.9) — SAVES 0.2 on the constant but ADDS 0.167 to the L-coefficient (0.6 vs 0.433). Piece 3 unchanged: 12.7279·C₀. So my L-coefficient: 0.6 + 12.7279·0.433 = 0.6 + 5.511 = 6.111 vs D-056's 5.95 (0.433·13.73). LL: 0.886 + 12.7279·0.886 = 12.163 ≈ 12.16 ✓ same. Constants: 2.7 + 12.7279·2.9 + 7.064 + 0.57 + 0.38 = 2.7 + 36.91 + 7.064 + 0.57 + 0.38 = 47.62 vs D-056's 47.84 — actually LOWER (the two-unit form's constant 2.7 < 2.9). So total: 6.111L + 12.163LL + 47.62 ≤ 10.5L + 48 ⟺ 12.163·LL ≤ 4.389·L + 0.38. At the pinch L = e: 12.163 ≤ 11.93 + 0.38 = 12.31 ✓ FITS by 0.15!! Let me double-check the pinch point: max of 12.163·log L − 4.389·L over L ≥ log 12 = 2.485: d/dL = 12.163/L − 4.389 = 0 ⟹ L* = 2.7716; value: 12.163·log(2.7716) − 4.389·2.7716 = 12.163·1.01947 − 12.1656 = 12.400 − 12.166 = 0.234 ≤ 0.38 ✓✓ FITS by 0.146 at the worst point. At L = 2.485 (t=10): 12.163·0.9103 − 4.389·2.485 = 11.072 − 10.907 = 0.165 ≤ 0.38 ✓ by 0.215. So the honest assembly fits 10.5/48 with margin ~0.15 at the pinch — TIGHT but provable (4–6× tighter than the D-056 fold's apparent margin, but the pinch is a smooth one-variable max — certifiable by calculus + interval evaluation). BUT — the piece-2 two-unit form (0.6L + 0.886LL + 2.7) is NOT derivable from the per-unit perimeter (2·C0hat = 0.866L + 1.77LL + 5.8 — the LL and constant terms blow the fold: LL-side would be 1.772 + 11.277 = 13.05, constants 5.8+36.91+7.06+0.95 = 50.72 — breaks 48 by 2.7 and the pinch: 13.05·LL ≤ (10.5−6.377)·L + (48−50.72) = 4.123L − 2.72: at L=2.485: LHS 13.05·0.91 = 11.88 vs RHS 10.25−2.72 = 7.53 — FAILS). So the two-unit perimeter form is REQUIRED. Confirmed the need for the new declared specialization. Now — the alternative interpretation: rather than a new perimeter item, note that the two-unit count bound 0.6L + 0.886LL + 2.7 could be declared as a SECOND clause of ZeroCountProp (the same declaration, two window shapes — both Trudgian specializations). Or a separate `ZeroCountProp2`. Either way it's a perimeter growth requiring user sign-off. Hmm, wait — actually, hold on. Is there any chance the two-unit form is derivable from the one-unit form + a SHIFT? #{(t−1,t]} + #{(t,t+1]} ≤ C0hat(t) + C0hat(t+1). C0hat(t) + C0hat(t+1) vs the two-unit form 0.6L+0.886LL+2.7: C0hat(t)+C0hat(t+1) = 0.433·(log(t+2)+log(t+3)) + 0.886·(LL(t+2)+LL(t+3)) + 5.8 ≈ 0.866L + 1.772LL + 5.8. Too big (0.866 > 0.6). No. So: 5f requires a new declared two-unit count. This is a perimeter growth (same Trudgian source). ALSO: I still owe the user the H(T)/3C0hat² clearance-coverage finding for ii′-6 (the near-sum count/clearance accounting on the contour) — that's a SEPARATE issue from piece 2, affecting marginTilde's baked 3·C0hat² and (2/3)·C0hat coefficients. Hmm — wait, let me re-examine whether that's real too, since it affects whether the baked margin survives at all. ii′-6's H(T) (horizontal contour bound): |ζ′/ζ(σ+iT)| ≤ Σ_{|γ−T|<1} 1/|s−ρ| + |R(s)|. The near sum: count × clearance. L3 (exists_zero_avoiding_T) gives T ∈ [a, a+1] with clearance 1/(3·C0hat(a+1)) vs zeros with γ ∈ [a, a+1] ONLY. The near window |γ−T|<1 ⊂ (a−1, a+2). Zeros in (a+1, a+2) or (a−1, a): NO clearance from L3. So |ζ′/ζ| on the horizontal is NOT bounded by C₀/d_min as D-036 claimed — the honest bound needs the extended pigeonhole (clearance vs all zeros in (a−1, a+2), count ≤ 3·C0hat) ⟹ near sum ≤ 3C₀·(extended clearance 1/(9C₀+3))... Hmm wait — actually, hold on: is that right? Let me redo: exists_avoiding_midpoint with the window [a, a+1] and k+1 midpoints where k = count bound: returns T ∈ [a, a+1] avoiding the k window zeros by 1/(2(k+1)). For the extended version: apply exists_avoiding_midpoint to the window [a−1/2, a+1/2]?? Hmm — but we need T at a specific height range for the contour (T ∈ [√n, √n+1]-ish for the height-window slack argument). Apply the midpoint lemma on [a, a+1] with the zero set = zeros in (a−1, a+2) (3-unit count ≤ 3C₀): midpoints in [a, a+1] — k₀+1 of them with k₀ = 3C₀ — each zero blocks ≤ 1 midpoint ⟹ T with clearance ≥ 1/(2(3C₀+1)) ≥ 1/(7C₀) from ALL zeros within (a−1, a+2) ⊇ |γ−T|<1 ✓. Then near sum ≤ count(|γ−T|<1) · 7C₀ ≤ 3C₀·7C₀ = 21·C₀². vs baked 3·C0hat². 7× worse on the C0hat² coefficient. As computed before, that kills the margin at 8×10⁴ (the crossover jumps past the certified base points and possibly past 5×10⁵!?). Hmm, no wait — my earlier smarter split: near sum ≤ inner + outer: inner |γ−T| < 1/4: count ≤ C₀ (one unit), terms ≤ 7C₀ ⟹ 7C₀²; outer 1/4 ≤ |γ−T| < 1: terms ≤ 4, count ≤ 2C₀ ⟹ 8C₀. Total ≤ 7C₀² + 8C₀. vs baked 3C₀². The increment: 4C₀² + 8C₀. In the margin at n = 8×10⁴: the C0hat²-piece of B̃ is 2(e⁴+1)·7·(coefficient)·C0hat² — coefficient 3 → 7: increment 2(e⁴+1)·7·4·47.3 ≈ 111.2·28·47.3 ≈ 147 300?!? margin(8×10⁴) was ~15 764 — NEGATIVE. At n = 5×10⁵: C0hat² ≈ 54.9: increment ≈ 111.2·28·54.9 ≈ 170 900; margin(5×10⁵) = 2.0×10⁶ → 1.83M ✓ fine. The crossover: from 80 000 to...? The increment grows like C0hat² ~ (log T)² ~ (log n)² while S grows like n log n — the crossover moves modestly (the increment at crossover n ≈ 33 000: T ≈ 183: C0hat ≈ 6.7, C0hat² ≈ 45: increment ≈ 140 000 — vs margin at 33 000 ≈ 0 (crossover!). Hmm the crossover moves to where S − B − 140 000·(C0hat²/45)-ish = 0 — maybe n ≈ 60 000–120 000. N₀ was adopted 80 000 with margin 8001 — the new margin at 80 000 is NEGATIVE (increment 147 300 > 15 764). So N₀ must move to where margin > 0 — need recomputation, but plausibly ~1.5–2×10⁵ — still ≤ 5×10⁵ (the finite verification cap) ✓ workable. The convexity/secant argument: pos_of_convex_of_two_points with base points at N₀ and 10⁵... re-certify. So the ii′-6 H(T) issue is REAL and moves the margin significantly (but survivably). HOWEVER — scope check: 5f is ONLY the R-bound. The H(T) issue belongs to ii′-6 (L0 assembly). For 5f, the required decision is just the two-unit perimeter form. The H(T) issue I should DOCUMENT (journal + a repair-map entry) but not solve now. Hmm, wait — but if the H(T) issue will force a margin re-fold at ii′-6 anyway, does the 10.5/48 R-bound still fit the (future) margin? The R-bound enters the margin via Hhat's linear term (10.5·log + 48) AND I_III's (2/3·C0hat + 10.5 log + 48). If ii′-6's near-sum accounting changes C0hat²'s coefficient 3 → 7, the margin's B-side grows by ~4·C0hat²·778 — and the crossover moves — but the R-bound's 10.5/48 stays VALID (it's a standalone analytic bound). The margin re-verification at ii′-6 will use the same R-bound. So 5f at 10.5/48 is safe to do now. Hmm — although — wait. Should I double-check the 3C0hat² in Hhat once more against ii′-6's actual future need? D-036 §2: "|ζ′/ζ(s)| ≤ C₀(T)/d_min + A log(T+2) + B₀ ≤ 3C₀(T)² + A log(T+2) + B₀ =: H(T)" — the near sum C₀(T)/d_min with d_min ≥ 1/(3C₀(√n+1)): C₀(T)·3C₀(√n+1) ≈ 3C₀². The count C₀(T) for |γ−T|<1 (two-unit window — the piece-2 issue AGAIN: honest count is the two-unit form 0.6L+0.886LL+2.7 ≈ C₀ + 0.167L − 0.2, fine) AND the clearance coverage issue (out-of-window zeros — the 3C₀² → 7C₀²+8C₀ issue). So Hhat has BOTH issues. ii′-6 will need the full repair. NOT 5f's problem — 5f is the standalone R-bound. DECISION for 5f: proceed with the honest assembly at 10.5/48, which requires the two-unit count form. Present to the user: 1. The piece-2 finding (D-056's one-C₀ usage for the two-unit window — a real but small assembly gap; the bound survives via the honest two-unit Trudgian form + the unfolded loglog pinch analysis with ~0.15 margin at the pinch). 2. The required perimeter growth: a two-unit mult-weighted count bound (same Trudgian source, new specialization: 0.6·log(t+2) + 0.886·loglog(t+2) + 2.7 for |γ−t| ≤ 1, t ≥ 10). 3. The documented ii′-6 finding (H(T) clearance coverage — 3C0hat² → ~7C0hat²+8C0hat honest; margin impact to be faced at ii′-6; N₀/crossover will move). Actually hold on — before presenting, let me double-check the two-unit closed form once more, since it must be EXACT (it's a declared bound — well, it's a hypothesis, so it just needs to be TRUE and reasonably clean): Two-unit mult-weighted count: #{ρ : |γ−t| ≤ 1, mult} = N(t+1) − N(t−1) ≤ F(t+1) − F(t−1) + S_b(t+1) + S_b(t−1) (Trudgian 2014: N(T) = F(T) + S(T), |S(T)| ≤ S_b(T) := 0.137 log T + 0.443 log log T + 1.588 for T ≥ e). F(t+1) − F(t−1): F(T) = (T/2π)(log(T/2π) − 1) + 7/8. F is convex-increasing (F'(T) = (1/2π)log(T/2π) > 0 for T > 2π). F(t+1)−F(t−1) = ∫_{t−1}^{t+1} F' ≤ 2·F'(t+1) = (1/π)·log((t+1)/2π) (F' increasing). ≤ (1/π)·log(t+2)... hmm need ≤ (1/π)·log(t+2) − 0.585-ish for the fold. Actually for the declaration I just need the CLOSED FORM to honestly majorize: claim N(t+1)−N(t−1) ≤ 0.6·log(t+2) + 0.886·loglog(t+2) + 2.7 for t ≥ 10: - F-part ≤ (1/π)·log((t+1)/2π) ≤ 0.31831·log(t+2) − 0.31831·log(2π)·(1 − ...) hmm: log((t+1)/2π) = log(t+2) − log(2π) − log((t+2)/(t+1)) ≤ L − 1.8379 (since log((t+2)/(t+1)) ≥ 0). So F-part ≤ 0.31831·L − 0.58492. - S-pair ≤ 0.274·L + 0.886·LL + 3.176 (as before: 0.137·2·L... wait: 0.137·(log(t+1)+log(t−1)) ≤ 0.137·2·log(t+1) ≤ 0.274·L? log(t+1) ≤ log(t+2) = L ✓. 0.443·(LL(t+1)+LL(t−1)) ≤ 0.443·2·LL = 0.886·LL ✓ (t−1 ≥ 9 > e so LL(t−1) ≥ 0... loglog(t−1) requires log(t−1) ≥ 0 ⟺ t ≥ 2 ✓; and LL monotone ✓). Constants: 2·1.588 = 3.176. - Total ≤ (0.31831 + 0.274)·L + 0.886·LL + (3.176 − 0.58492) = 0.59231·L + 0.886·LL + 2.5911. - Closed form: 0.6·L + 0.886·LL + 2.7: difference = (0.6−0.59231)·L + (2.7−2.5911) = 0.00769·L + 0.1089 ≥ 0 ✓ for all L ≥ 0. HONEST ✓. So the declared two-unit form: #{mult-weighted, |γ − t| ≤ 1} ≤ 0.6·log(t+2) + 0.886·loglog(t+2) + 2.7 for t ≥ 10. (Hmm — should it be |t| for negative t too? The R-bound is stated for |t| ≥ 10 with σ ∈ [−5/2, 3] — the s = σ+it with t possibly negative. D-056 states |t| ≥ 10. The near window |γ−t|<1 for t negative uses the conjugate symmetry. For the Lean statement, handle t ≥ 10 and extend to |t| ≥ 10 by conjugation? The LiDisc capstones handled all |t| ≥ 10 — via nearZeros t with t possibly negative (they had the conj machinery: isNontrivialZero_conj). For 5f, following D-056: state for t ≥ 10 first? D-056 says |t| ≥ 10. The ii′-6 consumer needs |t| = T ≥ 10 positive heights (T = √n+1 > 0) — and the conjugate for the bottom horizontal. Let me design the Lean theorem for t ≥ 10 and note the t ≤ −10 extension via conj if needed. Actually the LiDisc capstone `logDeriv_riemannZeta_sub_nearZeros_le` was stated for 10 ≤ |t| (both signs) with the near sum over nearZeros t. For 5f the tight version should match: 10 ≤ |t|. The proof: t ≥ 10 direct; t ≤ −10 via conjugation (logDeriv ζ (conj s) = conj (logDeriv ζ s)? — riemannZeta_conj: ζ(conj s) = conj ζ(s); logDeriv conj: logDeriv ζ (conj s) = conj (logDeriv ζ s) — needs deriv under conj — Zeta23 might have it; the 5c/5d capstones handled both signs via logDeriv_riemannZeta_sub_nearZeros_le_left/right separately — for the LEFT half they reflected. For t < 0, nearZeros t = conj (nearZeros (−t)) presumably via isNontrivialZero_conj. This is mechanical but adds work. Design choice: prove for t ≥ 10; add the t ≤ −10 corollary via conjugation.) OK. Now — WAIT. One more simplification check: does 5f really need the two-unit form, or can the near window be SHRUNK? The near sum in R(s) is Σ_{|γ−t|<1} m/(s−ρ) — the window |γ−t|<1 is intrinsic to the R-bound's definition (it's what ii′-6 subtracts). Could 5f instead prove the R-bound for a DIFFERENT near window, e.g. |γ−t| < 1/2 (one unit)? Then the far sum includes 1/2 ≤ |γ−t| < 1 zeros with per-term ≤ 4.5√2/(x(1+x)) at x ∈ [1/2, 1] — the far-sum interval sum starts at k=... the |t−γ| ∈ [1/2,1] interval: per-term ≤ 4.5/(0.5·√1.25) = 8.05; count ≤ C₀; so the far sum gains ≤ 8.05·C₀... and piece 2 becomes ≤ C₀(t) (one unit!). Net: piece2 saves 0.167L−0.2, far sum gains 8.05·C₀ vs the k=1 interval's previous 4.5√2/(1·2)·C₀ = 3.18·C₀ — increment 4.87·C₀ ≈ 2.1·L. WORSE. No. So the two-unit perimeter form is needed. But actually — hmm, ONE more alternative: bound the near sum via the SERIES difference directly without the count?? Σ_near m/|s₀−ρ| ≤ Σ_near m — no alternative. Alright — also quickly reconsider (β) once more (honest A=11.2, B₀=51 from the per-unit perimeter) vs (α) (two-unit declaration): (β) requires re-baking marginTilde/Hhat constants + re-verifying convexity (session-011 proof, ~2 tight numeric blocks) + re-certifying base points + N₀ crossover recomputation + paper text at ii′-7. (α) requires: one new declared hypothesis (same Trudgian source) + the pinch-point calculus lemma. (α) is much cheaper and keeps all certified artifacts valid. RECOMMEND (α). Note the perimeter growth is honest but must be declared in the paper's appendix at ii′-7 (the freeze allows this at ii′-7). Hmm — one more thought on (α): is the two-unit form really a "new" perimeter item, or can it be folded into ZeroCountProp as a conjunction? ZeroCountProp currently: ∀ t ≥ 2, (window [t,t+1] mult-count) ≤ C0hat(t+1). The two-unit form: ∀ t ≥ 10, (#{|γ−t| ≤ 1} mult-count) ≤ 0.6 log(t+2) + 0.886 LL(t+2) + 2.7. These are two different shapes — cleanest as a separate def `ZeroCountProp2` (or a renamed combined prop). A separate def keeps the existing consumers untouched. The capstone signatures then take (hZC : ZeroCountProp) (hZC2 : ZeroCountProp2). The perimeter count goes from 4 to 5 declared items (same source family). At ii′-7, the paper's appendix declaration updates. Hmm, or... actually — reconsider ONE more time whether the two-unit bound can be DERIVED from ZeroCountProp by a smarter split: #{|γ−t|≤1} = #{(t−1, t−1/2]} + #{(t−1/2, t]} + #{(t, t+1/2]} + #{(t+1/2, t+1]} — half-unit windows, each ≤ the unit bound C0hat — 4·C0hat?? worse. No: sub-window counts ≤ full-window count (monotonicity of the count in the window inclusion!) — each half-window ⊆ a unit window ⟹ ≤ C0hat. 4 half-windows ≤ 4·C0hat. Worse than 2·C0hat. No gain. The perimeter only speaks about full unit windows. CONFIRMED: need the declaration. Let me also double check that the honest two-unit form is indeed TRUE (it's a declaration, but it must be mathematically valid — the Trudgian S_b bound applies for T ≥ e ✓; F' increasing for T > 2π ✓; the mult-weighted N(t+1)−N(t−1) = Σ_{t−1 < γ ≤ t+1} m ✓ — N(T) counts with multiplicity by definition ✓; |γ−t| ≤ 1 vs (t−1, t+1]: the open/closed endpoints don't matter for the bound ✓). And the pinch lemma: for L ≥ log 12 (t ≥ 10): 12.163·log L ≤ 4.389·L + 0.38 — hmm let me restate with cleaner constants. The full assembly: |R| ≤ 6.111·L + 12.163·LL + 47.62 where L = log(t+2), LL = log L. Wait — but I should double-check the piece-3 right-side count: intervals (t+k, t+k+1] for k = 1..⌈t⌉-ish have counts ≤ C0hat(t+k+1) ≤ C0hat(2t+1)?? The window start t+k ≥ t+1 ≥ 11 ≥ 2 ✓ perimeter applies. C0hat(2t+1) = 0.433·log(2t+3) + 0.886·LL(2t+3) + 2.9 ≤ 0.433·(L + log 2·(1+...)) hmm: log(2t+3) vs L = log(t+2): (2t+3)/(t+2) = 2 − 1/(t+2) ≤ 2 ⟹ log(2t+3) ≤ L + log 2 = L + 0.693. LL(2t+3) = log(log(2t+3)) ≤ log(L + 0.693) ≤ LL + 0.693/L ≤ LL + 0.28 (L ≥ 2.485). So C0hat(2t+1) ≤ C0hat(t+1) + 0.433·0.693 + 0.886·0.28 = C0hat + 0.30 + 0.248 = C0hat + 0.548 ≤ C0hat + 0.55. (D-056 said +0.58 — consistent.) Piece 3 ≤ 4.5√2·[C0hat(t+1) + (C0hat(t+1) + 0.55) + 0.53]·... wait the tail: "k > t tail ≤ C₀(2t)/(t+1) + 0.433/t ≤ 0.53" — let me trust D-056's 0.53 but redo: tail = Σ_{k > t} 4.5√2·count_k/(k(k+1)) + the negative-γ side. Hmm — actually the per-interval sum Σ_{k=1}^{K} 1/(k(k+1)) = 1 − 1/(K+1) ≤ 1 — the LEFT side intervals (k = 1..~t−1): ≤ C0hat(t+1)·(1). The RIGHT side (k = 1..~t): ≤ C0hat(2t+1)·1. The TAIL (k > t): Σ_{k>t} C0hat(t+k+1)/(k(k+1)) — with C0hat(t+k+1) ≤ C0hat(2k+1) ≤ 0.433·log(2k+3) + ... ≤ 0.433·(log k + 0.7) + ... — D-056's bound: ≤ C₀(2t)/(t+1) + 0.433/t ≈ 0.53 at t=10 decreasing. For the Lean proof this tail needs a clean summable bound: Σ_{k>t} C0hat(t+k+1)/(k(k+1)) ≤ Σ_{k>t} [0.433·log(t+k+1) + 0.886·LL(t+k+1) + 2.9]/(k(k+1)) ≤ [0.433·log(2t+... hmm — for k > t: t+k+1 ≤ 2k+... ≤ 3k: log(t+k+1) ≤ log(3k) = log 3 + log k. And Σ_{k>t} log k/(k(k+1)) ≤ Σ_{k>t} log k/k² ≤ ∫_{t−1}... ≤ (log t + 1)/t·... At t ≥ 10: ≤ (log 10+1)/10 ≈ 0.33. Plus 2.9·Σ_{k>t} 1/(k(k+1)) = 2.9/(t+1) ≤ 0.27. Plus the LL piece ≤ 0.886·LL(3t)/... small. Tail ≤ ~0.7 at t = 10 decreasing. D-056 used 0.53. For safety use 0.75. Then piece 3 ≤ 4.5√2·[C0hat(t+1) + C0hat(t+1) + 0.55 + 0.75] = 6.36396·[2·C0hat(t+1) + 1.30] = 12.7279·C0hat(t+1) + 8.273. Hmm — slightly bigger constant than D-056's 7.06 (my tail is cruder). Total constants: 0.57 + 2.7 + 8.273 + 0.38 = 11.92; the C0hat constant piece: 12.7279·2.9 = 36.91. Total constant: 36.91 + 11.92 = 48.83 — vs 48!! OVER by 0.83. Hmm. Tighten the tail: at t ≥ 10: Σ_{k>t} log(3k)/(k(k+1)): bound Σ_{k>t} 1/(k(k+1)) = 1/(⌊t⌋+1) ≤ 1/10.5 hmm t ≥ 10 ⟹ k ≥ 11 (k > t ≥ 10, k integer ≥ 11): Σ_{k≥11} 1/(k(k+1)) = 1/11 ≈ 0.0909. Σ_{k≥11} log k/(k(k+1)) ≤ Σ_{k≥11} log k/k² ≤ ∫_{10}^∞ (log x)/x² dx = [−(log x + 1)/x]_{10}^∞ = (log 10 + 1)/10 = 0.3303. So tail ≤ 0.433·(0.3303 + log 3·0.0909) + 0.886·LL-ish·0.0909 + 2.9·0.0909 ≤ 0.433·(0.3303+0.0999) + 0.886·(log log(3·11))·0.0909 + 0.2636 ≈ 0.433·0.4302 + 0.886·1.206·0.0909 + 0.2636 ≈ 0.1863 + 0.0971 + 0.2636 ≈ 0.547. Hmm ≈ 0.55. So tail ≤ 0.55 (not 0.75). Piece 3 constant: 6.36396·(0.55 + 0.55) = 6.36396·1.10 = 7.0004 — wait: piece 3 = 4.5√2·[C₀ + (C₀+0.55) + 0.55] = 4.5√2·(2C₀ + 1.10) = 12.7279·C₀ + 7.0004. Constants: 0.57 + 2.7 + 7.00 + 0.38 = 10.65; C0hat-constant: 36.91. Total: 47.56 ≤ 48 ✓ (0.44 room). L-side: 6.111L + 12.163LL. Pinch check: need 12.163·LL − 4.389·L ≤ 0.44 for L ≥ 2.485: max at L* = 12.163/4.389 = 2.7716: value 12.163·1.01947 − 4.389·2.7716 = 12.400 − 12.166 = 0.234 ≤ 0.44 ✓ (1.9× margin). At L = 2.485: 0.165 ≤ 0.44 ✓. OK — FITS with ~0.2–0.44 margin. Tight but certifiable. (These are all my hand estimates — the Lean proof will need the constants done exactly; there's enough room.) Also pieces 4–6 need their honest forms: piece 4/5: |1/s − 1/s₀| ≤ |s₀−s|/(|s||s₀|) ≤ 4.5/t² ≤ 0.045 ✓; piece 6: the ψ-difference — Lemma D (digamma remainder) + the log-difference bound: ½|log(s/2) − log(s₀/2)| + ½|1/s − 1/s₀| + ½(|r(s/2)|+|r(s₀/2)|) — D-056 got ≤ 0.29. Lemma D in Lean: `norm_digamma_sub_log_le_of_two_le_abs_im` (5d) gives ‖ψ(w) − log w‖ ≤ 3 for |im w| ≥ 2 — much weaker than Lemma D's 1.2/|w|² but here we only need the DIFFERENCE ψ(s/2) − ψ(s₀/2) = log(s/2) − log(s₀/2) + O(1/|s|²): |log(s/s₀)| = |log(s/s₀)| with s/s₀ near 1: |log(s/s₀)| ≤ 2·|s/s₀ − 1| ≤ 2·|s₀−s|/|s₀| ≤ 2·4.5/|t| ≤ 9/t. And the remainder difference: via 5d's ‖ψ−log‖ ≤ 3: |ψ(s/2)−ψ(s₀/2)| ≤ |log(s/2)−log(s₀/2)| + 6 — the +6 is WAY too big (piece 6 budget 0.29!). So 5f needs the SHARP digamma remainder (Lemma D: |r(w)| ≤ 1.2/|w|²) — which is D-039's content... which D-056 §1 PROVED on paper (the Binet + recurrence argument) but is it in Lean? 5d's bound is the crude ‖ψ(w) − log w‖ ≤ 3. Lemma D (1.2/|w|²) is NOT in Lean (D-056 §1 was a paper proof; the Lean side has only the 5d crude bound). So 5f also needs Lemma D in Lean — the Binet second formula + the recurrence error E(w) — that's a real analytic sub-build (~0.5 session per D-056 §1's structure: Binet integral bound + the max-principle argument for E(w)... the max-principle on g(u)/u⁴ — Lean has the maximum modulus machinery ✓ but this is work). Hmm — OR avoid Lemma D: bound the ψ-DIFFERENCE directly via the digamma series: ψ(s/2) − ψ(s₀/2) = Σ_j [1/(s₀/2+j) − 1/(s/2+j)] = (s/2 − s₀/2)·Σ_j 1/((s/2+j)(s₀/2+j))... Σ_j 1/((s/2+j)(s₀/2+j)) ≤ Σ_j 1/|s₀/2+j|²-ish ≤ Σ 1/(t/2)²-ish — the series Σ_{j≥0} 1/((t/2)²+j²)-ish ≈ (π/t)-ish... Hmm: ψ(w₁) − ψ(w₂) = Σ_{n≥0} [1/(w₂+n) − 1/(w₁+n)] (the Weierstrass series difference — termwise) = (w₁−w₂)·Σ 1/((w₁+n)(w₂+n)). With |w₁−w₂| = |s−s₀|/2 ≤ 2.25 and |1/((w₁+n)(w₂+n))| ≤ 1/(|im|−...)²... For w = s/2, im w = t/2 ≥ 5: |w+n| ≥ t/2; |w₀+n| ≥ t/2: term ≤ 4/t². Σ over n ≥ 0 of 4/t² DIVERGES. Need the smarter form: |1/((w₁+n)(w₂+n))| ≤ 1/|w₀+n|²·(1+...)... Σ_n 1/|w+n|² for w with im = t/2: Σ_n 1/((t/2)² + (n+re w)²) ≈ ∫ dx/((t/2)²+x²) = π/(t/2) = 2π/t. So the difference ≤ 2.25·(2π/t)·(1+o(1)) ≈ 14/t·... hmm at t = 10: ≈ 1.4 — still bigger than 0.29·2 = 0.58 budget (piece 6 is ½|ψ-diff| ≤ 0.29 ⟹ |ψ-diff| ≤ 0.58). 2.25·2π/10 = 1.41 > 0.58. Hmm. But the sharp version: ψ(w) = log w − 1/(2w) + O(1/|w|²): the difference ψ(w)−ψ(w₀) = log(w/w₀) − (1/2)(1/w − 1/w₀) + O(1/|w|²): |log(w/w₀)| ≤ 1.1·|w/w₀ − 1| = 1.1·|w−w₀|/|w₀| ≤ 1.1·2.25/5 = 0.495 at t=10; the 1/(2w) difference: (1/2)·|w−w₀|/(|w||w₀|) ≤ 0.5·2.25/25 = 0.045; the r-difference: 2·1.2/|w|²·... ≤ 2.4/25 = 0.096. Total |ψ-diff| ≤ 0.495+0.045+0.096 = 0.636; half: 0.318 — hmm slightly over D-056's 0.29 but the log part: |log(w/w₀)| with w/w₀ = (s/2)/(s₀/2) = s/s₀: |s/s₀| = |s|/|s₀| ∈ [0.55/1, ...]... σ ∈ [−5/2,3], s₀ = 2+it: |s−s₀| = |σ−2| ≤ 4.5; |s₀| ≥ |t|: |log(s/s₀)| ≤ |s/s₀ − 1|/(1−|s/s₀−1|)-ish ≤ 1.1·(4.5/10) = 0.495 at t=10. So ½|ψ-diff| ≤ 0.318 vs D-056's 0.29. Over by 0.03 — because D-056's 0.23 for ½|log(s/s₀)| used |arg(s/s₀)| ≤ 4.5/|t| hmm: |log(s/s₀)|² = (log|s/s₀|)² + arg²; D-056: "½|log(s/s₀)| ≤ 0.23 at |t| = 10" — via |log|s/s₀|| ≤ 0.02 and |arg| ≤ 4.5/|t| = 0.45: |log(s/s₀)| ≤ √(0.02² + 0.45²) ≈ 0.45; ½·0.45 = 0.225 ≤ 0.23 ✓. My 1.1·|Δ| bound gave 0.495 (lossy by the 1.1 + only-modulus). The arg form: |arg(s/s₀)| ≤ |s−s₀|/|s₀|·(1+...) = 4.5/10 = 0.45 (arg ≤ tan-ish). OK so with the arg/modulus split, ½|log| ≤ 0.226, ½|1/(2w)-diff| ≤ 0.023, ½|r-diff| ≤ 0.048: total 0.297 ≈ 0.29 ✓ D-056's. So piece 6 needs the ARG bound on log(s/s₀) + the sharp digamma remainder r bound 1.2/|w|². The r bound (Lemma D) is the Binet argument — a real sub-build. Alternatively, piece 6 crude-but-sufficient: need ½|ψ(s/2) − ψ(s₀/2)| ≤ C₆ with the total fitting. Budget for piece 6: 48 − (other pieces). Other pieces at the pinch: Z₂ 0.57 + piece2 2.7 + piece3-const 7.00 + pieces4–5 0.09 = 10.36; C0hat-const 36.91; total-without-6: 47.27. Room for piece 6: 48 − 47.27 = 0.73. So piece 6 ≤ 0.73 suffices!! My crude 0.318–0.636... the ½|ψ-diff| ≤ 0.318 (arg-split version) fits; the cruder 0.636/2... wait ½·0.636 = 0.318 ✓ also fits (0.318 ≤ 0.73). And even cruder: via 5d's ‖ψ(w) − log w‖ ≤ 3: ½|ψ-diff| ≤ ½|log(w/w₀)| + ½·6 = 0.226 + 3 = 3.23 — too big. So the middle route: the digamma SERIES difference |ψ(w)−ψ(w₀)| ≤ |w−w₀|·Σ_n 1/|w+n||w₀+n| with Σ ≤ 2π/t·(1+o(1)) — the o(1) needs care — gives ½·2.25·(2π/t + small) ≈ ½·2.25·0.66 = 0.74 at t=10 — JUST over 0.73! Knife-edge again. The ARG-split + series route: ½|log(w/w₀)| ≤ 0.226 + ½·|series-remainder-difference|... Hmm, actually the cleanest: |ψ(w) − ψ(w₀)| ≤ |log w − log w₀| + |(ψ−log)(w)| + |(ψ−log)(w₀)|. The (ψ−log) remainder via the SERIES: ψ(w) − log w = −1/(2w) − Σ_{n≥1} 1/((w+n)·n)·... the Weierstrass form: ψ(w) = −γ − 1/w + Σ_{n≥1}(1/n − 1/(w+n))... and log w = ... the identity ψ(w) = log w − 1/(2w) − Σ... not clean. OK — enough. The point: piece 6 has budget 0.73 and multiple routes land ≤ 0.32–0.74 — the sharp Lemma D route (0.29) is the paper's; a Lean-friendly route via the digamma series difference exists but needs the Σ 1/|w+n|² ≤ 2π/t·(1+o(1)) estimate (the 5d/5e-ii machinery has the separated reciprocal sums — `digamma_recip_sum_le` (C) gives Σ‖(w+j)⁻¹‖ ≤ 2/c + 2 + 2·log m for dist ≥ c — that's for the near-axis; the strip version Σ 1/((t/2)²+(n+u)²) ≤ π/(t/2)+... via arctan-FTC (5d's pattern) ✓ machinery exists). So 5f's full piece list in Lean: 1. dirichletC2 ≤ 0.57 — NEEDS a certified tsum bound! Σ Λ(n)/n² ≤ 0.57. In Lean: the tsum is symbolic. Options: (a) partial sum to N + tail bound — a finite computation: Σ_{n≤N} Λ(n)/n² + tail ≤ 0.57 with the tail (log N+1)/N... E-028 used N = 10⁶. In Lean, Σ_{n≤10⁶} Λ(n)/n² is a HUGE finite computation — decide-able but slow (10⁶ terms with real division... as rationals? Λ(n) is log p or 0 — the sum over prime powers: Σ_p log p ·(1/p² + 1/p⁴ + ...) = Σ_p log p/(p²−1)... the partial sum to 10⁶ as a rational number — evaluating in Lean by norm_num/decide is infeasible (10⁶ terms). Native_decide with floats?? Not trustworthy for the audit (well — native_decide IS trusted-ish... no, native_decide adds an axiom-free trust in the compiler — the project avoids it; the LiBasePoints used certified interval arithmetic via proved rational bounds). Alternative: (b) bound dirichletC2 by a clean analytic expression: Σ Λ(n)/n² = −ζ′(2)/ζ(2). Does Mathlib have ζ′(2)? No. (c) Coarser: Σ Λ(n)/n² ≤ Σ log n/n² =: −ζ′(2) ≈ 0.9375 — still needs a tsum bound. Σ_{n≥2} log n/n² ≤ ∫_1^∞ log x/x² + (max log x/x² at x = e^{1/2})... Σ_{n≥2} log n/n² ≤ (log 2)/4 + ∫_2^∞ log x/x² dx = 0.173 + (log 2 + 1)/2 = 0.173 + 0.847 = 1.02 — too big (need ≤ 0.57 + the 0.73 budget slack ≈ ≤ 1.3 — wait piece 1's budget: total constants 48 − (36.91 + 2.7 + 7.00 + 0.38) = 48 − 46.99 = 1.01! So piece 1 ≤ 1.01 suffices!! Σ Λ(n)/n² ≤ Σ_{n≥2} log n/n² ≤ 1.02 — KNIFE-EDGE over. Hmm. Sharper: Σ_{n≥2} log n/n²: exact ≈ 0.9375. Integral bound with the first terms exact: (log 2)/4 + (log 3)/9 + ∫_3^∞ log x/x² = 0.1733 + 0.1221 + (log 3+1)/3 = 0.1733+0.1221+0.6995 = 0.9949 ≤ 1.01 ✓ FITS by 0.015. KNIFE-EDGE but the first-terms-exact version is a clean Lean-provable bound (two exact rationals-logs + the integral (log 3 + 1)/3 via integration by parts — Mathlib has ∫ log x/x²? Hmm — `Real.integral_...`? Might need to derive: d/dx[−(log x + 1)/x] = (log x)/x² ✓ so ∫_3^N = (log 3+1)/3 − (log N+1)/N → (log 3+1)/3. Provable via FTC (intervalIntegral with the explicit antiderivative — doable: `intervalIntegral.integral_deriv_eq_sub` or by the hasDeriv pattern). And the tail series ≤ integral needs the decreasing-ness of log x/x² for x ≥ 3 (deriv ≤ 0) — `AntitoneOn.integral_le_sum` reversed: for decreasing f ≥ 0, Σ_{n≥N+1} f(n) ≤ ∫_N^∞ f — Mathlib: `Summable`/`integral_le_sum`... there are lemmas like `Real.sum_le_integral_of_decreasing`? For tsum: `tsum_le_integral...`? Might need the partial-sum form + limits. Routine but real work.) Actually — simpler: does the fold even need dirichletC2 ≤ 0.57? The R-bound theorem is |R| ≤ 10.5L + 48. Piece 1 enters the CONSTANT side. Budget 1.01. So I need dirichletC2 ≤ 1.01, provable via the first-two-terms + integral bound (≈ 0.995). OK — feasible. Note: this produces the bound ‖logDeriv ζ (2+it)‖ ≤ dirichletC2 ≤ 0.995 — slightly weaker than Z₂ = 0.57 but FITS the budget. 2. The two-unit count (perimeter growth — USER DECISION). 3. Piece 3 far sum: the per-interval machinery — significant Lean work (the interval decomposition of the far sum Σ_{|γ−t|≥1} m·(s₀−s)/((s−ρ)(s₀−ρ)) — needs: termwise bound 4.5√2/(x(1+x)) [x = |t−γ|]; the split into unit intervals on both sides + the negative-γ side via conjugation; per-interval mult-counts from the perimeter (left: ≤ C0hat(t+1) via mono for windows in [2, t]; the LOW windows (< 2): no zeros?? — need the zero-free input |γ| ≥ 14.13... WAIT — do we have that in Lean? The nontrivial zeros: |γ| ≥ 14.13 is the verified RH-to-height-3×10¹²'s weaker cousin — the zero-free region |t| ≤ 14-ish is... RHUpTo is a PERIMETER hypothesis (Platt–Trudgian) — available! hRH : RHUpTo 3×10¹² gives zeros on the line up to that height — but does it give the LOW bound |γ| ≥ 14? RHUpTo says zeros with |γ| ≤ 3×10¹² have re = 1/2 — it does NOT say there are no zeros with |γ| < 14!! The first-zero statement "no nontrivial zeros with |γ| ≤ 14" is a separate classical fact (backlund: the zeros start at 14.13). Is it in Zeta23 or our package? lowZeroConst — defined as Σ over lowZeros of mult·(1+1/‖ρ‖) — lowZeros := zeros with ‖ρ‖ ≤ some bound? Let me check the lowZeros def — from session-031: "lowZeroConst" built from the finite ball — if it's NONZERO, then the low windows have a count input via lowZeroConst (finite, unconditional). Let me check its definition/value. Hmm — actually for piece 3, the LEFT intervals (t−k−1, t−k] for k = 1..⌈t−2⌉: windows starting at t−k−1 ≥ ... ≥ 2 requires k ≤ t−3; for k ∈ (t−3, t): windows starting in [0, 2) — the zeros there: none (14.13) — OR use lowZeroConst if it covers them. But actually — hmm, simpler: for the left side, intervals with t−k−1 < 2 contain only zeros with γ < 3 < 14.13 — if we have the zero-free fact, those intervals are EMPTY. If we don't, we need SOME count. Let me check what zero-free inputs exist: grep "14.13" or "zeroFree" in Zeta23/our package. Also — wait, hmm: is it even true that the perimeter ZeroCountProp's range (t ≥ 2) suffices for all the left intervals? k from 1 to ~t: window start t−k−1 ranges from t−2 down to ~−1. Windows with start < 2: (t−k−1, t−k] with t−k−1 < 2 ⟺ k > t−3. For t ≥ 10: k ∈ (7, 10): windows like (1,2], (0,1], (−1,0]... zeros with γ ∈ (−1, 3]: NONE (|γ| ≥ 14.13). So need the zero-free fact. If unavailable: these intervals' zeros are part of the |γ| ≤ 3 ball — the lowZeros finset. lowZeroConst is a SUM (mult·(1+1/‖ρ‖)) — from it, the COUNT of lowZeros ≤ lowZeroConst/(1+1/‖ρ‖)-ish... messy. Check if Zeta23 has the 14.13 zero-free region. Let me grep for it.
Now checking what zero-free/low-zero inputs exist (piece 3's low intervals need them) and the `lowZeros`/`lowZeroConst` definitions.
tool: Bash
input
{
  "command": "cd D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1; grep -n \"def lowZeros\\|def lowZeroConst\\|lowZeros :=\" LiCircleBound.lean | head -4; grep -rn \"14.13\\|14.134\\|zeroFree\\|zero_free\\|no.*zero.*below\\|zeros.*empty\" LiSkeleton.lean LiCircleBound.lean LiDisc.lean | head -8; echo ===Z23===; grep -rn \"14.13\\|14.134\" D:/Python/Quantum/zeta-23-lean/Zeta23/ --include=\"*.lean\" -l | head -3",
  "description": "Find lowZeros definition and zero-free inputs"
}
#1716 assistant 2026-08-24 07:58:35.770 UTC · 753→2378 tok open ⤢
thinking (7063 chars)
- `lowZeros` = nontrivial zeros with ‖ρ‖ ≤ 3 — a finite subtype finset; `lowZeroConst` = Σ mult·(1+1/‖ρ‖) over it — a SYMBOLIC constant (not evaluated — the package has no zero-free input proving lowZeros is empty!). So the package does NOT currently have the |γ| ≥ 14.13 fact. The LiCircleBound series bound treated lowZeroConst symbolically. For 5f's piece-3 left-side intervals with start < 2: zeros with γ ∈ (−1, 3): these have ‖ρ‖ ≥ |γ|... hmm — the low-zero treatment: any zero with |γ| < 3 has ‖ρ‖ = √(re² + γ²) ≤ √(1 + 9) < 3.2... hmm — ‖ρ‖ ≤ 3 covers |γ| ≤ √8 ≈ 2.83. The count of lowZeros ≤ lowZeroConst·(something) — from lowZeroConst's definition: each term is mult·(1+1/‖ρ‖) ≥ mult·1 ⟹ the COUNT Σ mult ≤ lowZeroConst ✓. But lowZeroConst is symbolic — its VALUE is unknown (it's 0 in reality, but the package doesn't prove that). Using it in the 5f fold would inject a symbolic constant into the 10.5/48 fold — breaking the numeric target unless lowZeroConst is bounded. Is lowZeroConst ≤ anything provable? Its terms: mult·(1+1/‖ρ‖) for ‖ρ‖ ≤ 3 — the total mult-count of zeros in the ball ≤ A0count-style count: from LiCircleBound's count bridges (A0count covers all t) — Σ_{‖ρ‖≤3} mult ≤ the unit-window counts... The point: for piece 3, the intervals with window-start < 2 are at heights (−1, 3) for t ≤ ~13: these zeros have |γ| ≤ 3 — but actually nontrivial zeros have |γ| ≥ 14.13 (TRUE, but not in the package). Hmm — WAIT. Is that right? The package has the RHUpTo perimeter hypothesis (Platt–Trudgian: zeros with |γ| ≤ 3×10¹² have re = 1/2) — but that's about the real part, not exclusion of low zeros. The statement "there are NO nontrivial zeros with |γ| ≤ 14" is the statement that the first zero is at 14.13 — this FOLLOWS from RHUpTo + ... no! RHUpTo says zeros up to 3×10¹² are on the line — it doesn't say zeros EXIST at 14.13 or DON'T exist below 14. The nonexistence below 14 is a separate classical computation (Backlund 1914: N(14.5)-ish counts). Hmm — actually it follows from the Riemann–von Mangoldt count + the location of the first zeros... The package's zero-free inputs: Mathlib has ζ(s) ≠ 0 for re s ≥ 1 (riemannZeta_ne_zero_of_one_le_re) and re ≤ 0 via FE... but zeros in 0 < re < 1 with small |γ|: no input. BUT — do I actually NEED the low-interval emptiness for piece 3? The left-side intervals (t−k−1, t−k] for k = 1..~t: the ones with start < 2 are at heights (−1, 2]. Zeros there have |γ| ≤ 2 < 3. In the far sum, their contribution: per-term 4.5√2/(x(1+x)) with x = |t−γ| ≥ t−2 ≥ 8 (for t ≥ 10). So the low-zero contribution ≤ 4.5√2/(8·9)·(low mult-count) ≤ 0.0884·(count). The low mult-count ≤ lowZeroConst... symbolic. OR via A0count: the ball ‖ρ‖ ≤ 3 ⊂ window [−3, 3]... the A0count bridges count unit windows at ALL heights? `sum_zeroMult_le_of_im_band` (session 032): "band [a,b] + sign-separation c ⟹ 3·A₀·(b−a+2)·log(3·max|a||b|+5)" — for the band [−3, 3]: ≤ 3·A₀·8·log(14) ≈ 63·A₀. With A₀ symbolic (Classical.choose of the RvM existential) — its value is some fixed real, but not numerically bounded in the package?! Hmm — is A0count numerically bounded anywhere? A0count_pos exists. A0count's value: from zeta_local_zero_count — an existential — so A0count is symbolic-positive. The 5f fold needs NUMERIC constants. If A0count enters piece 3's low-interval count, the fold breaks (symbolic A₀ can't be ≤ a number). Hmm!! Wait — how did the 5c/5e capstones avoid this? They used A0count SYMBOLICALLY — the circle bounds have A₀ in them (400000·A₀·Ĉ₀·(log R)²) — symbolic A₀ was fine there (the squeeze only needed O((log R)³)). For 5f's NUMERIC 10.5/48, every piece must be numeric. Piece 3's low intervals need a numeric count → need the zero-free fact |γ| ≥ 14 (or a numeric bound on the low count). Options: (i) prove the zero-free fact |γ| ≥ 14 in Lean — that's the Backlund-style computation N(14.5) = 0-ish... actually the cleanest classical proof: the count N(T) for T = 14-ish via the argument principle numerically — HEAVY. OR from the perimeter! The RHUpTo perimeter hypothesis (Platt–Trudgian): zeros with |γ| ≤ 3×10¹² are on the line — combined with... no, still doesn't exclude low zeros. Hmm — actually, wait: does Platt–Trudgian's statement include the zero count/locations? Platt–Trudgian verified RH to 3×10¹², meaning all zeros with 0 < γ ≤ 3×10¹² have re = 1/2. It does NOT say the first zero is at 14.13. The first-zero location is a separate input (could be part of the same computational certificate — Platt's computation located the zeros). Hmm — but as a LEAN hypothesis, RHUpTo only encodes the on-line property. Hmm — actually, is there a cheap analytic proof that |γ| ≥ 14? The functional equation + the positivity of... The classical argument: N(T) counts via the argument principle: N(14.5) computed by evaluating the Riemann–Siegel / argument variation — shows 1 zero below 14.5 (at 14.13)... The nonexistence below 14.13 is genuinely computational (interval arithmetic on ξ). In Lean: could use the mult-count bridges + a numeric evaluation of the ARGUMENT PRINCIPLE integral... heavy. ALTERNATIVE for piece 3's low intervals: use the A0count bridge but with a NUMERIC bound on A0count! Is A0count numerically bounded anywhere? The RvM local count zeta_local_zero_count is an existential — but maybe its proof gives an explicit witness... In Zeta23, zeta_local_zero_count — let me check if the witness is explicit (then A0count ≤ explicit number could be proved). From LiCircleBound line 50: `def A0count : ℝ := Classical.choose Zeta23.RvM.zeta_local_zero_count` — Classical.choose of an existential: the value depends on the proof term. If the Zeta23 proof is constructive with an explicit constant, A0count has a defeq value... but Classical.choose extracts SOME witness; bounding it requires unfolding the proof. There might be a spec lemma: A0count_spec or similar. Hmm. Actually for the fold, ANY numeric bound on A0count suffices (the low intervals' contribution is tiny: 0.0884·(3·A₀·8·log 14) ≤ 17·A₀ — no wait, that's not tiny unless A₀ is small. The RvM local count constant is typically ~1–2. Let me check Zeta23 for the witness. Actually — hmm, hold on. Simpler: the low intervals (start < 2) only arise for t ∈ [10, ~13] (for t ≥ 14, ALL left intervals start ≥ 2... no wait — the left intervals go ALL the way down: (t−k−1, t−k] for k = 1..⌈t⌉ — for t = 1000, intervals down to height ~0! The low ones (start < 2) are only the last ~3 of them (heights (−1, 2]) regardless of t ✓. So the low-interval contribution: intervals (−1, 0], (0, 1], (1, 2] — zeros with γ ∈ (−1, 2] — and the negative side is handled by conjugation (γ < 0 mirrors γ > 0 — the far sum over γ < −... hmm wait, the LEFT side for t ≥ 10 is γ ∈ (0, t−1) — positive heights below t. The intervals (−1, 2] contain only zeros with |γ| ≤ 2 — in reality none. If the package can't prove that, their count is bounded by the A0count bridges numerically?— only if A0count has a numeric bound. Let me check whether Zeta23's zeta_local_zero_count has an explicit constant or a spec with a bound.
Checking whether `A0count` has a numeric bound (needed for piece 3's low intervals) — looking at the Zeta23 RvM local count statement and any spec lemmas.
tool: Bash
input
{
  "command": "grep -rn \"zeta_local_zero_count\" D:/Python/Quantum/zeta-23-lean/Zeta23/RvM/*.lean | head -5; grep -rn \"A0count_spec\\|A0count_le\\|A0count_eq\\|local_zero_count.*\u2264\\|local_zero_count.*<=\" D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1/*.lean D:/Python/Quantum/zeta-23-lean/Zeta23/RvM/*.lean 2>/dev/null | head -8",
  "description": "Check A0count for numeric bounds"
}
#1717 assistant 2026-08-24 08:05:06.815 UTC · 1100→10305 tok open ⤢
thinking (23768 chars)
The RvM constant is `max 1 (max (2 * A₁) K)` — symbolic (A₁ from half_count_large, K from a finite count) — no explicit numeric value. So A0count has no numeric bound in the package. Using it in 5f's numeric fold would require bounding it — a sub-project. So for piece 3's low intervals, the clean route is a **numeric zero-free input**: no nontrivial zeros with |γ| ≤ 14 (say). Is that derivable cheaply? Hmm — actually, wait. Let me think about whether piece 3 even needs the low-window counts to be NUMERIC... The far sum Σ_{|γ−t|≥1} m·(s₀−s)/((s−ρ)(s₀−ρ)): bound per term 4.5√2/(x(1+x)), x = |t−γ| ≥ 1. Split: - LEFT (γ < t−1, includes all negative γ and low positive): intervals (t−k−1, t−k], k = 1..K_max where the intervals bottom out at... γ ≥ −∞ — the intervals extend down indefinitely! (t−k−1, t−k] for k → ∞: γ → −∞. The per-interval count for low/negative heights: the A0count bridge gives count ≤ A₀·log(|height|+3) — SYMBOLIC A₀. The sum Σ_k A₀·log(k+5)/(k(k+1)) converges but has A₀ in it — the total would be (something)·A₀ — symbolic — BREAKS the numeric fold. Hmm!! Wait — but D-056's piece 3 says "left side ≤ C₀(t)". How does that handle the deep-negative γ? For γ very negative, x = |t−γ| = t + |γ| — large — the intervals are (t−k−1, t−k] with k up to t+|γ| — the per-interval counts C₀(t−k) for t−k < 0... C₀ of a negative height? D-056's left-side bound ≤ C₀(t) treats the whole left side as intervals with count ≤ C₀(t) — the count of the window at height t−k for k > t is the count of zeros in NEGATIVE-height windows — by conjugation = count at |t−k|... The honest statement: the interval (t−k−1, t−k] for k > t contains zeros with negative ordinates; by conjugation symmetry their count equals the count in (k−t, k−t+1] (positive) ≤ C₀(k−t+1)... which GROWS with k. The per-term weight 4.5√2/(k(k+1)). So the left side Σ = Σ_{k=1}^{∞} count_k·4.5√2/(k(k+1)) where count_k ≤ C0hat-ish(min(k−t+1, t+1)-ish)... For k ≤ t−2: count ≤ C₀(t). For k > t: count ≤ C₀(k−t+1) ≤ 0.433·log(k−t+3)+... The tail Σ_{k>t} C₀(k−t+1)/(k(k+1)) ≤ Σ_j C₀(j+1)/((j+t)(j+t+1)) ≤ C₀-ish·Σ 1/(j+t)² ≤ C₀(j~small)... — C₀(j+1) for small j is the LOW count again (symbolic via A₀)!! Hmm no — C₀ as a closed form 0.433 log(j+3) + ... is a VALID upper bound only where the perimeter/Trudgian applies (j+1 ≥ 2). For j < 2: the zeros with |γ| ≤ 3-ish: count unknown (symbolic). BUT the per-term weight at those k is ≤ 4.5√2/((t)(t+1)) ≤ 4.5√2/110 ≈ 0.058 at t = 10. So the low-zero contribution to the far sum ≤ 0.058·(low mult count). If the low mult count is symbolic (lowZeroConst-ish or A₀-based), the fold breaks by a symbolic term × 0.058. Hmm — UNLESS we use the A0count bridge and accept A₀ symbolically in the bound... but then the final fold ≤ 10.5L + 48 needs A₀ gone. OK so no matter what, 5f needs SOME numeric handle on the low zeros. Cleanest: the classical fact "no nontrivial zeros with |im| ≤ 14" (or ≤ 3, enough for the intervals at play... wait — the negative side: intervals (t−k−1, t−k] for k ∈ (t−3, t+3] cover heights (−4, 2]: zeros there have |γ| ≤ 4. So the needed input: no zeros with |γ| ≤ 4 (or 14). This is a FINITE numeric fact (the first zero is at 14.13). How to prove in Lean cheaply? Option (z1): from RHUpTo + ... no (RHUpTo doesn't exclude low zeros). Option (z2): a new tiny perimeter declaration: "no nontrivial zeros with |im| ≤ 14" — this is part of the Platt–Trudgian certificate semantically (they located the zeros) but NOT implied by RHUpTo as encoded. It's the same CLASS as the other perimeter items (computational, published). Hmm — perimeter growth again. Option (z3): prove it from the argument principle numerically — the rectangle integral of ζ′/ζ over the box [−1, 2]×[−14, 14]... in Lean, with interval arithmetic — a real sub-build (~1 session+, needs numeric ζ evaluation in Lean — we don't have a numeric ζ oracle in Lean!). Option (z4): derive from a ζ-value fact in Mathlib: does Mathlib have ζ(0) = −1/2 and nonvanishing on [some interval]? No zero-free strip in the critical strip. Option (z5): avoid the low intervals entirely by NOT splitting there: bound the left-side far sum differently — pair each far zero's term with 1/|ρ|... hmm: Σ_{|γ−t|≥1} m/((|t−γ|)(1+|t−γ|)) — for the zeros with |γ| ≤ 3: ≤ Σ_{|γ|≤3} m/((t−3)(t−2)) ≤ (low count)·2/t² — the low count via... symbolic. Circular. Hmm — wait, actually, hold on: maybe use the SERIES total instead. The far difference sum is bounded by Σ_all m/((x)(1+x))... Or bound the whole far sum via the CONVERGENT majorant Σ m/(1+γ²) (Zeta23's zero_sum_inv_sq — symbolic value?) — zero_sum_inv_sq gives SUMMABILITY, the sum's value is symbolic. Hmm. Actually — hmm, wait. Let me reconsider. For the low intervals, do we even need their count to be ZERO or numeric? The far-sum total must be ≤ 12.73·C₀ + 7.06 — NUMERIC. Every piece must be numeric. The low intervals contribute (low count)·(their weight). If the low count is symbolic, no numeric fold. So YES — need a numeric low-zero input. The honest cheapest: a small perimeter declaration `NoLowZeros : ∀ ρ, IsNontrivialZero ρ → 14 ≤ |ρ.im|` — justified as part of the Platt–Trudgian-class computational certificate (it's the classical first-zero location, machine-verified many times; arguably implied by the Platt–Trudgian computation which located all zeros to 3×10¹²). It's a new declared item. Hmm — wait, actually. Is it implied by RHUpTo + the N(T) machinery? N(T) for T = 14: F(14) ≈ (14/6.28)·log(14/6.28) − 14/6.28 + 0.875 ≈ 2.229·0.802 − 2.229 + 0.875 ≈ 1.788 − 1.354 = 0.434. |S(14)| ≤ S_b(14) = 0.137·2.64 + 0.443·0.97 + 1.588 ≈ 0.362 + 0.430 + 1.588 = 2.38. N(14) ≤ 0.434 + 2.38 = 2.81 — doesn't give 0. So no, the Trudgian count can't exclude low zeros (the S_b slack is too big). The first-zero exclusion needs the actual zero-location computation. So it's a genuine new perimeter item (Platt-class: Platt–Trudgian's certificate DOES include the zero locations to 3×10¹² — declaring "no nontrivial zeros with 0 < |im| ≤ 14" is a weak consequence of their certificate). Hmm hold on, wait — actually does it? Platt–Trudgian verified RH up to 3×10¹²: all zeros with 0 < γ ≤ 3×10¹² have re = 1/2. This doesn't exclude zeros at LOW heights either — it's an on-line statement, not a count. The zero LOCATIONS (first at 14.13) come from the zero-counting part of such computations (locating sign changes of Z(t)). Platt's 2017/Platt–Trudgian 2021 computations did isolate the zeros (that's HOW you verify RH — count zeros via Turing's method and locate them). So "no zeros with |γ| < 14" is a certified consequence of the Platt-class computation — same trust class. But as a LEAN hypothesis it's new. Hmm, wait — alternatively, is "no zeros with |γ| ≤ 14" provable from RHUpTo 3×10¹² + the RvM count + ...? No — RHUpTo is purely on-line. OK so 5f needs TWO perimeter additions: (P1) ZeroCountProp2 (two-unit mult-weighted window count, closed form 0.6L + 0.886LL + 2.7, t ≥ 10) — Trudgian N(T)/S(T) specialization. (P2) NoLowZeros (no nontrivial zeros with |im| ≤ 14 — or some explicit height) — Platt-class zero-location certificate. Both are honest, same-class-as-existing-perimeter declarations. But the perimeter is the trusted surface and growing it needs the user's sign-off — especially (P2). Hmm, wait — actually, let me reconsider (P2). Is there a way to bound the low-zero count numerically from EXISTING proved material? The mult-count of zeros with |γ| ≤ 3: via Jensen on a disc (LiDisc machinery!): scaledZeta_jensen_count gives a NUMERIC bound? The Jensen count: ≤ log((9/4)|t|²)/log(33/32) — for the disc at 2+it with |t| ≤ 3: log((9/4)·9)/log(33/32) = log(20.25)/0.03077 ≈ 3.008/0.0308 ≈ 97.8. So the low count ≤ 98 NUMERICALLY (the Jensen bound is fully proved in LiDisc — no perimeter!). The low-interval contribution: zeros with |γ| ≤ 3, in the far sum their x = |t−γ| ≥ t−3 ≥ 7: per-term ≤ 4.5√2/(7·8) = 0.1137; count ≤ 98: contribution ≤ 11.15?!? WAY too big (the far-sum budget is ~12.73·C₀ ≈ 60–100, but the constant side...). Hmm wait — 11.15 on the constant side: total constant 47.56 + 11.15 = 58.7 > 48. BREAKS. The Jensen count 98 is too lossy (true count is 0). Refine: the low zeros' far-sum contribution with the x-weight: Σ_{|γ|≤3} m·4.5√2/(x(1+x)) with x ≥ t−3: ≤ (count)·4.5√2/((t−3)(t−2)). At t = 10: 98·6.364/42 = 14.8. Too big. At larger t it decays (1/t²) but the fold's t=10 pinch is where it matters. So the Jensen route breaks the constants. NEED the true zero-free input (P2). Hmm, unless... bound the low count via the A0count bridge: count of zeros in [−3, 3] ≤ 3·A₀·8·log(14) ≈ 63·A₀ — A₀ symbolic. No. What about a TIGHTER Jensen: the disc of radius 5/2 at 2+it covers re ≥ −1/2... for the low zeros a disc centered at 2 (t=0) radius ~4: Jensen with the disc bound ‖ζ‖ ≤ (3/4)|t|²... at t=0 the disc bound is ‖ζ‖ ≤ (3/4)·|t|² — at t = 0 that's 0?! The LiDisc bound needed |t| ≥ 10. For a disc at height 0: ‖ζ‖ on B(2, 4): the max of |ζ| there — a numeric fact... could be computed from the EM representation (LiRBound's level-2 form!) at finitely many... — the EM bound: ‖ζ(s)‖ ≤ 1/2 + 1/|s−1| + |s(s+1)|·∫₁^∞ B̃₂(x)x^{−σ−2} — at re ≥ −1/2: the integral ≤ ∫₁^∞ (1/12)x^{−3/2} = 1/6-ish; so ‖ζ(s)‖ ≤ 1/2 + 1/(dist to 1) + |s(s+1)|/6 — on the circle |s−2| = 4: |s(s+1)| ≤ 6·7 = 42; 1/|s−1| ≤ 1/3 (nearest point s = −2: |−2−1| = 3); so ‖ζ‖ ≤ 0.5 + 0.34 + 7 = 7.84 on the circle. Jensen count of zeros in B(2, 3.5): ≤ log(7.84/|ζ(2)|)/log(4/3.5)·... |ζ(2)| = π²/6 ≈ 1.645: log(7.84/1.645) = log 4.77 = 1.562; radius ratio 4/3.5: log(8/7) = 0.1335: count ≤ 1.562/0.1335 = 11.7. So ≤ 11 zeros (with mult) in B(2, 3.5) ⊇ {|γ| ≤ 3}-ish. Contribution: 11·0.1137 = 1.25 at t=10 — still too big (budget-wise: constant side 47.56+1.25 = 48.8 > 48 ✗). Tighter disc: B(2, 3.2) count ≤ log(4.77)/log(4/3.2) = 1.562/0.223 = 7.0 ⟹ 7·(weight at x ≥ t−3.2+...) ≈ 7·6.364/((6.8)(7.8)) ≈ 0.84 at t=10. Still 0.84 over a budget of 0.44. Hmm. Tighter still: B(2, 2.5): log(4.77)/log(4/2.5) = 1.562/0.470 = 3.32 ⟹ count ≤ 3.32 — the zeros with |γ| ≤ √(2.5²−1) ≈ 2.3: contribution 3.32·6.364/((t−2.3)(t−2.3+1)) at t=10: 3.32·6.364/(7.7·8.7) = 0.315 ≤ 0.44 ✓ FITS! So a Jensen count ≤ 3.32 for zeros in B(2, 2.5) + the far-weight gives ≤ 0.32 at t=10 — but WAIT: zeros with 2.3 < |γ| ≤ 3 fall OUTSIDE this disc — they're in the far sum with x = |t−γ| ∈ [t−3, t−2.3]: their count via the LARGER disc B(2, 3.5) minus... the annulus count: ≤ 11.7 (B(2,3.5) count) with weight 4.5√2/((t−3)(t−2)) = 0.1137 at t=10: ≤ 1.33. Hmm — the annulus zeros (2.3 < |γ| ≤ 3) — do any exist? In reality NO (first zero 14.13). The Jensen count of the annulus = count(B(2,3.5)) − count(B(2,2.5))-ish — Jensen gives upper bounds only: 11.7 for the big disc INCLUDING the small one. Annulus ≤ 11.7. Contribution ≤ 11.7·0.1137 = 1.33. Over budget again. To kill it: need the annulus empty — zero-free. ARGH. Actually — the cleanest: the Jensen count on a disc containing ALL of {|γ| ≤ 3}: if that count is < 4 (say ≤ 3.32 via B(2, 2.5))... but zeros at |γ| ∈ (2.3, 3] aren't covered. Cover {|γ| ≤ 3} with a disc where Jensen gives < 1: count < 1 ⟹ count = 0 ⟹ ZERO-FREE! Jensen count < 1 needs log(M/|ζ(2)|)/log(R/r) < 1 ⟺ M/|ζ(2)| < R/r. With M = 7.84 (on |s−2| = 4), |ζ(2)| = 1.645: M/|ζ(2)| = 4.77; R/r = 4/r: need r > 4/4.77 = 0.84. So for the disc B(2, r) with r ∈ (0.84, ...): Jensen count ≤ log(4.77)/log(4/r) < 1 ⟺ r > 4/4.77 = 0.839. So: the count in B(2, 0.85) ≤ log(4.77)/log(4/0.85) = 1.562/1.549 = 1.008 — hmm > 1 barely. B(2, 0.9): 1.562/log(4/0.9) = 1.562/1.493 = 1.046 — worse (bigger disc). B(2, 0.84): log(4/0.84) = 1.560: 1.562/1.560 = 1.001. Hmm the ratio M/|ζ(2)| = 4.77 ≈ R/r needs r ≈ 0.84 — count ≤ 1.001 — just OVER 1. To get count < 1: need a bigger outer disc (better ratio): outer R = 5: M on |s−2| = 5: ‖ζ‖ ≤ 0.5 + 1/4 + |s(s+1)|/6 ≤ 0.75 + 8·9/6 = 12.75; M/|ζ(2)| = 7.75; log 7.75 = 2.048; inner r: need log(5/r) > 2.048 ⟺ r < 5/7.75 = 0.645. So B(2, 0.64) has count ≤ 2.048/log(5/0.64) = 2.048/2.056 = 0.996 < 1 ⟹ ZERO-FREE in B(2, 0.64) ⟹ no zeros with |γ| ≤ √(0.64² − ...) hmm — B(2, 0.64) covers |γ| ≤ √(0.64² − 1²)?? re ρ ∈ (0,1): ρ ∈ B(2, 0.64) requires |γ| ≤ 0.64... so zero-free for |γ| ≤ 0.64 only. The strip zeros with |γ| ∈ (0.64, 3]: not covered. Bigger discs have worse M. The disc approach can't reach |γ| ≤ 3 (M grows like |s(s+1)|/6 ~ R²/6, log M ~ 2 log R, and log(R/r) ~ log R — ratio → 2 — count → ~2·(log|ζ(2)|⁻¹+...)/1 — can't get below ~1.5–2 for r ~ 3). So Jensen CANNOT prove the low-zero emptiness to |γ| ≤ 3. It can only give count ≤ 2-ish for |γ| ≤ 3 — contribution to the far sum ~2·0.11 = 0.22 ≤ 0.44 budget ✓?? Let me redo: the best Jensen disc covering {|γ| ≤ 3}: need r ≥ √(9+1) ≈ 3.16 (re ρ ≤ 1: |ρ−2| ≤ √(1+γ²)): r = 3.2, outer R = 6: M on |s−2| = 6: ≤ 0.5+1/5+10·11/6 = 0.7+18.3 = 19; M/|ζ(2)| = 11.55; log = 2.447; log(6/3.2) = 0.628; count ≤ 2.447/0.628 = 3.90. ⟹ ≤ 3.9 for |γ| ≤ 3. Far-weight at t=10: x ≥ 10−3 = 7: 4.5√2/(7·8) = 0.1137 ⟹ contribution ≤ 3.9·0.1137 = 0.443 — JUST at the 0.44 budget!! KNIFE-EDGE. And my M estimate is crude (|s(s+1)| ≤ 10·11 — the max of |s(s+1)| on |s−2|=6 at s = 2+6i... |s| = |2+6i| = 6.32, |s+1| = 7.16: product 45.3/6 = 7.55; hmm |s(s+1)| max on the circle: s = −2−6i? |s| = 6.32, |s+1| = |−1−6i| = 6.08: 38.4. At s = 2+6i: 6.32·7.16 = 45.3. At s = 8: |s(s+1)| = 72. At s = −4: 4·3 = 12. So max ≈ 72 (s = 8): M ≤ 0.5 + 1/7 + 72/6 = 12.64. M/|ζ(2)| = 7.68, log = 2.039. count ≤ 2.039/0.628 = 3.25. Contribution 3.25·0.1137 = 0.369 ≤ 0.44 ✓.) So the Jensen route MIGHT fit the budget with a careful M — but every constant here needs exact Lean verification (the EM bound on a circle, |ζ(2)| = π²/6, the log evaluations...) and it only gives count ≤ 3.25 for |γ| ≤ 3 — whereas the TRUTH is 0. The contribution 0.37 vs budget 0.44 — knife-edge again, and it eats the pinch margin. vs (P2): declare "no nontrivial zeros with |im| ≤ 14" (Platt-class certificate — it IS part of what Platt–Trudgian-style computations certify; Turing's method explicitly counts and locates zeros). Then the low intervals are EMPTY and the issue vanishes. MUCH cleaner. So the honest 5f needs TWO perimeter additions: (P1) the two-unit count, (P2) the low-zero exclusion. Both same-class (published computational certificates). This is a perimeter growth from 4 to 6 items — significant, needs user sign-off. Hmm, wait — actually, let me reconsider (P2) ONE more time. Does the far sum REALLY hit the low zeros? The far sum Σ_{|γ−t|≥1} m(s₀−s)/((s−ρ)(s₀−ρ)) — for t ≥ 10, the zeros with |γ| ≤ 3 have x = |t−γ| ≥ 7, contributing ≤ (count)·4.5√2/(7·8)·... — with (P2) count = 0: contribution 0 ✓. Without (P2): symbolic. YES, (P2) or a numeric low-count is required. Hmm — OR: restate the far sum split to avoid low zeros: split at |γ−t| ≥ 1 into 1 ≤ |γ−t| ≤ 3 and |γ−t| > 3?? No... The low zeros are unavoidable in the far sum (they're part of seriesFun). Their contribution must be bounded numerically — either via (P2) (count 0) or a numeric count bound (Jensen — knife-edge 3.25 with heavy verification). Actually — WAIT. Alternative for the low-zero contribution without ANY new input: bound Σ_{|γ|≤3} m/(x(1+x)) ≤ Σ_{|γ|≤3} m/(x²) ≤ Σ_{|γ|≤3} m·2/(1+γ²)·(1+γ²)/x²... and Σ_{|γ|≤3} m/(1+γ²) is part of Zeta23's zero_sum_inv_sq total (symbolic sum value). No. OR use the LiSkeleton/E-011-style: the first zeros are at 14.13 — the E-008/E-011 zero tables computed 10⁴ zeros — but those are NUMERICS, not Lean facts. To get the fact into Lean: declaration (perimeter) or a verified-computation Lean proof (out of scope). So (P2) it is — as a declared perimeter item. Actually — hold on, one more: could RHUpTo be REPLACED/STRENGTHENED to include the low-zero exclusion? RHUpTo 3×10¹² (Platt–Trudgian) — the semantic content of the Platt–Trudgian certificate: "all zeros with 0 < γ ≤ 3×10¹² have re = 1/2 AND there are exactly N of them at the expected locations" — the Turing-method certificate includes the zero COUNT matching N(T) — which implies no zeros below the first located one. So (P2) is a consequence of the FULL Platt–Trudgian certificate. Declaring it separately under the same source is honest. (Paper appendix at ii′-7 will list it.) Alright — the design is now clear enough to present to the user. The 5f plan: **New perimeter declarations (2, same source classes as existing):** - (P1) `ZeroCountProp2`: the two-unit mult-weighted window count: ∀ t ≥ 10, Σ_{|γ−t|≤1} m ≤ 0.6·log(t+2) + 0.886·loglog(t+2) + 2.7 (Trudgian N(t+1)−N(t−1) + S_b pair specialization). - (P2) `NoLowZeros`: ∀ ρ nontrivial, 14 ≤ |ρ.im| (Platt-class zero-location certificate; the classical first-zero exclusion). **5f build (LiTightR.lean):** 1. The reference-point difference identity from partialFraction_identity at s and s₀ = 2+it (B cancels): logDeriv ζ s = logDeriv ζ s₀ + Σ m(1/(s−ρ)−1/(s₀−ρ)) − (1/s−1/s₀) − (1/(s−1)−1/(s₀−1)) − ½(ψ(s/2)−ψ(s₀/2)). Needs: the series difference termwise = Σ m(s₀−s)/((s−ρ)(s₀−ρ)) + summability of the difference series (the seriesSummable machinery + the difference identity — a tsum subtraction argument). 2. Piece 1: ‖logDeriv ζ s₀‖ ≤ dirichletC2 ≤ 0.995 (first-terms + integral bound on Σ Λ(n)/n²... wait — dirichletC2 = Σ ‖LSeries.term Λ 2 n‖ = Σ Λ(n)/n². The bound ≤ 0.995 via (log 2)/4 + (log 3)/9 + (log 3+1)/3 — needs Λ(n) ≤ log n and the integral Σ_{n≥4} log n/n² ≤ ∫_3^∞ log x/x² = (log 3+1)/3 — the decreasing-tail integral comparison (Mathlib: `Summable`... the lemma form: for f decreasing nonneg, Σ_{n≥N} f n ≤ f N + ∫_N^∞ — `tsum_le_integral`? hmm — there's `MeasureTheory...` no — for real decreasing f: `Real.tsum_le_integral...`? There might be something like `summable... integral_test` — the integral test gives equivalence not inequality. The inequality Σ_{n≥N+1} f(n) ≤ ∫_N^∞ f for decreasing f: `AntitoneOn...`? I recall `Real...`? If missing, prove via per-term f(n+1) ≤ ∫_n^{n+1} f and tsum of integrals = the big integral. ~30 lines.) Hmm — actually even simpler: dirichletC2 ≤ 0.995 might be avoidable: Σ Λ(n)/n² where Λ(n) ≤ log n·[n prime power]... the cheapest: Λ(n) ≤ log n for all n (ArithmeticFunction.vonMangoldt_le_log? — exists in Mathlib ✓ I believe) ⟹ dirichletC2 ≤ Σ_{n≥2} log n/n² — and that tsum ≤ 0.995 via the integral comparison. OK. 3. Piece 2: near sum at s₀ ≤ the two-unit count (P1) — needs |s₀−ρ| ≥ 1 for near zeros (re ρ < 1 ⟹ |s₀−ρ| ≥ 2−re ρ > 1... ≥ 1 via |re part| ≥ 1: |s₀−ρ| ≥ |re(s₀−ρ)| = 2 − re ρ ≥ 1 ✓ (re ρ < 1 ⟹ 2 − re ρ > 1 ≥ 1 — actually ≥ 1 suffices: abs_re_le_norm). 4. Piece 3: the far sum — the big one. Termwise: ‖(s₀−s)/((s−ρ)(s₀−ρ))‖ ≤ 4.5/(|t−γ|·√(1+(t−γ)²))·... hmm D-056 used |s−ρ| ≥ |t−γ| and |s₀−ρ| ≥ √(1+(t−γ)²) ≥ (1+|t−γ|)/√2. Then per-interval grouping + counts. In Lean: the interval machinery (like LiCircleBound's dyadic/band counts but with the TIGHT C0hat perimeter counts). The negative-γ side: via conjugation (isNontrivialZero_conj exists) or direct: intervals (t−k−1, t−k] for k > t cover negative heights — the count of zeros in (a, a+1] for a < −1... the perimeter ZeroCountProp requires t ≥ 2! Negative-height windows: via conjugation, count in (−b−1, −b] = count in [b, b+1)... (conj maps γ → −γ; the window (−b−1, −b] maps to [b, b+1)). So the negative-side interval counts via the positive-side perimeter + conj. LiCircleBound's shell_crit did exactly this (the conj for γ < 0 — banked). The count for windows starting below 2 (i.e., a ∈ (−2, 2)): EMPTY by (P2) (|γ| ≥ 14 > window range) — the intervals (a, a+1] with a+1 ≤ 14... hmm wait — the LEFT intervals (t−k−1, t−k] for k ≥ 1: when t−k ≥ 14... all fine; when t−k−1 < 2: those intervals cover heights < 3 < 14 ⟹ empty by (P2) IF the interval is within (−14, 14): (t−k−1, t−k] with t−k ≤ 14... for the negative side via conj, heights |γ| ≥ 14 ⟹ intervals (t−k−1, t−k] empty when t−k ≤ 14 AND t−k−1 ≥ −14. For t−k−1 < −14 (deep negative): count via conj = count in (|t−k−1|, |t−k|]-ish positive windows ≥ 14 ✓ perimeter applies. So the empty zone: windows inside (−14, 14): contribution 0 by (P2) ✓. The interval sum: Σ_k count_k·4.5√2/(k(k+1)) ≤ 4.5√2·[C0hat(t+1)·Σ_{1≤k≤t−2} 1/(k(k+1)) + 0 (empty zone) + C0hat(2t+1)·Σ_{...} + tail]. The bookkeeping: left side k=1..⌈t⌉−2-ish ≤ C0hat(t−... hmm the count for window (t−k−1, t−k] is ≤ C0hat(t−k) ≤ C0hat(t) ≤ C0hat(t+1) (mono, needs t−k−1 ≥ 2 ⟺ k ≤ t−3; for k ∈ (t−3, t+13]: empty; for k > t+13: conj side). This is getting intricate but it's the same FLAVOR as LiCircleBound's shell machinery (which took ~2 sessions). Estimate: 1–1.5 sessions for piece 3. 5. Pieces 4–5: |1/s − 1/s₀| ≤ 4.5/|t|² ≤ 0.045 (|s| ≥ |t|, |s₀| ≥ |t|... ‖1/s − 1/s₀‖ = |s₀−s|/(|s||s₀|) ≤ 4.5/t² ≤ 4.5/100 = 0.045 ✓ elementary). 6. Piece 6: the ψ-difference — needs the sharp remainder (Lemma D, 1.2/|w|²) OR the series-difference route with budget 0.73. The series route: ψ(w) − ψ(w₀) = Σ_{j≥0} [1/(w₀+j) − 1/(w+j)] hmm — the Weierstrass series: ψ(w) = −γ − 1/w + Σ_{j≥1} (1/j − 1/(w+j))? — difference: ψ(w)−ψ(w₀) = −(1/w − 1/w₀) − Σ_{j≥1}(1/(w+j) − 1/(w₀+j)) = −(1/w−1/w₀) + Σ_{j≥1} (w−w₀)/((w+j)(w₀+j)). With |w−w₀| ≤ 2.25, w₀ = s₀/2 = 1 + it/2, w = s/2: |(w+j)(w₀+j)| ≥ |im|²-ish... Σ_{j≥1} 1/|w+j||w₀+j| ≤ Σ 1/((t/2)² + (j+re w)²)-ish ≤ ∫... ≤ π/(t/2)·... ≈ 2π/t + 4/t². At t=10: 0.628+0.04 = 0.668; ×2.25 = 1.50. Over the 0.73 budget!! Hmm. The sharper per-term: |1/(w+j) − 1/(w₀+j)| = |w₀−w|/|w+j||w₀+j| — summed ≈ 2.25·2π/t = 1.41 at t=10 — the TRUE ψ-difference is ≈ |log(w/w₀)| ≈ 0.45 — the series bound is 3× lossy. Because the log(s/s₀) part IS the answer — the series difference sums to the log. So the sharp route (Lemma D) is needed: ψ(w) = log w − 1/(2w) + r(w), |r| ≤ 1.2/|w|²: ψ-diff = log(w/w₀) − (1/2)(1/w−1/w₀) + r-diff: |log(w/w₀)| ≤ 0.45-ish (arg/modulus split), |(1/2)(1/w−1/w₀)| ≤ (1/2)·2.25/(5·5) = 0.045, |r-diff| ≤ 2.4/25 = 0.096: total ≤ 0.45+0.045+0.096 = 0.591; ½·0.591 = 0.296 ≤ 0.73 ✓. So Lemma D (the 1.2/|w|² remainder) IS needed in Lean. That's D-056 §1's Binet + max-principle argument — a genuine analytic sub-build (~0.5–1 session: Binet's second formula is NOT in Mathlib! Building it: Binet's formula for log Γ or ψ... Mathlib has the Bohr–Mollerup / Weierstrass forms but Binet's integral? Probably not. Hmm — alternatives to Binet: the sharp remainder |ψ(w) − log w + 1/(2w)| ≤ 1.2/|w|² could be proved via the Euler–Maclaurin series with the Bernoulli remainder (the 5d EM machinery!) — EM to order 2 with the explicit remainder: ψ(w) − log w + 1/(2w) = −∫... the B̃₂ integral: from the level-2 EM in LiRBound (b2Fun machinery EXISTS!) — ψ(w) − log w + 1/(2w) = ∫_0^∞ B̃₂(x)/(x+w)³·... hmm — the EM representation for ψ: ψ(w) = log w − 1/(2w) − ∫₀^∞ B̃₂(x)/(x+w)³ dx (roughly) with |B̃₂| ≤ 1/12: |∫| ≤ (1/12)·∫₀^∞ dx/|x+w|³ ≤ (1/12)·(π/(2|im w|²))-ish... at |im| ≥ 5: ≤ (1/12)·(π/50)·... ≈ 0.005 — and the budget for |r| is 1.2/|w|² ≈ 0.048 — fits with 10× room. So Lemma D via the level-2 EM (LiRBound machinery exists!) is feasible: ~0.5 session.) So the FULL 5f build is more like 2–3 sessions with two new perimeter declarations. AND the D-056 piece-2 finding + the ii′-6 H(T) finding must be documented (D-069 + journal; the H(T) repair goes on the ii′-6 map). This is a significant scope expansion vs the "~1 session" estimate in STATE.md. Per the pacing directive and the fork rule, I should present this to the user now: the findings + the perimeter growth + the revised estimate. Let me write it up concisely and ask. Actually — the user already approved the mult-weighted strengthening (P0) with full context. P1 and P2 are the same class of decision. Let me present the complete 5f design with the two new declarations and the two findings, and ask for approval to proceed (or whether they'd prefer a different tradeoff).
The 5f design is complete, and it surfaced two real findings that need your call before I build. Summary: ## Finding 1 (5f-blocking): D-056's piece 2 uses one C₀(t) for a two-unit window The near sum Σ_{|γ−t|<1} m/|s₀−ρ| runs over the **two-unit** window (t−1, t+1), but D-056's assembly charges it one C₀(t) (the one-unit Trudgian form). Honest accounting: - The per-unit perimeter (even after today's mult-weighted fix) gives 2·Ĉ₀(t+1) — that fold is ≈ 11.2·log + 51, which **breaks the baked 10.5/48** constants. - But Trudgian's F/S-pair applied directly to the **two-unit** window N(t+1)−N(t−1) gives 0.6·L + 0.886·LL + 2.7 (the S-pair doesn't double), and then the full honest assembly is **6.111·L + 12.163·LL + 47.6 ≤ 10.5·L + 48 — it FITS**, worst point the loglog pinch at t ≈ 13 (margin ≈ 0.15–0.4, certifiable). So 10.5/48 survives, but only with the two-unit count form, which the current perimeter can't derive (2·Ĉ₀ is too lossy). ## Finding 2 (documented, ii′-6's to face): H(T)'s near sum has the same gap plus a clearance-coverage gap D-036's H(T) = 3·Ĉ₀² + … uses (i) the one-unit count for |γ−T|<1 and (ii) L3's clearance, which only covers zeros *inside* the pigeonhole window — out-of-window zeros can sit arbitrarily close to T. Honest version is ≈ 7·Ĉ₀² + O(Ĉ₀). This moves marginTilde's baked 3·Ĉ₀² — the crossover/base points will need re-verification at ii′-6 (margin survives per my estimates, but N₀ may move within the 5×10⁵ cap). Not 5f's scope; documented for the repair map. ## 5f needs two new perimeter declarations (same source classes as existing) - **(P1) `ZeroCountProp2`**: mult-weighted two-unit count Σ_{|γ−t|≤1} m ≤ 0.6·log(t+2) + 0.886·loglog(t+2) + 2.7 (t ≥ 10) — Trudgian N(T)/S(T) specialization (honesty-checked: honest form 0.592·L + 0.886·LL + 2.591, so the closed form has 0.008·L + 0.11 slack). - **(P2) `NoLowZeros`**: no nontrivial zeros with |im| ≤ 14 — Platt-class zero-location certificate (Turing-method computations locate the zeros; the far sum's low intervals are otherwise only symbolically bounded — Jensen gives ≈ 3.25 vs the true 0, which breaks the constants at the t = 10 pinch). With those, 5f = the reference-point difference identity (B cancels, from `partialFraction_identity`) + 6 pieces: dirichletC2 ≤ 0.995 (first terms + integral bound), piece 2 via P1, the far-sum interval machine (biggest piece, ~LiCircleBound-shell flavor), the elementary 4/5, and the sharp digamma remainder via the existing level-2 EM machinery (Lemma D, |r| ≤ 1.2/|w|²). Revised estimate: ~2–3 sessions, not 1.
tool: AskUserQuestion ok
input
{
  "questions": [
    {
      "question": "5f requires two new perimeter declarations (P1 two-unit Trudgian count, P2 low-zero exclusion) to keep the baked 10.5/48 constants. Proceed?",
      "header": "5f plan",
      "options": [
        {
          "label": "Approve P1+P2, build 5f (Recommended)",
          "description": "Declare both (same source classes as the existing perimeter: Trudgian N(T)/S(T) specialization + Platt-class zero-location certificate). Keeps all baked constants and certified artifacts valid; 5f ~2\u20133 sessions. Findings 1+2 documented (D-069 + repair map)."
        },
        {
          "label": "Only P1, avoid P2",
          "description": "Try to discharge the low-zero intervals via a Jensen numeric count (~3.25 for |\u03b3| \u2264 3, knife-edge vs the 0.44 budget, heavy EM-on-a-circle verification) instead of declaring the zero-location input."
        },
        {
          "label": "Re-fold constants instead",
          "description": "No new declarations; accept honest A \u2248 11.2, B\u2080 \u2248 51 from the per-unit perimeter and re-bake marginTilde/Hhat + re-verify convexity + re-certify base points (and face the H(T) repair now too, since it also moves constants)."
        },
        {
          "label": "Pause 5f, discuss",
          "description": "Hold here; review the findings (D-056 piece 2, H(T) clearance) before deciding."
        }
      ]
    }
  ]
}
result 2026-08-24 08:06:11Z → 2026-08-24 08:06:11Z
{
  "questions": [
    "question='5f requires two new perimeter declarations (P1 two-unit Trudgian count, P2 low-zero exclusion) to keep the baked 10.5/48 constants. Proceed?' header='5f plan' options=[QuestionOption(label='Approve P1+P2, build 5f (Recommended)', description='Declare both (same source classes as the existing perimeter: Trudgian N(T)/S(T) specialization + Platt-class zero-location certificate). Keeps all baked constants and certified artifacts valid; 5f ~2\u20133 sessions. Findings 1+2 documented (D-069 + repair map).', preview=None), QuestionOption(label='Only P1, avoid P2', description='Try to discharge the low-zero intervals via a Jensen numeric count (~3.25 for |\u03b3| \u2264 3, knife-edge vs the 0.44 budget, heavy EM-on-a-circle verification) instead of declaring the zero-location input.', preview=None), QuestionOption(label='Re-fold constants instead', description='No new declarations; accept honest A \u2248 11.2, B\u2080 \u2248 51 from the per-unit perimeter and re-bake marginTilde/Hhat + re-verify convexity + re-certify base points (and face the H(T) repair now too, since it also moves constants).', preview=None), QuestionOption(label='Pause 5f, discuss', description='Hold here; review the findings (D-056 piece 2, H(T) clearance) before deciding.', preview=None)] multi_select=False"
  ],
  "answers": {
    "5f requires two new perimeter declarations (P1 two-unit Trudgian count, P2 low-zero exclusion) to keep the baked 10.5/48 constants. Proceed?": "Approve P1+P2, build 5f (Recommended)"
  }
}
#1718 assistant 2026-08-24 08:07:55.814 UTC · 10492→2903 tok open ⤢
thinking (8127 chars)
User approved P1+P2. Plan for the build. First, write the design doc D-069 (documenting Finding 1, Finding 2, the two declarations, and the assembly). Then build. Actually — order of work. The full 5f is 2–3 sessions. Let me structure it into sub-stages (per §8.5): **5f-0 (this session, next)**: D-069 design doc + the two perimeter declarations (ZeroCountProp2, NoLowZeros) with errata documented + rebuild + commit. This is a clean sub-stage boundary. **5f-i**: The reference-point difference identity (the algebraic core): from partialFraction_identity at s and s₀ = 2+it: logDeriv ζ s − Σ_near m/(s−ρ) = logDeriv ζ s₀ − Σ_near m/(s₀−ρ) + Σ_far m(s₀−s)/((s−ρ)(s₀−ρ)) − (1/s − 1/s₀) − (1/(s−1) − 1/(s₀−1)) − ½(ψ(s/2) − ψ(s₀/2)). Needs: seriesFun s − seriesFun s₀ = Σ_all m(1/(s−ρ) − 1/(s₀−ρ)) (tsum_sub of the two seriesFun values — both summable ✓ via seriesSummable; termwise difference: (1/(s−ρ)+1/ρ) − (1/(s₀−ρ)+1/ρ) = 1/(s−ρ) − 1/(s₀−ρ) ✓); then the split near/far: Σ_all = Σ_near + Σ_far via tsum_split_finset (LiCircleBound has it — for the subtype-to-finset split: nearZeros t is a Finset ℂ not the subtype — hmm, nearZeros t : Finset ℂ (from LiDisc) while seriesFun is over the subtype {ρ // IsNontrivialZero ρ}. The near/far split needs the subtype version: nearZerosSub t : Finset {ρ // IsNontrivialZero ρ} := filter (|γ−t| < 1). tsum_split_finset exists (from 5e-v-b chunk 1: "tsum_split_finset (tsum = finset sum + if-zeroed tail via tsum_eq_sum)" — over the subtype presumably). The nearZeros t (Finset ℂ from LiDisc) vs the subtype finset — the R-bound's near sum in LiDisc's capstone is over nearZeros t : Finset ℂ. So the statement uses nearZeros t. Need the bridge: Σ over nearZeros t (Finset ℂ, with the mult) = Σ over the subtype filtered — a Finset.sum_subtype-ish bridge. Manageable. Wait — actually, what exactly should the final statement be? Match LiDisc's capstone shape: ```lean theorem logDeriv_riemannZeta_sub_nearZeros_le_tight (hZC : ZeroCountProp) (hZC2 : ZeroCountProp2) (hNLZ : NoLowZeros) {t : ℝ} (ht : 10 ≤ |t|) {s : ℂ} (hσ : -5/2 ≤ s.re ∧ s.re ≤ 3) (him : s.im = t) (hζ : riemannZeta s ≠ 0) (h0 : s ≠ 0) (h1 : s ≠ 1) (htriv : ∀ n : ℕ, 1 ≤ n → s ≠ -2 * (n : ℂ)) : ‖logDeriv riemannZeta s - ∑ ρ ∈ nearZeros t, (zeroMult ρ : ℂ) / (s - ρ)‖ ≤ 10.5 * Real.log (|t| + 2) + 48 ``` Hmm — the hypotheses for partialFraction_identity: ζ s ≠ 0, s ≠ 0, s ≠ 1, s ≠ −2n. For s with im = t, |t| ≥ 10: s ≠ 0, s ≠ 1 automatic (im ≠ 0); s ≠ −2n automatic (those are real, im = 0 ≠ t). So the hypotheses reduce nicely. Also s₀ = 2+it: ζ s₀ ≠ 0 (re ≥ 1... riemannZeta_ne_zero_of_one_le_re — wait that takes ONLY re: 1 ≤ re: re s₀ = 2 ✓). s₀ ≠ 0, 1, −2n ✓ (im = t ≠ 0). For t ≥ 10 vs t ≤ −10: the identity and pieces — D-056 stated for |t| ≥ 10 with σ ∈ [−5/2, 3]. The pieces: piece 1 (s₀ = 2+it, Dirichlet re = 2 ✓ any t); piece 2 (near window at height t — for t ≤ −10 use... the perimeter counts windows at height ≥ 2 — for t ≤ −10, the window (t−1, t+1] is at NEGATIVE heights — count via conjugation: zeros with im ∈ (t−1, t+1] ↔ conj zeros with im ∈ [−t−1, −t+1)-ish — the conj map + ZeroCountProp2 at −t. So ZeroCountProp2 should be stated for t ≥ 10 and the t ≤ −10 case uses conj. OR state ZeroCountProp2 for |t| ≥ 10 with the window symmetrically... Trudgian's N(T) is for positive T; the negative side follows by conjugation. For the Lean def, cleanest: `ZeroCountProp2 : ∀ t : ℝ, 10 ≤ t → (mult sum over |γ−t| ≤ 1) ≤ 0.6 log(t+2) + 0.886 loglog(t+2) + 2.7` and handle t ≤ −10 via isNontrivialZero_conj inside the proof. Hmm — actually for the first cut, maybe state the tight R-bound for t ≥ 10 only (the ii′-6 contour uses T = √n+1 ≥ 10 positive for the top horizontal and −T for the bottom — the bottom needs the t ≤ −10 version). The t ≤ −10 case: logDeriv ζ (conj s) = conj (logDeriv ζ s)? Via riemannZeta_conj and the deriv-under-conj — there's likely a clean bridge; nearZeros t vs nearZeros (−t) via conj image. This is mechanical but adds a chunk. Decision: prove for t ≥ 10 in 5f; the t ≤ −10 corollary as a final wrapper (conj machinery — isNontrivialZero_conj exists; the logDeriv conj identity might need building: logDeriv ζ (conj s) = conj (logDeriv ζ s): deriv of ζ∘conj... conj is not ℂ-differentiable! So logDeriv ζ at conj s ≠ conj of logDeriv directly via chain rule (conj isn't holomorphic). Instead: riemannZeta (conj s) = conj (riemannZeta s) gives, differentiating in s... ζ̄(s) := conj(ζ(conj s)) is holomorphic and = ζ(s)... hmm: define g(s) = conj(ζ(conj s)) — g is entire-ish and g = ζ (by riemannZeta_conj: conj(ζ(conj s)) = ζ(s)? riemannZeta_conj : riemannZeta (conj s) = conj (riemannZeta s) — so conj(ζ(conj s)) = conj(conj(ζ s)) = ζ s ✓ so g = ζ where g(s) = conj(ζ(conj s)). The deriv: g'(s) = conj(ζ'(conj s)) (the conj-of-deriv rule — there's a lemma: deriv (fun s => conj (f (conj s))) s = conj (deriv f (conj s)) — via the ℂ-differentiability of conj∘f∘conj... In Mathlib: `Complex.deriv_conj`? There should be something. If the capstone needs the t < 0 case, build that bridge. For now: design for t ≥ 10, flag the t ≤ −10 wrapper as a follow-up chunk (it's needed for the bottom horizontal of the ii′-6 contour — OR ii′-6 can conjugate the whole bottom-horizontal integral estimate, TBD there). Let me not over-plan. Sub-stage breakdown for 5f: - 5f-0: D-069 + perimeter declarations P1/P2 + rebuild + commit (this session). - 5f-i: the difference identity + the near/far split scaffolding + pieces 1, 2, 4, 5 (elementary ones). - 5f-ii: piece 6 (sharp digamma remainder via level-2 EM) + piece 3 (the far-sum interval machine) — the two big ones. - 5f-iii: the assembly (the pinch calculus lemma) + the capstone + audit. Let me start 5f-0: write D-069, add the two perimeter declarations. Where should they live? P1 (ZeroCountProp2) and P2 (NoLowZeros) — LiContour.lean next to ZeroCountProp (it's the perimeter file). For ZeroCountProp2's exact form: ```lean /-- [PERIMETER — Trudgian 2014 N(T)/S(T), two-unit specialization, D-069] The two-unit window count: the multiplicity-weighted count of nontrivial zeros with |γ − t| ≤ 1 is at most 0.6·log(t+2) + 0.886·log log(t+2) + 2.7 (t ≥ 10). ... -/ def ZeroCountProp2 : Prop := ∀ t : ℝ, 10 ≤ t → (((zeroAbsWindow_finite t).toFinset.sum fun ρ => zeroMult ρ) : ℝ) ≤ 0.6 * Real.log (t + 2) + 0.886 * Real.log (Real.log (t + 2)) + 2.7 ``` with `zeroAbsWindow t := {ρ | IsNontrivialZero ρ ∧ |ρ.im − t| ≤ 1}` and its finiteness (from zerosIn_finite like zeroWindow_finite). For NoLowZeros: ```lean /-- [PERIMETER — Platt-class zero-location certificate, D-069] There are no nontrivial zeros with |γ| ≤ 14 (the first nontrivial zero is at γ = 14.134725...; Platt–Trudgian-class Turing-method certificate). -/ def NoLowZeros : Prop := ∀ ρ : ℂ, IsNontrivialZero ρ → 14 ≤ |ρ.im| ``` Hmm — 14 ≤ |ρ.im|: the first zero is at 14.1347, so 14 is safe. Now — the ZeroCountProp2 window |γ−t| ≤ 1: as a set {ρ | IsNontrivialZero ρ ∧ |ρ.im − t| ≤ 1}. Finiteness: subset of zerosIn_finite (−...)... zerosIn_finite a b gives zeros with im in [a, b]? From zeroWindow_finite's proof: zerosIn_finite (a−1) (a+1) with the membership ⟨hρ.1, ?_, hρ.2.2⟩ — let me look at zerosIn_finite's signature to mirror. From zeroWindow_finite: `Set.Finite.subset (zerosIn_finite (a - 1) (a + 1))` and membership gives ⟨hρ.1, _, hρ.2.2⟩ with linarith on hρ.2.1 — so zerosIn_finite a b : {ρ | IsNontrivialZero ρ ∧ a ≤ ρ.im ∧ ρ.im ≤ b}.Finite presumably (two-sided window). For zeroAbsWindow t: |ρ.im − t| ≤ 1 ⟺ t−1 ≤ ρ.im ≤ t+1: subset of zerosIn_finite (t−1) (t+1) ✓. Let me write D-069 first (the design doc), then the Lean declarations, then rebuild + commit this sub-stage, then continue to 5f-i if time permits. Actually — the session has already done a lot (perimeter repair + design). Per §8.5 pacing, let me do 5f-0 (declarations + D-069) as this session's second commit, then continue with 5f-i (the difference identity) if it goes smoothly. Given the amount of context used, let me be efficient: declarations + D-069 now, then start 5f-i. Let me check zerosIn_finite's exact signature first.
Approved. Executing 5f-0: the two perimeter declarations + the D-069 design doc. Checking `zerosIn_finite`'s signature for the window finiteness proof.
tool: Bash
input
{
  "command": "grep -rn \"theorem zerosIn_finite\\|lemma zerosIn_finite\\|def zerosIn\" D:/Python/Quantum/zeta-23-lean/Zeta23/ | head -3; grep -rn \"zerosIn_finite\" D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1/LiContour.lean | head -2",
  "description": "Find zerosIn_finite signature"
}
#1719 assistant 2026-08-24 08:13:16.274 UTC · 396→3081 tok open ⤢
thinking (388 chars)
LiContour builds with the two new perimeter declarations. Now write D-069 (the 5f design doc), then commit this sub-stage (5f-0: design + perimeter declarations), then continue with 5f-i. Let me write D-069 concisely but completely: Finding 1 (piece-2 gap), Finding 2 (H(T) — ii′-6 repair map), the two declarations, the honest assembly arithmetic, the piece plan, and the sub-stage map.
LiContour green with both declarations. Writing the D-069 design doc.
tool: Write
input
{
  "file_path": "D:\\Python\\Quantum\\research\\derivations\\D-069-ii-prime-5f-design.md",
  "content": "# D-069 \u2014 ii\u2032-5f design: the tight R-bound in Lean (D-056's Theorem R)\nDate: 2026-08-23 | Session: 035 | Task: 5.1 tier ii\u2032-5f\nStatus: DESIGN COMPLETE; two perimeter additions (P1, P2) APPROVED by the\nuser 2026-08-23 and declared (LiContour.lean, session-035 commit).\n\n## 0. Target\n\nD-056's Theorem R, in the LiDisc-capstone shape:\n  \u2016logDeriv \u03b6 s \u2212 \u03a3_{\u03c1 \u2208 nearZeros t} m_\u03c1/(s\u2212\u03c1)\u2016 \u2264 10.5\u00b7log(|t|+2) + 48\nfor s = \u03c3 + it, \u03c3 \u2208 [\u22125/2, 3], |t| \u2265 10, s off the excluded set \u2014 from\n`partialFraction_identity` (5e-v-d) at s vs the reference point\ns\u2080 = 2 + it (B cancels; no evaluation of B needed).\n\n## 1. Finding 1 (session 035): D-056's piece 2 undercounts the near window\n\nD-056's assembly charges the near sum \u03a3_{|\u03b3\u2212t|<1} 1/|s\u2080\u2212\u03c1| ONE unit-window\ncount C\u2080(t), but |\u03b3\u2212t| < 1 spans TWO unit windows. Two honest routes:\n- **per-unit perimeter (even mult-weighted)**: \u03a3 \u2264 \u0108\u2080(t) + \u0108\u2080(t+1) \u2264\n  2\u00b7\u0108\u2080(t+1) = 0.866\u00b7L + 1.772\u00b7LL + 5.8 \u2014 the fold becomes \u2248 11.2\u00b7L + 51,\n  BREAKING the baked 10.5/48 constants (they were derived from the\n  one-C\u2080 piece 2).\n- **Trudgian F/S-pair applied to the two-unit window directly** (N(t+1)\n  \u2212 N(t\u22121)): the S_b-pair does NOT double vs the one-unit form, giving\n  \u2264 0.59231\u00b7L + 0.886\u00b7LL + 2.591. With this the full honest assembly is\n  6.111\u00b7L + 12.163\u00b7LL + 47.6 \u2264 10.5\u00b7L + 48 \u2014 **FITS**, worst point the\n  loglog pinch at t \u2248 13.1 (L = e, margin \u2248 0.15\u20130.4; see \u00a73).\n\nConclusion: the 10.5/48 constants survive, but ONLY via the two-unit\nform, which is NOT derivable from the per-unit perimeter \u27f9 new declared\nspecialization **(P1) `ZeroCountProp2`** (approved; LiContour.lean).\n\nThis is a D-054-class assembly slip (paper-side; the BOUND is true \u2014\nE-028 measured 26\u00d7 slack; the traced constants needed the sharper\ncount form). Erratum to D-056 \u00a72 piece 2 recorded here.\n\n## 2. The two perimeter additions (approved 2026-08-23)\n\n- **(P1) `ZeroCountProp2`**: \u2200 t \u2265 10, the mult-weighted count of zeros\n  with |\u03b3\u2212t| \u2264 1 is \u2264 0.6\u00b7log(t+2) + 0.886\u00b7log log(t+2) + 2.7. Honesty\n  check: the F/S-pair gives \u2264 0.59231\u00b7L + 0.886\u00b7LL + 2.591 (F-diff \u2264\n  (1/\u03c0)(L \u2212 log 2\u03c0); S_b-pair \u2264 0.274\u00b7L + 0.886\u00b7LL + 3.176), so the\n  closed form has 0.008\u00b7L + 0.109 slack. Same source as `ZeroCountProp`\n  (Trudgian 2014 N(T)/S(T), D-062 \u00a74 class).\n- **(P2) `NoLowZeros`**: no nontrivial zeros with |\u03b3| \u2264 14 (first zero\n  14.1347\u2026). This is the zero-LOCATION content of the Platt\u2013Trudgian-class\n  Turing-method certificate \u2014 NOT implied by `RHUpTo` (on-line only) nor\n  by the count bounds (S_b slack \u226b 1 at low height). Piece 3 consumes it:\n  the far sum's intervals below height 14 are otherwise only symbolically\n  bounded (Jensen gives \u2248 3.25 vs the true 0 \u2014 breaks the constants at\n  the t = 10 pinch).\n\nPaper-ii\u2032-7 duty: the appendix's perimeter list gains these two items\n(same trust classes as the existing entries).\n\n## 3. The honest assembly (the fold)\n\nWith L = log(t+2), LL = log L, C\u2080 := \u0108\u2080(t+1) = 0.433\u00b7L\u2032 + 0.886\u00b7LL\u2032 + 2.9\n(L\u2032 = log(t+3) \u2264 L + 1/12):\n1. \u2016\u03b6\u2032/\u03b6(s\u2080)\u2016 \u2264 dirichletC2 \u2264 0.995 (\u039b(n) \u2264 log n \u27f9 \u2264 \u03a3_{n\u22652} log n/n\u00b2\n   \u2264 (log 2)/4 + (log 3)/9 + \u222b\u2083^\u221e log x/x\u00b2 dx = (log 2)/4 + (log 3)/9 +\n   (log 3 + 1)/3 \u2248 0.1733 + 0.1221 + 0.6995 = 0.9949; budget 1.01).\n2. near \u2264 P1-count \u2264 0.6\u00b7L + 0.886\u00b7LL + 2.7 (|s\u2080\u2212\u03c1| \u2265 1 since re \u03c1 \u2264 1).\n3. far \u2264 4.5\u221a2\u00b7[C\u2080 + (C\u2080 + 0.55) + 0.55] = 12.7279\u00b7C\u2080 + 7.00\n   (per-interval |s\u2080\u2212s| \u2264 4.5, |s\u2212\u03c1| \u2265 x, |s\u2080\u2212\u03c1| \u2265 (1+x)/\u221a2 with\n   x = |t\u2212\u03b3|; \u03a3_{k\u22651} 1/(k(k+1)) = 1; C\u2080(2t+1) \u2264 C\u2080 + 0.55; the k > t\n   tail \u2264 0.55 via \u03a3_{k\u226511} log k/k\u00b2 \u2264 (log 10 + 1)/10 \u2264 0.331 and\n   \u03a3 1/(k(k+1)) \u2264 1/11; the height-< 14 intervals empty by P2; the\n   negative-\u03b3 side via conjugation).\n4./5. \u20161/s \u2212 1/s\u2080\u2016, \u20161/(s\u22121) \u2212 1/(s\u2080\u22121)\u2016 \u2264 4.5/|t|\u00b2 \u2264 0.045 each.\n6. \u00bd\u2016\u03c8(s/2) \u2212 \u03c8(s\u2080/2)\u2016 \u2264 0.30 (sharp digamma remainder |r(w)| \u2264\n   1.2/|w|\u00b2 via the level-2 EM (LiRBound b2Fun machinery) \u2014 the Lean\n   Lemma D; |log(w/w\u2080)| \u2264 0.45\u00b7(1+\u03b5) via the arg/modulus split).\nTotal: 6.111\u00b7L + 12.163\u00b7LL + 47.6 \u2264 10.5\u00b7L + 48 \u27fa\n12.163\u00b7LL \u2212 4.389\u00b7L \u2264 0.4, and max over L \u2265 log 12 is at L* = 12.163/4.389\n= 2.772 with value 12.163\u00b7log(2.772) \u2212 4.389\u00b72.772 \u2248 0.234 \u2264 0.4 \u2713\n(the pinch lemma: one-variable calculus + certified endpoint/point\nevaluation, LiBasePoints pattern).\n\n## 4. Finding 2 (session 035; ii\u2032-6 repair map \u2014 NOT 5f scope)\n\nD-036 \u00a72's H(T) = 3\u00b7\u0108\u2080\u00b2 + A\u00b7log + B\u2080 charges the horizontal-contour near\nsum (i) one unit-window count (Finding-1 issue again \u2014 the two-unit form\nfixes this part cheaply) and (ii) L3's clearance 1/(3\u00b7\u0108\u2080), which covers\nonly zeros INSIDE the pigeonhole window: with T \u2208 [a, a+1], zeros just\noutside [a, a+1] can sit at distance < 1/(3\u0108\u2080) from T. Honest repair:\nextend the pigeonhole to the 3-unit window (a\u22121, a+2) (count \u2264 3\u00b7\u0108\u2080,\nclearance \u2265 1/(7\u00b7\u0108\u2080)-ish) and split the near sum at |\u03b3\u2212T| = 1/4:\n\u03a3 \u2264 \u0108\u2080\u00b77\u0108\u2080 + 2\u0108\u2080\u00b74 = 7\u00b7\u0108\u2080\u00b2 + 8\u00b7\u0108\u2080. Impact: marginTilde's baked\n3\u00b7\u0108\u2080\u00b2 coefficient moves to \u2248 7 + o(1); the margin at the certified base\npoints drops by \u2248 2(e\u2074+1)\u00b77\u00b74\u00b7\u0108\u2080\u00b2 (\u2248 1.5\u00d710\u2075 at n = 8\u00d710\u2074) \u2014 the\ncrossover N\u2080 moves up (estimate: within [10\u2075, 5\u00d710\u2075], still under the\nfinite-verification cap); the convexity proof is structural and\nre-verifies. TO BE FACED at ii\u2032-6 (D-037's I_III (2/3)\u00b7\u0108\u2080 coefficient\ngets the analogous two-unit correction to (4/3)-ish). File under the\n4.5-class repair map. E-028's 26\u00d7 slack says the theorem survives; the\ncertified crossover artifacts move.\n\n## 5. Lean build plan (sub-stages)\n\n- **5f-0** (session 035, DONE): this design + P1/P2 declarations\n  (LiContour.lean: `zeroAbsWindow`, `zeroAbsWindow_finite`,\n  `ZeroCountProp2`, `NoLowZeros`) + the mult-weighted `ZeroCountProp`\n  repair (`one_le_zeroMult`; consumer adaptations in\n  exists_zero_avoiding_T, exists_gapCircle_radius).\n- **5f-i**: the reference-point difference identity (from\n  partialFraction_identity; seriesFun difference termwise + the\n  near/far split via tsum_split_finset + the nearZeros subtype bridge) +\n  the elementary pieces 1 (dirichletC2 \u2264 0.995 via \u039b \u2264 log + integral\n  comparison), 2 (P1 count \u00d7 |s\u2080\u2212\u03c1| \u2265 1), 4, 5 (norm algebra).\n- **5f-ii**: piece 6 (the sharp digamma remainder |r| \u2264 1.2/|w|\u00b2 via\n  the level-2 EM; then the log-difference arg/modulus split) and\n  piece 3 (the far-sum interval machine: per-interval C0hat counts from\n  the perimeter + conj for the negative side + P2 for the low intervals\n  + the \u03a3 1/(k(k+1)) = 1 telescoping sum).\n- **5f-iii**: the assembly + the pinch lemma (12.163\u00b7LL \u2264 4.389\u00b7L +\n  const for L \u2265 log 12 via the interior-max calculus) + the capstone\n  `logDeriv_riemannZeta_sub_nearZeros_le_tight` + audit.\n\nCapstone statement (5f-iii; t \u2265 10 first, the t \u2264 \u221210 corollary via\nconjugation if ii\u2032-6's bottom horizontal needs it \u2014 TBD there):\n  theorem logDeriv_riemannZeta_sub_nearZeros_le_tight\n      (hZC : ZeroCountProp) (hZC2 : ZeroCountProp2) (hNLZ : NoLowZeros)\n      {t : \u211d} (ht : 10 \u2264 t) {s : \u2102}\n      (h\u03c3 : -5/2 \u2264 s.re \u2227 s.re \u2264 3) (him : s.im = t)\n      (h\u03b6 : riemannZeta s \u2260 0) :\n      \u2016logDeriv riemannZeta s\n          - \u2211 \u03c1 \u2208 nearZeros t, (zeroMult \u03c1 : \u2102) / (s - \u03c1)\u2016\n        \u2264 10.5 * Real.log (|t| + 2) + 48\n\n## 6. Risks\n- Piece 3 is the longest piece (the interval machine; LiCircleBound-shell\n  flavor \u2014 1\u20131.5 sessions alone).\n- The pinch lemma's margin is \u2248 0.15\u20130.4 \u2014 certifiable but tight; every\n  piece constant must keep its budget (piece 1 \u2264 1.01, piece 6 \u2264 0.30).\n- The digamma EM remainder sign conventions (b2Fun) need care.\n"
}
#1720 assistant 2026-08-24 08:16:14.841 UTC · 735→3286 tok open ⤢
thinking (7392 chars)
5f-0 committed. Now 5f-i: the reference-point difference identity + the elementary pieces. Let me start a new Lean file LiTightR.lean. **5f-i content:** 1. The difference identity. From partialFraction_identity at s and s₀: logDeriv ζ s = B + seriesFun s − 1/s − 1/(s−1) + c − ψ(s/2)/2 (c := (log π)/2) logDeriv ζ s₀ = B + seriesFun s₀ − 1/s₀ − 1/(s₀−1) + c − ψ(s₀/2)/2 Subtract: logDeriv ζ s = logDeriv ζ s₀ + (seriesFun s − seriesFun s₀) − (1/s − 1/s₀) − (1/(s−1) − 1/(s₀−1)) − (ψ(s/2) − ψ(s₀/2))/2. 2. seriesFun s − seriesFun s₀ = Σ_ρ m·(1/(s−ρ) − 1/(s₀−ρ)): via tsum_sub (both summable: seriesSummable) + termwise algebra: seriesTerm s ρ − seriesTerm s₀ ρ = m·(1/(s−ρ) + 1/ρ) − m·(1/(s₀−ρ) + 1/ρ) = m·(1/(s−ρ) − 1/(s₀−ρ)). So: seriesFun s − seriesFun s₀ = ∑' ρ, m·(1/(s−ρ) − 1/(s₀−ρ)) := diffSeries s s₀. 3. Split the diff series into near (nearZeros t) and far: ∑' = Σ_near + Σ_far via the tsum_split_finset machinery. nearZeros t is a Finset ℂ in LiDisc — let me check its exact def (line 970): `def nearZeros (t : ℝ) : Finset ℂ := (zeroDiscFinset t).filter (|ρ.im − t| < 1)`-ish. The series is over the subtype {ρ // IsNontrivialZero ρ}. The split needs the subtype version: {ρ : subtype | ρ ∈ nearZeros t} as a Finset via Finset.subtype or filter. LiCircleBound's tsum_split_finset — let me check its exact form (5e-v-b chunk 1: "tsum_split_finset (tsum = finset sum + if-zeroed tail via tsum_eq_sum)"). 4. Then R(s) := logDeriv ζ s − Σ_near m/(s−ρ): R(s) = logDeriv ζ s₀ − Σ_near m/(s₀−ρ) + Σ_far m·(1/(s−ρ) − 1/(s₀−ρ)) − (1/s − 1/s₀) − (1/(s−1) − 1/(s₀−1)) − (ψ(s/2) − ψ(s₀/2))/2. With 1/(s−ρ) − 1/(s₀−ρ) = (s₀−s)/((s−ρ)(s₀−ρ)) termwise. 5. Piece bounds: - P1: ‖logDeriv ζ s₀‖ ≤ dirichletC2 (re s₀ = 2 ✓) ≤ 0.995 — the numeric bound on dirichletC2 (tsum of LSeries term norms). Hmm — dirichletC2 := ∑' n, ‖LSeries.term Λ 2 n‖. LSeries.term f a n = f n / n^a (for n ≥ 1; 0 for n = 0?). ‖term‖ = Λ(n)/n² (for n ≥ 1; n=0: term = 0). Bound: Λ(n) ≤ log n (Mathlib: ArithmeticFunction.vonMangoldt_le_log : Λ(n) ≤ log n ✓ exists I believe). So dirichletC2 ≤ ∑'_{n≥2} log n / n². The tsum ≤ 0.995 via: first terms exact (n=2: log 2/4, n=3: log 3/9) + tail Σ_{n≥4} log n/n² ≤ ∫₃^∞ log x/x² dx = (log 3 + 1)/3. The integral comparison for a decreasing function: need the lemma. Mathlib: `Real...`? Hmm — for the tail: Σ_{n≥4} log n/n² where f(x) = log x/x² decreasing for x ≥ e^{1/2} ≈ 1.65 ✓. The comparison Σ_{n≥N+1} f(n) ≤ ∫_N^∞ f: I recall Mathlib has something in `Mathlib.Analysis.SumOverResidueClass`... or `integral_test`? There's `MeasureTheory...`? Let me search for "tsum_le_integral" or build it: for each n ≥ 3: f(n+1) ≤ ∫_n^{n+1} f (f decreasing ⟹ f(n+1) ≤ f(x) on [n, n+1]) — `IntervalIntegral...` / `intervalIntegral.integral_mono_on`. Then tsum of f(n+1) ≤ tsum of ∫_n^{n+1} f = ∫₃^∞ f (the tsum of consecutive integrals = the big integral: `intervalIntegral...` hmm — needs the "sum of integrals = integral over union" for a sequence of consecutive intervals: `MeasureTheory.integral_iUnion...`? There's a simpler path: Mathlib has the integral test: `Real.summable_...`? hmm. Alternatively bound the tail by a computable series: for n ≥ 4, log n ≤ n^{1/2}·(something)... log n/n² ≤ n^{−3/2} for n ≥ ... (log n ≤ √n ⟺ n ≥ ~... log n ≤ √n for all n ≥ 1? log n ≤ n/2 ≤ ... hmm log n ≤ n^{1/2} fails for small n? log 1 = 0 ≤ 1 ✓, log 2 = 0.69 ≤ 1.41 ✓ — log x ≤ √x for x ≥ 0? At x = 1: 0 ≤ 1 ✓; derivative comparison... max of log x/√x at x = e²: 2/e ≈ 0.736 < 1 ✓ so log n ≤ 0.74·√n ⟹ log n/n² ≤ 0.74/n^{3/2}; Σ_{n≥4} n^{−3/2} ≤ ∫₃^∞ x^{−3/2} = 2/√3 ≈ 1.155 — too big (budget for the tail: 0.995 − 0.1733 − 0.1221 = 0.6996). 0.74·1.155 = 0.855 > 0.6996. Not enough. So need the actual integral ∫₃^∞ log x/x² = (log 3+1)/3 = 0.6995 — knife-edge vs budget 0.6996!! OUCH — 0.9949 vs budget 1.01 — fine actually: total piece-1 bound = 0.1733 + 0.1221 + 0.6995 = 0.9949 ≤ 1.01 budget ✓ (I confused myself — the tail budget is 0.6996 and the integral is 0.6995 ✓ fits, but TOO tight — need the integral bound done RIGHT with a hair of room). Hmm — actually the exact tail Σ_{n≥4} log n/n²: true value ≈ 0.9375 − 0.1733 − 0.1221 = 0.6421 (since Σ_{n≥2} log n/n² = −ζ′(2) ≈ 0.93755). The integral bound gives 0.6995 (lossy by 0.057). Total: 0.9949 vs budget 1.01 ✓ 0.015 room. OK — tight but fine. Alternatively include n=4,5 exactly: log4/16 = 0.0866, log5/25 = 0.0644; tail from 6: ∫₅^∞ = (log 5+1)/5 = 0.5219: total 0.1733+0.1221+0.0866+0.0644+0.5219 = 0.9683 — more room (0.04). Take more exact terms if needed. The integral comparison lemma is the work item. Let me search Mathlib for it at build time: candidates: `MeasureTheory.integral_...`? In practice: `summable_nat_add_iff`, and the termwise ∫_{n}^{n+1} f ≥ f(n+1): then Σ_{n=3}^{N} f(n+1) ≤ ∫₃^{N+1} f; take N → ∞: tsum ≤ lim of integrals = ∫₃^∞ (improper). The improper integral value (log 3+1)/3 via FTC on the antiderivative −(log x + 1)/x. Both halves need some API work; ~100 lines. OK. Hmm wait — actually, maybe simpler: bound dirichletC2 against a KNOWN Mathlib value: is there `Real... -ζ'(2)`? No. Or use Λ(n) ≤ log 2·(number-of-prime-power...) no. The integral route it is. - P2: near sum at s₀: ‖Σ_near m/(s₀−ρ)‖ ≤ Σ_near m·‖1/(s₀−ρ)‖ ≤ Σ_near m·1 (|s₀−ρ| ≥ 1: ‖s₀−ρ‖ ≥ |re(s₀−ρ)| = 2 − re ρ ≥ 1 since re ρ < 1... wait re ρ < 1 gives 2 − re ρ > 1 — strictly. ≥ 1 suffices for ‖1/(s₀−ρ)‖ ≤ 1: norm one-div: ‖1/w‖ = 1/‖w‖ ≤ 1/1 = 1 ✓). Then Σ_near m ≤ P1-count ≤ 0.6L + 0.886LL + 2.7 — the near sum Σ over nearZeros t... but P1's window is |γ−t| ≤ 1 while nearZeros t is |γ−t| < 1 — ⊂ ✓ so the nearZeros mult sum ≤ the abs-window mult sum ≤ P1 bound. Need the finset inclusion bridge: nearZeros t ⊆ zeroAbsWindow_finset t (as finsets of ℂ: nearZeros t's elements are nontrivial zeros with |im − t| < 1 ⊂ |·| ≤ 1 ✓). Then sum_mono (nonneg terms). Wait — is nearZeros t EXACTLY the nontrivial zeros with |im − t| < 1? From LiDisc: nearZeros t := (zeroDiscFinset t).filter (|ρ.im − t| < 1) — zeroDiscFinset t is zeros in a DISC around 2+it — the disc might not contain ALL |γ−t|<1 zeros! Let me check zeroDiscFinset's radius: from LiDisc, the disc was B(2+it, 5/2)-ish. A nontrivial zero with |γ−t| < 1 has re ∈ (0,1), so |ρ − (2+it)|² = (2−re)² + (γ−t)² ≤ 4 + 1 < (5/2)² = 6.25 ✓ — yes 4+1 = 5 < 6.25 so all near zeros are in the disc ✓. But is zeroDiscFinset t exactly the nontrivial zeros in that disc? From LiDisc: zeroDiscFinset + zeroDisc_isNontrivial (re ≥ 1 via one_le_re nonvanishing; re ≤ 0 via ΓR-pole/FE) — the disc zeros are all nontrivial ✓. So nearZeros t = {nontrivial zeros with |γ−t| < 1} exactly (as a finset of ℂ). Good — the P1 bridge is direct. - P4/P5: ‖1/s − 1/s₀‖ = ‖(s₀−s)/(s·s₀)‖ = |s₀−s|/(‖s‖‖s₀‖) ≤ 4.5/(|t|·|t|) ≤ 0.045 (|s₀−s| = |2−σ| ≤ 4.5 since σ ∈ [−5/2, 3]: |2−σ| ≤ max(|2−(−5/2)|, |2−3|) = 4.5 ✓; ‖s‖ ≥ |im s| = |t| ≥ 10; ‖s₀‖ ≥ |t|). Similarly 1/(s−1) − 1/(s₀−1): |s₀−s|/(‖s−1‖‖s₀−1‖) ≤ 4.5/(|t|−0)²... ‖s−1‖ ≥ |im(s−1)| = |t| ✓, ‖s₀−1‖ = |1+it| ≥ |t| ✓. ≤ 0.045 ✓. 6. The identity assembly (the norm chain): ‖R(s)‖ ≤ P1 + P2 + P3 + P4 + P5 + P6. 7. P6 (5f-ii): the ψ-difference. 8. P3 (5f-ii): the far-sum machine. 9. The pinch lemma (5f-iii): the final real-variable fold. Let me start LiTightR.lean with the identity + P1/P2/P4/P5 (5f-i). Actually — the tsum_split_finset signature: let me check LiCircleBound's.
5f-0 committed (`f850d9a`). Starting 5f-i — the difference identity + elementary pieces. Checking the split machinery signatures first.
tool: Bash
input
{
  "command": "cd D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1; grep -n \"theorem tsum_split_finset\\|lemma tsum_split_finset\" -A 6 LiCircleBound.lean | head -12; echo ===NEARZ===; sed -n '965,985p' LiDisc.lean; echo ===VML===; grep -rn \"vonMangoldt_le_log\\|vonMangoldt_le\" D:/Python/Quantum/zeta-23-lean/.lake/packages/mathlib/Mathlib/NumberTheory/VonMangoldt.lean 2>/dev/null | head -4",
  "description": "Check tsum_split_finset, nearZeros def, vonMangoldt_le_log"
}
#1721 assistant 2026-08-24 08:19:34.227 UTC · 3995→5370 tok open ⤢
thinking (14976 chars)
- `tsum_split_finset (hf : Summable f) (s : Finset ι) : ∑' i, f i = ∑ i ∈ s, f i + ∑' i, (if i ∈ s then 0 else f i)` — over ℝ-valued f. The series is ℂ-valued (seriesTerm is ℂ). Need the ℂ version — the proof pattern works for any normed group; check if tsum_split_finset is stated for ℝ only. It says {f : ι → ℝ}. For ℂ I'll need a ℂ analog (copy the proof pattern or generalize — easiest: write the ℂ version inline in LiTightR via tsum_eq_sum + the if-zeroed summable). Actually, hmm: maybe simpler to phrase the difference-series split via the SUBTYPE filter: seriesFun is ∑' over {ρ // IsNontrivialZero ρ}. The near set as a subtype finset: nearZerosSub t : Finset {ρ // IsNontrivialZero ρ} := (zeroAbsWindow... hmm. Let me think about what the capstone statement's near sum looks like: `∑ ρ ∈ nearZeros t, (zeroMult ρ : ℂ) / (s - ρ)` (Finset ℂ sum, matching LiDisc's capstone). The series split: seriesFun s − seriesFun s₀ = Σ' all m(1/(s−ρ) − 1/(s₀−ρ)). Split the tsum by the subtype finset {ρ : subtype | (ρ:ℂ) ∈ nearZeros t}: Σ'all = Σ_{subtype near} + Σ'_{not-near}. And Σ_{subtype near} (fun ρ => m·(1/(s−ρ) − 1/(s₀−ρ))) = Σ_{ρ ∈ nearZeros t} m·(1/(s−ρ) − 1/(s₀−ρ)) (the subtype-to-ambient finset sum bridge: Finset.sum_subtype... `Finset.sum_subtype (s : Finset α) {p : α → Prop} (h : ∀ x, x ∈ s ↔ p x) (f : {x // p x} → β) : ∑ x : {x // p x}, f x = ...`? There's `Finset.sum_subtype` hmm or for our direction: the subtype finset is s.subtype p := {x : {x // p x} | (x:α) ∈ s}. `Finset.sum_subtype (s : Finset α) (h : ∀ x, x ∈ s ↔ p x) (f)`: ∑ x in s.subtype p, f x = ∑ x in s, ... hmm the standard: `Finset.sum_subtype (s : Finset α) {p : α → Prop} [DecidablePred p] (h : ∀ x, x ∈ s ↔ p x) (f : {a // p a} → β) : ∑ x : {a // p a}, f x = ∑ x ∈ s, if h' : p x then f ⟨x, h'⟩ else 0`? Something like that. Or use `Finset.sum_finset_coe`... There might be a cleaner route: `Finset.sum_attach`? Hmm. Alternative cleaner: define the near sum directly over the subtype finset nearZerosSub t := (zeroAbsWindowSub t).filter... Let me define: ```lean def nearZerosSub (t : ℝ) : Finset {ρ : ℂ // IsNontrivialZero ρ} := (finite-of-subtype).toFinset.filter (fun ρ => |ρ.1.im − t| < 1) ``` hmm — the subtype's finite-in-balls machinery: LiCircleBound had `finite_subtype_norm_lt` — and the near subtype: {ρ : subtype | |im − t| < 1} is finite (contained in a norm ball: ‖ρ‖ ≤ |im|+1 ≤ |t|+2). So: ```lean def nearZerosSub (t : ℝ) : Finset {ρ : ℂ // IsNontrivialZero ρ} := (finite_subtype_norm_lt (|t| + 3)).toFinset.filter fun ρ => |ρ.1.im − t| < 1 ``` wait — need the filter to catch exactly the near zeros: the toFinset contains all subtype zeros with ‖ρ‖ < |t|+3; a near zero has ‖ρ‖ = √(re²+γ²) ≤ 1+|γ| ≤ 1+|t|+1 = |t|+2 < |t|+3 ✓ so the filter over that ball captures all near zeros ✓ (any near zero not in the ball would be missed — but ‖ρ‖ < |t|+3 covers all near ✓). Hmm — but for the sum bridge I need: Σ over nearZerosSub = Σ over nearZeros (ℂ-finset). And the split: Σ' over subtype = Σ nearZerosSub + Σ' complement. This subtype/ambient bridging is fiddly but routine. Given context budget, let me now write the 5f-i file with: 1. `diffSeries` def + summability + the seriesFun difference identity. 2. The near/far split + the subtype-ambient bridge. 3. The R(s) identity (the six-piece decomposition). 4. Pieces 1, 2, 4, 5. 5. Leave pieces 3, 6 as `sorry`-free separate lemmas with the assembly taking them as hypotheses? NO — no sorries allowed. Better: structure the file so pieces 3 and 6 are their own theorems proved in 5f-ii, and the capstone assembly in 5f-iii. For THIS session, build: the identity + pieces 1, 2, 4, 5 as standalone lemmas + commit. The capstone comes in 5f-iii when all pieces exist. Hmm — wait, actually, let me reconsider the diffSeries summability: seriesSummable gives Summable (seriesTerm s) for each s. Summable (fun ρ => seriesTerm s ρ − seriesTerm s₀ ρ) = Summable.sub seriesSummable seriesSummable ✓. And tsum_sub: ∑' (f − g) = ∑' f − ∑' g ✓. Termwise: seriesTerm s ρ − seriesTerm s₀ ρ = m·(1/(s−ρ) − 1/(s₀−ρ)): ring-ish: m·(1/(s−ρ)+1/ρ) − m·(1/(s₀−ρ)+1/ρ) = m·(1/(s−ρ) − 1/(s₀−ρ)) — by ring (field-free: it's just add/sub of the products — ring works over ℂ with the divisions as atoms? The identity m·(a+b) − m·(c+b) = m·(a−c) is pure ring ✓ with a,b,c atoms ✓). Define diffSeriesTerm s s₀ ρ := (zeroMult ρ : ℂ)·(1/(s−ρ) − 1/(s₀−ρ)) hmm wait — actually simpler to keep everything in the seriesTerm difference form and only introduce the (s₀−s)/((s−ρ)(s₀−ρ)) form in piece 3. The identity lemma: ```lean theorem seriesFun_sub_seriesFun (s s₀ : ℂ) : seriesFun s - seriesFun s₀ = ∑' ρ : {ρ // IsNontrivialZero ρ}, (zeroMult ρ : ℂ) * (1 / (s - ρ.1) - 1 / (s₀ - ρ.1)) := by rw [seriesFun, seriesFun, ← tsum_sub seriesSummable seriesSummable] exact tsum_congr fun ρ => by rw [seriesTerm, seriesTerm]; ring ``` seriesSummable's signature: from LiSeries — `seriesSummable (s : ℂ)? : Summable (seriesTerm s)`? Let me check: "seriesSummable at EVERY s" — theorem seriesSummable (s : ℂ) : Summable (fun ρ => seriesTerm s ρ)? approx. And tsum_sub (hf : Summable f) (hg : Summable g) : ∑' i, (f i − g i) = ∑' f − ∑' g — so ← direction: ∑' f − ∑' g = ∑' (f−g) ✓. And the congr: seriesTerm s ρ − seriesTerm s₀ ρ = m·(1/(s−ρ) − 1/(s₀−ρ)) by ring ✓ (divisions as atoms — ring handles: m*(a+b) − m*(c+b) = m*(a−c) ✓ pure ring identity in variables a = 1/(s−ρ), b = 1/ρ, c = 1/(s₀−ρ) ✓). Then the R-identity: ```lean theorem Rexpr_eq (hZC : ZeroCountProp) {t : ℝ} (ht : 10 ≤ t) {s : ℂ} (him : s.im = t) (hζ : riemannZeta s ≠ 0) ... : logDeriv riemannZeta s - ∑ ρ ∈ nearZeros t, (zeroMult ρ : ℂ) / (s - ρ) = logDeriv riemannZeta (2 + t * I) - nearSum₀ + farSum - (1/s − 1/s₀) − ... ``` hmm — wait. Actually do I even need the IDENTITY as a separate lemma? The capstone: ‖R(s)‖ ≤ ... — the proof: rw the identity then norm-chain. Let me structure: ```lean /-- The reference-point decomposition of the R-expression. -/ theorem Rexpr_decomp (hZC : ZeroCountProp) {s s₀ : ℂ} (hs : riemannZeta s ≠ 0) (hs0 : s ≠ 0) (hs1 : s ≠ 1) (hst : ∀ n : ℕ, 1 ≤ n → s ≠ -2 * (n : ℂ)) (hs₀ : riemannZeta s₀ ≠ 0) (hs₀0 : s₀ ≠ 0) (hs₀1 : s₀ ≠ 1) (hs₀t : ∀ n : ℕ, 1 ≤ n → s₀ ≠ -2 * (n : ℂ)) (t : ℝ) : logDeriv riemannZeta s - ∑ ρ ∈ nearZeros t, (zeroMult ρ : ℂ) / (s - ρ) = logDeriv riemannZeta s₀ - ∑ ρ ∈ nearZeros t, (zeroMult ρ : ℂ) / (s₀ - ρ) + (∑' ρ : {ρ // IsNontrivialZero ρ}, if (ρ : ℂ) ∈ nearZeros t then 0 else (zeroMult ρ : ℂ) * (1 / (s - ρ.1) - 1 / (s₀ - ρ.1))) - (1 / s - 1 / s₀) - (1 / (s - 1) - 1 / (s₀ - 1)) - (Complex.digamma (s / 2) - Complex.digamma (s₀ / 2)) / 2 := ... ``` Wait — the split needs the tsum over the subtype split by membership in nearZeros t (a Finset ℂ, membership of ρ.1). tsum_split_finset is over ℝ — need the ℂ version. Let me just prove a local ℂ tsum_split via tsum_eq_sum: ```lean lemma tsum_split_finset_complex {ι : Type*} [DecidableEq ι] {f : ι → ℂ} (hf : Summable f) (s : Finset ι) : ∑' i, f i = ∑ i ∈ s, f i + ∑' i, if i ∈ s then 0 else f i := ... ``` Copy LiCircleBound's proof (it's ~15 lines: Summable.of_norm_bounded for the if-parts + tsum_add + tsum_eq_sum). OR — check if LiCircleBound's tsum_split_finset generalizes: it's stated for ℝ. The proof: Summable (if i ∈ s then f i else 0) via of_norm_bounded hf.norm... For ℂ same proof works with the right generality — I'll write the ℂ variant in LiTightR (or better: check whether the existing one is used... it might already exist generically somewhere. Whatever — 15 lines.) Hmm, wait — actually maybe I can avoid the ℂ split: the identity R(s) = ... doesn't need the tsum SPLIT at the identity level — I can bound ‖R(s)‖ by first writing: R(s) = [logDeriv ζ s₀] + [−Σ_near m/(s₀−ρ)] + [Σ'_all m(1/(s−ρ)−1/(s₀−ρ)) − Σ_near m(1/(s−ρ) − 1/(s₀−ρ))...] — no, the far sum IS the difference. The identity: Σ'_all diff = Σ_near diff + Σ'_far diff (split) R(s) = logDeriv ζ s − Σ_near m/(s−ρ) = [logDeriv ζ s₀ + (seriesFun s − seriesFun s₀) − (1/s−1/s₀) − ... ] − Σ_near m/(s−ρ) = logDeriv ζ s₀ + Σ'_all diff − Σ_near m/(s−ρ) − elems = logDeriv ζ s₀ + Σ_near diff + Σ'_far diff − Σ_near m/(s−ρ) − elems = logDeriv ζ s₀ + Σ_near m·(1/(s−ρ) − 1/(s₀−ρ)) − Σ_near m/(s−ρ) + Σ'_far diff − elems = logDeriv ζ s₀ − Σ_near m/(s₀−ρ) + Σ'_far diff − elems ✓. So the identity needs: (i) the two partialFraction_identity instances, (ii) seriesFun difference = Σ'_all diff, (iii) the tsum split (ℂ), (iv) the subtype↔ambient bridge for the near sums: Σ over the subtype finset {ρ : subtype | ρ.1 ∈ nearZeros t} of f = Σ over nearZeros t of f∘coe. For (iv): Finset.sum_subtype? The lemma: `Finset.sum_subtype (s : Finset α) (h : ∀ x, x ∈ s ↔ p x) (f : {x // p x} → β) : ∑ x : {x // p x}, f x = ∑ x ∈ s, ...` hmm actually I recall: `Finset.sum_subtype (s : Finset α) {p : α → Prop} [DecidablePred p] (h : ∀ x, x ∈ s ↔ p x) (f : {a // p a} → β) : ∑ x : {a // p a}, f x = ∑ x ∈ s with hp : p x... ` no. The actual Mathlib lemma: `Finset.sum_subtype : ∑ x ∈ s.subtype p, f x = ∑ x ∈ s, if h : p x then f ⟨x, h⟩ else 0`? There's `Finset.sum_subtype (s : Finset α) {p} (h : ∀ x, x ∈ s ↔ p x) (f : {x // p x} → M) : ∑ x : {x // p x}, f x = ∑ x ∈ s.attach... ` hmm. Let me look at it: Mathlib has `Finset.sum_subtype`: ``` theorem Finset.sum_subtype {p : α → Prop} [DecidablePred p] {F : Type*} [AddCommMonoid F] (s : Finset α) (h : ∀ x, x ∈ s ↔ p x) (f : { x // p x } → F) : ∑ x : { x // p x }, f x = ∑ x ∈ s, if h' : p x then f ⟨x, h'⟩ else 0 := ... ``` Hmm no — the sum on the LHS is over the TYPE {x // p x} which requires a Fintype instance. The right form: `∑ x in s.subtype p, f x = ∑ x in s, ...`? For our case: the subtype finset is `nearZerosSub t := (something).toFinset.filter ...`. Ugh. Cleaner: keep the near sums in the SUBTYPE throughout the identity, and bridge to the ambient nearZeros only at the capstone. I.e., define: ```lean def nearZerosSub (t : ℝ) : Finset {ρ : ℂ // IsNontrivialZero ρ} := ((finite_subtype_norm_lt (|t| + 3)).toFinset).filter (fun ρ => |ρ.1.im − t| < 1) ``` Hmm — finite_subtype_norm_lt (X : ℝ) : {ρ : subtype | ‖ρ.1‖ < X}.Finite (from LiSeries, used in 5e). Then the near-sum over nearZerosSub. Bridge to ambient: Σ ρ ∈ nearZerosSub t, f ρ.1 = Σ ρ ∈ nearZeros t, f ρ — via Finset.sum_subtype-like: nearZerosSub t is the filter of a toFinset of a subtype finite set; the ambient nearZeros t is a filter of zeroDiscFinset. The membership correspondence: ρ.1 ∈ nearZeros t ↔ IsNontrivialZero ρ.1 ∧ |ρ.1.im − t| < 1 (via zeroDiscFinset's mem + the disc containment) — and ρ ∈ nearZerosSub t ↔ (ρ.1 near). Then the sum bridge: `Finset.sum_subtype`... Actually the cleanest: use `Finset.sum_finset_coe`? hmm. There's `Finset.sum_coe_sort`: `∑ x : s, f x = ∑ x ∈ s, f x` where the LHS is over the coercion of s to a type (s : Finset α) → (s : Type*) — ∑ x : ↥s, f x.1 = ∑ x ∈ s, f x ✓ THAT's the bridge: `Finset.sum_coe_sort (s : Finset α) (f : α → β) : ∑ x : s, f x = ∑ x ∈ s, f x`? Signature: `Finset.sum_coe_sort (s : Finset α) (f : s → M)?`... Hmm — actually for the near sum I can work the other direction: prove the identity with the near sums over the subtype finset nearZerosSub, and for the capstone statement rewrite Σ over nearZeros t as Σ over nearZerosSub t via sum_coe_sort-style bridges ONCE. Honestly — the near-sum form in the capstone matches LiDisc's capstone: `∑ ρ ∈ nearZeros t, (zeroMult ρ : ℂ) / (s - ρ)`. To minimize bridging pain, maybe restate the capstone's near sum as a subtype sum: `∑ ρ ∈ nearZerosSub t, (zeroMult ρ.1 : ℂ) / (s - ρ.1)`. The ii′-6 consumer doesn't exist yet — I'm free to choose the form! The subtype form is actually CLEANER for the consumer (the series is subtype-based). DECISION: the capstone's near sum is over `nearZerosSub t` (the subtype finset). No ambient bridge needed at all. Let me define nearZerosSub carefully. Requirements: ρ ∈ nearZerosSub t ↔ |ρ.1.im − t| < 1 (for subtype ρ). Via filter over a containing toFinset: any near subtype zero has ‖ρ.1‖ ≤ √(re² + im²) ≤ re + |im| ≤ 1 + (|t| + 1) = |t| + 2. So: def nearZerosSub (t : ℝ) : Finset {ρ : ℂ // IsNontrivialZero ρ} := (finite_subtype_norm_lt (|t| + 3)).toFinset.filter (fun ρ => |ρ.1.im − t| < 1) mem: ρ ∈ nearZerosSub t ↔ ρ ∈ toFinset ∧ near. ρ ∈ (finite_subtype_norm_lt X).toFinset ↔ ‖ρ.1‖ < X. For the mem characterization: ρ ∈ nearZerosSub t ↔ |ρ.1.im − t| < 1 — forward: trivial (filter). Backward: need ‖ρ.1‖ < |t| + 3 from |im − t| < 1: ‖ρ.1‖ ≤ |re| + |im| ≤ 1 + (|t|+1) = |t|+2 < |t|+3 ✓ (‖ρ‖ ≤ |re ρ| + |im ρ| via norm ≤ ...: ‖z‖ = √(re²+im²) ≤ |re| + |im| — lemma: Complex.norm_le_abs_re_add_abs_im ✓ exists I believe; re ρ ∈ (0,1) from IsNontrivialZero; |im| ≤ |im − t| + |t| ≤ 1 + |t| ✓). finite_subtype_norm_lt — check the exact name in LiSeries/LiCircleBound: from 5e-iii: "finite_subtype_norm_lt" — used: `(finite_subtype_norm_lt 4).subset ...` at lowZeros def: `(finite_subtype_norm_lt 4)` : {ρ : subtype | ‖ρ.1‖ < 4}.Finite? The lowZeros def used `(finite_subtype_norm_lt 4).subset (fun ρ hρ => lt_of_le_of_lt ...)` — so finite_subtype_norm_lt X : {ρ // IsNontrivialZero ρ ∧ ‖ρ‖ < X}? hmm — the lowZeros def: `(show {ρ : {ρ // IsNontrivialZero ρ} | ‖(ρ : ℂ)‖ ≤ 3}.Finite from (finite_subtype_norm_lt 4).subset (fun ρ hρ => lt_of_le_of_lt (show ‖(ρ:ℂ)‖ ≤ 3 from hρ) (by norm_num)))`. So finite_subtype_norm_lt 4 : {ρ : subtype | ‖ρ.1‖ < 4}.Finite where hρ : ‖ρ.1‖ ≤ 3 → ‖ρ.1‖ < 4 via the subset's hρ — the subset fn takes hρ : ρ ∈ {‖ρ‖ ≤ 3}... wait the subset direction: (finite_subtype_norm_lt 4) is the Finiteness of {‖ρ‖ < 4}; .subset (fun ρ hρ => ...) : {‖ρ‖ ≤ 3} ⊆ {‖ρ‖ < 4} where hρ : ρ ∈ {‖ρ‖ ≤ 3} i.e. ‖ρ‖ ≤ 3, and the fn returns lt_of_le_of_lt hρ (3 < 4) : ‖ρ‖ < 4 ✓. OK so finite_subtype_norm_lt (X) : {ρ : {ρ // IsNontrivialZero ρ} | ‖ρ.1‖ < X}.Finite ✓. Now the split form: Σ'_subtype diff = Σ_{nearZerosSub} diff + Σ'_{if-not-near} diff. With tsum_split_finset_complex (the ℂ variant) at the subtype. OK — I have a clear picture of 5f-i. Given context budget, let me now write the file with: 1. tsum_split_finset_complex (ℂ variant). 2. nearZerosSub + mem characterization. 3. seriesFun_sub_seriesFun (the difference identity). 4. Rexpr_decomp (the six-piece identity). 5. Piece 1: dirichletC2 ≤ 0.995 (the integral bound). 6. Piece 2: near sum at s₀ ≤ P1-count. 7. Pieces 4, 5: the elementary reciprocals. Pieces 3, 6 and the assembly in later chunks. Actually — piece 1's integral bound is the meatiest of these. Let me check what integral comparison machinery exists. Actually — simpler for piece 1: I need Σ_{n≥4} log n/n² ≤ (log 3 + 1)/3. Route: the function f(x) = log x/x² is decreasing on [3, ∞) (deriv = (1−2 log x)/x³ < 0 for x > e^{1/2}). The comparison: Σ_{n≥4} f(n) ≤ ∫₃^∞ f. Mathlib: is there `Real.tsum_le_integral_of_decreasing`? Let me grep quickly. There's `integral_test` machinery in Mathlib.Analysis... Let me search.
Checking piece-1 machinery (integral comparison for the tail) before writing.
tool: Bash
input
{
  "command": "M=D:/Python/Quantum/zeta-23-lean/.lake/packages/mathlib/Mathlib; grep -rn \"tsum_le_integral\\|sum_le_integral\" $M --include=\"*.lean\" | grep -i \"theorem\\|lemma\" | head -8; echo ===; grep -rn \"theorem.*integral.*log.*div.*pow\\|integral_log_div\" $M/Analysis/SpecialFunctions/Integrals.lean 2>/dev/null | head -4",
  "description": "Search for series-integral comparison lemmas"
}
#1722 assistant 2026-08-24 08:21:29.476 UTC · 923→2397 tok open ⤢
thinking (2702 chars)
`AntitoneOn.tsum_comp_add_le_integral` (used inside) and `AntitoneOn.tsum_le_integral` exist. The relevant one for my tail: `AntitoneOn.tsum_comp_add_le_integral (N) (anti) (integrable) (nonneg) : ∑' n, f (n + N) ≤ ∫ x in Ioi N, f x`-ish. Let me get its exact signature... From the code at line ~220-232: `AntitoneOn.tsum_comp_add_le_integral (N : ℝ)? ... : ∑' (n : ℕ), f ↑(n + N) ≤ ∫ x in Set.Ioi N, f x`. Close enough — I'll check exact form when building. For piece 1, this is getting heavy. Time/context check: this session has already delivered the perimeter repair + P1/P2 declarations + D-069 design. 5f-i (the identity + elementary pieces) is a solid next chunk but piece 1's integral bound alone is ~100 lines of fiddly integration. Given the pacing rules (no rush; clean sub-stages), and that this session has been long, let me assess: should I continue into 5f-i now or pause? The session protocol says break prompt when running long. The session has delivered: (1) perimeter repair (user-approved, committed), (2) D-069 design + P1/P2 (user-approved, committed). 5f-i is a natural next chunk but it's ~200+ lines of new Lean. I've been going a while. The BREAK PROMPT rule: "if work is running long — ESPECIALLY approaching 5:00 PM local time — pause and ASK the user whether to continue." Let me update STATE.md and the journal first (crash-safe — the design and findings are committed, but STATE's NEXT ACTION should point to 5f-i with the design summary), then ask the user whether to continue with 5f-i now or pause. Actually — let me at least get 5f-i's identity lemmas started... no. Let me be disciplined: update STATE.md NEXT ACTION to 5f-i with the piece map, update the journal (session-035 needs writing), update NGUYEN.md checklist, register in db, closure-commit — and ask about continuing. Actually the user said "Let's work on session 035" — they want the session to proceed. The session has two commits already. Let me do a proper checkpoint (journal + STATE + commit) and then ask whether to continue into 5f-i (the multi-hour Lean build) or pause. Hmm — actually, rather than asking immediately, let me estimate: 5f-i is the identity + pieces 1,2,4,5. That's substantial but mechanical. The risk of stopping mid-piece is low if I stop at a file boundary. Given the user is actively engaged (answered two questions promptly), let me continue with 5f-i but checkpoint first so a break can happen cleanly. Actually the session-end protocol requires journal+STATE+NGUYEN+db updates — I did the commits for the code but haven't written the session-035 journal yet. Let me write the journal NOW (crash-safe) with the current state, update STATE.md, then continue into 5f-i.
The integral-test machinery exists (`AntitoneOn.tsum_comp_add_le_integral`). Good checkpoint moment — let me write the journal + STATE update first (crash-safe), then continue into 5f-i.
tool: Write ok
input
{
  "file_path": "D:\\Python\\Quantum\\research\\journal\\session-035.md",
  "content": "# Session 035 \u2014 2026-08-23 \u2014 ii\u2032-5f STARTED: perimeter repair +\n# P1/P2 declarations + D-069 design (5f-0 COMPLETE)\n\n## Directive\nSession 035: ii\u2032-5f \u2014 the tight R-bound from the partial-fraction\nidentity (D-056's six-piece analysis \u27f9 |R(s)| \u2264 10.5\u00b7log(|t|+2) + 48,\nthe baked LiSkeleton constants). User: \"Let's work on session 035\".\n\n## Outcome part 1: PERIMETER REPAIR (user-approved, commit 75172e6)\n**Second ii\u2032-1a-class encoding defect found** (at the point of\nconsumption, 5f design): `ZeroCountProp` was encoded as the UNWEIGHTED\nset-card `Nat.card (zeroWindow t) \u2264 C0hat (t+1)`, but (i) the declared\nperimeter source (Trudgian 2014 N(T)/S(T), D-062 \u00a74) counts zeros WITH\nmultiplicity, and (ii) the 5f/ii\u2032-6 near sums are zeroMult-weighted\n(from seriesFun). The unconditional mult-weighted counts (Jensen/A\u2080)\nare ~100\u00d7 looser and would collapse the R-004 margin constants.\nUser chose **strengthen in place**: `ZeroCountProp` is now the\nmult-weighted form `(\u03a3 \u03c1 \u2208 window, zeroMult \u03c1 : \u211d) \u2264 C0hat (t+1)`.\nNew bridge lemma `one_le_zeroMult` (IsNontrivialZero \u03c1 \u27f9 1 \u2264 zeroMult \u03c1;\nanalyticAt_riemannZeta + AnalyticAt.analyticOrderAt_ne_zero +\nENat.toNat_pos). Consumers adapted via card \u2264 \u03a3 mult\n(Finset.card_eq_sum_ones as a REAL sum \u2014 the ascription\n((\u03a3 f : \u2115) : \u211d) elaborates to a real sum of casts, so bridge in \u211d\ndirectly): exists_zero_avoiding_T (LiContour), exists_gapCircle_radius\n(LiGapCircles, three window steps). Full build GREEN (8768 jobs);\naudit-session035-axioms.txt: 5 decls (incl. partialFraction_identity),\n3 standard axioms only.\n\n## Outcome part 2: TWO FINDINGS + P1/P2 PERIMETER ADDITIONS\n(user-approved, commit f850d9a; design D-069)\n- **Finding 1 (5f-blocking)**: D-056's piece 2 charges the near sum\n  \u03a3_{|\u03b3\u2212t|<1} 1/|s\u2080\u2212\u03c1| ONE unit-window count C\u2080(t), but |\u03b3\u2212t|<1 spans\n  TWO unit windows. The per-unit perimeter fold (2\u00b7\u0108\u2080) breaks 10.5/48\n  (\u2248 11.2\u00b7L + 51); the two-unit Trudgian F/S-pair form\n  (N(t+1)\u2212N(t\u22121), S-pair does NOT double: 0.59231\u00b7L + 0.886\u00b7LL + 2.591)\n  makes the honest assembly 6.111\u00b7L + 12.163\u00b7LL + 47.6 \u2264 10.5\u00b7L + 48 \u2014\n  FITS, worst point the loglog pinch at t \u2248 13.1 (margin \u2248 0.15\u20130.4).\n  \u27f9 **(P1) `ZeroCountProp2`** declared (two-unit mult-weighted count;\n  same Trudgian source; honesty slack 0.008\u00b7L + 0.109).\n- **Need (P2)**: the far sum's height-< 14 intervals need a numeric\n  count; Jensen gives \u2248 3.25 (breaks the pinch constants) vs the true\n  0 \u27f9 **`NoLowZeros`** declared (no nontrivial zeros with |\u03b3| \u2264 14;\n  Platt-class zero-location certificate \u2014 NOT implied by RHUpTo).\n- **Finding 2 (documented for ii\u2032-6, NOT 5f scope)**: D-036's H(T)\n  near-sum has the same count gap PLUS a clearance-coverage gap (L3's\n  clearance covers only in-window zeros). Honest H(T) near sum \u2248\n  7\u00b7\u0108\u2080\u00b2 + 8\u00b7\u0108\u2080 vs baked 3\u00b7\u0108\u2080\u00b2 \u2014 margin survives (E-028 26\u00d7 slack) but\n  the crossover/base points move; to be faced at ii\u2032-6 (D-069 \u00a74).\n\n## State of 5f (sub-stage map, D-069 \u00a75)\n- 5f-0 \u2714 (this session): design + P1/P2 + repair.\n- 5f-i: reference-point difference identity (partialFraction_identity\n  at s vs s\u2080 = 2+it, B cancels) + the near/far split (subtype finset\n  `nearZerosSub` + \u2102 tsum_split) + pieces 1 (dirichletC2 \u2264 0.995 via\n  \u039b \u2264 log + AntitoneOn.tsum_comp_add_le_integral), 2 (P1 \u00d7 |s\u2080\u2212\u03c1| \u2265 1),\n  4, 5 (\u20161/s \u2212 1/s\u2080\u2016 \u2264 4.5/|t|\u00b2 etc.).\n- 5f-ii: piece 6 (sharp digamma |r| \u2264 1.2/|w|\u00b2 via level-2 EM \u2014\n  LiRBound b2Fun machinery) + piece 3 (the far-sum interval machine;\n  conj for \u03b3 < 0; P2 for height < 14; \u03a3 1/(k(k+1)) = 1).\n- 5f-iii: assembly + the pinch lemma (12.163\u00b7LL \u2264 4.389\u00b7L + const,\n  interior max at L \u2248 2.772) + capstone\n  `logDeriv_riemannZeta_sub_nearZeros_le_tight` + audit.\n\n## Banked gotchas (session 035)\n- The ascription `((finset.sum f : \u2115) : \u211d)` elaborates to a REAL sum of\n  per-term casts (expected-type propagation INTO the sum) \u2014 so\n  Nat.cast_le.mpr (cast-of-\u2115-sum) does NOT match; bridge card \u2264 \u03a3 in \u211d\n  directly via `by simp` (card = \u03a3 1 in \u211d) + Finset.sum_le_sum +\n  exact_mod_cast.\n- `zerosIn T\u2081 T\u2082` is open-below (`T\u2081 < \u03c1.im`): for a |\u00b7| \u2264 1 window use\n  zerosIn (t\u22122) (t+1), NOT (t\u22121) (the boundary point \u03c1.im = t\u22121 is in\n  the abs-window but not in zerosIn (t\u22121) _).\n- le_or_lt absent (banked twice before \u2014 now also in journal-034).\n\n## Status / next\n5f-i: the difference identity + pieces 1/2/4/5 (LiTightR.lean, new\nfile). Inputs all verified live (tsum_split_finset \u211d-form in\nLiCircleBound:249 \u2014 needs the \u2102 variant; AntitoneOn.tsum_le_integral\nfamily in SumIntegralComparisons; nearZeros in LiDisc:970;\nvonMangoldt LSeries term norm = \u039b(n)/n\u00b2).\n"
}
result 2026-08-24 08:21:29Z → 2026-08-24 08:21:29Z
{
  "type": "create",
  "filePath": "D:\\Python\\Quantum\\research\\journal\\session-035.md",
  "content": "# Session 035 \u2014 2026-08-23 \u2014 ii\u2032-5f STARTED: perimeter repair +\n# P1/P2 declarations + D-069 design (5f-0 COMPLETE)\n\n## Directive\nSession 035: ii\u2032-5f \u2014 the tight R-bound from the partial-fraction\nidentity (D-056's six-piece analysis \u27f9 |R(s)| \u2264 10.5\u00b7log(|t|+2) + 48,\nthe baked LiSkeleton constants). User: \"Let's work on session 035\".\n\n## Outcome part 1: PERIMETER REPAIR (user-approved, commit 75172e6)\n**Second ii\u2032-1a-class encoding defect found** (at the point of\nconsumption, 5f design): `ZeroCountProp` was encoded as the UNWEIGHTED\nset-card `Nat.card (zeroWindow t) \u2264 C0hat (t+1)`, but (i) the declared\nperimeter source (Trudgian 2014 N(T)/S(T), D-062 \u00a74) counts zeros WITH\nmultiplicity, and (ii) the 5f/ii\u2032-6 near sums are zeroMult-weighted\n(from seriesFun). The unconditional mult-weighted counts (Jensen/A\u2080)\nare ~100\u00d7 looser and would collapse the R-004 margin constants.\nUser chose **strengthen in place**: `ZeroCountProp` is now the\nmult-weighted form `(\u03a3 \u03c1 \u2208 window, zeroMult \u03c1 : \u211d) \u2264 C0hat (t+1)`.\nNew bridge lemma `one_le_zeroMult` (IsNontrivialZero \u03c1 \u27f9 1 \u2264 zeroMult \u03c1;\nanalyticAt_riemannZeta + AnalyticAt.analyticOrderAt_ne_zero +\nENat.toNat_pos). Consumers adapted via card \u2264 \u03a3 mult\n(Finset.card_eq_sum_ones as a REAL sum \u2014 the ascription\n((\u03a3 f : \u2115) : \u211d) elaborates to a real sum of casts, so bridge in \u211d\ndirectly): exists_zero_avoiding_T (LiContour), exists_gapCircle_radius\n(LiGapCircles, three window steps). Full build GREEN (8768 jobs);\naudit-session035-axioms.txt: 5 decls (incl. partialFraction_identity),\n3 standard axioms only.\n\n## Outcome part 2: TWO FINDINGS + P1/P2 PERIMETER ADDITIONS\n(user-approved, commit f850d9a; design D-069)\n- **Finding 1 (5f-blocking)**: D-056's piece 2 charges the near sum\n  \u03a3_{|\u03b3\u2212t|<1} 1/|s\u2080\u2212\u03c1| ONE unit-window count C\u2080(t), but |\u03b3\u2212t|<1 spans\n  TWO unit windows. The per-unit perimeter fold (2\u00b7\u0108\u2080) breaks 10.5/48\n  (\u2248 11.2\u00b7L + 51); the two-unit Trudgian F/S-pair form\n  (N(t+1)\u2212N(t\u22121), S-pair does NOT double: 0.59231\u00b7L + 0.886\u00b7LL + 2.591)\n  makes the honest assembly 6.111\u00b7L + 12.163\u00b7LL + 47.6 \u2264 10.5\u00b7L + 48 \u2014\n  FITS, worst point the loglog pinch at t \u2248 13.1 (margin \u2248 0.15\u20130.4).\n  \u27f9 **(P1) `ZeroCountProp2`** declared (two-unit mult-weighted count;\n  same Trudgian source; honesty slack 0.008\u00b7L + 0.109).\n- **Need (P2)**: the far sum's height-< 14 intervals need a numeric\n  count; Jensen gives \u2248 3.25 (breaks the pinch constants) vs the true\n  0 \u27f9 **`NoLowZeros`** declared (no nontrivial zeros with |\u03b3| \u2264 14;\n  Platt-class zero-location certificate \u2014 NOT implied by RHUpTo).\n- **Finding 2 (documented for ii\u2032-6, NOT 5f scope)**: D-036's H(T)\n  near-sum has the same count gap PLUS a clearance-coverage gap (L3's\n  clearance covers only in-window zeros). Honest H(T) near sum \u2248\n  7\u00b7\u0108\u2080\u00b2 + 8\u00b7\u0108\u2080 vs baked 3\u00b7\u0108\u2080\u00b2 \u2014 margin survives (E-028 26\u00d7 slack) but\n  the crossover/base points move; to be faced at ii\u2032-6 (D-069 \u00a74).\n\n## State of 5f (sub-stage map, D-069 \u00a75)\n- 5f-0 \u2714 (this session): design + P1/P2 + repair.\n- 5f-i: reference-point difference identity (partialFraction_identity\n  at s vs s\u2080 = 2+it, B cancels) + the near/far split (subtype finset\n  `nearZerosSub` + \u2102 tsum_split) + pieces 1 (dirichletC2 \u2264 0.995 via\n  \u039b \u2264 log + AntitoneOn.tsum_comp_add_le_integral), 2 (P1 \u00d7 |s\u2080\u2212\u03c1| \u2265 1),\n  4, 5 (\u20161/s \u2212 1/s\u2080\u2016 \u2264 4.5/|t|\u00b2 etc.).\n- 5f-ii: piece 6 (sharp digamma |r| \u2264 1.2/|w|\u00b2 via level-2 EM \u2014\n  LiRBound b2Fun machinery) + piece 3 (the far-sum interval machine;\n  conj for \u03b3 < 0; P2 for height < 14; \u03a3 1/(k(k+1)) = 1).\n- 5f-iii: assembly + the pinch lemma (12.163\u00b7LL \u2264 4.389\u00b7L + const,\n  interior max at L \u2248 2.772) + capstone\n  `logDeriv_riemannZeta_sub_nearZeros_le_tight` + audit.\n\n## Banked gotchas (session 035)\n- The ascription `((finset.sum f : \u2115) : \u211d)` elaborates to a REAL sum of\n  per-term casts (expected-type propagation INTO the sum) \u2014 so\n  Nat.cast_le.mpr (cast-of-\u2115-sum) does NOT match; bridge card \u2264 \u03a3 in \u211d\n  directly via `by simp` (card = \u03a3 1 in \u211d) + Finset.sum_le_sum +\n  exact_mod_cast.\n- `zerosIn T\u2081 T\u2082` is open-below (`T\u2081 < \u03c1.im`): for a |\u00b7| \u2264 1 window use\n  zerosIn (t\u22122) (t+1), NOT (t\u22121) (the boundary point \u03c1.im = t\u22121 is in\n  the abs-window but not in zerosIn (t\u22121) _).\n- le_or_lt absent (banked twice before \u2014 now also in journal-034).\n\n## Status / next\n5f-i: the difference identity + pieces 1/2/4/5 (LiTightR.lean, new\nfile). Inputs all verified live (tsum_split_finset \u211d-form in\nLiCircleBound:249 \u2014 needs the \u2102 variant; AntitoneOn.tsum_le_integral\nfamily in SumIntegralComparisons; nearZeros in LiDisc:970;\nvonMangoldt LSeries term norm = \u039b(n)/n\u00b2).\n",
  "structuredPatch": [],
  "originalFile": null
}
#1723 assistant 2026-08-24 08:22:48.918 UTC · 518→277 tok open ⤢
thinking (706 chars)
Checkpoint committed. Now let me continue with 5f-i. Given the session length so far and the size of 5f-i (the identity + 4 pieces, ~300-400 lines of Lean), let me assess whether to push forward or pause. The user said "Let's work on session 035" — the session is active. The work so far: perimeter repair + P1/P2 + design, all committed. 5f-i is the next chunk. Per the pacing directive (§8.5: "if work is running long... pause and ASK"), I should check in with the user rather than barrel into a multi-hundred-line Lean build. Also I don't know the local time — the guideline says especially approaching 5 PM. I can't check the clock... actually I can: `Get-Date`/date. Let me check the time and decide.
Checkpoint committed (`0cca091`). Let me check the time before starting the 5f-i Lean build.
tool: Bash
input
{
  "command": "date /t & time /t",
  "description": "Check local time"
}
#1724 assistant 2026-08-24 08:23:36.857 UTC · 228→662 tok open ⤢
thinking (503 chars)
It's 1:23 AM local time (Aug 24) — well past any reasonable hour, and the pacing directive says to pause and ask, especially late in the day. The session has delivered two solid committed sub-stages (perimeter repair + P1/P2/D-069). 5f-i is a multi-hundred-line Lean build — a natural stopping point. Per the BREAK PROMPT rule, I should ask the user whether to continue or log off. Given it's 1:23 AM, I should flag the time and offer to stop cleanly (everything is committed; STATE.md points to 5f-i).
It's **1:23 AM** local time — flagging per the pacing rule. Session 035 has two committed sub-stages and a clean checkpoint: 1. **Perimeter repair** (`75172e6`): `ZeroCountProp` strengthened to the mult-weighted form (user-approved), `one_le_zeroMult` bridge, both consumers adapted, full build green, audit clean. 2. **5f-0** (`f850d9a`): D-069 design + the two new perimeter declarations (`ZeroCountProp2` two-unit count, `NoLowZeros` |γ| ≥ 14), both user-approved. 3. **Checkpoint** (`0cca091`): journal + STATE with the 5f-i piece map. Key findings documented in D-069: D-056's piece-2 two-unit window gap (10.5/48 survives via the two-unit Trudgian form — honest assembly 6.111L + 12.163LL + 47.6 ≤ 10.5L + 48 with pinch margin ~0.15–0.4 at t ≈ 13), and the H(T) clearance-coverage gap filed on the ii′-6 repair map. Everything is committed; STATE.md's NEXT ACTION is the 5f-i build (difference identity + pieces 1/2/4/5 in LiTightR.lean).
tool: AskUserQuestion ok
input
{
  "questions": [
    {
      "question": "It's 1:23 AM. Continue into the 5f-i Lean build (difference identity + pieces 1/2/4/5, a few hundred lines), or pause here?",
      "header": "Continue?",
      "options": [
        {
          "label": "Log off for tonight",
          "description": "Everything is committed and resumable; STATE.md points to 5f-i. Next session starts the LiTightR.lean build fresh."
        },
        {
          "label": "Continue with 5f-i",
          "description": "Start LiTightR.lean now: the reference-point difference identity + near/far split + the elementary pieces (1: dirichletC2 \u2264 0.995; 2: near count; 4/5: reciprocal bounds)."
        },
        {
          "label": "Just one more piece",
          "description": "Build only the difference identity + near/far split scaffolding tonight, then checkpoint."
        }
      ]
    }
  ]
}
result 2026-08-24 08:53:23Z → 2026-08-24 08:53:23Z
{
  "questions": [
    "question=\"It's 1:23 AM. Continue into the 5f-i Lean build (difference identity + pieces 1/2/4/5, a few hundred lines), or pause here?\" header='Continue?' options=[QuestionOption(label='Log off for tonight', description='Everything is committed and resumable; STATE.md points to 5f-i. Next session starts the LiTightR.lean build fresh.', preview=None), QuestionOption(label='Continue with 5f-i', description='Start LiTightR.lean now: the reference-point difference identity + near/far split + the elementary pieces (1: dirichletC2 \u2264 0.995; 2: near count; 4/5: reciprocal bounds).', preview=None), QuestionOption(label='Just one more piece', description='Build only the difference identity + near/far split scaffolding tonight, then checkpoint.', preview=None)] multi_select=False"
  ],
  "answers": {
    "It's 1:23 AM. Continue into the 5f-i Lean build (difference identity + pieces 1/2/4/5, a few hundred lines), or pause here?": "Continue with 5f-i"
  }
}
#1725 assistant 2026-08-24 09:00:34.291 UTC · 1785→11822 tok open ⤢
thinking (30861 chars)
The proof is generic except the type is ℝ. `Summable.of_norm_bounded` — works for any NormedAddCommGroup? The proof uses `hf.norm` (Summable of norms). For ℂ the same proof works verbatim if Summable.of_norm_bounded is general. Actually — simpler: rather than duplicating, I can make the ℂ version by the same 20 lines. Let me check `Summable.of_norm_bounded`: hmm — the standard is `Summable.of_norm_bounded (hf : Summable g) (h : ∀ i, ‖f i‖ ≤ g i) : Summable f`. So `Summable.of_norm_bounded hf.norm (fun i => ...)` where the bound is ‖f i‖ ≤ ‖f i‖ ✓. Fine for ℂ. Now writing LiTightR.lean. Let me draft the whole 5f-i file carefully. ```lean /- NguyenRH1/LiTightR.lean — tier ii′ sub-stage ii′-5f (D-069): the tight R-bound from the partial-fraction identity (reference-point method, D-056 §2 with the D-069 honest piece-2 count). §1: the ℂ tsum split (variant of LiCircleBound's tsum_split_finset). §2: the near-zero subtype finset `nearZerosSub` + membership. §3: the seriesFun difference identity. §4: the six-piece reference-point decomposition `Rexpr_decomp`. §5: piece 1 — `dirichletC2_le` (≤ 0.995). §6: piece 2 — the near sum at s₀ ≤ the ZeroCountProp2 count. §7: pieces 4/5 — the reciprocal differences. (pieces 3, 6: 5f-ii; the assembly + pinch lemma: 5f-iii.) -/ import Mathlib import NguyenRH1.LiSqueeze open Zeta23 Complex Filter Topology noncomputable section namespace NguyenRH1 ``` §1: ```lean /-! ## 1. The ℂ tsum split -/ /-- Splitting a summable complex tsum over a finset (the ℂ variant of LiCircleBound's `tsum_split_finset`). -/ lemma tsum_split_finset_complex {ι : Type*} [DecidableEq ι] {f : ι → ℂ} (hf : Summable f) (s : Finset ι) : ∑' i, f i = ∑ i ∈ s, f i + ∑' i, (if i ∈ s then 0 else f i) := by classical have h1 : Summable (fun i => if i ∈ s then f i else 0) := by apply Summable.of_norm_bounded hf.norm intro i by_cases hi : i ∈ s <;> simp [hi] have h2 : Summable (fun i => if i ∈ s then 0 else f i) := by apply Summable.of_norm_bounded hf.norm intro i by_cases hi : i ∈ s <;> simp [hi] have h3 : ∑' i, f i = ∑' i, ((if i ∈ s then f i else 0) + (if i ∈ s then 0 else f i)) := by apply tsum_congr intro i by_cases hi : i ∈ s <;> simp [hi] rw [h3, Summable.tsum_add h1 h2] congr 1 rw [tsum_eq_sum (s := s) (fun b hb => if_neg hb)] exact Finset.sum_congr rfl (fun b hb => if_pos hb) ``` Hmm — `Summable.of_norm_bounded hf.norm` — the exact name/signature: from the LiCircleBound usage it works for ℝ. For ℂ: `Summable.of_norm_bounded (hf : Summable g) (h : ∀ i, ‖f i‖ ≤ g i)`? The LiCircleBound call: `Summable.of_norm_bounded hf.norm` then `intro i` — so of_norm_bounded takes the dominator's Summable and returns a goal ∀ i, ‖f i‖ ≤ ‖f' i‖... For ℂ, hf.norm : Summable (fun i => ‖f i‖) ✓ same. OK — but wait: is `Summable.of_norm_bounded` the right name? The LiCircleBound code compiled with it ✓ (it's in the same Mathlib). For ℂ the lemma might need the CompleteSpace — ℂ is complete ✓. Fine — actually, might as well try to just USE the ℝ version via... no, ℂ needed. Alternatively state it for a general NormedField? Just do ℂ. Hmm wait — actually even simpler: can I state it for `{E : Type*} [NormedAddCommGroup E] [NormedSpace ℂ E]`? Overkill. ℂ only. §2: nearZerosSub. ```lean /-! ## 2. The near-zero subtype finset -/ /-- The near-zero subtype finset: nontrivial zeros with |γ − t| < 1, as a finset of the zero subtype (the seriesFun index type). -/ def nearZerosSub (t : ℝ) : Finset {ρ : ℂ // IsNontrivialZero ρ} := (finite_subtype_norm_lt (|t| + 3)).toFinset.filter fun ρ => |ρ.1.im - t| < 1 ``` Check `finite_subtype_norm_lt`'s exact name/form: from lowZeros def: `(finite_subtype_norm_lt 4)` : {ρ : {ρ // IsNontrivialZero ρ} | ‖(ρ:ℂ)‖ < 4}.Finite. So `finite_subtype_norm_lt (X : ℝ) : {ρ : subtype | ‖ρ.1‖ < X}.Finite` — hmm wait, the lowZeros def: `(show {ρ : {ρ // IsNontrivialZero ρ} | ‖(ρ : ℂ)‖ ≤ 3}.Finite from (finite_subtype_norm_lt 4).subset (fun ρ hρ => lt_of_le_of_lt (show ‖(ρ : ℂ)‖ ≤ 3 from hρ) (by norm_num)))`. So finite_subtype_norm_lt X : {ρ | ‖ρ.1‖ < X}.Finite where the subtype coercion ρ.1 or (ρ : ℂ) — both appear. OK. ```lean lemma mem_nearZerosSub {t : ℝ} {ρ : {ρ : ℂ // IsNontrivialZero ρ}} : ρ ∈ nearZerosSub t ↔ |ρ.1.im - t| < 1 := by rw [nearZerosSub, Finset.mem_filter] refine ⟨fun h => h.2, fun h => ⟨?_, h⟩⟩ rw [Set.Finite.mem_toFinset] -- goal: ρ ∈ {ρ | ‖ρ.1‖ < |t| + 3} show ‖ρ.1‖ < |t| + 3 have hre : |ρ.1.re| ≤ 1 := by have h1 := ρ.2.2.1 -- 0 < re have h2 := ρ.2.2.2 -- re < 1 rw [abs_le] constructor <;> linarith have him : |ρ.1.im| ≤ |t| + 1 := by have := abs_sub_abs_le_abs_sub ρ.1.im t -- hmm want |im| ≤ |im − t| + |t| ... ``` |im| ≤ |im − t| + |t|: `abs_sub_abs_le_abs_sub : |a| − |b| ≤ |a − b|`... I want |im| ≤ |im−t| + |t| = abs_sub_le_abs_add_abs_sub? The triangle: |im| = |(im−t) + t| ≤ |im−t| + |t| (abs_add_le) ✓. So |im| ≤ |im−t| + |t| < 1 + |t|. And ‖ρ.1‖ ≤ |re| + |im| (Complex.norm_le_abs_re_add_abs_im — check name; there's `Complex.norm_le_abs_re_add_abs_im : ‖z‖ ≤ |z.re| + |z.im|` ✓ I believe). So ‖ρ‖ < 1 + (1 + |t|) = |t| + 2 < |t| + 3 ✓. Set.Finite.mem_toFinset — signature: (hs : s.Finite)? Earlier usage: `Set.Finite.mem_toFinset hfin` (one arg) at LiContour:175. So `Set.Finite.mem_toFinset (finite_subtype_norm_lt _) : a ∈ ....toFinset ↔ a ∈ {ρ | ‖ρ.1‖ < X}` — membership in the set-builder = the predicate ✓ `show ‖ρ.1‖ < |t| + 3` should be defeq ✓. §3: the difference identity. ```lean /-! ## 3. The seriesFun difference identity -/ /-- seriesFun s − seriesFun s₀ as the termwise difference series. -/ theorem seriesFun_sub_seriesFun (s s₀ : ℂ) : seriesFun s - seriesFun s₀ = ∑' ρ : {ρ : ℂ // IsNontrivialZero ρ}, (zeroMult ρ.1 : ℂ) * (1 / (s - ρ.1) - 1 / (s₀ - ρ.1)) := by rw [seriesFun, seriesFun, ← tsum_sub seriesSummable seriesSummable] refine tsum_congr fun ρ => ?_ rw [seriesTerm, seriesTerm] ring ``` Check seriesSummable's signature: from LiSeries — "seriesSummable at EVERY s" — presumably `theorem seriesSummable (s : ℂ) : Summable (seriesTerm s)` or `Summable (fun ρ => seriesTerm s ρ)`. tsum_sub (hf : Summable f) (hg : Summable g) : ∑' (f − g) = ∑' f − ∑' g — so ← tsum_sub: ∑' f − ∑' g = ∑' (f − g) where f − g is the pointwise Pi.sub — ∑' ρ, (seriesTerm s − seriesTerm s₀) ρ = ∑' ρ, seriesTerm s ρ − seriesTerm s₀ ρ. Then tsum_congr with the pointwise identity: seriesTerm s ρ − seriesTerm s₀ ρ = (zeroMult ρ.1 : ℂ)·(1/(s−ρ.1) − 1/(s₀−ρ.1)) — via rw [seriesTerm, seriesTerm]: the def seriesTerm s ρ := (zeroMult ρ : ℂ)·(1/(s−(ρ:ℂ)) + 1/(ρ:ℂ)) — from LiSeries line 55-56: `def seriesTerm (s : ℂ) (ρ : {ρ : ℂ // IsNontrivialZero ρ}) : ℂ := (zeroMult ρ : ℂ) * (1 / (s - (ρ : ℂ)) + 1 / (ρ : ℂ))`. Hmm — (zeroMult ρ : ℂ) — ρ here is the subtype; zeroMult takes ℂ — so it's zeroMult ρ.1 with the coe. rw [seriesTerm] unfolds? For a def, `rw [seriesTerm]` uses the equation lemma — used in LiCircleBound (`rw [Fexpr]`). Hmm — actually `rw [seriesTerm]` might not work directly on defs... they used `rw [Fexpr]` in Fexpr_circle_le ✓ and `rw [Fexpr] at hG` in my capstone ✓ worked. For seriesTerm similar. But safer: `show` + ring, or `unfold seriesTerm`. Let me use `simp only [seriesTerm]`? hmm — I'll write `rw [seriesTerm, seriesTerm]` and if it fails, `unfold`. Actually there's a subtlety: after ← tsum_sub, the goal is ∑' ρ, seriesTerm s ρ − seriesTerm s₀ ρ = ∑' ρ, m·(1/(s−ρ.1) − 1/(s₀−ρ.1)). tsum_congr needs pointwise: seriesTerm s ρ − seriesTerm s₀ ρ = m·(...). rw [seriesTerm] rewrites the LHS occurrences: seriesTerm s ρ → (zeroMult ↑ρ : ℂ)·(1/(s − ↑ρ) + 1/↑ρ)... wait — does rw with a def name generate the equation? For `def f x := body`, rw [f] uses f.eq_def or the auto-generated equational lemma f : f x = body? In Lean4/Mathlib, `rw [f]` for a non-recursive def uses `f.eq_def`? There's the auto-generated `f.eq_def`? Hmm — the pattern used in the codebase: `rw [Fexpr]` at LiCircleBound:3846 and it worked. Also `rw [Gammaℝ_def]`-style. So `rw [seriesTerm, seriesTerm]` should unfold both applications — hmm, one rw [seriesTerm] unfolds ALL instances? Each rw [seriesTerm] unfolds every `seriesTerm ?s ?ρ` occurrence... it rewrites with the equation lemma `seriesTerm = fun s ρ => ...`? That would rewrite the FUNCTION, not the application — producing (fun s ρ => ...) s ρ redexes. Hmm — the codebase banked gotcha (session 027): "sum_add_tsum_nat_add's shifted terms are beta-redexes (state goals in redex form)". So rw [defname] produces beta-redexes which need beta reduction — `ring` after should still work (ring normalizes through beta-redexes? maybe not). The pattern that worked in Fexpr_circle_le: `rw [Fexpr]` then `exact norm_add_le _ _` — the goal after rw had the unfolded form ✓ worked there. Alternatively avoid rw: prove the pointwise identity by `show`: ```lean refine tsum_congr fun ρ => ?_ show (zeroMult ρ.1 : ℂ) * (1 / (s - ρ.1) + 1 / ρ.1) - (zeroMult ρ.1 : ℂ) * (1 / (s₀ - ρ.1) + 1 / ρ.1) = _ ring ``` The `show` needs the defeq form — seriesTerm s ρ is DEFEQ to its body (a plain def) ✓ `show` works. But I need to write the exact body form. The body: (zeroMult (ρ:ℂ) : ℂ) * (1 / (s - (ρ:ℂ)) + 1 / ((ρ:ℂ))). With ρ : subtype, (ρ : ℂ) = ρ.1 ✓. Let me write: ```lean refine tsum_congr fun ρ => ?_ show (zeroMult (ρ : ℂ) : ℂ) * (1 / (s - (ρ : ℂ)) + 1 / (ρ : ℂ)) - (zeroMult (ρ : ℂ) : ℂ) * (1 / (s₀ - (ρ : ℂ)) + 1 / (ρ : ℂ)) = (zeroMult (ρ : ℂ) : ℂ) * (1 / (s - (ρ : ℂ)) - 1 / (s₀ - (ρ : ℂ))) ring ``` And the goal's RHS has (zeroMult ρ.1 : ℂ) — ρ.1 vs (ρ : ℂ) — defeq, and the `show` target's defeq to the goal ✓ (Subtype coe is ρ.1 — syntactically ↑ρ; the goal written with ρ.1 vs ↑ρ — hmm, my §3 statement writes `zeroMult ρ.1` and `s - ρ.1` but the def body uses `(ρ : ℂ)`. These are the SAME (ρ.1 = ↑ρ syntactically? In Lean4, Subtype's coe is `Subtype.val` = ρ.1 — `(ρ : ℂ)` elaborates to `Subtype.val ρ` i.e. `ρ.1` ✓ same term). OK. §4: the six-piece decomposition. Statement: ```lean /-! ## 4. The reference-point decomposition -/ /-- The R-expression decomposed at the reference point s₀ (both s and s₀ good, so the partial-fraction identity applies at both): the near sums over `nearZerosSub t`, the far difference series, the elementary terms, and the digamma difference. -/ theorem Rexpr_decomp (hZC : ZeroCountProp) {s s₀ : ℂ} (hs : riemannZeta s ≠ 0) (hs0 : s ≠ 0) (hs1 : s ≠ 1) (hst : ∀ n : ℕ, 1 ≤ n → s ≠ -2 * (n : ℂ)) (hs₀ : riemannZeta s₀ ≠ 0) (hs₀0 : s₀ ≠ 0) (hs₀1 : s₀ ≠ 1) (hs₀t : ∀ n : ℕ, 1 ≤ n → s₀ ≠ -2 * (n : ℂ)) (t : ℝ) : logDeriv riemannZeta s - ∑ ρ ∈ nearZerosSub t, (zeroMult ρ.1 : ℂ) / (s - ρ.1) = logDeriv riemannZeta s₀ - ∑ ρ ∈ nearZerosSub t, (zeroMult ρ.1 : ℂ) / (s₀ - ρ.1) + (∑' ρ : {ρ : ℂ // IsNontrivialZero ρ}, if ρ ∈ nearZerosSub t then (0 : ℂ) else (zeroMult ρ.1 : ℂ) * (1 / (s - ρ.1) - 1 / (s₀ - ρ.1))) - (1 / s - 1 / s₀) - (1 / (s - 1) - 1 / (s₀ - 1)) - (Complex.digamma (s / 2) - Complex.digamma (s₀ / 2)) / 2 := by obtain ⟨B, hB⟩ := partialFraction_identity hZC have hsid := hB s hs hs0 hs1 hst have hs₀id := hB s₀ hs₀ hs₀0 hs₀1 hs₀t -- the series difference have hdiff := seriesFun_sub_seriesFun s s₀ -- the split of the difference series over nearZerosSub have hsplit := tsum_split_finset_complex (f := fun ρ : {ρ : ℂ // IsNontrivialZero ρ} => (zeroMult ρ.1 : ℂ) * (1 / (s - ρ.1) - 1 / (s₀ - ρ.1))) (by ...) (nearZerosSub t) ... ``` The summability of the diff-term: from hdiff's RHS — `hsplit`'s hf : Summable (fun ρ => m·(1/(s−ρ.1) − 1/(s₀−ρ.1))): from seriesFun_sub_seriesFun: the RHS tsum equals seriesFun s − seriesFun s₀ — summable because it's the difference: `Summable.sub seriesSummable seriesSummable` — hmm the term form: seriesTerm s ρ − seriesTerm s₀ ρ vs m·(1/(s−ρ)−1/(s₀−ρ)) — pointwise equal (the §3 congr) so the summability transfers via Summable.congr: (Summable.sub seriesSummable seriesSummable).congr (fun ρ => (the pointwise identity)). Let me package: in §3, ALSO prove `diffTerm_summable : Summable (fun ρ => m·(1/(s−ρ.1) − 1/(s₀−ρ.1)))`. Then the algebra: Rexpr = logDeriv s − near(s). From hsid: logDeriv s = B + seriesFun s − 1/s − 1/(s−1) + c − ψ(s/2)/2. So: Rexpr = B + seriesFun s − 1/s − 1/(s−1) + c − ψ(s/2)/2 − near(s) and logDeriv s₀ similarly. seriesFun s = seriesFun s₀ + Σ'all-diff (hdiff) = seriesFun s₀ + Σ_near diff + Σ'_far diff (hsplit). And Σ_near diff = Σ_near m·(1/(s−ρ) − 1/(s₀−ρ)) = near(s) − near(s₀) — the finset algebra: Σ ρ∈S, m·(1/(s−ρ) − 1/(s₀−ρ)) = Σ m/(s−ρ) − Σ m/(s₀−ρ) via Finset.sum_sub_distrib + mul_sub ✓. Assemble: Rexpr = logDeriv s₀ − near(s₀) + Σ'_far diff − (1/s − 1/s₀) − (1/(s−1) − 1/(s₀−1)) − (ψ(s/2)−ψ(s₀/2))/2. All linear algebra in ℂ — after the substitutions, `linear_combination` with the haves or a calc. The ψ piece: hsid has − Complex.digamma (s/2)/2 — wait the identity: logDeriv ζ s = B + seriesFun s − 1/s − 1/(s−1) + (log π)/2 − digamma(s/2)/2. So the ψ terms: −ψ(s/2)/2 + ψ(s₀/2)/2 = −(ψ(s/2) − ψ(s₀/2))/2 ✓. Proof sketch: ```lean have hnear : ∑ ρ ∈ nearZerosSub t, (zeroMult ρ.1 : ℂ) * (1 / (s - ρ.1) - 1 / (s₀ - ρ.1)) = ∑ ρ ∈ nearZerosSub t, (zeroMult ρ.1 : ℂ) / (s - ρ.1) - ∑ ρ ∈ nearZerosSub t, (zeroMult ρ.1 : ℂ) / (s₀ - ρ.1) := by rw [← Finset.sum_sub_distrib] refine Finset.sum_congr rfl fun ρ _ => ?_ rw [mul_sub, div_eq_mul_one_div, div_eq_mul_one_div] -- hmm m/(s−ρ) = m·(1/(s−ρ)) ring? ``` m·(1/(s−ρ) − 1/(s₀−ρ)) = m/(s−ρ) − m/(s₀−ρ): field_simp-free: div_eq_mul_one_div both sides then ring: m·(1/(s−ρ)) − m·(1/(s₀−ρ)) ✓ = m·(1/(s−ρ) − 1/(s₀−ρ)) ✓ ring. But rw div_eq_mul_one_div rewrites ALL divisions — including in the tsum... in this local have it's fine. Actually simpler: `rw [div_eq_mul_one_div, div_eq_mul_one_div, mul_sub]`? The goal: m·(1/(s−ρ) − 1/(s₀−ρ)) = m/(s−ρ) − m/(s₀−ρ): rw div_eq_mul_one_div twice turns RHS into m·(s−ρ)⁻¹ − m·(s₀−ρ)⁻¹; LHS has 1/(s−ρ) = (s−ρ)⁻¹ — one_div: 1/x = x⁻¹. So: rw [div_eq_mul_one_div (zeroMult ... : ℂ), div_eq_mul_one_div] — hmm the two divs are m/(s−ρ) and m/(s₀−ρ) — rw [div_eq_mul_one_div] rewrites ALL `_ / _` instances — including 1/(s−ρ) inside. Then LHS: m·((s−ρ)⁻¹·... no: 1/(s−ρ) = 1·(s−ρ)⁻¹ → (s−ρ)⁻¹ after one_mul? rw gives 1/(s−ρ) → 1 * (s−ρ)⁻¹. Messy. Cleanest: `field_simp`? No — pure commutive-ring identity with divisions as atoms: `linear_combination`? no haves. Just: have h : ∀ a b : ℂ, m·(a − b) = m·a − m·b := fun a b => mul_sub ..; the terms m/(s−ρ) = m·(1/(s−ρ)) via div_eq_mul_one_div... Actually simplest robust: prove with `rw [mul_sub]` after showing the div-forms match: m/(s−ρ) IS definitionally m·(s−ρ)⁻¹ and 1/(s−ρ) is 1·(s−ρ)⁻¹... The identity m·((s−ρ)⁻¹ − (s₀−ρ)⁻¹) = m·(s−ρ)⁻¹ − m·(s₀−ρ)⁻¹ is mul_sub ✓ and m/(s−ρ) = m·(s−ρ)⁻¹ = m·(1/(s−ρ)) since 1/(s−ρ) = (s−ρ)⁻¹ (one_div) and ·1... `one_mul`. So: ```lean refine Finset.sum_congr rfl fun ρ _ => ?_ rw [div_eq_mul_one_div, div_eq_mul_one_div, one_div, one_div] ring ``` div_eq_mul_one_div : a / b = a * (1 / b). So m/(s−ρ) → m·(1/(s−ρ)) ✓ then one_div: 1/(s−ρ) → (s−ρ)⁻¹ — the LHS term m·(1/(s−ρ) − 1/(s₀−ρ)) → m·((s−ρ)⁻¹ − (s₀−ρ)⁻¹) — wait one_div rewrites 1/(s−ρ) too — after div_eq_mul_one_div turned m/(s−ρ) into m·(1/(s−ρ)), there are MORE 1/· instances — the two one_div rewrites handle 1/(s−ρ) and 1/(s₀−ρ) — but div_eq_mul_one_div also rewrites the 1/(s−ρ) inside?? div_eq_mul_one_div matches a/b with a = 1: 1/(s−ρ) → 1·(s−ρ)⁻¹ — hmm it rewrites ALL _/_ occurrences: the goal m·(1/(s−ρ) − 1/(s₀−ρ)) = m/(s−ρ) − m/(s₀−ρ): after rw [div_eq_mul_one_div]: LHS: m·((1·(s−ρ)⁻¹) − (1·(s₀−ρ)⁻¹)); RHS: m·(1·(s−ρ)⁻¹) − m·(1·(s₀−ρ)⁻¹). Then ring closes (the 1·x are fine for ring) ✓. So just `rw [div_eq_mul_one_div]; ring`? rw once rewrites all div instances ✓. Let me use that. Then the full assembly by linear_combination with hsid, hs₀id, hdiff, hsplit, hnear: Goal: logDeriv s − near(s) = logDeriv s₀ − near(s₀) + far − (1/s−1/s₀) − (1/(s−1)−1/(s₀−1)) − (ψs−ψs₀)/2. linear_combination needs the goal minus a linear combination of haves to be a ring identity. Atoms: logDeriv s, logDeriv s₀, seriesFun s, seriesFun s₀, near(s), near(s₀), far-tsum-if, the all-diff-tsum, the if-near tsum, elems, ψs, ψs₀, B, c. Relations: - hsid: logDeriv s = B + seriesFun s − 1/s − 1/(s−1) + c − ψs/2 - hs₀id: logDeriv s₀ = B + seriesFun s₀ − 1/s₀ − 1/(s₀−1) + c − ψs₀/2 - hdiff: seriesFun s − seriesFun s₀ = alldiff - hsplit: alldiff = near-diff + far (tsum_split: ∑' = ∑ + ∑'if — the form: alldiff = Σ_near diff + far-tsum ✓) - hnear: near-diff-sum = near(s) − near(s₀) Goal: logDeriv s − near(s) = logDeriv s₀ − near(s₀) + far − (1/s − 1/s₀) − (1/(s−1) − 1/(s₀−1)) − (ψs−ψs₀)/2. linear_combination hsid − hs₀id + hdiff + hsplit + hnear: check: goal-LHS − goal-RHS = (logDeriv s − near(s)) − (logDeriv s₀ − near(s₀) + far − (1/s−1/s₀) − ...). Substitute: logDeriv s − logDeriv s₀ = (seriesFun s − seriesFun s₀) − (1/s − 1/s₀) − (1/(s−1) − 1/(s₀−1)) − (ψs−ψs₀)/2 [hsid − hs₀id]. Then goal becomes: (seriesFun s − seriesFun s₀) − near(s) + near(s₀) − far = 0-ish ⟸ alldiff = near-diff + far, near-diff = near(s) − near(s₀) ✓. So linear_combination hsid - hs₀id + hdiff + hsplit + hnear — need to get the signs right; linear_combination checks goal_lhs − goal_rhs − (combination of (have_lhs − have_rhs)) = 0 by ring. Let me just try `linear_combination hsid - hs₀id + hdiff + hsplit + hnear` and adjust signs at compile. Wait — but the statements: hsid : logDeriv riemannZeta s = B + seriesFun s − 1/s − 1/(s−1) + (↑(Real.log π))/2 − Complex.digamma (s/2)/2. The goal's far tsum: ∑' ρ, if ρ ∈ nearZerosSub t then 0 else m·(...) — and hsplit's form: tsum_split_finset_complex gives ∑' i, f i = ∑ i ∈ nearZerosSub t, f i + ∑' i, if i ∈ nearZerosSub t then 0 else f i ✓. One subtlety: the goal and haves must have SYNTACTICALLY matching atoms for ring: e.g. the goal's `∑ ρ ∈ nearZerosSub t, (zeroMult ρ.1 : ℂ) / (s - ρ.1)` vs hnear's RHS terms — written identically ✓. The `1 / s` forms ✓. The B from obtain ⟨B, hB⟩ — hsid/hs₀id both mention B ✓ cancels. §5: piece 1 — dirichletC2 ≤ 0.995. dirichletC2 := ∑' n, ‖LSeries.term (Λ) (2:ℂ) n‖. The term: LSeries.term f a n = f n / n^a for n ≥ 1, 0 for n = 0? LSeries.term: `LSeries.term f s n = if n = 0 then 0 else f n / n^s`. So ‖term‖ = if n=0 then 0 else Λ(n)/‖n^2‖ = Λ(n)/n² (for n ≥ 1; Λ(n) ≥ 0 real; ‖(n:ℂ)²‖ = n²). So dirichletC2 = Σ'_{n≥1} Λ(n)/n². Bound: Λ(n) ≤ log n (real): Mathlib `ArithmeticFunction.vonMangoldt_le_log : Λ n ≤ log n`? Let me check — there's `ArithmeticFunction.vonMangoldt_le_log : ∀ (n : ℕ), Λ n ≤ Real.log n`? I believe it exists (vonMangoldt_le_log). Check at build. Then the tail: Σ'_{n≥4} log n/n² ≤ ∫₃^∞ log x/x² dx = (log 3 + 1)/3. The integral: ∫ log x/x² dx = −(log x + 1)/x. Mathlib: is there `Real.integral_log_div_pow_two`? Unlikely. Prove via FTC: the antiderivative F(x) = −(log x + 1)/x has F'(x) = log x/x² for x > 0. Then ∫_{3}^{N} = F(N) − F(3) → −F(3) = (log 3+1)/3 as N → ∞ (F(N) → 0). The improper integral value + the comparison via AntitoneOn.tsum_comp_add_le_integral — its needs: AntitoneOn f (Ici N), IntegrableOn f (Ioi N), nonneg. IntegrableOn of log x/x² on Ioi 3 — from the explicit antiderivative + `intervalIntegral_tendsto_integral_Ioi`? There's machinery: `integrableOn_Ioi_of_intervalIntegral_norm_tendsto`... This is getting heavy. ALTERNATIVE cheaper bound for the tail avoiding integrals: for n ≥ 4: log n ≤ n^{0.34}·c? Hmm. log n/n² ≤ 1/n^{1.66}·(log n/n^{0.34}) — max of log n/n^{0.34} at n = e^{1/0.34} = e^{2.94} ≈ 18.9: value 2.94/18.9^{0.34}·... = (1/0.34)/e ≈ 1.0816/... hmm: max log n/n^ε = 1/(εe) at n = e^{1/ε}. ε = 0.34: 1/(0.34·e) = 1.0817. So log n/n² ≤ 1.0817/n^{1.66} — Σ_{n≥4} n^{−1.66} ≤ ∫₃^∞ x^{−1.66} = 3^{−0.66}/0.66 ≈ 0.484/0.66 = 0.733. Total tail ≤ 1.0817·0.733 = 0.793 > 0.6996 budget. Worse. ε = 0.5: max log n/√n = 2/e = 0.736; Σ n^{−1.5} from 4: ∫₃^∞ x^{−1.5} = 2/√3 = 1.155; 0.736·1.155 = 0.85 — worse. The integral route is needed for the sharp tail. Hmm — OR: take more exact head terms. Head n=2..7 exact-ish, tail Σ_{n≥8} log n/n² ≤ ∫₇^∞ log x/x² = (log 7 + 1)/7 = 0.4216. Head: log2/4 = 0.17329, log3/9 = 0.12207, log4/16 = 0.08664, log5/25 = 0.06438, log6/36 = 0.04977, log7/49 = 0.03971. Head sum = 0.53586. Total: 0.53586 + 0.4216 = 0.9575 ≤ 1.01 ✓ more room (0.05). But still needs the integral. OK the integral is unavoidable — let me look for the cleanest integral evaluation. Actually — Mathlib DOES have some: `Real.integral_...`? Search for `log.*div.*pow` in Integrals.lean at build time. Alternatively compute ∫₃^N log x/x² dx via `intervalIntegral.integral_deriv_eq_sub` with F = fun x => −(log x + 1)/x: F' = log x/x² (by deriv rules: deriv of −(log x+1)/x = −[(1/x)·x − (log x+1)]/x² = −[1 − log x − 1]/x² = log x/x² ✓). Then ∫_{Ioi 3} = lim F(N) − F(3) = 0 − (−(log 3+1)/3) = (log 3+1)/3. The Ioi integral from the interval integrals: `intervalIntegral_tendsto_integral_Ioi` (h : Tendsto F atTop (𝓝 L))-style. This is standard-but-fiddly ~80 lines. Hmm — actually, let me reconsider: is there an even cheaper majorant for dirichletC2 avoiding the tsum tail entirely? dirichletC2 = Σ Λ(n)/n² = −ζ′(2)/ζ(2). Closed form: −ζ′(2)/ζ(2) — Mathlib has ζ(2) = π²/6 (hasSum_zeta_two) but not ζ′(2). What about bounding the tsum by a geometric-ish comparison: for n ≥ 2, Λ(n) ≤ log n ≤ log 2·log₂ n... no. Alternative: use the PRIME-POWER structure: Σ_n Λ(n)/n² = Σ_p log p/(p²−1)·... = Σ_p log p·(1/p² + 1/p⁴ + ...) = Σ_p log p/(p²−1). Not easier in Lean. OR — completely different: skip the dirichletC2 numeric bound; note piece 1's budget is 1.01 and dirichletC2 = ∑' ‖term‖... can I bound dirichletC2 ≤ ζ(2)·something? Λ(n) ≤ log n ≤ (n^ε)/ε... Actually you know what — simplest robust: head to n = 2, 3 exact + the integral tail, with the integral via the explicit antiderivative. It's ~80-100 lines. That's the honest cost. Actually wait — maybe use `AntitoneOn.tsum_le_integral` with the integrable proof from... the integrability of log x/x² on Ioi 3 — Mathlib might have `integrableOn_Ioi_...`? Hmm. There IS `integrableOn_Ioi_of_intervalIntegral...`. Let me look for a slicker path: `Real.integrableOn_log_div_pow`? Unlikely to exist. OK — time/context management: the file is getting big in planning. Let me structure 5f-i to include pieces 1,2,4,5 with piece 1 possibly via the integral route, and see how far the compile gets. Actually — for THIS session's remaining budget, maybe I should scope 5f-i to §1–§4 (the identity + split + decomposition) + pieces 2, 4, 5 (pure algebra/count) and defer piece 1's integral to 5f-ii (grouping it with the other analytic pieces). That gives a clean commit tonight. Let me write LiTightR.lean with §1–§4 + §6(piece 2) + §7(pieces 4/5), and leave piece 1 (dirichletC2 bound) + pieces 3, 6 for 5f-ii. The capstone in 5f-iii. Piece 2 detail (near sum at s₀ ≤ P1-count): ```lean /-- Piece 2: the near sum at the reference point s₀ = 2 + it is bounded by the two-unit count (ZeroCountProp2), since |s₀ − ρ| ≥ 1 for every nontrivial zero. -/ theorem near_sum_refPoint_le (hZC2 : ZeroCountProp2) {t : ℝ} (ht : 10 ≤ t) : ‖∑ ρ ∈ nearZerosSub t, (zeroMult ρ.1 : ℂ) / ((2 + t * Complex.I) - ρ.1)‖ ≤ 0.6 * Real.log (t + 2) + 0.886 * Real.log (Real.log (t + 2)) + 2.7 := by -- per-term bound have hterm : ∀ ρ : {ρ : ℂ // IsNontrivialZero ρ}, ρ ∈ nearZerosSub t → ‖(zeroMult ρ.1 : ℂ) / ((2 + t * Complex.I) - ρ.1)‖ ≤ (zeroMult ρ.1 : ℝ) := by intro ρ hρ -- |s₀ − ρ| ≥ 1 have h1 : (1 : ℝ) ≤ ‖(2 + t * Complex.I) - ρ.1‖ := by have hre : ((2 + t * Complex.I) - ρ.1).re = 2 - ρ.1.re := by simp [sub_re] have h := abs_re_le_norm (((2 + t * Complex.I) - ρ.1)) rw [hre] at h -- |2 − re ρ| ≥ 1 since re ρ ≤ 1 (strictly < 1) have hρre : ρ.1.re < 1 := ρ.2.2.2 have : (1 : ℝ) ≤ |2 - ρ.1.re| := by rw [abs_of_nonneg (by linarith)]; linarith exact this.trans h rw [norm_div] have h2 : ‖(zeroMult ρ.1 : ℂ)‖ = (zeroMult ρ.1 : ℝ) := by rw [show (zeroMult ρ.1 : ℂ) = ((zeroMult ρ.1 : ℝ) : ℂ) by push_cast; ring, Complex.norm_real] exact abs_of_nonneg (Nat.cast_nonneg _) -- hmm norm_real gives |x| = x for x ≥ 0 rw [h2] exact (div_le_one (by linarith : (0:ℝ) < ‖(2 + t*I) − ρ.1‖)).mpr ... ``` hmm: ‖a/b‖ = ‖a‖/‖b‖ ≤ ‖a‖ iff ‖b‖ ≥ 1 (‖a‖ ≥ 0): div_le_iff₀: ‖a‖/‖b‖ ≤ ‖a‖ ⟺ ‖a‖ ≤ ‖a‖·‖b‖ ⟸ 1 ≤ ‖b‖ (mul_le_mul_of_nonneg_left). So: ```lean rw [norm_div, h2] calc (zeroMult ρ.1 : ℝ) / ‖(2 + t * Complex.I) - ρ.1‖ ≤ (zeroMult ρ.1 : ℝ) / 1 := div_le_div_of_nonneg_left (Nat.cast_nonneg _) (by linarith) h1 _ = (zeroMult ρ.1 : ℝ) := div_one _ ``` `div_le_div_of_nonneg_left (ha : 0 ≤ a) (hb : 0 < b) (h : b ≤ c) : a / c ≤ a / b` — signature check: div_le_div_of_nonneg_left (ha : 0 ≤ a) (hb : 0 < b) (hbc : b ≤ c) : a / c ≤ a / b. So `div_le_div_of_nonneg_left (Nat.cast_nonneg _) (by linarith [h1] : (0:ℝ) < 1) h1 : (zeroMult:ℝ)/‖..‖ ≤ (zeroMult:ℝ)/1` — wait direction: a/c ≤ a/b with b = 1 ≤ c = ‖..‖ ✓ gives (zeroMult)/‖..‖ ≤ (zeroMult)/1 ✓. Then: ```lean calc ‖∑ ρ ∈ nearZerosSub t, (zeroMult ρ.1 : ℂ) / ((2 + t * Complex.I) - ρ.1)‖ ≤ ∑ ρ ∈ nearZerosSub t, ‖(zeroMult ρ.1 : ℂ) / ((2 + t * Complex.I) - ρ.1)‖ := norm_sum_le _ _ _ ≤ ∑ ρ ∈ nearZerosSub t, (zeroMult ρ.1 : ℝ) := Finset.sum_le_sum hterm _ ≤ ((zeroAbsWindow_finite t).toFinset.sum fun ρ => zeroMult ρ : ℝ) := by -- nearZerosSub t (as a ℂ-finset) ⊆ zeroAbsWindow finset ... _ ≤ 0.6 * Real.log (t + 2) + 0.886 * Real.log (Real.log (t + 2)) + 2.7 := hZC2 t ht ``` The inclusion step: the nearZerosSub sum is over the SUBTYPE; the ZeroCountProp2 sum is over the ℂ-finset (zeroAbsWindow_finite t).toFinset. Bridge: Σ ρ ∈ nearZerosSub t, (zeroMult ρ.1 : ℝ) = Σ ρ ∈ (nearZerosSub t).image Subtype.val, (zeroMult ρ : ℝ) via Finset.sum_image (Subtype.val injective) — and the image ⊆ (zeroAbsWindow_finite t).toFinset: elements are nontrivial zeros with |im − t| < 1 ⊂ ≤ 1 ✓. Then Finset.sum_le_sum_of_subset_of_nonneg (terms ≥ 0). So: ```lean have hbridge : ∑ ρ ∈ nearZerosSub t, (zeroMult ρ.1 : ℝ) = ∑ ρ ∈ (nearZerosSub t).image (fun ρ => ρ.1), (zeroMult ρ : ℝ) := by rw [Finset.sum_image] · exact fun x _ y _ h => Subtype.ext h have hsub : (nearZerosSub t).image (fun ρ => ρ.1) ⊆ (zeroAbsWindow_finite t).toFinset := by intro ρ hρ rw [Finset.mem_image] at hρ obtain ⟨ρ', hρ'mem, hρ'eq⟩ := hρ rw [Set.Finite.mem_toFinset] -- ρ = ρ'.1, ρ' ∈ nearZerosSub t ⟹ |ρ.im − t| < 1 ⟹ ≤ 1 have hnear := (mem_nearZerosSub.mp hρ'mem) -- |ρ'.1.im − t| < 1 rw [← hρ'eq] -- ρ'.1 = ρ? hρ'eq : ρ'.1 = ρ refine ⟨ρ'.2, ?_⟩ · exact hnear.le -- |ρ'.1.im − t| ≤ 1 calc ... ``` Hmm — hρ'eq : (fun ρ => ρ.1) ρ' = ρ i.e. ρ'.1 = ρ. And zeroAbsWindow t = {ρ | IsNontrivialZero ρ ∧ |ρ.im − t| ≤ 1} — membership: ⟨ρ'.2, hnear.le⟩ with ρ'.1 = ρ — the rewriting: goal IsNontrivialZero ρ ∧ |ρ.im − t| ≤ 1; rw [← hρ'eq] changes ρ to ρ'.1 ✓ then exact ⟨ρ'.2, hnear.le⟩ ✓. Wait — `Set.Finite.mem_toFinset` for the membership in (zeroAbsWindow_finite t).toFinset: `Set.Finite.mem_toFinset (hs : s.Finite) : a ∈ hs.toFinset ↔ a ∈ s` ✓. Then `Finset.sum_le_sum_of_subset_of_nonneg hsub (fun ρ _ _ => Nat.cast_nonneg _)` : Σ image ≤ Σ window ✓. Hmm — the sum in ZeroCountProp2 is `(zeroAbsWindow_finite t).toFinset.sum fun ρ => zeroMult ρ` — a ℕ sum cast to ℝ: `(((zeroAbsWindow_finite t).toFinset.sum fun ρ => zeroMult ρ) : ℝ)`. My hbridge produces an ℝ-sum Σ (zeroMult ρ : ℝ). The cast bridge: ((Σ_{ℕ} zeroMult) : ℝ) = Σ_ℝ (zeroMult : ℝ) via Nat.cast_sum ✓ (push_cast handles). So: ```lean have hcast : (((zeroAbsWindow_finite t).toFinset.sum fun ρ => zeroMult ρ) : ℝ) = ∑ ρ ∈ (zeroAbsWindow_finite t).toFinset, (zeroMult ρ : ℝ) := by push_cast rfl -- hmm Nat.cast_sum: ↑(∑ f) = ∑ ↑f — push_cast normalizes the LHS to the RHS form rw [hcast] at hZC2t -- where hZC2t := hZC2 t ht ``` Then chain. OK. Piece 4/5: ```lean /-- Pieces 4/5: the reciprocal differences at s vs s₀ = 2 + it. -/ theorem one_div_sub_one_div_le {t : ℝ} (ht : 10 ≤ t) {s : ℂ} (hσ : -5/2 ≤ s.re ∧ s.re ≤ 3) (him : s.im = t) : ‖1 / s - 1 / (2 + t * Complex.I)‖ ≤ 0.045 ∧ ‖1 / (s - 1) - 1 / ((2 + t * Complex.I) - 1)‖ ≤ 0.045 := by ... ``` Details: 1/s − 1/s₀ = (s₀ − s)/(s·s₀): norm = |s₀−s|/(‖s‖‖s₀‖). |s₀ − s| = |2 − σ| (same t): (s₀ − s) = (2 − σ) + (t − t)i = 2 − σ: ‖s₀ − s‖ = |2 − σ| ≤ 4.5 (σ ∈ [−2.5, 3] ⟹ 2−σ ∈ [−1, 4.5] ⟹ |2−σ| ≤ 4.5). ‖s‖ ≥ |im s| = t ≥ 10 (im s = t; |im s| ≤ ‖s‖ via abs_im_le_norm... wait ‖s‖ ≥ |im s|: `Complex.abs_im_le_norm`? there's abs_re_le_norm (used in session 033) — abs_im_le_norm should exist too). ‖s₀‖ = ‖2 + tI‖ ≥ |im| = t. So norm ≤ 4.5/(t·t) ≤ 4.5/100 = 0.045. For the s−1 version: ‖s−1‖ ≥ |im(s−1)| = t (im(s−1) = im s = t); ‖s₀−1‖ = ‖1 + tI‖ ≥ t. Same bound ✓. The division identity: 1/s − 1/s₀ = (s₀ − s)/(s·s₀) — `one_div_sub_one_div` : 1/a − 1/b = (b − a)/(a·b)? There's `one_div_sub_one_div'`. Or field_simp with s ≠ 0, s₀ ≠ 0. The norms: ‖(s₀−s)/(s s₀)‖ = ‖s₀−s‖/(‖s‖‖s₀‖) (norm_div, norm_mul). Fine. Now — the assemble order. Let me also decide the exact final form of pieces to make the 5f-iii assembly smooth. But that's for later. Let me now WRITE the file with §1–§4 + piece 2 + pieces 4/5. Check `Complex.abs_im_le_norm` name... I'll use `Complex.abs_im_le_norm` — if not, `abs_im_le_norm` or via normSq. Risky names to verify: `abs_re_le_norm` (banked session-033 ✓ exists), `abs_im_le_norm` (probably exists), `Complex.norm_le_abs_re_add_abs_im` (check), `norm_sum_le` ✓ standard, `Finset.sum_image` ✓ (used before with f-pin — banked gotcha: "sum_image's f is auto-bound (pin (f := ...))" — hmm, from session 032: "sum_image's f is auto-bound (pin (f := ...))" — I'll write Finset.sum_image with the inj proof and pin if needed). `Complex.norm_le_abs_re_add_abs_im` — hmm not sure. Alternative for §2's membership: ‖ρ‖² = re² + im² (normSq) ≤ (|re|+|im|)²: ‖ρ‖ = √(re²+im²) ≤ |re|+|im| since re²+im² ≤ (|re|+|im|)² (cross term 2|re||im| ≥ 0) and sqrt monotone: `Real.sqrt_le_sqrt` + `Real.sqrt_le_left`?... Simpler: Complex.norm_le_abs_re_add_abs_im — grep at build; fallback: nlinarith with normSq: ‖ρ‖² = re²+im² ≤ (1 + (|t|+1))²: have ‖ρ‖^2 = re^2 + im^2 (Complex.norm_sq_eq... `Complex.normSq_eq_norm_sq : normSq z = ‖z‖²` ✓ banked) then (|re| + |im|)² ≥ re²+im² ⟹ ‖ρ‖ ≤ |re|+|im| via pow_le_pow_left₀-reverse (sq_le_sq₀)... `sq_le_sq₀ (norm_nonneg _) (h)`... Let me just use: ‖ρ‖ ≤ ‖ρ‖... you know what, simplest: ‖ρ‖ ≤ |re ρ| + |im ρ| — I'm fairly confident `Complex.norm_le_abs_re_add_abs_im` exists in Mathlib (Analysis/Complex/Basic.lean or .../Abs). If not: prove via nlinarith on squares. Let me check quickly before writing.
Continuing with 5f-i. Verifying the last few lemma names for the file.
tool: Bash
input
{
  "command": "M=D:/Python/Quantum/zeta-23-lean/.lake/packages/mathlib/Mathlib; grep -rn \"norm_le_abs_re_add_abs_im\\|abs_im_le_norm\" $M/Analysis/Complex/Basic.lean $M/Analysis/Complex/Abs.lean $M/Data/Complex/*.lean 2>/dev/null | head -5; grep -rn \"theorem finite_subtype_norm_lt\\|lemma finite_subtype_norm_lt\" D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1/*.lean | head -2; grep -rn \"theorem seriesSummable\" D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1/LiSeries.lean | head -2",
  "description": "Verify norm lemmas and seriesSummable signature"
}
#1726 assistant 2026-08-24 09:06:38.375 UTC · 977→11504 tok open ⤢
thinking (16452 chars)
All verified: - `Complex.abs_im_le_norm` (in Complex namespace at Norm.lean:185 — with `open Complex` it's abs_im_le_norm; but abs_re_le_norm was used unqualified in LiCircleBound — they're in the Complex namespace? Line 185 is `theorem abs_im_le_norm (z : ℂ)` inside `namespace Complex` presumably; the project used `abs_re_le_norm` unqualified with open Complex ✓ so abs_im_le_norm works the same). - `Complex.norm_le_abs_re_add_abs_im` ✓. - `finite_subtype_norm_lt (R : ℝ) : {ρ : subtype | ‖(ρ:ℂ)‖ < R}.Finite` ✓. - `seriesSummable (s : ℂ) : Summable (fun ρ : subtype => seriesTerm s ρ)` ✓. Now write the file. Pieces for 5f-i: §1 tsum_split_finset_complex §2 nearZerosSub + mem_nearZerosSub §3 diffTerm summable + seriesFun_sub_seriesFun §4 Rexpr_decomp §5 piece 2 (near_sum_refPoint_le) §6 pieces 4/5 (one_div bounds) Piece 1 (dirichletC2) deferred to 5f-ii (integral work), pieces 3, 6 likewise, assembly 5f-iii. Let me be careful with the Rexpr_decomp statement — matching atom forms exactly. I'll write the goal with the same term forms used in the proof haves. One concern in §4: the partialFraction_identity instance gives logDeriv ζ s = B + seriesFun s − 1/s − 1/(s−1) + ↑(Real.log π)/2 − ψ(s/2)/2. The hB form: hB s hs hs0 hs1 hst where the hypothesis order: (hζ : riemannZeta s ≠ 0) (hs0 : s ≠ 0) (hs1 : s ≠ 1) (hsn : ∀ n, 1 ≤ n → s ≠ −2n) ✓ matches my §4 hypotheses. The final algebra: goal: logDeriv ζ s − N(s) = logDeriv ζ s₀ − N(s₀) + FAR − (1/s − 1/s₀) − (1/(s−1) − 1/(s₀−1)) − (ψs − ψs₀)/2 where N(s) := ∑ ρ ∈ nearZerosSub t, m/(s−ρ), FAR := ∑' ρ, if ρ ∈ nearZerosSub t then 0 else m·(1/(s−ρ)−1/(s₀−ρ)). linear_combination hsid − hs₀id + hdiff + hsplit + hnear with: - hsid : logDeriv ζ s = B + seriesFun s − 1/s − 1/(s−1) + c − ψs/2 - hs₀id : logDeriv ζ s₀ = B + seriesFun s₀ − 1/s₀ − 1/(s₀−1) + c − ψs₀/2 - hdiff : seriesFun s − seriesFun s₀ = ALLDIFF (the Σ' of m·(1/(s−ρ)−1/(s₀−ρ))) - hsplit : ALLDIFF = NEARDIFF + FAR where NEARDIFF := ∑ ρ ∈ nearZerosSub t, m·(1/(s−ρ)−1/(s₀−ρ)) — from tsum_split_finset_complex hfsum (nearZerosSub t) : ∑' = ∑ + ∑'if ✓ (f := the diff term). - hnear : NEARDIFF = N(s) − N(s₀). Goal − (hsid − hs₀id + hdiff + hsplit + hnear): LHS−RHS of goal: (logDeriv s − N s) − (logDeriv s₀ − N s₀ + FAR − (1/s − 1/s₀) − (1/(s−1) − 1/(s₀−1)) − (ψs−ψs₀)/2). Minus hsid: −(B + seriesFun s − 1/s − 1/(s−1) + c − ψs/2) + logDeriv s — wait linear_combination h: goal_lhs − goal_rhs = coefficient·(h_lhs − h_rhs) must be ring-zero. Let me expand goal−[hsid − hs₀id + hdiff + hsplit + hnear]: goal(L−R) = Ls − Ns − Ls₀ + Ns₀ − FAR + (1/s − 1/s₀) + (1/(s−1) − 1/(s₀−1)) + (ψs−ψs₀)/2. hsid(L−R) = Ls − (B + Ss − 1/s − 1/(s−1) + c − ψs/2). hs₀id(L−R) = Ls₀ − (B + Ss₀ − 1/s₀ − 1/(s₀−1) + c − ψs₀/2). hdiff(L−R) = (Ss − Ss₀) − ALLDIFF. hsplit(L−R) = ALLDIFF − NEARDIFF − FAR. hnear(L−R) = NEARDIFF − (Ns − Ns₀). goal − hsid + hs₀id − hdiff − hsplit − hnear: = [Ls − Ns − Ls₀ + Ns₀ − FAR + Δ1 + Δ2 + Δψ/2] − [Ls − B − Ss + 1/s + 1/(s−1) − c + ψs/2] + [Ls₀ − B − Ss₀ + 1/s₀ + 1/(s₀−1) − c + ψs₀/2] − [Ss − Ss₀ − ALLDIFF] − [ALLDIFF − NEARDIFF − FAR] − [NEARDIFF − Ns + Ns₀] where Δ1 = (1/s − 1/s₀), Δ2 = (1/(s−1) − 1/(s₀−1)), Δψ = ψs − ψs₀. Collect Ls: 1 − 1 = 0 ✓. Ls₀: −1 + 1 = 0 ✓. Ns: −1 + 1 = 0 ✓ (last term +Ns). Ns₀: +1 − 1 = 0 ✓. FAR: −1 + 1 = 0 ✓. B: +1 − 1 = 0 ✓. Ss: +1 − 1 = 0 ✓. Ss₀: −1 + 1 = 0 ✓. ALLDIFF: +1 − 1 = 0 ✓. NEARDIFF: +1 − 1 = 0 ✓. c: +1 − 1 = 0 ✓. Constants: 1/s: from goal +1/s; from −hsid: +1/s... wait: goal has +Δ1 = +1/s − 1/s₀; −hsid contributes +1/s (since −(−1/s)... let me redo: −hsid(L−R) = −Ls + B + Ss − 1/s − 1/(s−1) + c − ψs/2. Hmm I need to be careful. Let me just trust linear_combination's ring to sort out: the remaining atoms: 1/s: goal +1, −hsid: −(−1/s)=+1/s·(−1)... Let me redo cleanly. linear_combination e computes (goal_lhs − goal_rhs) − e_expanded and checks = 0 by ring, where e = Σ cᵢ·(hᵢ_lhs − hᵢ_rhs). goal_lhs − goal_rhs = Ls − Ns − Ls₀ + Ns₀ − FAR + Δ₁ + Δ₂ + Δψ/2. hsid diff: hsid_l − hsid_r = Ls − B − Ss + (1/s) + (1/(s−1)) − c + ψs/2. hs₀id diff: Ls₀ − B − Ss₀ + (1/s₀) + (1/(s₀−1)) − c + ψs₀/2. hdiff diff: Ss − Ss₀ − ALLDIFF. hsplit diff: ALLDIFF − NEARDIFF − FAR. hnear diff: NEARDIFF − Ns + Ns₀. Try combination: goal − hsid + hs₀id − hdiff − hsplit − hnear: Ls: 1 − 1 = 0 ✓ Ns: −1 − (−1)·... hnear coeff is −1: −(− Ns) = +Ns: −1 + 1 = 0 ✓ Ls₀: −1 + 1 = 0 ✓ Ns₀: +1 + (−1)(+Ns₀) = 1 − 1 = 0 ✓ FAR: −1 + (−1)(−FAR) = −1 + 1 = 0 ✓ (hsplit coeff −1, its diff has −FAR: −(−FAR) = +FAR: −1 + 1 ✓) B: 0 − (−B) + (−B) = +B − B = 0 ✓ Ss: 0 − (−Ss) + (−1)(Ss) = Ss − Ss = 0 ✓ Ss₀: 0 + (−Ss₀) + (−1)(−Ss₀) = −Ss₀ + Ss₀ = 0 ✓ 1/s: +1 (from Δ₁) + (−1)(+1/s) = 1 − 1 = 0 ✓ 1/s₀: −1 (from Δ₁) + (+1)(+1/s₀) = −1 + 1 = 0 ✓ 1/(s−1): +1 + (−1)(+1/(s−1)) = 0 ✓ 1/(s₀−1): −1 + 1·(+1/(s₀−1)) = 0 ✓ c: 0 − (−c) + (+1)(−c) = c − c = 0 ✓ ψs: +1/2 + (−1)(ψs/2) = 0 ✓ ψs₀: −1/2 + (1)(ψs₀/2) = 0 ✓ ALLDIFF: 0 + (−1)(−ALLDIFF) + (−1)(ALLDIFF) = ALLDIFF − ALLDIFF = 0 ✓ NEARDIFF: 0 + (−1)(−NEARDIFF) + (−1)(NEARDIFF) = 0 ✓ So `linear_combination hsid - hs₀id ... ` wait my coeffs: goal − hsid + hs₀id − hdiff − hsplit − hnear — I.e., e := hsid − hs₀id + hdiff + hsplit + hnear, and linear_combination checks (goal_diff) = e_expanded... whatever the convention, `linear_combination hsid - hs₀id + hdiff + hsplit + hnear`? Hmm — I computed goal − hsid + hs₀id − hdiff − hsplit − hnear = 0, so e := hsid − hs₀id + hdiff + hsplit + hnear gives goal_diff − e_diff = 0 ✓ wait no: I computed goal − (hsid − hs₀id + hdiff + hsplit + hnear) = goal − hsid + hs₀id − hdiff − hsplit − hnear = 0 ✓. So `linear_combination hsid - hs₀id + hdiff + hsplit + hnear` — linear_combination e checks goal_diff − e = ring-zero, with e = hsid − hs₀id + hdiff + hsplit + hnear ✓. BUT — the atom matching for ring: the FAR term in the goal is `∑' ρ, if ρ ∈ nearZerosSub t then 0 else ...` and hsplit's is `∑' i, (if i ∈ nearZerosSub t then 0 else f i)` — same if the f and set match syntactically. tsum_split_finset_complex's statement: ∑' i, f i = ∑ i ∈ s, f i + ∑' i, (if i ∈ s then 0 else f i) — the if-term: `if i ∈ s then 0 else f i` with my f := fun ρ => (zeroMult ρ.1 : ℂ)·(1/(s−ρ.1) − 1/(s₀−ρ.1)). The goal's FAR must be written in EXACTLY this form for the ring atom match. I'll write the goal's FAR as `∑' ρ : {ρ : ℂ // IsNontrivialZero ρ}, if ρ ∈ nearZerosSub t then (0 : ℂ) else (zeroMult ρ.1 : ℂ) * (1 / (s - ρ.1) - 1 / (s₀ - ρ.1))`. The hsplit instance: tsum_split_finset_complex (f := fun ρ => (zeroMult ρ.1 : ℂ) * (1 / (s - ρ.1) - 1 / (s₀ - ρ.1))) hfsum (nearZerosSub t) — its if-term: `if ρ ∈ nearZerosSub t then 0 else (fun ρ => ...) ρ` — BETA REDEX! (fun ρ => ...) ρ vs the direct application — defeq but not syntactic; ring treats them as different atoms?? ring's atom matching is up to reducible defeq — a beta-redex (fun ρ => f ρ) x reduces to f x at whnf — ring should see through it (ring normalizes terms up to atomic instances... hmm, ring's atom recognition uses `ring_nf` which does reduce beta-redexes? To be safe, state hsplit via a `show` to normalize, or use `only`. The banked gotcha (session 027): "sum_add_tsum_nat_add's shifted terms are beta-redexes (state goals in redex form)" — i.e., BANKED: state the goal in the redex form to match. So in MY goal, write the FAR as the redex form? Ugly. Alternative: after obtaining hsplit, `simp only []` at it to beta-reduce? `beta_reduce`? There's `simp only []` does beta. Or `change` at hsplit. I'll handle with a `have hsplit := ... ; simp only [] at hsplit`? Hmm — cleaner: `rw` nothing; state the goal's FAR in the redex form... Actually simplest: make the diff term a DEF: ```lean def farDiffTerm (s s₀ : ℂ) (ρ : {ρ : ℂ // IsNontrivialZero ρ}) : ℂ := if ρ ∈ nearZerosSub t then 0 else ... ``` no — the membership depends on t. Let me just make the diff term a plain def WITHOUT the if, and the if applied to it: ```lean /-- The seriesFun difference term. -/ def seriesDiffTerm (s s₀ : ℂ) (ρ : {ρ : ℂ // IsNontrivialZero ρ}) : ℂ := (zeroMult ρ.1 : ℂ) * (1 / (s - ρ.1) - 1 / (s₀ - ρ.1)) ``` Then hdiff : seriesFun s − seriesFun s₀ = ∑' ρ, seriesDiffTerm s s₀ ρ; hsplit : ∑' ρ, seriesDiffTerm s s₀ ρ = ∑ ρ ∈ nearZerosSub t, seriesDiffTerm s s₀ ρ + ∑' ρ, if ρ ∈ nearZerosSub t then 0 else seriesDiffTerm s s₀ ρ — the if-else applies to the def-application (no redex: f is (seriesDiffTerm s s₀), a partial application, and (fun...) ρ = seriesDiffTerm s s₀ ρ ✓ syntactic). And the goal's FAR: ∑' ρ, if ρ ∈ nearZerosSub t then (0:ℂ) else seriesDiffTerm s s₀ ρ ✓ matches. hnear : ∑ ρ ∈ nearZerosSub t, seriesDiffTerm s s₀ ρ = N(s) − N(s₀) via sum_congr (each term: seriesDiffTerm s s₀ ρ = m/(s−ρ) − m/(s₀−ρ) by [unfold/rw seriesDiffTerm + div algebra]) + Finset.sum_sub_distrib. This def-form is robust. Let me use it. seriesFun_sub_seriesFun's congr then: seriesTerm s ρ − seriesTerm s₀ ρ = seriesDiffTerm s s₀ ρ via show+ring. Also for hsplit's Summable input: need Summable (seriesDiffTerm s s₀): from the congr with (seriesTerm s − seriesTerm s₀): Summable.congr (Summable.sub seriesSummable seriesSummable) (fun ρ => (pointwise)).symm — Summable.congr (hf : Summable f) (h : ∀ i, f i = g i) : Summable g ✓. OK. Also piece 2 and 4/5 as planned. One more check for piece 2: `norm_sum_le : ‖∑ i ∈ s, f i‖ ≤ ∑ i ∈ s, ‖f i‖` ✓ standard (`norm_sum_le (s : Finset ι) (f : ι → E)`). And the `Set.Finite.mem_toFinset` signature — from LiContour:175: `Set.Finite.mem_toFinset hfin : ρ ∈ hfin.toFinset ↔ ρ ∈ zeroWindow a` — one explicit arg ✓. For nearZerosSub mem (§2): ```lean lemma mem_nearZerosSub {t : ℝ} {ρ : {ρ : ℂ // IsNontrivialZero ρ}} : ρ ∈ nearZerosSub t ↔ |ρ.1.im - t| < 1 := by rw [nearZerosSub, Finset.mem_filter] refine ⟨fun h => h.2, fun h => ⟨?_, h⟩⟩ rw [Set.Finite.mem_toFinset] show ‖ρ.1‖ < |t| + 3 have hle : ‖ρ.1‖ ≤ |ρ.1.re| + |ρ.1.im| := Complex.norm_le_abs_re_add_abs_im _ have hre : |ρ.1.re| ≤ 1 := by have h1 : 0 < ρ.1.re := ρ.2.2.1 have h2 : ρ.1.re < 1 := ρ.2.2.2 rw [abs_le] constructor <;> linarith have him : |ρ.1.im| ≤ |t| + 1 := by calc |ρ.1.im| = |ρ.1.im - t + t| := by rw [sub_add_cancel] _ ≤ |ρ.1.im - t| + |t| := abs_add_le _ _ _ ≤ 1 + |t| := by linarith [h] _ = |t| + 1 := by ring linarith [hle, hre, him] ``` Hmm — the membership in the set-builder {ρ | ‖ρ.1‖ < |t|+3}: `Set.Finite.mem_toFinset` gives ρ ∈ toFinset ↔ ρ ∈ {ρ | ‖ρ.1‖ < |t|+3}; ρ ∈ {set-builder} is defeq to ‖ρ.1‖ < |t|+3 but needs a `show` — `show ‖(ρ : ℂ)‖ < |t| + 3` — careful: the set-builder predicate is ‖(ρ : ℂ)‖ < R where (ρ : ℂ) vs ρ.1 — same. `show ‖(ρ:ℂ)‖ < |t| + 3` should work (defeq via Set.mem_setOf_eq — deprecated in this Mathlib per warnings! "Set.mem_setOf_eq deprecated: use Set.mem_ofPred_eq" — the set-builder {ρ | p ρ} membership: `show p ρ`? The deprecation warnings suggest mem_setOf_eq exists but deprecated — usable (warnings only). For `show`: ρ ∈ {ρ : subtype | ‖ρ.1‖ < R} — the membership unfolds to the predicate by defeq? Set membership a ∈ {x | p x} is `p a` by definition (Set.mem_setOf is defeq — `rfl`-level? In Lean4 Mathlib, `a ∈ {x | p x}` is defeq to `p a` ✓ so `show ‖ρ.1‖ < |t| + 3` typechecks ✓ modulo the ρ.1 vs ↑ρ form). Also `abs_le` constructor: |x| ≤ 1 ↔ −1 ≤ x ∧ x ≤ 1: `abs_le.mpr ⟨h1, h2⟩`. My hre: from 0 < re < 1: |re| ≤ 1: abs_le: −1 ≤ re ∧ re ≤ 1 ✓ linarith both. OK — also for piece 2's hterm: ‖(zeroMult ρ.1 : ℂ) / w‖ where w = (2 + t·I) − ρ.1: need ‖w‖ ≥ 1: |re w| = |2 − re ρ| = 2 − re ρ (re ρ < 1 ⟹ 2 − re ρ > 1 > 0): |re w| = 2 − re ρ ≥ 1... abs_re_le_norm : |w.re| ≤ ‖w‖ ✓ (banked session-033: abs_re_le_norm exists). w.re: ((2 + t·I) − ρ.1).re = 2 − ρ.1.re: `sub_re` + the re of 2 + t·I: (2 : ℂ).re = 2 (Complex.ofReal_re? (2:ℂ) = ((2:ℝ):ℂ) by push_cast; or `Complex.add_re`: (2 + tI).re = 2 + 0... Let me compute: (2 + t * Complex.I).re: add_re: (2:ℂ).re + (t*I).re; (2:ℂ).re: `Complex.two_re`? hmm — (2:ℂ) is OfNat — `Complex.ofNat_re`? In practice: `simp [Complex.add_re, Complex.mul_re]` or push_cast. The robust route: `by simp [sub_re]` might not fully evaluate. Let me write: have hre : ((2 + t * Complex.I) - ρ.1).re = 2 - ρ.1.re := by simp [Complex.sub_re, Complex.add_re] — with (t*I).re = 0 (Complex.mul_re: (t·I).re = t·I.re − 0·I.im... = t·0 − 0·1 = 0; simp knows Complex.I_re : I.re = 0 ✓ and ofReal_re: (↑t).re = t ✓). simp [Complex.sub_re, Complex.add_re, Complex.mul_re] should give 2·1 − 0·... hmm the real part of t*I: t*I = (t:ℂ)·I: mul_re: (t:ℂ).re·I.re − (t:ℂ).im·I.im = t·0 − 0·1 = 0 ✓ simp with I_re, I_im, ofReal_re, ofReal_im. I'll write `by simp [Complex.sub_re, Complex.add_re]` and adjust if needed — actually simpler: `by simp` might just do it with the default simp set for re/im (Complex.ext_iff simp lemmas). Let me just compute: simp can evaluate (2 + t*I − ρ).re fully if given sub_re/add_re/mul_re/ofReal_re/ofReal_im/I_re/I_im — these are all simp lemmas ✓ plain `simp` should work. I'll use `by simp`. Piece 4/5 statement: ```lean theorem one_div_diff_le {t : ℝ} (ht : 10 ≤ t) {s : ℂ} (hσlo : -5/2 ≤ s.re) (hσhi : s.re ≤ 3) (him : s.im = t) (hs0 : s ≠ 0) : ‖1 / s - 1 / (2 + t * Complex.I)‖ ≤ 0.045 ∧ ‖1 / (s - 1) - 1 / ((2 + t * Complex.I) - 1)‖ ≤ 0.045 := by ... ``` Proof: - s₀ := 2 + t·I. ‖s₀ − s‖ = |2 − s.re| (since ims equal): s₀ − s = (2 − s.re) + (t − s.im)·I = (2 − s.re) + 0·I (him): so s₀ − s = ((2 − s.re : ℝ) : ℂ): norm = |2 − s.re| ≤ 4.5 (from −2.5 ≤ re ≤ 3: 2−re ∈ [−1, 4.5]). The cast: s₀ − s = ((2 − s.re : ℝ):ℂ): via Complex.ext_iff: re: 2 − re ✓; im: t − t = 0 ✓. Then norm of a real cast: Complex.norm_real : ‖(x:ℂ)‖ = |x| ✓. - ‖s‖ ≥ t: |im s| = |t| = t (ht ≥ 10 > 0): abs_im_le_norm: ‖s‖ ≥ |s.im| = |t| = t ✓ (rw [him]). - ‖s₀‖ ≥ t: |s₀.im| = t similarly (s₀.im = t by simp). - 1/s − 1/s₀ = (s₀ − s)/(s·s₀): `one_div_sub_one_div`? hmm — there's `one_div_sub_one_div' : 1/a − 1/b = (b − a)/(a·b)`? or field_simp. With hs0 : s ≠ 0 and hs₀0 : s₀ ≠ 0: field_simp [hs0, hs₀0] then ring: field_simp rewrites the goal 1/s − 1/s₀ = X to (s₀ − s)·... hmm field_simp on an equation with divisions: produces (s₀ − s) = X·(s·s₀)... messy. Better: `one_div_sub_one_div (ha : a ≠ 0) (hb : b ≠ 0) : 1/a − 1/b = (b − a)/(a*b)` — does this exist? I don't recall exactly; there IS `one_div_sub_one_div'`? Let me just prove via field: rw [div_sub_div _ _ hs0 hs₀0]? `div_sub_div (a b) (hc : c ≠ 0) (hd : d ≠ 0) : a/c − b/d = (a·d − c·b)/(c·d)` ✓ that's standard. So 1/s − 1/s₀ = (1·s₀ − s·1)/(s·s₀) = (s₀ − s)/(s·s₀) via div_sub_div + ring-ish (1·s₀ − s·1 = s₀ − s: by ring? as a rewrite the numerator form must match — after div_sub_div, norm: ‖(1·s₀ − s·1)/(s·s₀)‖; have : 1·s₀ − s·1 = s₀ − s := by ring; rw [this].) ✓. - Then ‖(s₀−s)/(s·s₀)‖ = ‖s₀−s‖/‖s·s₀‖ = ‖s₀−s‖/(‖s‖·‖s₀‖) ≤ 4.5/(t·t) ≤ 4.5/100 = 0.045: via div_le_div: numerator ≤ 4.5, denominator ≥ t·t ≥ 100: div_le_div (hnum : a ≤ b) (hden : c ≤ d)... the right lemma: a/c ≤ b/d... forms: div_le_div (hc : 0 ≤ c) (hab : a ≤ b) (hd : 0 < d) (hcd : c ≤ d)? hmm signature variants. `div_le_div (hc : 0 ≤ c) (hab : a ≤ b) (hd : 0 < d) (hcd : c ≤ d) : a / d ≤ b / c`? I recall `div_le_div (hac : a ≤ b) (hcd : c ≤ d) (c nonneg) (d pos)`... There are several forms; the safe one: `div_le_div_of_nonneg_left`/`div_le_div_iff`... Let me use: ‖s₀−s‖/(‖s‖‖s₀‖) ≤ 4.5/(‖s‖‖s₀‖) [div_le_div_of_nonneg_right? wait that's a/c ≤ b/c] — `div_le_div_right (hc : 0 < c) : a/c ≤ b/c ↔ a ≤ b` — hmm session-032 gotcha said "div_le_div_right does NOT exist". Use div_le_div_of_nonneg_right (h : a ≤ b) (hc : 0 ≤ c) : a/c ≤ b/c ✓ (banked exists). Then 4.5/(‖s‖‖s₀‖) ≤ 4.5/100: needs ‖s‖‖s₀‖ ≥ 100 and div_le_div_of_nonneg_left (0 ≤ 4.5) (0 < 100) (100 ≤ ‖s‖‖s₀‖) : 4.5/‖s‖‖s₀‖ ≤ 4.5/100 ✓. Then 4.5/100 = 0.045 by norm_num. ‖s‖·‖s₀‖ ≥ 100: from ‖s‖ ≥ t ≥ 10, ‖s₀‖ ≥ t: mul_le_mul (both ≥ 0): mul_le_mul (h1 : t ≤ ‖s‖)... need t ≥ 0: t ≥ 10 ✓. - For s−1: ‖s−1‖ ≥ |im(s−1)| = |s.im| = t; ‖s₀−1‖ = ‖1 + tI‖ ≥ |im| = t. Same. 0.045 — as a decimal literal in Lean ℝ: (0.045 : ℝ) — OfNat scientific — fine (they used 0.433 etc. in C0hat ✓). OK. Time to write the file. Also the far sum's eventual form for piece 3 (5f-ii): the far tsum with term (s₀−s)/((s−ρ)(s₀−ρ)) — from m·(1/(s−ρ) − 1/(s₀−ρ)) = m·(s₀−s)/((s−ρ)(s₀−ρ)): one_div_sub_one_div: 1/(s−ρ) − 1/(s₀−ρ) = (s₀−ρ − (s−ρ))/((s−ρ)(s₀−ρ)) = (s₀−s)/((s−ρ)(s₀−ρ)) ✓ (div_sub_div). For 5f-ii. Let me write the file now. I'll write §1–§6 (identity + piece 2 + pieces 4/5), defer piece 1 (dirichletC2 ≤ ...) to 5f-ii as noted in the header.
All verified. Writing LiTightR.lean with the identity + pieces 2/4/5 (piece 1's integral bound groups with the 5f-ii analytic pieces).
tool: Write
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean",
  "content": "/-\nNguyenRH1/LiTightR.lean \u2014 tier ii\u2032 sub-stage ii\u2032-5f (D-069): the tight\nR-bound from the partial-fraction identity (the reference-point method,\nD-056 \u00a72, with the D-069 honest piece-2 two-unit count).\n\n\u00a71: the \u2102 tsum split (variant of LiCircleBound's tsum_split_finset).\n\u00a72: the near-zero subtype finset `nearZerosSub` + membership.\n\u00a73: the seriesFun difference term + identity.\n\u00a74: the six-piece reference-point decomposition `Rexpr_decomp`.\n\u00a75: piece 2 \u2014 the near sum at s\u2080 = 2+it bounded by ZeroCountProp2.\n\u00a76: pieces 4/5 \u2014 the reciprocal differences \u2264 0.045.\n\nRemaining (5f-ii): piece 1 (dirichletC2 \u2264 0.995), piece 6 (the sharp\ndigamma remainder via the level-2 EM), piece 3 (the far-sum interval\nmachine). (5f-iii): the assembly + the pinch lemma + the capstone\n`logDeriv_riemannZeta_sub_nearZeros_le_tight`.\n\nArchive references: D-069 (design + Findings 1/2), D-056 \u00a72, journal-035.\n-/\nimport Mathlib\nimport NguyenRH1.LiSqueeze\n\nopen Zeta23 Complex Filter Topology\n\nnoncomputable section\n\nnamespace NguyenRH1\n\n/-! ## 1. The \u2102 tsum split -/\n\n/-- Splitting a summable complex tsum over a finset (the \u2102 variant of\nLiCircleBound's `tsum_split_finset`). -/\nlemma tsum_split_finset_complex {\u03b9 : Type*} [DecidableEq \u03b9] {f : \u03b9 \u2192 \u2102} (hf : Summable f)\n    (s : Finset \u03b9) :\n    \u2211' i, f i = \u2211 i \u2208 s, f i + \u2211' i, (if i \u2208 s then 0 else f i) := by\n  classical\n  have h1 : Summable (fun i => if i \u2208 s then f i else 0) := by\n    apply Summable.of_norm_bounded hf.norm\n    intro i\n    by_cases hi : i \u2208 s <;> simp [hi]\n  have h2 : Summable (fun i => if i \u2208 s then 0 else f i) := by\n    apply Summable.of_norm_bounded hf.norm\n    intro i\n    by_cases hi : i \u2208 s <;> simp [hi]\n  have h3 : \u2211' i, f i\n      = \u2211' i, ((if i \u2208 s then f i else 0) + (if i \u2208 s then 0 else f i)) := by\n    apply tsum_congr\n    intro i\n    by_cases hi : i \u2208 s <;> simp [hi]\n  rw [h3, Summable.tsum_add h1 h2]\n  congr 1\n  rw [tsum_eq_sum (s := s) (fun b hb => if_neg hb)]\n  exact Finset.sum_congr rfl (fun b hb => if_pos hb)\n\n/-! ## 2. The near-zero subtype finset -/\n\n/-- The near-zero subtype finset: the nontrivial zeros with |\u03b3 \u2212 t| < 1,\nas a finset of the zero subtype (the `seriesFun` index type). The\ncontaining ball: |\u03b3\u2212t| < 1 and 0 < re < 1 give \u2016\u03c1\u2016 \u2264 |re| + |im| <\n|t| + 3. -/\ndef nearZerosSub (t : \u211d) : Finset {\u03c1 : \u2102 // IsNontrivialZero \u03c1} :=\n  (finite_subtype_norm_lt (|t| + 3)).toFinset.filter fun \u03c1 => |\u03c1.1.im - t| < 1\n\nlemma mem_nearZerosSub {t : \u211d} {\u03c1 : {\u03c1 : \u2102 // IsNontrivialZero \u03c1}} :\n    \u03c1 \u2208 nearZerosSub t \u2194 |\u03c1.1.im - t| < 1 := by\n  rw [nearZerosSub, Finset.mem_filter]\n  refine \u27e8fun h => h.2, fun h => \u27e8?_, h\u27e9\u27e9\n  rw [Set.Finite.mem_toFinset]\n  show \u2016\u03c1.1\u2016 < |t| + 3\n  have hle : \u2016\u03c1.1\u2016 \u2264 |\u03c1.1.re| + |\u03c1.1.im| := Complex.norm_le_abs_re_add_abs_im _\n  have hre : |\u03c1.1.re| \u2264 1 := by\n    have h1 : 0 < \u03c1.1.re := \u03c1.2.2.1\n    have h2 : \u03c1.1.re < 1 := \u03c1.2.2.2\n    rw [abs_le]\n    constructor <;> linarith\n  have him : |\u03c1.1.im| \u2264 |t| + 1 := by\n    calc |\u03c1.1.im| = |\u03c1.1.im - t + t| := by rw [sub_add_cancel]\n      _ \u2264 |\u03c1.1.im - t| + |t| := abs_add_le _ _\n      _ \u2264 1 + |t| := by linarith [h]\n      _ = |t| + 1 := by ring\n  linarith [hle, hre, him]\n\n/-! ## 3. The seriesFun difference identity -/\n\n/-- The seriesFun difference term (a def so the tsum split matches\nsyntactically \u2014 no beta-redexes). -/\ndef seriesDiffTerm (s s\u2080 : \u2102) (\u03c1 : {\u03c1 : \u2102 // IsNontrivialZero \u03c1}) : \u2102 :=\n  (zeroMult \u03c1.1 : \u2102) * (1 / (s - \u03c1.1) - 1 / (s\u2080 - \u03c1.1))\n\n/-- The difference series is summable (the two seriesFun summabilities). -/\ntheorem seriesDiffTerm_summable (s s\u2080 : \u2102) :\n    Summable (seriesDiffTerm s s\u2080) := by\n  apply Summable.congr (Summable.sub seriesSummable seriesSummable)\n  intro \u03c1\n  show seriesTerm s \u03c1 - seriesTerm s\u2080 \u03c1 = seriesDiffTerm s s\u2080 \u03c1\n  rw [seriesDiffTerm, seriesTerm, seriesTerm]\n  ring\n\n/-- seriesFun s \u2212 seriesFun s\u2080 as the termwise difference series. -/\ntheorem seriesFun_sub_seriesFun (s s\u2080 : \u2102) :\n    seriesFun s - seriesFun s\u2080 = \u2211' \u03c1 : {\u03c1 : \u2102 // IsNontrivialZero \u03c1},\n      seriesDiffTerm s s\u2080 \u03c1 := by\n  rw [seriesFun, seriesFun, \u2190 tsum_sub seriesSummable seriesSummable]\n  refine tsum_congr fun \u03c1 => ?_\n  show seriesTerm s \u03c1 - seriesTerm s\u2080 \u03c1 = seriesDiffTerm s s\u2080 \u03c1\n  rw [seriesDiffTerm, seriesTerm, seriesTerm]\n  ring\n\n/-! ## 4. The reference-point decomposition -/\n\n/-- **The six-piece reference-point decomposition** (D-056 \u00a72, D-069 \u00a73):\nwith both s and s\u2080 good (so `partialFraction_identity` applies at both \u2014\nB cancels), the R-expression at s equals: the reference value, minus the\nnear sum at s\u2080, plus the far difference series, minus the elementary\ndifferences, minus the digamma difference. -/\ntheorem Rexpr_decomp (hZC : ZeroCountProp) {s s\u2080 : \u2102}\n    (hs : riemannZeta s \u2260 0) (hs0 : s \u2260 0) (hs1 : s \u2260 1)\n    (hst : \u2200 n : \u2115, 1 \u2264 n \u2192 s \u2260 -2 * (n : \u2102))\n    (hs\u2080 : riemannZeta s\u2080 \u2260 0) (hs\u20800 : s\u2080 \u2260 0) (hs\u20801 : s\u2080 \u2260 1)\n    (hs\u2080t : \u2200 n : \u2115, 1 \u2264 n \u2192 s\u2080 \u2260 -2 * (n : \u2102)) (t : \u211d) :\n    logDeriv riemannZeta s\n        - \u2211 \u03c1 \u2208 nearZerosSub t, (zeroMult \u03c1.1 : \u2102) / (s - \u03c1.1)\n      = logDeriv riemannZeta s\u2080\n        - \u2211 \u03c1 \u2208 nearZerosSub t, (zeroMult \u03c1.1 : \u2102) / (s\u2080 - \u03c1.1)\n        + (\u2211' \u03c1 : {\u03c1 : \u2102 // IsNontrivialZero \u03c1},\n            if \u03c1 \u2208 nearZerosSub t then (0 : \u2102) else seriesDiffTerm s s\u2080 \u03c1)\n        - (1 / s - 1 / s\u2080) - (1 / (s - 1) - 1 / (s\u2080 - 1))\n        - (Complex.digamma (s / 2) - Complex.digamma (s\u2080 / 2)) / 2 := by\n  obtain \u27e8B, hB\u27e9 := partialFraction_identity hZC\n  have hsid := hB s hs hs0 hs1 hst\n  have hs\u2080id := hB s\u2080 hs\u2080 hs\u20800 hs\u20801 hs\u2080t\n  have hdiff := seriesFun_sub_seriesFun s s\u2080\n  have hsplit := tsum_split_finset_complex (seriesDiffTerm_summable s s\u2080) (nearZerosSub t)\n  have hnear : \u2211 \u03c1 \u2208 nearZerosSub t, seriesDiffTerm s s\u2080 \u03c1\n      = \u2211 \u03c1 \u2208 nearZerosSub t, (zeroMult \u03c1.1 : \u2102) / (s - \u03c1.1)\n        - \u2211 \u03c1 \u2208 nearZerosSub t, (zeroMult \u03c1.1 : \u2102) / (s\u2080 - \u03c1.1) := by\n    rw [\u2190 Finset.sum_sub_distrib]\n    refine Finset.sum_congr rfl fun \u03c1 _ => ?_\n    rw [seriesDiffTerm, div_eq_mul_one_div, div_eq_mul_one_div]\n    ring\n  linear_combination hsid - hs\u2080id + hdiff + hsplit + hnear\n\n/-! ## 5. Piece 2: the near sum at the reference point -/\n\n/-- **Piece 2** (D-069 \u00a73, honest two-unit form): the near sum at\ns\u2080 = 2 + it is bounded by the ZeroCountProp2 count, since\n|s\u2080 \u2212 \u03c1| \u2265 2 \u2212 re \u03c1 \u2265 1 for every nontrivial zero. -/\ntheorem near_sum_refPoint_le (hZC2 : ZeroCountProp2) {t : \u211d} (ht : 10 \u2264 t) :\n    \u2016\u2211 \u03c1 \u2208 nearZerosSub t, (zeroMult \u03c1.1 : \u2102) / ((2 + t * Complex.I) - \u03c1.1)\u2016\n      \u2264 0.6 * Real.log (t + 2) + 0.886 * Real.log (Real.log (t + 2)) + 2.7 := by\n  classical\n  have hterm : \u2200 \u03c1 : {\u03c1 : \u2102 // IsNontrivialZero \u03c1}, \u03c1 \u2208 nearZerosSub t \u2192\n      \u2016(zeroMult \u03c1.1 : \u2102) / ((2 + t * Complex.I) - \u03c1.1)\u2016 \u2264 (zeroMult \u03c1.1 : \u211d) := by\n    intro \u03c1 _\n    have h\u03c1re : \u03c1.1.re < 1 := \u03c1.2.2.2\n    have h1 : (1 : \u211d) \u2264 \u2016(2 + t * Complex.I) - \u03c1.1\u2016 := by\n      have hre : ((2 + t * Complex.I) - \u03c1.1).re = 2 - \u03c1.1.re := by simp\n      have h := abs_re_le_norm ((2 + t * Complex.I) - \u03c1.1)\n      rw [hre] at h\n      have h2 : (1 : \u211d) \u2264 |2 - \u03c1.1.re| := by\n        rw [abs_of_nonneg (by linarith)]\n        linarith\n      exact h2.trans h\n    rw [norm_div]\n    have h2 : \u2016(zeroMult \u03c1.1 : \u2102)\u2016 = (zeroMult \u03c1.1 : \u211d) := by\n      rw [show (zeroMult \u03c1.1 : \u2102) = ((zeroMult \u03c1.1 : \u211d) : \u2102) by push_cast; ring,\n        Complex.norm_real]\n      exact abs_of_nonneg (Nat.cast_nonneg _)\n    rw [h2]\n    calc (zeroMult \u03c1.1 : \u211d) / \u2016(2 + t * Complex.I) - \u03c1.1\u2016\n        \u2264 (zeroMult \u03c1.1 : \u211d) / 1 :=\n          div_le_div_of_nonneg_left (Nat.cast_nonneg _)\n            (by norm_num : (0 : \u211d) < 1) h1\n      _ = (zeroMult \u03c1.1 : \u211d) := div_one _\n  have hbridge : \u2211 \u03c1 \u2208 nearZerosSub t, (zeroMult \u03c1.1 : \u211d)\n      = \u2211 \u03c1 \u2208 (nearZerosSub t).image (fun \u03c1 => \u03c1.1), (zeroMult \u03c1 : \u211d) := by\n    rw [Finset.sum_image (fun x _ y _ h => Subtype.ext h)]\n  have hsub : (nearZerosSub t).image (fun \u03c1 => \u03c1.1)\n      \u2286 (zeroAbsWindow_finite t).toFinset := by\n    intro \u03c1 h\u03c1\n    rw [Finset.mem_image] at h\u03c1\n    obtain \u27e8\u03c1', h\u03c1'mem, h\u03c1'eq\u27e9 := h\u03c1\n    have hnear := mem_nearZerosSub.mp h\u03c1'mem\n    rw [Set.Finite.mem_toFinset]\n    show IsNontrivialZero \u03c1 \u2227 |\u03c1.im - t| \u2264 1\n    rw [\u2190 h\u03c1'eq]\n    exact \u27e8\u03c1'.2, hnear.le\u27e9\n  calc \u2016\u2211 \u03c1 \u2208 nearZerosSub t, (zeroMult \u03c1.1 : \u2102) / ((2 + t * Complex.I) - \u03c1.1)\u2016\n      \u2264 \u2211 \u03c1 \u2208 nearZerosSub t, \u2016(zeroMult \u03c1.1 : \u2102) / ((2 + t * Complex.I) - \u03c1.1)\u2016 :=\n        norm_sum_le _ _\n    _ \u2264 \u2211 \u03c1 \u2208 nearZerosSub t, (zeroMult \u03c1.1 : \u211d) := Finset.sum_le_sum hterm\n    _ = \u2211 \u03c1 \u2208 (nearZerosSub t).image (fun \u03c1 => \u03c1.1), (zeroMult \u03c1 : \u211d) := hbridge\n    _ \u2264 \u2211 \u03c1 \u2208 (zeroAbsWindow_finite t).toFinset, (zeroMult \u03c1 : \u211d) :=\n        Finset.sum_le_sum_of_subset_of_nonneg hsub (fun \u03c1 _ _ => Nat.cast_nonneg _)\n    _ = (((zeroAbsWindow_finite t).toFinset.sum fun \u03c1 => zeroMult \u03c1) : \u211d) := by\n        push_cast\n        rfl\n    _ \u2264 0.6 * Real.log (t + 2) + 0.886 * Real.log (Real.log (t + 2)) + 2.7 :=\n        hZC2 t ht\n\n/-! ## 6. Pieces 4/5: the reciprocal differences -/\n\n/-- **Pieces 4/5** (D-056 \u00a72): the elementary reciprocal differences,\neach \u2264 4.5/|t|\u00b2 \u2264 0.045 (|s\u2080 \u2212 s| = |2 \u2212 \u03c3| \u2264 4.5; \u2016s\u2016, \u2016s\u2080\u2016 \u2265 t). -/\ntheorem one_div_diff_le {t : \u211d} (ht : 10 \u2264 t) {s : \u2102}\n    (h\u03c3lo : -5 / 2 \u2264 s.re) (h\u03c3hi : s.re \u2264 3) (him : s.im = t) (hs0 : s \u2260 0) :\n    \u20161 / s - 1 / (2 + t * Complex.I)\u2016 \u2264 0.045 \u2227\n      \u20161 / (s - 1) - 1 / ((2 + t * Complex.I) - 1)\u2016 \u2264 0.045 := by\n  have ht0 : (0 : \u211d) < t := by linarith\n  -- the difference s\u2080 \u2212 s is the real (2 \u2212 s.re)\n  have hdiff : (2 + t * Complex.I) - s = ((2 - s.re : \u211d) : \u2102) := by\n    rw [\u2190 Complex.ext_iff]\n    constructor\n    \u00b7 simp\n    \u00b7 simp [him]\n  have hsdiff : \u2016(2 + t * Complex.I) - s\u2016 = |2 - s.re| := by\n    rw [hdiff]\n    exact Complex.norm_real _\n  have hsdiffle : \u2016(2 + t * Complex.I) - s\u2016 \u2264 4.5 := by\n    rw [hsdiff, abs_le]\n    constructor <;> linarith\n  have hs_norm : (t : \u211d) \u2264 \u2016s\u2016 := by\n    have h := abs_im_le_norm s\n    rw [him, abs_of_nonneg ht0.le] at h\n    exact h\n  have hs0_norm : (t : \u211d) \u2264 \u20162 + t * Complex.I\u2016 := by\n    have h := abs_im_le_norm (2 + t * Complex.I)\n    rw [show (2 + t * Complex.I).im = t by simp, abs_of_nonneg ht0.le] at h\n    exact h\n  have hsm1_norm : (t : \u211d) \u2264 \u2016s - 1\u2016 := by\n    have h := abs_im_le_norm (s - 1)\n    rw [show (s - 1).im = t by simp [him], abs_of_nonneg ht0.le] at h\n    exact h\n  have hs0m1_norm : (t : \u211d) \u2264 \u2016(2 + t * Complex.I) - 1\u2016 := by\n    have h := abs_im_le_norm ((2 + t * Complex.I) - 1)\n    rw [show ((2 + t * Complex.I) - 1).im = t by simp, abs_of_nonneg ht0.le] at h\n    exact h\n  have hprods : (100 : \u211d) \u2264 \u2016s\u2016 * \u20162 + t * Complex.I\u2016 := by\n    have h1 := mul_le_mul hs_norm hs0_norm ht0.le (by positivity : (0 : \u211d) \u2264 \u2016s\u2016)\n    nlinarith [h1, ht]\n  have hprods1 : (100 : \u211d) \u2264 \u2016s - 1\u2016 * \u2016(2 + t * Complex.I) - 1\u2016 := by\n    have h1 := mul_le_mul hsm1_norm hs0m1_norm ht0.le (by positivity : (0 : \u211d) \u2264 \u2016s - 1\u2016)\n    nlinarith [h1, ht]\n  constructor\n  \u00b7 -- 1/s \u2212 1/s\u2080\n    have hs\u20800 : (2 + t * Complex.I) \u2260 0 := by\n      intro h\n      have : (2 + t * Complex.I).re = 0 := by rw [h]; simp\n      simp at this\n    rw [div_sub_div _ _ hs0 hs\u20800]\n    have hnum : 1 * (2 + t * Complex.I) - s * 1 = (2 + t * Complex.I) - s := by ring\n    rw [hnum, norm_div, norm_mul]\n    calc \u2016(2 + t * Complex.I) - s\u2016 / (\u2016s\u2016 * \u20162 + t * Complex.I\u2016)\n        \u2264 4.5 / (\u2016s\u2016 * \u20162 + t * Complex.I\u2016) :=\n          div_le_div_of_nonneg_right hsdiffle (by positivity)\n      _ \u2264 4.5 / 100 := div_le_div_of_nonneg_left (by norm_num) (by norm_num) hprods\n      _ = 0.045 := by norm_num\n  \u00b7 -- 1/(s\u22121) \u2212 1/(s\u2080\u22121)\n    have hs1 : s - 1 \u2260 0 := by\n      intro h\n      have : (s - 1).im = 0 := by rw [h]; simp\n      rw [show (s - 1).im = t by simp [him]] at this\n      linarith\n    have hs\u20801 : (2 + t * Complex.I) - 1 \u2260 0 := by\n      intro h\n      have : ((2 + t * Complex.I) - 1).re = 0 := by rw [h]; simp\n      simp at this\n    rw [div_sub_div _ _ hs1 hs\u20801]\n    have hnum : 1 * ((2 + t * Complex.I) - 1) - (s - 1) * 1\n        = (2 + t * Complex.I) - s := by ring\n    rw [hnum, norm_div, norm_mul]\n    calc \u2016(2 + t * Complex.I) - s\u2016 / (\u2016s - 1\u2016 * \u2016(2 + t * Complex.I) - 1\u2016)\n        \u2264 4.5 / (\u2016s - 1\u2016 * \u2016(2 + t * Complex.I) - 1\u2016) :=\n          div_le_div_of_nonneg_right hsdiffle (by positivity)\n      _ \u2264 4.5 / 100 := div_le_div_of_nonneg_left (by norm_num) (by norm_num) hprods1\n      _ = 0.045 := by norm_num\n\nend NguyenRH1\n\nend\n"
}
#1727 assistant 2026-08-24 09:12:44.105 UTC · 926→3630 tok open ⤢
thinking (9522 chars)
Five errors: 1. **Line 93 (seriesDiffTerm_summable)**: `Summable.sub seriesSummable` — seriesSummable takes explicit (s : ℂ). Fix: `Summable.sub (seriesSummable s) (seriesSummable s₀)`. 2. **Line 103**: `tsum_sub` unknown identifier. In this Mathlib it's `Summable.tsum_sub`. Fix: `← (seriesSummable s).tsum_sub (seriesSummable s₀)`. 3. **Line 102 unsolved goals** — consequence of the tsum_sub failure. 4. **Line 212**: `rw [← Complex.ext_iff]` — Complex.ext_iff is an iff (a = b ↔ re = re ∧ im = im), not an equation — can't rw with ← on an iff to turn an equality goal into the conjunction... Actually `rw [← Complex.ext_iff]` should work if Complex.ext_iff is `a = b ↔ ...`: rw [← iff] turns the conjunction INTO the equality — but my goal IS the equality, so I need `rw [Complex.ext_iff]` (forward: equality → conjunction). The error says it didn't find the pattern `re _ = re _ ∧ im _ = im _` — because rw [← h] looks for the RHS pattern... wait: rw [← Complex.ext_iff] rewrites occurrences of the RHS of the iff with the LHS: the RHS of Complex.ext_iff is `a.re = b.re ∧ a.im = b.im` — that's the "pattern" it searched for and didn't find, because the goal is the equality `2 + t*I − s = ↑(2−s.re)`. So I need the FORWARD direction: `rw [Complex.ext_iff]` turns the equality goal into the conjunction ✓. (I had it backwards.) 5. **Line 264** (hs₀1 in piece 5): `((2 + t*I) − 1).re = 0` after rw [h]: the simp at this gave `2 − 1 = 0`?? and then stuck — no wait, the error: `this : 2 - 1 = 0 ⊢ False` — the `simp at this` simplified ((2 + t*I) − 1).re to `2 − 1`?? Hmm — that means `.re` of (2 + t*I − 1) = 2 − 1 = 1 ≠ 0 — the simp reduced to `2 − 1 = 0` which is FALSE — simp should have closed it via norm_num... `simp at this` turned this : ((2+t*I)−1).re = 0 into `2 − 1 = 0` but didn't CLOSE it (simp doesn't do norm_num). Then goal False with this : 2 − 1 = 0 — need norm_num at this. Fix: `norm_num at this` — wait `this : 2 − 1 = 0` — `norm_num at this` closes any goal from a false numeric hypothesis ✓. Actually the pattern used in LiContour:204: `simp only [Complex.one_re] at hs; norm_num at hs`. Let me fix both hs₀1 and hs₀0 with that pattern: ```lean have hs₀0 : (2 + t * Complex.I) ≠ 0 := by intro h have : (2 + t * Complex.I).re = 0 := by rw [h]; simp simp at this -- reduces to a false numeric/norm equation ``` Hmm — what does `simp at this` produce for (2 + t*I).re = 0? It should give (2:ℝ) = 0 (i.e., False) directly — actually simp should reduce (2 + t*I).re to 2 and then `OfNat.ofNat = 0` is closed by simp (OfNat.ofNat_ne_zero)? Apparently at line 264 the simp produced `2 − 1 = 0` without closing. For (2 + t*I).re: simp gives `(2:ℝ) = 0` which simp should refute... it did `simp at this` leaving unsolved? The error at 264 was in hs₀1 (the second one), showing `this : 2 - 1 = 0 ⊢ False`. So simp reduced but didn't close. Fix: use `norm_num at this` after. Let me rewrite those two haves robustly: ```lean have hs₀0 : (2 + t * Complex.I) ≠ 0 := by intro h have hre : (2 + t * Complex.I).re = 0 := by rw [h]; simp simp at hre ``` If `simp at hre` reduces (2 + t*I).re = 0 to `2 = 0`-ish, simp might close it (OfNat.ne_zero is a simp lemma? `(2:ℝ) ≠ 0` is closed by norm_num not simp necessarily). Safest: ```lean have hs₀0 : (2 + t * Complex.I) ≠ 0 := by intro h have hre : (2 + t * Complex.I).re = 0 := by rw [h]; simp simp only [Complex.add_re, Complex.ofReal_re, Complex.I_re, Complex.mul_re, Complex.I_im, Complex.ofReal_im, mul_zero, sub_zero, mul_one, zero_mul] at hre -- hre : 2 = 0 norm_num at hre ``` Hmm — getting heavy. Alternative cleaner: use the norm: ‖2 + t·I‖ ≥ t ≥ 10 > 0 so ≠ 0: ```lean have hs₀0 : (2 + t * Complex.I) ≠ 0 := by intro h rw [h] at hs0_norm -- hs0_norm : t ≤ ‖(0:ℂ)‖ = 0 rw [norm_zero] at hs0_norm linarith ``` But hs0_norm is defined before these haves ✓ (it's in scope — defined earlier in the proof). Wait order: hs0_norm is defined before hprods; hs₀0 is inside the first constructor bullet after hprods — in scope ✓. And for hs₀1 (s₀ − 1 ≠ 0): use hs0m1_norm : t ≤ ‖s₀ − 1‖: rw [h] at it, norm_zero, linarith ✓. And hs1 (s − 1 ≠ 0): hsm1_norm ✓ same pattern. Let me rewrite all three with the norm route — cleaner. Also line 196: 'push_cast' does nothing warning — in the hcast step: `_ = (((zeroAbsWindow_finite t).toFinset.sum fun ρ => zeroMult ρ) : ℝ) := by push_cast; rfl` — the push_cast does nothing because... the goal after calc's `_ ≤ ... = ...` step: `∑ ρ ∈ ..., (zeroMult ρ : ℝ) = ((....sum fun ρ => zeroMult ρ : ℕ) : ℝ)`: push_cast on the goal — the RHS has the cast of a ℕ-sum; push_cast rewrites casts — Nat.cast_sum : ↑(∑ f) = ∑ ↑f — push_cast should push the outer cast inward: ↑(Σ zeroMult) → Σ (↑(zeroMult ρ)) = Σ (zeroMult ρ : ℝ)... The warning says it did nothing — maybe because the LHS/RHS need the sum's coercion shape... The issue: `Finset.sum` in the def ZeroCountProp2 is `(zeroAbsWindow_finite t).toFinset.sum (fun ρ => zeroMult ρ)` — a ℕ-valued sum, cast to ℝ. My hcast goal: `(∑ ρ ∈ toFinset, ((zeroMult ρ : ℕ) : ℝ)) = ((toFinset.sum fun ρ => zeroMult ρ : ℕ) : ℝ)`? Hmm — the calc step `_ = (((zeroAbsWindow_finite t).toFinset.sum fun ρ => zeroMult ρ) : ℝ) := by push_cast; rfl`: the goal is `∑ ρ ∈ X, (↑(zeroMult ρ) : ℝ) = ↑(X.sum fun ρ => zeroMult ρ)` — push_cast should turn RHS into LHS form... "does nothing" — maybe because Nat.cast_sum isn't a push_cast lemma in the right direction, or the sum forms differ (the fun ρ => zeroMult ρ vs the ∘). The `rfl` then fails? No — the build didn't report an rfl failure at that step... it reported the warning only. Wait — did the calc step succeed? The errors list only 93, 103, 102, 212, 264. Line 196 was just a warning. So `push_cast; rfl` worked (rfl after push_cast — but push_cast "does nothing"... if push_cast did nothing and rfl closed it, then the two sides were already rfl-equal: ∑ ρ ∈ X, (↑(zeroMult ρ)) ≡ ↑(X.sum (fun ρ => zeroMult ρ)) — these are NOT defeq in general (Nat.cast_sum is a lemma)... unless the LHS `∑ ρ ∈ X, (zeroMult ρ : ℝ)` IS displayed as `↑(X.sum ...)`? Hmm — the `(zeroMult ρ : ℝ)` I wrote is `(zeroMult ρ : ℂ → ℕ)` coerced — in my calc step `_ ≤ ∑ ρ ∈ (zeroAbsWindow_finite t).toFinset, (zeroMult ρ : ℝ)` — and then `_ = ((... .sum fun ρ => zeroMult ρ) : ℝ)` — the push_cast warning means the goal already had the pushed form and rfl closed it? Confusing but it PASSED (warning only). To silence: replace `push_cast; rfl` with just the appropriate: actually the goal `∑ ρ ∈ X, (↑(zeroMult ρ)) = ↑(X.sum fun ρ => zeroMult ρ)` — `exact (Nat.cast_sum X (fun ρ => zeroMult ρ)).symm`. Nat.cast_sum : ↑(∑ i ∈ s, f i) = ∑ i ∈ s, ↑(f i) — hmm my LHS is `∑ ρ ∈ X, ↑(zeroMult ρ)` and RHS `↑(X.sum fun ρ => zeroMult ρ)` = `↑(∑ ρ ∈ X, zeroMult ρ)`. So goal LHS = ↑(zeroMult ρ)-sum, RHS = ↑(Σ zeroMult): goal is Nat.cast_sum.symm? Nat.cast_sum : ↑(∑ i ∈ s, f i) = ∑ i ∈ s, ↑(f i): so RHS = LHS by Nat.cast_sum — goal LHS = RHS ⟸ Nat.cast_sum.symm? Nat.cast_sum gives ↑(Σ f) = Σ ↑f i.e. RHS = LHS: .symm : LHS = RHS ✓. `exact (Nat.cast_sum _ _).symm`. Cleaner. Hmm but wait — the exact form of Nat.cast_sum: `Nat.cast_sum (s : Finset ι) (f : ι → ℕ) : ↑(∑ x ∈ s, f x) = ∑ x ∈ s, ↑(f x)` ✓. Let me use that (or leave push_cast;rfl since it worked — but the warning is noise; the audit wants zero warnings. Replace with exact Nat.cast_sum.symm). Hmm wait — actually the warning was "push_cast tactic does nothing" — if push_cast did nothing, then rfl closed the goal, meaning the sides were syntactically equal already?? `∑ ρ ∈ X, (↑(zeroMult ρ))` vs `↑(X.sum fun ρ => zeroMult ρ)`... X.sum f = ∑ ρ ∈ X, f ρ (Finset.sum_eq... the `.sum` vs `∑ ρ ∈ X,`: Finset.sum X f IS ∑ x ∈ X, f x definitionally (Finset.sum is the primitive; the ∑ notation IS Finset.sum). So RHS = ↑(Finset.sum X (fun ρ => zeroMult ρ)) and LHS = Finset.sum X (fun ρ => ↑(zeroMult ρ)) — these differ (cast inside vs outside) — NOT defeq. But rfl closed it?? Unless push_cast DID work but on the "motive" — ugh. Whatever — replace with exact (Nat.cast_sum _ _).symm and move on. Actually — hold on, maybe push_cast normalized the RHS ↑(Σ zeroMult) to Σ ↑(zeroMult ρ) silently and then warned "does nothing" spuriously... no. Let me just replace and rebuild — the compiler will tell me. Also check line 93's fix and the Summable.sub form: `Summable.sub (hf : Summable f) (hg : Summable g) : Summable (f − g)` — the Pi.sub application: (seriesTerm s − seriesTerm s₀) ρ = seriesTerm s ρ − seriesTerm s₀ ρ — the Summable.congr target: I want Summable (seriesDiffTerm s s₀) from Summable (fun ρ => seriesTerm s ρ − seriesTerm s₀ ρ): Summable.sub gives Summable (seriesTerm s − seriesTerm s₀) — the function (seriesTerm s − seriesTerm s₀) vs (fun ρ => seriesTerm s ρ − seriesTerm s₀ ρ) — Pi.sub_apply defeq ✓ congr's h : ∀ ρ, (seriesTerm s − seriesTerm s₀) ρ = seriesDiffTerm s s₀ ρ — (seriesTerm s − seriesTerm s₀) ρ reduces to seriesTerm s ρ − seriesTerm s₀ ρ (Pi.sub_apply — defeq ✓) so my `show seriesTerm s ρ − seriesTerm s₀ ρ = seriesDiffTerm s s₀ ρ` is defeq to the congr obligation ✓. For line 103: `← tsum_sub` → `← (seriesSummable s).tsum_sub (seriesSummable s₀)`: tsum_sub (hf : Summable f) (hg : Summable g) : ∑' (f − g) = ∑' f − ∑' g. So ← direction: ∑' f − ∑' g = ∑' (f − g) ✓. Then the goal: ∑' ρ, (seriesTerm s − seriesTerm s₀) ρ = ∑' ρ, seriesDiffTerm s s₀ ρ — tsum_congr with the pointwise (Pi.sub_apply defeq to my show ✓). Let me apply all fixes.
Five fixable errors: `seriesSummable` needs its argument, `tsum_sub` is `Summable.tsum_sub`, `Complex.ext_iff` direction, the `≠ 0` proofs via norms, and the cast step. Fixing.
tool: Edit
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean",
  "old_string": "theorem seriesDiffTerm_summable (s s\u2080 : \u2102) :\n    Summable (seriesDiffTerm s s\u2080) := by\n  apply Summable.congr (Summable.sub seriesSummable seriesSummable)\n  intro \u03c1\n  show seriesTerm s \u03c1 - seriesTerm s\u2080 \u03c1 = seriesDiffTerm s s\u2080 \u03c1\n  rw [seriesDiffTerm, seriesTerm, seriesTerm]\n  ring\n\n/-- seriesFun s \u2212 seriesFun s\u2080 as the termwise difference series. -/\ntheorem seriesFun_sub_seriesFun (s s\u2080 : \u2102) :\n    seriesFun s - seriesFun s\u2080 = \u2211' \u03c1 : {\u03c1 : \u2102 // IsNontrivialZero \u03c1},\n      seriesDiffTerm s s\u2080 \u03c1 := by\n  rw [seriesFun, seriesFun, \u2190 tsum_sub seriesSummable seriesSummable]\n  refine tsum_congr fun \u03c1 => ?_\n  show seriesTerm s \u03c1 - seriesTerm s\u2080 \u03c1 = seriesDiffTerm s s\u2080 \u03c1\n  rw [seriesDiffTerm, seriesTerm, seriesTerm]\n  ring",
  "new_string": "theorem seriesDiffTerm_summable (s s\u2080 : \u2102) :\n    Summable (seriesDiffTerm s s\u2080) := by\n  apply Summable.congr ((seriesSummable s).sub (seriesSummable s\u2080))\n  intro \u03c1\n  show seriesTerm s \u03c1 - seriesTerm s\u2080 \u03c1 = seriesDiffTerm s s\u2080 \u03c1\n  rw [seriesDiffTerm, seriesTerm, seriesTerm]\n  ring\n\n/-- seriesFun s \u2212 seriesFun s\u2080 as the termwise difference series. -/\ntheorem seriesFun_sub_seriesFun (s s\u2080 : \u2102) :\n    seriesFun s - seriesFun s\u2080 = \u2211' \u03c1 : {\u03c1 : \u2102 // IsNontrivialZero \u03c1},\n      seriesDiffTerm s s\u2080 \u03c1 := by\n  rw [seriesFun, seriesFun, \u2190 (seriesSummable s).tsum_sub (seriesSummable s\u2080)]\n  refine tsum_congr fun \u03c1 => ?_\n  show seriesTerm s \u03c1 - seriesTerm s\u2080 \u03c1 = seriesDiffTerm s s\u2080 \u03c1\n  rw [seriesDiffTerm, seriesTerm, seriesTerm]\n  ring"
}
#1728 assistant 2026-08-24 09:15:54.527 UTC · 362→543 tok open ⤢
thinking (1192 chars)
The mismatch: the goal's RHS `(((zeroAbsWindow_finite t).toFinset.sum fun ρ => zeroMult ρ) : ℝ)` — note the `.sum` form vs the `∑ x ∈ s` form — they're the same thing, but the error shows the expected type as `∑ ρ ∈ ⋯.toFinset, ↑(zeroMult ρ) = ∑ ρ ∈ ⋯.toFinset, ↑(zeroMult ρ)` — WAIT: the expected RHS shows `∑ ρ ∈ ⋯.toFinset, ↑(zeroMult ρ)` — a sum of CASTS! So the RHS in the goal is NOT the cast-of-sum — it got elaborated as a sum of real casts! That means in ZeroCountProp2's def, `(((zeroAbsWindow_finite t).toFinset.sum fun ρ => zeroMult ρ) : ℝ)` elaborated as... the banked gotcha from this session's journal: "The ascription ((finset.sum f : ℕ) : ℝ) elaborates to a REAL sum of per-term casts (expected-type propagation)". So the def's sum is ACTUALLY a real-valued sum of casts, not a cast of a nat sum! That's exactly the gotcha I banked — and I wrote the ZeroCountProp2 def with the same ascription pattern, so it also has the real-sum-of-casts form. So the goal here is `∑ ρ ∈ X, ↑(zeroMult ρ) = ∑ ρ ∈ X, ↑(zeroMult ρ)` — closed by `rfl`! The original `push_cast; rfl` had push_cast do nothing (because already in cast-sum form) and rfl closed it. Let me revert to plain `rfl`.
The def's ascription already elaborates to a real sum of casts (the banked gotcha) — the step is just `rfl`.
tool: Edit
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean",
  "old_string": "    _ = (((zeroAbsWindow_finite t).toFinset.sum fun \u03c1 => zeroMult \u03c1) : \u211d) :=\n        (Nat.cast_sum _ _).symm",
  "new_string": "    _ = (((zeroAbsWindow_finite t).toFinset.sum fun \u03c1 => zeroMult \u03c1) : \u211d) := rfl"
}
#1729 assistant 2026-08-24 09:16:50.186 UTC · 365→177 tok open ⤢
thinking (116 chars)
Clean compile (no output = no errors/warnings). Now build via lake to get the olean, then commit this 5f-i progress.
Clean elaboration. Building and committing the 5f-i milestone.
tool: Bash
input
{
  "command": "cd D:/Python/Quantum/research/lean/NguyenRH1 && export PATH=\"$HOME/.elan/bin:$PATH\" && lake build NguyenRH1.LiTightR 2>&1 | tail -3",
  "description": "Build LiTightR olean",
  "timeout": 600000
}
#1730 assistant 2026-08-24 09:18:19.753 UTC · 874→976 tok open ⤢
thinking (2087 chars)
Committed. Now continue with piece 1 (dirichletC2 ≤ 0.995) — the integral bound. This is the remaining elementary piece; pieces 3, 6 go to 5f-ii. Piece 1 plan: ```lean theorem dirichletC2_le : dirichletC2 ≤ 0.995 ``` dirichletC2 := ∑' n, ‖LSeries.term (Λ) (2:ℂ) n‖. Step A: rewrite the term norm: for n ≥ 1, ‖LSeries.term Λ 2 n‖ = Λ(n)/n² (real); for n = 0: LSeries.term f s 0 = 0 (if n = 0 → 0). So dirichletC2 = ∑' n : ℕ, (if n = 0 then 0 else (Λ(n))/n²). LSeries.term def: `LSeries.term (f : ℕ → ℂ) (s : ℂ) (n : ℕ) : ℂ = f n / n ^ s`? with 0 for n=0? Let me check: LSeries.term f s n := if n = 0 then 0 else f n / n ^ s — I believe there's a `LSeries.term_of_ne_zero`/`LSeries.term_of_pos`. Let me check the def. Step B: bound Λ(n) ≤ log n: `ArithmeticFunction.vonMangoldt_le_log : Λ n ≤ log n`? Check name — I recall `ArithmeticFunction.vonMangoldt_le_log (n : ℕ) : Λ n ≤ Real.log n`? Hmm — might be `vonMangoldt_le_log` in Mathlib/NumberTheory/VonMangoldt.lean. My earlier grep of VonMangoldt.lean for "vonMangoldt_le_log\|vonMangoldt_le" returned nothing (the file may be named differently). Let me search. Step C: the tsum bound: ∑' n, (if n = 0 then 0 else log n / n²) ≤ 0.995. Route: tsum_eq_sum over {0,1,2,3} head + tail via AntitoneOn.tsum_comp_add_le_integral... The head terms: n=0: 0; n=1: log 1/1 = 0; n=2: log 2/4; n=3: log 3/9. Tail: Σ_{n≥4} log n/n² ≤ ∫₃^∞ log x/x² = (log 3+1)/3. Hmm — the AntitoneOn.tsum_le_integral family: `AntitoneOn.tsum_le_integral (anti : AntitoneOn f (Ici 0)) (integrable : IntegrableOn f (Ioi 0)) (nonneg) : ∑' n, f n ≤ f 0 + ∫ Ioi 0` — the integrability requirement (Ioi 0) is global — for f = log x/x² on Ici 3 only. The `tsum_comp_add_le_integral` variant: ∑' n, f (n + N) ≤ ∫ Ioi N — with anti/integrable on Ioi N... Let me read the exact signature of tsum_comp_add_le_integral. Actually — maybe simpler: the comparison via a CRUDE per-term bound that's still summable and computable: for n ≥ 4, log n ≤ n^{1/2}·(2/e)?? — computed before as lossy. The integral route is needed. Let me read the tsum_comp_add_le_integral signature.
Piece 1 (dirichletC2 ≤ 0.995) next. Checking the integral-comparison signature and the vonMangoldt bound.
tool: Bash
input
{
  "command": "M=D:/Python/Quantum/zeta-23-lean/.lake/packages/mathlib/Mathlib; sed -n '215,235p' $M/Analysis/SumIntegralComparisons.lean; echo ===VM===; grep -rn \"vonMangoldt_le_log\\|vonMangoldt_nonneg\" $M/NumberTheory/*.lean | head -5; echo ===TERM===; grep -rn \"def term\\|theorem term\" $M/NumberTheory/LSeries/Basic.lean | head -8",
  "description": "Check tsum_comp_add_le_integral, vonMangoldt bounds, LSeries.term"
}
#1731 assistant 2026-08-24 09:31:44.777 UTC · 929→21672 tok open ⤢
thinking (45458 chars)
The pattern is clear. For ∫_{Ioi 3} log x/x² dx with antiderivative F(x) = −(log x + 1)/x: - `integral_Ioi_of_hasDerivAt_of_tendsto' (hderiv : ∀ x ∈ Ici a, HasDerivAt F (F' x) x) (F'int : IntegrableOn F' (Ioi a)) (hf : Tendsto F atTop (𝓝 m)) : ∫ x in Ioi a, F' x = m − F a`. - F(x) = −(log x + 1)/x: HasDerivAt F (log x / x²) x for x ≥ 3: deriv computation: d/dx[−(log x + 1)/x] = −[(1/x)·x − (log x + 1)·1]/x² = −[1 − log x − 1]/x² = log x/x² ✓. In Lean: HasDerivAt (fun x => −(log x + 1)/x) (log x/x²) x: via (hasDerivAt_log (x≠0)).add_const, .div (hasDerivAt_id'?)... let me build: ((log x + 1)/x)': use HasDerivAt.div (hc : HasDerivAt c c' x) (hd : HasDerivAt d d' x) (hd0 : d x ≠ 0): HasDerivAt (c/d) ((c'·d x − c x·d')/(d x)²): with c = log + 1 (c' = 1/x), d = id (d' = 1): ((1/x)·x − (log x + 1)·1)/x² = (1 − log x − 1)/x² = −log x/x². Then negate: −(c/d) has deriv +log x/x² ✓. So: ```lean have hF : ∀ x ∈ Ici (3:ℝ), HasDerivAt (fun x => -(Real.log x + 1)/x) (Real.log x / x^2) x := by intro x hx have hx0 : x ≠ 0 := by ... (x ≥ 3) have h1 : HasDerivAt (fun x => (Real.log x + 1)/x) (-(Real.log x)/x^2) x := by have h := ((Real.hasDerivAt_log hx0).add_const 1).div (hasDerivAt_id' x) hx0 -- h : HasDerivAt ((log · + 1)/id) ((1/x * x − (log x + 1) * 1)/x²) x convert h using 1 -- or field_simp + ring the derivative value · ext y; rfl? -- the function (log y + 1)/y vs (fun x => (log x + 1)/x) ✓ same · field_simp; ring -- the derivative value exact h1.neg ``` Hmm — the exact forms need care (the div derivative form). Also `hasDerivAt_id'` — in this Mathlib: hasDerivAt_id' (x) : HasDerivAt id (1) x? The banked gotcha from session 033: "hasDerivAt_id' s₀ |>.div_const 2" ✓ exists. - F'int: IntegrableOn (fun x => log x/x²) (Ioi 3): via `integrableOn_Ioi_deriv_of_nonneg'` (used in the example above!): `apply integrableOn_Ioi_deriv_of_nonneg' _ _ tendsto-...` hmm — the example: `integrableOn_Ioi_deriv_of_nonneg' _ _ tendsto_log_atTop.inv_tendsto_atTop.neg` with goals: the hasDerivAt ∀ x ∈ Ioi? and nonneg. So integrableOn_Ioi_deriv_of_nonneg' (a) (F?) (htendsto : Tendsto F atTop (𝓝 0))?: let me infer from the example: `integrableOn_inv_div_log_sq_Ioi` proof: `apply integrableOn_Ioi_deriv_of_nonneg' _ _ tendsto_log_atTop.inv_tendsto_atTop.neg; · intro t _; convert! (hasDerivAt_inv_log ...).neg using 1; field; · intro t _; positivity`. So the lemma: integrableOn_Ioi_deriv_of_nonneg' (a : ℝ) (F : ℝ → ℝ) (hlim : Tendsto F atTop (𝓝 0))? (hderiv : ∀ x ∈ Ioi a, HasDerivAt F (F' x) x) (hnonneg : ∀ x ∈ Ioi a, 0 ≤ F' x) : IntegrableOn F' (Ioi a). I'll mimic exactly. - Tendsto F atTop (𝓝 0): F = −(log x + 1)/x → 0: (log x + 1)/x → 0: from `Real.tendsto_log_div_atTop`? hmm: log x/x → 0 is `Real.tendsto_log_div_atTop : Tendsto (fun x => log x / x) atTop (𝓝 0)` — exists? I believe `Real.tendsto_log_div_atTop` hmm or `tendsto_pow_log_div_...`? There is `Real.tendsto_log_div_atTop`? In recent Mathlib: `Real.tendsto_log_div_atTop : Tendsto (fun x => Real.log x / x) atTop (𝓝 0)` — I think it exists (in Analysis/SpecialFunctions/Log/Deriv.lean or Limits). And 1/x → 0. So (log x + 1)/x = log x/x + 1/x → 0. F = −that → 0: .neg. - Then ∫ Ioi 3 = m − F(3) = 0 − (−(log 3 + 1)/3) = (log 3 + 1)/3. - The antitone condition: f = log x/x² antitone on Ici 3: `AntitoneOn f (Ici 3)`: via deriv ≤ 0: `antitoneOn_of_deriv_nonpos`? Signature: antitoneOn_of_deriv_nonpos (hD : Convex ℝ D) (hf : ContinuousOn f D) (hf' : DifferentiableOn ℝ f (interior D)) (hder : ∀ x ∈ interior D, deriv f x ≤ 0) : AntitoneOn f D. For D = Ici 3 (convex, interior = Ioi 3): f' (x) = (1 − 2 log x)/x³ ≤ 0 for x > 3 (log x > 1.09 > 1/2 ✓). deriv f x: f = fun x => log x / x^2: deriv via rules; then ≤ 0. ~40 lines. - The nonneg: log x/x² ≥ 0 for x ≥ 3 ✓ (log 3 > 0). Then the assembly: dirichletC2 = ∑' n, ‖term n‖ = ∑' n, g(n) where g(0) = 0, g(n) = Λ n/n²: - step 1: show ‖LSeries.term Λ (2:ℂ) n‖ = (if n = 0 then (0:ℝ) else Λ n / n²): per n: cases n = 0 (term = 0, norm 0 ✓) / n ≥ 1: term = Λ n/(n:ℂ)²... ‖(Λ n : ℂ)/((n:ℂ)^(2:ℂ))‖ = Λ n / n²: norm_div + the cpow norm + the Λ-norm. Hmm — (n:ℂ)^(2:ℂ) is cpow. ‖(n:ℂ)^(2:ℂ)‖ = ‖(n:ℂ)‖^((2:ℂ).re)·... = n² via Complex.norm_cpow_eq_rpow_re_of_pos? For x = (n:ℝ) > 0: ‖(x:ℂ)^s‖ = x^(s.re) hmm the lemma name: `Complex.norm_cpow_eq_rpow_re_of_pos (hx : 0 < x) (s : ℂ) : ‖(x : ℂ) ^ s‖ = x ^ s.re`? Let me check: there's `Complex.norm_cpow_eq_rpow_re_of_pos` and `norm_cpow_eq_rpow_re_of_nonneg`? For s = 2: (n:ℝ)^(2:ℝ)... rpow vs pow: x^(2:ℝ) = x² via `Real.rpow_two`? Real.rpow_natCast: x^((2:ℕ):ℝ) = x^2. So ‖(n:ℂ)^(2:ℂ)‖ = ((n:ℝ)^(2:ℝ)) — need (2:ℂ).re = 2 and the cast (n:ℂ) = ((n:ℝ):ℂ)... Then (n:ℝ)^(2:ℝ) = n² (rpow_two: x^(2:ℝ) = x*x or rpow_natCast). Manageable. - step 2: ∑' g = g(0) + ... head/tail split: Σ' n, g n = Σ_{n<4} g n + Σ' n, g (n+4) via sum_add_tsum_nat_add (needs Summable g). Summable g: from Λ/n² ≤ log n/n² and the integral-test summability... circular-ish. Alternative: g summable from the LSeries absSummable (the Λ LSeries is abs-summable for re > 1 — `ArithmeticFunction.LSeriesSummable...`? LiCircleBound's norm_logDeriv_zeta_le_dirichlet used the summability — let me check what it used: `LSeries.absSummable...`. The term-norm series IS dirichletC2's summand — its summability: from `ArithmeticFunction.vonMangoldt` LSeries absSummable at 2: there should be `ArithmeticFunction.LSeries_vonMangoldt_absSummable`? or LSeriesSummable_vonMangoldt (hs : 1 < re s). Then dirichletC2's summand = |term| — summable = abs-summable ✓. So Summable g via that. - step 3: g n ≤ log n/n² for n ≥ 1 (vonMangoldt_le_log / n²) and = 0 at n = 0 (log 1 = 0 anyway... g 0 = 0 and log 1/1 = 0 ✓ so g n ≤ log n/n² for all n with log 0/0? n=0: log 0/0 — division by zero = 0 in Lean (1/0 = 0): log 0 = 0, 0/0 = 0 — and g 0 = 0 ✓ consistent). - step 4: h : Summable (fun n => log n / n²)? For tsum_le_tsum I need both summable. The log n/n² summability: via the integral test (AntitoneOn.summable_of_integrableOn_Ioi or similar) with the integrable from the FTC argument. OK. - step 5: Σ' g ≤ Σ' (log n/n²) [tsum_le_tsum pointwise] = head(4) + tail ≤ [(log 2)/4 + (log 3)/9] + (log 3 + 1)/3 ≤ 0.995 — the final numeric: log 2 ≤ 0.6932 (Real.log_two_lt_d9 : log 2 < 0.6931471808), log 3 ≤ 1.0987 (Real.log_three_lt? hmm — log 3 < 1.09861228866811? Mathlib has Real.log_... for 3? Not sure. log 3 bounds: maybe not in Mathlib. Can derive: log 3 = log 2 + log(3/2) — or via Real.log_le_sub_one_of_pos: log 3 ≤ 3−1 = 2 — too big. Hmm: need log 3 ≤ 1.0987-ish. Route: log 3 = −log(1/3) and... or log 3 ≤ (3−1)/√3·... the standard Mathlib-friendly: Real.log_le_sub_one_of_pos gives log x ≤ x − 1 — too weak. Better: log x ≤ √x − 1/√x (x ≥ 1)? There's `Real.log_le_sub_one_of_pos` only. Hmm — `Real.log_le_sub_one_of_pos`, `Real.log_le_self`? For log 3 ≤ 1.0987: 3 ≤ e^1.0987 — via Real.exp partial sums: e^1.1 ≥ Σ_{k≤4} 1.1^k/k! = 1 + 1.1 + 0.605 + 0.2218 + 0.0610 = 2.9878 < 3 — not enough; e^1.101: ~2.99... e^1.0989 ≥ ... this needs ~5-6 terms. There might be a cleaner bound: `Real.log_three_lt_d9`? Let me check. Actually — hmm, the budget: piece 1 ≤ 1.01; my computed total 0.9949 — the room is 0.015. If log 3's upper bound is sloppy (say ≤ 1.10), fine. log 3 ≤ 1.10 ⟸ 3 ≤ e^{1.10}: e^{1.1} ≥ partial sum to k=5: 1+1.1+0.605+0.22183+0.061004+0.013421 = 3.00126 ≥ 3 ✓ (Real.sum_le_exp_of_nonneg — used in LiBasePoints!). So log 3 ≤ 1.1 via: Real.log_le_iff... `Real.log_le_iff_le_exp`? There's Real.log_le_iff_le_exp (hx : 0 < x)? or le_exp: `Real.log_le_iff_le_exp : 0 < x → (log x ≤ y ↔ x ≤ exp y)`? Something like Real.log_le_iff_le_exp. Then 3 ≤ exp 1.1 via the partial sum (Real.sum_le_exp_of_nonneg (show 0 ≤ (1.1:ℝ)) (n := 5) : Σ_{k∈range 5} 1.1^k/k! ≤ exp 1.1) and the rational computation Σ = 3.00126... ≥ 3 by norm_num. OK — doable, ~20 lines. Similarly log 2 ≤ 0.6932 via Real.log_two_lt_d9 (exists ✓ used in project). So piece 1 total: log2/4 + log3/9 + (log3+1)/3 ≤ 0.6932/4 + 1.1/9 + (1.1+1)/3 = 0.17330 + 0.12222 + 0.70 = 0.99552 ≤ 0.9955. And budget: 1.01? Hmm — actually what's the real budget? Let me recompute the fold: the D-069 assembly: piece1 + piece2 + piece3 + pieces45 + piece6 ≤ 10.5L + 48 with the C0hat-containing pieces: piece2 ≤ 0.6L + 0.886LL + 2.7; piece3 ≤ 12.7279·C0hat(t+1) + 7.00 = 12.7279·(0.433L' + 0.886LL' + 2.9) + 7.00 where L' = log(t+3) ≤ L + 1/12·... hmm — let me be careful about L' vs L: piece 3 uses C0hat(t+1) = 0.433·log(t+3) + 0.886·loglog(t+3) + 2.9. log(t+3) ≤ log(t+2) + 1/(t+2)·... ≤ L + 1/12 (t ≥ 10: log(t+3) − log(t+2) = log(1 + 1/(t+2)) ≤ 1/(t+2) ≤ 1/12 ✓). Similarly LL(t+3) ≤ LL + (1/12)/L·... ≤ LL + 1/(12·2.48) ≤ LL + 0.034. So piece 3 ≤ 12.7279·(0.433(L+1/12) + 0.886(LL+0.034) + 2.9) + 7.00 = 12.7279·(0.433L + 0.886LL + 2.9 + 0.433/12 + 0.886·0.034) + 7.00 = 12.7279·(0.433L + 0.886LL + 2.9 + 0.0361 + 0.0301) + 7.00 = 12.7279·(0.433L + 0.886LL + 2.9662) + 7.00 = 5.5112L + 11.2769LL + 37.756 + 7.00 = 5.5112L + 11.2769LL + 44.756. Total: piece1 (≤ 1.01 const) + piece2 (0.6L + 0.886LL + 2.7) + piece3 (5.5112L + 11.2769LL + 44.756) + pieces45 (0.09) + piece6 (0.30): L-coeff: 0.6 + 5.5112 = 6.1112; LL: 0.886 + 11.2769 = 12.1629; const: 1.01 + 2.7 + 44.756 + 0.09 + 0.30 = 48.856?!? — over 48!! Wait: 1.01 + 2.7 = 3.71; +44.756 = 48.466; +0.09 = 48.556; +0.30 = 48.856. That's OVER 48 by 0.856!! Hmm — but wait, my piece-3 constant estimate: 12.7279·2.9662 = 37.756 — but D-069 §3 said piece3 ≤ 12.7279·C₀ + 7.00 with C₀ = C0hat(t+1)... the C0hat constant 2.9 × 12.7279 = 36.91 and the L'/L conversion added 12.7279·0.0662 = 0.843. Total const: 36.91 + 7.00 + 0.843 = 44.75. Plus pieces 1,2,4,5,6 constants: 1.01 + 2.7 + 0.09 + 0.30 = 4.10. Grand total: 48.86. Over by 0.86. Hmm!! My D-069 estimate said 47.6 — because I used the L' = L approximation without the +1/12 conversion slack. The honest conversion costs 0.84. So the current budget breaks by ~0.86. Can I recover? Options: (a) The L'/L conversion: instead of converting log(t+3) ≤ log(t+2) + 1/12, keep piece 3 in terms of log(t+3) and make the FINAL target 10.5·log(|t|+3)?? — no, the target is baked: 10.5·log(|t|+2) + 48. (b) Sharpen piece 3's constants: the tail 0.55 and the C₀(2t+1) ≤ C₀+0.55: the tail Σ_{k>t}: at t ≥ 10: ≤ 0.433·(log10+1)/10 + (2.9+0.886·LL(3t))/11·... my 0.55 estimate: 0.433·0.4302 + 0.886·1.206·0.0909 + 0.2636 = 0.186+0.097+0.264 = 0.547. Hmm. The +0.55 for C0hat(2t+1) − C0hat(t+1): 0.433·log((2t+3)/(t+3)) + 0.886·(LL(2t+3)−LL(t+3)): log((2t+3)/(t+3)) ≤ log 2·(1 − ...) ≤ 0.693·(t+3...)/(t+2)... = log(2 − 3/(t+3)) ≤ log 2 − 3/(2(t+3))·... ≈ 0.686 at t=10 decreasing to 0.693. So 0.433·0.686 = 0.297; LL-diff: LL(2t+3) − LL(t+3) = log(log(2t+3)/log(t+3)) ≈ log(1 + 0.686/2.56) ≈ 0.236 at t=10 decreasing; 0.886·0.236 = 0.209. Total 0.506 ≤ 0.55 ✓ tight-ish. (c) Reduce piece 1 to the true Z₂ = 0.57: certified via partial sums — in Lean that's the heavy computation. The difference: 0.995 − 0.57 = 0.43 savings. Still over by 0.43. (d) The pinch: actually — WAIT. The binding constraint isn't the constant alone: the target is 10.5L + 48 and the assembly is 6.111L + 12.163LL + 48.86. Need 12.163·LL − 4.389·L ≤ −0.86+... i.e. 12.163LL − 4.389L + 48.86 ≤ 48 ⟺ 12.163LL − 4.389L ≤ −0.86?? — but at the pinch (L = 2.77) the LHS is +0.234 > 0. So it FAILS — need the constant ≤ 48 − 0.234 = 47.77. Currently 48.86. Must save 1.09. (e) Sharpen piece 6: 0.30 → the true ψ-diff bound is ≈ 0.23 (D-056) — save 0.07. (f) Sharpen piece 3's leading: use the per-interval sharpened term 4.5/(k√(1+k²)) instead of 4.5√2/(k(k+1)): the per-side interval-sum constant 1.3227 vs √2·1 = 1.4142: saves (1.4142−1.3227)·2·C₀ = 0.183·C₀·... wait: piece 3 = 4.5·Σ count·term: with term ≤ 1/(k√(1+k²)): per side Σ = 1.3227·count-ish: total 4.5·[1.3227·(C₀ + C₀(2t+1)) + tail] = 4.5·[1.3227·(2C₀ + 0.55) + 0.547] = 4.5·[2.6454·C₀ + 0.7275 + 0.547] = 11.904·C₀ + 5.735. vs previous 12.7279·C₀ + 7.00. C₀ ≈ 0.433L' + 0.886LL' + 2.9 + conversion: 11.904·C₀ + 5.735 = 11.904·(0.433L + 0.886LL + 2.9662) + 5.735 = 5.154L + 10.547LL + 35.310 + 5.735 = 5.154L + 10.547LL + 41.045. New totals: L: 0.6 + 5.154 = 5.754; LL: 0.886 + 10.547 = 11.433; const: 1.01 + 2.7 + 41.045 + 0.09 + 0.30 = 45.145. Constraint: 11.433·LL − (10.5−5.754)·L + 45.145 ≤ 48 ⟺ 11.433·LL − 4.746·L ≤ 2.855. At the pinch L* = 11.433/4.746 = 2.409 (below log 12 = 2.485!): for L ≥ 2.485 the LHS is decreasing (deriv 11.433/L − 4.746 < 0 for L > 2.409) ⟹ max at L = 2.485: 11.433·0.9103 − 4.746·2.485 = 10.407 − 11.794 = −1.39 ≤ 2.855 ✓✓ HUGE margin. So with the sharpened per-interval term, the assembly fits 10.5/48 comfortably. But the sharpened term 1/(k√(1+k²)) needs the sum Σ 1/(k√(1+k²)) ≤ 1.3227 in Lean — a non-telescoping series bound (integral comparison again: Σ_{k≥1} 1/(k√(1+k²)) ≤ 1/√2 + ∫₁^∞ dx/(x√(1+x²))... ∫ dx/(x√(1+x²)) = ... substitution u = √(1+x²): = log(√(1+x²)−1) − log x = −log(√(1+x²)/x + ...) hmm: ∫ dx/(x√(1+x²)) = −arsinh(1/x)·... = log(x/(1+√(1+x²))). At ∞: log(1) = 0... the antiderivative is −log((1+√(1+x²))/x). Not in Mathlib directly — provable via hasDerivAt of that composition (sqrt chain) — ~30 lines. The value at 1: −log((1+√2)) = −log(2.414) = −0.8814; at ∞ → 0: integral = 0.8814. Total Σ ≤ 0.7071 + 0.8814 = 1.5885?? — that's the ∫ from 1 — hmm: Σ_{k≥1} ≤ f(1) + ∫₁^∞ f = 0.7071 + 0.8814 = 1.5885 — WORSE than 1.3227 (the integral from 1 is lossy). Take more head terms: f(1)+f(2)+f(3) + ∫₃^∞: 0.7071+0.2236+0.1054 + [−log((1+√(1+x²))/x)]₃^∞ = 1.0361 + (0 − (−log((1+√10)/3))) = 1.0361 + log(4.1623/3) = 1.0361 + log(1.3874) = 1.0361 + 0.3273 = 1.3634. Still worse than 1.3227 — the TRUE sum ≈ 1.3227 (computed numerically). The integral route converges slowly to the truth; more head: f(1..5) + ∫₅^∞: 1.1966 + log((1+√26)/5) = 1.1966 + log(6.099/5) = 1.1966 + 0.1985 = 1.3951?? worse?? no wait: ∫₅^∞ = −log((1+√(1+x²))/x)|₅→∞: at ∞: −log(1) = 0⁻... the antiderivative F(x) = −log((1+√(1+x²))/x): F(5) = −log((1+√26)/5) = −log(6.0990/5) = −log(1.2198) = −0.19866; F(∞) = −log(1) = 0. ∫₅^∞ f = F(∞) − F(5) = 0.19866. Head f(1)+...+f(4) = 0.7071+0.2236+0.1054+0.0606 = 1.0967. Total ≤ 1.0967 + 0.1987 = 1.2954 ≤ 1.3227?? hmm wait that's the sum from k=5: Σ_{k≥5} f(k) ≤ f(5) + ∫₅^∞ f = 0.0392 + 0.1987 = 0.2379; total Σ_{k≥1} ≤ 1.0967 + 0.2379 = 1.3346. Hmm — 1.3346 vs the telescoping √2-form's 1.4142. Savings: (1.4142 − 1.3346)·2·C₀·4.5 = 0.0796·2·4.5·C₀ = 0.7164·C₀ ≈ 0.7164·(0.433L+0.886LL+2.97) — that's 0.31L + 0.63LL + 2.13 — hmm wait that's a SAVING so the piece-3 total becomes 12.7279C₀ + 7.00 − 0.716C₀ = 12.01C₀ + 7.00. Let me recompute totals with Σ-const = 1.3346 (call it S₃): piece 3 = 4.5·[S₃·C₀ + S₃·(C₀+0.55) + 0.547] = 4.5·[2·S₃·C₀ + 0.55·S₃ + 0.547] = 9·S₃·C₀ + 4.5·(0.734+0.547) = 9·1.3346·C₀ + 4.5·1.281 = 12.0114·C₀ + 5.765. Totals: L: 0.6 + 12.0114·0.433 = 0.6 + 5.201 = 5.801; LL: 0.886 + 12.0114·0.886 = 11.528; const: 1.01 + 2.7 + (12.0114·2.9662 + 5.765) + 0.09 + 0.30 = 1.01+2.7+35.633+5.765+0.09+0.30 = 45.498. Constraint: 11.528·LL − 4.699·L ≤ 48 − 45.498 = 2.502. Pinch: L* = 11.528/4.699 = 2.453 < 2.485 ⟹ max at L = 2.485: 11.528·0.9103 − 4.699·2.485 = 10.494 − 11.678 = −1.18 ≤ 2.502 ✓ EASY. Hmm wait — but hold on: the per-interval sharpened term — the far sum's interval split: interval k gets term ≤ 4.5/(x√(1+x²)) ≤ 4.5/(k√(1+k²))·... wait the term is 4.5·|s₀−s|-normalized... let me recheck: the term is ‖(s₀−s)/((s−ρ)(s₀−ρ))‖ ≤ 4.5/(x·√(1+x²)) with x = |t−γ| (|s−ρ| ≥ x, |s₀−ρ| ≥ √(1+x²)). On the interval x ∈ [k, k+1): ≤ 4.5/(k√(1+k²)) ✓. The interval sum: Σ_k count_k·4.5/(k√(1+k²)) with count_k ≤ C₀ (left) / C₀(2t+1) (right) — monotone ✓. So piece 3 ≤ 4.5·[C₀·Σ_left + C₀(2t+1)·Σ_right + tail] where Σ_left, Σ_right ≤ Σ_{k≥1} 1/(k√(1+k²)) ≤ 1.3346 — hmm but the tail (k > t): the per-interval count C₀(t+k+1) GROWS with k — can't bound by C₀(2t+1) for k > t. D-056 handled the k > t tail separately: Σ_{k>t} count·term ≤ Σ_{k>t} C₀(t+k+1)/(k√(1+k²))·4.5 ≤ 4.5·Σ C₀(2k+1)·(1/k²-ish)... the tail ≤ 4.5·[0.433·((log 10+1)/10) + ...] ≈ 4.5·0.547/4.5 — wait I had tail ≤ 0.55 for the 4.5√2-included form. Let me redo: tail T := Σ_{k>t} C0hat(t+k+1)·4.5/(k√(1+k²)) ≤ 4.5·Σ_{k>t} [0.433·log(3k) + 0.886·loglog(3k) + 2.9]/k²·... ≤ 4.5·[0.433·Σ_{k>t} log(3k)/k² + 0.886·LL(3t)·Σ 1/k² + 2.9·Σ 1/k²]: Σ_{k>t} 1/k² ≤ 1/(t−1)·... ≤ 1/9 (t ≥ 10: Σ_{k≥11} 1/k² ≤ ∫₁₀^∞ dx/x² = 0.1 — hmm: Σ_{k≥11} 1/k² ≤ 1/121 + ∫₁₁^∞ = 0.0083 + 0.0909 = 0.0992). Σ_{k≥11} log(3k)/k² = log 3·Σ1/k² + Σ log k/k² ≤ 1.0986·0.0992 + 0.3303 = 0.4393 (the Σ log k/k² ≤ (log 10+1)/10 = 0.3303 from before). So tail ≤ 4.5·[0.433·0.4393 + 0.886·loglog(33)·0.0992 + 2.9·0.0992] = 4.5·[0.1902 + 0.886·1.1935·0.0992 + 0.2877] = 4.5·[0.1902 + 0.1049 + 0.2877] = 4.5·0.5828 = 2.6226?!? Hmm that's bigger than the 0.55 I had — because I previously factored 4.5 OUT. Let me redo: the tail bound 0.55 was for the FORM without the 4.5√2 factor? D-056's "the k > t tail ≤ C₀(2t)/(t+1) + 0.433/t ≤ 0.53" — that's INSIDE the 4.5√2 multiplier (piece 3 = 4.5√2·[... + 0.53]). So in the sharpened form: piece 3 = 4.5·[C₀·S₃ + (C₀+0.55)·S₃ + tail'] where tail' = Σ_{k>t} count_k/(k√(1+k²)) ≤ Σ_{k>t} C0hat(t+k+1)/k² ≤ 0.433·0.4393 + 0.886·1.1935·0.0992 + 2.9·0.0992 = 0.5828/4.5·4.5 hmm: tail' ≤ 0.1902+0.1049+0.2877 = 0.5828. So piece 3 ≤ 4.5·[S₃·C₀ + S₃·C₀ + 0.55·S₃ + 0.5828] = 4.5·[2·1.3346·C₀ + 0.734 + 0.5828] = 12.0114·C₀ + 4.5·1.3168 = 12.0114·C₀ + 5.926. OK consistent-ish with before. So the full honest totals: L: 5.801; LL: 11.528; const: 45.5; need 11.528·LL − 4.699·L ≤ 2.5 for L ≥ 2.485 — max at boundary L = 2.485: −1.18 ≤ 2.5 ✓ margin 3.7. And the t=10 endpoint value: full bound at t=10: 5.801·2.485 + 11.528·0.9103 + 45.5 = 14.42 + 10.49 + 45.5 = 70.41 ≤ 10.5·2.485+48 = 74.09 ✓ margin 3.7. At t = 10¹²: 5.801·27.63 + 11.528·3.319 + 45.5 = 160.3+38.3+45.5 = 244.1 ≤ 10.5·27.63+48 = 338.1 ✓ margin 94. GREAT — the sharpened assembly has robust margins everywhere (the pinch dissolves: the max of 11.528·LL − 4.699·L over L ≥ 2.485 is at the boundary and equals −1.18). Hmm wait — but the pinch region t ≈ 13: L = log(15.15) = 2.718: 11.528·LL(2.718)=11.528·1.0 = 11.528... at L = 2.718: 11.528·1.0 − 4.699·2.718 = 11.528 − 12.772 = −1.244 ≤ 2.5 ✓. Yes fine (the function 11.528·log L − 4.699·L is decreasing throughout L ≥ 2.485 since the critical point 2.453 < 2.485 ✓). BUT the sharpened interval sum Σ 1/(k√(1+k²)) ≤ 1.3346 needs: (i) the antiderivative of 1/(x√(1+x²)) — −log((1+√(1+x²))/x) — a sqrt-chain hasDerivAt (~30 lines, sqrt derivatives exist: Real.hasDerivAt_sqrt), (ii) the Ioi FTC again, (iii) the antitone condition. Compare: the telescoping form Σ 1/(k(k+1)) = 1 is FREE-ish in Lean? 1/(k(k+1)) = 1/k − 1/(k+1) telescopes: `Summable` + tsum = 1 — Mathlib probably has this or it's 20 lines. The √2-form piece 3 (12.7279·C₀ + 7.06) breaks the budget by ~0.86–1.09; the sharpened form (12.011·C₀ + 5.93) fits with margin 3.7. The extra cost: the 1/(k√(1+k²)) sum bound (~80-100 lines of integral plumbing). Worth it — it keeps the baked constants. Hmm — wait, actually, alternatively: keep the telescoping form but take the FIRST interval exactly: interval k=1: term ≤ 4.5/(1·√2) = 3.182 (both forms agree at k=1). The √2-form per-interval bound is 4.5√2/(k(k+1)): at k=1: 3.182 ✓ same; k=2: √2-form 4.5√2/6 = 1.0607 vs sharp 4.5/(2√5) = 1.0062... The total per-side: √2-form Σ = 4.5√2·1 = 6.364; sharp: 4.5·1.3346 = 6.006. Difference per side: 0.358; both sides + tail: ~0.72·C₀-independent... hmm the earlier computation: the difference between the two piece-3 totals: (12.7279 − 12.0114)·C₀ + (7.06 − 5.93) = 0.7165·C₀ + 1.13 — at C₀ ≈ 5 (t=10): 4.7 — yes that's the budget-breaking amount. OK so the sharp sum is needed. Alternatively — a MIDDLE route: avoid the antiderivative entirely by splitting at k = 1: interval k=1 term ≤ 4.5/√2; intervals k ≥ 2: term ≤ 4.5√2/(k(k+1))·(something)... hmm the ratio sharp/√2-form at k: [4.5/(k√(1+k²))]/[4.5√2/(k(k+1))] = (k+1)/(√2·√(1+k²)) = (k+1)/(√(2+2k²)): at k=2: 3/√10 = 0.949; k=3: 4/√20 = 0.894; k→∞: → 1/√2 = 0.707. The total ratio: ~0.94. The savings from the √2-form: 6.364·(1 − 0.94) per side... not clean. The k=1-exact trick: piece3 ≤ count₁·4.5/√2 + Σ_{k≥2} count·4.5√2/(k(k+1)) ≤ C₀·[4.5/√2 + 4.5√2·(1 − 1/2)]·2 + ... = C₀·[3.182 + 4.5√2·0.5]·2 = C₀·[3.182+3.182]·2 — no savings (4.5√2·(Σ_{k≥2} 1/(k(k+1))) = 4.5√2·(1/2) = 3.182 and the k=1 sharp 3.182 — equal!). Because the √2-form is EXACT at k=1 (3.182 = 3.182) — the slack starts at k=2. So splitting k=1 gives nothing. The slack is distributed. So the sharp sum is genuinely needed. OK — the integral plumbing for 1/(x√(1+x²)) is in. Actually hmm — wait, one more alternative: Σ_{k≥1} 1/(k√(1+k²)) ≤ Σ 1/k^{3/2}·(k/√(1+k²))... no: 1/(k√(1+k²)) ≤ 1/k² ⟹ Σ ≤ π²/6 = 1.645 — too big. The antiderivative route it is. OR — hmm, actually: 1/(k√(1+k²)) ≤ 1/(k(k+1))·(k+1)/√(1+k²) and (k+1)/√(1+k²) ≤ √(2(k+1)²/2)... (k+1)² ≤ 2(k²+1) ⟺ k²+2k+1 ≤ 2k²+2 ⟺ 0 ≤ k²−2k+1 = (k−1)² ✓ so (k+1)/√(1+k²) ≤ √2 — that's the D-056 form (consistent). The sharp form needs the integral. Fine. Hmm, wait — actually, let me reconsider. Maybe there's an even simpler decomposition avoiding the antiderivative: Σ_{k≥1} 1/(k√(1+k²)): substitute the integral test with f(x) = 1/(x·(1+x²)^{1/2}) — antitone on [1,∞) (product of antitone positive functions ✓ NO deriv needed! 1/x antitone, 1/√(1+x²) antitone — product of positive antitone is antitone ✓). The integral ∫₁^N dx/(x√(1+x²)): substitute x = 1/u? dx/(x√(1+x²)): u = √(1+x²) ⟹ u du = x dx... x² = u²−1: ∫ dx/(x√(1+x²)) = ∫ (x dx)/(x²√(1+x²)) = ∫ du/(u² − 1) = (1/2)log((u−1)/(u+1)). So the antiderivative = (1/2)·log((√(1+x²)−1)/(√(1+x²)+1)) = log((√(1+x²)−1)/x)·... = log(x) − log(1+√(1+x²))·... let me verify: (1/2)log((u−1)/(u+1)) with u = √(1+x²): (u−1)/(u+1) = (u−1)²/(u²−1) = (u−1)²/x²: (1/2)log((u−1)²/x²) = log((u−1)/x) = log((√(1+x²)−1)/x). And (√(1+x²)−1)/x = x/(√(1+x²)+1) ✓. So F(x) = log(x/(1+√(1+x²))). F'(x) = 1/(x√(1+x²)) ✓. In Lean: hasDerivAt of log(x/(1+√(1+x²))): log-deriv of the ratio: deriv log(g x) = g'/g — g(x) = x/(1+√(1+x²)): g'/g = 1/x − (√')/(1+√): √'(1+x²) = x/√(1+x²): so g'/g = 1/x − (x/√(1+x²))/(1+√(1+x²)) = 1/x − x/(√(1+x²)(1+√(1+x²))) = [√(1+x²)(1+√(1+x²)) − x²]/(x·√(1+x²)(1+√(1+x²))) = [√(1+x²) + 1+x² − x²]/(x·√(1+x²)(1+√)) = (√(1+x²)+1)/(x·√(1+x²)(1+√)) = 1/(x√(1+x²)) ✓. In Lean this is a `HasDerivAt.log` + div/sqrt chain + a field_simp/ring_nf algebraic identity — maybe 40 lines. F(∞) : x/(1+√(1+x²)) → 1 ⟹ F → log 1 = 0. The limit: x/(1+√(1+x²)) → 1 as x → ∞: √(1+x²) ~ x: ratio ~ x/(1+x) → 1: needs a tendsto argument (~20 lines: √(1+x²)/x → 1 via sqrt(1/x²+1) → 1...). OK. This is all doable but it's a lot of calculus plumbing. The honest assessment: 5f-i's remaining piece 1 + piece 6's digamma + piece 3's interval machine + assembly is ~2 sessions of Lean. Tonight I've done the identity + pieces 2/4/5. Given it's ~1:40 AM, let me finish piece 1 (dirichletC2 ≤ 0.995 — self-contained ~100 lines) and then wrap up the session cleanly. Actually — piece 1 needs: the term-norm form, the summabilities, the head/tail split, the tail integral ∫₃^∞ log x/x² = (log 3+1)/3 (antiderivative −(log x+1)/x — no sqrt! just log and div), the antitone condition, and the numeric fold with log 2/log 3 bounds. That's tractable tonight. Hmm — wait, for piece 1, do I even need the antitone/integral machinery? Alternative: Σ_{n≥4} log n/n² — bound by a DIRECT comparison with a telescoping series? log n/n² vs 1/n^{3/2}: log n ≤ (2/e)·√n ⟹ log n/n² ≤ (2/e)·n^{−3/2}: Σ_{n≥4} n^{−3/2} ≤ ∫₃^∞ x^{−3/2} dx = 2·3^{−1/2} = 1.1547: total ≤ (2/e)·1.1547 = 0.736·1.1547 = 0.8497 — vs the sharp integral 0.6995. Total piece 1: 0.1733 + 0.1221 + 0.8497 = 1.145 > 1.01 budget ✗. Hmm — but wait: with the sharpened piece 3, the constant budget changed: total const was 45.498 with piece 1 = 1.01; if piece 1 = 1.145: total = 45.633 vs the available 48 − (max pinch −1.18)... the constraint: const ≤ 48 − (11.528·LL − 4.699·L)_max = 48 − (−1.18) = 49.18. So the binding constraint is const ≤ 49.18!! Piece 1 = 1.145 gives 45.63 ≤ 49.18 ✓✓ EASY. Oh nice — with the sharpened piece 3, the pinch dissolved (the LL-L function is DECREASING on L ≥ 2.485, max at the boundary = −1.18), so the constant budget is a generous 49.18, and piece 1 can be as big as 1.145 + slack. Then the crude n^{−3/2} comparison suffices for piece 1 — no log integral needed! Let me double-check the Σ_{n≥4} n^{−3/2} ≤ 2/√3 without an integral: hmm — n^{−3/2} ≤ ∫_{n−1}^{n} x^{−3/2} dx (antitone) — still an integral comparison. Simpler: Σ_{n≥4} n^{−3/2} ≤ Σ_{n≥4} 1/(n^{1/2}·(n−1)·n)... hmm. Alternative telescoping: n^{−3/2} ≤ 2(1/√(n−1) − 1/√n)·something? 1/√(n−1) − 1/√n = (√n − √(n−1))/(√n√(n−1)) = 1/(√n√(n−1)(√n+√(n−1))) ≥ 1/(√n·√n·2√n) = 1/(2 n^{3/2})·(√n/√(n−1})... ≈ 1/(2n^{3/2})·(1+1/(2n))·... So n^{−3/2} ≤ 2·(1/√(n−1) − 1/√n)·(√(n−1)/√n) ≤ 2·(1/√(n−1) − 1/√n) — since √(n−1)/√n ≤ 1... wait direction: n^{−3/2} vs 2(Δ): Δ = 1/(√n√(n−1)(√n+√(n−1))) ≥ 1/(√n·√n·2√n) = 1/(2n^{3/2}) ✓ (since √(n−1) ≤ √n and √n+√(n−1) ≤ 2√n). So n^{−3/2} ≤ 2Δ = 2(1/√(n−1) − 1/√n) ✓ TELESCOPING! Σ_{n≥4} n^{−3/2} ≤ 2·(1/√3) = 1.1547 ✓. And the telescoping sum ∑' (1/√(n−1) − 1/√n) from n=4: = 1/√3 (limit) — in Lean: summable via the telescope + tsum of a telescoping difference = first term: there's `Summable` machinery for differences: ∑' (f(n+1) − f(n)) = ... hmm: Σ_{n≥4} (1/√(n−1) − 1/√n) = Σ_{m≥3} (1/√m − 1/√(m+1)) = 1/√3 (since 1/√m → 0). In Lean: the telescoping tsum: `Summable` of a difference where f → 0: there's a lemma `tsum_of_...`? The cleanest: Σ_{m≥3} (f m − f (m+1)) with f m → 0: tsum = f 3: hmm — `Summable.hasSum_iff`... Let me use: the partial sums telescope: Σ_{m=3}^{M} (f m − f(m+1)) = f 3 − f(M+1) → f 3. The tsum = f 3 via `HasSum` of the telescoping series: Mathlib: `hasSum_...`? There might be a direct lemma: `Summable.tsum_eq...`? I don't recall a named telescope-tsum lemma offhand, but the partial-sum form: tsum_eq_of... Alternatively use `Summable.hasSum`... The standard approach: `hasSum_iff_tendsto_nat_of_nonneg`? or the telescope: for f → 0: ∑' m, (f m − f (m+1)) = f 0 -ish. Hmm — there's `tsum_of...`... Actually the cleanest available might be through the integral after all. OR — even simpler: Σ_{n≥4} n^{−3/2} ≤ Σ_{n≥4} 2·(√(n) − √(n−1))/(n·... no. Hmm, hold on — actually the SIMPLEST: Σ_{n≥4} log n/n² ≤ Σ_{n≥4} (2/e)·n^{−3/2} — and Σ_{n≥4} n^{−3/2} ≤ Σ_{n≥4} (1/(n−1)^{1/2} − 1/n^{1/2})·2 — the telescope tsum: in Lean, `Summable (fun n => (1/√(n) − 1/√(n+1)))` and its tsum: there IS a lemma — `tsum_of_...`. Actually `MeasureTheory`... no. The plain fact: for f : ℕ → ℝ with f n → 0: ∑' (f n − f (n+1)) = f 0. I recall this IS in Mathlib as... `Summable.tsum_sub`? no. Hmm: it might be easier to use: ∑'_{n≥4} n^{−3/2} ≤ ∫₃^∞ x^{−3/2} via AntitoneOn.tsum_comp_add_le_integral — the integral ∫₃^∞ x^{−3/2} dx = 2/√3 has antiderivative −2/√x — the FTC route again (same machinery as the log integral but simpler function). The antitone condition for x^{−3/2}: easy (rpow antitone... `Real.rpow_antitoneOn`? or product of antitone: x⁻¹ antitone, x^{−1/2} antitone ⟹ product antitone ✓ no deriv). OK you know what — piece 1's exact shape (integral vs telescope) I'll decide at build time. The point: with the sharpened piece 3, piece 1's budget is generous (~1.9+), so even Σ_{n≥4} log n/n² ≤ 1.0 suffices. Actually — hold on, even simpler: Λ(n) ≤ log n ≤ (n−1) — way too big. Let me think about what crude bound on dirichletC2 is EASIEST in Lean: - dirichletC2 = Σ Λ(n)/n². Head exact: n ≤ 3. Tail Σ_{n≥4}: Λ(n)/n² ≤ log n/n² ≤ (2/e)·n^{−3/2}. Need Σ_{n≥4} n^{−3/2} ≤ 1.2 (say). Real.rpow-based: n^{−3/2} = 1/(n·√n) ≤ 1/((n−1)·√(n−1))... hmm. Or n^{−3/2} ≤ 2/(n·√(n−1))-ish... The telescoping √ difference is the clean one. Let me check if Mathlib has the telescope-tsum: grep "tsum_sub_tsum_...|hasSum_..._sub"? There's `Summable.hasSum` combos... Actually I do recall: `tsum_of_...`? Hmm, there might be a `Real...`? Whatever — I'll find it at build time or prove it via partial sums (Finset.sum_range_sub — the telescoping finset sum EXISTS: `Finset.sum_range_sub (f) (n) : ∑ i ∈ range n, (f (i+1) − f i) = f n − f 0` ✓ that's a standard lemma). Then the tsum via the partial-sum limit: tsum_eq_lim... `HasSum` from tendsto of partial sums: hasSum_iff... use `Summable.hasSum`... Actually: the series Σ (f(n+1) − f(n)) has partial sums f(N) − f(0) → L − f(0) if f → L. So hasSum (fun n => f(n+1) − f n) (L − f 0) via `HasSum` def + the partial-sum identity + tendsto: `hasSum_iff_tendsto_nat_of_summable`? or directly: HasSum f l ↔ Tendsto (partial sums) (𝓝 l) — `hasSum_iff_tendsto_nat_of_nonneg`? The general: HasSum f l ↔ Tendsto (fun N => ∑ n ∈ range N, f n) atTop (𝓝 l) — that's `hasSum_iff_tendsto_nat_of_summable`?? The name... `Summable.hasSum` no... it's `hasSum_iff_tendsto_nat_of_nonneg` (needs nonneg) hmm or for general: `hasSum_iff_tendsto_nat_of_summable`?? I'll find it. The machinery exists; ~40 lines for the telescope. Given the sharpened piece 3 makes piece 1 easy, the CRITICAL path is piece 3's sharp sum Σ 1/(k√(1+k²)) ≤ 1.3346 (needs the log-ratio antiderivative) OR... hmm — wait, actually — can piece 3's sum ALSO use a telescope? Σ_k 1/(k√(1+k²)): compare 1/(k√(1+k²)) ≤ 1/k² ≤ ...: telescope √-difference: 1/k² ≤ 1/(k(k−1)) = 1/(k−1) − 1/k (k ≥ 2) ✓! So Σ_{k≥2} 1/(k√(1+k²)) ≤ Σ_{k≥2} 1/k² ≤ Σ_{k≥2} 1/(k(k−1)) = 1. And the k=1 term: 1/√2 = 0.7071. Total ≤ 1.7071 — vs the needed ≤ 1.3346·(something). Hmm — 1.7071 vs 1.3346: the difference in piece 3: 4.5·(1.7071 − 1.3346)·2·C₀ = 3.35·C₀ — too big. But wait — do I need ≤ 1.3346 exactly? Let me recompute the required S₃ from the budget. Piece 3 = 4.5·[S₃·C₀ + S₃·(C₀+0.55) + tail'] = 9·S₃·C₀ + 4.5·(0.55·S₃ + 0.5828). With S₃ = 1.7071: 15.364·C₀ + 4.5·(0.9389+0.5828) = 15.364·C₀ + 6.848. Totals: L: 0.6 + 15.364·0.433 = 7.25; LL: 0.886 + 15.364·0.886 = 14.50; const: piece1 1.15 + 2.7 + (15.364·2.9662 + 6.848) + 0.09 + 0.30 = 1.15+2.7+45.58+6.848+0.09+0.30 = 56.67. Constraint: 14.50·LL − (10.5−7.25)·L + 56.67 ≤ 48?? 14.50·LL − 3.25·L ≤ −8.67 — FALSE (LHS at L=2.485: 14.50·0.91 − 3.25·2.485 = 13.2 − 8.08 = +5.12 > 0). BREAKS badly. So the k=1 exact + k≥2 telescope (S₃ = 1.7071) fails. Need S₃ ≤ ~1.34. What about S₃ via: k=1, k=2, k=3 exact + telescope from k=4? Σ_{k≥4} 1/(k√(1+k²)) ≤ Σ_{k≥4} 1/k² ≤ Σ_{k≥4} 1/(k(k−1)) = 1/3. Head: 1/√2 + 1/(2√5) + 1/(3√10) = 0.7071 + 0.2236 + 0.1054 = 1.0361. Total ≤ 1.0361 + 0.3333 = 1.3694. Hmm — closer. Piece 3 = 9·1.3694·C₀ + 4.5·(0.55·1.3694 + 0.5828) = 12.325·C₀ + 6.016. Totals: L: 0.6+5.337 = 5.937; LL: 0.886+10.918 = 11.804; const: 1.15+2.7+(12.325·2.9662)+6.016+0.09+0.30 = 1.15+2.7+36.56+6.016+0.09+0.30 = 46.82. Constraint: 11.804·LL − 4.563·L + 46.82 ≤ 48 ⟺ 11.804·LL − 4.563·L ≤ 1.18. Pinch: L* = 11.804/4.563 = 2.587 (t = 11.3): value 11.804·log(2.587) − 4.563·2.587 = 11.804·0.9504 − 11.805 = 11.219 − 11.805 = −0.586 ≤ 1.18 ✓ margin 1.77. And boundary L = 2.485: 11.804·0.9103 − 4.563·2.485 = 10.745 − 11.339 = −0.594 ✓. At large L: decreasing ✓. So with S₃ ≤ 1.3694 (k≤3 exact + telescope from 4) it FITS with margin ~1.77 at the pinch. And the telescope Σ_{k≥4} 1/(k(k−1)) = 1/3 is the standard telescoping sum (1/(k(k−1)) = 1/(k−1) − 1/k) — the Finset.sum_range_sub + limit machinery — and the per-term bound 1/(k√(1+k²)) ≤ 1/k²·(1) hmm: 1/(k√(1+k²)) ≤ 1/(k(k−1)) ⟺ k−1 ≤ √(1+k²) ✓ (k−1 ≤ k ≤ √(1+k²)·... √(1+k²) ≥ k > k−1 ✓). So per-term: 1/(k√(1+k²)) ≤ 1/(k(k−1)) for k ≥ 2 ✓ (via 1/k² ≤ 1/(k(k−1)) and 1/(k√(1+k²)) ≤ 1/k² since √(1+k²) ≥ k). All elementary — NO integral needed!! And the k=2,3 exact terms: 1/(2√5) and 1/(3√10) — with √5 ≥ 2.23, √10 ≥ 3.16 (rational lower bounds: (2.23)² = 4.9729 ≤ 5 ✓ so √5 ≥ 2.23; (3.16)² = 9.9856 ≤ 10 ✓ √10 ≥ 3.16): 1/(2·2.23) = 0.2242, 1/(3·3.16) = 0.1055. Head ≤ 0.7072 (1/√2: √2 ≥ 1.414: 1/√2 ≤ 1/1.414 = 0.70722) + 0.2242 + 0.1055 = 1.0369. Total S₃ ≤ 1.0369 + 1/3 = 1.3702 ≤ 1.3703. Pinch margin ~1.76. GOOD ENOUGH — no integral plumbing for piece 3's sum! Let me redo the FULL honest constant assembly with this S₃ to nail the final numbers: - piece 1: Z₂ ≤ 0.9955 (log2 ≤ 0.6932, log3 ≤ 1.1: (0.6932)/4 + 1.1/9 + (1.1+1)/3 = 0.1733+0.12222+0.7 = 0.9955) — via the ∫₃^∞ log/x² integral — OR the crude route: Σ_{n≥4} Λ/n² ≤ Σ log n/n² ≤ Σ (2/e)·n^{−3/2} ≤ (2/e)·(telescope 2/√3) = (2/e)·1.1547 = 0.85: piece 1 ≤ 0.1733 + 0.1222 + 0.85 = 1.1455. With the generous budget, use the crude route (no integral!): the √-telescope Σ n^{−3/2} ≤ 2/√3: n^{−3/2} ≤ 2(1/√(n−1) − 1/√n) ⟺ 1/(n√n) ≤ 2(√n−√(n−1))/(√n√(n−1)) ⟺ √(n−1) ≤ 2√n(√n−√(n−1))·... 2(√n−√(n−1)) = 2/(√n+√(n−1)): so need 1/(n√n) ≤ 2/(√n√(n−1)(√n+√(n−1))) ⟺ √(n−1)(√n+√(n−1)) ≤ 2n ⟺ √(n(n−1)) + (n−1) ≤ 2n ⟺ √(n(n−1)) ≤ n+1 ✓ (n(n−1) = n²−n ≤ n²+2n+1 ✓). Elementary ✓. And 2/e ≤ 0.7358 (e ≥ 2.718: 2/2.718 = 0.7359). And log n ≤ (2/e)·√n ⟺ log(√n)·... log n/√n ≤ 2/e ⟺ (log n)/n^{1/2} max at n = e²: value 2/e ✓ — the standard "log x ≤ x^a/a" — Real.log_le_rpow_div! (session 034's lemma: log x ≤ x^ε/ε): with ε = 1/2: log n ≤ 2·√n·... wait: log n ≤ n^{1/2}/(1/2) = 2√n. That's log n ≤ 2√n NOT (2/e)√n. The 2/e form: log n ≤ (2/e)·√n ⟺ log(n)/√n ≤ 2/e — from log_le_rpow_div with ε = 1/2: log n ≤ 2·n^{1/2} — the e-form is sharper but log_le_rpow_div gives 2·√n. Hmm — 2√n vs (2/e)√n = 0.736√n: the rpow_div lemma is lossy by e. With log n ≤ 2√n: Σ_{n≥4} log n/n² ≤ 2·Σ n^{−3/2} ≤ 2·(2/√3) = 4/√3 = 2.309: piece 1 ≤ 0.1733+0.1222+2.309 = 2.60 — too big? Budget check with S₃ = 1.3702: const total = piece1 2.60 + 2.7 + 36.56 + 6.016 + 0.09 + 0.30 = 48.27 — vs the available 48 − (pinch max −0.586) = 48.59. 48.27 ≤ 48.59 ✓ FITS by 0.32! TIGHT. Hmm. With piece 1 = 1.1455 (the (2/e) form): 46.82, fits by 1.77. The (2/e) form: log n ≤ (2/e)√n — from log_le_rpow_div... no. From the max of log x/√x: provable via deriv (log x/√x)' = (1/x·√x − log x/(2√x))/x = (1 − (log x)/2)/x^{3/2} — zero at x = e² — max value (log e²)/e = 2/e. The deriv argument: ~30 lines. OR use log_le_rpow_div with ε = 1/4: log n ≤ 4·n^{1/4}: Σ_{n≥4} 4/n^{7/4}: ≤ 4·∫₃^∞ x^{−7/4}·... telescope: n^{−7/4} ≤ (4/3)(1/(n−1)^{3/4} − 1/n^{3/4})? similar √-telescope with rpow 3/4: (n−1)^{−3/4} − n^{−3/4} = ... ≈ (3/4)n^{−7/4}: so n^{−7/4} ≤ (4/3)(...): Σ_{n≥4} ≤ (4/3)·3^{−3/4} = (4/3)·0.4387 = 0.585. ×4 = 2.34. no better. OR piece 1 via the sharp integral after all (∫₃^∞ log x/x² = (log 3+1)/3 — the antiderivative is clean (no sqrt!): F = −(log x + 1)/x): piece 1 ≤ 0.9955. Given the budget tightness (0.32 with the crude route), the sharp integral is worth it: piece 1 ≤ 0.9955 gives total 46.82, margin 1.77. Hmm — this is all getting tight. Let me consolidate the FINAL honest assembly (all pieces with Lean-feasible bounds): - piece 1: ≤ (log 2)/4 + (log 3)/9 + (log 3 + 1)/3 ≤ 0.1733 + 0.1223 + 0.7 = 0.9956 (sharp integral; log 2 ≤ 0.6932 via log_two_lt_d9; log 3 ≤ 1.1 via e^1.1 ≥ 3.0013 partial sum). - piece 2: ≤ 0.6L + 0.886LL + 2.7 (P1). - piece 3: ≤ 4.5·[S₃·C₀ + S₃·(C₀ + 0.55) + 0.5828] with S₃ ≤ 1.3703, C₀ = C0hat(t+1) ≤ 0.433(L + 1/12) + 0.886(LL + 0.034) + 2.9 ≤ 0.433L + 0.886LL + 2.9662 (the L' conversion — hmm 0.433/12 = 0.0361, 0.886·0.034 = 0.0301: 2.9+0.0361+0.0301 = 2.9662 ✓): piece 3 ≤ 9·1.3703·(0.433L + 0.886LL + 2.9662) + 4.5·(0.55·1.3703 + 0.5828) = 12.333·(0.433L + 0.886LL + 2.9662) + 4.5·1.3365 = 5.340L + 10.927LL + 36.585 + 6.014 = 5.340L + 10.927LL + 42.599. Hmm wait: 9·S₃·C₀ = 9·1.3703·C₀ = 12.3327·C₀ (the two sides: left S₃·C₀, right S₃·(C₀+0.55)): 4.5·(S₃·C₀ + S₃·C₀ + 0.55·S₃ + 0.5828) = 4.5·(2·1.3703·C₀ + 0.7537 + 0.5828) = 4.5·(2.7406·C₀ + 1.3365) = 12.333·C₀ + 6.014 ✓. - pieces 4/5: 0.045 + 0.045 = 0.09. - piece 6: ≤ 0.30 (the sharp digamma remainder route). TOTALS: L: 0.6 + 5.340 = 5.940; LL: 0.886 + 10.927 = 11.813; const: 0.9956 + 2.7 + 42.599 + 0.09 + 0.30 = 46.685. Constraint: 11.813·LL − (10.5 − 5.940)·L + 46.685 ≤ 48 ⟺ 11.813·LL − 4.560·L ≤ 1.315 for L ≥ 2.485. Pinch: L* = 11.813/4.560 = 2.590 (t = e^{2.590} − 2 = 11.33): value 11.813·log(2.590) − 4.560·2.590 = 11.813·0.9517 − 11.810 = 11.242 − 11.810 = −0.568 ≤ 1.315 ✓ margin 1.88. Boundary L = 2.485: 11.813·0.9103 − 4.560·2.485 = 10.753 − 11.332 = −0.579 ✓. Decreasing thereafter ✓. FITS with margin ≈ 1.9. OK so the final assembly fits 10.5/48 with comfortable margin (~1.9) using: - piece 1 sharp integral (0.9956), - piece 3 with S₃ ≤ 1.3703 (k≤3 exact + telescope from k=4), - the tail bound 0.5828, the C₀(2t+1) ≤ C₀ + 0.55, the L'/L conversion, - piece 6 ≤ 0.30. All bounds elementary except piece 1's integral (clean antiderivative) and piece 6's digamma remainder (level-2 EM). WAIT — one more check on piece 6's constant: D-056 got 0.29; budget 0.30. The sharp form: ½|ψ(s/2) − ψ(s₀/2)| with ψ(w) = log w − 1/(2w) + r(w), |r| ≤ 1.2/|w|²: |log(w/w₀)|: w = s/2, w₀ = s₀/2: |w − w₀| = |s−s₀|/2 ≤ 2.25; |w₀| ≥ t/2 ≥ 5: |log(w/w₀)| ≤ |w/w₀ − 1|·(1/(1−|w/w₀−1|)) hmm: |log(1+u)| ≤ |u|/(1−|u|) for |u| < 1 (provable? |log(1+u)| ≤ −log(1−|u|) — hmm — the standard: |log(1+u)| ≤ 2|u| for |u| ≤ 1/2 — Mathlib has `Complex.norm_log_one_add_le`? `Complex.abs_log_one_add_le`? There's `Complex.norm_log_one_add_le (h : ‖z‖ ≤ r)...`? I recall `Complex.norm_log_one_add_le : ‖log (1 + z)‖ ≤ ...`? hmm — there's `Complex.abs_log_one_add_lt`? In Mathlib: `Complex.norm_log_one_add_le (hz : ‖z‖ < 1) : ‖Complex.log (1 + z)‖ ≤ -Real.log (1 - ‖z‖)`? something like that. And −log(1−x) ≤ 2x for x ≤ 1/2 (Real.log... via log(1−x) ≥ −2x ⟸ ...). Then |u| = |w/w₀ − 1| = |w−w₀|/|w₀| ≤ 2.25/(t/2) = 4.5/t ≤ 0.45 (t ≥ 10): |log(w/w₀)| ≤ 2·0.45·... hmm wait — log(w/w₀) = log(1 + (w−w₀)/w₀): |·| ≤ 2·|u| with |u| ≤ 4.5/t·(1/2)·2 — hold on: |u| = |w−w₀|/|w₀| ≤ 2.25/(t/2) = 4.5/t. At t = 10: 0.45. |log(1+u)| ≤ 2|u| = 0.9?? D-056 had ½|log(s/s₀)| ≤ 0.23 ⟹ |log| ≤ 0.46. My 2|u| = 0.9 is 2× lossy. The tighter: |log(1+u)| ≤ |u|/(1−|u|) = 0.45/0.55 = 0.818 — still lossy vs 0.46. The arg/modulus split (D-056): |log(w/w₀)|² = (log|w/w₀|)² + (arg)²: |log|w/w₀|| ≤ |1 − |w/w₀||/(1−...)·... |w|/|w₀|: |w| ≥ t/2 − ... |w| ≥ |im w| = t/2 (im w = t/2 ✓); |w₀| ≥ t/2: ||w|−|w₀|| ≤ |w−w₀| ≤ 2.25: |log(|w|/|w₀|)| ≤ 2.25/(t/2 − 2.25)·... ≤ 2.25/2.75 = 0.818?? hmm at t=10: |w₀| ≥ 5, |w| ≥ 5 − 2.25 = 2.75: |log ratio| ≤ max(log(7.25/5), log(5/2.75)) = max(0.371, 0.598) = 0.598. arg: |arg(w/w₀)| ≤ |w−w₀|/|w₀|·... arg difference ≤ 2.25/5 = 0.45 rad? (the angle between w and w₀ — both have im = t/2: the ratio w/w₀ = (s/2)/(s₀/2) = s/s₀: arg(s/s₀): the points s, s₀ both at height t: arg(s/s₀) = arg s − arg s₀: |arg s − arg s₀| ≤ ... both near the imaginary axis: arg s ≈ π/2 − (σ)/t-ish: |arg s − arg s₀| ≈ |σ − 2|/t ≤ 4.5/t = 0.45 ✓. So |log(s/s₀)| ≤ √(0.598² + 0.45²) = √(0.3576+0.2025) = √0.560 = 0.748. ½·0.748 = 0.374. Plus ½·(1/(2w)−1/(2w₀)) ≤ ½·(1/2)·|w−w₀|/(|w||w₀|)·2 = ½·(1/2)·2.25/(2.75·5)·2·... let me redo: |1/(2w) − 1/(2w₀)| = (1/2)·|w₀−w|/(|w||w₀|) ≤ (1/2)·2.25/(2.75·5) = 1.125/13.75 = 0.0818; ½ of that: 0.041. Plus ½|r-diff|: |r(w)| + |r(w₀)| ≤ 1.2/|w|² + 1.2/|w₀|² ≤ 1.2/2.75² + 1.2/25 = 1.2/7.5625 + 0.048 = 0.1587+0.048 = 0.2067; ½·that = 0.103. Total piece 6: 0.374 + 0.041 + 0.103 = 0.518?!? Over the 0.30 budget. Hmm. The slack: my |log ratio| bound 0.598 is lossy (D-056 had ½|log| ≤ 0.23 ⟹ |log| ≤ 0.46 — via the arg ≤ 4.5/|t| AND |log|s/s₀|| ≤ 0.02: √(0.46²... 0.02² + 0.45² = 0.2029: √ = 0.4504; ½ = 0.225 ✓). The |log|s/s₀|| ≤ 0.02: |s|/|s₀|: |s| = √(σ²+t²), |s₀| = √(4+t²): ratio² = (σ²+t²)/(4+t²) ∈ [(t²+... for σ ∈ [−2.5,3]: σ² ≤ 9: ratio² ≤ (9+t²)/(4+t²) ≤ 9/4: |s|/|s₀| ≤ 1.5: |log ratio| ≤ log 1.5 = 0.405?? D-056 said 0.02?! Let me recheck: |s|/|s₀| for σ ∈ [−2.5, 3], t = 10: σ = 3: |s| = √(9+100) = 10.44; |s₀| = √104 = 10.198: ratio 1.024: log = 0.0237. σ = −2.5: |s| = √(6.25+100) = 10.307: ratio 1.0107: log = 0.0106. So |log ratio| ≤ 0.024 at t = 10 ✓ D-056's 0.02-ish. My |w|/|w₀| bound used |w| ≥ |im w| only — lossy; the correct one uses |w| = |s|/2 ≥ √(t²+0)/2 = t/2·... |s| ≥ t (|s| ≥ |im| = t ✓) and |s| ≤ √(9+t²) ≤ t·√(1+9/100) = 1.045t·... ratio |s|/|s₀| ∈ [t/√(4+t²)·... let me just: |s|/|s₀| ∈ [√(t²)/√(t²+4)·(min over σ...)]: min |s| = t (σ = 0 ∈ range ✓), min |s₀| = √(4+t²): ratio_min = t/√(t²+4) ≥ 10/√104 = 0.9806: log ≥ −0.0196. max |s| = √(9+t²) (σ = 3), |s₀| = √(4+t²): ratio = √(9+t²)/√(4+t²) ≤ √(109/104) = 1.0237: log ≤ 0.0234. So |log|s/s₀|| ≤ 0.024 at t=10, decreasing ✓. arg: |arg s − arg s₀| — both in the upper half plane: arg s = π/2 − arctan(σ/t)-ish: |arg s − arg s₀| = |arctan(σ/t) − arctan(2/t)| ≤ |σ−2|/t ≤ 4.5/t = 0.45 (arctan Lipschitz 1/(1+x²) ≤ 1). Hmm — is |arg s − arg s₀| ≤ |σ − 2|/t right? arg s = atan2(t, σ): for σ > 0: arg s = arctan(t/σ)... ugh — the clean bound: |arg(s/s₀)| = |arg(1 + (s−s₀)/s₀)| ≤ 2·|s−s₀|/|s₀|·... For |u| ≤ 1/2: |arg(1+u)| ≤ ... the log: |log(1+u)| ≤ 2|u| covers both. Alternatively just use |log(1+u)| ≤ 2|u| with |u| = |s−s₀|/|s₀| ≤ 4.5/10.198 = 0.441: |log(s/s₀)| ≤ 2·0.441 = 0.883 — too lossy. The tight route: |log(1+u)| ≤ |u|/(1−|u|) = 0.441/0.559 = 0.789 — still lossy. D-056's arg/modulus split gives 0.45. The Mathlib lemma for the split: Complex.log (1+u) = log|1+u| + i·arg(1+u): ‖log(1+u)‖ = √(log²|1+u| + arg²): needs the arg bound |arg(1+u)| ≤ ... For |u| < 1: |arg(1+u)| ≤ arcsin(|u|)-ish ≤ 2|u|·... Hmm — actually a cleaner classical bound: |log(1+u)| ≤ |u|·(1 + |u|/2 + |u|²/3+...) = |u|·(−log(1−|u|))/|u|·... = −log(1−|u|)·... the power series: log(1+u) = Σ u^k/k·(−1)^{k+1}: |log(1+u)| ≤ Σ |u|^k/k = −log(1−|u|) ✓ (norm of the series ≤ the series of norms — needs the absolute convergence — fine for |u| < 1). −log(1−x) ≤ x·(1 + x/2·(1/(1−x))·...) ≤ x/(1−x) ✓. So |log(s/s₀)| ≤ −log(1−0.441) = 0.581·... hmm −log(0.559) = 0.582. Still 0.582 vs D-056's 0.45. The difference: D-056 separates modulus (0.024) and arg (0.45) and takes the NORM of the complex log: √(0.024² + 0.45²) = 0.451 — the Pythagorean saving. To get the arg bound in Lean: |arg(1+u)| ≤ 2|u| for |u| ≤ 1/2-ish — is there a Mathlib lemma? `Complex.abs_arg_le...`? There's `Complex.abs_arg_le_pi_div_two`? or the abs of the imaginary part of log: |Im(log(1+u))| = |arg(1+u)| ≤ |log(1+u)|... circular. Hmm. There might be `Complex.norm_log_one_add_le`... OK — piece 6's exact form needs care but the budget: the total const budget is 48 − (pinch max) ≈ 48 + 0.57 = 48.57 (the pinch LL-term is NEGATIVE at the max, so the constraint is const ≤ 48 + 0.57·... — wait no: the constraint is 11.813·LL − 4.560·L + const ≤ 48 for ALL L ≥ 2.485; the max of (11.813·LL − 4.560·L) is −0.568; so const ≤ 48 − (−0.568) = 48.568. My pieces: 0.9956 + 2.7 + 42.599 + 0.09 + p6 ≤ 48.568 ⟺ p6 ≤ 2.18. So piece 6 has budget 2.18, not 0.30!! (D-056's 0.29 was part of HIS fold where the constant 47.84 left 0.16... his fold was tight differently.) With my sharper piece 3 (S₃ = 1.3703), the piece-6 budget is 2.18 — the CRUDE digamma bound (½|ψ-diff| ≤ ½|log(w/w₀)| + ½·(remainder sums)) with even a lossy remainder fits: |ψ(w)−ψ(w₀)| ≤ |log(w/w₀)| + |r(w)| + |r(w₀)| + |1/(2w)−1/(2w₀)|: with 5d's crude ‖ψ(w) − log w‖ ≤ 3: |ψ-diff| ≤ |log(w/w₀)| + 6 — too big (6 > 2·2.18). With the middle route: ψ(w) = log w − 1/(2w) + r with |r| ≤ C/|w|²... the level-2 EM gives |r| ≤ (1/12)·∫₀^∞ dx/|x+w|³·... For |im w| ≥ 5: |x+w| ≥ ... the integral ∫₀^∞ dx/|x+w|³: |x+w| ≥ √(x² + 25)... ∫₀^∞ dx/(x²+25)^{3/2} = [x/(25·√(x²+25))]₀^∞ = 1/25: so |r(w)| ≤ (1/12)·(1/25)·2?... hmm the EM form: ψ(w) = log w − 1/(2w) − ∫₀^∞ B̃₂(x)/(x+w)³ dx·(some factor): |B̃₂| ≤ 1/12: |∫| ≤ (1/12)·∫₀^∞ dx/|x+w|³ = (1/12)·(1/|im w|²)·∫₀^∞ du/(u²+1)^{3/2}·(u = x/|im|) — ∫₀^∞ du/(1+u²)^{3/2} = 1: so |r(w)| ≤ 1/(12·|im w|²)·... = 1/(12·(t/2)²) = 1/(3t²)·... hmm wait: ∫₀^∞ dx/|x+w|³ with |x+w| ≥ √(x² + (t/2)²): ∫₀^∞ dx/(x²+c²)^{3/2} = 1/c² (c = t/2): so |r| ≤ (1/12)·(1/c²) = 1/(12·(t/2)²)·... = 4/(12t²) = 1/(3t²). At t = 10: 1/300 = 0.0033!! Tiny. So piece 6: |ψ(w)−ψ(w₀)| ≤ |log(w/w₀)| + (1/2)|1/w − 1/w₀| + 2/(3t²)·... ≤ 0.582 + 0.0818 + 0.0067 = 0.67; ½·0.67 = 0.335 ≤ 2.18 ✓✓ EASY. Even the lossy |log(1+u)| ≤ −log(1−|u|) = 0.582 works. GREAT — piece 6 is comfortable with the level-2 EM remainder (the LiRBound b2Fun machinery) + the crude log bound. So the full 5f assembly is FEASIBLE with margin ~1.9, all pieces elementary-ish. The remaining big piece is piece 3 (the interval machine). Piece 1's integral (∫ log x/x²) — clean antiderivative. Let me now update D-069 §3 with these refined constants (the S₃ telescope form, the budgets) — actually the design doc says enough; the journal will record the refinements. Let me continue building: piece 1 next (dirichletC2 ≤ 0.9956... let me set the target: 0.1733+0.1223+0.7 = 0.9956 — prove dirichletC2 ≤ 0.9956). Actually — for Lean convenience, let me use the bound dirichletC2 ≤ 1 (rounder)! Budget check: piece 1 ≤ 1: total const = 1 + 2.7 + 42.599 + 0.09 + 0.335 = 46.724 ≤ 48.568 ✓ margin 1.84. So dirichletC2 ≤ 1 suffices!! And that's cleaner to prove (the fold: (log 2)/4 + (log 3)/9 + (log 3+1)/3 ≤ 1 ⟺ with log 2 ≤ 0.6932, log 3 ≤ 1.1: 0.1733+0.1223+0.7 = 0.9956 ≤ 1 ✓). dirichletC2 ≤ 1. That's the target. The steps: 1. term-norm form: ‖LSeries.term Λ 2 n‖ = if n = 0 then 0 else (Λ n)/n² (real-valued). 2. Summable g (g n = Λ n / n²): from the LSeries abs-summability — how did norm_logDeriv_zeta_le_dirichlet handle it? Let me look at its proof for the summability input. 3. g n ≤ log n/n² (vonMangoldt_le_log). 4. Σ' g ≤ head + tail with tail ≤ ∫₃^∞ log x/x² = (log 3+1)/3 ≤ 0.7. For step 2, let me read norm_logDeriv_zeta_le_dirichlet's proof to reuse its summability.
Piece 1 next. Checking how `norm_logDeriv_zeta_le_dirichlet` handles the summability (for reuse).
tool: Read
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiCircleBound.lean",
  "offset": 206,
  "limit": 45
}
#1732 assistant 2026-08-24 09:33:54.101 UTC · 22750→3786 tok open ⤢
thinking (8978 chars)
The summability: `ArithmeticFunction.LSeriesSummable_vonMangoldt (h : 1 < s.re)` + `summable_norm_iff`. ✓ Now write piece 1. The steps: ```lean /-- The term-norm form: ‖LSeries.term Λ 2 n‖ = if n = 0 then 0 else Λ n / n². -/ lemma dirichletTerm_norm_eq (n : ℕ) : ‖LSeries.term (fun n => (ArithmeticFunction.vonMangoldt n : ℂ)) (2 : ℂ) n‖ = if n = 0 then (0 : ℝ) else (ArithmeticFunction.vonMangoldt n) / (n : ℝ) ^ 2 := by rcases eq_or_ne n 0 with rfl | hn · simp [LSeries.term] · rw [LSeries.term_def, if_neg hn] -- ‖(Λ n : ℂ) / (n:ℂ)^(2:ℂ)‖ = Λ n / n² rw [norm_div] have h1 : ‖((ArithmeticFunction.vonMangoldt n : ℂ))‖ = ArithmeticFunction.vonMangoldt n := by -- Λ n : ℂ is a nonneg real cast rw [show (ArithmeticFunction.vonMangoldt n : ℂ) = ((ArithmeticFunction.vonMangoldt n : ℝ) : ℂ) by push_cast; ring, Complex.norm_real] exact abs_of_nonneg ArithmeticFunction.vonMangoldt_nonneg have h2 : ‖((n : ℂ)) ^ (2 : ℂ)‖ = (n : ℝ) ^ 2 := by have hn0 : (0 : ℝ) < n := by exact_mod_cast Nat.pos_of_ne_zero hn... -- ‖(n:ℂ)^(2:ℂ)‖ = (n:ℝ)^((2:ℂ).re) = n^2 rw [Complex.norm_cpow_eq_rpow_re_of_pos ...] hmm ``` The cpow norm: `Complex.norm_cpow_eq_rpow_re_of_pos (hx : 0 < x) (s : ℂ) : ‖(x : ℂ) ^ s‖ = x ^ s.re`? Let me check the exact name. In Mathlib: `Complex.norm_cpow_eq_rpow_re_of_pos (hx : 0 < x) : ‖(x : ℂ) ^ y‖ = x ^ y.re` — I think it's `Complex.norm_cpow_eq_rpow_re_of_pos`. Then ((2:ℂ).re = 2) and (n:ℝ)^(2:ℝ) = n² via Real.rpow_two? `Real.rpow_two (x) : x^(2:ℝ) = x^2`? there's rpow_two : x ^ (2:ℝ) = x * x. Then n*n = n² ring. OK. But hmm — is (n:ℂ)^(2:ℂ) a cpow — the term is f n / n^s with n : ℕ coerced and s : ℂ — n^s is `HPow ℂ ℂ` = cpow ✓. Alternatively avoid the cpow-norm: ‖(n:ℂ)^(2:ℂ)‖ = ‖(n:ℂ)‖^2 via... there's `Complex.norm_cpow_natCast`? hmm. Simplest might be: (n:ℂ)^(2:ℂ) = (n:ℂ)^2 (cpow with a natCast exponent: `cpow_two`? no — (x:ℂ)^((2:ℕ):ℂ) = x^2 via `cpow_natCast`? hmm: `Complex.cpow_natCast (x : ℂ) (n : ℕ) : x ^ (n : ℂ) = x ^ n`? I believe `cpow_natCast` exists (x ^ (↑n) = x ^ n). Then norm: ‖(n:ℂ)²‖ = ‖(n:ℂ)‖² = n² (norm_pow + Complex.norm_natCast). Let me use that: `Complex.cpow_natCast`? hmm the name could be `cpow_natCast` in root namespace. Check at build. Then: ```lean /-- dirichletC2 = Σ' Λ(n)/n² (the nonzero terms). -/ lemma dirichletC2_eq : dirichletC2 = ∑' n : ℕ, if n = 0 then (0 : ℝ) else ArithmeticFunction.vonMangoldt n / (n : ℝ) ^ 2 := by rw [dirichletC2] exact tsum_congr fun n => dirichletTerm_norm_eq n ``` Then: ```lean theorem dirichletC2_le_one : dirichletC2 ≤ 1 := by rw [dirichletC2_eq] -- majorant g n = if n = 0 then 0 else log n / n² ... ``` Plan: - hsum: Summable (fun n => if n = 0 then 0 else Λ n/n²) — from the LSeries summability via the norm form (the dirichletTerm_norm_eq congr + hsum2-style). - hlog: Summable (fun n => if n = 0 then (0:ℝ) else Real.log n / n²) — via the integral test (antitone tail) or from... hmm, need summability for tsum_le_tsum. The log n/n² summability: `Summable` of n ↦ log n/n²: from the comparison with n^{−3/2}·(log n/√n → 0)... or directly via the integral test (AntitoneOn.summable_of_integrableOn_Ioi_zero needs Ici 0 antitone — log x/x² is NOT antitone on [0, e^{1/2}]). Alternative: summable_nat_add_iff: Σ_{n≥4} log n/n² summable + finite head. The tail's summability from the integral test (f antitone on Ici 3 ✓ + integrable on Ioi 3 ✓ from the FTC). So hlog := (summable_nat_add_iff 4).mpr (tail summable). The exact lemma: `summable_nat_add_iff (k : ℕ) : Summable (fun n => f (n + k)) ↔ Summable f` ✓ exists. - tsum_le_tsum pointwise (Λ n ≤ log n) then the log-series bound: Σ' logseries = Σ_{n<4} + Σ_{n≥4}: via sum_add_tsum_nat_add 4: ∑' n, f n = (∑ n ∈ range 4, f n) + ∑' n, f (n+4): head: f 0 = 0 (if-pos), f 1 = log 1/1 = 0, f 2 = log 2/4, f 3 = log 3/9. Tail: ∑' n, log(n+4)/(n+4)² ≤ ∫ Ioi 3 (log x/x²) via AntitoneOn.tsum_comp_add_le_integral (N := 3): ∑' n, f(n+3+1) = ∑' n, f(n+4) ✓ with f x = log x/x², anti on Ici 3, integrable on Ioi 3, nonneg on Ioi 3. - The integral = (log 3 + 1)/3 via integral_Ioi_of_hasDerivAt_of_tendsto' with F = −(log x + 1)/x → 0. - The numeric fold: log 2/4 + log 3/9 + (log 3+1)/3 ≤ 1: with log 2 ≤ 0.6932 (Real.log_two_lt_d9 : log 2 < 0.6931471808), log 3 ≤ 1.1 (via e^1.1 ≥ 3.00126 partial sum): 0.6932/4 + 1.1/9 + (1.1+1)/3 = 0.1733 + 0.1223 + 0.7 = 0.9956 ≤ 1 ✓. The antitone condition for f(x) = log x/x² on Ici 3: via deriv ≤ 0 — needs deriv of log x/x² = (1−2log x)/x³ ≤ 0 for x ≥ 3 (log 3 ≥ 1.0986 ≥ 1/2 — needs log 3 ≥ 1/2: from log 3 ≥ log e^{1/2}... e^{1/2} ≤ 1.65 ≤ 3 ✓ via exp(1/2) partial sum: e^{0.5} ≤ ... hmm Real.exp_one_lt_d9 : e < 2.7182818286; e^{1/2} ≤ 1.65: via exp partial sums: e^{0.5} ≤ Σ_{k≤4} 0.5^k/k! + tail: 1+0.5+0.125+0.0208+0.0026+... ≈ 1.6487 ≤ 1.65 ✓ — the Lean route: Real.exp_le_of... there's `Real.exp_one_lt_d9` for e¹; for e^{0.5} there's... `Real.exp_half_...`? Hmm. Alternative: log 3 ≥ 1: 3 ≥ e ⟸ Real.exp_one_lt_d9 (e ≤ 2.7183 ≤ 3) + Real.log_le_log (0 < e) (e ≤ 3): log e = 1 ≤ log 3 ✓✓ — `Real.log_le_iff_le_exp`? or Real.log_exp: log (exp 1) = 1 ≤ log 3 via Real.log_le_log (exp_pos 1) (by linarith [Real.exp_one_lt_d9.le] : exp 1 ≤ 3) ✓ clean!). So log 3 ≥ 1 ⟹ for x ≥ 3: 2 log x ≥ 2 ⟹ 1 − 2 log x ≤ −1 < 0 ⟹ deriv f x = (1 − 2 log x)/x³ ≤ 0 ⟹ antitone via antitoneOn_of_deriv_nonpos (convex (Ici 3)) (continuousOn f) (differentiableOn interior) (deriv ≤ 0). ContinuousOn f: log x/x² continuous on Ici 3 (x ≠ 0) ✓ via ContinuousOn.div (Real.continuousOn_log... (Real.continuousOn_log : ContinuousOn log {0}ᶜ) hmm — `Real.continuousOn_log : ContinuousOn Real.log {0}ᶜ` ✓ I believe). DifferentiableOn: similar. deriv f x: deriv (fun x => log x/x²) x = ... via deriv_div (hasDerivAt...). ~50 lines. The Ioi-FTC: integral_Ioi_of_hasDerivAt_of_tendsto' (hderiv : ∀ x ∈ Ici a, HasDerivAt F (f' x) x) (f'int) (hlim : Tendsto F atTop (𝓝 m)) : ∫ Ioi a f' = m − F a. With F = fun x => −(log x + 1)/x, f' x = log x/x²: - hderiv: HasDerivAt (fun x => −(log x + 1)/x) (log x/x²) x for x ≥ 3: from HasDerivAt.div of (log + 1) and id: (hasDerivAt_log'?). Real.hasDerivAt_log (hx : x ≠ 0) : HasDerivAt log (1/x) x ✓. (.add_const 1) : HasDerivAt (fun x => log x + 1) (1/x) x ✓ (HasDerivAt.add_const). Then .div (hasDerivAt_id' x) (hx0 : x ≠ 0)... HasDerivAt.div (hc : HasDerivAt c c' x) (hd : HasDerivAt d d' x) (hd0 : d x ≠ 0) : HasDerivAt (fun y => c y / d y) ((c' * d x − c x * d') / (d x)^2) x. With c = log+1, c' = 1/x, d = id, d' = 1: ((1/x)·x − (log x + 1)·1)/x² = (1 − log x − 1)/x² = −log x/x². So the div gives HasDerivAt ((log+1)/id) (−log x/x²) x — then .neg: HasDerivAt (−(log+1)/x) (log x/x²) x ✓. The value form needs convert/field_simp+ring to match log x / x^2. The function form: (fun y => (log y + 1)/y) vs (fun x => −(log x + 1)/x).neg — (fun y => −((log y+1)/y)) vs (fun y => −(log y + 1)/x)... should be fine via congr/ring_nf. - f'int: IntegrableOn (fun x => log x/x²) (Ioi 3): via `integrableOn_Ioi_deriv_of_nonneg'` — wait — from the example: integrableOn_Ioi_deriv_of_nonneg' (c) (F) (hlim : Tendsto F atTop (𝓝 0))? (hderiv : ∀ x ∈ Ioi c, HasDerivAt F (f x) x) (hnonneg : ∀ x ∈ Ioi c, 0 ≤ f x): IntegrableOn f (Ioi c) — hmm the example called `integrableOn_Ioi_deriv_of_nonneg' _ _ tendsto_log_atTop.inv_tendsto_atTop.neg` then two goals (hasDerivAt, nonneg). So signature: integrableOn_Ioi_deriv_of_nonneg' (a : ℝ) (F : ℝ → ℝ) (hF : Tendsto F atTop (𝓝 0)) (hderiv : ∀ x ∈ Ioi a, ...) (hpos : ∀ x ∈ Ioi a, 0 ≤ f' x)? Roughly. I'll mimic. - hlim: Tendsto (fun x => −(log x + 1)/x) atTop (𝓝 0): (log x + 1)/x = log x/x + 1/x: tendsto: Real.tendsto_log_div_atTop? — check name: I believe `Real.tendsto_log_div_atTop : Tendsto (fun x => Real.log x / x) atTop (𝓝 0)` — hmm might not exist by that name; there IS `Real.tendsto_pow_div_exp...`? For log x / x → 0: it's a special case of `Real.tendsto_log_div_rpow...`? or `tendsto_div_log_...`? There's `Real.tendsto_log_div_atTop` — I'm fairly confident (in Analysis/SpecialFunctions/Log/Deriv... or Limits). If missing: log x/x = (1/x)·log x — bound |log x/x| ≤ 2/√x·... via log x ≤ 2√x hmm — or Real.tendsto_log_div_atTop exists. Check at build. Then (log x + 1)/x = log x/x + 1/x → 0 + 0: Tendsto.add + tendsto_one_div_atTop... `tendsto_one_div_atTop_nhds_zero`? hmm: Tendsto (fun x => 1/x) atTop (𝓝 0) = `tendsto_one_div_atTop_nhds_zero` ✓-ish. Then .neg for the outer minus. OK — I have the full plan for piece 1. Let me also plan piece 6 (digamma) since it's the other 5f-ii piece, then decide what to build tonight. Actually — time: it's ~1:45 AM. Piece 1 is ~150 lines. Let me build piece 1 now, then checkpoint. Piece 3 and 6 are the big ones for 5f-ii. Actually — wait. Let me reconsider whether to include piece 1 tonight. It's self-contained but involves the integral plumbing. Let me try — if it gets stuck, I'll bank the state and leave it for the next session. Let me write piece 1 into LiTightR.lean (§7).
The summability route is clear (`ArithmeticFunction.LSeriesSummable_vonMangoldt` + `summable_norm_iff`). Writing piece 1 (dirichletC2 ≤ 1) — the integral-test tail with the clean antiderivative −(log x + 1)/x.
tool: Bash
input
{
  "command": "M=D:/Python/Quantum/zeta-23-lean/.lake/packages/mathlib/Mathlib; grep -rn \"theorem tendsto_log_div_atTop\\|tendsto_log_div_atTop\" $M --include=\"*.lean\" | head -2; grep -rn \"theorem cpow_natCast\\|cpow_natCast\" $M/Analysis/SpecialFunctions/Pow/Complex.lean | head -2; grep -rn \"theorem.*summable_nat_add_iff\" $M --include=\"*.lean\" | head -2; grep -rn \"integrableOn_Ioi_deriv_of_nonneg'\" $M --include=\"*.lean\" | head -3",
  "description": "Verify tendsto_log_div_atTop, cpow_natCast, summable_nat_add_iff, integrableOn_Ioi_deriv_of_nonneg'"
}
#1733 assistant 2026-08-24 09:38:37.902 UTC · 924→8363 tok open ⤢
thinking (9505 chars)
`tendsto_pow_log_div_mul_add_atTop (a b : ℝ) (n : ℕ) (ha : a ≠ 0) : Tendsto (fun x => log x ^ n / (a * x + b)) atTop (𝓝 0)`. With a = 1, b = 0, n = 1: Tendsto (fun x => log x / (1·x + 0)) atTop (𝓝 0) = log x / x → 0 ✓. So: (log x + 1)/x = log x/x + 1/x → 0: ```lean have hlim : Tendsto (fun x => Real.log x / x) atTop (𝓝 0) := by have h := tendsto_pow_log_div_mul_add_atTop 1 0 1 one_ne_zero -- h : Tendsto (fun x => log x ^ 1 / (1 * x + 0)) atTop (𝓝 0) convert h using 1 -- log x^1/(1*x+0) = log x/x · ext x; simp · simp ``` Hmm — `convert h using 1` then prove the function equality: (fun x => log x ^ 1 / (1*x+0)) = (fun x => log x / x): ext x; simp (pow_one, mul_one, add_zero) ✓ maybe just `simpa using h`. Then F(x) = −(log x + 1)/x = −(log x/x + 1/x): ```lean have hFlim : Tendsto (fun x => -(Real.log x + 1)/x) atTop (𝓝 0) := by have h1 : Tendsto (fun x => (Real.log x + 1)/x) atTop (𝓝 0) := by have hA : Tendsto (fun x => Real.log x / x + 1 / x) atTop (𝓝 (0 + 0)) := hlim.add tendsto_one_div_atTop_nhds_zero -- hmm: (log x + 1)/x = log x/x + 1/x — congr have heq : (fun x => (Real.log x + 1)/x) = (fun x => Real.log x / x + 1 / x) := by ext x; ring_nf -- (log x + 1)/x = log x/x + 1/x: ring with division: (a+b)/c = a/c + b/c — `add_div`: ring_nf should handle rw [heq] simpa using hA exact h1.neg ... ``` Hmm — `tendsto_one_div_atTop_nhds_zero` — exact name: `tendsto_one_div_atTop_nhds_zero : Tendsto (fun x => 1 / x) atTop (𝓝 0)`? There's `tendsto_one_div_atTop_nhds_zero` in Topology/Algebra/Order/... I think ✓. Check at build. The neg: −(log x + 1)/x vs −((log x + 1)/x): neg_div: −(a/b) = (−a)/b — the function (fun x => -(log x + 1)/x) parses as (−(log x + 1))/x and h1.neg : Tendsto (fun x => −((log x + 1)/x)) — these differ by neg_div — `simpa [neg_div] using h1.neg` or convert. Also for hF (the HasDerivAt of F): F = fun x => −(log x + 1)/x. The derivative: I'll compute via HasDerivAt: ((Real.hasDerivAt_log hx0).add_const 1) : HasDerivAt (fun x => Real.log x + 1) (1/x) x — wait add_const : HasDerivAt (fun x => log x + 1) (1/x + 0)? — HasDerivAt.add_const (c) : HasDerivAt (fun x => f x + c) f' x. Then .div (hasDerivAt_id' x) hx0? — hmm hasDerivAt_id' might be `hasDerivAt_id' : HasDerivAt id 1 x`? and .div: HasDerivAt.div (hc) (hd : HasDerivAt d d' x) (hd0 : d x ≠ 0) : HasDerivAt (fun y => c y / d y) ((c' * d x − c x * d') / (d x)^2) x. So the value: ((1/x)·x − (log x + 1)·1)/x². Then .neg : HasDerivAt (fun y => −((log y+1)/y)) (−((1/x·x − (log x+1)·1)/x²)) x. I need HasDerivAt F (log x/x²) x where F = fun x => −(log x + 1)/x: (i) function match: −(log x + 1)/x vs −((log x + 1)/x) — neg_div defeq ✓ or via congr. (ii) value match: −((1/x·x − (log x+1))/x²) = log x/x² for x ≠ 0: field_simp + ring or: 1/x·x = 1 (div_mul_cancel₀): −((1 − (log x + 1))/x²) = −(−log x/x²) = log x/x² ✓. In Lean: `convert ... using 1` then `field_simp; ring`? Or compute: have : −((1/x * x - (Real.log x + 1) * 1) / x^2) = Real.log x / x^2 := by field_simp; ring — hmm field_simp with x ≠ 0: clears x, x²: LHS·x² = −(1 − (log x+1))·... field_simp might produce a polynomial identity. Let me write it as: ```lean have hderiv (x : ℝ) (hx : 3 ≤ x) : HasDerivAt (fun y => -(Real.log y + 1)/y) (Real.log x / x^2) x := by have hx0 : x ≠ 0 := by positivity? (x ≥ 3 ⟹ x ≠ 0: by linarith) have h1 := ((Real.hasDerivAt_log hx0).add_const 1).div (hasDerivAt_id x) hx0 -- h1 : HasDerivAt (fun y => (log y + 1)/y) ((1/x * x - (log x + 1) * 1)/x^2) x have h2 := h1.neg -- h2 : HasDerivAt (fun y => -((log y + 1)/y)) (-((1/x * x - (log x + 1) * 1)/x^2)) x convert h2 using 1 · ext y; rw [neg_div] · field_simp; ring ``` Hmm — the .div's function: HasDerivAt.div's conclusion function is fun y => c y / d y where c = fun y => log y + 1, d = id: (log y + 1)/(id y) = (log y + 1)/y ✓ (id y = y defeq — might need simp only [id_eq]). hasDerivAt_id vs hasDerivAt_id': the banked form was `hasDerivAt_id' s₀` ✓. The antitone condition: f(x) = log x/x² = F'(x). AntitoneOn f (Ici 3): via antitoneOn_of_deriv_nonpos? Hmm — actually with the hderiv in hand, maybe use `StrictAntiOn`/`AntitoneOn` from the derivative: the cleanest: `antitoneOn_of_hasDerivWithinAt_nonpos`? or use monotonicity of... f(x) = log x/x² — antitone for x ≥ e^{1/2}: Alternatively use the ratio form: for 3 ≤ x ≤ y: log x/x² ≥ log y/y² ⟺ ... messy directly. Use the deriv route: Mathlib lemma `antitoneOn_of_deriv_nonpos (hD : Convex ℝ D) (hf : ContinuousOn f D) (hf' : DifferentiableOn ℝ f (interior D)) (h : ∀ x ∈ interior D, deriv f x ≤ 0)`. deriv f x = (1 − 2 log x)/x³ — needs deriv computation: deriv (fun x => log x / x^2) — via hderiv's HasDerivAt: hderiv gives HasDerivAt F (f x) — wait that's the OTHER direction (F's derivative is f). For f's own derivative: deriv (log x/x²) = ((1/x)·x² − log x·2x)/x⁴ = (x − 2x log x)/x⁴ = (1 − 2 log x)/x³ ✓ via deriv_div... In Lean: (Real.deriv log...)... Use `(Real.hasDerivAt_log hx0).div (hasDerivAt_pow 2 x)?` — hmm: deriv (fun x => log x / x^2) via HasDerivAt.div (log) (x^2): ((1/x)·x² − log x·(2x))/(x²)². Then show ≤ 0 for x ≥ 3: (1 − 2 log x)/x³ ≤ 0 ⟸ 1 − 2 log x ≤ 0 ⟸ log x ≥ 1/2 ⟸ log 3 ≥ 1 ≥ 1/2 and log mono. Then HasDerivAt.deriv to get deriv = that value. OK ~40 lines. Alternatively — the antitone of f(x) = log x/x² could avoid derivs: f(x) = log x · x⁻² — not a product of antitone functions (log is increasing). So deriv route needed. Fine. The IntegrableOn: integrableOn_Ioi_deriv_of_nonneg' (hderiv on Ici 3 ✓) (g'pos: ∀ x ∈ Ioi 3, 0 ≤ log x/x² ✓ log x ≥ log 3 > 0) (hg : Tendsto F atTop (𝓝 0) — wait the signature: (hg : Tendsto g atTop (𝓝 l)) with g = F (the antiderivative): Tendsto F atTop (𝓝 0) ✓ hFlim). Then ∫ Ioi 3 f = 0 − F(3) = (log 3 + 1)/3 via integral_Ioi_of_hasDerivAt_of_tendsto' hderiv f'int hFlim : ∫ x in Ioi 3, f x = 0 − F 3. F 3 = −(log 3 + 1)/3. So ∫ = (log 3 + 1)/3 ✓. Then the tail bound: Σ_{n≥4} f n ≤ ∫ Ioi 3 f via AntitoneOn.tsum_comp_add_le_integral (N := 3): gives ∑' n, f (↑(n + 3 + 1)) ≤ ∫ Ioi 3 — f (↑(n+4)) with the Nat cast: f ((n+4 : ℕ) : ℝ) = log (n+4)/(n+4)² ✓. Need the cast form to match the tail ∑' n, f (n+4 : ℕ) — exact_mod_cast or push_cast. Then the assembly: ``` dirichletC2 = ∑' n, g n (g n = if n = 0 then 0 else Λ n/n²) ≤ ∑' n, h n (h n = if n = 0 then 0 else log n/n²) [tsum_le_tsum; pointwise: n=0: 0 ≤ 0 ✓; n ≥ 1: Λ n ≤ log n / n² — div monotone ✓] = (h 0 + h 1 + h 2 + h 3) + ∑' n, h (n+4) [sum_add_tsum_nat_add 4] = (0 + 0 + log 2/4 + log 3/9) + tail ≤ 0.1733 + 0.1223 + (log 3 + 1)/3 ≤ 0.1733 + 0.1223 + 0.7 = 0.9956 ≤ 1 ``` The head sum: ∑ n ∈ range 4, h n = h 0 + h 1 + h 2 + h 3: expand via Finset.sum_range_succ four times or `decide`-free: range 4 = {0,1,2,3}: Finset.sum_range... The values: h 0 = 0 (if_pos rfl), h 1 = if neg (1 ≠ 0) = log 1/1 = 0/1 = 0 (Real.log_one), h 2 = log 2/4: ((2:ℕ):ℝ)² = 4: push_cast + norm_num, h 3 = log 3/9. The if-neg for n = 1,2,3: if_neg (by norm_num : (2:ℕ) ≠ 0). Routine. sum_add_tsum_nat_add: `sum_add_tsum_nat_add (k : ℕ) (hf : Summable f) : ∑' n, f n = ∑ n ∈ range k, f n + ∑' n, f (n + k)`? Hmm the name — in this Mathlib: `sum_add_tsum_nat_add`? I believe it's `sum_add_tsum_nat_add (k) (h : Summable f) : (∑ i ∈ range k, f i) + ∑' i, f (i + k) = ∑' i, f i` — direction! Might be the = direction flipped. Also the cast: f (i + k) with i + k : ℕ and f : ℕ → ℝ ✓. The banked gotcha (session 027): "sum_add_tsum_nat_add's shifted terms are beta-redexes (state goals in redex form)". OK. The summability of h (the log-majorant): Summable (fun n => if n = 0 then 0 else log n/n²): via the tail: Summable (fun n => h (n + 4)): from the integral test's summable: AntitoneOn.summable_of_integrableOn_Ioi... the lemma `AntitoneOn.summable_of_integrableOn_Ioi_zero` needs Ici 0; there's presumably `AntitoneOn.summable_of_integrableOn_Ioi (anti : AntitoneOn f (Ici N)) (integrable : IntegrableOn f (Ioi N)) (nonneg) : Summable (fun n => f (↑(n + N + 1)))`? From the proof of tsum_comp_add_le_integral, summability is implied. Hmm — actually for tsum_le_tsum I need Summable h. Let me get it from: Summable (fun n => h (n+4)) via the integral-test summability (the `summable_of_integrableOn_Ioi` mentioned at line 215-218: `AntitoneOn.summable_of_integrableOn_Ioi (anti : AntitoneOn f (Ici N)) (int : IntegrableOn f (Ioi N)) (nonneg) : Summable (fun n ↦ f (↑n + N + 1))`? from the first block: `summable_of_integrableOn_Ioi (N := 0) (mod_cast anti)...` — so `AntitoneOn.summable_of_integrableOn_Ioi` exists with an N. Then Summable h via (summable_nat_add_iff 4).mp/mpr: summable_nat_add_iff (k : ℕ) : Summable (fun n => f (n + k)) ↔ Summable f — for ℝ≥0?? The grep found it in NNReal/Lemmas.lean for ℝ≥0 — the ℝ version: `summable_nat_add_iff` should exist for general: it's in Topology/Algebra/InfiniteSum/Nat... `summable_nat_add_iff {f : ℕ → M} (k : ℕ) : Summable (fun n ↦ f (n + k)) ↔ Summable f` — hmm wait the grep found `Topology/Instances/NNReal/Lemmas.lean:187: nonrec theorem summable_nat_add_iff {f : ℕ → ℝ≥0}` — a NNReal specialization; the general one exists in `Mathlib.Topology.Algebra.InfiniteSum.Group` or similar as `summable_nat_add_iff`? The NNReal one is `nonrec` — suggesting the general one exists (the NNReal version is a re-derivation). The general: I believe `summable_nat_add_iff (k : ℕ) : Summable (fun n => f (n + k)) ↔ Summable f` in a normed group ✓. Check at build. OK — writing piece 1 now. This is the last piece for tonight (it's ~1:50 AM). Let me write it.
All the calculus machinery is confirmed available. Writing piece 1 (dirichletC2 ≤ 1) into LiTightR.lean.
tool: Edit
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean",
  "old_string": "/-! ## 6. Pieces 4/5: the reciprocal differences -/",
  "new_string": "/-! ## 6. Piece 1: the Dirichlet bound at the reference point -/\n\n/-- The Dirichlet term norm at 2: \u2016LSeries.term \u039b 2 n\u2016 = (if n = 0 then\n0 else) \u039b(n)/n\u00b2. -/\nlemma dirichletTerm_norm_eq (n : \u2115) :\n    \u2016LSeries.term (fun n => (ArithmeticFunction.vonMangoldt n : \u2102)) (2 : \u2102) n\u2016\n      = if n = 0 then (0 : \u211d)\n        else (ArithmeticFunction.vonMangoldt n) / (n : \u211d) ^ 2 := by\n  rcases eq_or_ne n 0 with rfl | hn\n  \u00b7 simp [LSeries.term]\n  \u00b7 rw [LSeries.term_def, if_neg hn, norm_div]\n    have h1 : \u2016(ArithmeticFunction.vonMangoldt n : \u2102)\u2016\n        = ArithmeticFunction.vonMangoldt n := by\n      rw [show (ArithmeticFunction.vonMangoldt n : \u2102)\n          = ((ArithmeticFunction.vonMangoldt n : \u211d) : \u2102) by push_cast; ring,\n        Complex.norm_real]\n      exact abs_of_nonneg ArithmeticFunction.vonMangoldt_nonneg\n    have h2 : \u2016((n : \u2102)) ^ (2 : \u2102)\u2016 = (n : \u211d) ^ 2 := by\n      rw [show ((n : \u2102)) ^ (2 : \u2102) = ((n : \u2102)) ^ (2 : \u2115) by\n            exact_mod_cast rfl, norm_pow]\n      rw [show ((n : \u2102)) = ((n : \u211d) : \u2102) by push_cast; ring, Complex.norm_real]\n      exact abs_of_nonneg (by positivity)\n    rw [h1, h2]\n\n/-- The integral of log x/x\u00b2 over Ioi 3 is (log 3 + 1)/3 (the\nantiderivative \u2212(log x + 1)/x \u2192 0). -/\nlemma integral_log_div_sq_Ioi_three :\n    \u222b x in Set.Ioi (3 : \u211d), Real.log x / x ^ 2 = (Real.log 3 + 1) / 3 := by\n  have hderiv : \u2200 x \u2208 Set.Ici (3 : \u211d),\n      HasDerivAt (fun y => -(Real.log y + 1) / y) (Real.log x / x ^ 2) x := by\n    intro x hx\n    have hx0 : x \u2260 0 := by\n      have : (3 : \u211d) \u2264 x := hx\n      linarith\n    have h1 := ((Real.hasDerivAt_log hx0).add_const 1).div (hasDerivAt_id' x) hx0\n    have h2 := h1.neg\n    have hval : -((x\u207b\u00b9 * x - (Real.log x + 1) * 1) / x ^ 2) = Real.log x / x ^ 2 := by\n      field_simp\n      ring\n    have hfn : (fun y => -((Real.log y + 1) / y)) = (fun y => -(Real.log y + 1) / y) := by\n      ext y\n      rw [neg_div]\n    rw [\u2190 hfn, hval] at *\n    exact h2\n  have hnonneg : \u2200 x \u2208 Set.Ioi (3 : \u211d), 0 \u2264 Real.log x / x ^ 2 := by\n    intro x hx\n    have hx3 : (3 : \u211d) < x := hx\n    have hlog : (0 : \u211d) \u2264 Real.log x := Real.log_nonneg (by linarith)\n    positivity\n  have hlim : Tendsto (fun y => -(Real.log y + 1) / y) atTop (\ud835\udcdd 0) := by\n    have hA : Tendsto (fun x => Real.log x / x) atTop (\ud835\udcdd 0) := by\n      have h := tendsto_pow_log_div_mul_add_atTop 1 0 1 one_ne_zero\n      simpa using h\n    have hB : Tendsto (fun x => (1 : \u211d) / x) atTop (\ud835\udcdd 0) :=\n      tendsto_one_div_atTop_nhds_zero\n    have hC : Tendsto (fun x => Real.log x / x + 1 / x) atTop (\ud835\udcdd (0 + 0)) :=\n      hA.add hB\n    have heq : (fun y => -(Real.log y + 1) / y) = (fun x => Real.log x / x + 1 / x) := by\n      ext x\n      rw [neg_div, add_div]\n    rw [heq]\n    simpa using hC\n  have hint : IntegrableOn (fun x => Real.log x / x ^ 2) (Set.Ioi (3 : \u211d)) volume :=\n    integrableOn_Ioi_deriv_of_nonneg' hderiv hnonneg (by simpa using hlim)\n  have h := integral_Ioi_of_hasDerivAt_of_tendsto' hderiv hint hlim\n  rw [h]\n  have hF3 : -(Real.log 3 + 1) / (3 : \u211d) = -(Real.log 3 + 1) / 3 := rfl\n  field_simp\n  ring\n\n/-- The tail bound: \u03a3_{n\u22654} log n/n\u00b2 \u2264 (log 3 + 1)/3 (integral test; f\nantitone on Ici 3 since its derivative (1 \u2212 2 log x)/x\u00b3 \u2264 0 for x \u2265 3\nas log x \u2265 log 3 \u2265 1). -/\nlemma tsum_log_div_sq_tail_le :\n    \u2211' n : \u2115, Real.log (n + 4) / (n + 4 : \u211d) ^ 2 \u2264 (Real.log 3 + 1) / 3 := by\n  have hanti : AntitoneOn (fun x => Real.log x / x ^ 2) (Set.Ici (3 : \u211d)) := by\n    apply antitoneOn_of_deriv_nonpos (convex_Ici 3)\n    \u00b7 -- continuity\n      intro x hx\n      have hx0 : x \u2260 0 := by have := (Set.mem_Ici.mp hx); linarith\n      exact (Real.continuousAt_log hx0).continuousWithinAt.div\n        (continuousWithinAt_pow _ _ _) (pow_ne_zero 2 hx0)\n    \u00b7 -- differentiability in the interior\n      intro x hx\n      have hx0 : x \u2260 0 := by\n        have : (3 : \u211d) < x := Set.mem_Ioi.mp (by simpa [Set.interior_Ici] using hx)\n        linarith\n      exact (Real.differentiableAt_log hx0).div (differentiableAt_pow _ _)\n        (pow_ne_zero 2 hx0) |>.differentiableWithinAt\n    \u00b7 -- derivative \u2264 0 in the interior\n      intro x hx\n      have hx3 : (3 : \u211d) < x := Set.mem_Ioi.mp (by simpa [Set.interior_Ici] using hx)\n      have hx0 : x \u2260 0 := by linarith\n      have hlog3 : (1 : \u211d) \u2264 Real.log 3 := by\n        have h := Real.log_le_log (Real.exp_pos 1) (by linarith [Real.exp_one_lt_d9.le] :\n          Real.exp 1 \u2264 3)\n        rwa [Real.log_exp] at h\n      have hlogx : (1 : \u211d) \u2264 Real.log x :=\n        hlog3.trans (Real.log_le_log (by positivity : (0 : \u211d) < 3) hx3.le)\n      have hderiv : deriv (fun y => Real.log y / y ^ 2) x\n          = (1 - 2 * Real.log x) / x ^ 3 := by\n        have h := (Real.hasDerivAt_log hx0).div (hasDerivAt_pow 2 x) (pow_ne_zero 2 hx0)\n        rw [h.deriv]\n        congr 1\n        field_simp\n        ring\n      rw [hderiv]\n      have hnum : (1 : \u211d) - 2 * Real.log x \u2264 0 := by linarith [hlogx]\n      exact div_nonpos_of_nonpos_of_nonneg hnum (by positivity)\n  have hnn : \u2200 t \u2208 Set.Ioi (3 : \u211d), 0 \u2264 Real.log t / t ^ 2 := by\n    intro t ht\n    have ht3 : (3 : \u211d) < t := ht\n    have hlog : (0 : \u211d) \u2264 Real.log t := Real.log_nonneg (by linarith)\n    positivity\n  have hint : IntegrableOn (fun x => Real.log x / x ^ 2) (Set.Ioi (3 : \u211d)) volume := by\n    rw [\u2190 integral_log_div_sq_Ioi_three] at *\n    exact integrableOn_Ioi_deriv_of_nonneg'\n      (fun x hx => (by\n        have hx0 : x \u2260 0 := by have := (Set.mem_Ici.mp hx); linarith\n        have h1 := ((Real.hasDerivAt_log hx0).add_const 1).div (hasDerivAt_id' x) hx0\n        have h2 := h1.neg\n        have hval : -((x\u207b\u00b9 * x - (Real.log x + 1) * 1) / x ^ 2) = Real.log x / x ^ 2 := by\n          field_simp; ring\n        have hfn : (fun y => -((Real.log y + 1) / y))\n            = (fun y => -(Real.log y + 1) / y) := by ext y; rw [neg_div]\n        rw [\u2190 hfn, hval] at *\n        exact h2))\n      hnn (by\n        have hA : Tendsto (fun x => Real.log x / x) atTop (\ud835\udcdd 0) := by\n          have h := tendsto_pow_log_div_mul_add_atTop 1 0 1 one_ne_zero\n          simpa using h\n        have hB : Tendsto (fun x => (1 : \u211d) / x) atTop (\ud835\udcdd 0) :=\n          tendsto_one_div_atTop_nhds_zero\n        have hC : Tendsto (fun x => Real.log x / x + 1 / x) atTop (\ud835\udcdd (0 + 0)) :=\n          hA.add hB\n        have heq : (fun y => -(Real.log y + 1) / y)\n            = (fun x => Real.log x / x + 1 / x) := by\n          ext x; rw [neg_div, add_div]\n        rw [heq]\n        simpa using hC)\n  have hle := hanti.tsum_comp_add_le_integral 3 hint hnn\n  have hrearrange : (\u2211' n : \u2115, Real.log (n + 4) / (n + 4 : \u211d) ^ 2)\n      = \u2211' n : \u2115, (fun x => Real.log x / x ^ 2) ((\u2191(n + 3 + 1) : \u2115) : \u211d) := by\n    refine tsum_congr fun n => ?_\n    have hcast : ((\u2191(n + 3 + 1) : \u2115) : \u211d) = (n : \u211d) + 4 := by push_cast; ring\n    rw [hcast]\n    have hcast2 : ((n : \u211d) + 4) = ((n + 4 : \u2115) : \u211d) := by push_cast; ring\n    rw [hcast2]\n  rw [hrearrange]\n  exact hle\n\n/-- **Piece 1** (D-069 \u00a73): dirichletC2 \u2264 1. The honest value is\n\u2212\u03b6\u2032/\u03b6(2) \u2248 0.56997; the bound here uses \u039b(n) \u2264 log n, the exact head\nn = 2, 3, and the integral-test tail (log 3 + 1)/3 \u2264 0.7. -/\ntheorem dirichletC2_le_one : dirichletC2 \u2264 1 := by\n  rw [dirichletC2]\n  -- the majorant h\n  set h : \u2115 \u2192 \u211d := fun n => if n = 0 then (0 : \u211d)\n    else Real.log n / (n : \u211d) ^ 2 with hh\n  have hsumm_g : Summable (fun n : \u2115 =>\n      \u2016LSeries.term (fun n => (ArithmeticFunction.vonMangoldt n : \u2102)) (2 : \u2102) n\u2016) := by\n    rw [summable_norm_iff]\n    exact ArithmeticFunction.LSeriesSummable_vonMangoldt (by norm_num)\n  have hterm : \u2200 n : \u2115,\n      \u2016LSeries.term (fun n => (ArithmeticFunction.vonMangoldt n : \u2102)) (2 : \u2102) n\u2016\n        = (if n = 0 then (0 : \u211d) else ArithmeticFunction.vonMangoldt n / (n : \u211d) ^ 2) :=\n    fun n => dirichletTerm_norm_eq n\n  have hle_pointwise : \u2200 n : \u2115,\n      \u2016LSeries.term (fun n => (ArithmeticFunction.vonMangoldt n : \u2102)) (2 : \u2102) n\u2016\n        \u2264 h n := by\n    intro n\n    rw [hterm n, hh]\n    rcases eq_or_ne n 0 with rfl | hn\n    \u00b7 simp\n    \u00b7 rw [if_neg hn, if_neg hn]\n      exact div_le_div_of_nonneg_right ArithmeticFunction.vonMangoldt_le_log\n        (by positivity : (0 : \u211d) \u2264 (n : \u211d) ^ 2)\n  -- summability of h via the tail\n  have htail_sum : Summable (fun n : \u2115 => Real.log (n + 4) / (n + 4 : \u211d) ^ 2) := by\n    -- from the integral comparison (reuse tsum_log_div_sq_tail_le's inputs)\n    have hnn : \u2200 t \u2208 Set.Ioi (3 : \u211d), 0 \u2264 Real.log t / t ^ 2 := by\n      intro t ht\n      have ht3 : (3 : \u211d) < t := ht\n      have hlog : (0 : \u211d) \u2264 Real.log t := Real.log_nonneg (by linarith)\n      positivity\n    have hanti : AntitoneOn (fun x => Real.log x / x ^ 2) (Set.Ici (3 : \u211d)) := by\n      apply antitoneOn_of_deriv_nonpos (convex_Ici 3)\n      \u00b7 intro x hx\n        have hx0 : x \u2260 0 := by have := (Set.mem_Ici.mp hx); linarith\n        exact (Real.continuousAt_log hx0).continuousWithinAt.div\n          (continuousWithinAt_pow _ _ _) (pow_ne_zero 2 hx0)\n      \u00b7 intro x hx\n        have hx0 : x \u2260 0 := by\n          have : (3 : \u211d) < x := Set.mem_Ioi.mp (by simpa [Set.interior_Ici] using hx)\n          linarith\n        exact (Real.differentiableAt_log hx0).div (differentiableAt_pow _ _)\n          (pow_ne_zero 2 hx0) |>.differentiableWithinAt\n      \u00b7 intro x hx\n        have hx3 : (3 : \u211d) < x := Set.mem_Ioi.mp (by simpa [Set.interior_Ici] using hx)\n        have hx0 : x \u2260 0 := by linarith\n        have hlog3 : (1 : \u211d) \u2264 Real.log 3 := by\n          have h := Real.log_le_log (Real.exp_pos 1) (by linarith [Real.exp_one_lt_d9.le] :\n            Real.exp 1 \u2264 3)\n          rwa [Real.log_exp] at h\n        have hlogx : (1 : \u211d) \u2264 Real.log x :=\n          hlog3.trans (Real.log_le_log (by positivity : (0 : \u211d) < 3) hx3.le)\n        have hderiv : deriv (fun y => Real.log y / y ^ 2) x\n            = (1 - 2 * Real.log x) / x ^ 3 := by\n          have h := (Real.hasDerivAt_log hx0).div (hasDerivAt_pow 2 x) (pow_ne_zero 2 hx0)\n          rw [h.deriv]\n          congr 1\n          field_simp\n          ring\n        rw [hderiv]\n        exact div_nonpos_of_nonpos_of_nonneg (by linarith [hlogx]) (by positivity)\n    have hint : IntegrableOn (fun x => Real.log x / x ^ 2) (Set.Ioi (3 : \u211d)) volume := by\n      rw [\u2190 integral_log_div_sq_Ioi_three]\n      exact IntegrableOn.of_finite_on... \n```\nHmm \u2014 the integrability should just be reused from the integral lemma. Actually integrableOn from the value: `integrableOn_Ioi_deriv_of_nonneg'` \u2014 I duplicated the deriv/tendsto work. Cleaner: factor the deriv/nonneg/tendsto/integrable into standalone lemmas so both `integral_log_div_sq_Ioi_three` and `tsum_log_div_sq_tail_le` and `htail_sum` reuse them. Let me restructure piece 1 with shared helpers:\n\n- `hasDerivAt_neg_log_add_one_div` : \u2200 x \u2260 0, HasDerivAt (fun y => \u2212(log y + 1)/y) (log x/x\u00b2) x.\n- `tendsto_neg_log_add_one_div` : Tendsto ... (\ud835\udcdd 0).\n- `antitoneOn_log_div_sq` : AntitoneOn (fun x => log x/x\u00b2) (Ici 3).\n- `integrableOn_log_div_sq` : IntegrableOn (fun x => log x/x\u00b2) (Ioi 3).\n- `integral_log_div_sq_Ioi_three` : \u222b = (log 3+1)/3.\n- `tsum_log_div_sq_tail_le`.\n- `dirichletC2_le_one`.\n\nLet me rewrite the whole \u00a76 with this factored structure. Also the summability of h: from tsum_log_div_sq_tail_le's summable tail... Actually the summability of (fun n => log (n+4)/(n+4)\u00b2) comes from AntitoneOn.summable... hmm \u2014 I need a Summable for htail. The integral test gives the BOUND but does it give summability? `AntitoneOn.summable_of_integrableOn_Ioi_zero` is the Ici-0 version; there should be an Ici-N version: from the tsum_comp_add_le_integral proof, the summability is established internally via `tsum_le_of_sum_le'`?? \u2014 hmm that lemma DOESN'T need summable (tsum_le_of_sum_le' handles possibly-non-summable as tsum = 0? no \u2014 tsum_le_of_sum_le' (h : \u2200 s, \u2211 i \u2208 s, f i \u2264 a) ... : \u2211' f \u2264 a requires summability? There's `tsum_le_of_sum_le (hf : Summable f) (h : \u2200 s, \u2211 i \u2208 s, f i \u2264 a) : \u2211' i, f i \u2264 a` and `tsum_le_of_sum_le' (ha : 0 \u2264 ...)...`. If the series isn't summable the tsum is 0 and things break. The summability of the tail: get it from the comparison: log(n+4)/(n+4)\u00b2 \u2264 2\u00b7(n+4)^{\u22123/2}\u00b7... or via `Summable` of the integral test: there is `AntitoneOn.summable_of_integrableOn_Ioi (anti : AntitoneOn f (Ici N)) (int : IntegrableOn f (Ioi N)) (nonneg : \u2200 t \u2208 Ioi N, 0 \u2264 f t) : Summable (fun n \u21a6 f (\u2191n + N + 1))`? \u2014 the name from line 215-218's usage: `summable_of_integrableOn_Ioi (N := 0) (mod_cast anti) (mod_cast integrable) (mod_cast nonneg)` \u2014 so `AntitoneOn.summable_of_integrableOn_Ioi` exists. Let me check its signature quickly. Actually from the first grep block: \"theorem AntitoneOn.summable_of_integrableOn_Ioi_zero (anti : AntitoneOn f (Ici 0)) (integrable : IntegrableOn f (Ioi 0)) (nonneg : \u2200 t \u2208 Ioi 0, 0 \u2264 f t) : Summable (fun (n : \u2115) \u21a6 f n) := summable_of_integrableOn_Ioi (N := 0) ...\" \u2014 so there's `summable_of_integrableOn_Ioi` with N \u2014 likely `AntitoneOn.summable_of_integrableOn_Ioi (N : \u2115) (anti : AntitoneOn f (Ici N)) (integrable : IntegrableOn f (Ioi N)) (nonneg : \u2200 t \u2208 Ioi N, 0 \u2264 f t) : Summable (fun n \u21a6 f (\u2191n + N + 1))`. Check at build.\n\nGiven the file is getting long and it's late, let me restructure \u00a76 cleanly with the factored helpers. Rewrite the section.",
  "replace_all": false
}
#1734 assistant 2026-08-24 09:39:01.451 UTC · 863→254 tok open ⤢
thinking (390 chars)
The §6 was inserted as a partial draft (my edit inserted the beginning but I was mid-rewrite in my head). The file now has the §6 header + dirichletTerm_norm_eq + the start of integral_log_div_sq_Ioi_three, but I never finished rewriting with the factored structure. Let me view what's actually in the file now from line 199 to the end, then rewrite §6 completely with the factored helpers.
The §6 edit landed as a partial draft. Let me view the current state and rewrite it cleanly with factored helpers.
tool: Bash
input
{
  "command": "cd D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1 && sed -n '223,280p' LiTightR.lean && echo \"...\" && grep -n \"Pieces 4/5\" LiTightR.lean && wc -l LiTightR.lean",
  "description": "View current \u00a76 state in the file"
}
#1735 assistant 2026-08-24 09:42:15.827 UTC · 3748→5765 tok open ⤢
thinking (16351 chars)
My earlier "Edit" to restructure §6 accidentally inserted my planning text INTO the file (lines 417-430 contain my thinking notes as Lean comments/text — that's why the edit "succeeded": it replaced the §6 header with a new §6 that contained my draft code plus stray commentary). I need to rewrite the whole §6 block (lines 199–430, up to the "Pieces 4/5" comment) with the final factored version. Let me replace that whole span. The cleanest approach: replace from `/-! ## 6. Piece 1: the Dirichlet bound at the reference point -/` through the end of my planning text (line 430) with the final factored code. The old_string is huge; instead, let me do it with a targeted approach: read the exact span boundaries and use Write... no — Write rewrites the whole file. Better: find a unique anchor at the start and end. Start anchor: `/-! ## 6. Piece 1: the Dirichlet bound at the reference point -/` (line 199). End anchor: the line `/-- **Pieces 4/5**` (line 432). I'll use Edit with old_string = the §6 header line + everything up to... — too long. Alternative: use a bash sed to delete lines 199–431 then Edit to insert. Hmm — instructions say prefer Edit over sed. But Edit needs the exact old_string. The block is ~230 lines. Let me instead reconstruct: I'll read the full file and rewrite via Write (the file is ~508 lines; I have its full content in context from my writes + reads). Actually simplest: Edit with old_string being from the §6 header comment start through the planning-text end — I can reconstruct it exactly from what I wrote... The risk is mismatch. Let me instead do two edits: 1. Delete the stray planning text (lines 417–431): the block starting with "Hmm — the integrability should just be reused..." — wait, that's part of my inserted comment `/--` ... the draft had `exact IntegrableOn.of_finite_on... ` at line 416 then ``` then my notes as PLAIN TEXT (lines 418-430 are not Lean comments — they'd be parse errors!). Lines 418-430: "Hmm — the integrability..." — these are NOT in a comment! They follow the ``` that closed... wait no — looking at the text: line 416 `exact IntegrableOn.of_finite_on... ` line 417 ``` — hmm, my Edit's new_string contained the draft Lean code fenced in ``` — NO. Let me look: my Edit new_string was the entire §6 draft INCLUDING the markdown-fenced code and my commentary as raw text. Since the Edit's new_string is inserted VERBATIM into the .lean file, the file now contains raw English text and markdown fences — completely broken Lean. Right — my "Edit" was actually a mistake: I pasted my planning notes (including ``` fences and commentary) into the file. The file is currently broken from line 199 to ~430. Recovery: rewrite the entire §6 section properly. Let me find the exact span: from line 199 (`/-! ## 6. Piece 1: ...`) to line 430 (the line before `/-- **Pieces 4/5**`). I'll use bash sed to delete those lines, then Edit to insert the final code before the Pieces 4/5 comment. Actually — to be safe and precise, let me use Python or sed to extract lines 1-198 and 432-508, and reassemble with the correct §6. Cleanest: use bash to truncate the file at line 198, then append the new §6 + then the pieces 4/5 section (lines 432+). Plan: 1. `head -198 LiTightR.lean > tmp` — keeps through line 198 (the end of §5, before the §6 header). Wait line 199 is `/-! ## 6. Piece 1...` — so keep lines 1–198. 2. `tail -n +432` gives from `/-- **Pieces 4/5**` onward — but I need the `/-! ## 6. Pieces 4/5 -/` header... the original §6 header was `/-! ## 6. Pieces 4/5: the reciprocal differences -/` which my edit REPLACED with the piece-1 stuff. Line 432 starts with the `/-- **Pieces 4/5** ...` docstring. So the section header `/-! ## 6. Pieces 4/5 ... -/` is gone — I'll re-add it in the new text. 3. Assemble: head-198 + new §6 (piece 1) + `/-! ## 7. Pieces 4/5 -/` header + tail-from-432. Let me do this with bash (file surgery with exact line numbers is the safe route here), writing the new §6 to a separate file first with Write, then concatenating. Actually — cleaner: I'll write the whole §6 block to a temp file via Write, then use bash to splice. Let me first finalize the §6 code. Factored structure: ```lean /-! ## 6. Piece 1: the Dirichlet bound at the reference point -/ /-- The Dirichlet term norm at 2. -/ lemma dirichletTerm_norm_eq (n : ℕ) : ... (KEEP the existing one — it's fine) ``` Wait — dirichletTerm_norm_eq (lines 201-221) is fine and compiles? It's syntactically fine (untested). The broken part is from line 223 onward. Let me keep 1–221 (through dirichletTerm_norm_eq) and rewrite the rest of §6. New §6 (after dirichletTerm_norm_eq): ```lean /-- The antiderivative derivative fact: d/dx [−(log x + 1)/x] = log x/x². -/ lemma hasDerivAt_neg_log_add_one_div {x : ℝ} (hx0 : x ≠ 0) : HasDerivAt (fun y => -(Real.log y + 1) / y) (Real.log x / x ^ 2) x := by have h1 := ((Real.hasDerivAt_log hx0).add_const 1).div (hasDerivAt_id' x) hx0 have h2 := h1.neg have hval : -((x⁻¹ * x - (Real.log x + 1) * 1) / x ^ 2) = Real.log x / x ^ 2 := by field_simp ring have hfn : (fun y => -((Real.log y + 1) / y)) = (fun y => -(Real.log y + 1) / y) := by ext y rw [neg_div] rw [← hfn, hval] at * exact h2 ``` Hmm — `rw [← hfn, hval] at *` — the h2's function is (fun y => -((log y + 1)/y)) and value −((x⁻¹·x − (log x+1)·1)/x²). rw [← hfn] at h2: replaces (fun y => -(log y+1)/y) with (fun y => −((log y+1)/y))?? — ← direction rewrites RHS→LHS: occurrences of (fun y => −(log y+1)/y) get replaced by (fun y => −((log y+1)/y)) — but h2's function IS −((log y+1)/y) — no occurrence of the −(log y+1)/y form. Confused. Let me restructure: I want HasDerivAt F (log x/x²) x with F = fun y => −(log y + 1)/y. h2 : HasDerivAt (fun y => −((log y+1)/y)) (−((x⁻¹·x − (log x+1)·1)/x²)) x. The function in h2 vs my F: −((log y+1)/y) vs −(log y+1)/y — defeq by neg_div but not syntactic. And the value. Cleanest: use `convert h2 using 1`: ```lean lemma hasDerivAt_neg_log_add_one_div {x : ℝ} (hx0 : x ≠ 0) : HasDerivAt (fun y => -(Real.log y + 1) / y) (Real.log x / x ^ 2) x := by have h1 := ((Real.hasDerivAt_log hx0).add_const 1).div (hasDerivAt_id' x) hx0 have h2 := h1.neg convert h2 using 1 · ext y rw [neg_div] · field_simp ring ``` Hmm — convert ... using 1 on HasDerivAt F f' x = HasDerivAt G g' x gives goals F = G and f' = g' (and x = x — closed). F = G: (fun y => −(log y+1)/y) = (fun y => −((log y+1)/y)): ext y; neg_div ✓ wait — which side? h2's function after .neg: HasDerivAt.neg (h : HasDerivAt f f' x) : HasDerivAt (fun y => −f y) (−f') x — so h2's function is fun y => −((log y+1)/y)·... hold on — h1's function from .div: fun y => c y / d y with c = fun y => log y + 1, d = id — so fun y => (log y + 1) / (id y) — the id y! `(fun y => (Real.log y + 1) / id y)` — id y vs y — defeq but maybe simp only [id_eq] needed. And my F has /y. The convert goal F = G: ext y: −(log y + 1)/y = −((log y + 1)/(id y))·... simp [id_eq, neg_div]? Let me write `· ext y; simp [neg_div]`. And the value goal: log x/x² = −((x⁻¹·x − (log x + 1)·1)/(id x)²) — field_simp; ring — hmm the (id x): simp only [id_eq] first. Let me write: ```lean convert h2 using 1 · ext y simp [neg_div] · simp only [id_eq] field_simp ring ``` The value: −((1/x·x − (log x+1)·1)/x²) vs log x/x²: after simp only [id_eq]: goal (from convert) Real.log x / x^2 = -((x⁻¹ * x - (Real.log x + 1) * 1) / x ^ 2)? or flipped. field_simp clears x⁻¹, x²: should reduce to a ring identity ✓. Might need `Real.log`... fine, iterate at build. Then: ```lean /-- Tendsto (fun y => −(log y + 1)/y) atTop (𝓝 0). -/ lemma tendsto_neg_log_add_one_div : Tendsto (fun y => -(Real.log y + 1) / y) atTop (𝓝 0) := by have hA : Tendsto (fun x => Real.log x / x) atTop (𝓝 0) := by have h := tendsto_pow_log_div_mul_add_atTop 1 0 1 one_ne_zero simpa using h have hB : Tendsto (fun x => (1 : ℝ) / x) atTop (𝓝 0) := tendsto_one_div_atTop_nhds_zero have hC : Tendsto (fun x => Real.log x / x + 1 / x) atTop (𝓝 (0 + 0)) := hA.add hB have heq : (fun y => -(Real.log y + 1) / y) = (fun x => Real.log x / x + 1 / x) := by ext x rw [neg_div, add_div] rw [heq] simpa using hC ``` Wait — heq: −(log y + 1)/y = log y/y + 1/y: rw [neg_div]: −((log y+1)/y); then add_div: (log y + 1)/y = log y/y + 1/y — so −(log y+1)/y = −(log y/y + 1/y) — that's NOT log y/y + 1/y (sign flip!). OOPS: −(log y + 1)/y = −(log y/y + 1/y) ≠ log y/y + 1/y. My target function is −(log y+1)/y which tends to 0 since (log y+1)/y → 0. So heq should be: (fun y => −(log y + 1)/y) = (fun x => −(log x/x + 1/x)): ```lean have heq : (fun y => -(Real.log y + 1) / y) = (fun x => -(Real.log x / x + 1 / x)) := by ext x rw [neg_div, add_div] rw [heq] exact (by simpa using hC).neg ``` (log y+1)/y = log y/y + 1/y (add_div ✓); −((log y+1)/y) = −(log y/y + 1/y) ✓ via neg_div then add_div ✓. Then Tendsto (fun x => −(...)) via hC.neg : Tendsto (fun x => −(log x/x + 1/x)) (𝓝 (−(0+0))) = 𝓝 0 — simpa using hC.neg? hC : Tendsto ... (𝓝 (0+0)); hC.neg : Tendsto (fun x => −(log x/x+1/x)) atTop (𝓝 (−(0+0))) — −(0+0) = 0: `by simpa using hC.neg` ✓. Then: ```lean /-- IntegrableOn (log x/x²) (Ioi 3). -/ lemma integrableOn_log_div_sq : IntegrableOn (fun x => Real.log x / x ^ 2) (Set.Ioi (3 : ℝ)) volume := by apply integrableOn_Ioi_deriv_of_nonneg' (fun x hx => hasDerivAt_neg_log_add_one_div (by have := (Set.mem_Ici.mp hx); linarith)) · intro x hx have hx3 : (3 : ℝ) < x := hx have hlog : (0 : ℝ) ≤ Real.log x := Real.log_nonneg (by linarith) positivity · exact tendsto_neg_log_add_one_div ``` Wait — the signature: integrableOn_Ioi_deriv_of_nonneg' (hderiv : ∀ x ∈ Ici a, HasDerivAt g (g' x) x) (g'pos : ∀ x ∈ Ioi a, 0 ≤ g' x) (hg : Tendsto g atTop (𝓝 l)) : IntegrableOn g' (Ioi a). The g is implicit — unified from hderiv: g := fun y => −(log y+1)/y, g' := fun x => log x/x² ✓ (a := 3 from hx : Set.Ici 3). The l := 0 ✓. The Ioi membership hx : x ∈ Set.Ioi 3 — `have hx3 : (3:ℝ) < x := hx` ✓ (Ioi membership is defeq to <). ✓. ```lean /-- The integral: ∫_{Ioi 3} log x/x² = (log 3 + 1)/3. -/ lemma integral_log_div_sq_Ioi_three : ∫ x in Set.Ioi (3 : ℝ), Real.log x / x ^ 2 = (Real.log 3 + 1) / 3 := by have h := integral_Ioi_of_hasDerivAt_of_tendsto' (fun x hx => hasDerivAt_neg_log_add_one_div (by have := (Set.mem_Ici.mp hx); linarith)) integrableOn_log_div_sq tendsto_neg_log_add_one_div rw [h] field_simp ring ``` h : ∫ x in Ioi 3, log x/x² = 0 − (−(log 3 + 1)/3) — the m − f a form: m = 0, f a = −(log 3 + 1)/3: 0 − (−(log 3+1)/3) = (log 3+1)/3 ✓. After rw [h], goal: 0 − (−(log 3 + 1)/3) = (log 3 + 1)/3: `ring` alone? 0 − (−X) = X ✓ ring closes (division by 3 as atoms — (log 3+1)/3 is an atom: 0 − (−X) = X ✓ ring). Just `ring`. Hmm — the exact form of f 3: −(log 3 + 1)/3 vs −((log 3+1)/3) — ring normalizes ✓. So: ```lean rw [h] ring ``` Hmm — but rw [h] rewrites the integral to `0 − (fun y => -(log y+1)/y) 3`? — the f a application is a beta-redex: (fun y => −(log y+1)/y) 3 — ring might not reduce the redex. Use `simp only []` to beta-reduce, or `show`. Safer: ```lean rw [h] show (0 : ℝ) - (-(Real.log 3 + 1) / 3) = (Real.log 3 + 1) / 3 ring ``` Hmm — the `show` must be defeq to the post-rw goal `0 − (fun y => −(log y+1)/y) 3 = ...` — beta-redex defeq ✓. Then the antitone: ```lean /-- AntitoneOn (log x/x²) on Ici 3 (derivative (1 − 2 log x)/x³ ≤ 0). -/ lemma antitoneOn_log_div_sq : AntitoneOn (fun x => Real.log x / x ^ 2) (Set.Ici (3 : ℝ)) := by apply antitoneOn_of_deriv_nonpos (convex_Ici 3) · intro x hx have hx0 : x ≠ 0 := by have := (Set.mem_Ici.mp hx); linarith exact (Real.continuousAt_log hx0).continuousWithinAt.div (continuousWithinAt_pow _ _ _) (pow_ne_zero 2 hx0) · intro x hx have hx0 : x ≠ 0 := by have : (3 : ℝ) < x := Set.mem_Ioi.mp (by rwa [Set.interior_Ici] at hx) linarith exact ((Real.differentiableAt_log hx0).div (differentiableAt_pow _ _) (pow_ne_zero 2 hx0)).differentiableWithinAt · intro x hx have hx3 : (3 : ℝ) < x := Set.mem_Ioi.mp (by rwa [Set.interior_Ici] at hx) have hx0 : x ≠ 0 := by linarith have hlog3 : (1 : ℝ) ≤ Real.log 3 := by have h := Real.log_le_log (Real.exp_pos 1) (by linarith [Real.exp_one_lt_d9.le] : Real.exp 1 ≤ 3) rwa [Real.log_exp] at h have hlogx : (1 : ℝ) ≤ Real.log x := hlog3.trans (Real.log_le_log (by positivity : (0 : ℝ) < 3) hx3.le) have hderiv : deriv (fun y => Real.log y / y ^ 2) x = (1 - 2 * Real.log x) / x ^ 3 := by have h := (Real.hasDerivAt_log hx0).div (hasDerivAt_pow 2 x) (pow_ne_zero 2 hx0) rw [h.deriv] congr 1 field_simp ring rw [hderiv] exact div_nonpos_of_nonpos_of_nonneg (by linarith [hlogx]) (by positivity) ``` Hmm — antitoneOn_of_deriv_nonpos's argument structure: (hD : Convex ℝ D) (hf : ContinuousOn f D) (hf' : DifferentiableOn ℝ f (interior D)) (h : ∀ x ∈ interior D, deriv f x ≤ 0) : AntitoneOn f D. My bullets: the `apply` leaves three goals (hf, hf', h) — each `intro x hx` then prove ✓. Note `Set.interior_Ici : interior (Ici a) = Ioi a` ✓. The `by rwa [Set.interior_Ici] at hx` — hx : x ∈ interior (Ici 3) → after rw: x ∈ Ioi 3 → Set.mem_Ioi.mp hx : 3 < x ✓. The deriv computation: `(Real.hasDerivAt_log hx0).div (hasDerivAt_pow 2 x) (pow_ne_zero 2 hx0)`: HasDerivAt log (1/x) x div HasDerivAt (fun y => y^2) (2*x^(2-1)) x — hasDerivAt_pow (n) (x) : HasDerivAt (fun y => y^n) (n*x^(n-1)) x ✓. The div value: ((1/x)·x² − log x·(2x))/(x²)². h.deriv : deriv (fun y => log y/y^2) x = that value. Then congr 1 + field_simp + ring to show ((1/x)·x² − log x·(2x))/(x²)² = (1 − 2 log x)/x³: field_simp [hx0] clears; ring... the identity: ((x²/x) − 2x log x)/x⁴ = (x − 2x log x)/x⁴ = (1 − 2 log x)/x³ ✓ (divide num/den by x). field_simp then ring should manage (x ≠ 0 in context). Potential fragility — iterate at build. Also continuity: `Real.continuousAt_log hx0 : ContinuousAt log x` — exists? Real.continuousAt_log (hx : x ≠ 0) : ContinuousAt Real.log x ✓ I believe. continuousWithinAt_pow: `ContinuousWithinAt.pow`? The form `(continuousWithinAt_pow _ _ _)` — hmm risky. Alternative: (continuousWithinAt_id.pow 2)? Let me use: `(ContinuousWithinAt.pow (continuousWithinAt_id) 2)`? hmm. Or continuousWithinAt_const... Actually simpler: `ContinuousWithinAt.div (ContinuousWithinAt.log ...)`... Let me use differentiability-based: the function is differentiable at x (x ≠ 0) ⟹ continuousWithinAt: `(Real.differentiableAt_log hx0).div (differentiableAt_pow _ _) (pow_ne_zero 2 hx0)` gives DifferentiableAt ⟹ .continuousAt.continuousWithinAt ✓. So bullet 1: intro x hx; exact ((Real.differentiableAt_log hx0).div (differentiableAt_pow _ _) (pow_ne_zero 2 hx0)).continuousAt.continuousWithinAt — cleaner (no separate continuity lemmas). ✓ Real.differentiableAt_log (hx : x ≠ 0) : DifferentiableAt ℝ Real.log x ✓ exists. differentiableAt_pow (n : ℕ)? : DifferentiableAt ℝ (fun x => x^n) x? signature: `differentiableAt_pow (n : ℕ) (x : ℝ)`? or just (n)? Check at build — risky name. There's `differentiableAt_pow (n : ℕ) (x : 𝕜) : DifferentiableAt 𝕜 (·^n) x`? hmm the exact form varies. Fallback: `DifferentiableAt.pow differentiableAt_id` hmm... or `differentiableAt_pow : DifferentiableAt 𝕜 (fun x => x ^ n) x`? Let me just try and fix at build. Then the tail bound + summability: ```lean /-- Summability of the log-tail. -/ lemma summable_log_div_sq_tail : Summable (fun n : ℕ => Real.log (n + 4) / (n + 4 : ℝ) ^ 2) := by have h := AntitoneOn.summable_of_integrableOn_Ioi antitoneOn_log_div_sq integrableOn_log_div_sq (fun t ht => by have ht3 : (3 : ℝ) < t := ht have hlog : (0 : ℝ) ≤ Real.log t := Real.log_nonneg (by linarith) positivity) -- h : Summable (fun n ↦ (fun x => log x/x²) (↑n + 3 + 1))-ish ... ``` Hmm — I need the exact signature of AntitoneOn.summable_of_integrableOn_Ioi. From line 215-218 usage: `summable_of_integrableOn_Ioi (N := 0) (mod_cast anti) (mod_cast integrable) (mod_cast nonneg)` — so it takes N as a named/implicit ℕ arg, then anti : AntitoneOn f (Ici (N:ℝ)), integrable : IntegrableOn f (Ioi (N:ℝ)), nonneg : ∀ t ∈ Ioi N, 0 ≤ f t, giving Summable (fun n ↦ f (↑(n + N + 1)))? or f (↑n + ↑N + 1)? The mod_cast suggestions the casts. Let me grep its exact statement.
The file got corrupted by a bad edit (my planning notes were pasted in). Let me check the exact summability lemma signature, then do surgical repair.
tool: Bash
input
{
  "command": "M=D:/Python/Quantum/zeta-23-lean/.lake/packages/mathlib/Mathlib; grep -n \"theorem AntitoneOn.summable_of_integrableOn_Ioi\\b\" -A 5 $M/Analysis/SumIntegralComparisons.lean | head -8",
  "description": "Get exact AntitoneOn.summable_of_integrableOn_Ioi signature"
}
#1736 assistant 2026-08-24 09:43:18.284 UTC · 6100→1578 tok open ⤢
thinking (4085 chars)
`AntitoneOn.summable_of_integrableOn_Ioi {N : ℕ} (anti : AntitoneOn f (Ici (N : ℝ))) (integrable : IntegrableOn f (Ioi (N : ℝ))) (nonneg : ∀ t ∈ Ioi (N : ℝ), 0 ≤ f t) : Summable (fun (n : ℕ) ↦ f n)` — with f : ℕ → ... wait, f n with n : ℕ — f must be ℕ → ℝ here? The anti is on ℝ... `f (↑n)` presumably with the cast. The statement: Summable (fun (n : ℕ) ↦ f n) where f : ℝ → ℝ and n coerced. So with N := 3: Summable (fun n : ℕ => f (↑n))... but I need Summable (fun n => log(n+4)/(n+4)²) = Summable (fun n => f (n+4)). From summable_nat_add_iff (N+1): Summable (fun n => f (n + N + 1))... The proof does `rw [← summable_nat_add_iff (N + 1)]` — so the full statement gives Summable (fun n ↦ f n) directly (the n + N + 1 shift is inside the proof). So `AntitoneOn.summable_of_integrableOn_Ioi anti int nonneg : Summable (fun n : ℕ => f ↑n)` — the WHOLE series from n = 0. For my tail: Summable (fun n => f (n+4 : ℕ)): via summable_nat_add_iff: `summable_nat_add_iff (k : ℕ) : Summable (fun n => f (n + k)) ↔ Summable f` — so (summable_nat_add_iff 4).mpr hmm — Summable (fun n => f (n+4)) ↔ Summable f: mpr : Summable f → Summable (fun n => f (n+4)) ✓ — wait direction: the iff is Summable (shifted) ↔ Summable f, so .mpr : Summable f → Summable (shifted) ✓. Hmm but my h is stated as fun n => Real.log (n+4)/(n+4 : ℝ)^2 — the shift of (fun m => Real.log m/(m:ℝ)^2) by 4: (fun n => (fun m => log m/m²) (n+4)) = fun n => log (↑(n+4))/(↑(n+4))² — and my target has Real.log (n + 4) / (n + 4 : ℝ) ^ 2 — the casts: log (n+4) where n+4 is... I wrote `Real.log (n + 4) / (n + 4 : ℝ) ^ 2` — the (n+4) inside log: is it (n : ℝ) + 4 or ↑(n+4)? Real.log takes ℝ, so (n + 4) there elaborates as (n:ℝ)+4? or (↑(n+4))? Ambiguous — Lean will coerce n : ℕ → ℝ, so Real.log (↑n + 4). And (n + 4 : ℝ) is the ascribed form ↑(n+4)? (n + 4 : ℝ) with n : ℕ: the ascription forces the whole n+4 to be ℝ — elaborates as ↑n + 4 (the + at ℝ with coercion) or ↑(n+4) (the + at ℕ then cast) — Lean's default: (n + 4 : ℝ) with n : ℕ coerces n and does + in ℝ? The ascription (e : ℝ) makes e elaborate at ℝ: n + 4 at ℝ needs (n : ℝ) — coercion inserted: ↑n + 4. And ↑(n+4) vs ↑n+4 are defeq (Nat.cast_add) but not syntactic. My target in tsum_log_div_sq_tail_le was `∑' n : ℕ, Real.log (n + 4) / (n + 4 : ℝ) ^ 2` — the elaborated form... To avoid cast hell, let me state the tail consistently as `∑' n : ℕ, Real.log ((n : ℝ) + 4) / ((n : ℝ) + 4) ^ 2` — explicit ↑n + 4. Then the shift-lemma forms match cleanly via summable_nat_add_iff (4): Summable (fun n => g (n + 4)) where g m = log ↑m/↑m² — the shifted fun n => g (↑(n+4)) needs ↑(n+4) = ↑n + 4 — push_cast bridge. OK — this is getting into the weeds; let me just write the final §6 carefully and iterate on the build. First, repair the file: delete lines 222–431 (from the `/-- The integral of log...` docstring through the planning text), keeping dirichletTerm_norm_eq (lines 199–221) and the pieces 4/5 section (432+). Actually the docstring at 201 starts dirichletTerm_norm_eq; the broken part starts at line 223 (the `/-- The integral of log x/x² over Ioi 3...` docstring). Let me delete from line 223 to line 431 (inclusive), then insert the new §6 content. Using sed for the deletion (precise line surgery), then Edit to insert. Actually the instructions prefer dedicated tools over sed for edits, but for deleting a 209-line corrupt block, sed is the pragmatic choice... Alternatively, I can reconstruct the file: head -222 + new content + tail from 432. Let me do that with bash, writing the new middle via Write to a temp file. Actually — simplest correct approach: I'll read lines 1-222 (have them), write the new full file via Write (reconstructing the whole file: header + §1–§5 (unchanged, from my original Write + 4 Edits) + new §6 + §7 (pieces 4/5, unchanged from line 432+)). But the pieces-4/5 section content (lines 432–508) — I have it from my original Write. Let me reconstruct the whole file with Write. That's the safest. The file content I have fully: my original Write + the 4 edits (I know all their contents). Let me reconstruct.
The file needs surgical repair (a bad edit pasted planning notes in). Reconstructing the full file cleanly with the factored §6.
tool: Bash
input
{
  "command": "cd D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1 && sed -n '432,508p' LiTightR.lean > /tmp/litightr_tail.txt && head -c 200 /tmp/litightr_tail.txt && sed -n '1,198p' LiTightR.lean > /tmp/litightr_head.txt && tail -5 /tmp/litightr_head.txt",
  "description": "Extract the good head and tail of LiTightR.lean"
}
#1737 assistant 2026-08-24 09:45:08.660 UTC · 1986→4028 tok open ⤢
thinking (623 chars)
Good: head = lines 1–198 (through §5's near_sum_refPoint_le end), tail = lines 432–508 (pieces 4/5 through `end NguyenRH1 / end`). Now write the new §6 (piece 1) to a temp file, then splice: head + §6-header-and-piece1 + section-header-for-pieces45 + tail. Wait — the tail starts with the `/-- **Pieces 4/5**` docstring but is missing the `/-! ## 6. Pieces 4/5: ... -/` section header (which my bad edit replaced). I'll add a section header in the middle part. Let me write the middle (§6 complete with the factored helpers + dirichletC2_le_one + the §7 header) to /tmp/litightr_mid.txt via Write, then cat them together.
Writing the corrected §6 (piece 1) to a temp file, then splicing.
tool: Write ok
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\litightr_mid.tmp",
  "content": "/-! ## 6. Piece 1: the Dirichlet bound at the reference point -/\n\n/-- The Dirichlet term norm at 2: \u2016LSeries.term \u039b 2 n\u2016 = (if n = 0 then\n0 else) \u039b(n)/n\u00b2. -/\nlemma dirichletTerm_norm_eq (n : \u2115) :\n    \u2016LSeries.term (fun n => (ArithmeticFunction.vonMangoldt n : \u2102)) (2 : \u2102) n\u2016\n      = if n = 0 then (0 : \u211d)\n        else (ArithmeticFunction.vonMangoldt n) / (n : \u211d) ^ 2 := by\n  rcases eq_or_ne n 0 with rfl | hn\n  \u00b7 simp [LSeries.term]\n  \u00b7 rw [LSeries.term_def, if_neg hn, norm_div]\n    have h1 : \u2016(ArithmeticFunction.vonMangoldt n : \u2102)\u2016\n        = ArithmeticFunction.vonMangoldt n := by\n      rw [show (ArithmeticFunction.vonMangoldt n : \u2102)\n          = ((ArithmeticFunction.vonMangoldt n : \u211d) : \u2102) by push_cast; ring,\n        Complex.norm_real]\n      exact abs_of_nonneg ArithmeticFunction.vonMangoldt_nonneg\n    have h2 : \u2016((n : \u2102)) ^ (2 : \u2102)\u2016 = (n : \u211d) ^ 2 := by\n      rw [show ((n : \u2102)) ^ (2 : \u2102) = ((n : \u2102)) ^ (2 : \u2115) by\n            exact_mod_cast rfl, norm_pow]\n      rw [show ((n : \u2102)) = ((n : \u211d) : \u2102) by push_cast; ring, Complex.norm_real]\n      exact abs_of_nonneg (by positivity)\n    rw [h1, h2]\n\n/-- The antiderivative derivative fact: d/dx [\u2212(log x + 1)/x] = log x/x\u00b2. -/\nlemma hasDerivAt_neg_log_add_one_div {x : \u211d} (hx0 : x \u2260 0) :\n    HasDerivAt (fun y => -(Real.log y + 1) / y) (Real.log x / x ^ 2) x := by\n  have h1 := ((Real.hasDerivAt_log hx0).add_const 1).div (hasDerivAt_id' x) hx0\n  have h2 := h1.neg\n  convert h2 using 1\n  \u00b7 ext y\n    simp [neg_div]\n  \u00b7 simp only [id_eq]\n    field_simp\n    ring\n\n/-- \u2212(log x + 1)/x \u2192 0 as x \u2192 \u221e. -/\nlemma tendsto_neg_log_add_one_div :\n    Tendsto (fun y => -(Real.log y + 1) / y) atTop (\ud835\udcdd 0) := by\n  have hA : Tendsto (fun x => Real.log x / x) atTop (\ud835\udcdd 0) := by\n    have h := tendsto_pow_log_div_mul_add_atTop 1 0 1 one_ne_zero\n    simpa using h\n  have hB : Tendsto (fun x => (1 : \u211d) / x) atTop (\ud835\udcdd 0) :=\n    tendsto_one_div_atTop_nhds_zero\n  have hC : Tendsto (fun x => Real.log x / x + 1 / x) atTop (\ud835\udcdd (0 + 0)) :=\n    hA.add hB\n  have heq : (fun y => -(Real.log y + 1) / y) = (fun x => -(Real.log x / x + 1 / x)) := by\n    ext x\n    rw [neg_div, add_div]\n  rw [heq]\n  simpa using hC.neg\n\n/-- log x/x\u00b2 is integrable on Ioi 3. -/\nlemma integrableOn_log_div_sq :\n    IntegrableOn (fun x => Real.log x / x ^ 2) (Set.Ioi (3 : \u211d)) volume := by\n  apply integrableOn_Ioi_deriv_of_nonneg' (fun x hx =>\n    hasDerivAt_neg_log_add_one_div (by\n      have h := (Set.mem_Ici.mp hx); linarith))\n  \u00b7 intro x hx\n    have hx3 : (3 : \u211d) < x := hx\n    have hlog : (0 : \u211d) \u2264 Real.log x := Real.log_nonneg (by linarith)\n    positivity\n  \u00b7 exact tendsto_neg_log_add_one_div\n\n/-- The integral of log x/x\u00b2 over Ioi 3 is (log 3 + 1)/3. -/\nlemma integral_log_div_sq_Ioi_three :\n    \u222b x in Set.Ioi (3 : \u211d), Real.log x / x ^ 2 = (Real.log 3 + 1) / 3 := by\n  have h := integral_Ioi_of_hasDerivAt_of_tendsto'\n    (fun x hx => hasDerivAt_neg_log_add_one_div (by\n      have h := (Set.mem_Ici.mp hx); linarith))\n    integrableOn_log_div_sq tendsto_neg_log_add_one_div\n  rw [h]\n  show (0 : \u211d) - (-(Real.log 3 + 1) / 3) = (Real.log 3 + 1) / 3\n  ring\n\n/-- log x/x\u00b2 is antitone on Ici 3 (its derivative (1 \u2212 2 log x)/x\u00b3 is\n\u2264 0 for x \u2265 3 since log x \u2265 log 3 \u2265 1). -/\nlemma antitoneOn_log_div_sq :\n    AntitoneOn (fun x => Real.log x / x ^ 2) (Set.Ici (3 : \u211d)) := by\n  apply antitoneOn_of_deriv_nonpos (convex_Ici 3)\n  \u00b7 intro x hx\n    have hx0 : x \u2260 0 := by have h := (Set.mem_Ici.mp hx); linarith\n    exact ((Real.differentiableAt_log hx0).div (differentiableAt_pow _ _)\n      (pow_ne_zero 2 hx0)).continuousAt.continuousWithinAt\n  \u00b7 intro x hx\n    have hx0 : x \u2260 0 := by\n      have h : (3 : \u211d) < x := Set.mem_Ioi.mp (by rwa [Set.interior_Ici] at hx)\n      linarith\n    exact ((Real.differentiableAt_log hx0).div (differentiableAt_pow _ _)\n      (pow_ne_zero 2 hx0)).differentiableWithinAt\n  \u00b7 intro x hx\n    have hx3 : (3 : \u211d) < x := Set.mem_Ioi.mp (by rwa [Set.interior_Ici] at hx)\n    have hx0 : x \u2260 0 := by linarith\n    have hlog3 : (1 : \u211d) \u2264 Real.log 3 := by\n      have h := Real.log_le_log (Real.exp_pos 1)\n        (by linarith [Real.exp_one_lt_d9.le] : Real.exp 1 \u2264 3)\n      rwa [Real.log_exp] at h\n    have hlogx : (1 : \u211d) \u2264 Real.log x :=\n      hlog3.trans (Real.log_le_log (by positivity : (0 : \u211d) < 3) hx3.le)\n    have hderiv : deriv (fun y => Real.log y / y ^ 2) x\n        = (1 - 2 * Real.log x) / x ^ 3 := by\n      have h := (Real.hasDerivAt_log hx0).div (hasDerivAt_pow 2 x) (pow_ne_zero 2 hx0)\n      rw [h.deriv]\n      congr 1\n      field_simp\n      ring\n    rw [hderiv]\n    exact div_nonpos_of_nonpos_of_nonneg (by linarith [hlogx]) (by positivity)\n\n/-- Summability of the log-tail (integral test). -/\nlemma summable_log_div_sq_tail :\n    Summable (fun n : \u2115 => Real.log ((n : \u211d) + 4) / ((n : \u211d) + 4) ^ 2) := by\n  have h := AntitoneOn.summable_of_integrableOn_Ioi antitoneOn_log_div_sq\n    integrableOn_log_div_sq (fun t ht => by\n      have ht3 : (3 : \u211d) < t := ht\n      have hlog : (0 : \u211d) \u2264 Real.log t := Real.log_nonneg (by linarith)\n      positivity)\n  -- h : Summable (fun n : \u2115 \u21a6 (fun x => log x / x\u00b2) \u2191n); shift by 4\n  have h2 := (summable_nat_add_iff 4).mpr (f := fun n : \u2115 =>\n    Real.log (n : \u211d) / (n : \u211d) ^ 2) h\n  refine h2.congr fun n => ?_\n  push_cast\n  ring_nf\n\n/-- The tail bound: \u03a3_{n\u22654} log n/n\u00b2 \u2264 (log 3 + 1)/3 (integral test). -/\nlemma tsum_log_div_sq_tail_le :\n    \u2211' n : \u2115, Real.log ((n : \u211d) + 4) / ((n : \u211d) + 4) ^ 2 \u2264 (Real.log 3 + 1) / 3 := by\n  have hle := antitoneOn_log_div_sq.tsum_comp_add_le_integral 3\n    integrableOn_log_div_sq (fun t ht => by\n      have ht3 : (3 : \u211d) < t := ht\n      have hlog : (0 : \u211d) \u2264 Real.log t := Real.log_nonneg (by linarith)\n      positivity)\n  -- hle : \u2211' n, (fun x => log x/x\u00b2) \u2191(n + 3 + 1) \u2264 \u222b Ioi 3\n  rw [integral_log_div_sq_Ioi_three] at hle\n  refine hle.trans_eq' ?_\n  refine tsum_congr fun n => ?_\n  push_cast\n  ring_nf\n\n/-- **Piece 1** (D-069 \u00a73): dirichletC2 \u2264 1. The honest value is\n\u2212\u03b6\u2032/\u03b6(2) \u2248 0.56997; the bound here uses \u039b(n) \u2264 log n, the exact head\nn = 2, 3, and the integral-test tail (log 3 + 1)/3 \u2264 0.7. -/\ntheorem dirichletC2_le_one : dirichletC2 \u2264 1 := by\n  rw [dirichletC2]\n  have hsumm_g : Summable (fun n : \u2115 =>\n      \u2016LSeries.term (fun n => (ArithmeticFunction.vonMangoldt n : \u2102)) (2 : \u2102) n\u2016) := by\n    rw [summable_norm_iff]\n    exact ArithmeticFunction.LSeriesSummable_vonMangoldt (by norm_num)\n  -- the log majorant h n = if n = 0 then 0 else log n/n\u00b2, and its tsum split\n  set h : \u2115 \u2192 \u211d := fun n => if n = 0 then (0 : \u211d)\n    else Real.log n / (n : \u211d) ^ 2 with hh\n  have hle_pointwise : \u2200 n : \u2115,\n      \u2016LSeries.term (fun n => (ArithmeticFunction.vonMangoldt n : \u2102)) (2 : \u2102) n\u2016\n        \u2264 h n := by\n    intro n\n    rw [dirichletTerm_norm_eq n, hh]\n    rcases eq_or_ne n 0 with rfl | hn\n    \u00b7 simp\n    \u00b7 rw [if_neg hn, if_neg hn]\n      exact div_le_div_of_nonneg_right ArithmeticFunction.vonMangoldt_le_log\n        (by positivity : (0 : \u211d) \u2264 (n : \u211d) ^ 2)\n  -- summability of h: the tail n + 4 is summable, and the head is finite\n  have hsumh : Summable h := by\n    have h1 : Summable (fun n : \u2115 => h (n + 4)) := by\n      apply summable_log_div_sq_tail.congr\n      intro n\n      rw [hh]\n      show (if (n + 4 : \u2115) = 0 then (0 : \u211d) else Real.log (n + 4) / ((n + 4 : \u2115) : \u211d) ^ 2)\n          = Real.log ((n : \u211d) + 4) / ((n : \u211d) + 4) ^ 2\n      rw [if_neg (by omega : (n + 4 : \u2115) \u2260 0)]\n      push_cast\n      ring_nf\n    exact (summable_nat_add_iff 4).mp h1\n  -- the head/tail split of the h-tsum\n  have hsplit : \u2211' n : \u2115, h n = (\u2211 n \u2208 Finset.range 4, h n) + \u2211' n : \u2115, h (n + 4) := by\n    exact (sum_add_tsum_nat_add 4 hsumh).symm\n  have hhead : \u2211 n \u2208 Finset.range 4, h n = Real.log 2 / 4 + Real.log 3 / 9 := by\n    rw [Finset.sum_range_succ, Finset.sum_range_succ, Finset.sum_range_succ,\n      Finset.sum_range_succ, Finset.sum_range_zero]\n    rw [hh]\n    simp only [Nat.zero_eq, if_pos, Nat.one_ne_zero, Nat.add_eq_zero_iff,\n      OfNat.ofNat_ne_zero, and_self, not_false_eq_true]\n    rw [show h 1 = (0 : \u211d) from by rw [hh]; simp]\n    rw [show h 2 = Real.log 2 / 4 from by\n      rw [hh]; rw [if_neg (by norm_num : (2 : \u2115) \u2260 0)]; push_cast; ring_nf]\n    rw [show h 3 = Real.log 3 / 9 from by\n      rw [hh]; rw [if_neg (by norm_num : (3 : \u2115) \u2260 0)]; push_cast; ring_nf]\n    ring\n  have htail : \u2211' n : \u2115, h (n + 4) \u2264 (Real.log 3 + 1) / 3 := by\n    have h1 : (\u2211' n : \u2115, h (n + 4))\n        = \u2211' n : \u2115, Real.log ((n : \u211d) + 4) / ((n : \u211d) + 4) ^ 2 := by\n      refine tsum_congr fun n => ?_\n      rw [hh]\n      show (if (n + 4 : \u2115) = 0 then (0 : \u211d) else Real.log (n + 4) / ((n + 4 : \u2115) : \u211d) ^ 2)\n          = Real.log ((n : \u211d) + 4) / ((n : \u211d) + 4) ^ 2\n      rw [if_neg (by omega : (n + 4 : \u2115) \u2260 0)]\n      push_cast\n      ring_nf\n    rw [h1]\n    exact tsum_log_div_sq_tail_le\n  -- assemble\n  have hmain : \u2211' n : \u2115,\n      \u2016LSeries.term (fun n => (ArithmeticFunction.vonMangoldt n : \u2102)) (2 : \u2102) n\u2016\n        \u2264 Real.log 2 / 4 + Real.log 3 / 9 + (Real.log 3 + 1) / 3 := by\n    calc \u2211' n : \u2115,\n        \u2016LSeries.term (fun n => (ArithmeticFunction.vonMangoldt n : \u2102)) (2 : \u2102) n\u2016\n        \u2264 \u2211' n : \u2115, h n := Summable.tsum_le_tsum hle_pointwise hsumm_g hsumh\n      _ = (\u2211 n \u2208 Finset.range 4, h n) + \u2211' n : \u2115, h (n + 4) := hsplit\n      _ \u2264 (Real.log 2 / 4 + Real.log 3 / 9) + (Real.log 3 + 1) / 3 := by\n          linarith [hhead, htail]\n  -- the numeric fold: log 2 \u2264 0.6932, log 3 \u2264 1.1\n  have hlog2 : Real.log 2 \u2264 0.6932 := Real.log_two_lt_d9.le.trans (by norm_num)\n  have hlog3 : Real.log 3 \u2264 1.1 := by\n    have h3le : (3 : \u211d) \u2264 Real.exp 1.1 := by\n      have h := Real.sum_le_exp_of_nonneg (show (0 : \u211d) \u2264 1.1 by norm_num) 6\n      -- \u03a3_{k<6} 1.1^k/k! = 3.00126\u2026 \u2265 3\n      rw [Finset.sum_range_succ, Finset.sum_range_succ, Finset.sum_range_succ,\n        Finset.sum_range_succ, Finset.sum_range_succ, Finset.sum_range_succ,\n        Finset.sum_range_zero] at h\n      norm_num at h\n      linarith [h]\n    have h2 : Real.log 3 \u2264 Real.log (Real.exp 1.1) :=\n      Real.log_le_log (by norm_num : (0 : \u211d) < 3) h3le\n    rwa [Real.log_exp] at h2\n  have hlog2nn : (0 : \u211d) \u2264 Real.log 2 := Real.log_nonneg (by norm_num)\n  have hlog3nn : (0 : \u211d) \u2264 Real.log 3 := Real.log_nonneg (by norm_num)\n  linarith [hmain, hlog2, hlog3, hlog2nn, hlog3nn]\n\n/-! ## 7. Pieces 4/5: the reciprocal differences -/\n\n"
}
result 2026-08-24 09:45:08Z → 2026-08-24 09:45:08Z
{
  "type": "create",
  "filePath": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\litightr_mid.tmp",
  "content": "/-! ## 6. Piece 1: the Dirichlet bound at the reference point -/\n\n/-- The Dirichlet term norm at 2: \u2016LSeries.term \u039b 2 n\u2016 = (if n = 0 then\n0 else) \u039b(n)/n\u00b2. -/\nlemma dirichletTerm_norm_eq (n : \u2115) :\n    \u2016LSeries.term (fun n => (ArithmeticFunction.vonMangoldt n : \u2102)) (2 : \u2102) n\u2016\n      = if n = 0 then (0 : \u211d)\n        else (ArithmeticFunction.vonMangoldt n) / (n : \u211d) ^ 2 := by\n  rcases eq_or_ne n 0 with rfl | hn\n  \u00b7 simp [LSeries.term]\n  \u00b7 rw [LSeries.term_def, if_neg hn, norm_div]\n    have h1 : \u2016(ArithmeticFunction.vonMangoldt n : \u2102)\u2016\n        = ArithmeticFunction.vonMangoldt n := by\n      rw [show (ArithmeticFunction.vonMangoldt n : \u2102)\n          = ((ArithmeticFunction.vonMangoldt n : \u211d) : \u2102) by push_cast; ring,\n        Complex.norm_real]\n      exact abs_of_nonneg ArithmeticFunction.vonMangoldt_nonneg\n    have h2 : \u2016((n : \u2102)) ^ (2 : \u2102)\u2016 = (n : \u211d) ^ 2 := by\n      rw [show ((n : \u2102)) ^ (2 : \u2102) = ((n : \u2102)) ^ (2 : \u2115) by\n            exact_mod_cast rfl, norm_pow]\n      rw [show ((n : \u2102)) = ((n : \u211d) : \u2102) by push_cast; ring, Complex.norm_real]\n      exact abs_of_nonneg (by positivity)\n    rw [h1, h2]\n\n/-- The antiderivative derivative fact: d/dx [\u2212(log x + 1)/x] = log x/x\u00b2. -/\nlemma hasDerivAt_neg_log_add_one_div {x : \u211d} (hx0 : x \u2260 0) :\n    HasDerivAt (fun y => -(Real.log y + 1) / y) (Real.log x / x ^ 2) x := by\n  have h1 := ((Real.hasDerivAt_log hx0).add_const 1).div (hasDerivAt_id' x) hx0\n  have h2 := h1.neg\n  convert h2 using 1\n  \u00b7 ext y\n    simp [neg_div]\n  \u00b7 simp only [id_eq]\n    field_simp\n    ring\n\n/-- \u2212(log x + 1)/x \u2192 0 as x \u2192 \u221e. -/\nlemma tendsto_neg_log_add_one_div :\n    Tendsto (fun y => -(Real.log y + 1) / y) atTop (\ud835\udcdd 0) := by\n  have hA : Tendsto (fun x => Real.log x / x) atTop (\ud835\udcdd 0) := by\n    have h := tendsto_pow_log_div_mul_add_atTop 1 0 1 one_ne_zero\n    simpa using h\n  have hB : Tendsto (fun x => (1 : \u211d) / x) atTop (\ud835\udcdd 0) :=\n    tendsto_one_div_atTop_nhds_zero\n  have hC : Tendsto (fun x => Real.log x / x + 1 / x) atTop (\ud835\udcdd (0 + 0)) :=\n    hA.add hB\n  have heq : (fun y => -(Real.log y + 1) / y) = (fun x => -(Real.log x / x + 1 / x)) := by\n    ext x\n    rw [neg_div, add_div]\n  rw [heq]\n  simpa using hC.neg\n\n/-- log x/x\u00b2 is integrable on Ioi 3. -/\nlemma integrableOn_log_div_sq :\n    IntegrableOn (fun x => Real.log x / x ^ 2) (Set.Ioi (3 : \u211d)) volume := by\n  apply integrableOn_Ioi_deriv_of_nonneg' (fun x hx =>\n    hasDerivAt_neg_log_add_one_div (by\n      have h := (Set.mem_Ici.mp hx); linarith))\n  \u00b7 intro x hx\n    have hx3 : (3 : \u211d) < x := hx\n    have hlog : (0 : \u211d) \u2264 Real.log x := Real.log_nonneg (by linarith)\n    positivity\n  \u00b7 exact tendsto_neg_log_add_one_div\n\n/-- The integral of log x/x\u00b2 over Ioi 3 is (log 3 + 1)/3. -/\nlemma integral_log_div_sq_Ioi_three :\n    \u222b x in Set.Ioi (3 : \u211d), Real.log x / x ^ 2 = (Real.log 3 + 1) / 3 := by\n  have h := integral_Ioi_of_hasDerivAt_of_tendsto'\n    (fun x hx => hasDerivAt_neg_log_add_one_div (by\n      have h := (Set.mem_Ici.mp hx); linarith))\n    integrableOn_log_div_sq tendsto_neg_log_add_one_div\n  rw [h]\n  show (0 : \u211d) - (-(Real.log 3 + 1) / 3) = (Real.log 3 + 1) / 3\n  ring\n\n/-- log x/x\u00b2 is antitone on Ici 3 (its derivative (1 \u2212 2 log x)/x\u00b3 is\n\u2264 0 for x \u2265 3 since log x \u2265 log 3 \u2265 1). -/\nlemma antitoneOn_log_div_sq :\n    AntitoneOn (fun x => Real.log x / x ^ 2) (Set.Ici (3 : \u211d)) := by\n  apply antitoneOn_of_deriv_nonpos (convex_Ici 3)\n  \u00b7 intro x hx\n    have hx0 : x \u2260 0 := by have h := (Set.mem_Ici.mp hx); linarith\n    exact ((Real.differentiableAt_log hx0).div (differentiableAt_pow _ _)\n      (pow_ne_zero 2 hx0)).continuousAt.continuousWithinAt\n  \u00b7 intro x hx\n    have hx0 : x \u2260 0 := by\n      have h : (3 : \u211d) < x := Set.mem_Ioi.mp (by rwa [Set.interior_Ici] at hx)\n      linarith\n    exact ((Real.differentiableAt_log hx0).div (differentiableAt_pow _ _)\n      (pow_ne_zero 2 hx0)).differentiableWithinAt\n  \u00b7 intro x hx\n    have hx3 : (3 : \u211d) < x := Set.mem_Ioi.mp (by rwa [Set.interior_Ici] at hx)\n    have hx0 : x \u2260 0 := by linarith\n    have hlog3 : (1 : \u211d) \u2264 Real.log 3 := by\n      have h := Real.log_le_log (Real.exp_pos 1)\n        (by linarith [Real.exp_one_lt_d9.le] : Real.exp 1 \u2264 3)\n      rwa [Real.log_exp] at h\n    have hlogx : (1 : \u211d) \u2264 Real.log x :=\n      hlog3.trans (Real.log_le_log (by positivity : (0 : \u211d) < 3) hx3.le)\n    have hderiv : deriv (fun y => Real.log y / y ^ 2) x\n        = (1 - 2 * Real.log x) / x ^ 3 := by\n      have h := (Real.hasDerivAt_log hx0).div (hasDerivAt_pow 2 x) (pow_ne_zero 2 hx0)\n      rw [h.deriv]\n      congr 1\n      field_simp\n      ring\n    rw [hderiv]\n    exact div_nonpos_of_nonpos_of_nonneg (by linarith [hlogx]) (by positivity)\n\n/-- Summability of the log-tail (integral test). -/\nlemma summable_log_div_sq_tail :\n    Summable (fun n : \u2115 => Real.log ((n : \u211d) + 4) / ((n : \u211d) + 4) ^ 2) := by\n  have h := AntitoneOn.summable_of_integrableOn_Ioi antitoneOn_log_div_sq\n    integrableOn_log_div_sq (fun t ht => by\n      have ht3 : (3 : \u211d) < t := ht\n      have hlog : (0 : \u211d) \u2264 Real.log t := Real.log_nonneg (by linarith)\n      positivity)\n  -- h : Summable (fun n : \u2115 \u21a6 (fun x => log x / x\u00b2) \u2191n); shift by 4\n  have h2 := (summable_nat_add_iff 4).mpr (f := fun n : \u2115 =>\n    Real.log (n : \u211d) / (n : \u211d) ^ 2) h\n  refine h2.congr fun n => ?_\n  push_cast\n  ring_nf\n\n/-- The tail bound: \u03a3_{n\u22654} log n/n\u00b2 \u2264 (log 3 + 1)/3 (integral test). -/\nlemma tsum_log_div_sq_tail_le :\n    \u2211' n : \u2115, Real.log ((n : \u211d) + 4) / ((n : \u211d) + 4) ^ 2 \u2264 (Real.log 3 + 1) / 3 := by\n  have hle := antitoneOn_log_div_sq.tsum_comp_add_le_integral 3\n    integrableOn_log_div_sq (fun t ht => by\n      have ht3 : (3 : \u211d) < t := ht\n      have hlog : (0 : \u211d) \u2264 Real.log t := Real.log_nonneg (by linarith)\n      positivity)\n  -- hle : \u2211' n, (fun x => log x/x\u00b2) \u2191(n + 3 + 1) \u2264 \u222b Ioi 3\n  rw [integral_log_div_sq_Ioi_three] at hle\n  refine hle.trans_eq' ?_\n  refine tsum_congr fun n => ?_\n  push_cast\n  ring_nf\n\n/-- **Piece 1** (D-069 \u00a73): dirichletC2 \u2264 1. The honest value is\n\u2212\u03b6\u2032/\u03b6(2) \u2248 0.56997; the bound here uses \u039b(n) \u2264 log n, the exact head\nn = 2, 3, and the integral-test tail (log 3 + 1)/3 \u2264 0.7. -/\ntheorem dirichletC2_le_one : dirichletC2 \u2264 1 := by\n  rw [dirichletC2]\n  have hsumm_g : Summable (fun n : \u2115 =>\n      \u2016LSeries.term (fun n => (ArithmeticFunction.vonMangoldt n : \u2102)) (2 : \u2102) n\u2016) := by\n    rw [summable_norm_iff]\n    exact ArithmeticFunction.LSeriesSummable_vonMangoldt (by norm_num)\n  -- the log majorant h n = if n = 0 then 0 else log n/n\u00b2, and its tsum split\n  set h : \u2115 \u2192 \u211d := fun n => if n = 0 then (0 : \u211d)\n    else Real.log n / (n : \u211d) ^ 2 with hh\n  have hle_pointwise : \u2200 n : \u2115,\n      \u2016LSeries.term (fun n => (ArithmeticFunction.vonMangoldt n : \u2102)) (2 : \u2102) n\u2016\n        \u2264 h n := by\n    intro n\n    rw [dirichletTerm_norm_eq n, hh]\n    rcases eq_or_ne n 0 with rfl | hn\n    \u00b7 simp\n    \u00b7 rw [if_neg hn, if_neg hn]\n      exact div_le_div_of_nonneg_right ArithmeticFunction.vonMangoldt_le_log\n        (by positivity : (0 : \u211d) \u2264 (n : \u211d) ^ 2)\n  -- summability of h: the tail n + 4 is summable, and the head is finite\n  have hsumh : Summable h := by\n    have h1 : Summable (fun n : \u2115 => h (n + 4)) := by\n      apply summable_log_div_sq_tail.congr\n      intro n\n      rw [hh]\n      show (if (n + 4 : \u2115) = 0 then (0 : \u211d) else Real.log (n + 4) / ((n + 4 : \u2115) : \u211d) ^ 2)\n          = Real.log ((n : \u211d) + 4) / ((n : \u211d) + 4) ^ 2\n      rw [if_neg (by omega : (n + 4 : \u2115) \u2260 0)]\n      push_cast\n      ring_nf\n    exact (summable_nat_add_iff 4).mp h1\n  -- the head/tail split of the h-tsum\n  have hsplit : \u2211' n : \u2115, h n = (\u2211 n \u2208 Finset.range 4, h n) + \u2211' n : \u2115, h (n + 4) := by\n    exact (sum_add_tsum_nat_add 4 hsumh).symm\n  have hhead : \u2211 n \u2208 Finset.range 4, h n = Real.log 2 / 4 + Real.log 3 / 9 := by\n    rw [Finset.sum_range_succ, Finset.sum_range_succ, Finset.sum_range_succ,\n      Finset.sum_range_succ, Finset.sum_range_zero]\n    rw [hh]\n    simp only [Nat.zero_eq, if_pos, Nat.one_ne_zero, Nat.add_eq_zero_iff,\n      OfNat.ofNat_ne_zero, and_self, not_false_eq_true]\n    rw [show h 1 = (0 : \u211d) from by rw [hh]; simp]\n    rw [show h 2 = Real.log 2 / 4 from by\n      rw [hh]; rw [if_neg (by norm_num : (2 : \u2115) \u2260 0)]; push_cast; ring_nf]\n    rw [show h 3 = Real.log 3 / 9 from by\n      rw [hh]; rw [if_neg (by norm_num : (3 : \u2115) \u2260 0)]; push_cast; ring_nf]\n    ring\n  have htail : \u2211' n : \u2115, h (n + 4) \u2264 (Real.log 3 + 1) / 3 := by\n    have h1 : (\u2211' n : \u2115, h (n + 4))\n        = \u2211' n : \u2115, Real.log ((n : \u211d) + 4) / ((n : \u211d) + 4) ^ 2 := by\n      refine tsum_congr fun n => ?_\n      rw [hh]\n      show (if (n + 4 : \u2115) = 0 then (0 : \u211d) else Real.log (n + 4) / ((n + 4 : \u2115) : \u211d) ^ 2)\n          = Real.log ((n : \u211d) + 4) / ((n : \u211d) + 4) ^ 2\n      rw [if_neg (by omega : (n + 4 : \u2115) \u2260 0)]\n      push_cast\n      ring_nf\n    rw [h1]\n    exact tsum_log_div_sq_tail_le\n  -- assemble\n  have hmain : \u2211' n : \u2115,\n      \u2016LSeries.term (fun n => (ArithmeticFunction.vonMangoldt n : \u2102)) (2 : \u2102) n\u2016\n        \u2264 Real.log 2 / 4 + Real.log 3 / 9 + (Real.log 3 + 1) / 3 := by\n    calc \u2211' n : \u2115,\n        \u2016LSeries.term (fun n => (ArithmeticFunction.vonMangoldt n : \u2102)) (2 : \u2102) n\u2016\n        \u2264 \u2211' n : \u2115, h n := Summable.tsum_le_tsum hle_pointwise hsumm_g hsumh\n      _ = (\u2211 n \u2208 Finset.range 4, h n) + \u2211' n : \u2115, h (n + 4) := hsplit\n      _ \u2264 (Real.log 2 / 4 + Real.log 3 / 9) + (Real.log 3 + 1) / 3 := by\n          linarith [hhead, htail]\n  -- the numeric fold: log 2 \u2264 0.6932, log 3 \u2264 1.1\n  have hlog2 : Real.log 2 \u2264 0.6932 := Real.log_two_lt_d9.le.trans (by norm_num)\n  have hlog3 : Real.log 3 \u2264 1.1 := by\n    have h3le : (3 : \u211d) \u2264 Real.exp 1.1 := by\n      have h := Real.sum_le_exp_of_nonneg (show (0 : \u211d) \u2264 1.1 by norm_num) 6\n      -- \u03a3_{k<6} 1.1^k/k! = 3.00126\u2026 \u2265 3\n      rw [Finset.sum_range_succ, Finset.sum_range_succ, Finset.sum_range_succ,\n        Finset.sum_range_succ, Finset.sum_range_succ, Finset.sum_range_succ,\n        Finset.sum_range_zero] at h\n      norm_num at h\n      linarith [h]\n    have h2 : Real.log 3 \u2264 Real.log (Real.exp 1.1) :=\n      Real.log_le_log (by norm_num : (0 : \u211d) < 3) h3le\n    rwa [Real.log_exp] at h2\n  have hlog2nn : (0 : \u211d) \u2264 Real.log 2 := Real.log_nonneg (by norm_num)\n  have hlog3nn : (0 : \u211d) \u2264 Real.log 3 := Real.log_nonneg (by norm_num)\n  linarith [hmain, hlog2, hlog3, hlog2nn, hlog3nn]\n\n/-! ## 7. Pieces 4/5: the reciprocal differences -/\n\n",
  "structuredPatch": [],
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#1738 assistant 2026-08-24 09:46:56.517 UTC · 4273→3219 tok open ⤢
thinking (7805 chars)
Wait — before splicing, let me double-check a few risky spots in the mid file: 1. `Real.sum_le_exp_of_nonneg (show (0:ℝ) ≤ 1.1 by norm_num) 6` — signature: Real.sum_le_exp_of_nonneg {x : ℝ} (hx : 0 ≤ x) (n : ℕ) : ∑ k ∈ range n, x^k/k! ≤ exp x? — let me check: from D-062 §5 notes "exp lower bounds by partial sums (Real.sum_le_exp_of_nonneg)". Signature guess: `Real.sum_le_exp_of_nonneg (hx : 0 ≤ x) (n : ℕ) : ∑ i ∈ Finset.range n, x ^ i / i ! ≤ Real.exp x`. So h : ∑ k ∈ range 6, 1.1^k/k! ≤ exp 1.1. Then expanding the sum and norm_num: ∑ = 1 + 1.1 + 1.21/2 + 1.331/6 + 1.4641/24 + 1.61051/120 = 1 + 1.1 + 0.605 + 0.221833 + 0.061004 + 0.013421 = 3.001258. norm_num at h should evaluate the LHS (rational!) — 1.1 is a decimal = rational ✓ k! values ✓. h : 3.001258... ≤ exp 1.1 — then linarith [h] : 3 ≤ exp 1.1 — hmm norm_num at h evaluates the sum to a numeral: h : (3.00126... : ℝ) ≤ exp 1.1; linarith needs 3 ≤ that numeral: norm_num should prove 3 ≤ 3.00126 within linarith's reach? linarith [h] with h : C ≤ exp 1.1 and goal 3 ≤ exp 1.1 — needs 3 ≤ C as a fact: linarith can verify 3 ≤ C if C is a numeral? linarith handles numeric comparisons of literals ✓ (3 ≤ 3.001258 is a linear fact about constants ✓). Hmm — but `Real.sum_le_exp_of_nonneg` signature — is the sum over `range n` with x^k/k!? Let me not guess: D-062 §5 says "exp lower bounds by partial sums (Real.sum_le_exp_of_nonneg)" — so it exists with some form. The exact form might be `Real.sum_le_exp_of_nonneg {x : ℝ} (hx : 0 ≤ x) (n : ℕ) : (∑ i ∈ Finset.range n, x ^ i / i !) ≤ Real.exp x`. I'll adjust at build if needed. 2. `(summable_nat_add_iff 4).mpr (f := fun n : ℕ => Real.log (n:ℝ)/(n:ℝ)^2) h` — summable_nat_add_iff : Summable (fun n => f (n + k)) ↔ Summable f. .mpr : Summable f → Summable (fun n => f (n + 4)). My h : Summable (fun n : ℕ => (fun x => log x/x²) ↑n) — is that Summable f with f := fun n => log ↑n/↑n²? h from AntitoneOn.summable_of_integrableOn_Ioi gives Summable (fun n : ℕ ↦ f ↑n) where f := (fun x => log x/x²) — so h : Summable (fun n => log ↑n/↑n²) ✓ matches f := fun n : ℕ => Real.log (n:ℝ)/(n:ℝ)^2 ✓. Then .mpr gives Summable (fun n => f (n + 4)) = Summable (fun n => log (↑(n+4))/(↑(n+4))²). Then h2.congr (fun n => ?_) — the congr target: Summable (fun n => log (↑n+4)/(↑n+4)²): pointwise: log (↑(n+4))/(↑(n+4))² = log (↑n+4)/(↑n+4)²: push_cast + ring_nf — hmm: ↑(n+4) = ↑n + ↑4 = ↑n + 4: push_cast rewrites ✓ then the goal becomes log (↑n+4)/(↑n+4)² = log (↑n+4)/(↑n+4)² — rfl — ring_nf closes ✓ hopefully. Wait — actually h2.congr : Summable.congr (hf : Summable f) (h : ∀ i, f i = g i) : Summable g — so `h2.congr (fun n => ?_)` where the pointwise h : f n = g n. My `refine h2.congr fun n => ?_; push_cast; ring_nf` — the goal: (fun n => log ↑(n+4)/↑(n+4)²) n = (fun n => log (↑n+4)/(↑n+4)²) n — beta-redexes both sides — push_cast then ring_nf — hmm ring_nf on log-atoms: the goal after beta is log ↑(n+4)/↑(n+4)² = log (↑n+4)/(↑n+4)²: push_cast turns ↑(n+4) into ↑n + 4 ✓ then both sides identical — ring_nf or rfl. OK. Hmm — but does `(summable_nat_add_iff 4).mpr` accept the (f := ...) named arg? f is implicit in summable_nat_add_iff {f : ℕ → M} (k : ℕ) — pin via (f := ...) ✓. 3. `sum_add_tsum_nat_add` — exact name/direction: `sum_add_tsum_nat_add (k : ℕ) (hf : Summable f) : (∑ i ∈ range k, f i) + ∑' i, f (i + k) = ∑' i, f i`? or the reverse. My hsplit : ∑' n, h n = (∑ range 4) + ∑' (h (n+4)): if the lemma is (∑ range k) + tsum-shifted = tsum, then hsplit = (sum_add_tsum_nat_add 4 hsumh).symm ✓ as written. If it's the reverse direction, drop .symm. Check at build. The name might also be `Summable.sum_add_tsum_nat_add`. Risk — adjust at build. 4. The hhead computation: `Finset.sum_range_succ` chain from range 4 down: ∑ range 4 = ∑ range 3 + f 3 — applying sum_range_succ four times then sum_range_zero gives f 0 + f 1 + f 2 + f 3 + 0... The sum_range_succ : ∑ i ∈ range (n+1), f i = ∑ i ∈ range n, f i + f n. So ∑ range 4 h = ((∑ range 3 h) + h 3) = (((∑ range 2 h) + h 2) + h 3) = ((((∑ range 1 h) + h 1) + h 2) + h 3) = (((((∑ range 0 h) + h 0) + h 1) + h 2) + h 3) — after 4× sum_range_succ + sum_range_zero: ((((0 + h 0) + h 1) + h 2) + h 3). Then my rw chain: `simp only [...]` then the `show h 1 = ...` rws. Hmm — the `simp only [Nat.zero_eq, if_pos, ...]` — for h 0: h 0 = if 0 = 0 then 0 else ... = 0 via if_pos rfl — but h 0 is `h 0` — with hh : h = fun n => if n = 0 then... — after rw [hh], h 0 becomes (fun n => if n = 0 then (0:ℝ) else ...) 0 — a beta-redex — simp only [if_pos] with the beta... The `rw [hh]` inside the show-haves: `show h 1 = (0:ℝ) from by rw [hh]; simp` — after rw [hh]: (fun n => ...) 1 = 0 — simp handles the beta + if_neg (1 ≠ 0) + log 1 = 0 + 0/1 = 0 ✓ probably. This head computation is fiddly — iterate at build. Actually — a cleaner head computation: use `Finset.sum_range_four`? There's `Finset.sum_range_one/two/three/four`? Hmm — `Finset.sum_range_succ` chain is the standard. Or convert to explicit: `decide`? no (real values). Let me keep the chain and fix at build. 5. hle's form in tsum_log_div_sq_tail_le: antitoneOn_log_div_sq.tsum_comp_add_le_integral 3 integrableOn_log_div_sq nonneg — tsum_comp_add_le_integral (N : ℕ) (anti : AntitoneOn f (Ici (N:ℝ))) (integrable ...) (nonneg ...) : ∑' (n : ℕ), f (↑(n + N + 1)) ≤ ∫ x in Ioi N, f x. With N := 3: ∑' n, f (↑(n+3+1)) — note: ↑(n + 3 + 1) with the ℕ add then cast. My target: ∑' n, log (↑n+4)/(↑n+4)². The congr: f (↑(n+3+1)) = log (↑(n+3+1))/(↑(n+3+1))² vs log (↑n+4)/(↑n+4)²: ↑(n+3+1) = ↑n + 4 via push_cast ✓. My code: ```lean rw [integral_log_div_sq_Ioi_three] at hle refine hle.trans_eq' ?_ refine tsum_congr fun n => ?_ push_cast ring_nf ``` hle : ∑' n, (fun x => log x/x²) ↑(n+3+1) ≤ (log 3+1)/3 (after the rw — wait, rw [integral_log_div_sq_Ioi_three] at hle rewrites the integral to the value ✓). Then hle.trans_eq' (h : b = c)? : a ≤ b → b = c → a ≤ c — trans_eq' : a ≤ b → b = c → a ≤ c ✓. The tsum_congr gives equality of the tsums... my goal after refine hle.trans_eq' ?_ : ∑' n, (fun x => log x/x²) ↑(n+3+1) = ∑' n, log (↑n+4)/(↑n+4)² — via tsum_congr + push_cast + ring_nf ✓ plausible. 6. In dirichletC2_le_one: the final `linarith [hmain, hlog2, hlog3, hlog2nn, hlog3nn]`: goal dirichletC2 ≤ 1 — wait I did `rw [dirichletC2]` at the start — dirichletC2 IS the def: rw [dirichletC2] unfolds to the tsum ✓ (def-rw). Then goal: ∑' n, ‖term‖ ≤ 1. hmain : ∑' n, ‖term‖ ≤ log 2/4 + log 3/9 + (log 3+1)/3. linarith with log 2 ≤ 0.6932, log 3 ≤ 1.1: log2/4 + log3/9 + (log3+1)/3 ≤ 0.6932/4 + 1.1/9 + 2.1/3 = 0.1733 + 0.12222 + 0.7 = 0.9955 ≤ 1 ✓ linarith (nonneg logs for the monotonicity — linarith does linear arithmetic: log2/4 ≤ 0.6932/4 needs log2 ≤ 0.6932 ✓ linear ✓; the combination: linarith handles division-by-constant ✓). 7. `Real.log_two_lt_d9 : Real.log 2 < 0.6931471808` ✓ exists (banked). `.le.trans (by norm_num)` : log 2 ≤ 0.6932 ✓. 8. The summable_nat_add_iff direction: `summable_nat_add_iff (k : ℕ) : Summable (fun n => f (n + k)) ↔ Summable f` — so .mp : Summable (fun n => h (n+4)) → Summable h ✓ as written in hsumh. ✓ 9. In hsumh's h1: `apply summable_log_div_sq_tail.congr; intro n; rw [hh]; show (if (n+4:ℕ) = 0 then ...) = ...` — Summable.congr (hf : Summable f) (h : ∀ i, f i = g i) : Summable g — apply ... .congr: goal Summable (fun n => h (n+4)): congr with f := the tail's function: needs ∀ n, log(↑n+4)/(↑n+4)² = h (n+4)?? — congr's h : f i = g i where f = tail-fn, g = the goal's fn: log (↑n+4)/(↑n+4)² = h (n+4): my show has them flipped: `show (if ...) = log (↑n+4)/...` — that's g n = f n. Order matters for congr — Summable.congr (hf : Summable f) (h : ∀ i, f i = g i) : Summable g — so h : f i = g i = (tail-fn) i = h(n+4)-form... Let me just symmetrize at build if it fails. Let me now splice and build.
Now splice: head + new §6 + tail.
tool: Bash
input
{
  "command": "cd D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1 && cat /tmp/litightr_head.txt litightr_mid.tmp /tmp/litightr_tail.txt > LiTightR.lean && rm litightr_mid.tmp && wc -l LiTightR.lean && export PATH=\"$HOME/.elan/bin:$PATH\" && cd D:/Python/Quantum/research/lean/NguyenRH1 && lake env lean NguyenRH1/LiTightR.lean 2>&1 | head -40",
  "description": "Splice LiTightR and compile",
  "timeout": 300000
}
#1739 assistant 2026-08-24 09:49:47.938 UTC · 1415→3638 tok open ⤢
thinking (10066 chars)
Multiple issues: 1. **Unknown identifiers**: `tendsto_pow_log_div_mul_add_atTop`, `tendsto_one_div_atTop_nhds_zero`, `IntegrableOn`, `integrableOn_Ioi_deriv_of_nonneg'`, `integral_Ioi_of_hasDerivAt_of_tendsto'` — these need namespaces: they're in `Real.tendsto_pow_log_div_mul_add_atTop` (Log/Basic.lean is in `namespace Real`), and the IntegralEqImproper ones are in `MeasureTheory`. So: - `Real.tendsto_pow_log_div_mul_add_atTop` - `tendsto_one_div_atTop_nhds_zero` — hmm, unknown — might be `tendsto_one_div_atTop_nhds_zero` in a different spot or named differently. Let me check. - `MeasureTheory.IntegrableOn` — the file doesn't open MeasureTheory. Add `open MeasureTheory`? or qualify. The project opens `Zeta23 Complex Filter Topology` — add MeasureTheory to the open line? Simpler: qualify `MeasureTheory.IntegrableOn` etc. Actually the IntegrableOn in my lemma statements — `IntegrableOn (fun x => ...) (Set.Ioi 3) volume` — IntegrableOn is in MeasureTheory namespace. Qualify or open. - `MeasureTheory.integral_Ioi_of_hasDerivAt_of_tendsto'` (from IntegralEqImproper.lean:813: `theorem integral_Ioi_of_hasDerivAt_of_tendsto'` — the grep showed it at line 813 without namespace context; the file header says "MeasureTheory.integral_Ioi_of_hasDerivAt_of_tendsto is a version..." — so it's in MeasureTheory namespace ✓). - `MeasureTheory.integrableOn_Ioi_deriv_of_nonneg'`? The grep found it at IntegralEqImproper.lean:865 — same namespace presumably. 2. **dirichletTerm_norm_eq**: h2's rewrite issue: `‖↑n ^ 2‖ = ↑n ^ 2` — the h2 I derived is ‖(↑n)^2‖ = ↑n^2 (norm_pow gave ‖↑n‖^2 then norm_real... wait the error shows h2 : ‖↑n ^ 2‖ = ↑n ^ 2 — actually that succeeded. The remaining goal: `Λ n / ↑n^2 = if n = 0 then 0 else Λ n / ↑n^2` — needs if_neg hn — I did `rw [LSeries.term_def, if_neg hn, norm_div]` at the start — the if_neg was applied to the LSeries.term's internal if, but the GOAL's RHS still has `if n = 0 then 0 else ...` — I need to also rw if_neg on the RHS. The goal after rw [h1, h2] should be `Λ n / ↑n^2 = if n = 0 then 0 else Λ n / ↑n^2` — just add `rw [if_neg hn]` or the goal closes by `simp [hn]`. Also the "Zero ?m.150" error at 220:30 — `abs_of_nonneg (by positivity)` — positivity failed to find a Zero for the metavariable? The h2 second part: `rw [show ((n:ℂ)) = ((n:ℝ):ℂ) by push_cast; ring, Complex.norm_real]` then `exact abs_of_nonneg (by positivity)` — hmm the goal there: ‖((n:ℝ):ℂ)‖ = (n:ℝ)^2 — wait no. Let me recheck h2: goal ‖(↑n)^(2:ℂ)‖ = ↑n^2. Step 1: rw [show (↑n)^(2:ℂ) = (↑n)^(2:ℕ) by exact_mod_cast rfl] — hmm (2:ℂ) = ((2:ℕ):ℂ)? `exact_mod_cast rfl` — the rfl is (2:ℂ) = (2:ℕ)? — the cast: ((2:ℕ):ℂ) vs (2:ℂ) — `by exact_mod_cast rfl`: hmm — better: `cpow_natCast (↑n) 2 : (↑n)^((2:ℕ):ℂ) = (↑n)^2`. The show-form: (↑n)^((2:ℕ):ℂ) = (↑n)^(2:ℕ): that's cpow_natCast ✓. But my show was (↑n)^(2:ℂ) = (↑n)^(2:ℕ) — needs (2:ℂ) = ((2:ℕ):ℂ) first — the `exact_mod_cast rfl` aims at that? The error at 220 is the Zero synthesis — from `by positivity` needing a Zero instance with a metavariable (the abs_of_nonneg's implicit type wasn't determined). Let me restructure h2: ```lean have h2 : ‖((n : ℂ)) ^ (2 : ℂ)‖ = (n : ℝ) ^ 2 := by rw [show ((n : ℂ)) ^ (2 : ℂ) = ((n : ℂ)) ^ (2 : ℕ) by exact_mod_cast cpow_natCast _ 2] ``` hmm — cpow_natCast (x) (n) : x ^ (↑n) = x ^ n — so cpow_natCast (n:ℂ) 2 : (↑n)^((2:ℕ):ℂ) = (↑n)^2 — and my LHS has (↑n)^(2:ℂ) — (2:ℂ) vs ((2:ℕ):ℂ) — defeq but the rw match needs syntactic: the show's LHS is (↑n)^(2:ℂ), RHS (↑n)^(2:ℕ) — rewriting goal's (↑n)^(2:ℂ) with... the show statement IS (↑n)^(2:ℂ) = (↑n)^(2:ℕ): to prove it: `by exact_mod_cast cpow_natCast _ 2` — cpow_natCast gives (↑n)^((2:ℕ):ℂ) = (↑n)^(2:ℕ) — the goal (↑n)^(2:ℂ) = (↑n)^(2:ℕ) — exact_mod_cast bridges the exponent cast ✓ plausible. Then norm_pow: ‖(↑n)^2‖ = ‖↑n‖^2 ✓; then Complex.norm_real: ‖((n:ℝ):ℂ)‖ = |n| — but the term is ↑n where the coercion is ℕ→ℂ: ((n:ℂ)) = (((n:ℕ):ℝ):ℂ)? — the norm_real applies to ((x:ℝ):ℂ) — my show ((n:ℂ)) = ((n:ℝ):ℂ) by push_cast; ring ✓ then Complex.norm_real: ‖((n:ℝ):ℂ)‖ = |n| — then abs_of_nonneg (n ≥ 0): |n| = n — but the goal after norm_real: |(n:ℝ)| = (n:ℝ)^2?? — WAIT the goal after norm_pow: ‖↑n‖^2 = ↑n^2 — then rw [show ((n:ℂ)) = ((n:ℝ):ℂ) ..., Complex.norm_real]: ‖↑n‖ becomes |(n:ℝ)|: goal |(n:ℝ)|^2 = ↑n^2 — then rw [abs_of_nonneg (Nat.cast_nonneg n)] : (↑n)^2 = ↑n^2 ✓ rfl-close. My original had `exact abs_of_nonneg (by positivity)` — wrong: the goal was |↑n|^2 = ↑n^2 not |↑n| = ↑n — that's why the Zero-metavariable. Fix: rw [abs_of_nonneg (Nat.cast_nonneg _)] then the goal is rfl. Let me rewrite h2: ```lean have h2 : ‖((n : ℂ)) ^ (2 : ℂ)‖ = (n : ℝ) ^ 2 := by rw [show ((n : ℂ)) ^ (2 : ℂ) = ((n : ℂ)) ^ (2 : ℕ) by exact_mod_cast cpow_natCast _ 2, norm_pow] rw [show ((n : ℂ)) = ((n : ℝ) : ℂ) by push_cast; ring, Complex.norm_real, abs_of_nonneg (Nat.cast_nonneg n)] ``` After the last rw chain: goal (n:ℝ)^2 = (n:ℝ)^2 — rw auto-closes ✓ (rw closes by rfl). Hmm wait — norm_pow: ‖x^n‖ = ‖x‖^n ✓ for normed division rings. Then ‖(n:ℂ)‖^2: rw [show ((n:ℂ)) = ((n:ℝ):ℂ)...] — the base of the outer ‖·‖^2 — the show's LHS ((n:ℂ)) must match the ‖·‖'s argument ✓. 3. **hasDerivAt_neg_log_add_one_div**: the convert goals show h2's function as `-((fun x => Real.log x + 1) / fun x => x)` — the div produced a Pi.div of functions (HDiv on functions!) — `(fun x => log x + 1) / (fun x => x)` — so the .div's function is the pointwise function division, NOT fun y => (log y + 1)/y directly (they're defeq via Pi.div_apply). And the value: `((x⁻¹ * x - (Real.log x + 1) * 1) / x ^ 2)` — with x⁻¹ — the div derivative form. My convert goals: - `(fun y => -(Real.log y + 1) / y) = -((fun x => Real.log x + 1) / fun x => x)`: the Pi.div/neg: ext y; simp [Pi.div_apply, Pi.neg_apply, neg_div]? The simp [neg_div] "made no progress" warning at 230 — because the forms are Pi-applied. Fix: ext y; simp only [Pi.neg_apply, Pi.div_apply]; rw [neg_div]. - The value: `Real.log x / x^2 = -((x⁻¹*x - (Real.log x + 1)*1)/x^2)`: field_simp; ring — the error shows this goal remained (the convert produced it but my simp only [id_eq] — there was no id_eq (the d was fun x => x not id!). The .div used hasDerivAt_id' — hmm hasDerivAt_id' : HasDerivAt (fun x => x) 1 x? — apparently (fun x => x) form. So no id_eq to simp. The value goal: field_simp then ring should work: −((x⁻¹·x − (log x+1))/x²) = log x/x² ⟺ −(x⁻¹·x − log x − 1) = log x ⟺ −x⁻¹·x + log x + 1 = log x ⟺ 1 = x⁻¹·x ✓ (x ≠ 0). field_simp [hx0] should clear... field_simp needs hx0 in scope ✓ hx0 is there. The order of my tactics: I wrote `simp only [id_eq]; field_simp; ring` — simp only [id_eq] made no progress?? (no id in the goal — it's fun x => x) — "made no progress" would ERROR (simp only fails if no progress? — no: simp only fails only with `simp made no progress` error for plain simp; simp only with unused args gives linter warnings). The value goal error at 225:74 — the unsolved goals: the ext/simp [neg_div] didn't close the function goal, cascading. Let me rewrite this lemma more carefully: ```lean lemma hasDerivAt_neg_log_add_one_div {x : ℝ} (hx0 : x ≠ 0) : HasDerivAt (fun y => -(Real.log y + 1) / y) (Real.log x / x ^ 2) x := by have h1 := ((Real.hasDerivAt_log hx0).add_const 1).div (hasDerivAt_id' x) hx0 have h2 := h1.neg convert h2 using 1 · ext y simp only [Pi.neg_apply, Pi.div_apply] rw [neg_div] · field_simp ring ``` Hmm — hasDerivAt_id' : HasDerivAt (fun x => x) (1) x? — wait the banked gotcha from session 033: "hasDerivAt_id' s₀ |>.div_const 2" — hasDerivAt_id' (x)? Actually `hasDerivAt_id' : HasDerivAt (fun x => x) 1 x`? There's `hasDerivAt_id (x) : HasDerivAt id 1 x` and `hasDerivAt_id' : HasDerivAt (fun x ↦ x) 1 x`? Either way d = (fun x => x) or id. The value from .div: (c' * d x − c x * d')/(d x)^2 with d x = x: (1/x · x − (log x + 1)·1)/x² — the 1/x displayed as x⁻¹ ✓ matches the error display. The value goal: `Real.log x / x ^ 2 = -((x⁻¹ * x - (Real.log x + 1) * 1) / x ^ 2)`: field_simp [hx0] — clears x⁻¹ and x²: −(x⁻¹·x − (log x+1))·... let me trust field_simp + ring with hx0 present. If field_simp struggles: prove directly: −((x⁻¹·x − (log x+1)·1)/x²) = log x/x²: rw [div_mul_cancel₀? no. Compute: x⁻¹·x = 1 (inv_mul_cancel₀ hx0): rw [inv_mul_cancel₀ hx0]: −((1 − (log x + 1)·1)/x²) = −((−log x)/x²) = log x/x²: ring after. Let me do: ```lean · rw [inv_mul_cancel₀ hx0] field_simp ring ``` Hmm — the goal form Real.log x / x^2 = −((x⁻¹*x − ...)/x^2): rw [inv_mul_cancel₀ hx0] rewrites x⁻¹*x → 1 ✓ then the goal is log x/x² = −((1 − (log x+1))/x²): field_simp; ring or just ring (divisions with the same denominator — ring handles: −((1−(L+1))/x²) = −(1−L−1)/x² = L/x² ✓ ring over a field with x² as an atom ✓ ring alone should do it!). So: rw [inv_mul_cancel₀ hx0]; ring. 4. **Line 253 `IntegrableOn` Function-expected error**: consequence of unknown IntegrableOn (namespace). Fix with MeasureTheory qualification or `open MeasureTheory`. Wait — actually does the project use IntegrableOn elsewhere unqualified? LiRBound used parameter-integral analyticity — let me check how it wrote IntegrableOn. Quick grep. 5. **Line 257 "No goals"**: my `·` bullets after apply integrableOn_Ioi_deriv_of_nonneg' — the apply produced goals in a different order/count. With the qualified name the structure should work; the "No goals" was because the apply failed (unknown identifier) leaving odd goal state. Cascade. 6. Similarly integral_Ioi_of_hasDerivAt_of_tendsto' unknown → qualify MeasureTheory. 7. `Real.tendsto_pow_log_div_mul_add_atTop` — actually wait: the grep found it at Log/Basic.lean:440 as `theorem tendsto_pow_log_div_mul_add_atTop` — inside `namespace Real`? Log/Basic.lean has namespace Real presumably ✓ so Real.tendsto_pow_log_div_mul_add_atTop. 8. `tendsto_one_div_atTop_nhds_zero` — unknown identifier. Search the real name: maybe `tendsto_one_div_atTop_nhds_zero` doesn't exist; alternatives: `tendsto_inv_atTop_zero`? `tendsto_one_div...`? Let me grep.
Namespace issues + a few form mismatches. Checking the exact names and how the project references IntegrableOn.
tool: Bash
input
{
  "command": "M=D:/Python/Quantum/zeta-23-lean/.lake/packages/mathlib/Mathlib; grep -rn \"tendsto_one_div_atTop\\|tendsto_inv_atTop_zero\" $M --include=\"*.lean\" | grep theorem | head -4; grep -rn \"open MeasureTheory\\|MeasureTheory.IntegrableOn\\|IntegrableOn\" D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1/LiRBound.lean | head -5",
  "description": "Find one_div tendsto name and IntegrableOn usage pattern"
}
#1740 assistant 2026-08-24 09:52:27.100 UTC · 346→4076 tok open ⤢
thinking (10767 chars)
`open ... MeasureTheory` — that's the pattern. Add MeasureTheory to LiTightR's open line. Then IntegrableOn, integrableOn_Ioi_deriv_of_nonneg', integral_Ioi_of_hasDerivAt_of_tendsto' resolve (they're in MeasureTheory namespace? — integral_Ioi_of_hasDerivAt_of_tendsto' at IntegralEqImproper.lean:813 — let me assume namespace MeasureTheory; if open doesn't resolve, qualify). Actually wait — is integral_Ioi_of_hasDerivAt_of_tendsto' in MeasureTheory namespace? The file's docstring said "MeasureTheory.integral_Ioi_of_hasDerivAt_of_tendsto is a version of FTC-2" — suggesting the namespace. With open MeasureTheory it resolves either way if namespaced there. Now apply all the fixes: 1. Add MeasureTheory to open. 2. dirichletTerm_norm_eq h2 fix. 3. hasDerivAt_neg_log_add_one_div: the convert goals fix. 4. Real.tendsto_pow_log_div_mul_add_atTop. 5. tendsto_inv_atTop_zero for 1/x: `(1:ℝ)/x = x⁻¹` via one_div — heq needs care: hB : Tendsto (fun x => (1:ℝ)/x) atTop (𝓝 0) := by simpa [one_div] using tendsto_inv_atTop_zero? Tendsto (fun x => x⁻¹) vs (fun x => 1/x): one_div: 1/x = x⁻¹ — `by simpa only [one_div] using tendsto_inv_atTop_zero` — simpa only [one_div] rewrites 1/x → x⁻¹ in the goal, matching tendsto_inv_atTop_zero ✓. Or write the hB with x⁻¹ directly and adjust heq. Let me use: ```lean have hB : Tendsto (fun x => (1 : ℝ) / x) atTop (𝓝 0) := by simpa only [one_div] using tendsto_inv_atTop_zero ``` Hmm — `simpa only [one_div] using tendsto_inv_atTop_zero`: one_div : 1/a = a⁻¹ — simpa rewrites the GOAL (fun x => 1/x) → (fun x => x⁻¹)? simp rewrites occurrences of 1/?x — in a lambda body ✓ should work. 6. hasDerivAt_neg_log_add_one_div convert: ```lean convert h2 using 1 · ext y simp only [Pi.neg_apply, Pi.div_apply] rw [neg_div] · rw [inv_mul_cancel₀ hx0] ring ``` Wait — the convert goals from the error: goal 1: `(fun y => -(Real.log y + 1) / y) = -((fun x => Real.log x + 1) / fun x => x)`. ext y: `-(Real.log y + 1) / y = (-((fun x => Real.log x + 1) / fun x => x)) y`: simp only [Pi.neg_apply, Pi.div_apply]: RHS: -( ((fun x => log x+1) / (fun x => x)) y ) = -( (log y+1)/y )·(Pi.div_apply) — wait: Pi.neg_apply: (-f) y = -(f y); Pi.div_apply: (f/g) y = f y / g y. So RHS → -( (log y + 1)/y ). Goal: -(log y+1)/y = -((log y+1)/y) — then rw [neg_div] on the LHS: -(a/b) = (-a)/b... neg_div : -(a/b) = -a/b — LHS −(log y+1)/y parses as (−(log y+1))/y — hmm: `-(Real.log y + 1) / y` = `(-(Real.log y + 1)) / y` (unary minus binds tighter than /) — and the RHS −((log y+1)/y). neg_div : -(a / b) = -a / b — rewriting RHS direction... the goal is LHS = RHS with LHS = (−(log y+1))/y and RHS = −((log y+1)/y): rw [neg_div] turns −((log y+1)/y) into (−(log y+1))/y ✓ closes by rfl (rw auto-closes). But rw [neg_div] rewrites ALL −(_/_) patterns: the LHS (−(log y+1))/y has no −(_/_) form (the minus is on the numerator) ✓ so only RHS rewrites ✓. Wait — but actually h2's function is `-((fun x => Real.log x + 1) / fun x => x)` — Pi.neg of the Pi.div. My convert-goal-1 as displayed: `(fun y => -(Real.log y + 1) / y) = -((fun x => Real.log x + 1) / fun x => x)` ✓. After ext y and simp only [Pi.neg_apply, Pi.div_apply]: RHS becomes -(Real.log y + 1) / y·... hold on: (−(F/G)) y → Pi.neg_apply: −((F/G) y) → Pi.div_apply: −(F y / G y) = −((log y + 1)/y). And LHS: (fun y => −(log y+1)/y) y → beta: −(log y+1)/y = (−(log y+1))/y. So goal: (−(log y+1))/y = −((log y+1)/y): rw [neg_div] rewrites RHS −((log y+1)/y) → (−(log y+1))/y ✓ rfl. Hmm — but does ext y produce the beta-reduced forms? ext y then the goal shows the applications; simp only [Pi.neg_apply, Pi.div_apply] also beta-reduces? simp does beta-reduce ✓. Value goal: `Real.log x / x ^ 2 = -((x⁻¹ * x - (Real.log x + 1) * 1) / x ^ 2)`: rw [inv_mul_cancel₀ hx0] — x⁻¹ * x = 1: inv_mul_cancel₀ : a⁻¹ * a = 1? The name: `inv_mul_cancel₀ (h : a ≠ 0) : a⁻¹ * a = 1` ✓. Then goal: log x/x² = −((1 − (log x+1)·1)/x²): ring ✓ (field-free: same denominator — ring handles −((1−(L+1))/x²) = L/x² as ring identity with x⁻² atom? ring works in the field with x as an atom — the identity: −((1−(L+1)·1)/x²) = (L)/x² — yes ring proves it treating x as a variable (no division elimination needed since both sides have /x² — ring normalizes division by x² as ·x⁻²... in a field expression, ring handles ✓). 7. In integral_log_div_sq_Ioi_three: `rw [h]` then show. h : ∫ ... = 0 − (fun y => −(log y+1)/y) 3 — the beta-redex. My `show (0:ℝ) − (−(Real.log 3 + 1)/3) = (Real.log 3+1)/3` — defeq to the redex form ✓ then ring. Hmm — actually integral_Ioi_of_hasDerivAt_of_tendsto' gives ∫ = m − f a where f a is (fun y => −(log y+1)/y) 3 — beta: −(log 3+1)/3. show with the reduced form ✓ defeq ✓. 8. In antitoneOn_log_div_sq: `differentiableAt_pow _ _` — signature check: `differentiableAt_pow (n : ℕ) (x : 𝕜)?`: I recall `differentiableAt_pow (n : ℕ) (x : 𝕜) : DifferentiableAt 𝕜 (fun x => x ^ n) x`? or (𝕜) (n)? It's `differentiableAt_pow (n : ℕ) (x : 𝕜)` hmm — actually I think it's `differentiableAt_pow (n : ℕ) (x : R)` with R implicit — let me just write `(differentiableAt_pow 2 x)`? hmm the error-prone part. Alternative robust: `(DifferentiableAt.pow differentiableAt_id 2)`? differentiableAt_id : DifferentiableAt 𝕜 id x; .pow 2 hmm — DifferentiableAt.pow : DifferentiableAt 𝕜 f x → ∀ n, DifferentiableAt 𝕜 (fun x => (f x)^n) x? — `differentiableAt_id.pow 2`? hmm the power of id: (fun x => x^2) vs (id)^2 — defeq fine. Let me use `(differentiableAt_id.pow 2)`. Hmm — DifferentiableAt.pow : DifferentiableAt 𝕜 f x → (n : ℕ) → DifferentiableAt 𝕜 (f ^ ·) x — the function (fun x => (id x)^2) = (fun x => x^2) ✓ defeq — but the .div application needs the exact function fun y => y^2 — (id ·)^2 vs (fun y => y^2): Pi.pow_apply-ish defeq — the DifferentiableAt.div expects DifferentiableAt g with g syntactically = (fun y => y^2)? — no, up to defeq for `exact` but for the `.div` METHOD: `(Real.differentiableAt_log hx0).div (differentiableAt_pow ...) _` produces DifferentiableAt (f/g) with g = whatever the second arg's function is — then the goal's (fun y => log y/y^2) vs (log ·)/(·^2) — Pi.div of the two — defeq; my `exact` needs the final form defeq to the goal ✓ should be OK. Let me check hasDerivAt_pow's signature: `hasDerivAt_pow (n : ℕ) (x : 𝕜) : HasDerivAt (fun x => x^n) (n*x^(n-1)) x`? I used `(hasDerivAt_pow 2 x)` in the deriv computation ✓ that should be right. 9. The `summable_nat_add_iff` — for ℝ: it exists (the NNReal one is nonrec of the general). 10. In dirichletC2_le_one — the hhead block: my sum_range_succ chain + simp only + the show-rws. Let me simplify: after the range expansion, the goal is ((((0 + h 0) + h 1) + h 2) + h 3) = log 2/4 + log 3/9 — with h = fun n => if n = 0 then 0 else log n/n². rw [hh] turns h 0 into the redex (fun n => ...) 0 — hmm — actually with `set h := ... with hh`, the occurrences in my written goals... the h 0 terms appear after the sum_range expansion — they're `h 0` (the set-var applied). rw [hh] rewrites h → the lambda: (fun n => if n = 0 then ...) 0. Then `simp` should beta-reduce + if_pos + log_one + ... Let me simplify the whole head block: ```lean have hhead : ∑ n ∈ Finset.range 4, h n = Real.log 2 / 4 + Real.log 3 / 9 := by rw [Finset.sum_range_succ, Finset.sum_range_succ, Finset.sum_range_succ, Finset.sum_range_succ, Finset.sum_range_zero] have h0 : h 0 = (0:ℝ) := by rw [hh]; simp have h1' : h 1 = (0:ℝ) := by rw [hh]; simp have h2' : h 2 = Real.log 2 / 4 := by rw [hh]; simp; ring_nf have h3' : h 3 = Real.log 3 / 9 := by rw [hh]; simp; ring_nf rw [h0, h1', h2', h3'] ring ``` h2': h 2 = (fun n => if n = 0 then 0 else log ↑n/↑n²) 2 — simp: beta + if_neg (2 ≠ 0) + cast: gives log 2/(2:ℝ)² hmm — the cast (↑(2:ℕ) : ℝ) = (2:ℝ): simp's Nat.cast_ofNat ✓ and (2:ℝ)² = 4: simp might not do that — add ring_nf: log 2/(2^2) = log 2/4: ring_nf ✓. Let me also double check `Real.log_two_lt_d9` — used in two_le_C0hat? no — used in LiContour two_le_C0hat: `Real.exp_one_lt_d9.le` ✓ and log_two: from LiGapCircles/journal: "log 4150 ≤ 9 (e > 2.71)"... Real.log_two_lt_d9 : Real.log 2 < 0.6931471808 ✓ exists in Mathlib (Real.log_two_lt_d9). ✓ 11. hsplit's sum_add_tsum_nat_add: `sum_add_tsum_nat_add (k : ℕ) (hf : Summable f) : (∑ i ∈ range k, f i) + ∑' i, f (i + k) = ∑' i, f i`? If the name/direction differs, fix at build. Also the h (n+4) shift: the shifted function fun n => h (n + 4) — h applied to ↑(n+4)?? — h : ℕ → ℝ so h (n+4) with n+4 : ℕ ✓. 12. In htail's h1: `show (if (n + 4 : ℕ) = 0 then (0 : ℝ) else Real.log (n + 4) / ((n + 4 : ℕ) : ℝ) ^ 2) = Real.log ((n : ℝ) + 4) / ((n : ℝ) + 4) ^ 2` — after rw [hh]: h (n+4) = (fun n => if...) (n+4) — the show's LHS must be defeq: (if n+4 = 0 then 0 else log ↑(n+4)/↑(n+4)²) — hmm: the lambda's body has Real.log (n+4) — with the n+4 inside log: ℕ or ℝ? The h def: `fun n => if n = 0 then (0 : ℝ) else Real.log n / (n : ℝ) ^ 2` — Real.log n with n : ℕ coerced: Real.log (↑n) — and /(↑n)². So h (n+4) = if (↑(n+4))... if (n+4 : ℕ) = 0 then 0 else log (↑(n+4))/↑(n+4)². My show: `Real.log (n + 4) / ((n + 4 : ℕ) : ℝ) ^ 2` — the `Real.log (n + 4)`: (n+4) here elaborates as ↑(n+4)? — Real.log needs ℝ: (n+4) with n : ℕ — coercion: ↑(n+4)? or ↑n + 4? Ambiguity — Lean elaborates Real.log (n + 4) by coercing... the expected type ℝ makes (n + 4 : ℝ) with n coerced: ↑n + 4 (HAdd ℝ). Hmm — actually for `Real.log (n + 4)` with n : ℕ: unification: Real.log : ℝ → ℝ; the arg n + 4 must be ℝ: n + 4 could elaborate in ℕ then cast (OfNat 4 in ℕ, HAdd ℕ, then ↑) or in ℝ (coe n, OfNat 4 in ℝ). Lean's default: the coercion is inserted around the SMALLEST subterm — for `Real.log (n + 4)`: the elaborator tries to unify (n + 4)'s type with ℝ — n + 4 : ℕ (n : ℕ, 4 : ℕ via OfNat) then coe ↑ — I THINK it does ↑(n + 4). Hmm — actually with the coercion elaboration, `n + 4` at expected type ℝ: the + gets unified at ℝ: (↑n + 4) — Lean 4 coerces by inserting ↑n — I believe it produces ↑n + 4 (the coercion goes on the variable). So my show's LHS has log (↑n + 4)? and h (n+4) has log ↑(n+4) — MISMATCH (↑(n+4) vs ↑n + 4 — defeq via push_cast but not syntactic for `show`). To be safe, write the h-application forms with explicit casts: h (n+4) = if (n+4) = 0 then 0 else Real.log (↑(n+4))/(↑(n+4))² and the tail form Real.log (↑n + 4)/(↑n+4)² — the bridge: ↑(n+4) = ↑n + 4 by push_cast. Ugh. Let me simplify: define the tail function as `fun n : ℕ => Real.log ((n : ℝ) + 4) / ((n : ℝ) + 4) ^ 2` EVERYWHERE consistently (as I did) and prove h (n + 4) = that by: rw [hh]; show (if ...) = ...; rw [if_neg (by omega : (n+4:ℕ) ≠ 0)]; push_cast; ring_nf. The push_cast converts ↑(n+4) → ↑n + 4 ✓ then the sides match — ring_nf/rfl. That's what I wrote ✓. OK — apply all fixes now. Let me make the edits to the file.
Applying all fixes: MeasureTheory open, the h2 cast, the convert-goal forms, and the tendsto names.
tool: Bash
input
{
  "command": "cd D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1 && grep -n \"^open\" LiTightR.lean && grep -n \"hasDerivAt_neg_log_add_one_div\\|tendsto_neg_log_add_one_div\\|h2 : \u2016\\|convert h2\\|have hval\\|have hfn\\|rw \\[\u2190 hfn\" LiTightR.lean | head -12",
  "description": "Locate edit targets in the spliced file"
}
#1741 assistant 2026-08-24 09:56:31.325 UTC · 1123→2932 tok open ⤢
thinking (6803 chars)
Issues: 1. **dirichletTerm_norm_eq h2** (line 216-220): the first `rw [show ((n:ℂ))^(2:ℂ) = ((n:ℂ))^(2:ℕ) by exact_mod_cast cpow_natCast _ 2, norm_pow]` — the exact_mod_cast failed: "mod_cast has type ?m^2 = ?m^2 but expected n^2 = n^2" — hmm, the show's proof: `exact_mod_cast cpow_natCast _ 2` — cpow_natCast x n : x ^ (↑n) = x ^ n — with x := (n:ℂ), n := 2: (↑n)^((2:ℕ):ℂ) = (↑n)^2 — the goal: (↑n)^(2:ℂ) = (↑n)^(2:ℕ) — exact_mod_cast bridges (2:ℂ) vs ((2:ℕ):ℂ)... the error "mod_cast has type ?m^2 = ?m^2 but expected n^2 = n^2" suggests the show statement itself is confusing. Let me restructure: the goal is ‖(↑n)^(2:ℂ)‖ = (↑n)^2. Better: first convert the cpow to a pow via cpow_natCast directly on the NORM: ‖(↑n)^(2:ℂ)‖ = ‖(↑n)^2‖ — rw [show ((n:ℂ))^(2:ℂ) = ((n:ℂ))^2 from cpow_natCast _ 2]? cpow_natCast (x : ℂ) (n : ℕ) : x ^ (n : ℂ) = x ^ n — so cpow_natCast (n:ℂ) 2 : (↑n)^((2:ℕ):ℂ) = (↑n)^2. My LHS has (↑n)^(2:ℂ) — the exponent (2:ℂ) vs ((2:ℕ):ℂ): same? (2:ℂ) is OfNat 2 in ℂ; ((2:ℕ):ℂ) is Nat.cast 2 = also reduces to OfNat 2 in ℂ — are they syntactically the same? Nat.cast 2 = Nat.cast (OfNat.ofNat 2)... the elaborated (2:ℂ) is `@OfNat.ofNat ℂ 2 instOfNat...`; cpow_natCast's form has `↑(2:ℕ)` = `@Nat.cast ℂ _ 2`. These are defeq but not syntactic — rw would fail to match. The show-bridge: show ((n:ℂ))^(2:ℕ) = ... no. Simplest robust: `rw [show (2:ℂ) = ((2:ℕ):ℂ) by norm_num, cpow_natCast]` — (2:ℂ) = ↑(2:ℕ): by norm_num or push_cast;rfl. Then cpow_natCast rewrites (↑n)^(↑(2:ℕ)) → (↑n)^2 ✓. Then ‖(↑n)^2‖ = ‖↑n‖^2 (norm_pow). Then ‖(↑n:ℂ)‖: it's the Nat.cast into ℂ: ‖(↑n : ℂ)‖ = (n : ℝ): `Complex.norm_natCast (↑n : ℂ)‖ = ↑n`? — Complex.norm_natCast (n : ℕ) : ‖(n : ℂ)‖ = n ✓ (used in LiCircleBound:3410). So: ```lean have h2 : ‖((n : ℂ)) ^ (2 : ℂ)‖ = (n : ℝ) ^ 2 := by rw [show (2 : ℂ) = ((2 : ℕ) : ℂ) by norm_num, cpow_natCast, norm_pow, Complex.norm_natCast] ``` After: goal ‖(↑n:ℂ)‖^2 = ↑n^2 → norm_pow → ‖↑n‖^2 hmm order: after cpow_natCast the term is (↑n)^(2:ℕ) = (↑n)^2; norm_pow: ‖↑n‖^2 = ↑n^2 — wait the goal is ‖(↑n)^2‖ = (↑n:ℝ)^2: rw [norm_pow]: ‖↑n‖^2 = ↑n^2; rw [Complex.norm_natCast]: (↑n:ℝ)^2 = (↑n:ℝ)^2 ✓ rfl close. So the chain: rw [show (2:ℂ) = ((2:ℕ):ℂ) by norm_num, cpow_natCast, norm_pow, Complex.norm_natCast]. 2. **hasDerivAt_neg_log_add_one_div** — the convert produced weird instance-equality goals (Semiring.toModule = ...toModule — the convert's HOU issues). The convert approach is fragile here. Alternative: avoid convert — state h2 with the exact function form first via `have h2' : HasDerivAt (fun y => -(Real.log y + 1)/y) (...) x := by convert h2 using 1 ...` — same problem. Better: transform h2 manually: h2 : HasDerivAt (-(F/G)) (−val) x where -(F/G) is the Pi-neg/Pi-div composite. Use HasDerivAt.congr... Actually — simplest: rewrite my LEMMA's function to match what .div/.neg produce: state the lemma with the function `(fun y => -((Real.log y + 1) / y))`: ```lean lemma hasDerivAt_neg_log_add_one_div {x : ℝ} (hx0 : x ≠ 0) : HasDerivAt (fun y => -((Real.log y + 1) / y)) (Real.log x / x ^ 2) x := by have h1 := ((Real.hasDerivAt_log hx0).add_const 1).div (hasDerivAt_id' x) hx0 have h2 := h1.neg rw [show (fun y => -((Real.log y + 1) / y)) = -((fun x => Real.log x + 1) / fun x => x) from by ext y; simp only [Pi.neg_apply, Pi.div_apply]] -- hmm this rewrites my goal's function INTO h2's form rw [show Real.log x / x ^ 2 = -((x⁻¹ * x - (Real.log x + 1) * 1) / x ^ 2) from by rw [inv_mul_cancel₀ hx0]; ring] exact h2 ``` The first show: (fun y => −((log y+1)/y)) = −((fun x => log x+1)/(fun x => x)): ext y: LHS y = −((log y+1)/y); RHS y = (−(F/G)) y = −((F/G) y) = −(F y/G y) = −((log y+1)/y) — via simp only [Pi.neg_apply, Pi.div_apply] ✓ closes (rfl after simp). The rw [show ...] on the goal rewrites my function to h2's exact form ✓ then exact h2. The second show: log x/x² = −((x⁻¹·x − (log x+1)·1)/x²): rw [inv_mul_cancel₀ hx0]: the pattern x⁻¹·x — hmm the error said "did not find pattern x⁻¹ * x" in a bizarre instance-goal — that was from the convert mess. In the show's standalone proof: goal log x/x² = −((x⁻¹·x − (log x+1)·1)/x²): rw [inv_mul_cancel₀ hx0] — the term (x⁻¹ * x) is present ✓ → −((1 − (log x+1)·1)/x²): ring ✓. Then at the USE sites (integrableOn_log_div_sq etc.), the function form is (fun y => −((log y+1)/y)) — update those statements to match: integrableOn_log_div_sq's apply produces g := (fun y => −((log y+1)/y)) ✓ and the Tendsto lemma: tendsto_neg_log_add_one_div's statement should use (fun y => −((Real.log y + 1)/y)) for direct matching. Update that too: ```lean lemma tendsto_neg_log_add_one_div : Tendsto (fun y => -((Real.log y + 1) / y)) atTop (𝓝 0) := by ... have heq : (fun y => -((Real.log y + 1) / y)) = (fun x => -(Real.log x / x + 1 / x)) := by ext x rw [neg_div, add_div] rw [heq] simpa using hC.neg ``` heq: −((log y+1)/y) = −(log y/y + 1/y): rw [add_div] on RHS: −(log y/y + 1/y)... the goal: −((log y+1)/y) = −(log y/y + 1/y): suffices (log y+1)/y = log y/y + 1/y = add_div ✓ — so `rw [add_div]` turns RHS's (log x/x + 1/x) into ((log x + 1)/x)? add_div : (a + b)/c = a/c + b/c — rewrites the /-form: RHS −(log x/x + 1/x): add_div would rewrite (log x + 1)/x if present — it's not; the RHS has the SUM of two divisions. rw [add_div] rewrites occurrences of (?a+?b)/?c — none present on RHS (it's −(A + B) with A,B divisions); LHS has −((log y+1)/y) which IS (a+b)/c form: rw [add_div] rewrites LHS → −(log y/y + 1/y) ✓ then rfl with RHS −(log y/y + 1/y) ✓ (the y vs x dummy — after ext x both are x ✓). So heq: ext x; rw [add_div]. Hmm wait: LHS −((log x+1)/x) → add_div → −(log x/x + 1/x) = RHS ✓ closed by rfl (rw closes). Then the final: Tendsto (−(log x/x + 1/x)) from hC.neg : Tendsto (fun x => −(log x/x + 1/x)) (𝓝 (−(0+0))) — −(0+0) = 0: simpa using hC.neg ✓. 3. The hC : Tendsto ... (𝓝 (0 + 0)) then .neg gives 𝓝 (−(0+0)) — simpa normalizes to 𝓝 0 ✓. Also the `hA`: `Real.tendsto_pow_log_div_mul_add_atTop 1 0 1 one_ne_zero : Tendsto (fun x => log x^1/(1·x+0)) ...` — simpa using h: the function (fun x => log x ^ 1 / (1*x+0)) vs (fun x => log x/x): simpa normalizes (pow_one, one_mul, add_zero) ✓. Hmm — is it in namespace Real? The grep showed it at Log/Basic.lean:440 `theorem tendsto_pow_log_div_mul_add_atTop` — inside namespace Real presumably (the file is about Real.log) — I wrote Real.tendsto_pow_log_div_mul_add_atTop. If it's root-level, drop the Real. — the earlier error was "unknown identifier" for the UNqualified form, so it IS namespaced. Real is my best guess. 4. hB: `tendsto_inv_atTop_zero : Tendsto (fun r : 𝕜 => r⁻¹) atTop (𝓝 0)` — for 𝕜 = ℝ: simpa only [one_div] using it: goal Tendsto (fun x => 1/x) ...: simp only [one_div] rewrites 1/x → x⁻¹ ✓ matches. ✓ Let me apply these fixes.
Fixing the remaining form mismatches (cpow bridge, the Pi.neg/Pi.div function forms).
tool: Edit
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean",
  "old_string": "    have h2 : \u2016((n : \u2102)) ^ (2 : \u2102)\u2016 = (n : \u211d) ^ 2 := by\n      rw [show ((n : \u2102)) ^ (2 : \u2102) = ((n : \u2102)) ^ (2 : \u2115) by\n            exact_mod_cast cpow_natCast _ 2, norm_pow]\n      rw [show ((n : \u2102)) = ((n : \u211d) : \u2102) by push_cast; ring, Complex.norm_real,\n        abs_of_nonneg (Nat.cast_nonneg n)]\n    rw [h1, h2, if_neg hn]",
  "new_string": "    have h2 : \u2016((n : \u2102)) ^ (2 : \u2102)\u2016 = (n : \u211d) ^ 2 := by\n      rw [show (2 : \u2102) = ((2 : \u2115) : \u2102) by norm_num, cpow_natCast, norm_pow,\n        Complex.norm_natCast]\n    rw [h1, h2, if_neg hn]"
}
#1742 assistant 2026-08-24 09:59:07.161 UTC · 960→2698 tok open ⤢
thinking (7033 chars)
Progress. Remaining issues: 1. **Line 269**: the `show` — the goal is `0 - -((Real.log 3 + 1) / 3) = ...` (with the outer-neg form −((X)/3)) vs my show's `0 - -(Real.log 3 + 1) / 3` (neg on numerator). Fix the show to match: `show (0:ℝ) - -((Real.log 3 + 1) / 3) = (Real.log 3 + 1) / 3` then ring. 2. **differentiableAt_pow _ _**: signature is `differentiableAt_pow (n) (x)?` — the error "Function expected at differentiableAt_pow ?m.91" — it takes ONE explicit arg probably: `differentiableAt_pow (n : ℕ) : DifferentiableAt 𝕜 (·^n) x`? with x implicit. So `differentiableAt_pow 2` hmm — but I wrote `(differentiableAt_pow _ _)` — two args. Fix: use `(differentiableAt_pow 2)`? Hmm the error says applying to argument _ fails because differentiableAt_pow ?m returns a DifferentiableAt (not a function). So it takes ONE arg: `differentiableAt_pow 2`... wait — maybe the signature is `differentiableAt_pow (x : 𝕜) (n : ℕ)`? The error: "differentiableAt_pow ?m.91 has type DifferentiableAt ?m.86 (fun x => x ^ ?m.91) ?m.92" — so the first explicit arg is n (a ℕ), and x is implicit? Actually "?m.91" is the n — so `differentiableAt_pow 2` gives DifferentiableAt ?𝕜 (fun x => x^2) ?x with x a metavariable — unified by the .div. Let me use `(differentiableAt_pow 2)` — hmm wait, maybe it's `differentiableAt_pow (n : ℕ) (x : 𝕜)` with x explicit? The error suggests after the first arg it's already a term. Let me check. 3. **Set.interior_Ici unknown** — the name is different: maybe `interior_Ici` (root namespace, no Set prefix). In recent Mathlib: `interior_Ici : interior (Ici a) = Ioi a` ✓ root namespace. 4. **deriv rewrite** (line 299): `rw [h.deriv]` failed — h.deriv : deriv (Real.log / fun x => x^2) x = val — but the goal has deriv (fun y => Real.log y / y^2) x — the function forms differ (Real.log / (fun x => x^2) [Pi.div] vs (fun y => log y/y^2) [pointwise lambda]). Need the show-bridge: `have h' : HasDerivAt (fun y => Real.log y / y^2) (...) x := by convert h using 1; ext y; rw [Pi.div_apply]`... simpler: ```lean have h' : HasDerivAt (fun y => Real.log y / y ^ 2) ((x⁻¹ * x ^ 2 - Real.log x * (↑2 * x ^ (2 - 1))) / (x ^ 2) ^ 2) x := by convert h using 1 ext y rw [Pi.div_apply] rw [h'.deriv] field_simp ring ``` The final value: ((x⁻¹·x² − log x·(2·x))/(x²)²) = (1 − 2 log x)/x³: field_simp [hx0] then ring: LHS = (x − 2x log x)/x⁴ = (1 − 2 log x)/x³ ✓ (divide by x). field_simp then ring should handle with hx0. Hmm — field_simp produces cross-multiplied polynomial identity: (x⁻¹·x² − log x·2x)·x³ = (1−2log x)·(x²)²·... messy but ring cancels after field_simp's clearing. Might need `ring_nf` instead. Iterate. 5. **Line 315: Invalid argument name `f` for Iff.mpr** — in summable_log_div_sq_tail: `(summable_nat_add_iff 4).mpr (f := fun n : ℕ => ...)` — summable_nat_add_iff is an Iff; .mpr doesn't take named f that way. Fix: `(summable_nat_add_iff (f := fun n : ℕ => Real.log (n:ℝ)/(n:ℝ)^2) 4).mpr h`? The named arg goes on the iff itself: summable_nat_add_iff {f} {k}?? — its signature: `summable_nat_add_iff {f : ℕ → M} (k : ℕ) : Summable (fun n => f (n + k)) ↔ Summable f` — f implicit. So `(summable_nat_add_iff (f := fun n : ℕ => Real.log (n:ℝ)/(n:ℝ)^2) 4).mpr h`. Hmm — but actually — is the implicit name f? Could be. The .mpr with named-arg error came from writing `.mpr (f := ...)` — fix by putting (f := ...) on the lemma call. Actually simpler for h2: ```lean have h2 : Summable (fun n : ℕ => Real.log ((n : ℝ) + 4) / ((n : ℝ) + 4) ^ 2) := by have hs := (summable_nat_add_iff (f := fun n : ℕ => Real.log (n : ℝ) / (n : ℝ) ^ 2) 4).mpr h refine hs.congr fun n => ?_ push_cast ring_nf ``` Hmm — h : Summable (fun n : ℕ ↦ (fun x => log x/x²) ↑n) — with f := fun n : ℕ => Real.log (n:ℝ)/(n:ℝ)^2: the h's function (fun x => log x/x²) applied to ↑n = log ↑n/↑n² — the redex vs the direct — h's type displays as Summable (fun n => (fun x => log x/x²) ↑n)? — the summable_of_integrableOn_Ioi conclusion: `Summable (fun (n : ℕ) ↦ f n)` with f := (fun x => log x/x²) — so the term is fun n ↦ (fun x => log x/x²) ↑n — a beta-redex inside. The Iff.mpr's expected Summable f with my pinned f := fun n => log ↑n/↑n² — defeq (beta) ✓ .mpr h should accept (defeq). Then hs.congr fun n => _: goal: (fun n => log ↑(n+4)/↑(n+4)²) n = log (↑n+4)/(↑n+4)²: push_cast; ring_nf ✓. Hmm wait — `hs.congr` — Summable.congr (hf : Summable f) (h : ∀ i, f i = g i) : Summable g — the pointwise: f n = g n where f = shifted: log ↑(n+4)/↑(n+4)² and g = log (↑n+4)/(↑n+4)²: push_cast turns ↑(n+4) into ↑n + 4 ✓ then identical — ring_nf closes (or rfl). OK. 6. The push_cast-does-nothing warning at 213 — the h1's show-bridge `by push_cast; ring` — the push_cast did nothing (the cast was already in the right form); keep ring only? The warning is just a linter warning — acceptable? The project aims for zero warnings. Fix: replace `by push_cast; ring` with `by ring`? The show: (Λ n : ℂ) = ((Λ n : ℝ):ℂ) — Λ n is ℝ-valued (ArithmeticFunction.vonMangoldt n : ℝ): (Λ n : ℂ) vs ((Λ n : ℝ):ℂ) — these are the SAME (the LHS is already the cast) — so the show is `rfl`! Because ArithmeticFunction.vonMangoldt n : ℝ, and (Λ n : ℂ) IS ((Λ n : ℝ):ℂ) — the coercion ℝ → ℂ. So h1's show is just rfl: `rw [show (ArithmeticFunction.vonMangoldt n : ℂ) = ((ArithmeticFunction.vonMangoldt n : ℝ) : ℂ) from rfl, Complex.norm_real]` — hmm actually if it's rfl then no rw needed at all: directly `rw [Complex.norm_real]`? The term in the goal: ‖(Λ n : ℂ)‖ where (Λ n : ℂ) = ((Λ n : ℝ) : ℂ) — norm_real : ‖(x : ℝ)‖... wait Complex.norm_real : ‖(x : ℂ)‖... Complex.norm_real (x : ℝ) : ‖(x : ℂ)‖ = |x| — the term ‖(↑(Λ n) : ℂ)‖ — with the coercion ℝ→ℂ visible as (↑(Λ n) : ℂ)? The LSeries term has (ArithmeticFunction.vonMangoldt n : ℂ) — the coe from ℝ: `((ArithmeticFunction.vonMangoldt n : ℝ) : ℂ)`. So norm_real applies directly IF the term displays as a Real-cast. It does (Λ n : ℝ, coerced to ℂ). So: rw [Complex.norm_real] then abs_of_nonneg. The show+push_cast+ring was redundant. Simplify: ```lean have h1 : ‖(ArithmeticFunction.vonMangoldt n : ℂ)‖ = ArithmeticFunction.vonMangoldt n := by rw [Complex.norm_real] exact abs_of_nonneg ArithmeticFunction.vonMangoldt_nonneg ``` Hmm — will Complex.norm_real rewrite ‖(Λ n : ℂ)‖? norm_real : ‖(x : ℝ)‖ = |x| — wait: `Complex.norm_real (x : ℝ) : ‖(x : ℂ)‖ = |x|`. The goal's term: ‖(ArithmeticFunction.vonMangoldt n : ℂ)‖ — is that ↑-of-real? ArithmeticFunction.vonMangoldt : ℕ → ℝ — so (vonMangoldt n : ℂ) is a coercion ℝ → ℂ of (vonMangoldt n : ℝ) ✓ norm_real matches ✓. Let me check: does the goal's h1 statement parse ‖(ArithmeticFunction.vonMangoldt n : ℂ)‖ as the ℝ→ℂ cast? `ArithmeticFunction.vonMangoldt n` has type ℝ (the AF is ℝ-valued); writing (… : ℂ) coerces ✓. 7. The `(by omega : (n + 4 : ℕ) ≠ 0)` — omega on ℕ goals ✓ fine. 8. `Real.log_le_log (by positivity : (0:ℝ) < 3) hx3.le` — signature Real.log_le_log (hx : 0 < x) (h : x ≤ y) ✓ as used before. Let me apply all fixes.
Applying the round-3 fixes (show form, differentiableAt_pow arity, interior_Ici name, deriv bridge, Iff.mpr named-arg, h1 simplification).
tool: Edit
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean",
  "old_string": "    have h1 : \u2016(ArithmeticFunction.vonMangoldt n : \u2102)\u2016\n        = ArithmeticFunction.vonMangoldt n := by\n      rw [show (ArithmeticFunction.vonMangoldt n : \u2102)\n          = ((ArithmeticFunction.vonMangoldt n : \u211d) : \u2102) by push_cast; ring,\n        Complex.norm_real]\n      exact abs_of_nonneg ArithmeticFunction.vonMangoldt_nonneg",
  "new_string": "    have h1 : \u2016(ArithmeticFunction.vonMangoldt n : \u2102)\u2016\n        = ArithmeticFunction.vonMangoldt n := by\n      rw [Complex.norm_real]\n      exact abs_of_nonneg ArithmeticFunction.vonMangoldt_nonneg"
}
#1743 assistant 2026-08-24 10:04:48.036 UTC · 1039→2129 tok open ⤢
thinking (4238 chars)
From NatInt.lean's doc: "formula `∑ i ∈ range k, f i + ∑' i, f (i + k) = ∑' i, f i`, ∈ `sum_add_tsum_nat_add`" — so the lemma is `∑ i ∈ range k, f i + ∑' i, f (i + k) = ∑' i, f i` (range-first). And the LiDigammaLeft usage: their hsplit is `∑' = ∑ range + ∑' shifted` with `.symm` ✓ — exactly my form. So `(hsumh.sum_add_tsum_nat_add 4).symm` ✓ correct. Note also their shifted term: `(fun m : ℕ => ...) (n + N)` — they state the shifted tsum with the explicit lambda application. And the important gotcha (banked session 027): "sum_add_tsum_nat_add's shifted terms are beta-redexes (state goals in redex form)". So in MY hsplit, the shifted term should be written as `∑' n : ℕ, (fun m : ℕ => ...) (n + 4)` in redex form to match! My current hsplit: `∑' n : ℕ, h (n + 4)` — h is a set-variable (a function variable), so h (n+4) is NOT a redex — it matches (fun m => h m) (n+4)? The lemma's shifted form: ∑' i, f (i + k) — with f := h (the set var): ∑' n, h (n+4) ✓ exactly (f (i+k) with f = h — the application f (i + k) = h (n + 4) ✓ syntactic match!). Since h is an opaque variable (not a lambda), no redex issue ✓. But then htail's h1 and the congr steps DO have h as a lambda after rw [hh]... in htail I rw [hh] exposing the lambda — the show-form issue at line 366: my show `(if n + 4 = 0 then 0 else Real.log (↑n + 4) / ↑(n + 4) ^ 2) = Real.log (↑n + 4) / (↑n + 4) ^ 2` vs target `Real.log (↑n + 4) / (↑n + 4) ^ 2 = (fun n => ...) (n + 4)` — the target's LHS/RHS are flipped vs my show AND the target has the redex `(fun n => ...) (n+4)`. The goal in htail's h1 was: after `refine tsum_congr fun n => ?_` — goal: `(fun n => Real.log (↑n+4)/(↑n+4)²) n`? hmm — the error shows target `Real.log (↑n + 4) / (↑n + 4) ^ 2 = (fun n => if ...) (n + 4)` — so the tsum_congr goal was (tail-fn) n = (shifted-h) n — i.e. the tsum_congr's pointwise direction is my-tail-fn = h(n+4) — my `rw [h1]`-style — let me rewrite htail's h1 block: ```lean have htail : ∑' n : ℕ, h (n + 4) ≤ (Real.log 3 + 1) / 3 := by have h1 : (∑' n : ℕ, h (n + 4)) = ∑' n : ℕ, Real.log ((n : ℝ) + 4) / ((n : ℝ) + 4) ^ 2 := by refine tsum_congr fun n => ?_ rw [hh] show (fun n => if n = 0 then (0 : ℝ) else Real.log (n : ℝ) / (n : ℝ) ^ 2) (n + 4) = Real.log ((n : ℝ) + 4) / ((n : ℝ) + 4) ^ 2 show (if (n + 4 : ℕ) = 0 then (0 : ℝ) else Real.log (↑(n + 4)) / (↑(n + 4) : ℝ) ^ 2) = Real.log ((n : ℝ) + 4) / ((n : ℝ) + 4) ^ 2 rw [if_neg (by omega : (n + 4 : ℕ) ≠ 0)] push_cast ring_nf rw [h1] exact tsum_log_div_sq_tail_le ``` Hmm — the double show is ugly. The issue: after rw [hh], h (n+4) becomes (fun n => if n = 0 then ...) (n + 4) — a redex. The first show: `(fun n => ...) (n+4) = tail-value` — is that defeq to the goal `h (n+4) = tail-value`? After rw [hh], the goal IS (fun n => ...) (n+4) = tail — the first show is syntactic-identical ✓ (fine, no-op). Then the second show with the beta-reduced form: defeq ✓ (beta). Then rw [if_neg ...] on the reduced form ✓ then push_cast: ↑(n+4) → ↑n+4 ✓ ring_nf closes. Hmm — but does the `show` with `Real.log (↑(n + 4))`... the lambda body's `Real.log n` with n : ℕ coerced: Real.log ↑n — at n+4: Real.log ↑(n+4) ✓. Actually — simpler: skip the double show; use `beta_reduce` or `simp only []`: after rw [hh]: `show` directly the reduced form: ```lean rw [hh] show (if (n + 4 : ℕ) = 0 then (0 : ℝ) else Real.log (↑(n + 4)) / (↑(n + 4) : ℝ) ^ 2) = Real.log ((n : ℝ) + 4) / ((n : ℝ) + 4) ^ 2 rw [if_neg (by omega : (n + 4 : ℕ) ≠ 0)] push_cast ring_nf ``` The show is defeq to the redex goal ✓ (show accepts defeq). The previous failure was because my show had the sides flipped AND mismatched cast forms. This version: LHS reduced-if form with ↑(n+4) casts, RHS the (↑n+4) form. After if_neg + push_cast (turns ↑(n+4) into ↑n+4): both sides log (↑n+4)/(↑n+4)² — ring_nf closes. Hmm wait — will push_cast normalize `↑(n + 4)` to `↑n + 4`? Nat.cast_add: ↑(n+4) = ↑n + ↑4; Nat.cast_ofNat: ↑4 = 4 ✓ push_cast does these ✓. Also the same fix needed in hsumh's h1 block (line ~366). Let me look at my current text there and fix both, plus hle_pointwise, hderiv, the tail proof. Let me make the edits.
Applying the round-4 fixes (deriv bridge via Pi.div form, the cast handling in the tail, hle_pointwise show, htail congr, hhead simp, sum_add_tsum_nat_add method form).
tool: Edit
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean",
  "old_string": "    have hderiv : deriv (fun y => Real.log y / y ^ 2) x\n        = (1 - 2 * Real.log x) / x ^ 3 := by\n      have h := (Real.hasDerivAt_log hx0).div (hasDerivAt_pow 2 x) (pow_ne_zero 2 hx0)\n      have h' : HasDerivAt (fun y => Real.log y / y ^ 2)\n          ((x\u207b\u00b9 * x ^ 2 - Real.log x * (\u21912 * x ^ (2 - 1))) / (x ^ 2) ^ 2) x := by\n        convert h using 1\n        ext y\n        rw [Pi.div_apply]\n      rw [h'.deriv]\n      field_simp\n      ring\n    rw [hderiv]\n    exact div_nonpos_of_nonpos_of_nonneg (by linarith [hlogx]) (by positivity)",
  "new_string": "    have hderiv : deriv (fun y => Real.log y / y ^ 2) x\n        = (1 - 2 * Real.log x) / x ^ 3 := by\n      have h := (Real.hasDerivAt_log hx0).div (hasDerivAt_pow 2 x) (pow_ne_zero 2 hx0)\n      have h'' : (fun y => Real.log y / y ^ 2) = Real.log / (fun y => y ^ 2) := by\n        ext y\n        rw [Pi.div_apply]\n      rw [h'', h.deriv]\n      have hsimp : (\u21912 : \u211d) * x ^ (2 - 1) = 2 * x := by\n        rw [show (2 : \u2115) - 1 = 1 from rfl, pow_one]\n        push_cast\n        ring\n      rw [hsimp]\n      field_simp\n      ring\n    rw [hderiv]\n    exact div_nonpos_of_nonpos_of_nonneg (by linarith [hlogx]) (by positivity)"
}
#1744 assistant 2026-08-24 10:08:04.217 UTC · 2301→5589 tok open ⤢
thinking (9667 chars)
I see the current state. Remaining fixes needed: 1. **hle_pointwise** (lines 360-369): `rw [dirichletTerm_norm_eq n, hh]` then `rcases` — the issue: after rw [dirichletTerm_norm_eq n, hh], the goal for the n=0 case is `(if 0 = 0 then 0 else Λ 0/0²) ≤ h 0`... wait — the rcases produces n := 0 substitution — but the rw happened BEFORE rcases, so for rfl case: dirichletTerm_norm_eq 0... Let me restructure: rcases first, then handle: ```lean have hle_pointwise : ∀ n : ℕ, ‖LSeries.term (fun n => (ArithmeticFunction.vonMangoldt n : ℂ)) (2 : ℂ) n‖ ≤ h n := by intro n rcases eq_or_ne n 0 with rfl | hn · rw [dirichletTerm_norm_eq 0, hh] simp · rw [dirichletTerm_norm_eq n, if_neg hn, hh] show ArithmeticFunction.vonMangoldt n / (n : ℝ) ^ 2 ≤ if n = 0 then (0 : ℝ) else Real.log (n : ℝ) / (n : ℝ) ^ 2 rw [if_neg hn] exact div_le_div_of_nonneg_right ArithmeticFunction.vonMangoldt_le_log (by positivity : (0 : ℝ) ≤ (n : ℝ) ^ 2) ``` The n=0 case: goal ‖term 0‖ ≤ h 0: dirichletTerm_norm_eq 0 gives ‖term 0‖ = if 0 = 0 then 0 else ... = 0 — rw then the goal's LHS becomes (if (0:ℕ) = 0 then (0:ℝ) else ...) — hmm dirichletTerm_norm_eq 0's RHS: `if 0 = 0 then 0 else Λ 0/↑0²` — rw replaces ‖term 0‖ with that if. And h 0 after rw [hh]: (fun n => if n = 0 then ...) 0 = if 0 = 0 then 0 else ... Then `simp` should close: if_pos rfl both sides → 0 ≤ 0 ✓. So: ```lean · rw [dirichletTerm_norm_eq 0, hh] simp ``` The error at line 357 area was "if n = 0 then..." pattern not found because the rw order was wrong (rw before rcases with n unsubstituted... actually the error was in the inr case: after rw [dirichletTerm_norm_eq n, hh], goal: Λ n/↑n² ≤ (fun n => if n = 0 then ...) n — the redex — my `rw [if_neg hn, if_neg hn]` failed since the if is under the redex. The show fixes it. For the inl case (rfl): goal after rw [dirichletTerm_norm_eq 0, hh]: (if (0:ℕ)=0 then 0 else Λ 0/↑0^2) ≤ (fun n => ...) 0 — hmm the RHS redex: `simp` should evaluate both (if_pos + beta + the h-def if) — `simp` closes 0 ≤ 0 ✓. Hmm — will simp evaluate (fun n => if n = 0 then (0:ℝ) else ...) 0? simp beta-reduces and if_pos ✓. OK. 2. **hsumh's h1** (lines 372-380): `apply summable_log_div_sq_tail.congr; intro n` — Summable.congr (hf : Summable f) (h : ∀ i, f i = g i) : Summable g — with f = the tail's fn, g = (fun n => h (n+4)): the pointwise goal: f n = g n: `Real.log (↑n+4)/(↑n+4)² = h (n+4)` — my current show has it flipped: `show (if ...) = Real.log (↑n+4)/...` — the goal is `Real.log (↑n+4)/(↑n+4)² = h (n+4)` — wait which order? apply summable_log_div_sq_tail.congr: summable_log_div_sq_tail : Summable g' where g' = fun n => log (↑n+4)/(↑n+4)²; congr : Summable f → (∀ i, f i = g i) → Summable g — apply ... .congr to goal Summable (fun n => h (n+4)): unifies g := (fun n => h (n+4)), f := g' (from the lemma's type). Then intro n: goal f n = g n: `Real.log (↑n+4)/(↑n+4)² = (fun n => h (n+4)) n` = h (n+4). After rw [hh]: h (n+4) = (fun n => if n = 0 then ...) (n+4) — a redex. So the goal: log(↑n+4)/(↑n+4)² = (fun n => if n = 0 then 0 else log ↑n/↑n²) (n+4). My show: `show (if (n+4:ℕ) = 0 then 0 else ...) = Real.log (↑n+4)/...` — FLIPPED vs the goal. Fix: show `Real.log (↑n+4)/(↑n+4)² = if (n+4:ℕ) = 0 then (0:ℝ) else Real.log ↑(n+4)/↑(n+4)²` — hmm the cast forms: the lambda body has Real.log ↑m / ↑m² at m = n+4: Real.log ↑(n+4)/↑(n+4)². So: ```lean rw [hh] show Real.log ((n : ℝ) + 4) / ((n : ℝ) + 4) ^ 2 = if (n + 4 : ℕ) = 0 then (0 : ℝ) else Real.log (↑(n + 4)) / (↑(n + 4) : ℝ) ^ 2 rw [if_neg (by omega : (n + 4 : ℕ) ≠ 0)] push_cast ring_nf ``` Wait — after rw [if_neg]: RHS becomes Real.log ↑(n+4)/↑(n+4)²; goal: log (↑n+4)/(↑n+4)² = log ↑(n+4)/↑(n+4)²: push_cast normalizes ↑(n+4) → ↑n + 4 ✓ both sides match → ring_nf or rfl. But push_cast rewrites the GOAL's ↑(n+4) — both sides — ✓ then goal becomes syntactically equal → closed by... push_cast doesn't close; ring_nf closes by normalization? After push_cast both sides are identical — `rfl`? or ring_nf closes identical goals ✓ (ring_nf closes by rfl up to normalization). Hmm — is `show ... = if ...` defeq to the goal `log(↑n+4)/... = (fun n => ...) (n+4)`? The redex (fun n => if n = 0 then ...) (n+4) beta-reduces to if (n+4) = 0 then ... — defeq ✓ show accepts. 3. **hsplit** (line 383-384): `exact (sum_add_tsum_nat_add 4 hsumh).symm` — unknown identifier. Fix: `exact (hsumh.sum_add_tsum_nat_add 4).symm` — the LiDigammaLeft pattern ✓. And the shifted form: the lemma's shifted term is ∑' i, f (i + k) — with f := h (a variable) — h (n+4) ✓ syntactic ✓. 4. **hhead** (lines 385-396): the sum_range chain + simp only + the show-rws. Current form has issues (the `rw [show h 1 = ...]` after simp only might not find `h 1` since simp only [if_pos...] may have already evaluated h 0 and h 1's ifs). Let me rewrite hhead robustly: ```lean have hhead : ∑ n ∈ Finset.range 4, h n = Real.log 2 / 4 + Real.log 3 / 9 := by rw [Finset.sum_range_succ, Finset.sum_range_succ, Finset.sum_range_succ, Finset.sum_range_succ, Finset.sum_range_zero] have h0 : h 0 = (0 : ℝ) := by rw [hh]; simp have h1' : h 1 = (0 : ℝ) := by rw [hh]; simp have h2' : h 2 = Real.log 2 / 4 := by rw [hh] show (if (2 : ℕ) = 0 then (0 : ℝ) else Real.log (↑(2:ℕ)) / (↑(2:ℕ) : ℝ) ^ 2) = _ rw [if_neg (by norm_num)] push_cast ring_nf have h3' : h 3 = Real.log 3 / 9 := by rw [hh] show (if (3 : ℕ) = 0 then (0 : ℝ) else Real.log (↑(3:ℕ)) / (↑(3:ℕ) : ℝ) ^ 2) = _ rw [if_neg (by norm_num)] push_cast ring_nf rw [h0, h1', h2', h3'] ring ``` hmm — the show for h2': after rw [hh], h 2 = (fun n => if n = 0 then ...) 2 — the show's LHS `if (2:ℕ) = 0 then 0 else Real.log ↑(2:ℕ)/↑(2:ℕ)²` is defeq (beta) ✓. After if_neg: Real.log ↑(2:ℕ)/↑(2:ℕ)² = Real.log 2/4: push_cast: ↑(2:ℕ) → (2:ℝ) ✓ then (2:ℝ)^2 = 4: ring_nf normalizes the division: log 2 / 2^2 vs log 2/4: ring_nf handles (2^2 = 4) ✓ hopefully; if not, `norm_num` for the 2^2=4 then congr. The h1' : h 1 = 0: rw [hh]; simp: (fun n => ...) 1 → beta → if (1:ℕ) = 0 then... if_neg (1 ≠ 0) → log ↑1/↑1²: log 1 = 0 (Real.log_one simp) → 0/1 = 0: simp closes ✓ (need the cast ↑1 = 1: simp's Nat.cast_one ✓). OK. 5. The final assembly linarith at 435: with hmain + the log bounds ✓ should be fine. 6. The htail's h1 (lines 397-406): same flipped-show issue: goal after refine tsum_congr fun n => ?_: h (n+4) = log (↑n+4)/(↑n+4)² — my show has LHS `if (n+4) = 0 then...` — defeq to h (n+4) after rw [hh] ✓ (rw [hh] exposes the redex; show reduced-if = tail-value: defeq ✓). So htail's show: `(if (n+4:ℕ) = 0 then (0:ℝ) else Real.log ↑(n+4)/↑(n+4)²) = Real.log (↑n+4)/(↑n+4)²` — wait the error earlier was "show ... is not definitionally equal to target Real.log (↑n+4)/(↑n+4)^2 = (fun n => ...) (n+4)" — the TARGET has h(n+4) on the RIGHT (the tsum_congr direction h(n+4)-tsum = tail-tsum gives pointwise h (n+4) = tail-value). My show had (if-form) = tail-value — the mismatch: target is `Real.log (↑n+4)/(↑n+4)^2 = (fun n => ...) (n+4)`?? — that's tail-value = h(n+4)! The tsum_congr for h1 : (∑' h(n+4)) = (∑' tail): tsum_congr (h : ∀ i, f i = g i) : ∑' f = ∑' g — so pointwise h (n+4) = tail n — the goal should be h (n+4) = tail-value. The error's target shows `Real.log (↑n + 4)/... = (fun n => ...) (n + 4)` — hmm that has tail-value on the LEFT — meaning the tsum_congr direction was f = tail-fn, g = h-shifted — i.e., my h1's statement `(∑' n, h (n+4)) = ∑' n, tail n` — tsum_congr proves f-tsum = g-tsum from f i = g i: f := (fun n => h (n+4)), g := tail-fn: pointwise: h (n+4) = tail n — the error shows the goal as `Real.log (↑n+4)/... = (fun n => ...) (n+4)` which is tail = h(n+4) — FLIPPED from what I said. Because tsum_congr's h might be the reverse... Whatever — the error message's target: `Real.log (↑n + 4) / (↑n + 4) ^ 2 = (fun n => if ...) (n + 4)` — so I need my show to be THAT: after rw [hh]: show `Real.log (↑n+4)/(↑n+4)² = if (n+4:ℕ) = 0 then (0:ℝ) else Real.log ↑(n+4)/↑(n+4)²` — defeq ✓. Then rw [if_neg]; push_cast; ring_nf ✓. So for BOTH hsumh.h1 and htail.h1, the show should be: `Real.log (↑n+4)/(↑n+4)² = if-form` (tail on LEFT). Let me fix both shows to that direction. Actually — simpler and more robust: skip the show entirely; use `simp only [if_neg..., Nat.cast_add, Nat.cast_ofNat]`: ```lean refine tsum_congr fun n => ?_ rw [hh] rw [show ((fun n : ℕ => if n = 0 then (0 : ℝ) else Real.log (n : ℝ) / (n : ℝ) ^ 2) (n + 4)) = Real.log (↑(n + 4) : ℝ) / (↑(n + 4) : ℝ) ^ 2 from rfl] -- beta ... ``` Too fragile. Let me just fix the show directions. For hsumh.h1: the goal after `apply summable_log_div_sq_tail.congr; intro n`: tail-fn n = (fun n => h (n+4)) n — i.e. `Real.log (↑n+4)/(↑n+4)² = h (n+4)`: rw [hh]: RHS becomes the redex: show `Real.log (↑n+4)/(↑n+4)² = if (n+4:ℕ) = 0 then (0:ℝ) else Real.log ↑(n+4)/↑(n+4)²` — defeq ✓ (beta on RHS). rw [if_neg (by omega)]; push_cast; ring_nf ✓. Wait — after rw [hh], the RHS `(fun n => h (n+4)) n` — hmm: g = (fun n => h (n+4)); g n beta-reduces to h (n+4) automatically? The goal displayed as `... = h (n + 4)`? or with the redex? The apply-congr goal: f n = g n where g = (fun n => h (n+4)) — g n displays as h (n+4) after beta (Lean elaborates the application). rw [hh] rewrites the h INSIDE: h (n+4) → (fun m => if m = 0 then ...) (n+4) — a redex. My show: `tail-value = if-form` — the if-form is defeq to the redex ✓. OK let me make these three edits (hle_pointwise restructure, hsumh.h1 show, hsplit method-form, hhead rewrite, htail.h1 show).
Applying the fixes to the assembly block (hle_pointwise, hsumh, hsplit, hhead, htail).
tool: Edit
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean",
  "old_string": "  have hle_pointwise : \u2200 n : \u2115,\n      \u2016LSeries.term (fun n => (ArithmeticFunction.vonMangoldt n : \u2102)) (2 : \u2102) n\u2016\n        \u2264 h n := by\n    intro n\n    rw [dirichletTerm_norm_eq n, hh]\n    rcases eq_or_ne n 0 with rfl | hn\n    \u00b7 simp\n    \u00b7 rw [if_neg hn, if_neg hn]\n      exact div_le_div_of_nonneg_right ArithmeticFunction.vonMangoldt_le_log\n        (by positivity : (0 : \u211d) \u2264 (n : \u211d) ^ 2)\n  -- summability of h: the tail n + 4 is summable, and the head is finite\n  have hsumh : Summable h := by\n    have h1 : Summable (fun n : \u2115 => h (n + 4)) := by\n      apply summable_log_div_sq_tail.congr\n      intro n\n      rw [hh]\n      show (if (n + 4 : \u2115) = 0 then (0 : \u211d) else Real.log (n + 4) / ((n + 4 : \u2115) : \u211d) ^ 2)\n          = Real.log ((n : \u211d) + 4) / ((n : \u211d) + 4) ^ 2\n      rw [if_neg (by omega : (n + 4 : \u2115) \u2260 0)]\n      push_cast\n      ring_nf\n    exact (summable_nat_add_iff 4).mp h1\n  -- the head/tail split of the h-tsum\n  have hsplit : \u2211' n : \u2115, h n = (\u2211 n \u2208 Finset.range 4, h n) + \u2211' n : \u2115, h (n + 4) := by\n    exact (sum_add_tsum_nat_add 4 hsumh).symm\n  have hhead : \u2211 n \u2208 Finset.range 4, h n = Real.log 2 / 4 + Real.log 3 / 9 := by\n    rw [Finset.sum_range_succ, Finset.sum_range_succ, Finset.sum_range_succ,\n      Finset.sum_range_succ, Finset.sum_range_zero]\n    rw [hh]\n    simp only [Nat.zero_eq, if_pos, Nat.one_ne_zero, Nat.add_eq_zero_iff,\n      OfNat.ofNat_ne_zero, and_self, not_false_eq_true]\n    rw [show h 1 = (0 : \u211d) from by rw [hh]; simp]\n    rw [show h 2 = Real.log 2 / 4 from by\n      rw [hh]; rw [if_neg (by norm_num : (2 : \u2115) \u2260 0)]; push_cast; ring_nf]\n    rw [show h 3 = Real.log 3 / 9 from by\n      rw [hh]; rw [if_neg (by norm_num : (3 : \u2115) \u2260 0)]; push_cast; ring_nf]\n    ring\n  have htail : \u2211' n : \u2115, h (n + 4) \u2264 (Real.log 3 + 1) / 3 := by\n    have h1 : (\u2211' n : \u2115, h (n + 4))\n        = \u2211' n : \u2115, Real.log ((n : \u211d) + 4) / ((n : \u211d) + 4) ^ 2 := by\n      refine tsum_congr fun n => ?_\n      rw [hh]\n      show (if (n + 4 : \u2115) = 0 then (0 : \u211d) else Real.log (n + 4) / ((n + 4 : \u2115) : \u211d) ^ 2)\n          = Real.log ((n : \u211d) + 4) / ((n : \u211d) + 4) ^ 2\n      rw [if_neg (by omega : (n + 4 : \u2115) \u2260 0)]\n      push_cast\n      ring_nf\n    rw [h1]\n    exact tsum_log_div_sq_tail_le",
  "new_string": "  have hle_pointwise : \u2200 n : \u2115,\n      \u2016LSeries.term (fun n => (ArithmeticFunction.vonMangoldt n : \u2102)) (2 : \u2102) n\u2016\n        \u2264 h n := by\n    intro n\n    rcases eq_or_ne n 0 with rfl | hn\n    \u00b7 rw [dirichletTerm_norm_eq 0, hh]\n      simp\n    \u00b7 rw [dirichletTerm_norm_eq n, if_neg hn, hh]\n      show ArithmeticFunction.vonMangoldt n / (n : \u211d) ^ 2\n          \u2264 if n = 0 then (0 : \u211d) else Real.log (n : \u211d) / (n : \u211d) ^ 2\n      rw [if_neg hn]\n      exact div_le_div_of_nonneg_right ArithmeticFunction.vonMangoldt_le_log\n        (by positivity : (0 : \u211d) \u2264 (n : \u211d) ^ 2)\n  -- summability of h: the tail n + 4 is summable, and the head is finite\n  have hsumh : Summable h := by\n    have h1 : Summable (fun n : \u2115 => h (n + 4)) := by\n      apply summable_log_div_sq_tail.congr\n      intro n\n      rw [hh]\n      show Real.log ((n : \u211d) + 4) / ((n : \u211d) + 4) ^ 2\n          = if (n + 4 : \u2115) = 0 then (0 : \u211d)\n            else Real.log (\u2191(n + 4)) / (\u2191(n + 4) : \u211d) ^ 2\n      rw [if_neg (by omega : (n + 4 : \u2115) \u2260 0)]\n      push_cast\n      ring_nf\n    exact (summable_nat_add_iff 4).mp h1\n  -- the head/tail split of the h-tsum\n  have hsplit : \u2211' n : \u2115, h n = (\u2211 n \u2208 Finset.range 4, h n) + \u2211' n : \u2115, h (n + 4) := by\n    exact (hsumh.sum_add_tsum_nat_add 4).symm\n  have hhead : \u2211 n \u2208 Finset.range 4, h n = Real.log 2 / 4 + Real.log 3 / 9 := by\n    rw [Finset.sum_range_succ, Finset.sum_range_succ, Finset.sum_range_succ,\n      Finset.sum_range_succ, Finset.sum_range_zero]\n    have h0 : h 0 = (0 : \u211d) := by rw [hh]; simp\n    have h1' : h 1 = (0 : \u211d) := by rw [hh]; simp\n    have h2' : h 2 = Real.log 2 / 4 := by\n      rw [hh]\n      show (if (2 : \u2115) = 0 then (0 : \u211d) else Real.log (\u2191(2:\u2115)) / (\u2191(2:\u2115) : \u211d) ^ 2) = _\n      rw [if_neg (by norm_num)]\n      push_cast\n      ring_nf\n    have h3' : h 3 = Real.log 3 / 9 := by\n      rw [hh]\n      show (if (3 : \u2115) = 0 then (0 : \u211d) else Real.log (\u2191(3:\u2115)) / (\u2191(3:\u2115) : \u211d) ^ 2) = _\n      rw [if_neg (by norm_num)]\n      push_cast\n      ring_nf\n    rw [h0, h1', h2', h3']\n    ring\n  have htail : \u2211' n : \u2115, h (n + 4) \u2264 (Real.log 3 + 1) / 3 := by\n    have h1 : (\u2211' n : \u2115, h (n + 4))\n        = \u2211' n : \u2115, Real.log ((n : \u211d) + 4) / ((n : \u211d) + 4) ^ 2 := by\n      refine tsum_congr fun n => ?_\n      rw [hh]\n      show (if (n + 4 : \u2115) = 0 then (0 : \u211d) else Real.log (\u2191(n + 4)) / (\u2191(n + 4) : \u211d) ^ 2)\n          = Real.log ((n : \u211d) + 4) / ((n : \u211d) + 4) ^ 2\n      rw [if_neg (by omega : (n + 4 : \u2115) \u2260 0)]\n      push_cast\n      ring_nf\n    rw [h1]\n    exact tsum_log_div_sq_tail_le"
}
#1745 assistant 2026-08-24 10:10:13.849 UTC · 517→2805 tok open ⤢
thinking (6351 chars)
Two issues: 1. **Line 303**: `congr 1` — wait, I removed the congr 1 in my edit... line 303 is the `rw [h'', h.deriv]` area. "No goals to be solved" at 303 — the rw [h'', h.deriv] closed the goal?! The goal was `deriv (fun y => log y/y^2) x = (1−2log x)/x^3`; rw [h''] changes LHS to deriv (Real.log / fun y => y^2) x; rw [h.deriv] changes it to the value `(x⁻¹*x^2 − log x*(↑2*x^(2−1)))/(x^2)^2` — so the goal becomes `value = (1−2log x)/x^3` — NOT closed. Then line 303 `have hsimp ...` — hmm "No goals to be solved" at 303:12 — the rw [h'', h.deriv] might have CLOSED the goal?? No — the next error at 305 shows the goal `(x⁻¹*x^2 − ...)/(x^2)^2 = (1−2log x)/x^3` still open at the hsimp rw. So the "No goals" at 303 is a cascade artifact... Actually looking again: the two errors are: 303:8 "No goals to be solved" and 305:10 the rewrite failed. Line 303 is `rw [h'', h.deriv]`?? — if rw [h'', h.deriv] closed the goal (defeq between the value and (1−2log x)/x^3? no...). Hmm — actually "No goals" at 303 means the PREVIOUS tactic closed everything. Let me look at what's at line 303. From my edit: line ~297-306: ``` rw [h'', h.deriv] have hsimp : (↑2 : ℝ) * x ^ (2 - 1) = 2 * x := by rw [show (2 : ℕ) - 1 = 1 from rfl, pow_one] push_cast ring rw [hsimp] field_simp ring ``` Line 303:8 = `rw [show (2:ℕ) − 1 = 1 from rfl, pow_one]` — "No goals to be solved": the hsimp's statement `(↑2:ℝ) * x^(2−1) = 2*x` — hmm "No goals" at the rw inside hsimp's proof — that means the show-statement `(↑2 : ℝ) * x ^ (2 - 1) = 2 * x` was ALREADY closed before the rw... no wait — "No goals to be solved" for the rw means the hsimp have's proof... Hmm — actually if hsimp's STATEMENT elaborated to `2 * x ^ (2-1) = 2 * x` (with (↑2:ℝ) evaluated to 2 by norm_num1 during elaboration?) then... the rw [show (2:ℕ)−1 = 1 from rfl] — the pattern (2:ℕ)−1 might not appear (already evaluated to 1)? Then rw fails with "did not find" — but the error is "No goals to be solved". Confusing cascade. And 305: rw [hsimp] failed — hsimp : 2 * x^(2−1) = 2*x but the goal has `↑2 * x^(2−1)` (with the Nat.cast ↑2) — hsimp's LHS is `2 * x^(2−1)` (OfNat 2) vs the goal's `↑2 * x^(2−1)` (Nat.cast 2) — MISMATCH: the deriv value has ↑2 (Nat cast) but my hsimp wrote (↑2 : ℝ) which displays as... I wrote `(↑2 : ℝ) * x ^ (2 - 1)` — and the error says hsimp : `2 * x ^ (2 - 1) = 2 * x` — so the elaborated hsimp has plain 2 not ↑2 (the (↑2:ℝ) got normalized by norm_num1 in the elaborator? or the ascription made it OfNat). And the goal has ↑2 (Nat.cast). So rw [hsimp] doesn't match. Fix: make hsimp's LHS match the goal's `↑2 * x^(2−1)`: state hsimp as `((2:ℕ):ℝ) * x ^ (2 - 1) = 2 * x`: ```lean have hsimp : ((2 : ℕ) : ℝ) * x ^ (2 - 1) = 2 * x := by rw [show (2 : ℕ) - 1 = 1 from rfl, pow_one] push_cast ring ``` push_cast turns ((2:ℕ):ℝ) into (2:ℝ) ✓ then ring: 2*x = 2*x ✓. Hmm — but the "No goals" at 303 — maybe after rw [h'', h.deriv] the elaborator... let me just also consider: maybe rw [h'', h.deriv] DIDN'T close; the "No goals" at 303 could be about the `have hsimp` block position... Actually the simplest: rewrite the hderiv block as: ```lean have hderiv : deriv (fun y => Real.log y / y ^ 2) x = (1 - 2 * Real.log x) / x ^ 3 := by have h := (Real.hasDerivAt_log hx0).div (hasDerivAt_pow 2 x) (pow_ne_zero 2 hx0) have h'' : (fun y => Real.log y / y ^ 2) = Real.log / (fun y => y ^ 2) := by ext y rw [Pi.div_apply] rw [h'', h.deriv] have hsimp : ((2 : ℕ) : ℝ) * x ^ (2 - 1) = 2 * x := by rw [show (2 : ℕ) - 1 = 1 from rfl, pow_one] push_cast ring rw [hsimp] field_simp ring ``` The remaining risk: after rw [h'', h.deriv], goal: `(x⁻¹ * x ^ 2 - Real.log x * (↑2 * x ^ (2 - 1))) / (x ^ 2) ^ 2 = (1 - 2 * Real.log x) / x ^ 3`. rw [hsimp] (matching ↑2): → `(x⁻¹ * x^2 − log x * (2*x))/(x^2)^2 = (1 − 2 log x)/x^3`. field_simp: clears denominators: LHS·(x²)²·x³ = RHS·... — produces a polynomial identity in x, log x, x⁻¹: (x⁻¹·x² − 2x·log x)·x³ =? (1−2 log x)·(x²)² ⟺ x·x³ − 2x⁴·log x·... hmm: (x⁻¹·x²)·x³ = x⁴·... let me verify the identity: LHS = (x − 2x·log x)/x⁴ = (1 − 2 log x)·x/x⁴ = (1−2log x)/x³ ✓ TRUE. field_simp + ring should manage with hx0 in context (field_simp uses hx0? field_simp needs the nonzero hyps: `field_simp [hx0]`). Let me write `field_simp [hx0]` — hmm field_simp picks up ne-hyps from context automatically? It looks for `x ≠ 0`-shaped hyps? Safer: field_simp [hx0]. Then ring. Wait — actually, will `field_simp` produce something ring can close? The identity after clearing: (x⁻¹·x² − log x·(2x))·x³ = (1 − 2·log x)·(x²)²? Both sides polynomial in x and x⁻¹: LHS = x⁻¹·x²·x³ − 2x·log x·x³ = x⁴ − 2x⁴·log x·... x⁻¹·x²·x³ = x⁴? x⁻¹·x² = x; x·x³ = x⁴ ✓. RHS = x⁴ − 2x⁴ log x ✓ — ring closes (x⁻¹·x = 1 needed! ring treats x⁻¹ as an independent atom — x⁻¹·x² = x requires inv_mul_cancel! field_simp should eliminate x⁻¹ by clearing ALL denominators: the goal has x⁻¹, /(x²)², /x³ — field_simp multiplies through by x⁴·x³-ish: LHS·(x²)²·x³ and RHS... the x⁻¹ gets multiplied by x's — field_simp clears to: (x²·x³·...)·... it should work with hx0. If not, manually: rw [show x⁻¹ * x^2 = x from by field_simp [hx0]] first. Let me preemptively: ```lean rw [hsimp] have hx1 : x⁻¹ * x ^ 2 = x := by field_simp [hx0] rw [hx1] field_simp [hx0] ring ``` hx1: x⁻¹·x² = x: field_simp [hx0]: multiplies: x² = x·x ✓ — hmm field_simp proves equalities with divisions; x⁻¹·x² = x — field_simp [hx0] might close it directly (it's a field identity) ✓ or `by rw [inv_mul_cancel_left₀ hx0]`? inv_mul_cancel_left₀ : a⁻¹ * a * b = b? hmm: x⁻¹·x² = x⁻¹·x·x = 1·x = x: rw [pow_two, ← mul_assoc, inv_mul_cancel₀ hx0, one_mul] — explicit: ```lean have hx1 : x⁻¹ * x ^ 2 = x := by rw [pow_two, ← mul_assoc, inv_mul_cancel₀ hx0, one_mul] ``` inv_mul_cancel₀ (h : a ≠ 0) : a⁻¹ * a = 1 ✓ (used earlier). Then after rw [hx1]: (x − log x·(2x))/(x²)² = (1−2log x)/x³: field_simp [hx0]; ring: LHS = (x − 2x log x)/x⁴; field_simp cross-multiplies by x⁴·x³: (x − 2x log x)·x³ = (1 − 2 log x)·x⁴: ring: x·x³ = x⁴ ✓ and 2x·log x·x³ = 2·x⁴·log x ✓ ring closes ✓. 2. **Line 305 area** — the same block. OK covered. Let me rewrite the hderiv block with these.
Fixing the hsimp cast form and the field_simp chain in hderiv.
tool: Edit
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean",
  "old_string": "      rw [h'', h.deriv]\n      have hsimp : (\u21912 : \u211d) * x ^ (2 - 1) = 2 * x := by\n        rw [show (2 : \u2115) - 1 = 1 from rfl, pow_one]\n        push_cast\n        ring\n      rw [hsimp]\n      field_simp\n      ring\n    rw [hderiv]\n    exact div_nonpos_of_nonpos_of_nonneg (by linarith [hlogx]) (by positivity)",
  "new_string": "      rw [h'', h.deriv]\n      have hsimp : ((2 : \u2115) : \u211d) * x ^ (2 - 1) = 2 * x := by\n        rw [show (2 : \u2115) - 1 = 1 from rfl, pow_one]\n        push_cast\n        ring\n      rw [hsimp]\n      have hx1 : x\u207b\u00b9 * x ^ 2 = x := by\n        rw [pow_two, \u2190 mul_assoc, inv_mul_cancel\u2080 hx0, one_mul]\n      rw [hx1]\n      field_simp [hx0]\n      ring\n    rw [hderiv]\n    exact div_nonpos_of_nonpos_of_nonneg (by linarith [hlogx]) (by positivity)"
}
#1746 assistant 2026-08-24 10:11:26.106 UTC · 980→285 tok open ⤢
thinking (445 chars)
Line 310 `ring` — "No goals to be solved": the `field_simp [hx0]` at 309 already closed the goal! (field_simp can close field identities on its own.) Fix: remove the trailing `ring`. Or replace `field_simp [hx0]; ring` with just `field_simp [hx0]` — but if field_simp reduces to a non-closed form, need ring. The safe pattern: `field_simp [hx0]` then try ring only if needed — but "No goals" means field_simp closed it. Remove line 310's `ring`.
`field_simp` closed the goal itself — removing the trailing `ring`.
tool: Edit
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean",
  "old_string": "      rw [hx1]\n      field_simp [hx0]\n      ring\n    rw [hderiv]",
  "new_string": "      rw [hx1]\n      field_simp [hx0]\n    rw [hderiv]"
}
#1747 assistant 2026-08-24 10:12:16.025 UTC · 216→167 tok open ⤢
thinking (85 chars)
Clean compile — zero errors, zero warnings. Build the olean and commit 5f-i complete.
Clean. Building the olean and committing 5f-i.
tool: Bash
input
{
  "command": "cd D:/Python/Quantum/research/lean/NguyenRH1 && export PATH=\"$HOME/.elan/bin:$PATH\" && lake build NguyenRH1.LiTightR 2>&1 | tail -3",
  "description": "Build LiTightR olean",
  "timeout": 600000
}
#1748 assistant 2026-08-24 10:13:57.842 UTC · 994→1530 tok open ⤢
thinking (1057 chars)
5f-i complete and committed. Remaining in 5f: pieces 3 (far-sum interval machine — the big one) and 6 (digamma difference via level-2 EM), then the assembly + pinch lemma (5f-iii). It's ~2:10 AM. The user said continue with 5f-i, which is now done. 5f-ii is the two big analytic pieces (piece 6 digamma, piece 3 interval machine). Given the time and that the user approved continuing "5f-i" specifically, this is a natural stopping point — but the user is clearly engaged and wants progress. Let me assess: pieces 3 and 6 are each substantial (piece 3 alone is 1–1.5 sessions estimated). It's 2 AM. The clean call: update the journal + STATE, do a closure commit for session 035, and tell the user where we are. The session has delivered a lot: perimeter repair, P1/P2, D-069, 5f-i complete. Actually — the user's last answer was "Continue with 5f-i" — that's done. I should checkpoint (journal/STATE update + commit) and report, letting the user decide whether to start 5f-ii now (it's 2 AM their time). Let me update the journal and STATE, then report.
5f-i complete and committed (`1eeda9b`). Updating the journal + STATE for the checkpoint.
tool: Edit
input
{
  "file_path": "D:\\Python\\Quantum\\research\\journal\\session-035.md",
  "old_string": "## Status / next\n5f-i: the difference identity + pieces 1/2/4/5 (LiTightR.lean, new\nfile). Inputs all verified live (tsum_split_finset \u211d-form in\nLiCircleBound:249 \u2014 needs the \u2102 variant; AntitoneOn.tsum_le_integral\nfamily in SumIntegralComparisons; nearZeros in LiDisc:970;\nvonMangoldt LSeries term norm = \u039b(n)/n\u00b2).",
  "new_string": "## Outcome part 3: 5f-i COMPLETE (commits d808f52 + 1eeda9b)\nNew file **LiTightR.lean** (~510 lines, clean, zero warnings; not yet\nroot-imported):\n- `tsum_split_finset_complex` (\u2102 variant), `nearZerosSub` +\n  `mem_nearZerosSub` (the subtype near finset; the capstone's near sum\n  is over the SUBTYPE finset \u2014 cleaner for ii\u2032-6),\n  `seriesDiffTerm` + `seriesDiffTerm_summable` +\n  `seriesFun_sub_seriesFun`, **`Rexpr_decomp`** (the six-piece\n  reference-point decomposition: partialFraction_identity at s and\n  s\u2080 = 2+it, B cancels; linear_combination\n  hsid \u2212 hs\u2080id + hdiff + hsplit + hnear).\n- `near_sum_refPoint_le` (piece 2): near sum at s\u2080 \u2264 ZeroCountProp2\n  count (|s\u2080\u2212\u03c1| \u2265 1 from re \u03c1 < 1; subtype\u2192ambient image bridge).\n- `one_div_diff_le` (pieces 4/5): \u2264 4.5/|t|\u00b2 \u2264 0.045 each.\n- `dirichletC2_le_one` (piece 1): dirichletC2 \u2264 1 \u2014 the level-2\n  integral machinery: `hasDerivAt_neg_log_add_one_div` (antiderivative\n  \u2212(log x+1)/x), `tendsto_neg_log_add_one_div`,\n  `integrableOn_log_div_sq`, `integral_log_div_sq_Ioi_three`\n  (= (log 3+1)/3 via integral_Ioi_of_hasDerivAt_of_tendsto'),\n  `antitoneOn_log_div_sq` (deriv (1\u22122 log x)/x\u00b3 \u2264 0 via log 3 \u2265 1),\n  `tsum_log_div_sq_tail_le` (AntitoneOn.tsum_comp_add_le_integral),\n  then head n \u2264 3 + tail + the numeric fold (log 2 \u2264 0.6932 via\n  log_two_lt_d9; log 3 \u2264 1.1 via e^1.1 \u2265 3.00126 partial-sum).\n\n## Banked gotchas (session 035, LiTightR build)\n- `cpow_natCast` needs the `(2:\u2102) = ((2:\u2115):\u2102)` norm_num bridge first.\n- `HasDerivAt.div/.neg` produce Pi.div/Pi.neg FUNCTION forms \u2014\n  `rw [show]` bridges (or Pi.neg_apply/Pi.div_apply); NEVER `convert`\n  on HasDerivAt (HOU instance-goal explosion: Semiring.toModule = ...).\n- `Set.interior_Ici` is the ROOT-namespace `interior_Ici`.\n- `differentiableAt_pow` takes ONE explicit arg (the exponent).\n- `Summable.sum_add_tsum_nat_add` is the METHOD form; tsum-first needs\n  `.symm`.\n- tsum_congr pointwise goals come as `tail-fn n = shifted-h n` \u2014\n  `show` with the tail on the LEFT.\n- `field_simp [hx0]` can CLOSE the goal (no trailing ring).\n- Tendsto 1/x: `tendsto_inv_atTop_zero` + simpa only [one_div];\n  log x/x \u2192 0: `Real.tendsto_pow_log_div_mul_add_atTop 1 0 1 one_ne_zero`\n  + simpa.\n\n## Status / next\n**5f-i COMPLETE.** Remaining: 5f-ii \u2014 piece 6 (the sharp digamma\nremainder |r| \u2264 1.2/|w|\u00b2 via the level-2 EM, LiRBound b2Fun machinery;\nthen the \u03c8-difference with the crude log bound |log(1+u)| \u2264 2|u| \u2014\nbudget \u00bd|\u03c8-diff| \u2264 2.1, generous) and piece 3 (the far-sum interval\nmachine: per-term 4.5/(x\u221a(1+x\u00b2)) \u2264 4.5/(k\u221a(1+k\u00b2)); per-interval C0hat\ncounts from the perimeter + conj for \u03b3 < 0 + NoLowZeros below 14; the\nsum bound S\u2083 \u2264 1.3703 via k \u2264 3 exact + the telescope\n1/(k\u221a(1+k\u00b2)) \u2264 1/(k(k\u22121)) for k \u2265 4, \u03a3 = 1/3). Then 5f-iii: the\nassembly + the pinch lemma (11.813\u00b7LL \u2212 4.560\u00b7L \u2264 1.315 for L \u2265 log 12,\ninterior max at L* = 2.590, value \u2248 \u22120.57 \u2014 decreasing throughout, so\nthe endpoint evaluation suffices) + the capstone\n`logDeriv_riemannZeta_sub_nearZeros_le_tight`."
}
#1749 assistant 2026-08-24 10:16:37.237 UTC · 370→898 tok open ⤢
thinking (338 chars)
All committed. It's ~2:15 AM. The session has delivered a lot. The user said "Continue with 5f-i" which is now complete. 5f-ii (pieces 3 + 6) is a substantial build — piece 3 alone was estimated at 1–1.5 sessions. Given the time, this is the right moment to report status and let the user decide whether to continue into 5f-ii or log off.
**Session 035 status — 5f-i COMPLETE**, all committed. It's 2:15 AM. ## Delivered tonight (5 commits) 1. **`75172e6`** — Perimeter repair (you approved): `ZeroCountProp` strengthened to the mult-weighted form (matching the declared Trudgian N(T) source), `one_le_zeroMult` bridge, both consumers adapted. Full build green, audit clean. 2. **`f850d9a`** — 5f-0: D-069 design + the two new perimeter declarations (you approved): `ZeroCountProp2` (two-unit count) and `NoLowZeros` (|γ| ≥ 14). 3. **`0cca091`, `d808f52`, `1eeda9b`, `c97c3f1`** — 5f-i complete: **LiTightR.lean** (~510 lines, clean, zero warnings): - `Rexpr_decomp` — the six-piece reference-point decomposition (the identity at s vs s₀ = 2+it, B cancels; one `linear_combination`). - Piece 1 `dirichletC2_le_one` — the level-2 integral machinery (antiderivative −(log x+1)/x, integral test, antitone-via-deriv). - Piece 2 `near_sum_refPoint_le` (≤ ZeroCountProp2 count), pieces 4/5 `one_div_diff_le` (≤ 0.045). ## The key findings (documented in D-069) - **Finding 1**: D-056's piece 2 charges the near sum one C₀(t) for a *two-unit* window — the per-unit perimeter fold breaks 10.5/48, but the two-unit Trudgian form makes the honest assembly fit with margin ~1.9. - **Finding 2** (ii′-6 repair map): H(T)'s near sum has a clearance-coverage gap (L3 covers only in-window zeros); honest ≈ 7·Ĉ₀² vs baked 3·Ĉ₀² — margin survives, crossover moves. ## Remaining in 5f - **5f-ii**: piece 6 (digamma ψ-difference via the level-2 EM — budget is generous at 2.1) and piece 3 (the far-sum interval machine — the big piece, ~1–1.5 sessions). - **5f-iii**: assembly + pinch lemma (dissolves: the LL−L function is decreasing on L ≥ 2.485, max ≈ −0.57 vs budget 1.32) + the capstone. STATE.md's NEXT ACTION has the full 5f-ii piece map.
tool: AskUserQuestion ok
input
{
  "questions": [
    {
      "question": "5f-i is complete and committed. It's 2:15 AM \u2014 continue into 5f-ii (pieces 6 + 3, the heavier analytic builds) or log off?",
      "header": "Continue?",
      "options": [
        {
          "label": "Log off for tonight",
          "description": "Clean state: 5f-i committed, STATE.md points to 5f-ii with the full piece map. Resume fresh next session."
        },
        {
          "label": "Continue with piece 6",
          "description": "Build the digamma \u03c8-difference piece (level-2 EM remainder) \u2014 the smaller of the two 5f-ii pieces \u2014 then checkpoint."
        },
        {
          "label": "Continue with piece 3",
          "description": "Start the far-sum interval machine (the biggest 5f piece) tonight."
        }
      ]
    }
  ]
}
result 2026-08-24 11:02:29Z → 2026-08-24 11:02:29Z
{
  "questions": [
    "question=\"5f-i is complete and committed. It's 2:15 AM \u2014 continue into 5f-ii (pieces 6 + 3, the heavier analytic builds) or log off?\" header='Continue?' options=[QuestionOption(label='Log off for tonight', description='Clean state: 5f-i committed, STATE.md points to 5f-ii with the full piece map. Resume fresh next session.', preview=None), QuestionOption(label='Continue with piece 6', description='Build the digamma \u03c8-difference piece (level-2 EM remainder) \u2014 the smaller of the two 5f-ii pieces \u2014 then checkpoint.', preview=None), QuestionOption(label='Continue with piece 3', description='Start the far-sum interval machine (the biggest 5f piece) tonight.', preview=None)] multi_select=False"
  ],
  "answers": {
    "5f-i is complete and committed. It's 2:15 AM \u2014 continue into 5f-ii (pieces 6 + 3, the heavier analytic builds) or log off?": "Continue with piece 6"
  }
}
#1750 assistant 2026-08-24 11:03:22.984 UTC · 460892→1655 tok open ⤢
thinking (3442 chars)
Continue with piece 6 — the digamma ψ-difference bound. Goal: bound ½‖ψ(s/2) − ψ(s₀/2)‖ for s = σ+it, σ ∈ [−5/2, 3], s₀ = 2+it, t ≥ 10. Let w = s/2, w₀ = s₀/2. Both have im = t/2 ≥ 5. Plan (from the budget analysis): ψ(w) − ψ(w₀) = [log w − log w₀] − (1/2)[1/w − 1/w₀] + [r(w) − r(w₀)] where ψ(w) = log w − 1/(2w) + r(w) with |r(w)| ≤ 1.2/|w|² (Lemma D). Bounds: - |w − w₀| = |s − s₀|/2 ≤ 4.5/2 = 2.25. - |w₀| ≥ |im w₀| = t/2 ≥ 5; |w| ≥ t/2 ≥ 5. - |log w − log w₀|: w/w₀ = 1 + (w−w₀)/w₀, |u| := |w−w₀|/|w₀| ≤ 2.25/5 = 0.45 ≤ 1/2. |log(1+u)| ≤ 2|u| for |u| ≤ 1/2 (Mathlib: Complex.norm_log_one_add_le? or abs_log_one_add_le?). Need the exact lemma. There might be `Complex.norm_log_one_add_le (h : ‖z‖ ≤ r) (hr : r < 1)? : ‖log (1 + z)‖ ≤ ...`. Let me search. Or `Complex.abs_log_one_add_le (hz : ‖z‖ < 1) : ‖log (1+z)‖ ≤ -log(1−‖z‖)`? and −log(1−x) ≤ 2x for x ≤ 1/2. Then |log diff| ≤ 2·0.45 = 0.9 at t=10. Hmm — ½·0.9 = 0.45. Plus the other pieces: ½·|(1/2)(1/w − 1/w₀)| ≤ ½·(1/2)·|w−w₀|/(|w||w₀|) ≤ ¼·2.25/25 = 0.0225. Plus ½·(|r(w)| + |r(w₀)|) ≤ ½·2·1.2/25 = 0.048. Total: 0.45 + 0.0225 + 0.048 = 0.52. Budget 2.1 ✓ HUGE margin. Actually even the crudest |log| bound works. Wait — but the digamma difference is (ψ(s/2) − ψ(s₀/2))/2 in the decomposition (Rexpr_decomp has `− (Complex.digamma (s/2) − Complex.digamma (s₀/2))/2`). So piece 6's target: ‖(ψ(s/2) − ψ(s₀/2))/2‖ ≤ something ≤ 2.1. With the above: ≤ 0.52. Let me set the target: ‖(digamma (s/2) − digamma (s₀/2))/2‖ ≤ 1 (round, comfortable). Actually let me compute a cleaner number: ≤ 0.9/2 + 0.0225 + 0.048... the /2 applies to the whole difference: ‖(ψs − ψs₀)/2‖ = ½‖ψs − ψs₀‖ ≤ ½(0.9 + 0.045 + 0.096) = ½·1.041 = 0.5205. So ≤ 0.53 with room; claim ≤ 1 for comfort. Now the Lean proof structure: 1. **The sharp digamma remainder** (Lemma D form): for w with |im w| ≥ 5 (re arbitrary? or re w ∈ some range?): ψ(w) = log w − 1/(2w) + r(w), ‖r(w)‖ ≤ 1.2/‖w‖². How to prove in Lean via the level-2 EM? What's available: LiRBound has the level-2 Euler–Maclaurin for ζ. For ψ/digamma, what exists? From 5d: `norm_digamma_sub_log_le_of_two_le_abs_im` : ‖ψ(w) − log w‖ ≤ 3 for 2 ≤ |im w| (digamma_add_natCast shift + first-order EM + arctan-FTC). The first-order EM gave ψ(w) − log w = −1/(2w) − ∫ B̃₁(x)/(x+w)² dx-ish. For the sharp remainder I need one more EM level: ψ(w) = log w − 1/(2w) − ∫₀^∞ B̃₂(x)/(x+w)³ dx·(factor). Hmm — actually, what does the digamma EM look like exactly? The digamma series: ψ(w) = log w − 1/(2w) − Σ... The classical Binet: ψ(w) = log w − 1/(2w) − 2∫₀^∞ t/((t²+w²)(e^{2πt}−1)) dt (Binet's second formula for ψ). D-056 §1 used Binet. But in Lean, we don't have Binet. The EM route: how did 5d's norm_digamma_sub_log_le work? Let me look at its proof structure (LiReflect.lean) — it built ψ(w) − log w via the shift + first-order EM `sum_eq_integral_add_integral_deriv` + arctan-FTC. For the sharp version, one more EM level on the digamma series: ψ(w) = −γ − 1/w + Σ_{n≥1} (1/n − 1/(w+n))·... hmm. Actually the cleanest EM form for ψ: from the series ψ(w) = −γ + Σ_{n≥0} (1/(n+1) − 1/(w+n)): and Σ_{n≥0} 1/(w+n) vs ∫₀^∞ dx/(w+x) + (1/2)(1/w) + ...: EM: Σ_{n≥0} f(n) = ∫₀^∞ f + f(0)/2 + ∫ B̃₁ f' — divergent for f = 1/(w+x). The convergent form uses the difference series. Hmm. Let me look at how 5d's norm_digamma_sub_log_le_of_two_le_abs_im was actually proved — that's the pattern to extend. Let me read LiReflect.lean's relevant section.
Continuing with piece 6. First, studying how 5d's digamma bound was built (the EM pattern to extend).
tool: Bash
input
{
  "command": "cd D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1 && grep -n \"norm_digamma_sub_log_le_of_two_le_abs_im\\|theorem\\|lemma\" LiReflect.lean | grep -n \"digamma\\|Digamma\" | head -20",
  "description": "Find the digamma bound structure in LiReflect"
}
#1751 assistant 2026-08-24 11:05:50.601 UTC · 2624→4498 tok open ⤢
thinking (9587 chars)
I see the 5d structure: the first-order EM (`sum_eq_integral_add_integral_deriv`) on f(y) = (w+y)⁻¹, with the B̃₁ remainder. For piece 6's sharp remainder, I'd need the SECOND-order EM (B̃₂). That's a heavier build. BUT — wait. Given the budget for piece 6 is now 2.1 (generous), do I even need the SHARP remainder? Let me reconsider: with the CRUDE 5d bound ‖ψ(w) − log w‖ ≤ 3: |ψ(w) − ψ(w₀)| ≤ |log w − log w₀| + ‖ψ(w)−log w‖ + ‖ψ(w₀)−log w₀‖ ≤ |log(w/w₀)| + 6. ½·that ≤ ½·0.9 + 3 = 3.45 > 2.1. Just over. Hmm. Middle route: get ‖ψ(w) − log w‖ ≤ something smaller for |im w| ≥ 5. The 5d bound ≤ 3 is uniform for |im| ≥ 2. For |im| ≥ 5 (our case: im w = t/2 ≥ 5), the bound improves: the B̃₁ remainder ∫ B̃₁(x)/(w+x)² dx ≤ (1/2)·∫ dx/|w+x|² ≤ (1/2)·(π/(2·|im w|))·... — the arctan integral ∫₀^∞ dx/((x+a)²+c²) ≤ π/c with c = |im w| ≥ 5: ≤ π/5 ≈ 0.628. And the boundary terms (w⁻¹ − (w+n)⁻¹)/2 ≤ (1/|w| + 1/|w+n|)/2 ≤ (1/5+1/5)/2 = 0.1. And the StirlingVert part at v (re v > 0, |im v| ≥ 5): ‖ψ(v) − log v‖ ≤ ... the 5d assembly gave 3 total with the crude pieces. For |im| ≥ 5 the remainder pieces shrink: the total ‖ψ(w) − log w‖ ≈ 1/(2|w|) + 0.63 + small ≤ 0.73-ish. Then |ψ-diff| ≤ 0.9 + 2·0.73 = 2.36; ½·2.36 = 1.18 ≤ 2.1 ✓. Hmm — but that requires redoing the 5d assembly with the sharper constants — comparable work to the level-2 EM. Hold on — actually, is there a slicker approach entirely? The digamma DIFFERENCE directly: ψ(w) − ψ(w₀) = Σ_{j≥0} [1/(w₀+j) − 1/(w+j)] (the Weierstrass series difference — the series Σ_j (1/(w+j) − 1/(w₀+j)) converges since the terms are (w₀−w)/((w+j)(w₀+j)) ~ 1/j²). Zeta23's `DigammaSeries.digamma_series`: ψ(z) = −γ − 1/z + Σ'_n (1/(n+1) − 1/(z+n+1)) — exists (noted in D-068 §1: "Zeta23 DigammaSeries.digamma_series ... exists, axiom-checked"). So: ψ(w) − ψ(w₀) = −(1/w − 1/w₀) + Σ'_{n≥0} [(1/(n+1) − 1/(w+n+1)) − (1/(n+1) − 1/(w₀+n+1))] = −(1/w − 1/w₀) + Σ'_{n≥0} (w − w₀)/((w+n+1)(w₀+n+1)). The series: |w − w₀|·Σ'_n 1/(|w+n+1||w₀+n+1|). Now |w+n+1| ≥ |im w| = t/2 (n+1 real ≥ 0: |w+n+1| ≥ |im(w+n+1)| = t/2 ✓), similarly |w₀+n+1| ≥ t/2. And more precisely |w+n+1| ≥ √((n+1+re w)² + (t/2)²) ≥ √((n + 1 − 5/4)² + 25)... For the sum: Σ_{n≥0} 1/(|w+n+1||w₀+n+1|) ≤ Σ_{n≥0} 1/((n + a)² + (t/2)²) with a = 1 + min(re w, re w₀) hmm re w = σ/2 ∈ [−5/4, 3/2]: n+1+re w ≥ n − 1/4. So |w+n+1|² ≥ (n−1/4)² + (t/2)² and |w₀+n+1|² ≥ (n+2)² + (t/2)². The product sum: ≤ Σ_n 1/(((n−1/4)²+25)^{1/2}·((n+2)²+25)^{1/2})·... ≤ Σ_n 1/((n−1/4)² + 25)^{1/2}((n+2)²+25)^{1/2} — hmm. Bound each: |w+n+1||w₀+n+1| ≥ ((n−1/4)²+25)^{1/2}((n+2)²+25)^{1/2} ≥ ((n−1/4)(n+2) + 25)·... by Cauchy (a₁a₂ + b₁b₂ ≤ √(a₁²+b₁²)√(a₂²+b₂²)) — the reverse: √(a²+c²)√(b²+c²) ≥ ab + c² — hmm that gives |w+n+1||w₀+n+1| ≥ (n−1/4)(n+2) + 25 — for n ≥ 1: (n−1/4)(n+2) ≥ (3/4)·3 = 2.25: so ≥ 27.25 for n ≥ 1, and ≥ 25 for n = 0. Then Σ_n 1/(27.25-ish)?? — that's just the per-term bound 1/25 — DIVERGES (Σ 1/27 over all n). Need the j² decay: the product |w+n+1||w₀+n+1| ~ n² for large n: ≥ (n−1/4)(n+2) + 25 ≥ (n² + (7/4)n − 1/2) + 25 ≥ n² + 25 for n ≥ 1 (n² + 1.75n − 0.5 ≥ n² for n ≥ 0.3 ✓). So the terms ≤ 1/(n² + 25) for n ≥ 1 and ≤ 1/25 for n = 0. Σ_{n≥1} 1/(n²+25) ≤ ∫₀^∞ dx/(x²+25) = π/10 ≈ 0.314. Total ≤ 1/25 + 0.314 = 0.354. Then |series| ≤ 2.25·0.354 = 0.80. Plus |1/w − 1/w₀| = |w−w₀|/(|w||w₀|) ≤ 2.25/25 = 0.09. Total |ψ-diff| ≤ 0.80 + 0.09 = 0.89; ½·0.89 = 0.45. Hmm — comparable to the log-route's 0.52. Both fine. But the Weierstrass-difference route avoids the log entirely and avoids EM! The catch: (i) need digamma_series from Zeta23 (exists, axiom-checked per D-068), (ii) the termwise difference of the two tsums (tsum_sub — both summable — is the digamma series summable in the Zeta23 form? digamma_series gives ψ(z) = −γ − 1/z + ∑' ... — the ∑' is summable by construction), (iii) the per-term algebra + the norm bound Σ 1/((n−1/4)²+25)-ish ≤ 1/25 + π/10 — the integral ∫₀^∞ dx/(x²+25) = π/10 needs the arctan FTC (5d used arctan-FTC: `∫dx/((x+a)²+c²) ≤ π/c` — machinery EXISTS from 5d ✓). Hmm — the per-term bound 1/((n−1/4)²+25)^{1/2}((n+2)²+25)^{1/2} ≤ 1/(n²+25) via Cauchy — the Cauchy step in Lean: √((n−1/4)²+25)·√((n+2)²+25) ≥ (n−1/4)(n+2) + 25 — this is Cauchy-Schwarz (a·b + c·c ≤ √(a²+c²)√(b²+c²)) — Mathlib: `Real.inner_le_L2_mul_L2`? or for the explicit form: (a·b + c²)² ≤ (a²+c²)(b²+c²) ⟺ a²b² + 2abc² + c⁴ ≤ a²b² + a²c² + b²c² + c⁴ ⟺ 2ab ≤ a² + b² ✓ — provable via nlinarith/sq_nonneg. But the a = (n−1/4) can be NEGATIVE (n = 0): then ab + c² could be < c² and the inequality √√ ≥ ab + c² with ab < 0: √((n−1/4)²+25)√((n+2)²+25) ≥ |(n−1/4)(n+2)| + 25·... — the safe form: √√ ≥ |ab| + c²? No — Cauchy gives √√ ≥ |ab| (from the c²≥... no: (a²+c²)(b²+c²) ≥ (ab+c²)² — if ab+c² > 0 always (c² = 25 > |ab| for small n): the square form (a²+c²)(b²+c²) ≥ (ab+c²)² holds always ✓ (it expands to (ab−...)... let me verify: (a²+c²)(b²+c²) − (ab+c²)² = a²c² + b²c² − 2abc² = c²(a−b)² ≥ 0 ✓ ALWAYS). So √((n−1/4)²+25)·√((n+2)²+25) ≥ |(n−1/4)(n+2) + 25| ≥ (n−1/4)(n+2) + 25 when the latter ≥ 0 (n ≥ 1: ✓; n = 0: (−1/4)(2) + 25 = 24.5 ≥ 0 ✓). So per-term ≤ 1/((n−1/4)(n+2) + 25) ≤ 1/(n² + 24.5) for n ≥ 1 (since (n−1/4)(n+2) = n² + (7/4)n − 1/2 ≥ n² for n ≥ 1? n² + 1.75n − 0.5 ≥ n² ⟺ 1.75n ≥ 0.5 ⟺ n ≥ 2/7 ✓ n ≥ 1). And n = 0: ≤ 1/24.5. Then Σ_{n≥0} ≤ 1/24.5 + Σ_{n≥1} 1/(n² + 24.5). Σ_{n≥1} 1/(n²+24.5) ≤ ∫₀^∞ dx/(x² + 24.5) = π/(2√24.5) = π/9.899 ≈ 0.317. Total ≤ 0.0408 + 0.317 = 0.358. |series| ≤ 2.25·0.358 = 0.806. Same as before ✓. The Lean work: (i) the digamma series form from Zeta23 (digamma_series — need to check its exact statement and whether the difference-of-tsums is tractable), (ii) the per-term algebra (1/(w+n+1) − 1/(w₀+n+1)) = (w₀−w)/((w+n+1)(w₀+n+1)) — div_sub_div ✓, (iii) the norm bounds with the Cauchy step (sq_nonneg arithmetic), (iv) the sum bound Σ 1/(n²+24.5) ≤ 1/24.5 + π/(2√24.5) via the arctan-FTC machinery (from 5d: ∫dx/((x+a)²+c²) ≤ π/c exists? — 5d's `sum_eq_integral_add_integral_deriv` + arctan-FTC — let me check what exactly exists for the arctan integral). Hmm — this is getting substantial too. Let me compare routes: (A) Level-2 EM remainder |r| ≤ 1.2/|w|²: needs the second-order EM (sum_eq_integral_add_integral_deriv is first-order; is there a B̃₂ version? — the level-2 EM was built in LiRBound for the ζ integral (b2Fun machinery) — but for the DIGAMMA reciprocal sum I'd need sum_eq_integral... at level 2 — does Mathlib have it? The LiRBound b2Fun work was for a specific integral IBP. Building the second-order EM sum formula = significant). (B) The Weierstrass-difference route: digamma_series difference + per-term norm bounds + the arctan sum bound. ~150-200 lines. (C) The crude-5d route with sharpened constants for |im| ≥ 5: reuse norm_digamma_sub_log_le_of_two_le_abs_im's proof structure with c = 5: the bound becomes ≈ 1/(2·5) + π/(2·5) + ... hmm — the 5d proof gives ‖ψ(w) − log w‖ ≤ 3 uniformly; a sharper variant ‖ψ(w)−log w‖ ≤ C(|im|) would need re-running the whole 5d argument with the sharper numbers. Then |ψ(w)−ψ(w₀)| ≤ |log(w/w₀)| + 2·C(5). If C(5) ≈ 0.8: 0.9 + 1.6 = 2.5; ½·2.5 = 1.25 ≤ 2.1 ✓. But re-running 5d's proof with different constants is ~as much work as (B). Actually — WAIT. Much simpler idea: bound the difference via the LOG + the crude 5d bound applied SMARTER. ‖ψ(w) − ψ(w₀)‖ ≤ ‖ψ(w) − log w‖ + ‖log w − log w₀‖ + ‖ψ(w₀) − log w₀‖ ≤ 3 + 0.9 + 3 = 6.9; ½·6.9 = 3.45 > 2.1. Over. Hmm. What if I only need to fit the FINAL assembly — let me recompute the budget precisely with piece 6 = ½·(|log diff| + 6): Total const: piece1 0.9956 + piece2-const 2.7 + piece3-const 42.599 + pieces45 0.09 + piece6. Constraint: const ≤ 48 − (max of 11.813·LL − 4.560·L over L ≥ 2.485). The max of the LL−L function: critical point L* = 11.813/4.560 = 2.5906 (t = 11.34): value 11.813·log(2.5906) − 4.560·2.5906 = 11.813·0.9518 − 11.813 = 11.243 − 11.813 = −0.570. At L = 2.485 (t = 10): 11.813·0.9103 − 4.560·2.485 = 10.753 − 11.332 = −0.579. So max ≈ −0.57. const budget: 48 + (−0.57) = 48.57. Pieces 1-5 const: 0.9956 + 2.7 + 42.599 + 0.09 = 46.385. Piece 6 budget: 48.57 − 46.385 = 2.185. So ½|ψ-diff| ≤ 2.185 needed; ½(0.9 + 6) = 3.45 > 2.185 ✗. With the C(5)-sharpened 5d: ½(0.9 + 2·0.8) = 1.25 ✓. With the Weierstrass route: ½(0.806+0.09) = 0.45 ✓✓. Hmm hold on — actually, let me reconsider the log-diff bound once more, because ½(0.9 + 2·3)... the +6 dominates. What if the ψ−log remainder is bounded directly by 1/|im w|-ish for |im| ≥ 5 via the FIRST-order EM remainder estimate that 5d already did but tracking the |im| dependence? 5d's bound ≤ 3 came from: the B̃₁ remainder ≤ π/(2c) (c = |im|) + boundary 1/|w| + StirlingVert part. For c = 5: π/10 = 0.314 + 1/5 = 0.2 + ... The 5d proof's constant 3 was loose. Re-deriving with c = 5: ‖ψ(w) − log w‖ ≤ (pieces) ≈ 0.1 + 0.314 + (StirlingVert diff at v ≈ 1/(6|v|²)·...) — actually the 5d proof's Stirling part: ψ(v) − log v for re v > 0 via digamma_stirling (Zeta23 StirlingVert) — what's the remainder there? digamma_stirling: ψ(v) = log v − 1/(2v) + O(1/|v|²)? The Zeta23 StirlingVert: `digamma_stirling` gives ‖ψ(v) − log v‖ ≤ something·... Let me check what 5d used: "StirlingVert digamma_stirling" — its bound? If digamma_stirling gives ‖ψ(v) − log v + 1/(2v)‖ ≤ C/|v|² then the whole piece 6 is easy: ψ(w) = log w − 1/(2w) + r(w) with |r| ≤ C/|w|² DIRECTLY from digamma_stirling for re w > 0 — and for re w ≤ 0 (our w has re ∈ [−5/4, 3/2]) via the shift w → w+2 (re+2 ∈ [3/4, 7/2] — still need re > 0 for Stirling? re w + 2 ≥ 3/4 > 0 ✓!). Let me check digamma_stirling's exact statement in Zeta23.
Let me check what Zeta23's `digamma_stirling` actually gives (it might make piece 6 nearly free).
tool: Bash
input
{
  "command": "grep -rn \"theorem digamma_stirling\\|lemma digamma_stirling\" -A 6 D:/Python/Quantum/zeta-23-lean/Zeta23/ | head -20",
  "description": "Read digamma_stirling statement"
}
#1752 assistant 2026-08-24 11:09:32.821 UTC · 4925→7245 tok open ⤢
thinking (15097 chars)
`Zeta23.GammaFacts.StirlingVert.digamma_stirling (hw : 0 < w.re) (ht : 1/2 ≤ |w.im|) : ‖digamma w − log w + (1/2)/w‖ ≤ 3 / w.im²`. So ψ(w) − log w + 1/(2w) ≤ 3/(im w)² for re w > 0, |im w| ≥ 1/2. That's the sharp remainder with constant 3 (vs Lemma D's 1.2/|w|²) — MORE than enough for our budget. Our w = s/2 has re w = σ/2 ∈ [−5/4, 3/2] — can be ≤ 0 (for σ ∈ [−5/2, 0])! So digamma_stirling applies directly only when σ > 0. For σ ≤ 0, shift: w ↦ w+2 (re w+2 = σ/2 + 2 ≥ 3/4 > 0 ✓): ψ(w+2) − log(w+2) + 1/(2(w+2)) ≤ 3/(im)². And ψ(w+2) = ψ(w) + 1/w + 1/(w+1) (digamma_add_natCast with n = 2). So ψ(w) = ψ(w+2) − 1/w − 1/(w+1). The ψ-difference: ψ(w) − ψ(w₀) — with w₀ = s₀/2 = 1 + it/2: re w₀ = 1 > 0 ✓ direct. For w with re w = σ/2: - If σ/2 > 0 (σ ∈ (0, 3]): direct digamma_stirling on both. - If σ ≤ 0: shift w by 2. Hmm — case split on σ. Cleaner: apply the shift for ALL w? For re w > 0 the direct is fine; for re w ≤ 0 shift by 2. The difference bound: Case A (re w > 0): |ψ(w) − ψ(w₀)| = |[log w − 1/(2w) + r(w)] − [log w₀ − 1/(2w₀) + r(w₀)]| ≤ |log w − log w₀| + (1/2)|1/w − 1/w₀| + 3/(im w)² + 3/(im w₀)². With im w = im w₀ = t/2 ≥ 5: ≤ |log diff| + (1/2)·2.25/25 + 6/25 = |log diff| + 0.045 + 0.24. Case B (re w ≤ 0): ψ(w) = ψ(w+2) − 1/w − 1/(w+1); ψ(w+2) = log(w+2) − 1/(2(w+2)) + r(w+2). So ψ(w) = log(w+2) − 1/(2(w+2)) − 1/w − 1/(w+1) + r(w+2). And ψ(w₀) = log w₀ − 1/(2w₀) + r(w₀). The difference: [log(w+2) − log w₀] − (1/2)[1/(w+2) − 1/w₀] − [1/w + 1/(w+1)] + [r(w+2) − r(w₀)]. Bounds: |1/w| ≤ 1/|im w| = 2/t ≤ 0.2; |1/(w+1)|: im(w+1) = t/2 ⟹ ≤ 2/t ≤ 0.2. |log(w+2) − log w₀|: w+2 = (σ/2+2) + it/2, w₀ = 1 + it/2: |(w+2) − w₀| = |σ/2 + 1| ≤ 5/4 + 1 = 2.25 (σ ∈ [−5/2, 0]: σ/2 + 1 ∈ [−1/4, 1]: |σ/2+1| ≤ 1 hmm wait σ/2 ∈ [−5/4, 0] so σ/2 + 1 ∈ [−1/4, 1], |·| ≤ 1 — even better; but let me keep 2.25 for safety — no: |σ/2 + 1| ≤ max(|−1/4|, 1) = 1). |log(w+2) − log w₀| ≤ 2·|(w+2−w₀)/w₀| ≤ 2·1/5 = 0.2·2 = 0.4 (|w₀| ≥ 5). Actually |log(1+u)| ≤ 2|u| for |u| ≤ 1/2: |u| = |(w+2−w₀)/w₀| ≤ 1/5 = 0.2: ≤ 0.4 ✓. Hmm — the case split makes it messy. Let me simplify: is there a UNIFORM form? Actually — simpler: apply digamma_stirling at w+2 and w₀+2?? No wait — the cleanest uniform approach: the difference ψ(w) − ψ(w₀) where BOTH get shifted: no. Alternative uniform approach: use the RECURRENCE relation differently. Actually, let me reconsider: our w = s/2 with σ ∈ [−5/2, 3]. The digamma difference bound — the cleanest uniform statement: For ANY w with |im w| ≥ 5 and re w ≥ −5/4 (our range), and w₀ = 1 + it/2: Use the shifted form for w only when needed. OR: uniformly shift w by 2: ψ(w) = ψ(w+2) − 1/w − 1/(w+1) (valid for im w ≠ 0 ✓ digamma_add_natCast n=2 needs im ≠ 0 ✓). And ψ(w+2) = log(w+2) − 1/(2(w+2)) + r(w+2) with re(w+2) = σ/2+2 ≥ 3/4 > 0 ✓ ALWAYS (σ ≥ −5/2). So uniformly: ψ(w) = log(w+2) − 1/(2(w+2)) − 1/w − 1/(w+1) + r(w+2), ‖r(w+2)‖ ≤ 3/(t/2)² = 12/t². ψ(w₀) = log w₀ − 1/(2w₀) + r(w₀), ‖r(w₀)‖ ≤ 12/t². Difference: ψ(w) − ψ(w₀) = [log(w+2) − log w₀] − (1/2)[1/(w+2) − 1/w₀] − 1/w − 1/(w+1) + [r(w+2) − r(w₀)]. Hmm — the −1/w − 1/(w+1) extra terms: |1/w| ≤ 2/t, |1/(w+1)| ≤ 2/t. These are the price of the uniform shift: ≤ 4/t ≤ 0.4. And log(w+2) − log w₀: |(w+2) − w₀| = |σ/2 + 1| ≤ 2.25 (uniform σ range): |u| ≤ 2.25/5 = 0.45: |log diff| ≤ 2·0.45 = 0.9. (1/2)|1/(w+2) − 1/w₀| ≤ (1/2)·|(w+2)−w₀|/(|w+2||w₀|) ≤ (1/2)·2.25/(5·5) = 0.045. r-difference ≤ 24/t² ≤ 0.24. Total: 0.9 + 0.045 + 0.4 + 0.24 = 1.585. ½·1.585 = 0.7925 ≤ 2.185 ✓✓ FITS with huge margin. And it's UNIFORM (no case split). Wait — actually, hmm: ψ(w) = ψ(w+2) − 1/w − 1/(w+1) — digamma_add_natCast (w) (2): ψ(w+2) = ψ(w) + Σ_{j<2} (w+j)⁻¹ = ψ(w) + w⁻¹ + (w+1)⁻¹ ✓ so ψ(w) = ψ(w+2) − w⁻¹ − (w+1)⁻¹ ✓. digamma_add_natCast needs hw : w.im ≠ 0 ✓ (im w = t/2 ≥ 5). So piece 6's Lean proof: 1. `digamma_stirling` at w+2 and at w₀ (both re > 0, |im| = t/2 ≥ 5 ≥ 1/2 ✓): ‖ψ(v) − log v + (1/2)/v‖ ≤ 3/(im v)². 2. ψ(w) via the recurrence. 3. The log difference |log(w+2) − log w₀| ≤ 2·(|(w+2)−w₀|/|w₀|): the |log(1+u)| ≤ 2|u| bound — Mathlib lemma? `Complex.norm_log_one_add_le`? Let me search: there's `Complex.abs_log_one_add_le`? or `Complex.norm_log_one_add_le (h : ‖z‖ ≤ 1/2) : ‖log (1+z)‖ ≤ 2‖z‖`? I recall something like `Complex.norm_log_one_add_le (hz : ‖z‖ < 1) : ‖log (1 + z)‖ ≤ -Real.log (1 - ‖z‖)`? and then −log(1−x) ≤ 2x for x ≤ 1/2 via Real.log... Let me check what exists. Actually the log DIFFERENCE: log(w+2) − log w₀ = log((w+2)/w₀)? — needs the arg care (Complex.log of a ratio: log a − log b = log(a/b) requires... Complex.log_sub? no — log(a/b) = log a − log b when... in ℂ this needs the arguments to not cross the slit. The safe form: log(w+2) − log w₀ = log(1 + u) where u = (w+2−w₀)/w₀ — the identity log(1+u) = log(w+2) − log(w₀) holds when...? Complex.log(1+u) = log(w+2) − log w₀ where 1+u = (w+2)/w₀: Complex.log_div? Hmm — Complex.log (a/b) = log a − log b requires re b ≠ 0 or... there's `Complex.log_div (ha : a ≠ 0) (hb : b ≠ 0)`? — not always true in ℂ (the arg wrap). BUT for our case: w+2 and w₀ both have im > 0 and re > 0 — they're in the right half-plane, both args in (−π/2, π/2), so the ratio's arg is in (−π, π) — no slit crossing: log(w+2) − log w₀ = log((w+2)/w₀) ✓ valid. Mathlib: `Complex.log_div (ha : a.re > 0)?`... there's `Complex.log_div_of...`? Hmm — or via log_mul_of... For safety: Complex.log_div_of_real? Let me search for what's available. Alternatively avoid the ratio: bound ‖log(w+2) − log w₀‖ directly via the FTC: log(w+2) − log w₀ = ∫_{w₀}^{w+2} dz/z along the straight segment (both in the right half-plane, segment stays in re ≥ 3/4... re(w+2) ≥ 3/4, re w₀ = 1: segment re ≥ 3/4 > 0 ✓): |∫ dz/z| ≤ |segment|·max|1/z| = 2.25·(1/(min re... |z| ≥ re z ≥ 3/4 along the segment): ≤ 2.25/(3/4) = 3?? too big — hmm: |1/z| ≤ 1/|z| ≤ 1/(t/2 − ...)|: |z| ≥ |im z| = t/2 ≥ 5 along the segment (im constant t/2!) — the segment from w₀ to w+2 has constant im = t/2 ✓ so |z| ≥ t/2 ≥ 5 ⟹ |∫| ≤ 2.25/5 = 0.45!! Clean — the FTC-along-the-segment bound: |log(w+2) − log w₀| = |∫_{segment} dz/z| ≤ |w+2−w₀|·sup|1/z| ≤ 2.25·(2/t) = 4.5/t ≤ 0.45 at t=10 ✓. The FTC: Complex integral along a segment of 1/z — Mathlib: `Complex...`? Hmm — path integrals in Lean are painful. Alternative: the identity via HasDerivAt + the fundamental theorem for line integrals... Mathlib has `Complex.integral_...`? Actually — simpler: use the real-parameter FTC: define g(y) = Complex.log(w₀ + y·(w+2−w₀)) for y ∈ [0,1] (real parameter): g' = (w+2−w₀)/(w₀ + y(w+2−w₀)) (chain rule, Complex.log differentiable off the slit — the segment has re ≥ 3/4 > 0 so all points in slitPlane ✓). Then log(w+2) − log w₀ = g(1) − g(0) = ∫₀¹ g'(y) dy (real FTC for ℂ-valued — intervalIntegral with complex integrand ✓ used in 5d: sum_eq_integral_add_integral_deriv is ℂ-valued ✓). Bound: ‖g'(y)‖ ≤ |w+2−w₀|/|w₀+y(w+2−w₀)| ≤ 2.25/(t/2) (im of the point = t/2 ✓ constant). ∫ ≤ 2.25·(2/t)·1 = 4.5/t. This is exactly the 5d pattern (the log FTC at LiReflect:724-729: `HasDerivAt (fun y : ℝ => Complex.log (w + y)) ((w+x)⁻¹)` ✓ SAME form). So piece 6's log bound: ‖log(w+2) − log w₀‖ ≤ 4.5/t via the segment FTC (the 5d pattern, ~60 lines given the machinery exists). Total piece 6 target: ‖(digamma (s/2) − digamma (s₀/2))/2‖ ≤ C₆ with C₆ = ½·(0.45 + 0.045 + 0.4 + 0.24)·... let me recompute with the /2: ½·1.585 = 0.7925. Set the target ≤ 1 (round). Actually — hold on, let me reconsider whether to include the shift terms for ALL w or to keep them only when needed... The uniform-shift form has the extra −1/w − 1/(w+1) terms costing 0.4 — fine (budget 2.185). Hmm wait — actually, let me simplify FURTHER: apply digamma_stirling at v := w + 2 and v₀ := w₀ (direct, re w₀ = 1 > 0): ψ(w) − ψ(w₀) = [ψ(w+2) − 1/w − 1/(w+1)] − ψ(w₀) = [log(w+2) − 1/(2(w+2)) + r_v] − 1/w − 1/(w+1) − [log w₀ − 1/(2w₀) + r₀] = [log(w+2) − log w₀] + [1/(2w₀) − 1/(2(w+2))] − 1/w − 1/(w+1) + [r_v − r₀]. Bounds (all with |·| ≥ t/2 on every point involved): - ‖log(w+2) − log w₀‖ ≤ 4.5/t. - ‖1/(2w₀) − 1/(2(w+2))‖ = ½·‖(w+2 − w₀)/(w₀(w+2))‖ ≤ ½·2.25/((t/2)(t/2)) = ½·2.25·4/t² = 4.5/t². - ‖1/w‖ ≤ 2/t; ‖1/(w+1)‖ ≤ 2/t. - ‖r_v‖ ≤ 3/(t/2)² = 12/t²; ‖r₀‖ ≤ 12/t². Total: 4.5/t + 4.5/t² + 4/t + 24/t² ≤ (at t ≥ 10, t² ≥ 10t): 4.5/t + 0.45/t + 4/t + 2.4/t = 11.35/t ≤ 1.135 at t = 10. So ‖ψ(w)−ψ(w₀)‖ ≤ 11.35/t; half: 5.675/t ≤ 0.5675. TARGET: ‖(digamma (s/2) − digamma (s₀/2))/2‖ ≤ 6/t — hmm let me set: ≤ 5.7/t ≤ 0.57. Or just ≤ 1 for roundness. The assembly uses a specific constant; let me use ≤ 0.6 (safe) — hmm, actually let me just target ‖(ψ-diff)/2‖ ≤ 6/t (then 6/t ≤ 0.6 for t ≥ 10). Simpler: prove ‖(digamma (s/2) − digamma (s₀/2))/2‖ ≤ 6/t. Hmm — one subtlety: digamma_stirling needs 0 < re: v = w+2: re v = σ/2 + 2 ≥ 3/4 ✓ (σ ≥ −5/2). v₀ = w₀: re = 1 ✓. And the |im| ≥ 1/2: t/2 ≥ 5 ✓. Also the r_v bound: digamma_stirling gives ‖digamma v − log v + (1/2)/v‖ ≤ 3/(v.im)² = 3/(t/2)² = 12/t² ✓. Let me now write piece 6. Structure: ```lean /-- Piece 6 (digamma difference): for σ ∈ [−5/2, 3], s = σ + it, t ≥ 10, s₀ = 2 + it: ‖(ψ(s/2) − ψ(s₀/2))/2‖ ≤ 6/t. Via the +2 shift into the right half-plane (re(w+2) ≥ 3/4), Zeta23's digamma_stirling at w+2 and w₀, the recurrence ψ(w) = ψ(w+2) − 1/w − 1/(w+1), and the segment-FTC log bound (im constant t/2 ⟹ |∫ dz/z| ≤ 2.25·(2/t)). -/ theorem digamma_diff_le {t : ℝ} (ht : 10 ≤ t) {s : ℂ} (hσlo : -5/2 ≤ s.re) (hσhi : s.re ≤ 3) (him : s.im = t) : ‖(Complex.digamma (s / 2) - Complex.digamma ((2 + t * Complex.I) / 2)) / 2‖ ≤ 6 / t := by ... ``` Components: (a) w := s/2, w₀ := (2+tI)/2 = 1 + (t/2)I. w₀'s form: (2 + tI)/2 = 1 + (t/2)I: by ring-ish. Let me define w₀ := 1 + (t/2)*I and show (2+t*I)/2 = w₀ by ring (field_simp): (2+tI)/2 = 1 + (t/2)I ✓ ring (char 0 field) ✓. (b) w.im = t/2 (s.im = t: (s/2).im = s.im/2 = t/2 ✓ simp [him]). (c) ‖w‖ ≥ t/2: |im w| = t/2 ≤ ‖w‖ (abs_im_le_norm). (d) The recurrence: digamma w = digamma (w+2) − w⁻¹ − (w+1)⁻¹ — from digamma_add_natCast (w) (hw : w.im ≠ 0) (2): digamma (w+2) = digamma w + Σ_{j<2} (w+j)⁻¹ = digamma w + w⁻¹ + (w+1)⁻¹. Need w.im ≠ 0 ✓ (t/2 ≥ 5). The sum: Finset.range 2 = {0,1}: (w+0)⁻¹ + (w+1)⁻¹ = w⁻¹ + (w+1)⁻¹ ✓ (Finset.sum_range_two? or sum_range_succ twice). (e) digamma_stirling at v = w+2: ‖digamma v − log v + (1/2)/v‖ ≤ 3/(v.im)² = 3/(t/2)²; re v = σ/2 + 2 ≥ 3/4 > 0 ✓; |im v| = t/2 ≥ 5 ≥ 1/2 ✓. (f) digamma_stirling at w₀: re = 1 > 0 ✓; ‖digamma w₀ − log w₀ + (1/2)/w₀‖ ≤ 3/(t/2)². (g) the log difference: ‖log(w+2) − log w₀‖ ≤ 4.5/t via segment FTC. This is the meaty part: ```lean have hseg : ∀ y : ℝ, y ∈ Set.uIcc (0:ℝ) 1 → (w₀ + y * ((w + 2) - w₀)).re ≥ 3/4 ∧ ... ``` Hmm — w₀ + y·((w+2) − w₀): re = 1 + y·(σ/2 + 1) ∈ [1 − ...]: σ/2 + 1 ∈ [−1/4, 2]: re = 1 + y·(σ/2+1) ≥ 1 − 1/4 = 3/4 ✓ (y ∈ [0,1], σ/2+1 ≥ −1/4: re ≥ 1 − 1/4 = 3/4 ✓). im = t/2 (constant: im(y·(w+2−w₀)) = y·im(w+2−w₀) = y·0 = 0 since im(w+2) = im w₀ = t/2 ✓). So the segment point z(y) = w₀ + y·δ (δ := w+2−w₀) has re ≥ 3/4 (so ∈ slitPlane, z ≠ 0) and im = t/2 (so ‖z‖ ≥ t/2). Then log(w+2) − log w₀ = ∫₀¹ δ·z(y)⁻¹ dy (the chain-rule FTC): g(y) := Complex.log(z(y)): HasDerivAt g (δ·z(y)⁻¹) y: Complex.log's deriv: hasDerivAt_log (z ≠ 0, slitPlane membership): Complex.hasDerivAt_log (hz : z ∈ slitPlane)? The name: `Complex.hasDerivAt_log (hz : z ≠ 0)?` — hmm: Complex.log is differentiable on slitPlane: `Complex.hasDerivAt_log (hx : x ∈ slitPlane) : HasDerivAt log x⁻¹ x`? or `Complex.hasDerivAt_log (hx : x ≠ 0)`? For the slitPlane: I think there's `Complex.hasDerivAt_log_of_mem_slitPlane`? or log is analytic off (−∞, 0]. From 5d (LiReflect:725): `HasDerivAt (fun y : ℝ => Complex.log (w + y)) ((w+x)⁻¹) x` — they used `hslit : w + (x:ℂ) ∈ Complex.slitPlane` and presumably Complex.hasDerivAt_log. Let me check the exact name used there. Then the FTC: ∫₀¹ g' = g(1) − g(0) via intervalIntegral.integral_deriv_eq_sub (g cont, g' = ...) — for ℂ-valued: `intervalIntegral.integral_deriv_eq_sub (f cont...) (hderiv : ∀ x ∈ uIcc, HasDerivAt f (f' x) x) (hint : IntervalIntegrable f')`: f(1) − f(0) = ∫₀¹ f' — name check: intervalIntegral.integral_deriv_eq_sub (hf : ContinuousOn f uIcc?) (hderiv : ∀ x ∈ interior, HasDerivWithinAt...) — 5d used `sum_eq_integral_add_integral_deriv` which is built on it. The direct: `intervalIntegral.integral_deriv_eq_sub (f f' a b) (hcont : ContinuousOn f (uIcc a b)) (hderiv : ∀ x ∈ uIoo a b, HasDerivAt f (f' x) x) (hint : IntervalIntegrable f' ...) : ∫ x in a..b, f' x = f b − f a` ✓ standard. Then ‖∫₀¹ δ·z⁻¹‖ ≤ ∫₀¹ ‖δ·z⁻¹‖ ≤ ∫₀¹ ‖δ‖·(2/t) = (2.25)·(2/t) = 4.5/t — via intervalIntegral.norm_integral_le_of_norm_le_const? `intervalIntegral.norm_integral_le_of_norm_le_const (h : ∀ x ∈ uIoc, ‖f x‖ ≤ C) : ‖∫ a..b f‖ ≤ C·|b−a|`? something like that (used in 5d presumably). Then ‖δ‖ = ‖w+2 − w₀‖ = ‖(s/2 + 2) − (1 + (t/2)I)‖ = ‖(σ/2 + 1) + 0·I‖·... = |σ/2 + 1| ≤ 2.25 (σ/2 ∈ [−1.25, 1.5]: σ/2+1 ∈ [−0.25, 2.5]: |·| ≤ 2.5 hmm: σ/2 ∈ [−5/4, 3/2]: σ/2 + 1 ∈ [−1/4, 5/2]: |σ/2+1| ≤ 5/2 = 2.5). So ‖δ‖ ≤ 2.5: ∫ ≤ 2.5·2/t = 5/t. Hmm — 2.5 not 2.25 (σ/2 up to 3/2 gives σ/2+1 up to 5/2). Fine: 5/t. Let me redo the totals with 5/t: log diff ≤ 5/t; 1/(2·) diff ≤ ½·‖δ‖·(2/t)² = ½·2.5·4/t² = 5/t²; 1/w + 1/(w+1) ≤ 2/t + 2/t = 4/t; r-pieces ≤ 24/t². Total: 5/t + 5/t² + 4/t + 24/t² ≤ 5/t + 0.5/t + 4/t + 2.4/t = 11.9/t (at t ≥ 10). Half: ≤ 5.95/t. Target: ‖(ψ-diff)/2‖ ≤ 6/t ✓. (h) The final assembly: ψ(w) − ψ(w₀) = [log(w+2) − log w₀] + [1/(2w₀) − 1/(2(w+2))] − w⁻¹ − (w+1)⁻¹ + [r_v − r₀] — via linear_combination with the recurrence + the two Stirling haves. Then the norm chain (norm_add_le etc.) + the per-piece bounds + t ≥ 10 arithmetic. The algebra: from (d): ψ(w) = ψ(w+2) − w⁻¹ − (w+1)⁻¹. From (e): ψ(w+2) = log(w+2) − (1/2)/(w+2) + r_v where r_v := digamma v − log v + (1/2)/v (so digamma v = log v − (1/2)/v + r_v — wait: ‖digamma v − log v + (1/2)/v‖ ≤ 3/(im)²: set r_v := digamma v − Complex.log v + (1/2)/v: then digamma v = log v − (1/2)/v + r_v ✓ linear). Similarly r₀ := digamma w₀ − log w₀ + (1/2)/w₀. Then: ψ(w) − ψ(w₀) = ψ(v) − w⁻¹ − (w+1)⁻¹ − ψ(w₀) = [log v − (1/2)/v + r_v] − w⁻¹ − (w+1)⁻¹ − [log w₀ − (1/2)/w₀ + r₀] = [log v − log w₀] − (1/2)/v + (1/2)/w₀ − w⁻¹ − (w+1)⁻¹ + r_v − r₀ ✓. Norm chain: ‖ψ(w) − ψ(w₀)‖ ≤ ‖log v − log w₀‖ + ½‖1/v − 1/w₀‖ hmm the (1/2)/v − (1/2)/w₀ = (1/2)·(1/v − 1/w₀): ‖·‖ ≤ ½·‖1/v − 1/w₀‖ = ½·‖(w₀−v)/(v·w₀)‖ = ½·‖w₀−v‖/(‖v‖‖w₀‖). w₀ − v = w₀ − (w+2) = −δ: ‖·‖ = ‖δ‖ ≤ 2.5. ‖v‖ ≥ t/2 (im v = t/2 ✓), ‖w₀‖ ≥ t/2 ✓. So ≤ ½·2.5/((t/2)²) = ½·2.5·4/t² = 5/t² ✓. ‖w⁻¹‖ = 1/‖w‖ ≤ 2/t; ‖(w+1)⁻¹‖ ≤ 2/t (im(w+1) = t/2 ✓). ‖r_v‖ ≤ 3/(t/2)² = 12/t²; ‖r₀‖ ≤ 12/t². Then the /2: ‖(ψ(w)−ψ(w₀))/2‖ = ½‖ψ(w)−ψ(w₀)‖. And the fold to 6/t: 5/t + 5/t² + 2/t + 2/t + 12/t² + 12/t² = 9/t + 29/t² ≤ 9/t + 29/(10t) = 9/t + 2.9/t = 11.9/t. Half: 5.95/t ≤ 6/t ✓. This is a solid ~200-line build. Given the time (2:20 AM), let me go for it — it's mechanical given the pieces. Actually — one more check: Complex.hasDerivAt_log's exact form for the segment FTC. From LiReflect:725-729, they have `HasDerivAt (fun y : ℝ => Complex.log (w + (y:ℂ))) ((w + (x:ℂ))⁻¹) x` — let me read that part to copy the exact pattern.
`digamma_stirling` gives ‖ψ(v) − log v + (1/2)/v‖ ≤ 3/(im v)² — piece 6 has a comfortable route. Checking the 5d segment-FTC pattern to copy for the log difference.
tool: Read ok
input
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result 2026-08-24 11:09:33Z → 2026-08-24 11:09:33Z
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  "file": {
    "filePath": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiReflect.lean",
    "content": "  -- the log FTC\n  have hanti : \u2200 x \u2208 Set.uIcc 0 (n : \u211d),\n      HasDerivAt (fun y : \u211d => Complex.log (w + (y : \u2102))) ((w + (x : \u2102))\u207b\u00b9) x := by\n    intro x _\n    have hne := hne_all x\n    have hslit : w + (x : \u2102) \u2208 Complex.slitPlane := by\n      rw [Complex.mem_slitPlane_iff]\n      right\n      rw [Complex.add_im, Complex.ofReal_im, add_zero]\n      exact him\n    have h1 : HasDerivAt (fun z : \u2102 => Complex.log (w + z)) ((w + (x : \u2102))\u207b\u00b9) (x : \u2102) := by\n      have h2 := (Complex.hasDerivAt_log hslit).comp (x : \u2102)\n        ((hasDerivAt_id' (x : \u2102)).const_add w)\n      simpa [Function.comp_def] using h2\n    exact h1.comp_ofReal\n  have hconti : IntervalIntegrable (fun y : \u211d => (w + (y : \u2102))\u207b\u00b9) volume 0 (n : \u211d) := by\n    apply ContinuousOn.intervalIntegrable\n    apply Continuous.continuousOn\n    apply Continuous.inv\u2080 _ hne_all\n    exact continuous_const.add Complex.continuous_ofReal\n  have hint : \u222b x in (0 : \u211d)..(n : \u211d), (w + (x : \u2102))\u207b\u00b9 = Complex.log v - Complex.log w := by\n    rw [intervalIntegral.integral_eq_sub_of_hasDerivAt hanti hconti]\n    simp [hv]\n  -- the arctan comparison integral\n  have hanti2 : \u2200 x \u2208 Set.uIcc 0 (n : \u211d),\n      HasDerivAt (fun y : \u211d => (1 / |w.im|) * Real.arctan ((y + w.re) / |w.im|))\n        (((x + w.re) ^ 2 + |w.im| ^ 2)\u207b\u00b9) x := by\n    intro x _\n    have h1 : HasDerivAt (fun y : \u211d => (y + w.re) / |w.im|) (1 / |w.im|) x :=\n      ((hasDerivAt_id x).add_const w.re).div_const |w.im|\n    have h2 := h1.arctan\n    have h3 := h2.const_mul (1 / |w.im|)\n    refine h3.congr_deriv ?_\n    field_simp [hc0.ne']\n    ring\n  have hconti2 : IntervalIntegrable (fun x : \u211d => ((x + w.re) ^ 2 + |w.im| ^ 2)\u207b\u00b9)\n      volume 0 (n : \u211d) := by\n    apply ContinuousOn.intervalIntegrable\n    apply Continuous.continuousOn\n    apply Continuous.inv\u2080 _ (fun x => by\n      have h1 : (0 : \u211d) < (x + w.re) ^ 2 + |w.im| ^ 2 := by\n        nlinarith [sq_nonneg (x + w.re), hc0]\n      exact ne_of_gt h1)\n    exact (continuous_id.add continuous_const).pow 2 |>.add continuous_const\n  have harctan : \u222b x in (0 : \u211d)..(n : \u211d), ((x + w.re) ^ 2 + |w.im| ^ 2)\u207b\u00b9\n      \u2264 Real.pi / |w.im| := by\n    rw [intervalIntegral.integral_eq_sub_of_hasDerivAt hanti2 hconti2]\n    have h1 : Real.arctan (((n : \u211d) + w.re) / |w.im|)\n        - Real.arctan ((0 + w.re) / |w.im|) \u2264 Real.pi := by\n      have hu := Real.arctan_lt_pi_div_two (((n : \u211d) + w.re) / |w.im|)\n      have hv2 := Real.arctan_lt_pi_div_two (-((0 + w.re) / |w.im|))\n      rw [Real.arctan_neg] at hv2\n      linarith [Real.pi_pos, hv2]\n    calc (1 / |w.im|) * Real.arctan (((n : \u211d) + w.re) / |w.im|)\n          - (1 / |w.im|) * Real.arctan ((0 + w.re) / |w.im|)\n        = (1 / |w.im|) * (Real.arctan (((n : \u211d) + w.re) / |w.im|)\n            - Real.arctan ((0 + w.re) / |w.im|)) := by ring\n      _ \u2264 (1 / |w.im|) * Real.pi :=\n          mul_le_mul_of_nonneg_left h1 (by positivity)\n      _ = Real.pi / |w.im| := by ring\n  -- the B\u0303\u2081 remainder bound\n  have hderiv_eq2 : \u2200 x : \u211d, deriv (fun y : \u211d => (w + (y : \u2102))\u207b\u00b9) x\n      = -(((w + (x : \u2102)) ^ 2)\u207b\u00b9) := fun x => (hder x).deriv\n  have hn1 : \u2200 x : \u211d, \u2016-(((w + (x : \u2102)) ^ 2)\u207b\u00b9)\u2016 = \u2016(w + (x : \u2102))\u207b\u00b9\u2016 ^ 2 := by\n    intro x\n    simp only [norm_neg, norm_inv, norm_pow, inv_pow]\n  have hnorm_eq : (fun x : \u211d => \u2016deriv (fun y : \u211d => (w + (y : \u2102))\u207b\u00b9) x * (B1 x : \u2102)\u2016)\n      = fun x : \u211d => \u2016(w + (x : \u2102))\u207b\u00b9\u2016 ^ 2 * \u2016B1 x\u2016 := by\n    funext x\n    rw [hderiv_eq2 x, norm_mul, Complex.norm_real, hn1 x]\n  have hnsq : \u2200 x : \u211d, \u2016w + (x : \u2102)\u2016 ^ 2 = (x + w.re) ^ 2 + |w.im| ^ 2 := by\n    intro x\n    rw [\u2190 Complex.normSq_eq_norm_sq, Complex.normSq_apply]\n    have h1 : (w + (x : \u2102)).re = w.re + x := by simp [Complex.add_re, Complex.ofReal_re]\n    have h2 : (w + (x : \u2102)).im = w.im := by simp [Complex.add_im, Complex.ofReal_im]",
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#1753 assistant 2026-08-24 11:11:19.725 UTC · 8872→3470 tok open ⤢
thinking (7869 chars)
I have the exact patterns: - `Complex.hasDerivAt_log hslit` with `hslit : z ∈ Complex.slitPlane` (via `Complex.mem_slitPlane_iff` — the right case: im ≠ 0). - `(Complex.hasDerivAt_log hslit).comp (x:ℂ) ((hasDerivAt_id' (x:ℂ)).const_add w)` for the affine precomposition, then `.comp_ofReal`. - `intervalIntegral.integral_eq_sub_of_hasDerivAt hanti hconti` : ∫ x in a..b, f' = f b − f a (with hanti : ∀ x ∈ uIcc, HasDerivAt f (f' x) x and hconti : IntervalIntegrable f'). - The norm bound for the integral: I'll need `intervalIntegral.norm_integral_le_of_norm_le_const` or similar — let me just bound via: ‖∫₀¹ δ·z(y)⁻¹ dy‖ ≤ ∫₀¹ ‖δ·z(y)⁻¹‖ dy (intervalIntegral.norm_integral_le_integral_norm or intervalIntegral.norm_integral_le_of_norm_le_const). The latter: `intervalIntegral.norm_integral_le_of_norm_le_const (h : ∀ x ∈ uIoc a b, ‖f x‖ ≤ C) : ‖∫ x in a..b, f x‖ ≤ C * |b − a|`? — I think it exists. Or the norm-of-integral ≤ integral-of-norm + the constant bound. Let me plan with norm_integral_le_of_norm_le_const (check at build). For piece 6's log difference, I need: g(y) := Complex.log (w₀ + (y:ℂ)·δ) where δ := (w+2) − w₀. - z(y) := w₀ + (y:ℂ)·δ has re ≥ 3/4 (so z(y) ≠ 0 and in slitPlane — via re > 0: mem_slitPlane_iff's LEFT case: re ≠ 0? slitPlane = ℂ ∖ (−∞, 0]: mem_slitPlane_iff : z ∈ slitPlane ↔ re z ≠ 0 ∨ im z ≠ 0? no: slitPlane = {z | re z > 0} ∪ {im ≠ 0}? Complex.mem_slitPlane_iff : z ∈ slitPlane ↔ 0 < z.re ∨ z.im ≠ 0 — I think it's (0 < re ∨ im ≠ 0). re ≥ 3/4 > 0 ✓ left case. - HasDerivAt g (δ·z(y)⁻¹) y: via (Complex.hasDerivAt_log hslit).comp ((hasDerivAt_id' _).const_add ... hmm the composition: z(y) = w₀ + y·δ: as a function of the real y: first build the ℂ-version: HasDerivAt (fun z : ℂ => Complex.log (w₀ + z·δ)) (Complex.log' ... ·δ)?? — the chain: (fun z => w₀ + z·δ) has deriv δ; log has deriv z⁻¹; composite: δ·z⁻¹ or z⁻¹·δ — HasDerivAt.comp: (hasDerivAt_log hslit).comp z₀ (h_affine): h_affine : HasDerivAt (fun z => w₀ + z·δ) δ z₀: (hasDerivAt_id' z₀).const_mul δ |>.const_add w₀? HasDerivAt.const_mul : HasDerivAt f f' x → HasDerivAt (fun x => f x * c) (f' * c) x ✓ then const_add. Then comp gives HasDerivAt (fun z => log (w₀ + z·δ)) (z₀-related value ·) — the comp value: (log' at w₀+z₀·δ) * δ = (w₀+z₀δ)⁻¹ * δ. Then .comp_ofReal : HasDerivAt (fun y : ℝ => log (w₀ + (y:ℂ)·δ)) (((w₀+(x:ℂ)δ)⁻¹·δ)) x — then the value form (w₀+xδ)⁻¹·δ vs δ·(w₀+xδ)⁻¹ — mul_comm ✓. - FTC: ∫₀¹ (fun y => δ·z(y)⁻¹) = g 1 − g 0 = log(w₀ + δ) − log w₀ = log(w+2) − log w₀ ✓ (w₀ + 1·δ = w₀ + δ = w+2 ✓ by ring-ish: δ := w+2−w₀: w₀ + δ = w+2 ✓). - norm bound: ‖∫₀¹ δ·z⁻¹‖ ≤ ∫₀¹ ‖δ·z⁻¹‖ ≤ (5/2)·(2/t)·(1−0) = 5/t: via intervalIntegral.norm_integral_le_of_norm_le_const (h : ∀ y ∈ uIoc 0 1, ‖δ·z(y)⁻¹‖ ≤ 5/t): ‖δ·z⁻¹‖ = ‖δ‖·‖z‖⁻¹ ≤ (5/2)·(2/t) = 5/t ✓ (‖z‖ ≥ t/2 from |im z| = t/2). Then the final algebra. Let me now write the whole piece 6. Structure: ```lean /-! ## 7. Piece 6: the digamma difference -/ /-- The log difference along the constant-imaginary segment: for w, w₀ with the same imaginary part t/2 ≥ 5 and real parts in [3/4, 7/2]... ‖log w − log w₀‖ ≤ (5/2)·(2/t)·... -/ ``` Hmm — actually let me parametrize cleanly. Set: - w := s/2, w₀ := (2 + t·I)/2 = 1 + (t/2)·I. - δ := w + 2 − w₀ = (s/2 + 2) − (1 + (t/2)I) = (σ/2 + 1) (purely real!) — since im(s/2) = t/2 = im w₀, the difference is real: δ = ((σ/2 + 1 : ℝ) : ℂ). ‖δ‖ = |σ/2 + 1| ≤ 5/2 (σ/2 + 1 ∈ [−1/4, 5/2]). The segment z(y) = w₀ + y·δ: re = 1 + y(σ/2+1) ∈ [3/4, 7/2], im = t/2. Let me write the theorem: ```lean /-- Piece 6 helper: the log difference bound along the constant-im segment. For σ ∈ [−5/2, 3], t ≥ 10: with w = s/2, w₀ = 1 + (t/2)I: ‖log (w + 2) − log w₀‖ ≤ 5/t. -/ theorem log_diff_le {t : ℝ} (ht : 10 ≤ t) {s : ℂ} (hσlo : -5 / 2 ≤ s.re) (hσhi : s.re ≤ 3) (him : s.im = t) : ‖Complex.log (s / 2 + 2) - Complex.log (1 + (t / 2) * Complex.I)‖ ≤ 5 / t := by ... ``` Wait — should I phrase with w₀ = 1 + (t/2)·I or (2+tI)/2? The Rexpr_decomp has digamma (s₀/2) with s₀ = 2 + t·I. So s₀/2 = (2 + t·I)/2. The bridge (2+t·I)/2 = 1 + (t/2)·I: by ring? (2 + t·I)/2 = 1 + (t·I)/2 = 1 + (t/2)·I: `by ring` should handle (field, char 0): (2 + t·I)/2 = 1 + (t/2)·I ✓ ring. Hmm — t·I/2 vs (t/2)·I: ring normalizes ✓. Let me write the full piece 6 now. Components: ```lean theorem digamma_diff_le {t : ℝ} (ht : 10 ≤ t) {s : ℂ} (hσlo : -5 / 2 ≤ s.re) (hσhi : s.re ≤ 3) (him : s.im = t) : ‖(Complex.digamma (s / 2) - Complex.digamma ((2 + t * Complex.I) / 2)) / 2‖ ≤ 6 / t := by have ht0 : (0 : ℝ) < t := by linarith have ht2 : (5 : ℝ) ≤ t / 2 := by linarith -- w := s/2, w₀ := (2+tI)/2 = 1 + (t/2)I set w : ℂ := s / 2 with hw set w₀ : ℂ := (2 + t * Complex.I) / 2 with hw₀ have hw₀eq : w₀ = 1 + (t / 2) * Complex.I := by rw [hw₀]; ring have hwim : w.im = t / 2 := by rw [hw]; simp [him] have hw₀im : w₀.im = t / 2 := by rw [hw₀eq]; simp have hwre : w.re = s.re / 2 := by rw [hw]; simp have hw₀re : w₀.re = 1 := by rw [hw₀eq]; simp have himw : w.im ≠ 0 := by rw [hwim]; positivity? (t/2 ≥ 5 > 0: linarith) -- (i) the recurrence: ψ(w) = ψ(w+2) − w⁻¹ − (w+1)⁻¹ have hrec : Complex.digamma (w + 2) = Complex.digamma w + (w⁻¹ + (w + 1)⁻¹) := by have h := digamma_add_natCast himw 2 rw [Finset.sum_range_succ, Finset.sum_range_succ, Finset.sum_range_zero] at h -- h : ψ(w+2) = ψ(w) + ((w+0)⁻¹ + (w+1)⁻¹) — cast forms convert h using 1 · ring_nf ... ``` Hmm — digamma_add_natCast {w : ℂ} (hw : w.im ≠ 0) (n : ℕ) : digamma (w + n) = digamma w + ∑ j ∈ range n, (w + (j:ℂ))⁻¹. With n = 2: digamma (w + (2:ℕ)) = digamma w + ((w+0)⁻¹ + (w+1)⁻¹): the sum over range 2: Finset.sum_range_two? or sum_range_succ twice from range 0: ∑ j ∈ range 2, f j = f 0 + f 1: `Finset.sum_range_two`? hmm. The sum: range 2: sum_range_succ (range 1): ∑ range 1 + f 1 = (range 0 + f 0) + f 1 = 0 + f 0 + f 1. With f j = (w + (j:ℂ))⁻¹: f 0 = (w + 0)⁻¹ = w⁻¹ (Nat.cast_zero, add_zero); f 1 = (w+1)⁻¹ (Nat.cast_one). So: ```lean have h := digamma_add_natCast himw 2 rw [show w + ((2:ℕ):ℂ) = w + 2 by push_cast; ring] at h -- hmm the cast (↑2:ℂ) vs (2:ℂ) rw [Finset.sum_range_succ, Finset.sum_range_succ, Finset.sum_range_zero] at h simp only [Nat.cast_zero, add_zero, Nat.cast_one] at h -- h : ψ(w+2) = ψ(w) + (0 + w⁻¹ + (w+1)⁻¹) linarith? no — ring_nf at h; exact? ``` The sum form: ((0 + w⁻¹) + (w+1)⁻¹) — with the leading 0 from sum_range_zero: h : ψ(w+2) = ψ(w) + (0 + w⁻¹ + (w+1)⁻¹)-ish — normalize: `simp only [Nat.cast_zero, add_zero, Nat.cast_one, zero_add] at h` gives h : ψ(w+2) = ψ(w) + (w⁻¹ + (w+1)⁻¹) ✓. The cast: digamma_add_natCast's statement has w + ↑n with n : ℕ — (2:ℕ) cast to ℂ: w + (↑(2:ℕ)) — I want w + 2: push_cast or the show bridge: rw [show w + ((2:ℕ):ℂ) = w + 2 by push_cast; ring] at h ✓. - (ii) Stirling at v := w + 2: re v = σ/2 + 2 ≥ 3/4 > 0: ```lean have hvre : (0 : ℝ) < (w + 2).re := by rw [Complex.add_re]; simp [hwre]; linarith [hσlo] ``` (w+2).re = w.re + 2 = s.re/2 + 2 ≥ −5/4 + 2 = 3/4 > 0 ✓ — via simp [Complex.add_re, hwre] then linarith [hσlo]: (w+2).re = w.re + (2:ℂ).re = s.re/2 + 2 ✓. hvim : (w+2).im = t/2: simp [Complex.add_im, hwim] ✓. ```lean have hStir1 := Zeta23.GammaFacts.digamma_stirling (w := w + 2) hvre (by rw [hvim... |im| = t/2 ≥ 5 ≥ 1/2] ...) ``` digamma_stirling (hw : 0 < w.re) (ht : 1/2 ≤ |w.im|) : ‖digamma w − log w + (1/2)/w‖ ≤ 3/w.im². The namespace: Zeta23.GammaFacts.digamma_stirling? or it's open Zeta23... the file opens Zeta23 — the lemma is at Zeta23/GammaFacts/StirlingVert.lean:483 — inside `namespace`? Let me check how LiReflect references it: LiReflect used "StirlingVert digamma_stirling" per the journal. Let me grep for the usage. - (iii) Stirling at w₀: re = 1 > 0 ✓, |im| = t/2 ≥ 1/2 ✓. - (iv) the log difference bound (the segment FTC). - (v) assembly. Let me check the digamma_stirling usage form in LiReflect.
The patterns are all confirmed. Checking how `digamma_stirling` is referenced in LiReflect, then writing piece 6.
tool: Bash
input
{
  "command": "cd D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1 && grep -rn \"digamma_stirling\" *.lean | head -4; grep -n \"norm_integral_le_of_norm_le_const\\|norm_integral_le\" LiReflect.lean | head -4",
  "description": "Find digamma_stirling usage and integral norm bound forms"
}
#1754 assistant 2026-08-24 11:13:39.852 UTC · 3816→4347 tok open ⤢
thinking (10647 chars)
- `StirlingVert.digamma_stirling hwre (by rw [hvim]; linarith [...])` — the usage pattern ✓. - `intervalIntegral.norm_integral_le_integral_norm (h : 0 ≤ a) : ‖∫ x in a..b, f x‖ ≤ ∫ x in a..b, ‖f x‖`? — from LiReflect:834 usage: `(intervalIntegral.norm_integral_le_integral_norm (Nat.cast_nonneg n)).trans ?_` — so norm_integral_le_integral_norm takes the a ≤ b nonneg proof and gives ‖∫ a..b f‖ ≤ ∫ a..b ‖f‖. Then I bound ∫₀¹ ‖δ·z⁻¹‖ ≤ (5/t)·1 by the constant: intervalIntegral.integral_of_le? or since ‖δ·z⁻¹‖ ≤ 5/t pointwise: `intervalIntegral.integral_mono_on`? hmm — ∫₀¹ (5/t) dx = 5/t: `intervalIntegral.integral_const`... the comparison: ∫₀¹ ‖f‖ ≤ ∫₀¹ (5/t) = 5/t: via intervalIntegral.integral_mono_on (h : ∀ x ∈ uIoc, ‖f x‖ ≤ 5/t)? `intervalIntegral.integral_mono_on (hab : a ≤ b) (hf : IntervalIntegrable...) (hg...) (h : ∀ x ∈ uIoc a b, f x ≤ g x) : ∫ a..b f ≤ ∫ a..b g` ✓ standard-ish. Now write piece 6. Full text: ```lean /-! ## 7. Piece 6: the digamma difference -/ /-- The log difference along the constant-imaginary segment: for s = σ + it with σ ∈ [−5/2, 3] and t ≥ 10, with w = s/2 and w₀ = 1 + (t/2)·I: ‖log (w + 2) − log w₀‖ ≤ 5/t. The segment FTC: every point of [w₀, w+2] has re ≥ 3/4 (slit-plane) and im = t/2. -/ theorem log_diff_le {t : ℝ} (ht : 10 ≤ t) {s : ℂ} (hσlo : -5 / 2 ≤ s.re) (hσhi : s.re ≤ 3) (him : s.im = t) : ‖Complex.log (s / 2 + 2) - Complex.log (1 + (t / 2) * Complex.I)‖ ≤ 5 / t := by have ht0 : (0 : ℝ) < t := by linarith set w : ℂ := s / 2 with hw set w₀ : ℂ := 1 + (t / 2) * Complex.I with hw₀ have hwim : w.im = t / 2 := by rw [hw]; simp [him] have hw₀im : w₀.im = t / 2 := by rw [hw₀]; simp have hwre : w.re = s.re / 2 := by rw [hw]; simp have hw₀re : w₀.re = 1 := by rw [hw₀]; simp -- the difference δ = w + 2 − w₀ is real, = σ/2 + 1 set δ : ℂ := w + 2 - w₀ with hδ have hδeq : δ = ((s.re / 2 + 1 : ℝ) : ℂ) := by rw [hδ, hw₀] rw [Complex.ext_iff] constructor · simp [hwre] -- re: w.re + 2 − 1 = s.re/2 + 1 ... ``` Hmm — δ.re: (w + 2 − w₀).re = w.re + 2 − 1 = s.re/2 + 1 ✓ (simp [Complex.sub_re, Complex.add_re, hwre] — the (2:ℂ).re = 2, (1:ℂ).re = 1, ((t/2)·I).re = 0). δ.im: = w.im + 0 − t/2 = 0 ✓. So δ = ((s.re/2 + 1 : ℝ):ℂ) via Complex.ext_iff: the RHS's re: ((x:ℝ):ℂ).re = x (ofReal_re) ✓ and im = 0 ✓. The simp calls need the re/im computation lemmas: `by simp [Complex.sub_re, Complex.add_re, hwre, hw₀re]`-ish. Let me write: ```lean have hδeq : δ = ((s.re / 2 + 1 : ℝ) : ℂ) := by rw [Complex.ext_iff] constructor · rw [hδ] simp [Complex.sub_re, Complex.add_re, hwre, hw₀re, Complex.ofReal_re] ring? ``` Hmm — after simp the goal is an arithmetic identity s.re/2 + 2 − 1 = s.re/2 + 1 — simp might leave (s.re/2 + 2 − 1) = (s.re/2+1) — close by linarith? or ring_nf. Let me: `· rw [hδ]; simp [Complex.sub_re, Complex.add_re, hwre, hw₀re]; ring_nf`... risky forms. Alternative robust: compute δ.re and δ.im separately as haves then ext: ```lean have hδre : δ.re = s.re / 2 + 1 := by rw [hδ] simp [Complex.sub_re, Complex.add_re, hwre, hw₀re] ring_nf -- hmm — after simp gives w.re + 2 − 1 = ... ``` The simp should evaluate: (w + 2 − w₀).re = w.re + (2:ℂ).re − w₀.re = w.re + 2 − 1 — with rw [hwre] — hmm the simp [hwre] rewrites w.re → s.re/2 ✓. So δ.re = s.re/2 + 2 − 1 = s.re/2 + 1 — the final arithmetic: after simp the goal might be `s.re / 2 + 2 - 1 = s.re / 2 + 1` — linarith/ring closes. Ugh — the exact simp behavior is uncertain. Let me use a more explicit approach: ```lean have hδre : δ.re = s.re / 2 + 1 := by rw [hδ, Complex.sub_re, Complex.add_re, hwre, hw₀re] simp ring_nf ``` Hmm `(2:ℂ).re`: simp knows (by `Complex.ofNat_re`? or ofReal). Plain `simp` after the rw should evaluate (2:ℂ).re = 2, (1:ℂ).re... and then the goal `s.re / 2 + 2 - 1 = s.re / 2 + 1` — simp doesn't close arithmetic — hmm. The issue: rw [Complex.sub_re] etc transform the LHS of the equation (δ.re = ...): rw at the goal's LHS: (w + 2 − w₀).re → w.re + 2.re − w₀.re — wait sub_re: (a − b).re = a.re − b.re; add_re: (a+b).re = a.re + b.re. So (w+2−w₀).re = (w+2).re − w₀.re = (w.re + (2:ℂ).re) − w₀.re. rw [hwre]: w.re → s.re/2; hw₀re: w₀.re → 1. Goal: s.re/2 + (2:ℂ).re − 1 = s.re/2 + 1. simp evaluates (2:ℂ).re = 2 (via Complex.ofNat_re or ofReal_re — simp handles ✓). Then s.re/2 + 2 − 1 = s.re/2 + 1: `by norm_num`? or linarith. Let me write the whole thing with explicit terminal: ```lean have hδre : δ.re = s.re / 2 + 1 := by rw [hδ, Complex.sub_re, Complex.add_re, hwre, hw₀re] simp ring_nf have hδim : δ.im = 0 := by rw [hδ, Complex.sub_im, Complex.add_im, hwim, hw₀im] simp ring_nf ``` The `simp` after the rws evaluates the OfNat re/im; ring_nf closes the arithmetic. Hmm — but if simp CLOSES the goal (via deciding), the ring_nf errors "no goals". Risk both ways. Alternative bulletproof: ```lean have hδre : δ.re = s.re / 2 + 1 := by rw [hδ, Complex.sub_re, Complex.add_re, hwre, hw₀re, Complex.ofNat_re] -- hmm (2:ℂ).re lemma name ring_nf ``` The (2:ℂ).re: the term (2:ℂ) is OfNat; its .re: `Complex.ofNat_re`? or it might just compute via `Complex.re_ofNat`? — risky. The safest known pattern from the codebase: `simp` handles re/im of literals (used all over: `by simp [him]` for (s/2).im etc.). For the arithmetic close, use linarith instead of ring_nf after a NON-closing simp... but if simp closes it, linarith errors. You know what — the cleanest: prove δre via a single `simp [...]` + `ring_nf` won't both be needed... Let me look at how the codebase handles e.g. (w + 2).re computations. From LiDigammaLeft:783's hvre — let me check that pattern. Actually from my piece-2 work in this file: `hre : ((2 + t * Complex.I) - ρ.1).re = 2 - ρ.1.re := by simp` — a bare `simp` closed a similar re-computation ✓. So `simp` handles (2:ℂ).re etc. Then the arithmetic: `simp` might fully close `s.re/2 + 2 − 1 = s.re/2 + 1`?? — no, simp doesn't do arithmetic. Plan: `by simp; ring_nf`?? — if simp closes: "no goals" error for ring_nf. Ugh. The bulletproof pattern used in this codebase (session-033 gotcha): "congrArg Complex.re + simp is the robust cast-bridge". And for the arithmetic: `by simp; ring_nf` risks no-goals; `by simp` alone might leave the arithmetic. Let me use: `by simp only [...]; ring_nf`: simp only with specific lemmas NEVER closes the arithmetic goal (only the listed rewrites), leaving it for ring_nf: ```lean have hδre : δ.re = s.re / 2 + 1 := by rw [hδ] simp only [Complex.sub_re, Complex.add_re, hwre, hw₀re, Complex.ofNat_re, Complex.ofReal_re] ring ``` Hmm — the (2:ℂ).re — is it Complex.ofNat_re or does it need `(2:ℂ)` as OfNat: simp only [Complex.ofNat_re]? Is there such a lemma? There's `Complex.ofNat_re : (OfNat.ofNat n : ℂ).re = ...`? Hmm — maybe not. The (2:ℂ).re might need `(2:ℂ) = ((2:ℝ):ℂ)` cast + Complex.ofReal_re. Let me use: ```lean have hδre : δ.re = s.re / 2 + 1 := by have h2re : (2 : ℂ).re = 2 := by simp have h1re : (1 : ℂ).re = 1 := by simp -- not needed if w₀re given rw [hδ, Complex.sub_re, Complex.add_re, hwre, hw₀re, h2re] ring ``` `have h2re : (2:ℂ).re = 2 := by simp` — simp should evaluate (2:ℂ).re (the OfNat re — simp knows via Complex.ofNat_re or norm_cast simp set ✓ plausible — my piece-2 used `by simp` for a similar re computation and it worked ✓). Then the goal: s.re/2 + 2 − 1 = s.re/2 + 1: ring ✓. This is getting long. Given it's 2:25 AM and piece 6 is a ~250-line build, let me write it in full carefully and compile-iterate. Actually — let me reconsider the structure to minimize the re/im friction: instead of δ as a complex number with re/im computations, note the segment points: z(y) = w₀ + (y:ℂ)·δ — with δ real-cast: z(y) = w₀ + ((y·(s.re/2+1) : ℝ):ℂ): re = 1 + y·(s.re/2+1), im = t/2. Let me define things in terms of the real scalar: c := s.re/2 + 1 (real), z(y) := w₀ + ((y·c : ℝ):ℂ). Then: - z(y).re = 1 + y·c; z(y).im = t/2. - w + 2 = w₀ + ((c:ℝ):ℂ) (since w + 2 = (σ/2 + 2) + (t/2)I and w₀ + c = (1 + c) + (t/2)I = (σ/2 + 2) + (t/2)I ✓). - The FTC: g(y) := log(z(y)); HasDerivAt g (z(y)⁻¹ · c) y (chain rule: z(y) = w₀ + (y·c:ℂ) — d/dy = c (real cast): via hasDerivAt_log.comp with the affine map y ↦ w₀ + y·c — the 5d pattern: ((hasDerivAt_id' (x:ℂ)).const_add w) had the form w + y; mine: w₀ + (y:ℂ)·((c:ℝ):ℂ) = w₀ + ((y:ℂ)·c') with c' := ((c:ℝ):ℂ): the deriv is c': (hasDerivAt_id' (x:ℂ)).const_mul c' |>.const_add w₀? — hmm const_mul: HasDerivAt (fun z => z * c') (1 * c') hmm — (hasDerivAt_id' z₀).const_mul c' : HasDerivAt (fun z => z * c') (1 * c' = c') z₀ ✓ then .const_add w₀ : HasDerivAt (fun z => w₀ + z*c') (c') z₀ ✓ then comp with hasDerivAt_log: HasDerivAt (fun z => log (w₀ + z*c')) ((w₀+z₀*c')⁻¹ * c') z₀ ✓ then .comp_ofReal: HasDerivAt (fun y : ℝ => log (w₀ + (y:ℂ)*c')) (((w₀+(x:ℂ)*c')⁻¹ * c')) x ✓. - The integral: ∫₀¹ c'·z(y)⁻¹ = g 1 − g 0 = log(w₀ + c') − log w₀ = log(w+2) − log w₀ ✓ (w₀ + 1·c' = w₀ + c' = w+2 — via the h bridge w+2 = w₀ + c'). - The norm: ‖c'·z(y)⁻¹‖ = |c|·‖z(y)‖⁻¹ ≤ (5/2)·(2/t) = 5/t: |c| = |σ/2 + 1| ≤ 5/2 (σ/2+1 ∈ [−1/4, 5/2] ⟹ |·| ≤ 5/2 ✓); ‖z(y)‖ ≥ |im z(y)| = t/2 ✓. - ∫₀¹ 5/t = 5/t: intervalIntegral.integral_const. The slit-plane for z(y): re = 1 + yc ≥ 1 − |c|·... c ≥ −1/4: re ≥ 1 + 1·(−1/4)·... y ∈ [0,1]: y·c ≥ min(0, c) = c (if c < 0) ≥ −1/4: re ≥ 1 − 1/4 = 3/4 > 0 ✓. mem_slitPlane_iff: 0 < re ∨ im ≠ 0 — left: re > 0 ✓ (or right: im = t/2 ≠ 0 ✓ — use the RIGHT case, simpler: im z(y) = t/2 ≠ 0 ✓ always!). OK let me write the whole piece 6. Also note: `intervalIntegral.integral_eq_sub_of_hasDerivAt hanti hconti : ∫ x in a..b, f' x = f b − f a` — the argument order from 5d: hanti (the ∀ x ∈ uIcc, HasDerivAt f (f' x) x) and hconti (IntervalIntegrable f'). ✓ And the norm bound: ‖∫₀¹ f'‖ ≤ ∫₀¹ ‖f'‖ via intervalIntegral.norm_integral_le_integral_norm (a ≤ b proof? from the 5d usage: `(intervalIntegral.norm_integral_le_integral_norm (Nat.cast_nonneg n)).trans` — takes (h : 0 ≤ a)-ish... the signature: norm_integral_le_integral_norm (hab : a ≤ b) : ‖∫ x in a..b, f x‖ ≤ ∫ x in a..b, ‖f x‖ — the 5d usage passed (Nat.cast_nonneg n) which is 0 ≤ (n:ℝ) — so the arg is a ≤ b with a = 0: 0 ≤ (n:ℝ) ✓ so signature (hab : a ≤ b). For me: (by norm_num : (0:ℝ) ≤ 1). Then ∫₀¹ ‖f'‖ ≤ ∫₀¹ (5/t) via intervalIntegral.integral_mono_on (h01 : 0 ≤ 1) (hf int) (hg int) (h : ∀ x ∈ uIoc 0 1, ‖f' x‖ ≤ 5/t)? signature check at build. Or simpler: bound via intervalIntegral.norm_integral_le_of_norm_le_const: `intervalIntegral.norm_integral_le_of_norm_le_const (hab : a ≤ b) (h : ∀ x ∈ uIoc a b, ‖f x‖ ≤ C) : ‖∫ x in a..b, f x‖ ≤ C * (b − a)`? Let me check the exact form.
Checking the integral norm-bound lemma name, then writing piece 6 in full.
tool: Bash
input
{
  "command": "M=D:/Python/Quantum/zeta-23-lean/.lake/packages/mathlib/Mathlib; grep -rn \"theorem norm_integral_le_of_norm_le_const\\|norm_integral_le_of_norm_le_const\" $M/MeasureTheory/Integral/IntervalIntegral*.lean $M/Analysis/**/*.lean 2>/dev/null | head -3; grep -rn \"norm_integral_le_of_norm_le_const\" D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1/*.lean | head -3",
  "description": "Find norm_integral_le_of_norm_le_const"
}
#1755 assistant 2026-08-24 11:14:43.340 UTC · 688→1409 tok open ⤢
thinking (3140 chars)
`intervalIntegral.norm_integral_le_of_norm_le_const (h : ∀ x ∈ Ι a b, ‖f x‖ ≤ C) : ‖∫ x in a..b, f x‖ ≤ C * |b − a|` ✓ (Ι = uIoc). Now writing piece 6 in full. Let me append §7 to LiTightR.lean (before `end NguyenRH1`). The current file ends with §7 (pieces 4/5) then `end NguyenRH1` / `end`. I'll insert piece 6 as a new §8 before the ends. Full piece-6 text: ```lean /-! ## 8. Piece 6: the digamma difference -/ /-- The log difference along the constant-imaginary segment: for s = σ + it with σ ∈ [−5/2, 3] and t ≥ 10, with w = s/2 and w₀ = 1 + (t/2)·I: ‖log (w + 2) − log w₀‖ ≤ 5/t. The segment FTC: every point of the segment has im = t/2 (so norm ≥ t/2) and the real scalar difference c = σ/2 + 1 ∈ [−1/4, 5/2]. -/ theorem log_diff_le {t : ℝ} (ht : 10 ≤ t) {s : ℂ} (hσlo : -5 / 2 ≤ s.re) (hσhi : s.re ≤ 3) (him : s.im = t) : ‖Complex.log (s / 2 + 2) - Complex.log (1 + (t / 2) * Complex.I)‖ ≤ 5 / t := by have ht0 : (0 : ℝ) < t := by linarith set w₀ : ℂ := 1 + (t / 2) * Complex.I with hw₀ set c : ℝ := s.re / 2 + 1 with hc set c' : ℂ := (c : ℂ) with hc' have hw₀im : w₀.im = t / 2 := by rw [hw₀]; simp have hc_le : c ≤ 5 / 2 := by rw [hc]; linarith [hσhi] have hc_ge : -1 / 4 ≤ c := by rw [hc]; linarith [hσlo] have hcnorm : |c| ≤ 5 / 2 := by rw [abs_le]; constructor <;> linarith -- the segment point z(y) = w₀ + (y·c : ℂ), y ∈ [0,1] set z : ℝ → ℂ := fun y => w₀ + ((y * c : ℝ) : ℂ) with hz have hzim : ∀ y : ℝ, (z y).im = t / 2 := by intro y rw [hz, hw₀] simp [Complex.add_im, Complex.ofReal_im] have hzre : ∀ y : ℝ, (z y).re = 1 + y * c := by intro y rw [hz, hw₀] simp [Complex.add_re, Complex.ofReal_re] have hznorm : ∀ y : ℝ, t / 2 ≤ ‖z y‖ := by intro y have h := abs_im_le_norm (z y) rw [hzim y, abs_of_nonneg (by linarith : (0:ℝ) ≤ t / 2)] at h exact h -- w₀ + c' = s/2 + 2 have htarget : w₀ + c' = s / 2 + 2 := by rw [hw₀, hc', hc] rw [Complex.ext_iff] constructor · simp [him] -- re: 1 + c vs s.re/2 + 2: c = s.re/2+1 ⟹ 1 + c = s.re/2 + 2 ... ``` Hmm — the re/im of (s/2 + 2): re = s.re/2 + 2, im = t/2. And w₀ + c': re = 1 + c = 1 + (s.re/2+1) = s.re/2 + 2 ✓; im = t/2 + 0 ✓. The simp forms: `simp [Complex.add_re, Complex.ofReal_re, Complex.div_re...]` — (s/2).re: div_re: (s/2).re = s.re/2 — simp has Complex.div_re? or the division by 2 — (s/2) = s·(1/2): hmm. Let me compute the re/im of s/2: s/2 = s·(2⁻¹): re = s.re·(1/2) — the simp lemma: Complex.div_re : (a/b).re = a.re/b.re − a.im/b.im? no — for real denominator: (s/2).re = s.re/2 — simp might do it via `Complex.div_re` (which is (a/b).re = (a.re*b.re + a.im*b.im)/(a.re²+b.im²)-ish — ugly). Earlier in this file: `hwre : w.re = s.re / 2 := by rw [hw]; simp` — wait that's in my planned piece 6 — in the WORKING piece-2/4-5 code, `hre : ((2 + t * Complex.I) - ρ.1).re = 2 - ρ.1.re := by simp` compiled ✓ — so simp handles re-computations including (s/2).re? Uncertain about (s/2).re. Let me test compile and adjust. This is getting long — let me just write the whole piece 6 and iterate on the build. Let me write it now (append §8 before `end NguyenRH1`).
All patterns confirmed. Writing piece 6 (the digamma difference) into LiTightR.lean.
tool: Read ok
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean",
  "offset": 495,
  "limit": 25
}
result 2026-08-24 11:14:43Z → 2026-08-29 00:19:23Z
{
  "type": "text",
  "file": {
    "filePath": "C:\\Users\\lucky\\AppData\\Local\\Programs\\Python\\Python314\\Lib\\wsgiref\\handlers.py",
    "content": "        raise NotImplementedError\n\n    def _flush(self):\n        \"\"\"Override in subclass to force sending of recent '_write()' calls\n\n        It's okay if this method is a no-op (i.e., if '_write()' actually\n        sends the data.\n        \"\"\"\n        raise NotImplementedError\n\n    def get_stdin(self):\n        \"\"\"Override in subclass to return suitable 'wsgi.input'\"\"\"\n        raise NotImplementedError\n\n    def get_stderr(self):\n        \"\"\"Override in subclass to return suitable 'wsgi.errors'\"\"\"\n        raise NotImplementedError\n\n    def add_cgi_vars(self):\n        \"\"\"Override in subclass to insert CGI variables in 'self.environ'\"\"\"\n        raise NotImplementedError\n\n\nclass SimpleHandler(BaseHandler):\n    \"\"\"Handler that's just initialized with streams, environment, etc.\n\n    This handler subclass is intended for synchronous HTTP/1.0 origin servers,\n    and handles sending the entire response output, given the correct inputs.\n\n    Usage::\n\n        handler = SimpleHandler(\n            inp,out,err,env, multithread=False, multiprocess=True\n        )\n        handler.run(app)\"\"\"\n\n    def __init__(self,stdin,stdout,stderr,environ,\n        multithread=True, multiprocess=False\n    ):\n        self.stdin = stdin\n        self.stdout = stdout\n        self.stderr = stderr\n        self.base_env = environ\n        self.wsgi_multithread = multithread\n        self.wsgi_multiprocess = multiprocess\n\n    def get_stdin(self):\n        return self.stdin\n\n    def get_stderr(self):\n        return self.stderr\n\n    def add_cgi_vars(self):\n        self.environ.update(self.base_env)\n\n    def _write(self,data):\n        result = self.stdout.write(data)\n        if result is None or result == len(data):\n            return\n        from warnings import warn\n        warn(\"SimpleHandler.stdout.write() should not do partial writes\",\n            DeprecationWarning)\n        while data := data[result:]:\n            result = self.stdout.write(data)\n",
    "numLines": 65,
    "startLine": 418,
    "totalLines": 575
  }
}
#1756 assistant 2026-08-24 11:25:03.135 UTC · 1882→19321 tok open ⤢
thinking (20981 chars)
I accidentally wrote `sorry` placeholders into the file (I was drafting the structure and left them). I must NOT leave sorries — let me complete the hbound proof and the digamma_diff_le proof properly before compiling. Let me think through the remaining pieces: **hbound**: ‖(z y)⁻¹ * ((c:ℝ):ℂ)‖ ≤ 5/t. ‖(z y)⁻¹ * ((c:ℝ):ℂ)‖ = ‖(z y)⁻¹‖ * ‖((c:ℝ):ℂ)‖ = ‖z y‖⁻¹ * |c| (norm_inv, and ‖((c:ℝ):ℂ)‖ = |c| via Complex.norm_real). ≤ (t/2)⁻¹ · (5/2) = (2/t)·(5/2) = 5/t: via mul_le_mul (inv_le: ‖z y‖⁻¹ ≤ (t/2)⁻¹ from hznorm: t/2 ≤ ‖z y‖ ⟹ ‖z y‖⁻¹ ≤ (t/2)⁻¹ via inv_le_inv₀ (norm_pos (z y ≠ 0 from hznorm > 0) (t/2 > 0)) — inv_le_inv₀ (ha : 0 < a) (hb : 0 < b) : a⁻¹ ≤ b⁻¹ ↔ b ≤ a — hmm direction: ‖z y‖⁻¹ ≤ (t/2)⁻¹ ⟺ t/2 ≤ ‖z y‖ ✓ hznorm. So: ```lean have hbound : ∀ y ∈ Set.uIoc (0 : ℝ) 1, ‖((z y)⁻¹) * ((c : ℝ) : ℂ)‖ ≤ 5 / t := by intro y _ have hzy : (0 : ℝ) < ‖z y‖ := by have h := hznorm y positivity have h1 : ‖((z y)⁻¹) * ((c : ℝ) : ℂ)‖ = ‖z y‖⁻¹ * |c| := by rw [norm_mul, norm_inv] rw [show ((c : ℝ) : ℂ) = (((|c| : ℝ)) : ℂ) ...] -- no ``` Hmm — ‖((c:ℝ):ℂ)‖ = |c|: `Complex.norm_real : ‖(x : ℂ)‖ = |x|`? — wait Complex.norm_real (x : ℝ) : ‖(x : ℂ)‖ = |x|? Actually it's `Complex.norm_real (x : ℝ) : ‖(x : ℂ)‖ = ‖x‖`? — hmm: `Complex.norm_real : ‖(x : ℂ)‖ = |x|`? Let me recall: `Complex.norm_real (x : ℝ) : ‖(x : ℂ)‖ = |x|`? — hmm, actually I believe `Complex.norm_real (x : ℝ) : ‖(x : ℂ)‖ = |x|`? — wait, actually in Mathlib it's `Complex.norm_real (x : ℝ) : ‖(↑x : ℂ)‖ = |x|`? Hmm — I've seen `Complex.norm_real : ‖(x : ℂ)‖ = |x|`? hmm. Actually: `Complex.norm_real (x : ℝ) : ‖(x : ℂ)‖ = |x|` hmm — hold on, actually it's stated as `Complex.norm_real (x : ℝ) : ‖(x : ℂ)‖ = |x|`? — hmm I recall `Complex.norm_real : ‖(x : ℂ)‖ = |x|`? Let me just say: the codebase used `Complex.norm_real` at line 3866 (session-033 Fexpr): `rw [show (2 : ℂ) = ((2 : ℝ) : ℂ) by push_cast; ring, Complex.norm_real]; norm_num` — so Complex.norm_real : ‖((x:ℝ):ℂ)‖ = |x| ✓ and then abs handling. So: ```lean have h1 : ‖((z y)⁻¹) * ((c : ℝ) : ℂ)‖ = ‖z y‖⁻¹ * |c| := by rw [norm_mul, norm_inv, Complex.norm_real] ``` Wait — the term is ((c : ℝ) : ℂ) — the Real-cast ✓ norm_real applies ✓. ```lean rw [h1] have h2 : ‖z y‖⁻¹ ≤ (t / 2)⁻¹ := by rw [inv_le_inv₀ hzy (by positivity)] exact hznorm y calc ‖z y‖⁻¹ * |c| ≤ (t / 2)⁻¹ * (5 / 2) := mul_le_mul h2 hcnorm (abs_nonneg _) (by positivity) _ = 5 / t := by field_simp; ring ``` Hmm — inv_le_inv₀ signature: `inv_le_inv₀ (ha : 0 < a) (hb : 0 < b) : a⁻¹ ≤ b⁻¹ ↔ b ≤ a` ✓. So h2 : ‖z y‖⁻¹ ≤ (t/2)⁻¹ via (inv_le_inv₀ hzy ht2pos).mpr (hznorm y) — hznorm : t/2 ≤ ‖z y‖ ✓ matches b ≤ a with a := ‖z y‖, b := t/2: a⁻¹ ≤ b⁻¹ ⟺ b ≤ a ✓. mul_le_mul (h2 : ‖z y‖⁻¹ ≤ (t/2)⁻¹) (hcnorm : |c| ≤ 5/2) (0 ≤ |c|) (0 ≤ (t/2)⁻¹): gives ‖z y‖⁻¹·|c| ≤ (t/2)⁻¹·(5/2) ✓. (t/2)⁻¹·(5/2) = 5/t: field_simp; ring — hmm: (t/2)⁻¹ = 2/t: (2/t)·(5/2) = 5/t ✓ field_simp with t ≠ 0 (ht0.ne') in context? field_simp [ht0.ne'] then ring. Then the final: ‖∫₀¹ ...‖ ≤ (5/t)·|1 − 0| = 5/t via intervalIntegral.norm_integral_le_of_norm_le_const hbound : ‖∫ y in 0..1, f y‖ ≤ (5/t)·|1−0| = 5/t ✓: ```lean calc ‖∫ y in (0:ℝ)..(1:ℝ), ((z y)⁻¹) * ((c : ℝ) : ℂ)‖ ≤ (5 / t) * |1 - 0| := intervalIntegral.norm_integral_le_of_norm_le_const hbound _ = 5 / t := by norm_num [abs_one] -- |1 − 0| = 1: abs_of... |1-0| = 1: rw [abs_of_nonneg (by norm_num)]; norm_num ``` Hmm — `intervalIntegral.norm_integral_le_of_norm_le_const (h : ∀ x ∈ Ι a b, ‖f x‖ ≤ C) : ‖∫ x in a..b, f‖ ≤ C * |b − a|` — the Ι a b is uIoc — my hbound is over Set.uIoc 0 1 — Ι = uIoc ✓ same thing (Set.uIoc = Ι? Ι a b := uIoc a b ∪ uIoc b a — intervaloc). The lemma's h is over Ι a b = uIoc a b ∪ uIoc b a. My hbound : ∀ y ∈ Set.uIoc 0 1 — since 0 ≤ 1, Ι 0 1 = uIoc 0 1 ✓ but syntactically Ι vs uIoc differ — `Set.uIoc_eq...`? Ι is notation for Set.uIoc?? No — Ι a b is `Set.uIoc a b ∪ Set.uIoc b a`? No: Ι a b = uIoc (min a b) (max a b). Hmm — `Set.uIoc` vs `Ι`: Ι a b := Set.uIoc (min a b) (max a b). For a ≤ b: Ι a b = uIoc a b (min_eq_left, max_eq_right). The membership conversion: hbound : ∀ y ∈ Set.uIoc 0 1, ... and I need ∀ y ∈ Ι 0 1: rw [show Ι (0:ℝ) 1 = Set.uIoc 0 1 from by rw [Set.uIoc...]]... ugh. Actually — from LiReflect's usage and HasPrimitives.lean:245: `intervalIntegral.norm_integral_le_of_norm_le_const hw` where hw presumably over Ι. Let me just provide the h over Ι: intro y hy — hy : y ∈ Ι 0 1 — convert to uIoc membership: `Set.mem_uIoc`... the Ι is `Set.uIoc a b ∪ Set.uIoc b a`?? Actually Ι a b is DEFINED as Set.uIoc (min...) hmm no: in Mathlib, `Ι a b := Set.uIoc a b ∪ Set.uIoc b a`? Let me recall — Ι is the "unordered interval": `Set.Ι a b := uIoc (min a b) (max a b)`? and there's `Set.uIoc_eq_Ι`? Hmm — actually `Ι a b = uIoc a b ∪ uIoc b a`?? No wait: I recall `Set.Ι a b := uIoc (min a b) (max a b)` and lemmas `Set.mem_Ι`... This is a rabbit hole; simplest: state hbound over `Set.Ι (0:ℝ) 1` directly and convert membership: hy : y ∈ Ι 0 1 — get bounds: y ∈ (0, 1]: `Set.mem_Ι`? or since my proof only uses hznorm (true for ALL y), the membership is unused! Look at hbound's proof: intro y _ — the membership is UNUSED (the bound holds for all y). So I can state hbound over ANY set: `∀ y ∈ Set.Ι (0:ℝ) 1, ...` with intro y _ and never use the membership ✓. Let me state it over Ι directly. The name: `Set.Ι` — in Lean: `Set.Ι` or `uIoc`? The lemma statement shows `Ι a b` — that's `Set.Ι`. In my code: `Set.Ι (0:ℝ) 1`? The Ι is notation for `Set.Ι`... Let me just use `Set.uIoc` and hope Ι = uIoc is defeq — NO. Let me check: from HasPrimitives usage: `intervalIntegral.norm_integral_le_of_norm_le_const hw` — let me look at hw's statement there to see the set form. Actually — the simplest robust: use the uIoc form and if the set mismatch bites, bridge via `Set.uIoc_of_le (by norm_num : (0:ℝ) ≤ 1)`? There's `Set.uIoc_of_le (h : a ≤ b) : uIoc a b = Ι a b`? or the reverse `Set.Ι_of_le`: `Set.Ι_of_le (h : a ≤ b) : Ι a b = uIoc a b`? I recall `Set.Ι_of_le (h : a ≤ b) : Ι a b = uIoc a b` ✓ plausible. So: ```lean have hbound : ∀ y ∈ Set.Ι (0 : ℝ) 1, ‖((z y)⁻¹) * ((c : ℝ) : ℂ)‖ ≤ 5 / t := by intro y _ ... ``` with the membership unused ✓ (works regardless of Ι's definition). **digamma_diff_le**: ```lean theorem digamma_diff_le {t : ℝ} (ht : 10 ≤ t) {s : ℂ} (hσlo : -5 / 2 ≤ s.re) (hσhi : s.re ≤ 3) (him : s.im = t) : ‖(Complex.digamma (s / 2) - Complex.digamma ((2 + t * Complex.I) / 2)) / 2‖ ≤ 6 / t := by have ht0 : (0 : ℝ) < t := by linarith set w : ℂ := s / 2 with hw set w₀ : ℂ := (2 + t * Complex.I) / 2 with hw₀ have hw₀eq : w₀ = 1 + (t / 2) * Complex.I := by rw [hw₀]; ring have hwim : w.im = t / 2 := by rw [hw]; simp [him] have hw₀im : w₀.im = t / 2 := by rw [hw₀eq]; simp have himw : w.im ≠ 0 := by rw [hwim]; positivity -- the recurrence: ψ(w + 2) = ψ(w) + w⁻¹ + (w+1)⁻¹ have hrec : Complex.digamma (w + 2) = Complex.digamma w + (w⁻¹ + (w + 1)⁻¹) := by have h := digamma_add_natCast himw 2 rw [show w + ((2 : ℕ) : ℂ) = w + 2 by push_cast; ring] at h rw [Finset.sum_range_succ, Finset.sum_range_succ, Finset.sum_range_zero] at h simp only [Nat.cast_zero, add_zero, Nat.cast_one, zero_add] at h exact h ``` Hmm — the sum form after the range rws: ((0 + w⁻¹) + (w+1)⁻¹)? The sum: ∑ j ∈ range 2, (w + (j:ℂ))⁻¹ = (w + 0)⁻¹ + (w + 1)⁻¹ after the two sum_range_succ from range 0: (((∑ range 0) + f 0) + f 1) = ((0 + f 0) + f 1): simp only [Nat.cast_zero, add_zero, Nat.cast_one, zero_add]: f 0 = (w + (0:ℕ))⁻¹ → (w + 0)⁻¹ → w⁻¹ (cast_zero + add_zero ✓); f 1 = (w + (1:ℕ))⁻¹ → (w + 1)⁻¹ (cast_one ✓); the (0 + w⁻¹) → w⁻¹ via zero_add ✓. So h : digamma (w+2) = digamma w + (w⁻¹ + (w+1)⁻¹) ✓. Wait — digamma_add_natCast's signature: (hw : w.im ≠ 0) (n : ℕ) : digamma (w + ↑n) = digamma w + ∑ j ∈ range n, (w + ↑j)⁻¹ — the w + ↑(2:ℕ): my show `w + ((2:ℕ):ℂ) = w + 2` by push_cast; ring ✓. - Stirling at w+2 and w₀: ```lean have hvre : (0 : ℝ) < (w + 2).re := by have hwre : w.re = s.re / 2 := by rw [hw]; simp have h : (w + 2).re = w.re + 2 := by simp rw [h, hwre] linarith [hσlo] have hvim : (w + 2).im = t / 2 := by have h : (w + 2).im = w.im := by simp rw [h, hwim] have hStir1 := StirlingVert.digamma_stirling hvre (by rw [hvim, abs_of_nonneg (by linarith : (0:ℝ) ≤ t/2)] linarith : (1/2 : ℝ) ≤ |(w + 2).im|) ``` Hmm the second arg: 1/2 ≤ |(w+2).im|: rw [hvim]: |(t/2)| — abs_of_nonneg → t/2: linarith (t/2 ≥ 5 ≥ 1/2 ✓). Let me write: `(by rw [hvim]; rw [abs_of_nonneg (by linarith)]; linarith)`. Hmm — the term after rw [hvim] is |t/2|: rw [abs_of_nonneg (show (0:ℝ) ≤ t/2 by linarith)] : t/2: goal 1/2 ≤ t/2 ✓ linarith. The (w+2).re computation: (w+2).re = w.re + (2:ℂ).re = w.re + 2: `by simp` should evaluate (2:ℂ).re = 2 ✓ (Complex.add_re simp lemma + OfNat re — my piece-2 code did `hre : ((2 + t * Complex.I) - ρ.1).re = 2 - ρ.1.re := by simp` which needed (2 + t·I).re = 2 — worked ✓). So `have h : (w + 2).re = w.re + 2 := by simp` ✓. Similarly im: (w+2).im = w.im ✓ by simp. - Stirling at w₀: ```lean have hw₀re : (0 : ℝ) < w₀.re := by rw [hw₀eq]; simp ``` w₀.re = (1 + (t/2)I).re = 1 + 0 = 1 > 0 ✓ by simp then... `rw [hw₀eq]; simp` — the goal (0:ℝ) < w₀.re → (1 + (t/2)·I).re = 1: simp gives 0 < 1 ✓ closes. ```lean have hStir2 := StirlingVert.digamma_stirling hw₀re (by rw [hw₀im, abs_of_nonneg (by linarith : (0:ℝ) ≤ t/2)]; linarith) ``` - Set the remainders: ```lean set r1 : ℂ := Complex.digamma (w + 2) - Complex.log (w + 2) + (1 / 2) / (w + 2) with hr1 set r0 : ℂ := Complex.digamma w₀ - Complex.log w₀ + (1 / 2) / w₀ with hr0 have hr1le : ‖r1‖ ≤ 3 / (t / 2) ^ 2 := by rw [hr1]; rw [hvim] at hStir1; exact hStir1 ``` hmm — hStir1 : ‖digamma (w+2) − log (w+2) + (1/2)/(w+2)‖ ≤ 3/(w+2).im² — rw [hvim] at hStir1 changes (w+2).im → t/2 ✓ then hr1le : ‖r1‖ ≤ 3/(t/2)² = hStir1 (r1 is set to exactly that expression ✓ defeq via set). - the assembly: ψ(w) − ψ(w₀) = [log(w+2) − log w₀] + [(1/2)/w₀ − (1/2)/(w+2)] − w⁻¹ − (w+1)⁻¹ + [r1 − r0]. Check: ψ(w) = ψ(w+2) − w⁻¹ − (w+1)⁻¹ (from hrec) and ψ(w+2) = log(w+2) − (1/2)/(w+2) + r1 (from hr1: r1 = ψ(w+2) − log(w+2) + (1/2)/(w+2) ⟹ ψ(w+2) = log(w+2) − (1/2)/(w+2) + r1 ✓ linear) and ψ(w₀) = log w₀ − (1/2)/w₀ + r0 ✓. So ψ(w) − ψ(w₀) = log(w+2) − (1/2)/(w+2) + r1 − w⁻¹ − (w+1)⁻¹ − log w₀ + (1/2)/w₀ − r0 ✓. The identity as a have: ```lean have hdecomp : Complex.digamma w - Complex.digamma w₀ = (Complex.log (w + 2) - Complex.log w₀) + ((1 / 2) / w₀ - (1 / 2) / (w + 2)) - w⁻¹ - (w + 1)⁻¹ + (r1 - r0) := by rw [hr1, hr0] -- hmm — unfold r1/r0 linear_combination hrec ``` Hmm — with set r1 := expr1, hr1 : r1 = expr1. To unfold: rw [hr1] replaces r1 with expr1? hr1 : r1 = expr1 — rw [hr1] rewrites r1 → expr1 in the goal ✓ (and r0). Then the goal is a linear identity in the atoms with hrec: linear_combination hrec: goal: ψw − ψw₀ = (log(w+2) − log w₀) + ((1/2)/w₀ − (1/2)/(w+2)) − w⁻¹ − (w+1)⁻¹ + ((ψ(w+2) − log(w+2) + (1/2)/(w+2)) − (ψ w₀ − log w₀ + (1/2)/w₀)). hrec: ψ(w+2) = ψ w + (w⁻¹ + (w+1)⁻¹). goal − hrec: ψw − ψw₀ − ψ(w+2) + ψw + w⁻¹ + (w+1)⁻¹ vs the RHS expression... let me verify: RHS = log(w+2) − log w₀ + (1/2)/w₀ − (1/2)/(w+2) − w⁻¹ − (w+1)⁻¹ + ψ(w+2) − log(w+2) + (1/2)/(w+2) − ψ w₀ + log w₀ − (1/2)/w₀ = ψ(w+2) − w⁻¹ − (w+1)⁻¹ − ψ w₀. So goal: ψw − ψw₀ = ψ(w+2) − w⁻¹ − (w+1)⁻¹ − ψ w₀ ⟺ ψw = ψ(w+2) − w⁻¹ − (w+1)⁻¹ ⟺ hrec rearranged ✓. linear_combination hrec: goal_diff − (hrec_diff) = (ψw − ψw₀ − [ψ(w+2) − w⁻¹ − (w+1)⁻¹ − ψ w₀]) − (ψ(w+2) − [ψw + w⁻¹ + (w+1)⁻¹]) = ψw − ψ(w+2) + ψw + w⁻¹ + (w+1)⁻¹ − ψ(w+2) + ψw... let me just trust linear_combination hrec (sign maybe −hrec; fix at build). - the norm chain: ```lean have hnorm : ‖Complex.digamma w - Complex.digamma w₀‖ ≤ 5 / t + 5 / t ^ 2 + 2 / t + 2 / t + (3 / (t / 2) ^ 2 + 3 / (t / 2) ^ 2) := by rw [hdecomp] -- five-part norm chain via norm haves + linarith have hL : ‖Complex.log (w + 2) - Complex.log w₀‖ ≤ 5 / t := by rw [hw₀eq] -- log w₀ = log (1 + (t/2)I) -- and w = s/2: log (w + 2) = log (s/2 + 2) rw [hw] exact log_diff_le ht hσlo hσhi him have h12 : ‖(1 / 2 : ℂ) / w₀ - (1 / 2) / (w + 2)‖ ≤ 5 / t ^ 2 := by -- (1/2)/w₀ − (1/2)/(w+2) = (1/2)·(w+2−w₀)/(w₀(w+2)): norm ≤ (1/2)·|c|/(‖w₀‖‖w+2‖) ... ``` The (1/2)/w₀ − (1/2)/(w+2): = (1/2)·(1/w₀ − 1/(w+2)) = (1/2)·(w+2−w₀)/(w₀·(w+2)). And w+2 − w₀ = c' = ((c:ℝ):ℂ) (from htarget: w₀ + c' = s/2 + 2 = w + 2 ⟹ w + 2 − w₀ = c' ✓). ‖·‖ = (1/2)·|c|/(‖w₀‖‖w+2‖) ≤ (1/2)·(5/2)/((t/2)(t/2)) = (5/4)·(4/t²) = 5/t² ✓. In Lean: ```lean have h12 : ‖(1 / 2 : ℂ) / w₀ - (1 / 2) / (w + 2)‖ ≤ 5 / t ^ 2 := by have hw₀0 : w₀ ≠ 0 := by intro h have := hznorm... -- hmm w₀ = z 0: ‖w₀‖ ≥ t/2 > 0 have hw2 : w + 2 ≠ 0 := by ... have h1 : (1 / 2 : ℂ) / w₀ - (1 / 2) / (w + 2) = (1 / 2) * ((w + 2 - w₀) / (w₀ * (w + 2))) := by field_simp ring rw [h1, norm_mul, norm_div] ... ``` field_simp with hw₀0, hw2: (1/2)/w₀ − (1/2)/(w+2) = (1/2)(w+2−w₀)/(w₀(w+2)): field_simp [hw₀0, hw2] then ring — the identity: LHS·(w₀(w+2)) = (1/2)(w+2) − (1/2)w₀ = (1/2)(w+2−w₀) ✓. Then norm: (1/2)·‖w+2−w₀‖/(‖w₀‖‖w+2‖). ‖w+2−w₀‖ = |c| (htarget rearranged: w+2−w₀ = c' — from htarget : w₀ + ↑c = w + 2: w + 2 − w₀ = ↑c: by linear_combination htarget? or: have : w + 2 − w₀ = ((c:ℝ):ℂ) := by linear_combination htarget — hmm htarget : w₀ + ↑c = w + 2: w + 2 − w₀ = ↑c ⟺ htarget: linear_combination htarget ✓). ‖↑c‖ = |c| ≤ 5/2. ‖w₀‖ ≥ t/2 (hznorm 0: z 0 = w₀ + 0 = w₀: rw [hz] at hznorm 0: z 0 = w₀ + ((0·c:ℝ):ℂ) = w₀: simp). ‖w+2‖ ≥ t/2 (im = t/2 via hvim + abs_im_le_norm). So the product ≥ t²/4: 1/(product) ≤ 4/t². Then (1/2)·(5/2)·(4/t²) = 5/t² ✓. The ≠ 0's: w₀ ≠ 0 (‖w₀‖ ≥ t/2 ≥ 5 > 0); w+2 ≠ 0 (‖w+2‖ ≥ t/2 > 0); w ≠ 0 (‖w‖ ≥ t/2); w+1 ≠ 0 (im(w+1) = t/2 ≠ 0 or ‖w+1‖ ≥ t/2). ```lean have hw1 : ‖(w⁻¹ : ℂ)‖ ≤ 2 / t := by rw [norm_inv] have h : t / 2 ≤ ‖w‖ := by have h1 := abs_im_le_norm w rw [hwim, abs_of_nonneg (by linarith : (0:ℝ) ≤ t/2)] at h1 exact h1 rw [inv_le...] hmm: ‖w⁻¹‖ = ‖w‖⁻¹ ≤ (t/2)⁻¹ = 2/t: have h2 : ‖w‖⁻¹ ≤ (t / 2)⁻¹ := by rw [inv_le_inv₀ (by positivity ... ‖w‖ > 0) (by positivity : (0:ℝ) < t/2)] exact h rw [h2] -- hmm ‖w⁻¹‖ = ‖w‖⁻¹ already from norm_inv field_simp? (t/2)⁻¹ = 2/t: ``` ‖w⁻¹‖ = ‖w‖⁻¹ ≤ (t/2)⁻¹ = 2/t: the last: (t/2)⁻¹ = 2/t: `by field_simp`? (t/2)⁻¹ = 2/t ⟺ 1/(t/2) = 2/t ⟺ t = 2·(t/2) ✓ field_simp with t ≠ 0. So: ```lean have hw1 : ‖(w : ℂ)⁻¹‖ ≤ 2 / t := by have hwn : t / 2 ≤ ‖w‖ := by have h1 := abs_im_le_norm w rw [hwim, abs_of_nonneg (by linarith : (0:ℝ) ≤ t/2)] at h1 exact h1 have hpos : (0 : ℝ) < ‖w‖ := by positivity rw [norm_inv] calc ‖w‖⁻¹ ≤ (t / 2)⁻¹ := by rw [inv_le_inv₀ hpos (by positivity : (0:ℝ) < t/2)] exact hwn _ = 2 / t := by field_simp ``` Hmm — (t/2)⁻¹ = 2/t: field_simp needs t ≠ 0: ht0.ne' in context ✓ — `by field_simp` should find ht0.ne'? field_simp looks for ne hyps in context ✓ or `by rw [inv_div]...`: (t/2)⁻¹ = 2/t: inv_div: (a/b)⁻¹ = b/a ✓ `rw [inv_div]` — wait inv_div : (a/b)⁻¹ = b/a ✓. So `(t/2)⁻¹ = 2/t` by rw [inv_div] — hmm inv_div on (t/2)⁻¹ gives 2/t ✓ directly. Let me use that (no field_simp): `_ = 2 / t := by rw [inv_div]`. ✓ Similarly hw1' : ‖(w+1)⁻¹‖ ≤ 2/t: im(w+1) = w.im = t/2 ✓ same. - the r bounds: hr1le : ‖r1‖ ≤ 3/(t/2)², hr0le similarly. - the chain: ‖ψw − ψw₀‖ ≤ hL + h12 + hw1 + hw1' + (hr1le + hr0le) via the norm haves + linarith pattern (banked): ```lean have hnorm : ‖Complex.digamma w - Complex.digamma w₀‖ ≤ (5 / t) + (5 / t ^ 2) + (2 / t) + (2 / t) + (3 / (t / 2) ^ 2) + (3 / (t / 2) ^ 2) := by rw [hdecomp] have hc1 : ‖(Complex.log (w + 2) - Complex.log w₀) + ((1 / 2 : ℂ) / w₀ - (1 / 2) / (w + 2)) - w⁻¹ - (w + 1)⁻¹ + (r1 - r0)‖ ≤ ‖(Complex.log (w + 2) - Complex.log w₀) + ((1 / 2 : ℂ) / w₀ - (1 / 2) / (w + 2)) - w⁻¹ - (w + 1)⁻¹‖ + ‖r1 - r0‖ := norm_add_le _ _ ... (the per-step haves + linarith pattern) ``` Then the final fold: 5/t + 5/t² + 2/t + 2/t + 3/(t/2)² + 3/(t/2)² = 9/t + 5/t² + 24/t² = 9/t + 29/t². And ‖(ψw − ψw₀)/2‖ = ½‖ψw − ψw₀‖ ≤ (9/t + 29/t²)/2. Target 6/t: need (9/t + 29/t²)/2 ≤ 6/t ⟺ 9/t + 29/t² ≤ 12/t ⟺ 29/t² ≤ 3/t ⟺ 29 ≤ 3t ⟺ t ≥ 29/3 = 9.67 ✓ t ≥ 10. The norm of /2: ‖x/2‖ = ‖x‖/2 (norm_div with ‖(2:ℂ)‖ = 2 — from my one_div_diff_le's hψnorm pattern: `rw [norm_div]; have h1 : ‖(2:ℂ)‖ = 2 := by rw [show (2:ℂ) = ((2:ℝ):ℂ) by push_cast; ring, Complex.norm_real]; norm_num; rw [h1]` ✓ reuse). The final assembly: ```lean rw [hw, hw₀] -- the goal's digamma args back to w, w₀? — w := s/2 IS the arg -- goal: ‖(digamma w − digamma w₀)/2‖ ≤ 6/t rw [norm_div] -- hmm the /2 norm have h2norm : ‖(2 : ℂ)‖ = 2 := by rw [show (2 : ℂ) = ((2 : ℝ) : ℂ) by push_cast; ring, Complex.norm_real] norm_num rw [h2norm] rw [div_le_iff₀ (by norm_num : (0:ℝ) < 2)] -- goal: ‖digamma w − digamma w₀‖ ≤ 6/t * 2 have hfold : (5 / t) + (5 / t ^ 2) + (2 / t) + (2 / t) + (3 / (t / 2) ^ 2) + (3 / (t / 2) ^ 2) ≤ 6 / t * 2 := by rw [div_le_iff₀...] hmm — 3/(t/2)² = 12/t²: have h1 : (3 : ℝ) / (t / 2) ^ 2 = 12 / t ^ 2 := by field_simp ring rw [h1] -- 5/t + 5/t² + 2/t + 2/t + 12/t² + 12/t² = 9/t + 29/t² ≤ 12/t rw [div_le_iff₀ ht0] -- hmm the t's — let me just clear denominators have ht2 : (0 : ℝ) < t ^ 2 := by positivity rw [div_le_iff₀ ht2]?? — the terms have different denominators — messy. Better: multiply through: show (9/t + 29/t²) ≤ 12/t: div_le_div... Let me: have hkey : 9 / t + 29 / t ^ 2 ≤ 12 / t := by rw [div_le_div_iff ht0 ht0]?? no — different denoms. ``` Cleaner: 9/t + 29/t² ≤ 12/t ⟺ (multiply by t² > 0): 9t + 29 ≤ 12t ⟺ 29 ≤ 3t ✓ t ≥ 10. In Lean: ```lean have hkey : 9 / t + 29 / t ^ 2 ≤ 12 / t := by have h1 : (9 / t + 29 / t ^ 2) * t ^ 2 ≤ (12 / t) * t ^ 2 := by rw [div_le_iff₀... no — mul_le_mul_of_nonneg_right (h : a ≤ b) (hc : 0 ≤ c) — I need the forward: prove a·t² ≤ b·t² then conclude a ≤ b via (mul_le_mul_right ht2).mp. Let me: suffices h : (9 / t + 29 / t ^ 2) * t ^ 2 ≤ (12 / t) * t ^ 2 by exact (mul_le_mul_right ht2).mp h rw [div_mul_cancel₀ ... ] -- messy division forms ``` Hmm — div_mul forms: (9/t)·t² = 9t: `div_mul_cancel₀`? 9/t·t² = 9·t: rw [div_mul_eq_mul_div, ...]. Ugh. Cleanest: field_simp [ht0.ne'] on the SUFFICES goal then nlinarith: ```lean have hkey : 9 / t + 29 / t ^ 2 ≤ 12 / t := by rw [div_le_iff₀ ht0] -- (9/t + 29/t²) ≤ 12/t ⟺ ... hmm div_le_iff₀ is a/c ≤ b ↔ a ≤ b·c — the LHS here isn't a single division. ``` Let me use the positive-multiplier trick: ```lean have hkey : 9 / t + 29 / t ^ 2 ≤ 12 / t := by rw [show (12 : ℝ) / t = 12 * t / t ^ 2 by field_simp] rw [show 9 / t + 29 / t ^ 2 = (9 * t + 29) / t ^ 2 by field_simp] exact div_le_div_of_nonneg_right ... no — same denominator: div_le_div_of_nonneg_right (h : a ≤ b) (c ≥ 0) : a/c ≤ b/c ✓: apply div_le_div_of_nonneg_right _ (by positivity : (0:ℝ) ≤ t^2) -- hmm direction nlinarith [ht] ``` (9t + 29)/t² ≤ 12t/t² ⟸ 9t + 29 ≤ 12t ⟸ 29 ≤ 3t ✓ (t ≥ 10: 3t ≥ 30 ≥ 29 ✓ nlinarith [ht] — wait ht : 10 ≤ t: 3t ≥ 30 > 29 ✓ linarith). div_le_div_of_nonneg_right (hab : 9*t+29 ≤ 12*t) (hc : 0 ≤ t^2) : (9t+29)/t² ≤ 12t/t² ✓. The show-forms: 12/t = 12t/t²: field_simp (t≠0) ✓; 9/t + 29/t² = (9t+29)/t²: field_simp ✓. Then the total: 5/t + 5/t² + 2/t + 2/t + 12/t² + 12/t² = 9/t + 29/t²: by ring (same-denominator normalization ✓ ring handles). So: ```lean have hfold : (5 : ℝ) / t + 5 / t ^ 2 + 2 / t + 2 / t + 3 / (t / 2) ^ 2 + 3 / (t / 2) ^ 2 ≤ 6 / t * 2 := by have h1 : (3 : ℝ) / (t / 2) ^ 2 = 12 / t ^ 2 := by field_simp [ht0.ne'] ring rw [h1] have hkey : 9 / t + 29 / t ^ 2 ≤ 12 / t := by ... have hsum : (5 : ℝ) / t + 5 / t ^ 2 + 2 / t + 2 / t + 12 / t ^ 2 + 12 / t ^ 2 = 9 / t + 29 / t ^ 2 := by ring rw [hsum] linarith [hkey, ht0] -- 9/t + 29/t² ≤ 12/t and 12/t = 6/t·2: hmm 6/t*2 = 12/t by ring — linarith sees 12/t and 6/t*2 as different atoms? (6/t)*2 vs 12/t: linarith treats 6/t*2 as (6/t)*2 — atom 6/t scaled — and 12/t is a DIFFERENT atom. Bridge: have : (6:ℝ)/t*2 = 12/t := by ring; rw [this]... let me restructure the goal as ≤ 12/t directly. ``` Let me simplify: make the final bound 12/t and note 6/t*2... — actually the goal after div_le_iff₀ (0<2): ‖ψw − ψw₀‖ ≤ (6/t)·2: 6/t·2 = 12/t: have h6 : (6:ℝ)/t * 2 = 12 / t := by ring. rw [h6]. Then the chain: hnorm gives ≤ 5/t + 5/t² + 2/t + 2/t + 3/(t/2)² + 3/(t/2)²; show that's ≤ 12/t via h1 + hsum + hkey. OK. Let me now also double check the hdecomp + hnorm chain plumbing. This is a LOT of fiddly code. Let me write it all out and compile. Writing the complete piece 6 now (replacing the sorry draft).
I left `sorry` placeholders in the draft — let me write the complete piece 6 properly (no sorries).
tool: Edit
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean",
  "old_string": "/-! ## 8. Piece 6: the digamma difference -/\n\n/-- The log difference along the constant-imaginary segment: for\ns = \u03c3 + it with \u03c3 \u2208 [\u22125/2, 3] and t \u2265 10: \u2016log (s/2 + 2) \u2212 log (1 +\n(t/2)\u00b7I)\u2016 \u2264 5/t. The segment FTC: every point of the segment has\nim = t/2 (so norm \u2265 t/2) and re \u2265 3/4 (slit plane); the scalar\ndifference c = \u03c3/2 + 1 \u2208 [\u22121/4, 5/2]. -/\ntheorem log_diff_le {t : \u211d} (ht : 10 \u2264 t) {s : \u2102}\n    (h\u03c3lo : -5 / 2 \u2264 s.re) (h\u03c3hi : s.re \u2264 3) (him : s.im = t) :\n    \u2016Complex.log (s / 2 + 2) - Complex.log (1 + (t / 2) * Complex.I)\u2016 \u2264 5 / t := by\n  have ht0 : (0 : \u211d) < t := by linarith\n  set w\u2080 : \u2102 := 1 + (t / 2) * Complex.I with hw\u2080\n  set c : \u211d := s.re / 2 + 1 with hc\n  have hcle : |c| \u2264 5 / 2 := by\n    rw [hc, abs_le]\n    constructor <;> linarith\n  -- the segment z(y) = w\u2080 + (y\u00b7c : \u2102), y \u2208 [0,1]\n  set z : \u211d \u2192 \u2102 := fun y => w\u2080 + ((y * c : \u211d) : \u2102) with hz\n  have hzim : \u2200 y : \u211d, (z y).im = t / 2 := by\n    intro y\n    rw [hz, hw\u2080]\n    simp [Complex.add_im, Complex.ofReal_im]\n  have hznorm : \u2200 y : \u211d, t / 2 \u2264 \u2016z y\u2016 := by\n    intro y\n    have h := abs_im_le_norm (z y)\n    rw [hzim y, abs_of_nonneg (by linarith : (0 : \u211d) \u2264 t / 2)] at h\n    exact h\n  have hzslit : \u2200 y : \u211d, z y \u2208 Complex.slitPlane := by\n    intro y\n    rw [Complex.mem_slitPlane_iff]\n    right\n    rw [hzim y]\n    positivity\n  -- the endpoint: w\u2080 + c' = s/2 + 2\n  have htarget : w\u2080 + ((c : \u211d) : \u2102) = s / 2 + 2 := by\n    rw [hw\u2080, hc]\n    rw [Complex.ext_iff]\n    constructor\n    \u00b7 have h1 : (s / 2 + 2).re = s.re / 2 + 2 := by simp\n      rw [h1]\n      simp [Complex.add_re, Complex.ofReal_re]\n      ring_nf\n    \u00b7 have h1 : (s / 2 + 2).im = t / 2 := by simp [him]\n      rw [h1]\n      simp [Complex.add_im, Complex.ofReal_im]\n      ring_nf\n  -- the FTC derivative family\n  have hanti : \u2200 y \u2208 Set.uIcc (0 : \u211d) 1,\n      HasDerivAt (fun x : \u211d => Complex.log (z x)) (((z y)\u207b\u00b9) * ((c : \u211d) : \u2102)) y := by\n    intro y _\n    have h1 : HasDerivAt (fun u : \u2102 => Complex.log (w\u2080 + u * ((c : \u211d) : \u2102)))\n        (((z y)\u207b\u00b9) * ((c : \u211d) : \u2102)) ((y : \u211d) : \u2102) := by\n      have h2 := (Complex.hasDerivAt_log (hzslit y)).comp ((y : \u211d) : \u2102)\n        (((hasDerivAt_id' ((y : \u211d) : \u2102)).mul_const ((c : \u211d) : \u2102)).const_add w\u2080)\n      simpa [hz, Function.comp_def, mul_comm] using h2\n    exact h1.comp_ofReal\n  have hconti : IntervalIntegrable\n      (fun y : \u211d => ((z y)\u207b\u00b9) * ((c : \u211d) : \u2102)) volume 0 1 := by\n    apply ContinuousOn.intervalIntegrable\n    apply Continuous.continuousOn\n    apply Continuous.mul continuous_const\n    apply Continuous.inv\u2080 _ (fun y => by\n      have h := hznorm y\n      positivity)\n    rw [hz]\n    exact (continuous_const.add (Complex.continuous_ofReal.mul continuous_const))\n  -- the integral identity and bound\n  have hint : \u222b y in (0 : \u211d)..(1 : \u211d), ((z y)\u207b\u00b9) * ((c : \u211d) : \u2102)\n      = Complex.log (s / 2 + 2) - Complex.log w\u2080 := by\n    rw [intervalIntegral.integral_eq_sub_of_hasDerivAt hanti hconti]\n    rw [hz]\n    simp only [Nat.cast_one, one_mul, Nat.cast_zero, zero_mul, add_zero]\n    rw [htarget]\n  rw [\u2190 hint]\n  have hbound : \u2200 y \u2208 Set.\u0399 (0 : \u211d) 1,\n      \u2016((z y)\u207b\u00b9) * ((c : \u211d) : \u2102)\u2016 \u2264 5 / t := by\n    intro y _\n    have hzy : (0 : \u211d) < \u2016z y\u2016 := by\n      have h := hznorm y\n      positivity\n    have h1 : \u2016((z y)\u207b\u00b9) * ((c : \u211d) : \u2102)\u2016 = \u2016z y\u2016\u207b\u00b9 * |c| := by\n      rw [norm_mul, norm_inv, Complex.norm_real]\n    rw [h1]\n    have h2 : \u2016z y\u2016\u207b\u00b9 \u2264 (t / 2)\u207b\u00b9 := by\n      rw [inv_le_inv\u2080 hzy (by positivity : (0 : \u211d) < t / 2)]\n      exact hznorm y\n    calc \u2016z y\u2016\u207b\u00b9 * |c| \u2264 (t / 2)\u207b\u00b9 * (5 / 2) :=\n        mul_le_mul h2 hcle (abs_nonneg _) (by positivity)\n      _ = 5 / t := by field_simp\n  calc \u2016\u222b y in (0 : \u211d)..(1 : \u211d), ((z y)\u207b\u00b9) * ((c : \u211d) : \u2102)\u2016\n      \u2264 (5 / t) * |1 - 0| := intervalIntegral.norm_integral_le_of_norm_le_const hbound\n    _ = 5 / t := by norm_num [abs_one]\n\n/-- **Piece 6** (D-069 \u00a73): the digamma difference\n\u00bd\u2016\u03c8(s/2) \u2212 \u03c8(s\u2080/2)\u2016 \u2264 6/t. Via the +2 shift (re(w+2) \u2265 3/4), Zeta23's\ndigamma_stirling at w+2 and w\u2080, the recurrence \u03c8(w) = \u03c8(w+2) \u2212 w\u207b\u00b9 \u2212\n(w+1)\u207b\u00b9, and the segment-FTC log bound. -/\ntheorem digamma_diff_le {t : \u211d} (ht : 10 \u2264 t) {s : \u2102}\n    (h\u03c3lo : -5 / 2 \u2264 s.re) (h\u03c3hi : s.re \u2264 3) (him : s.im = t) :\n    \u2016(Complex.digamma (s / 2) - Complex.digamma ((2 + t * Complex.I) / 2)) / 2\u2016\n      \u2264 6 / t := by\n  have ht0 : (0 : \u211d) < t := by linarith\n  set w : \u2102 := s / 2 with hw\n  set w\u2080 : \u2102 := (2 + t * Complex.I) / 2 with hw\u2080\n  have hw\u2080eq : w\u2080 = 1 + (t / 2) * Complex.I := by rw [hw\u2080]; ring\n  have hwim : w.im = t / 2 := by rw [hw]; simp [him]\n  have hw\u2080im : w\u2080.im = t / 2 := by rw [hw\u2080eq]; simp\n  have himw : w.im \u2260 0 := by rw [hwim]; positivity\n  have hwre : w.re = s.re / 2 := by rw [hw]; simp\n  have hw\u2080re : (0 : \u211d) < w\u2080.re := by rw [hw\u2080eq]; simp\n  -- the recurrence: \u03c8(w + 2) = \u03c8(w) + w\u207b\u00b9 + (w+1)\u207b\u00b9\n  have hrec : Complex.digamma (w + 2) = Complex.digamma w + (w\u207b\u00b9 + (w + 1)\u207b\u00b9) := by\n    have h := digamma_add_natCast himw 2\n    rw [show w + ((2 : \u2115) : \u2102) = w + 2 by push_cast; ring] at h\n    rw [Finset.sum_range_succ, Finset.sum_range_succ, Finset.sum_range_zero] at h\n    simp only [Nat.cast_zero, add_zero, Nat.cast_one, zero_add] at h\n    exact h\n  -- the Stirling bounds at w + 2 and w\u2080\n  have hvre : (0 : \u211d) < (w + 2).re := by\n    have h : (w + 2).re = w.re + 2 := by simp\n    rw [h, hwre]\n    linarith [h\u03c3lo]\n  have hvim : (w + 2).im = t / 2 := by\n    have h : (w + 2).im = w.im := by simp\n    rw [h, hwim]\n  have hStir1 := StirlingVert.digamma_stirling hvre (by\n    rw [hvim, abs_of_nonneg (by linarith : (0 : \u211d) \u2264 t / 2)]; linarith)\n  have hStir2 := StirlingVert.digamma_stirling hw\u2080re (by\n    rw [hw\u2080im, abs_of_nonneg (by linarith : (0 : \u211d) \u2264 t / 2)]; linarith)\n  -- the remainders\n  set r1 : \u2102 := Complex.digamma (w + 2) - Complex.log (w + 2) + (1 / 2) / (w + 2) with hr1\n  set r0 : \u2102 := Complex.digamma w\u2080 - Complex.log w\u2080 + (1 / 2) / w\u2080 with hr0\n  have hr1le : \u2016r1\u2016 \u2264 3 / (t / 2) ^ 2 := by\n    have h := hStir1\n    rw [hvim] at h\n    exact h\n  have hr0le : \u2016r0\u2016 \u2264 3 / (t / 2) ^ 2 := by\n    have h := hStir2\n    rw [hw\u2080im] at h\n    exact h\n  -- the decomposition\n  have hdecomp : Complex.digamma w - Complex.digamma w\u2080\n      = (Complex.log (w + 2) - Complex.log w\u2080)\n        + ((1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)) - w\u207b\u00b9 - (w + 1)\u207b\u00b9 + (r1 - r0) := by\n    rw [hr1, hr0]\n    linear_combination hrec\n  -- the pieces\n  have hL : \u2016Complex.log (w + 2) - Complex.log w\u2080\u2016 \u2264 5 / t := by\n    rw [hw, hw\u2080eq]\n    exact log_diff_le ht h\u03c3lo h\u03c3hi him\n  have hw0norm : t / 2 \u2264 \u2016w\u2080\u2016 := by\n    have h1 := abs_im_le_norm w\u2080\n    rw [hw\u2080im, abs_of_nonneg (by linarith : (0 : \u211d) \u2264 t / 2)] at h1\n    exact h1\n  have hw2norm : t / 2 \u2264 \u2016w + 2\u2016 := by\n    have h1 := abs_im_le_norm (w + 2)\n    rw [hvim, abs_of_nonneg (by linarith : (0 : \u211d) \u2264 t / 2)] at h1\n    exact h1\n  have hwnorm : t / 2 \u2264 \u2016w\u2016 := by\n    have h1 := abs_im_le_norm w\n    rw [hwim, abs_of_nonneg (by linarith : (0 : \u211d) \u2264 t / 2)] at h1\n    exact h1\n  have hw1norm : t / 2 \u2264 \u2016w + 1\u2016 := by\n    have h1 := abs_im_le_norm (w + 1)\n    have h2 : (w + 1).im = t / 2 := by simp [hwim]\n    rw [h2, abs_of_nonneg (by linarith : (0 : \u211d) \u2264 t / 2)] at h1\n    exact h1\n  have hw\u20800 : w\u2080 \u2260 0 := by\n    intro h\n    rw [h, norm_zero] at hw0norm\n    linarith\n  have hw2 : w + 2 \u2260 0 := by\n    intro h\n    rw [h, norm_zero] at hw2norm\n    linarith\n  have hw0 : w \u2260 0 := by\n    intro h\n    rw [h, norm_zero] at hwnorm\n    linarith\n  have hw1 : w + 1 \u2260 0 := by\n    intro h\n    rw [h, norm_zero] at hw1norm\n    linarith\n  have h12 : \u2016(1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)\u2016 \u2264 5 / t ^ 2 := by\n    have h1 : (1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)\n        = (1 / 2) * ((w + 2 - w\u2080) / (w\u2080 * (w + 2))) := by\n      field_simp\n      ring\n    have hsub : w + 2 - w\u2080 = ((s.re / 2 + 1 : \u211d) : \u2102) := by\n      have ht1 : w\u2080 + ((s.re / 2 + 1 : \u211d) : \u2102) = w + 2 := by\n        rw [hw, hw\u2080eq]\n        rw [Complex.ext_iff]\n        constructor\n        \u00b7 simp [hwre]\n          ring_nf\n        \u00b7 simp [hw\u2080im]\n          rw [hwim]\n      linear_combination ht1\n    rw [h1, hsub, norm_mul, norm_div, Complex.norm_real]\n    have hc : |s.re / 2 + 1| \u2264 5 / 2 := by\n      rw [abs_le]\n      constructor <;> linarith\n    have h12n : \u2016(1 / 2 : \u2102)\u2016 = 1 / 2 := by\n      rw [show (1 / 2 : \u2102) = ((1 / 2 : \u211d) : \u2102) by push_cast; ring, Complex.norm_real]\n      norm_num\n    rw [h12n]\n    have hprod : (t / 2) * (t / 2) \u2264 \u2016w\u2080\u2016 * \u2016w + 2\u2016 :=\n      mul_le_mul hw0norm hw2norm (by positivity) (by positivity)\n    calc (1 / 2) * (|s.re / 2 + 1| / (\u2016w\u2080\u2016 * \u2016w + 2\u2016))\n        \u2264 (1 / 2) * ((5 / 2) / (\u2016w\u2080\u2016 * \u2016w + 2\u2016)) := by\n          apply mul_le_mul_of_nonneg_left _ (by norm_num)\n          exact div_le_div_of_nonneg_right hc (by positivity)\n      _ \u2264 (1 / 2) * ((5 / 2) / ((t / 2) * (t / 2))) := by\n          apply mul_le_mul_of_nonneg_left _ (by norm_num)\n          exact div_le_div_of_nonneg_left (by norm_num) (by positivity) hprod\n      _ = 5 / t ^ 2 := by field_simp; ring\n  have hw1b : \u2016(w : \u2102)\u207b\u00b9\u2016 \u2264 2 / t := by\n    rw [norm_inv]\n    have hpos : (0 : \u211d) < \u2016w\u2016 := by positivity\n    calc \u2016w\u2016\u207b\u00b9 \u2264 (t / 2)\u207b\u00b9 := by\n          rw [inv_le_inv\u2080 hpos (by positivity : (0 : \u211d) < t / 2)]\n          exact hwnorm\n      _ = 2 / t := by rw [inv_div]\n  have hw1'b : \u2016(w + 1 : \u2102)\u207b\u00b9\u2016 \u2264 2 / t := by\n    rw [norm_inv]\n    have hpos : (0 : \u211d) < \u2016w + 1\u2016 := by positivity\n    calc \u2016w + 1\u2016\u207b\u00b9 \u2264 (t / 2)\u207b\u00b9 := by\n          rw [inv_le_inv\u2080 hpos (by positivity : (0 : \u211d) < t / 2)]\n          exact hw1norm\n      _ = 2 / t := by rw [inv_div]\n  -- the norm chain\n  have hnorm : \u2016Complex.digamma w - Complex.digamma w\u2080\u2016\n      \u2264 5 / t + 5 / t ^ 2 + (2 / t + 2 / t) + (3 / (t / 2) ^ 2 + 3 / (t / 2) ^ 2) := by\n    rw [hdecomp]\n    have hc1 : \u2016(Complex.log (w + 2) - Complex.log w\u2080)\n          + ((1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)) - w\u207b\u00b9 - (w + 1)\u207b\u00b9 + (r1 - r0)\u2016\n        \u2264 \u2016(Complex.log (w + 2) - Complex.log w\u2080)\n          + ((1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)) - w\u207b\u00b9 - (w + 1)\u207b\u00b9\u2016 + \u2016r1 - r0\u2016 :=\n      norm_add_le _ _\n    have hc2 : \u2016(Complex.log (w + 2) - Complex.log w\u2080)\n          + ((1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)) - w\u207b\u00b9 - (w + 1)\u207b\u00b9\u2016\n        \u2264 \u2016(Complex.log (w + 2) - Complex.log w\u2080)\n          + ((1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)) - w\u207b\u00b9\u2016 + \u2016(w + 1)\u207b\u00b9\u2016 :=\n      norm_sub_le _ _\n    have hc3 : \u2016(Complex.log (w + 2) - Complex.log w\u2080)\n          + ((1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)) - w\u207b\u00b9\u2016\n        \u2264 \u2016(Complex.log (w + 2) - Complex.log w\u2080)\n          + ((1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2))\u2016 + \u2016w\u207b\u00b9\u2016 :=\n      norm_sub_le _ _\n    have hc4 : \u2016(Complex.log (w + 2) - Complex.log w\u2080)\n          + ((1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2))\u2016\n        \u2264 \u2016Complex.log (w + 2) - Complex.log w\u2080\u2016\n          + \u2016(1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)\u2016 :=\n      norm_add_le _ _\n    have hc5 : \u2016r1 - r0\u2016 \u2264 \u2016r1\u2016 + \u2016r0\u2016 := norm_sub_le _ _\n    linarith [hc1, hc2, hc3, hc4, hc5, hL, h12, hw1b, hw1'b, hr1le, hr0le]\n  -- the fold to 6/t\n  have h2norm : \u2016(2 : \u2102)\u2016 = 2 := by\n    rw [show (2 : \u2102) = ((2 : \u211d) : \u2102) by push_cast; ring, Complex.norm_real]\n    norm_num\n  rw [hw, hw\u2080, norm_div, h2norm]\n  rw [div_le_iff\u2080 (by norm_num : (0 : \u211d) < 2)]\n  have h1 : (3 : \u211d) / (t / 2) ^ 2 = 12 / t ^ 2 := by\n    field_simp\n    ring\n  have hsum : 5 / t + 5 / t ^ 2 + (2 / t + 2 / t) + (12 / t ^ 2 + 12 / t ^ 2)\n      = 9 / t + 29 / t ^ 2 := by\n    field_simp\n    ring\n  have hkey : 9 / t + 29 / t ^ 2 \u2264 12 / t := by\n    rw [show (12 : \u211d) / t = 12 * t / t ^ 2 by field_simp; ring]\n    rw [show 9 / t + 29 / t ^ 2 = (9 * t + 29) / t ^ 2 by field_simp; ring]\n    apply div_le_div_of_nonneg_right _ (by positivity : (0 : \u211d) \u2264 t ^ 2)\n    nlinarith [ht]\n  calc \u2016Complex.digamma w - Complex.digamma w\u2080\u2016\n      \u2264 5 / t + 5 / t ^ 2 + (2 / t + 2 / t) + (3 / (t / 2) ^ 2 + 3 / (t / 2) ^ 2) := hnorm\n    _ = 9 / t + 29 / t ^ 2 := by rw [h1]; rw [hsum]\n    _ \u2264 12 / t := hkey\n    _ = 6 / t * 2 := by ring\n\nend NguyenRH1\n\nend",
  "new_string": "      _ \u2264 4.5 / 100 := div_le_div_of_nonneg_left (by norm_num) (by norm_num) hprods1\n      _ = 0.045 := by norm_num\n\n/-! ## 8. Piece 6: the digamma difference -/\n\n/-- The log difference along the constant-imaginary segment: for\ns = \u03c3 + it with \u03c3 \u2208 [\u22125/2, 3] and t \u2265 10: \u2016log (s/2 + 2) \u2212 log (1 +\n(t/2)\u00b7I)\u2016 \u2264 5/t. The segment FTC: every point of the segment has\nim = t/2 (so norm \u2265 t/2) and re \u2265 3/4 (slit plane); the scalar\ndifference c = \u03c3/2 + 1 \u2208 [\u22121/4, 5/2]. -/\ntheorem log_diff_le {t : \u211d} (ht : 10 \u2264 t) {s : \u2102}\n    (h\u03c3lo : -5 / 2 \u2264 s.re) (h\u03c3hi : s.re \u2264 3) (him : s.im = t) :\n    \u2016Complex.log (s / 2 + 2) - Complex.log (1 + (t / 2) * Complex.I)\u2016 \u2264 5 / t := by\n  have ht0 : (0 : \u211d) < t := by linarith\n  set w\u2080 : \u2102 := 1 + (t / 2) * Complex.I with hw\u2080\n  set c : \u211d := s.re / 2 + 1 with hc\n  have hcle : |c| \u2264 5 / 2 := by\n    rw [hc, abs_le]\n    constructor <;> linarith\n  -- the segment z(y) = w\u2080 + (y\u00b7c : \u2102), y \u2208 [0,1]\n  set z : \u211d \u2192 \u2102 := fun y => w\u2080 + ((y * c : \u211d) : \u2102) with hz\n  have hzim : \u2200 y : \u211d, (z y).im = t / 2 := by\n    intro y\n    rw [hz, hw\u2080]\n    simp [Complex.add_im, Complex.ofReal_im]\n  have hznorm : \u2200 y : \u211d, t / 2 \u2264 \u2016z y\u2016 := by\n    intro y\n    have h := abs_im_le_norm (z y)\n    rw [hzim y, abs_of_nonneg (by linarith : (0 : \u211d) \u2264 t / 2)] at h\n    exact h\n  have hzslit : \u2200 y : \u211d, z y \u2208 Complex.slitPlane := by\n    intro y\n    rw [Complex.mem_slitPlane_iff]\n    right\n    rw [hzim y]\n    positivity\n  -- the endpoint: w\u2080 + c' = s/2 + 2\n  have htarget : w\u2080 + ((c : \u211d) : \u2102) = s / 2 + 2 := by\n    rw [hw\u2080, hc]\n    rw [Complex.ext_iff]\n    constructor\n    \u00b7 have h1 : (s / 2 + 2).re = s.re / 2 + 2 := by simp\n      rw [h1]\n      simp [Complex.add_re, Complex.ofReal_re]\n      ring_nf\n    \u00b7 have h1 : (s / 2 + 2).im = t / 2 := by simp [him]\n      rw [h1]\n      simp [Complex.add_im, Complex.ofReal_im]\n      ring_nf\n  -- the FTC derivative family\n  have hanti : \u2200 y \u2208 Set.uIcc (0 : \u211d) 1,\n      HasDerivAt (fun x : \u211d => Complex.log (z x)) (((z y)\u207b\u00b9) * ((c : \u211d) : \u2102)) y := by\n    intro y _\n    have h1 : HasDerivAt (fun u : \u2102 => Complex.log (w\u2080 + u * ((c : \u211d) : \u2102)))\n        (((z y)\u207b\u00b9) * ((c : \u211d) : \u2102)) ((y : \u211d) : \u2102) := by\n      have h2 := (Complex.hasDerivAt_log (hzslit y)).comp ((y : \u211d) : \u2102)\n        (((hasDerivAt_id' ((y : \u211d) : \u2102)).mul_const ((c : \u211d) : \u2102)).const_add w\u2080)\n      simpa [hz, Function.comp_def, mul_comm] using h2\n    exact h1.comp_ofReal\n  have hconti : IntervalIntegrable\n      (fun y : \u211d => ((z y)\u207b\u00b9) * ((c : \u211d) : \u2102)) volume 0 1 := by\n    apply ContinuousOn.intervalIntegrable\n    apply Continuous.continuousOn\n    apply Continuous.mul continuous_const\n    apply Continuous.inv\u2080 _ (fun y => by\n      have h := hznorm y\n      positivity)\n    rw [hz]\n    exact (continuous_const.add (Complex.continuous_ofReal.mul continuous_const))\n  -- the integral identity and bound\n  have hint : \u222b y in (0 : \u211d)..(1 : \u211d), ((z y)\u207b\u00b9) * ((c : \u211d) : \u2102)\n      = Complex.log (s / 2 + 2) - Complex.log w\u2080 := by\n    rw [intervalIntegral.integral_eq_sub_of_hasDerivAt hanti hconti]\n    rw [hz]\n    simp only [Nat.cast_one, one_mul, Nat.cast_zero, zero_mul, add_zero]\n    rw [htarget]\n  rw [\u2190 hint]\n  have hbound : \u2200 y \u2208 Set.\u0399 (0 : \u211d) 1,\n      \u2016((z y)\u207b\u00b9) * ((c : \u211d) : \u2102)\u2016 \u2264 5 / t := by\n    intro y _\n    have hzy : (0 : \u211d) < \u2016z y\u2016 := by\n      have h := hznorm y\n      positivity\n    have h1 : \u2016((z y)\u207b\u00b9) * ((c : \u211d) : \u2102)\u2016 = \u2016z y\u2016\u207b\u00b9 * |c| := by\n      rw [norm_mul, norm_inv, Complex.norm_real]\n    rw [h1]\n    have h2 : \u2016z y\u2016\u207b\u00b9 \u2264 (t / 2)\u207b\u00b9 := by\n      rw [inv_le_inv\u2080 hzy (by positivity : (0 : \u211d) < t / 2)]\n      exact hznorm y\n    calc \u2016z y\u2016\u207b\u00b9 * |c| \u2264 (t / 2)\u207b\u00b9 * (5 / 2) :=\n        mul_le_mul h2 hcle (abs_nonneg _) (by positivity)\n      _ = 5 / t := by field_simp\n  calc \u2016\u222b y in (0 : \u211d)..(1 : \u211d), ((z y)\u207b\u00b9) * ((c : \u211d) : \u2102)\u2016\n      \u2264 (5 / t) * |1 - 0| := intervalIntegral.norm_integral_le_of_norm_le_const hbound\n    _ = 5 / t := by norm_num [abs_one]\n\n/-- **Piece 6** (D-069 \u00a73): the digamma difference\n\u00bd\u2016\u03c8(s/2) \u2212 \u03c8(s\u2080/2)\u2016 \u2264 6/t. Via the +2 shift (re(w+2) \u2265 3/4), Zeta23's\ndigamma_stirling at w+2 and w\u2080, the recurrence \u03c8(w) = \u03c8(w+2) \u2212 w\u207b\u00b9 \u2212\n(w+1)\u207b\u00b9, and the segment-FTC log bound. -/\ntheorem digamma_diff_le {t : \u211d} (ht : 10 \u2264 t) {s : \u2102}\n    (h\u03c3lo : -5 / 2 \u2264 s.re) (h\u03c3hi : s.re \u2264 3) (him : s.im = t) :\n    \u2016(Complex.digamma (s / 2) - Complex.digamma ((2 + t * Complex.I) / 2)) / 2\u2016\n      \u2264 6 / t := by\n  have ht0 : (0 : \u211d) < t := by linarith\n  set w : \u2102 := s / 2 with hw\n  set w\u2080 : \u2102 := (2 + t * Complex.I) / 2 with hw\u2080\n  have hw\u2080eq : w\u2080 = 1 + (t / 2) * Complex.I := by rw [hw\u2080]; ring\n  have hwim : w.im = t / 2 := by rw [hw]; simp [him]\n  have hw\u2080im : w\u2080.im = t / 2 := by rw [hw\u2080eq]; simp\n  have himw : w.im \u2260 0 := by rw [hwim]; positivity\n  have hwre : w.re = s.re / 2 := by rw [hw]; simp\n  have hw\u2080re : (0 : \u211d) < w\u2080.re := by rw [hw\u2080eq]; simp\n  -- the recurrence: \u03c8(w + 2) = \u03c8(w) + w\u207b\u00b9 + (w+1)\u207b\u00b9\n  have hrec : Complex.digamma (w + 2) = Complex.digamma w + (w\u207b\u00b9 + (w + 1)\u207b\u00b9) := by\n    have h := digamma_add_natCast himw 2\n    rw [show w + ((2 : \u2115) : \u2102) = w + 2 by push_cast; ring] at h\n    rw [Finset.sum_range_succ, Finset.sum_range_succ, Finset.sum_range_zero] at h\n    simp only [Nat.cast_zero, add_zero, Nat.cast_one, zero_add] at h\n    exact h\n  -- the Stirling bounds at w + 2 and w\u2080\n  have hvre : (0 : \u211d) < (w + 2).re := by\n    have h : (w + 2).re = w.re + 2 := by simp\n    rw [h, hwre]\n    linarith [h\u03c3lo]\n  have hvim : (w + 2).im = t / 2 := by\n    have h : (w + 2).im = w.im := by simp\n    rw [h, hwim]\n  have hStir1 := StirlingVert.digamma_stirling hvre (by\n    rw [hvim, abs_of_nonneg (by linarith : (0 : \u211d) \u2264 t / 2)]; linarith)\n  have hStir2 := StirlingVert.digamma_stirling hw\u2080re (by\n    rw [hw\u2080im, abs_of_nonneg (by linarith : (0 : \u211d) \u2264 t / 2)]; linarith)\n  -- the remainders\n  set r1 : \u2102 := Complex.digamma (w + 2) - Complex.log (w + 2) + (1 / 2) / (w + 2) with hr1\n  set r0 : \u2102 := Complex.digamma w\u2080 - Complex.log w\u2080 + (1 / 2) / w\u2080 with hr0\n  have hr1le : \u2016r1\u2016 \u2264 3 / (t / 2) ^ 2 := by\n    have h := hStir1\n    rw [hvim] at h\n    exact h\n  have hr0le : \u2016r0\u2016 \u2264 3 / (t / 2) ^ 2 := by\n    have h := hStir2\n    rw [hw\u2080im] at h\n    exact h\n  -- the decomposition\n  have hdecomp : Complex.digamma w - Complex.digamma w\u2080\n      = (Complex.log (w + 2) - Complex.log w\u2080)\n        + ((1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)) - w\u207b\u00b9 - (w + 1)\u207b\u00b9 + (r1 - r0) := by\n    rw [hr1, hr0]\n    linear_combination hrec\n  -- the pieces\n  have hL : \u2016Complex.log (w + 2) - Complex.log w\u2080\u2016 \u2264 5 / t := by\n    rw [hw, hw\u2080eq]\n    exact log_diff_le ht h\u03c3lo h\u03c3hi him\n  have hw0norm : t / 2 \u2264 \u2016w\u2080\u2016 := by\n    have h1 := abs_im_le_norm w\u2080\n    rw [hw\u2080im, abs_of_nonneg (by linarith : (0 : \u211d) \u2264 t / 2)] at h1\n    exact h1\n  have hw2norm : t / 2 \u2264 \u2016w + 2\u2016 := by\n    have h1 := abs_im_le_norm (w + 2)\n    rw [hvim, abs_of_nonneg (by linarith : (0 : \u211d) \u2264 t / 2)] at h1\n    exact h1\n  have hwnorm : t / 2 \u2264 \u2016w\u2016 := by\n    have h1 := abs_im_le_norm w\n    rw [hwim, abs_of_nonneg (by linarith : (0 : \u211d) \u2264 t / 2)] at h1\n    exact h1\n  have hw1norm : t / 2 \u2264 \u2016w + 1\u2016 := by\n    have h1 := abs_im_le_norm (w + 1)\n    have h2 : (w + 1).im = t / 2 := by simp [hwim]\n    rw [h2, abs_of_nonneg (by linarith : (0 : \u211d) \u2264 t / 2)] at h1\n    exact h1\n  have hw\u20800 : w\u2080 \u2260 0 := by\n    intro h\n    rw [h, norm_zero] at hw0norm\n    linarith\n  have hw2 : w + 2 \u2260 0 := by\n    intro h\n    rw [h, norm_zero] at hw2norm\n    linarith\n  have hw0 : w \u2260 0 := by\n    intro h\n    rw [h, norm_zero] at hwnorm\n    linarith\n  have hw1 : w + 1 \u2260 0 := by\n    intro h\n    rw [h, norm_zero] at hw1norm\n    linarith\n  have h12 : \u2016(1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)\u2016 \u2264 5 / t ^ 2 := by\n    have h1 : (1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)\n        = (1 / 2) * ((w + 2 - w\u2080) / (w\u2080 * (w + 2))) := by\n      field_simp\n      ring\n    have hsub : w + 2 - w\u2080 = ((s.re / 2 + 1 : \u211d) : \u2102) := by\n      have ht1 : w\u2080 + ((s.re / 2 + 1 : \u211d) : \u2102) = w + 2 := by\n        rw [hw, hw\u2080eq]\n        rw [Complex.ext_iff]\n        constructor\n        \u00b7 simp [hwre]\n          ring_nf\n        \u00b7 simp [hw\u2080im]\n          rw [hwim]\n      linear_combination ht1\n    rw [h1, hsub, norm_mul, norm_div, Complex.norm_real]\n    have hc : |s.re / 2 + 1| \u2264 5 / 2 := by\n      rw [abs_le]\n      constructor <;> linarith\n    have h12n : \u2016(1 / 2 : \u2102)\u2016 = 1 / 2 := by\n      rw [show (1 / 2 : \u2102) = ((1 / 2 : \u211d) : \u2102) by push_cast; ring, Complex.norm_real]\n      norm_num\n    rw [h12n]\n    have hprod : (t / 2) * (t / 2) \u2264 \u2016w\u2080\u2016 * \u2016w + 2\u2016 :=\n      mul_le_mul hw0norm hw2norm (by positivity) (by positivity)\n    calc (1 / 2) * (|s.re / 2 + 1| / (\u2016w\u2080\u2016 * \u2016w + 2\u2016))\n        \u2264 (1 / 2) * ((5 / 2) / (\u2016w\u2080\u2016 * \u2016w + 2\u2016)) := by\n          apply mul_le_mul_of_nonneg_left _ (by norm_num)\n          exact div_le_div_of_nonneg_right hc (by positivity)\n      _ \u2264 (1 / 2) * ((5 / 2) / ((t / 2) * (t / 2))) := by\n          apply mul_le_mul_of_nonneg_left _ (by norm_num)\n          exact div_le_div_of_nonneg_left (by norm_num) (by positivity) hprod\n      _ = 5 / t ^ 2 := by field_simp; ring\n  have hw1b : \u2016(w : \u2102)\u207b\u00b9\u2016 \u2264 2 / t := by\n    rw [norm_inv]\n    have hpos : (0 : \u211d) < \u2016w\u2016 := by positivity\n    calc \u2016w\u2016\u207b\u00b9 \u2264 (t / 2)\u207b\u00b9 := by\n          rw [inv_le_inv\u2080 hpos (by positivity : (0 : \u211d) < t / 2)]\n          exact hwnorm\n      _ = 2 / t := by rw [inv_div]\n  have hw1'b : \u2016(w + 1 : \u2102)\u207b\u00b9\u2016 \u2264 2 / t := by\n    rw [norm_inv]\n    have hpos : (0 : \u211d) < \u2016w + 1\u2016 := by positivity\n    calc \u2016w + 1\u2016\u207b\u00b9 \u2264 (t / 2)\u207b\u00b9 := by\n          rw [inv_le_inv\u2080 hpos (by positivity : (0 : \u211d) < t / 2)]\n          exact hw1norm\n      _ = 2 / t := by rw [inv_div]\n  -- the norm chain\n  have hnorm : \u2016Complex.digamma w - Complex.digamma w\u2080\u2016\n      \u2264 5 / t + 5 / t ^ 2 + (2 / t + 2 / t) + (3 / (t / 2) ^ 2 + 3 / (t / 2) ^ 2) := by\n    rw [hdecomp]\n    have hc1 : \u2016(Complex.log (w + 2) - Complex.log w\u2080)\n          + ((1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)) - w\u207b\u00b9 - (w + 1)\u207b\u00b9 + (r1 - r0)\u2016\n        \u2264 \u2016(Complex.log (w + 2) - Complex.log w\u2080)\n          + ((1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)) - w\u207b\u00b9 - (w + 1)\u207b\u00b9\u2016 + \u2016r1 - r0\u2016 :=\n      norm_add_le _ _\n    have hc2 : \u2016(Complex.log (w + 2) - Complex.log w\u2080)\n          + ((1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)) - w\u207b\u00b9 - (w + 1)\u207b\u00b9\u2016\n        \u2264 \u2016(Complex.log (w + 2) - Complex.log w\u2080)\n          + ((1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)) - w\u207b\u00b9\u2016 + \u2016(w + 1)\u207b\u00b9\u2016 :=\n      norm_sub_le _ _\n    have hc3 : \u2016(Complex.log (w + 2) - Complex.log w\u2080)\n          + ((1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)) - w\u207b\u00b9\u2016\n        \u2264 \u2016(Complex.log (w + 2) - Complex.log w\u2080)\n          + ((1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2))\u2016 + \u2016w\u207b\u00b9\u2016 :=\n      norm_sub_le _ _\n    have hc4 : \u2016(Complex.log (w + 2) - Complex.log w\u2080)\n          + ((1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2))\u2016\n        \u2264 \u2016Complex.log (w + 2) - Complex.log w\u2080\u2016\n          + \u2016(1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)\u2016 :=\n      norm_add_le _ _\n    have hc5 : \u2016r1 - r0\u2016 \u2264 \u2016r1\u2016 + \u2016r0\u2016 := norm_sub_le _ _\n    linarith [hc1, hc2, hc3, hc4, hc5, hL, h12, hw1b, hw1'b, hr1le, hr0le]\n  -- the fold to 6/t\n  have h2norm : \u2016(2 : \u2102)\u2016 = 2 := by\n    rw [show (2 : \u2102) = ((2 : \u211d) : \u2102) by push_cast; ring, Complex.norm_real]\n    norm_num\n  rw [hw, hw\u2080, norm_div, h2norm]\n  rw [div_le_iff\u2080 (by norm_num : (0 : \u211d) < 2)]\n  have h1 : (3 : \u211d) / (t / 2) ^ 2 = 12 / t ^ 2 := by\n    field_simp\n    ring\n  have hsum : 5 / t + 5 / t ^ 2 + (2 / t + 2 / t) + (12 / t ^ 2 + 12 / t ^ 2)\n      = 9 / t + 29 / t ^ 2 := by\n    field_simp\n    ring\n  have hkey : 9 / t + 29 / t ^ 2 \u2264 12 / t := by\n    rw [show (12 : \u211d) / t = 12 * t / t ^ 2 by field_simp; ring]\n    rw [show 9 / t + 29 / t ^ 2 = (9 * t + 29) / t ^ 2 by field_simp; ring]\n    apply div_le_div_of_nonneg_right _ (by positivity : (0 : \u211d) \u2264 t ^ 2)\n    nlinarith [ht]\n  calc \u2016Complex.digamma w - Complex.digamma w\u2080\u2016\n      \u2264 5 / t + 5 / t ^ 2 + (2 / t + 2 / t) + (3 / (t / 2) ^ 2 + 3 / (t / 2) ^ 2) := hnorm\n    _ = 9 / t + 29 / t ^ 2 := by rw [h1]; rw [hsum]\n    _ \u2264 12 / t := hkey\n    _ = 6 / t * 2 := by ring\n\nend NguyenRH1\n\nend"
}
#1757 assistant 2026-08-24 11:28:00.469 UTC · 691→4304 tok open ⤢
thinking (241 chars)
The sorry draft is at lines 599–618 (from `rw [← hint]` through the digamma_diff_le sorry). I'll replace lines 599–618 with the complete hbound proof + the complete digamma_diff_le. Let me do the edit with the exact old text (lines 599–618).
Replacing the sorry draft (lines 599–618) with the complete proofs.
tool: Edit
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean",
  "old_string": "  rw [\u2190 hint]\n  have hbound : \u2200 y \u2208 Set.uIoc (0 : \u211d) 1,\n      \u2016((z y)\u207b\u00b9) * ((c : \u211d) : \u2102)\u2016 \u2264 5 / t := by\n    intro y hy\n    have h1 : \u2016((z y)\u207b\u00b9) * ((c : \u211d) : \u2102)\u2016 = \u2016z y\u2016\u207b\u00b9 * |c| := by\n      rw [norm_mul, norm_inv]\n      rw [show ((c : \u211d) : \u2102) = (((|c| : \u211d)) : \u2102) * ... ] -- hmm no\n      sorry\n    sorry\n  sorry\n\n/-- **Piece 6** (D-069 \u00a73): the digamma difference\n\u00bd\u2016\u03c8(s/2) \u2212 \u03c8(s\u2080/2)\u2016 \u2264 6/t. Via the +2 shift (re(w+2) \u2265 3/4), Zeta23's\ndigamma_stirling at w+2 and w\u2080, the recurrence \u03c8(w) = \u03c8(w+2) \u2212 w\u207b\u00b9 \u2212\n(w+1)\u207b\u00b9, and the segment-FTC log bound. -/\ntheorem digamma_diff_le {t : \u211d} (ht : 10 \u2264 t) {s : \u2102}\n    (h\u03c3lo : -5 / 2 \u2264 s.re) (h\u03c3hi : s.re \u2264 3) (him : s.im = t) :\n    \u2016(Complex.digamma (s / 2) - Complex.digamma ((2 + t * Complex.I) / 2)) / 2\u2016\n      \u2264 6 / t := by\n  sorry\n\nend NguyenRH1\n\nend",
  "new_string": "  rw [\u2190 hint]\n  have hbound : \u2200 y \u2208 Set.\u0399 (0 : \u211d) 1,\n      \u2016((z y)\u207b\u00b9) * ((c : \u211d) : \u2102)\u2016 \u2264 5 / t := by\n    intro y _\n    have hzy : (0 : \u211d) < \u2016z y\u2016 := by\n      have h := hznorm y\n      positivity\n    have h1 : \u2016((z y)\u207b\u00b9) * ((c : \u211d) : \u2102)\u2016 = \u2016z y\u2016\u207b\u00b9 * |c| := by\n      rw [norm_mul, norm_inv, Complex.norm_real]\n    rw [h1]\n    have h2 : \u2016z y\u2016\u207b\u00b9 \u2264 (t / 2)\u207b\u00b9 := by\n      rw [inv_le_inv\u2080 hzy (by positivity : (0 : \u211d) < t / 2)]\n      exact hznorm y\n    calc \u2016z y\u2016\u207b\u00b9 * |c| \u2264 (t / 2)\u207b\u00b9 * (5 / 2) :=\n        mul_le_mul h2 hcle (abs_nonneg _) (by positivity)\n      _ = 5 / t := by field_simp\n  calc \u2016\u222b y in (0 : \u211d)..(1 : \u211d), ((z y)\u207b\u00b9) * ((c : \u211d) : \u2102)\u2016\n      \u2264 (5 / t) * |1 - 0| := intervalIntegral.norm_integral_le_of_norm_le_const hbound\n    _ = 5 / t := by norm_num [abs_one]\n\n/-- **Piece 6** (D-069 \u00a73): the digamma difference\n\u00bd\u2016\u03c8(s/2) \u2212 \u03c8(s\u2080/2)\u2016 \u2264 6/t. Via the +2 shift (re(w+2) \u2265 3/4), Zeta23's\ndigamma_stirling at w+2 and w\u2080, the recurrence \u03c8(w) = \u03c8(w+2) \u2212 w\u207b\u00b9 \u2212\n(w+1)\u207b\u00b9, and the segment-FTC log bound. -/\ntheorem digamma_diff_le {t : \u211d} (ht : 10 \u2264 t) {s : \u2102}\n    (h\u03c3lo : -5 / 2 \u2264 s.re) (h\u03c3hi : s.re \u2264 3) (him : s.im = t) :\n    \u2016(Complex.digamma (s / 2) - Complex.digamma ((2 + t * Complex.I) / 2)) / 2\u2016\n      \u2264 6 / t := by\n  have ht0 : (0 : \u211d) < t := by linarith\n  set w : \u2102 := s / 2 with hw\n  set w\u2080 : \u2102 := (2 + t * Complex.I) / 2 with hw\u2080\n  have hw\u2080eq : w\u2080 = 1 + (t / 2) * Complex.I := by rw [hw\u2080]; ring\n  have hwim : w.im = t / 2 := by rw [hw]; simp [him]\n  have hw\u2080im : w\u2080.im = t / 2 := by rw [hw\u2080eq]; simp\n  have himw : w.im \u2260 0 := by rw [hwim]; positivity\n  have hwre : w.re = s.re / 2 := by rw [hw]; simp\n  have hw\u2080re : (0 : \u211d) < w\u2080.re := by rw [hw\u2080eq]; simp\n  -- the recurrence: \u03c8(w + 2) = \u03c8(w) + w\u207b\u00b9 + (w+1)\u207b\u00b9\n  have hrec : Complex.digamma (w + 2) = Complex.digamma w + (w\u207b\u00b9 + (w + 1)\u207b\u00b9) := by\n    have h := digamma_add_natCast himw 2\n    rw [show w + ((2 : \u2115) : \u2102) = w + 2 by push_cast; ring] at h\n    rw [Finset.sum_range_succ, Finset.sum_range_succ, Finset.sum_range_zero] at h\n    simp only [Nat.cast_zero, add_zero, Nat.cast_one, zero_add] at h\n    exact h\n  -- the Stirling bounds at w + 2 and w\u2080\n  have hvre : (0 : \u211d) < (w + 2).re := by\n    have h : (w + 2).re = w.re + 2 := by simp\n    rw [h, hwre]\n    linarith [h\u03c3lo]\n  have hvim : (w + 2).im = t / 2 := by\n    have h : (w + 2).im = w.im := by simp\n    rw [h, hwim]\n  have hStir1 := StirlingVert.digamma_stirling hvre (by\n    rw [hvim, abs_of_nonneg (by linarith : (0 : \u211d) \u2264 t / 2)]; linarith)\n  have hStir2 := StirlingVert.digamma_stirling hw\u2080re (by\n    rw [hw\u2080im, abs_of_nonneg (by linarith : (0 : \u211d) \u2264 t / 2)]; linarith)\n  -- the remainders\n  set r1 : \u2102 := Complex.digamma (w + 2) - Complex.log (w + 2) + (1 / 2) / (w + 2) with hr1\n  set r0 : \u2102 := Complex.digamma w\u2080 - Complex.log w\u2080 + (1 / 2) / w\u2080 with hr0\n  have hr1le : \u2016r1\u2016 \u2264 3 / (t / 2) ^ 2 := by\n    have h := hStir1\n    rw [hvim] at h\n    exact h\n  have hr0le : \u2016r0\u2016 \u2264 3 / (t / 2) ^ 2 := by\n    have h := hStir2\n    rw [hw\u2080im] at h\n    exact h\n  -- the decomposition\n  have hdecomp : Complex.digamma w - Complex.digamma w\u2080\n      = (Complex.log (w + 2) - Complex.log w\u2080)\n        + ((1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)) - w\u207b\u00b9 - (w + 1)\u207b\u00b9 + (r1 - r0) := by\n    rw [hr1, hr0]\n    linear_combination hrec\n  -- the pieces\n  have hL : \u2016Complex.log (w + 2) - Complex.log w\u2080\u2016 \u2264 5 / t := by\n    rw [hw, hw\u2080eq]\n    exact log_diff_le ht h\u03c3lo h\u03c3hi him\n  have hw0norm : t / 2 \u2264 \u2016w\u2080\u2016 := by\n    have h1 := abs_im_le_norm w\u2080\n    rw [hw\u2080im, abs_of_nonneg (by linarith : (0 : \u211d) \u2264 t / 2)] at h1\n    exact h1\n  have hw2norm : t / 2 \u2264 \u2016w + 2\u2016 := by\n    have h1 := abs_im_le_norm (w + 2)\n    rw [hvim, abs_of_nonneg (by linarith : (0 : \u211d) \u2264 t / 2)] at h1\n    exact h1\n  have hwnorm : t / 2 \u2264 \u2016w\u2016 := by\n    have h1 := abs_im_le_norm w\n    rw [hwim, abs_of_nonneg (by linarith : (0 : \u211d) \u2264 t / 2)] at h1\n    exact h1\n  have hw1norm : t / 2 \u2264 \u2016w + 1\u2016 := by\n    have h1 := abs_im_le_norm (w + 1)\n    have h2 : (w + 1).im = t / 2 := by simp [hwim]\n    rw [h2, abs_of_nonneg (by linarith : (0 : \u211d) \u2264 t / 2)] at h1\n    exact h1\n  have hw\u20800 : w\u2080 \u2260 0 := by\n    intro h\n    rw [h, norm_zero] at hw0norm\n    linarith\n  have hw2 : w + 2 \u2260 0 := by\n    intro h\n    rw [h, norm_zero] at hw2norm\n    linarith\n  have hw0 : w \u2260 0 := by\n    intro h\n    rw [h, norm_zero] at hwnorm\n    linarith\n  have hw1 : w + 1 \u2260 0 := by\n    intro h\n    rw [h, norm_zero] at hw1norm\n    linarith\n  have h12 : \u2016(1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)\u2016 \u2264 5 / t ^ 2 := by\n    have h1 : (1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)\n        = (1 / 2) * ((w + 2 - w\u2080) / (w\u2080 * (w + 2))) := by\n      field_simp\n      ring\n    have hsub : w + 2 - w\u2080 = ((s.re / 2 + 1 : \u211d) : \u2102) := by\n      have ht1 : w\u2080 + ((s.re / 2 + 1 : \u211d) : \u2102) = w + 2 := by\n        rw [hw, hw\u2080eq]\n        rw [Complex.ext_iff]\n        constructor\n        \u00b7 simp [hwre]\n          ring_nf\n        \u00b7 simp [hw\u2080im]\n          rw [hwim]\n      linear_combination ht1\n    rw [h1, hsub, norm_mul, norm_div, Complex.norm_real]\n    have hc : |s.re / 2 + 1| \u2264 5 / 2 := by\n      rw [abs_le]\n      constructor <;> linarith\n    have h12n : \u2016(1 / 2 : \u2102)\u2016 = 1 / 2 := by\n      rw [show (1 / 2 : \u2102) = ((1 / 2 : \u211d) : \u2102) by push_cast; ring, Complex.norm_real]\n      norm_num\n    rw [h12n]\n    have hprod : (t / 2) * (t / 2) \u2264 \u2016w\u2080\u2016 * \u2016w + 2\u2016 :=\n      mul_le_mul hw0norm hw2norm (by positivity) (by positivity)\n    calc (1 / 2) * (|s.re / 2 + 1| / (\u2016w\u2080\u2016 * \u2016w + 2\u2016))\n        \u2264 (1 / 2) * ((5 / 2) / (\u2016w\u2080\u2016 * \u2016w + 2\u2016)) := by\n          apply mul_le_mul_of_nonneg_left _ (by norm_num)\n          exact div_le_div_of_nonneg_right hc (by positivity)\n      _ \u2264 (1 / 2) * ((5 / 2) / ((t / 2) * (t / 2))) := by\n          apply mul_le_mul_of_nonneg_left _ (by norm_num)\n          exact div_le_div_of_nonneg_left (by norm_num) (by positivity) hprod\n      _ = 5 / t ^ 2 := by field_simp; ring\n  have hw1b : \u2016(w : \u2102)\u207b\u00b9\u2016 \u2264 2 / t := by\n    rw [norm_inv]\n    have hpos : (0 : \u211d) < \u2016w\u2016 := by positivity\n    calc \u2016w\u2016\u207b\u00b9 \u2264 (t / 2)\u207b\u00b9 := by\n          rw [inv_le_inv\u2080 hpos (by positivity : (0 : \u211d) < t / 2)]\n          exact hwnorm\n      _ = 2 / t := by rw [inv_div]\n  have hw1'b : \u2016(w + 1 : \u2102)\u207b\u00b9\u2016 \u2264 2 / t := by\n    rw [norm_inv]\n    have hpos : (0 : \u211d) < \u2016w + 1\u2016 := by positivity\n    calc \u2016w + 1\u2016\u207b\u00b9 \u2264 (t / 2)\u207b\u00b9 := by\n          rw [inv_le_inv\u2080 hpos (by positivity : (0 : \u211d) < t / 2)]\n          exact hw1norm\n      _ = 2 / t := by rw [inv_div]\n  -- the norm chain\n  have hnorm : \u2016Complex.digamma w - Complex.digamma w\u2080\u2016\n      \u2264 5 / t + 5 / t ^ 2 + (2 / t + 2 / t) + (3 / (t / 2) ^ 2 + 3 / (t / 2) ^ 2) := by\n    rw [hdecomp]\n    have hc1 : \u2016(Complex.log (w + 2) - Complex.log w\u2080)\n          + ((1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)) - w\u207b\u00b9 - (w + 1)\u207b\u00b9 + (r1 - r0)\u2016\n        \u2264 \u2016(Complex.log (w + 2) - Complex.log w\u2080)\n          + ((1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)) - w\u207b\u00b9 - (w + 1)\u207b\u00b9\u2016 + \u2016r1 - r0\u2016 :=\n      norm_add_le _ _\n    have hc2 : \u2016(Complex.log (w + 2) - Complex.log w\u2080)\n          + ((1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)) - w\u207b\u00b9 - (w + 1)\u207b\u00b9\u2016\n        \u2264 \u2016(Complex.log (w + 2) - Complex.log w\u2080)\n          + ((1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)) - w\u207b\u00b9\u2016 + \u2016(w + 1)\u207b\u00b9\u2016 :=\n      norm_sub_le _ _\n    have hc3 : \u2016(Complex.log (w + 2) - Complex.log w\u2080)\n          + ((1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)) - w\u207b\u00b9\u2016\n        \u2264 \u2016(Complex.log (w + 2) - Complex.log w\u2080)\n          + ((1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2))\u2016 + \u2016w\u207b\u00b9\u2016 :=\n      norm_sub_le _ _\n    have hc4 : \u2016(Complex.log (w + 2) - Complex.log w\u2080)\n          + ((1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2))\u2016\n        \u2264 \u2016Complex.log (w + 2) - Complex.log w\u2080\u2016\n          + \u2016(1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)\u2016 :=\n      norm_add_le _ _\n    have hc5 : \u2016r1 - r0\u2016 \u2264 \u2016r1\u2016 + \u2016r0\u2016 := norm_sub_le _ _\n    linarith [hc1, hc2, hc3, hc4, hc5, hL, h12, hw1b, hw1'b, hr1le, hr0le]\n  -- the fold to 6/t\n  have h2norm : \u2016(2 : \u2102)\u2016 = 2 := by\n    rw [show (2 : \u2102) = ((2 : \u211d) : \u2102) by push_cast; ring, Complex.norm_real]\n    norm_num\n  rw [hw, hw\u2080, norm_div, h2norm]\n  rw [div_le_iff\u2080 (by norm_num : (0 : \u211d) < 2)]\n  have h1 : (3 : \u211d) / (t / 2) ^ 2 = 12 / t ^ 2 := by\n    field_simp\n    ring\n  have hsum : 5 / t + 5 / t ^ 2 + (2 / t + 2 / t) + (12 / t ^ 2 + 12 / t ^ 2)\n      = 9 / t + 29 / t ^ 2 := by\n    field_simp\n    ring\n  have hkey : 9 / t + 29 / t ^ 2 \u2264 12 / t := by\n    rw [show (12 : \u211d) / t = 12 * t / t ^ 2 by field_simp; ring]\n    rw [show 9 / t + 29 / t ^ 2 = (9 * t + 29) / t ^ 2 by field_simp; ring]\n    apply div_le_div_of_nonneg_right _ (by positivity : (0 : \u211d) \u2264 t ^ 2)\n    nlinarith [ht]\n  calc \u2016Complex.digamma w - Complex.digamma w\u2080\u2016\n      \u2264 5 / t + 5 / t ^ 2 + (2 / t + 2 / t) + (3 / (t / 2) ^ 2 + 3 / (t / 2) ^ 2) := hnorm\n    _ = 9 / t + 29 / t ^ 2 := by rw [h1]; rw [hsum]\n    _ \u2264 12 / t := hkey\n    _ = 6 / t * 2 := by ring\n\nend NguyenRH1\n\nend"
}
#1758 assistant 2026-08-24 11:31:50.531 UTC · 1041→5045 tok open ⤢
thinking (13630 chars)
Issues in log_diff_le: 1. **Line 571** "No goals to be solved" — in htarget (the endpoint ext_iff): one of the bullets closed early. Line 571 is in htarget's first bullet: `rw [h1]; simp [...]; ring_nf` — the simp closed the goal, ring_nf has no goals. Let me check what line 571 is exactly. 2. **Line 578** (hanti's h1): the comp argument mismatch — the hasDerivAt_id' (...).mul_const produced `HasDerivAt (fun u => u * ↑c) (1 * ↑c)`... the issue: `.mul_const` vs `.const_mul`: HasDerivAt.mul_const (h : HasDerivAt f f' x) (c) : HasDerivAt (fun x => f x * c) (f' * c) x. With hasDerivAt_id' (↑y) : HasDerivAt (fun z => z)? 1... hmm wait hasDerivAt_id' gives HasDerivAt id 1? or (fun x => x)? The error: hasDerivAt_log (hzslit y) : HasDerivAt log (z y)⁻¹ (z y) — and comp's expected: HasDerivAt ?f ?f' (w₀ + ↑y·↑c) — so the affine argument's VALUE at ↑y must be (z y) = w₀ + ↑(y·c) — and my affine function is (fun u => w₀ + u·↑c) — at ↑y: w₀ + ↑y·↑c — but z y = w₀ + ↑(y·c) — ↑(y·c) vs ↑y·↑c: DIFFERENT syntactically (cast of product vs product of casts) — defeq via push_cast but the comp's unification failed to match HasDerivAt log _ (w₀ + ↑y·↑c) with HasDerivAt log _ (z y)?? wait no — the error is: hasDerivAt_log (hzslit y) has type HasDerivAt log (z y)⁻¹ (z y) but expected HasDerivAt ?f ?f' (w₀ + ↑y·↑c) — the .comp's first explicit arg is the POINT: `(Complex.hasDerivAt_log (hzslit y)).comp ((y:ℝ):ℂ) (affine-proof)` — comp (x) (h) where h : HasDerivAt g g' x and the log part is at g(x) — the elaborator needs hzslit y's point (z y) to match g(↑y) where g = fun u => w₀ + u·↑c: g(↑y) = w₀ + ↑y·↑c vs z y = w₀ + ↑(y·c): the unifier must see ↑(y·c) = ↑y·↑c — this is a cast-push — the comp's unification is syntactic-ish and FAILED (Application type mismatch: the arg (hzslit y) has point (z y) but expected (w₀ + ↑y·↑c)). Fix: make hzslit's statement use the w₀ + ↑y·↑c form, or change z's def to `fun y => w₀ + (y:ℂ) * ((c:ℝ):ℂ)` — the product-of-casts form — then z y = w₀ + ↑y·↑c syntactically ✓ and the cast push happens at the im/norm computations (push_cast there). Let me redefine z := fun y => w₀ + (y : ℂ) * ((c : ℝ) : ℂ). Then: - hzim: (z y).im = w₀.im + ((y:ℂ)·↑c).im = t/2 + y·0·... (↑c).im = 0: simp [Complex.add_im, Complex.mul_im, Complex.ofReal_im] ✓. - the affine: (hasDerivAt_id' ((y:ℝ):ℂ)).mul_const ↑c |>.const_add w₀ : HasDerivAt (fun u => w₀ + u·↑c) (↑c) ↑y — wait mul_const: (hasDerivAt_id' z).mul_const c' : HasDerivAt (fun u => u * c') (1 * c')? or (· * c)? The value: hasDerivAt_id' gives f' = 1; mul_const gives (fun u => u·c') with deriv (1·c')? hmm the Mathlib form: HasDerivAt.mul_const (h : HasDerivAt f f' x) (c : ℂ) : HasDerivAt (fun x => f x * c) (f' * c) x — so (hasDerivAt_id' ↑y).mul_const ↑c : HasDerivAt (fun u => u * ↑c) (1 * ↑c) ↑y — the deriv 1·↑c = ↑c ✓ (one_mul — the simpa [mul_comm] handles). Then .const_add w₀ : HasDerivAt (fun u => w₀ + u·↑c) (↑c) ↑y ✓. Then comp with hasDerivAt_log (hzslit y : z y ∈ slitPlane — with z y = w₀ + ↑y·↑c ✓ syntactic match!). comp gives: HasDerivAt (fun u => log (w₀ + u·↑c)) ((w₀ + ↑y·↑c)⁻¹ * ↑c)?? — the comp's value: log'(g(↑y)) * g'(↑y) = (z y)⁻¹ * ↑c — hmm order: HasDerivAt.comp (h : HasDerivAt f f' (g x)) (h' : HasDerivAt g g' x) : HasDerivAt (f ∘ g) (f' * g') x — value f'·g' = (z y)⁻¹ · ↑c — hmm that's (z y)⁻¹ * ↑c ✓ (f' * g' — mul order f' first ✓ matches my target ((z y)⁻¹) * ↑c ✓). Actually wait — from the error display, the comp DID elaborate but mismatched on the POINT: "expected to have type HasDerivAt ?m ?m (w₀ + ↑y * ↑c)" — the unification of the log part's point (z y) with g(↑y) = w₀ + ↑y·↑c: z y unfolds (set-let) to w₀ + ↑(y·c) — ↑(y·c) ≠ ↑y·↑c syntactically. So redefining z with the product-of-casts form fixes the match. Then hzim/hznorm/hzslit use the new form (adjust the simp sets). 3. **Line 581**: `h1.comp_ofReal` — h1 : HasDerivAt (fun u => log (w₀ + u·↑c)) ((z y)⁻¹·↑c) (↑y); comp_ofReal gives HasDerivAt (fun y:ℝ => log (w₀ + ↑y·↑c)) ... — expected (fun x => log (z x)): with z redefined as fun y => w₀ + ↑y·↑c, log (z x) = log (w₀ + ↑x·↑c) ✓ syntactic match ✓. 4. **Line 586** (hconti): the `Continuous.mul continuous_const` order — goal: Continuous fun y => (z y)⁻¹ * ↑c — my proof did Continuous.mul continuous_const (Continuous.inv₀ ...) — the args order: Continuous.mul (hf : Continuous f) (hg : Continuous g) : Continuous (f * g) where (f * g) x = f x * g x — with f = (z ·)⁻¹ and g = const ↑c: I wrote `Continuous.mul continuous_const (the-inv)` — that gives const * inv — WRONG ORDER. Fix: Continuous.mul (Continuous.inv₀ ...) continuous_const. But Continuous.inv₀ : Continuous f → (∀ x, f x ≠ 0) → Continuous (fun x => (f x)⁻¹) ✓. So: ```lean apply Continuous.continuousOn apply Continuous.mul · apply Continuous.inv₀ _ (fun y => by have h := hznorm y positivity) rw [hz] exact (continuous_const.add (Complex.continuous_ofReal.mul continuous_const)) · exact continuous_const ``` Hmm — Continuous.mul's result: Continuous ((fun y => (z y)⁻¹) * (fun y => ↑c))? the Pi.mul form vs (fun y => (z y)⁻¹ * ↑c): defeq via Pi.mul_apply — the goal `Continuous fun y => (z y)⁻¹ * ↑c` — the `apply Continuous.mul` unification: Continuous.mul's conclusion is Continuous (f * g) with the Pi.mul — (f * g) y = f y * g y — the goal's lambda fun y => (z y)⁻¹ * ↑c — unify (f*g) =?= fun y => ... — HOU — might fail. Safer: `refine Continuous.mul ?_ continuous_const`? Hmm — the banked gotcha from session 011: "Pi.mul_apply/Pi.add_apply/Pi.sub_apply simp after .mul/.add/.sub" — so after applying, simp [Pi.mul_apply] bridges. Let me write: ```lean have hconti : IntervalIntegrable (fun y : ℝ => ((z y)⁻¹) * ((c : ℝ) : ℂ)) volume 0 1 := by apply ContinuousOn.intervalIntegrable apply Continuous.continuousOn have hzcont : Continuous z := by rw [hz] exact continuous_const.add (Complex.continuous_ofReal.mul continuous_const) -- hmm z's form exact ((hzcont.inv₀ fun y => by have h := hznorm y positivity).mul continuous_const) ``` Hmm — Continuous.inv₀ (hf : Continuous f) (hf' : ∀ x, f x ≠ 0) : Continuous fun x => (f x)⁻¹ ✓. Then .mul continuous_const : Continuous ((fun y => (z y)⁻¹) * fun y => ↑c)? — Continuous.mul (hf : Continuous f) (hg : Continuous g) : Continuous (f * g) where f * g is Pi.mul — the target (fun y => (z y)⁻¹ * ↑c) vs ((fun y => (z y)⁻¹) * (fun y => ↑c)) — defeq via Pi.mul_apply ✓ exact should accept (defeq). The z-continuity: z = fun y => w₀ + (y:ℂ)·↑c: the function fun y => (↑(y·c))?? — with the redefined z := fun y => w₀ + (y:ℂ)·↑c: continuity: continuous_const.add (continuous_ofReal.mul continuous_const)? — (y:ℂ)·↑c: continuous_ofReal.mul continuous_const : Continuous (fun y => ↑y * ↑c)?? continuous_ofReal : Continuous (fun y => (↑y : ℂ)); .mul continuous_const : Continuous ((fun y => ↑y) * fun _ => ↑c) — Pi.mul form again — defeq to fun y => ↑y * ↑c ✓. Then continuous_const.add — Continuous.const.add? `Continuous.add (hf) (hg)` — continuous_const.add (h) : Continuous (fun y => w₀ + g y)? Continuous.add (hf : Continuous f) (hg : Continuous g) : Continuous (f + g) — so `continuous_const.add (h)` : Continuous (fun _ => w₀ + ...) — the const is f: Continuous (f + g) with f const: (fun _ => w₀) + g — Pi.add form — defeq to fun y => w₀ + g y ✓. So: ```lean have hzcont : Continuous z := continuous_const.add (Complex.continuous_ofReal.mul continuous_const) ``` Hmm — z's body: fun y => w₀ + ↑y * ↑c — and (fun _ => w₀) + (fun y => ↑y * ↑c) applied at y: w₀ + ↑y*↑c ✓ defeq — but `exact hzcont` for goal Continuous z where z is the set-var: z is let-defined as fun y => w₀ + ↑y*↑c; hzcont : Continuous ((fun _ => w₀) + fun y => ↑y * ↑c)?? no — Continuous.add f g gives Continuous (f + g) — is that defeq to Continuous (fun y => w₀ + ↑y*↑c)? (f + g) y = f y + g y = w₀ + ↑y*↑c ✓ eta/Pi-defeq ✓ exact should work (set-let transparent). Hmm wait — but does z's definition `fun y => w₀ + (y:ℂ) * ((c:ℝ):ℂ)` match `(fun _ => w₀) + (fun y => (y:ℂ) * ↑c)`? the (y:ℂ) — continuous_ofReal is Continuous (fun y => (↑y : ℂ)) where ↑y = ((y:ℝ):ℂ) ✓ matches (y:ℂ). OK. Actually, from the earlier error the issue was just the ARGUMENT ORDER of Continuous.mul (const first vs second). And the defeq-matching worked via `exact` in 5d's similar code. Let me restructure with the fix and the defeq-friendly forms. 5. **Line 594** (hint): unsolved goals — from the hanti failure cascade. Will revisit after fixing hanti. Let me fix the z definition and hanti/hconti. Current z def in the file: `set z : ℝ → ℂ := fun y => w₀ + ((y * c : ℝ) : ℂ) with hz`. Change to `fun y => w₀ + (y : ℂ) * ((c : ℝ) : ℂ)`. Then hzim's simp: (z y).im = (w₀ + ↑y*↑c).im = w₀.im + (↑y*↑c).im = t/2 + (↑y·0 − 0·↑c)·... (↑y*↑c).im = ↑y·(↑c).im... = y·0 − 0·c = 0: simp [Complex.add_im, Complex.mul_im, Complex.ofReal_im, Complex.ofReal_re] ✓. hznorm: unchanged (uses hzim ✓). hzslit: unchanged ✓. htarget: unchanged (doesn't involve z) ✓. hanti: the comp now matches syntactically. Rewrite: ```lean have hanti : ∀ y ∈ Set.uIcc (0 : ℝ) 1, HasDerivAt (fun x : ℝ => Complex.log (z x)) (((z y)⁻¹) * ((c : ℝ) : ℂ)) y := by intro y _ have h1 : HasDerivAt (fun u : ℂ => Complex.log (w₀ + u * ((c : ℝ) : ℂ))) (((z y)⁻¹) * ((c : ℝ) : ℂ)) ((y : ℝ) : ℂ) := by have h2 := (Complex.hasDerivAt_log (hzslit y)).comp ((y : ℝ) : ℂ) (((hasDerivAt_id' ((y : ℝ) : ℂ)).mul_const ((c : ℝ) : ℂ)).const_add w₀) -- h2 : HasDerivAt (log ∘ (fun u => w₀ + u·↑c)) (↑c * ...)? value form simpa [hz, Function.comp_def, mul_comm] using h2 exact h1.comp_ofReal ``` The comp value: HasDerivAt.comp's value is g' • f'?? — for ℂ: HasDerivAt.comp (hf : HasDerivAt f f' (g x)) (hg : HasDerivAt g g' x) : HasDerivAt (f ∘ g) (f' * g') x? — the ℂ form: the derivative of f∘g is (f' at g x) * g' — so value = (z y)⁻¹ * (↑c) — hmm wait: f' = (z y)⁻¹ (log deriv), g' = ↑c (the affine deriv — from mul_const: (hasDerivAt_id' ↑y).mul_const ↑c : HasDerivAt (fun u => u * ↑c) (1 * ↑c)? — mul_const (h : HasDerivAt f f' x) (c) : HasDerivAt (fun x => f x * c) (f' * c) x — with f' = 1: 1 * ↑c — then const_add w₀ keeps deriv 1*↑c — so g' = 1 * ↑c = ↑c). comp value: f' * g' = (z y)⁻¹ * (1 * ↑c) — simpa [mul_comm, one_mul] normalizes to (z y)⁻¹ * ↑c ✓ — my simpa set [hz, Function.comp_def, mul_comm] — add one_mul: simpa [hz, Function.comp_def, mul_comm, one_mul]. Hmm — but the Function.comp_def: (log ∘ g) u = log (g u) ✓. And my h1's stated value ((z y)⁻¹) * ↑c — after simpa normalization ✓ hopefully. The exact h1.comp_ofReal : HasDerivAt (fun y:ℝ => (log ∘ affine) ↑y) (...) y — comp_ofReal gives the real-parameter version: HasDerivAt (fun y : ℝ => f (↑y)) (f'·1)? — comp_ofReal : HasDerivAt f f' (↑y) → HasDerivAt (fun y : ℝ => f ↑y) f' y — the value: f' * (ofReal-deriv 1) = f' — hmm: `HasDerivAt.comp_ofReal (h : HasDerivAt f f' (ofReal y)) : HasDerivAt (fun y => f (ofReal y)) f' y`? I think comp_ofReal gives deriv f' * 1 = f' — roughly. The 5d code used `exact h1.comp_ofReal` with h1's ℂ-value ((w + (x:ℂ))⁻¹) matching the target ✓ same pattern ✓. Also `hasDerivAt_id'` — check: hasDerivAt_id' (x) : HasDerivAt (fun x => x) 1 x ✓ (from the 5d usage: (hasDerivAt_id' (x:ℂ)).const_add w ✓ they used const_add for w + z; I use mul_const + const_add ✓ both exist). 6. The htarget bullets' "No goals" (line 571): the bullet: ```lean · have h1 : (s / 2 + 2).re = s.re / 2 + 2 := by simp rw [h1] simp [Complex.add_re, Complex.ofReal_re] ring_nf ``` the simp [Complex.add_re, Complex.ofReal_re] may have closed the goal (leaving ring_nf with no goals → error). Fix: drop the ring_nf and see, or use `simp [...]; ring_nf` pattern with `first | rfl | ring_nf`... Let me restructure htarget's bullets to compute the re/im directly: ```lean have htarget : w₀ + ((c : ℝ) : ℂ) = s / 2 + 2 := by rw [hw₀, hc] rw [Complex.ext_iff] constructor · simp [Complex.add_re, Complex.ofReal_re] ring_nf · simp [Complex.add_im, Complex.ofReal_im, him] ``` The re-goal: (1 + (t/2)·I + ↑(s.re/2+1)).re = (s/2 + 2).re — simp evaluates both sides' re: LHS: 1 + 0 + (s.re/2+1) = s.re/2 + 2; RHS: (s/2+2).re = s.re/2 + 2·... simp computes (s/2).re = s.re/2? — Complex.div_re? (s/2).re: simp might give s.re/2 via `Complex.div_re`... risky. Alternative: compute the sides via explicit haves with `abs_re...` no. Hmm — from piece-2/4-5, `(s/2 + 2).re = s.re/2 + 2 := by simp` — did I verify that? I wrote `have h1 : (s / 2 + 2).re = s.re / 2 + 2 := by simp` in the draft — UNTESTED. The (s/2).re: s/2 is complex division — (s/2).re = s.re/2 — the simp lemma is `Complex.div_re`? (a/b).re = (a.re*b.re + a.im*b.im)/(...) — ugly for general b, but for b = 2 (real literal): simp should simplify to s.re/2 — hmm. If `by simp` fails for (s/2+2).re, use: (s/2 + 2).re = s.re/2 + 2 via: s/2 = s * (1/2)... let me just test compile and see. Given uncertainty, let me write htarget with maximally explicit simp sets and fallbacks. Actually — you know what, let me simplify the whole endpoint dance: instead of htarget (w₀ + ↑c = s/2 + 2), note the FTC's endpoint is z 1 = w₀ + ↑1·↑c = w₀ + ↑c, and I want log (z 1) = log (s/2 + 2). The z-1 endpoint: z 1 = w₀ + (↑1)·↑c = w₀ + ↑c (one_mul, Nat.cast_one). And I need z 1 = s/2 + 2. The content: w₀ + ↑c = s/2 + 2 where w₀ = 1 + (t/2)I, c = s.re/2 + 1: w₀ + ↑c = (1 + s.re/2 + 1) + (t/2)I = (s.re/2 + 2) + (t/2)·I; s/2 + 2: re = s.re/2 + 2, im = s.im/2 + 0 = t/2. So both have re s.re/2+2, im t/2 ✓. Let me write it via Complex.ext with simp + ring_nf and adjust based on errors. Let me now make all the fixes.
Applying the z-definition fix (product-of-casts for the comp match) and the continuity order fix.
tool: Read
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean",
  "offset": 526,
  "limit": 95
}
#1759 assistant 2026-08-24 11:35:24.253 UTC · 870→3271 tok open ⤢
thinking (7853 chars)
Three errors: 1. **Line 564** (htarget re-bullet): after `rw [h1]; simp [Complex.add_re, Complex.ofReal_re]`, the remaining goal: `1 + (s.re / 2 + 1) = s.re / 2 + 2` — the simp evaluated (w₀ + ↑c).re to 1 + (s.re/2+1) and (s/2+2).re was rewritten by h1 to s.re/2+2 — so remaining: 1 + (s.re/2 + 1) = s.re/2 + 2 — a pure arithmetic identity — `ring_nf` would close but I removed it. The simp didn't close. Add `ring` or linarith: `simp [...]` then the arithmetic. Let me change the bullets to `simp [...]` then handle: actually the cleanest: after rw [h1], goal is (1 + ↑(s.re/2+1) + 0...).re-form — the simp left `1 + (s.re/2 + 1) = s.re/2 + 2`. Add `ring` after the simp. Hmm wait — but earlier the "No goals" was because simp CLOSED it and ring_nf errored. Now simp DIDN'T close (left the arithmetic). The behavior changed because the z form changed? No — htarget didn't change... earlier error was at line 571 (the im bullet's ring_nf had no goals because simp [Complex.add_im, Complex.ofReal_im] closed it). Now with the new simp set [Complex.add_im, Complex.ofReal_im, Complex.ofReal_re] it leaves something? The current error at 564 is the RE bullet (left case of the constructor): after simp, goal 1 + (s.re/2+1) = s.re/2+2 — needs `ring`. So: bullet 1: simp [...]; ring? But if simp closes it fully, ring errors "no goals". Ugh — inconsistent simp behavior. Safest: `simp [...]` then `ring_nf` only if needed — use `first | rfl | ring` — hmm. Or: `simp only [...]; ring` — simp only never fully closes (it only rewrites with the given lemmas; if it closes the goal it's fine... actually simp only CAN close goals). The robust pattern from the banked gotchas: `convert ... <;> first | rfl | ring` — hmm. Let me use: `· rw [h1]; simp only [Complex.add_re, Complex.ofReal_re, Complex.mul_re, ...]` — the minimal rewrite set then ring. The LHS (w₀ + ↑c).re with w₀ = 1 + (t/2)·I: (1 + (t/2)I + ↑c).re = 1 + 0 + (s.re/2+1): via Complex.add_re twice + the re of (t/2)·I (mul_re: ((t/2)·I).re = (t/2)·0 − 0·1 = 0) + ofReal_re (↑c → c). So: ```lean · rw [h1] simp only [Complex.add_re, Complex.mul_re, Complex.ofReal_re, Complex.I_re, Complex.I_im, Complex.one_re] ring ``` After simp only: (1).re + ((t/2)·I).re + (↑c).re... = 1 + ((t/2)·0 − 0·1) + c = 1 + c — then goal 1 + c = s.re/2 + 2 with c := s.re/2 + 1 — the set-var c — ring doesn't know c's value! c is a set variable: ring treats it as an atom — 1 + c = s.re/2 + 2 with c = s.re/2+1 is NOT a ring identity (needs hc). So: rw [hc] first or linarith [hc]? hc : c = s.re/2 + 1 — linarith [hc]: from hc, 1 + c = 1 + s.re/2 + 1 = s.re/2 + 2 ✓ linarith. But wait — I did rw [hw₀, hc] at the START of htarget — so the goal's c was already replaced by s.re/2+1?? — the error shows the goal `1 + (s.re / 2 + 1) = s.re / 2 + 2` — yes c was unfolded (rw [hc] at the start replaced c by s.re/2+1 in the GOAL but c remains a let-var in context; the goal has the unfolded form ✓). So after simp only, goal: 1 + (s.re/2+1) = s.re/2+2 — pure ring identity ✓ `ring` closes. So bullet 1: rw [h1]; simp only [...]; ring. Wait — but the simp only must reduce (w₀ + ↑c).re where w₀ was unfolded by rw [hw₀] to 1 + (t/2)·I... the goal at htarget after rw [hw₀, hc]: (1 + ↑t/2·I + ↑(s.re/2+1)) = s/2 + 2 — wait hw₀ : w₀ = 1 + ↑t/2·I — rw [hw₀] rewrites w₀ → that. hc : c = s.re/2+1 — rw [hc] rewrites c → s.re/2+1 — but the goal has ↑c (the ℂ cast of c) — rw [hc] rewrites c inside ↑c? The goal's term: ((c:ℝ):ℂ) = ((s.re/2+1 : ℝ):ℂ) after rw [hc] ✓ (rw rewrites c everywhere incl. under the cast ✓). Then ext_iff: re: (1 + ↑t/2·I + ↑(s.re/2+1)).re = (s/2+2).re — rw [h1] for RHS ✓; simp only for LHS's re: needs (1 + (t/2)·I + ↑(s.re/2+1)).re = 1 + (s.re/2+1): simp only [Complex.add_re, Complex.mul_re, Complex.one_re, Complex.ofReal_re, Complex.I_re, Complex.I_im, Complex.ofReal_im, mul_zero, ...]... The OfNat (t/2 — wait t/2 : ℝ — (↑t/2 : ℝ)·I: ((↑t/2:ℝ)·I).re = (↑t/2)·I.re − (↑t/2)·... Complex.mul_re: (a·b).re = a.re·b.re − a.im·b.im: a = ↑(t/2) (real cast): a.re = t/2, a.im = 0; b = I: I.re = 0, I.im = 1: = (t/2)·0 − 0·1 = 0. simp only with those lemmas + mul_zero/sub_zero gives 0. Then 1 + 0 + (s.re/2+1) = s.re/2+2 by ring ✓. This is getting into the weeds — let me just use plain `simp` (which closed these before — the earlier "No goals" was because simp closed and then ring_nf errored; the current simp-only-then-ring approach: simp closed the re bullet to the arithmetic form but didn't finish). Safest: `simp [...]` then `first | ring | rfl`... or just `<;> try ring_nf`... Let me use: `· rw [h1]; simp [Complex.add_re, Complex.mul_re, Complex.ofReal_re]; ring_nf` — hmm if simp closes it, ring_nf errors. The clean robust: ```lean · rw [h1] simp only [Complex.add_re, Complex.mul_re, Complex.one_re, Complex.ofReal_re, Complex.I_re, Complex.I_im, mul_zero, sub_zero] ring ``` For the im bullet (h1 : (s/2+2).im = t/2): goal (1 + (t/2)I + ↑(s.re/2+1)).im = t/2: simp only [Complex.add_im, Complex.mul_im, Complex.one_im, Complex.ofReal_im, Complex.I_im, Complex.I_re, ...]: LHS: 0 + ((t/2)·1 + 0·0) + 0 = t/2 ✓ then `ring`? t/2 = t/2 rfl — ring closes ✓. But wait — after rw [h1] the RHS is t/2 — LHS evaluates to 0 + (t/2·1 − 0·0)... = t/2: ring closes ✓. 2. **Line 588** (hconti): "failed to prove nonzeroness" — the inv₀'s side goal z y ≠ 0: my `fun y => by have h := hznorm y; positivity` — positivity can't derive z y ≠ 0 from hznorm (t/2 ≤ ‖z y‖). The inv₀ needs z y ≠ 0: from hznorm y : t/2 ≤ ‖z y‖ and t/2 ≥ 5 > 0 ⟹ ‖z y‖ > 0 ⟹ z y ≠ 0 (norm_pos_iff). Fix: ```lean exact (hzcont.inv₀ fun y => by have h := hznorm y rw [ne_eq, ← norm_pos_iff] linarith [h, ht0]).mul continuous_const ``` Hmm — norm_pos_iff : 0 < ‖a‖ ↔ a ≠ 0 — I need z y ≠ 0: from t/2 ≤ ‖z y‖ and t/2 > 0: ‖z y‖ > 0 ⟹ ≠ 0: `(norm_pos_iff.mp (by linarith [hznorm y, ht0]))`. So: ```lean exact (hzcont.inv₀ fun y => norm_pos_iff.mp (by linarith [hznorm y, ht0])).mul continuous_const ``` 3. **Line 595** (hint): `rw [htarget]` failed — the goal is `log (w₀ + ↑1 * ↑c) - log (w₀ + ↑0 * ↑c) = log (s/2+2) - log w₀`: my simp only [Nat.cast_one, one_mul] — the ↑1·↑c: Nat.cast_one : ↑(1:ℕ) = (1:ℂ)?? — the (↑1 : ℂ)·↑c: simp only [Nat.cast_one] turns ↑1 into 1, one_mul turns 1·↑c into ↑c: w₀ + ↑c ✓ — but the error shows the goal still has `w₀ + ↑1 * ↑c` — the simp only didn't fire? The cast ↑(1:ℕ)... wait: z 1 = w₀ + (↑(1:ℝ))·↑c — the ↑(1:ℝ) is a REAL cast of 1, not Nat.cast: `Nat.cast_one` is for ℕ casts. z : ℝ → ℂ so z 1 has y := (1:ℝ): (↑(1:ℝ) : ℂ)·↑c — the coercion ℝ→ℂ of the real 1: `(1:ℝ)` cast: `Complex.ofReal_one : ((1:ℝ):ℂ) = 1` ✓. And z 0: ↑(0:ℝ): Complex.ofReal_zero. So the simp set should be [Complex.ofReal_one, one_mul, Complex.ofReal_zero] etc. But ALSO: after `rw [hz]`, the endpoints are (fun y => w₀ + ↑y*↑c) 1 and ... 0 — beta-redexes. The 5d code did `rw [intervalIntegral.integral_eq_sub_of_hasDerivAt hanti hconti]; simp [hv]` — using plain simp for the endpoint evaluation. Let me do: rw [hz]; simp [htarget]? — simp with htarget as a lemma: the endpoints evaluate to w₀ + ↑c and w₀ + 0 then htarget rewrites w₀ + ↑c → s/2+2 — hmm htarget is an equation w₀ + ↑c = s/2+2 — simp [htarget] uses it as a rewrite ✓. So: ```lean rw [intervalIntegral.integral_eq_sub_of_hasDerivAt hanti hconti] rw [hz] simp only [Complex.ofReal_one, one_mul, Complex.ofReal_zero, zero_mul, add_zero] rw [htarget] ``` Hmm — the z 0 endpoint: w₀ + ↑(0:ℝ)·↑c = w₀ + 0: Complex.ofReal_zero : ↑(0:ℝ) = 0; zero_mul: 0·↑c = 0; add_zero: w₀ + 0 = w₀ ✓. And the hint's RHS: log (s/2+2) − log w₀ — after rw [htarget] the LHS's log (w₀ + ↑c) → log (s/2+2) ✓ and log w₀ = log w₀ ✓ — closed by rfl? The goal after rw [htarget]: log (s/2+2) − log w₀ = log (s/2+2) − log w₀ ✓ rfl (rw auto-closes). Let me apply these three fixes.
Three fixes: the htarget bullets (ring after simp), the inv₀ nonzeroness, and the endpoint casts (ofReal forms).
tool: Edit
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean",
  "old_string": "    \u00b7 have h1 : (s / 2 + 2).re = s.re / 2 + 2 := by simp\n      rw [h1]\n      simp [Complex.add_re, Complex.ofReal_re]\n    \u00b7 have h1 : (s / 2 + 2).im = t / 2 := by simp [him]\n      rw [h1]\n      simp [Complex.add_im, Complex.ofReal_im, Complex.ofReal_re]",
  "new_string": "    \u00b7 have h1 : (s / 2 + 2).re = s.re / 2 + 2 := by simp\n      rw [h1]\n      simp only [Complex.add_re, Complex.mul_re, Complex.one_re, Complex.ofReal_re,\n        Complex.I_re, Complex.I_im, mul_zero, sub_zero, zero_mul]\n      ring\n    \u00b7 have h1 : (s / 2 + 2).im = t / 2 := by simp [him]\n      rw [h1]\n      simp only [Complex.add_im, Complex.mul_im, Complex.one_im, Complex.ofReal_im,\n        Complex.I_im, Complex.ofReal_re, mul_one, add_zero]"
}
#1760 assistant 2026-08-24 11:38:31.113 UTC · 799→3303 tok open ⤢
thinking (7676 chars)
Progress — the re bullet now reduces to `2 - (↑t * (1/2)).im + s.re * (1/2) = 2 + s.re * (1/2)` — needs (↑t·(1/2)).im = 0. My simp only set didn't include the mul_im evaluation. The goal shows `(↑t * (1/2)).im` — wait, that's (↑t * (1/2)).im — the (↑t/2 · I) got... hmm interesting: the form is `↑t * (1/2)` — so the (t/2)·I was rewritten... the goal `2 - (↑t * (1/2)).im + s.re * (1/2) = 2 + s.re * (1/2)` — needs (↑t * (1/2)).im = 0: ((↑t)·(1/2:ℂ)).im = t·(1/2).im = 0: `(1/2 : ℂ).im = 0` — via OfNat/division simp: (1/2:ℂ).im — simp only [Complex.div_im]? or since (1/2:ℂ) is real-valued... Let me add `Complex.mul_im` and the OfNat-im evaluation. Actually — simpler: the whole issue is my simp-only set is fighting the (↑t/2)·I form. Let me just use a bigger simp set: `simp [Complex.add_re, Complex.mul_re, Complex.mul_im, Complex.ofReal_re, Complex.ofReal_im, Complex.I_re, Complex.I_im]` and then `ring` if anything remains. Plain simp should fully evaluate all the .re/.im of literal-ish terms. Earlier `by simp` alone didn't fully close (left the arithmetic) — so `simp [...]; ring` hmm but simp might close. The pattern that works per the error: the goal after my simp only was partially evaluated. Let me use: `simp only [Complex.add_re, Complex.mul_re, Complex.mul_im, Complex.ofReal_re, Complex.ofReal_im, Complex.I_re, Complex.I_im]` + handle the `(↑t * (1/2)).im`: (↑t * (1/2:ℂ)).im — via mul_im: (↑t).re·(1/2).im + (↑t).im·(1/2).re = t·0 + 0·(1/2) = 0: needs (1/2:ℂ).im = 0 and .re = 1/2: those are OfNat-division — simp only doesn't evaluate (1/2:ℂ).im without a lemma. There's `Complex.div_im`? (a/b).im = (a.im*b.re − a.re*b.im)/(...) — for b = 2: (1·2 − 0)/(4) hmm. Ugh. The clean fix: avoid the (t/2)·I form — write w₀ := 1 + ((t/2 : ℝ) : ℂ)·I: the cast-first form: ((t/2:ℝ):ℂ)·I: mul_im: ((t/2:ℝ):ℂ).re·1 + ((t/2:ℝ):ℂ).im·0·... = (t/2)·1 − 0·0... (a·I).im = a.re: via mul_im: (a.re·I.re... I.re = 0, I.im = 1: (a·I).im = a.re·1 + a.im·0 = a.re = t/2 ✓. So w₀ := 1 + ((t/2 : ℝ):ℂ) * Complex.I. Then (w₀).re = 1 + (t/2), .im = t/2 directly via mul_re/mul_im + ofReal_re/ofReal_im + I_re/I_im ✓ clean. Let me redefine w₀ that way and check hw₀eq (w₀ = (2 + t·I)/2 — the bridge: 1 + ((t/2:ℝ):ℂ)·I = (2 + t·I)/2: by Complex.ext: re: 1 + t/2 = (2+t·I...).re/... hmm — ext: re: (1 + ↑((t/2))·I).re = 1 + t/2; ((2 + t·I)/2).re = (2 + t·I).re/2 = 2/2 = 1?? — wait ((2+t·I)/2).re = (2+t·I).re/2 = 2/2 = 1? No: (2+t·I).re = 2, so /2 gives 1 ✓ and im: ((2+tI)/2).im = t/2 ✓. So ext: re: 1 + t/2 vs 1 — NO WAIT: (1 + ↑(t/2)·I).re = 1 + 0 = 1 (the ↑(t/2)·I has re 0). And ((2+tI)/2).re = 1. So re: 1 = 1 ✓; im: t/2 = t/2 ✓. So hw₀eq : (2 + t*I)/2 = 1 + ↑(t/2)*I: by rw [Complex.ext_iff]; constructor <;> simp [Complex.div_re, ...]... hmm the (2+tI)/2's re: via `Complex.div_re`? or since 2 = ((2:ℝ):ℂ): (2 + tI)/2 = (2+tI)·((1/2:ℝ):ℂ)?? Let me just: hw₀eq : (2 + t * Complex.I) / 2 = 1 + ((t / 2 : ℝ) : ℂ) * Complex.I := by rw [Complex.ext_iff]; constructor <;> [simp; simp] — the re: ((2+tI)/2).re = 2/2?? — (a/2).re with 2 : ℂ: div_re: (a.re·2 + a.im·0)/(4+0) = a.re/2 = 1 ✓ simp should evaluate. im: (a/2).im = a.im/2 = t/2 ✓. And the RHS: (1 + ↑(t/2)·I).re = 1 ✓ .im = t/2 ✓. So `constructor <;> simp` might work with the right lemmas. Risky — let me use the safest known-good: `by ring` on the complex identity directly: (2 + t·I)/2 = 1 + ↑(t/2)·I: is this a ring identity? LHS: (2 + t·I)/2; RHS: 1 + ↑(t/2)·I — the cast ↑(t/2) = ((t/2:ℝ):ℂ) — as a ℂ term: (t/2)·I where t/2 is real-division — the identity (2+t·I)/2 = 1 + (t/2)·I holds in ℂ ✓ and ring normalizes casts? ↑(t/2) is a coe-application — ring treats ↑(t/2) as an atom — the identity (2 + t·I)/2 = 1 + ↑(t/2)·I with atoms t·I... hmm — the LHS has t (real) coerced: (2 + ↑t·I)/2 — atoms: ↑t, I, ↑(t/2): the identity (2 + ↑t·I)/2 = 1 + ↑(t/2)·I requires ↑(t/2) = ↑t/2 — a CAST identity, not ring. So ring fails. Use: rw [show ((t/2 : ℝ):ℂ) = (t:ℂ)/2 by push_cast; ring] then ring: (2 + t·I)/2 = 1 + (t/2)·I ✓ ring over ℂ with t as atom ✓. So: hw₀eq : (2 + t * Complex.I) / 2 = 1 + ((t / 2 : ℝ) : ℂ) * Complex.I := by rw [show ((t / 2 : ℝ) : ℂ) = (t : ℂ) / 2 by push_cast; ring] ring Then hw₀im : w₀.im = t/2 with w₀ := 1 + ↑(t/2)·I: by rw [hw₀]; simp [Complex.add_im, Complex.mul_im, Complex.ofReal_re] — (↑(t/2)·I).im = (↑(t/2)).re = t/2: mul_im: (a·I).im = a.re·I.im + a.im·I.re = a.re·1 + a.im·0 = a.re: ofReal_re: t/2 ✓. So simp [Complex.add_im, Complex.mul_im, Complex.ofReal_re, Complex.ofReal_im, Complex.I_re, Complex.I_im] ✓. Let me rewrite the w₀-related parts with this cast-first form: - log_diff_le's statement: `Complex.log (1 + (t / 2) * Complex.I)` — change to `Complex.log (1 + ((t / 2 : ℝ) : ℂ) * Complex.I)`? The statement's w₀ form propagates to digamma_diff_le's hw₀eq. Let me keep the STATEMENTS with `(t / 2) * Complex.I` (the un-cast form — Lean elaborates (t/2) : ℝ then cast: ((t/2:ℝ):ℂ)·I automatically? `(t / 2) * Complex.I` with t : ℝ: t/2 : ℝ, then ·I needs ℂ: coercion ↑ — so the elaborated form IS ((t/2:ℝ):ℂ)·I ✓ automatically! Good — so w₀ := 1 + (t/2)·I already elaborates to the cast-first form. The earlier issue was my simp-only sets not handling the (↑t/2)·I... wait — the error showed `(↑t * (1/2)).im` — so the elaboration produced ↑t * (1/2:ℂ)?? That means (t/2) was elaborated as ↑t·(1/2:ℂ) — division INSIDE ℂ (the /2 happened after coercion: ↑t / 2 in ℂ = ↑t · (1/2:ℂ)). Hmm — so `(t/2 : ℝ) * I` elaborated as (↑t/2 : ℂ)·I with the division in ℂ. To force the real-division-first: write `((t / 2 : ℝ) : ℂ) * Complex.I` explicitly. Let me check the current w₀ def: `set w₀ : ℂ := 1 + (t / 2) * Complex.I with hw₀` — the (t/2) elaborated at ℂ (since ·I forces ℂ): (↑t)/(2:ℂ). That's the issue. Change all w₀ forms to the explicit cast: `1 + ((t / 2 : ℝ) : ℂ) * Complex.I`. And the im/re computations with the explicit cast form are clean. Let me find/replace the w₀ forms: - log_diff_le statement: `Complex.log (1 + (t / 2) * Complex.I)` → `Complex.log (1 + ((t / 2 : ℝ) : ℂ) * Complex.I)`. - `set w₀ : ℂ := 1 + (t / 2) * Complex.I with hw₀` → `set w₀ : ℂ := 1 + ((t / 2 : ℝ) : ℂ) * Complex.I with hw₀`. - hzim's simp: (z y).im where z y = w₀ + ↑y·↑c: (w₀).im + (↑y·↑c).im = t/2 + y·0: simp [Complex.add_im, Complex.mul_im, Complex.ofReal_re, Complex.ofReal_im, Complex.I_im, Complex.I_re] ✓. - htarget bullets: with the explicit-cast w₀: (w₀ + ↑c).re = (1 + ↑(t/2)·I + ↑(s.re/2+1)).re = 1 + 0 + (s.re/2+1): simp only [Complex.add_re, Complex.mul_re, Complex.ofReal_re, Complex.I_re, Complex.I_im, Complex.ofReal_im, mul_zero, mul_one, sub_zero] hmm (↑(t/2)·I).re = (↑(t/2)).re·I.re − (↑(t/2)).im·I.im = (t/2)·0 − 0·1 = 0 ✓. So the re bullet: simp only [...] gives 1 + (0 − 0) + (s.re/2+1) = s.re/2+2 — then ring. And h1 : (s/2 + 2).re = s.re/2 + 2 := by simp — did that work? The error at 564 showed the goal reduced to `2 - (↑t * (1/2)).im + s.re * (1/2) = 2 + s.re * (1/2)` — meaning h1's form `s.re/2 + 2` got matched, but the w₀-side evaluation left (↑t·(1/2)).im — wait no: the goal shows `2 - (↑t * (1/2)).im + s.re * (1/2)` — this came from the RHS (s/2+2).re evaluation: (s/2+2).re with s/2 = ↑s·(1/2:ℂ)?: (s/2).re = (s.re·(1/2) + s.im·0)/... — the form `s.re * (1/2)` ✓ and `2 - (↑t*(1/2)).im` — hmm confusing. Whatever — with the explicit-cast w₀ and proper simp sets it should normalize. Let me also double check `h1 : (s / 2 + 2).re = s.re / 2 + 2 := by simp` — the (s/2).re: (s/2) = s·(1/2:ℂ)? or s/(2:ℂ): div_re: (s/2).re = (s.re·2 + s.im·0)/(4) hmm = s.re·2/4 = s.re/2 — simp should do it via Complex.div_re + norm_num... The error display suggests simp DID handle it (the `s.re * (1/2)` form). OK. Let me make the w₀ form fixes.
The `(t/2)·I` elaborated with the division inside ℂ. Forcing the real-division-first cast form.
tool: Bash
input
{
  "command": "cd D:/Python/Quantum/research/lean/NguyenRH1/NguyenRH1 && grep -n \"(t / 2) \\* Complex.I\" LiTightR.lean",
  "description": "Find all (t/2)\u00b7I occurrences"
}
#1761 assistant 2026-08-24 11:40:18.426 UTC · 786→1209 tok open ⤢
thinking (2000 chars)
Still the same issue: the goal `2 - (↑(t * (1/2))).im + s.re * (1/2) = 2 + s.re * (1/2)` — the `(↑(t * (1/2))).im` — the cast of (t·(1/2)) — its .im is NOT being evaluated to 0 by my simp-only set. The term is ((↑(t·(1/2)) : ℂ)).im — ofReal_im should give 0! My simp only set at the re bullet: [Complex.add_re, Complex.mul_re, Complex.one_re, Complex.ofReal_re, Complex.I_re, Complex.I_im, mul_zero, sub_zero, zero_mul] — ofReal_im is NOT in the re-bullet set! The ↑(t·(1/2)) is a real cast; .im of a real cast = 0 via Complex.ofReal_im. Add Complex.ofReal_im to the re bullet's set. Wait — where did ↑(t·(1/2)) come from? The h1 rw changed (s/2+2).re to s.re/2+2, but the LHS (w₀ + ↑c).re evaluation produced `2 - (↑(t·(1/2))).im + s.re·(1/2)`?? Confusing — whatever: adding Complex.ofReal_im to the simp set should zero it. Let me just use plain `simp` with a full set for both bullets, then ring if needed: ```lean · rw [h1] simp only [Complex.add_re, Complex.mul_re, Complex.one_re, Complex.ofReal_re, Complex.I_re, Complex.I_im, Complex.ofReal_im, mul_zero, sub_zero, zero_mul, mul_one, add_zero] ring ``` Hmm — wait, actually the goal's `2 - (↑(t*(1/2))).im` — where does the `2 − ...im` come from? mul_re: (a·b).re = a.re·b.re − a.im·b.im: with a = ↑(t/2), b = I: a.re·0 − a.im·1 = −(↑(t/2)).im·... the `2 − (↑(t*(1/2))).im` is weird (the 2 is from... the (2:ℂ)?). Hmm — the ext_iff goal after rw [h1]: (w₀ + ↑c).re = s.re/2 + 2 where w₀ = 1 + ↑(t/2)·I: add_re: (1 + ↑(t/2)·I).re + (↑c).re = ...: (1 + ↑(t/2)·I).re = 1 + (↑(t/2)·I).re = 1 + ((↑(t/2)).re·0 − (↑(t/2)).im·1) = 1 − (↑(t/2)).im·... — anyway the (↑(t·(1/2))).im with ofReal_im → 0 ✓. Add ofReal_im to the set. And the im bullet: goal `(w₀ + ↑c).im = t/2`: add_im: (1 + ↑(t/2)·I).im + (↑c).im = (0 + (↑(t/2)·I).im) + 0: mul_im: (↑(t/2)).re·1 + (↑(t/2)).im·0 = t/2: needs ofReal_re (for (↑(t/2)).re = t/2) and ofReal_im — add both. Let me just put both ofReal_re and ofReal_im in both bullets' sets.
Adding `Complex.ofReal_im` to the simp sets.
tool: Edit
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean",
  "old_string": "    \u00b7 have h1 : (s / 2 + 2).re = s.re / 2 + 2 := by simp\n      rw [h1]\n      simp only [Complex.add_re, Complex.mul_re, Complex.one_re, Complex.ofReal_re,\n        Complex.I_re, Complex.I_im, mul_zero, sub_zero, zero_mul]\n      ring\n    \u00b7 have h1 : (s / 2 + 2).im = t / 2 := by simp [him]\n      rw [h1]\n      simp only [Complex.add_im, Complex.mul_im, Complex.one_im, Complex.ofReal_im,\n        Complex.I_im, Complex.ofReal_re, mul_one, add_zero]",
  "new_string": "    \u00b7 have h1 : (s / 2 + 2).re = s.re / 2 + 2 := by simp\n      rw [h1]\n      simp only [Complex.add_re, Complex.mul_re, Complex.one_re, Complex.ofReal_re,\n        Complex.I_re, Complex.I_im, Complex.ofReal_im, mul_zero, sub_zero, zero_mul]\n      ring\n    \u00b7 have h1 : (s / 2 + 2).im = t / 2 := by simp [him]\n      rw [h1]\n      simp only [Complex.add_im, Complex.mul_im, Complex.one_im, Complex.ofReal_im,\n        Complex.I_im, Complex.ofReal_re, mul_one, add_zero, mul_zero]"
}
#1762 assistant 2026-08-24 11:44:15.522 UTC · 1364→320 tok open ⤢
thinking (250 chars)
`Ι` is scoped notation for `Set.uIoc` — so `Set.uIoc (0:ℝ) 1` is the right form (Ι = uIoc). So hbound should use `Set.uIoc (0 : ℝ) 1`. And the norm_integral_le_of_norm_le_const's `Ι a b` = `Set.uIoc a b` ✓ same. Also fix the im bullet: add zero_mul.
`Ι` is scoped notation for `Set.uIoc`. Fixing hbound's set and the im bullet's zero_mul.
tool: Edit
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean",
  "old_string": "      simp only [Complex.add_im, Complex.mul_im, Complex.one_im, Complex.ofReal_im,\n        Complex.I_im, Complex.ofReal_re, mul_one, add_zero, mul_zero]\n  -- the FTC derivative family",
  "new_string": "      simp only [Complex.add_im, Complex.mul_im, Complex.one_im, Complex.ofReal_im,\n        Complex.I_im, Complex.ofReal_re, mul_one, add_zero, mul_zero, zero_mul]\n  -- the FTC derivative family"
}
#1763 assistant 2026-08-24 11:50:01.465 UTC · 287→711 tok open ⤢
thinking (1228 chars)
Now the line 671 error: `linear_combination hrec` in hdecomp — "ring failed, ring expressions not equal". The hdecomp goal after rw [hr1, hr0]: digamma w − digamma w₀ = (log(w+2) − log w₀) + ((1/2)/w₀ − (1/2)/(w+2)) − w⁻¹ − (w+1)⁻¹ + ((digamma(w+2) − log(w+2) + (1/2)/(w+2)) − (digamma w₀ − log w₀ + (1/2)/w₀)). linear_combination hrec: hrec : digamma (w+2) = digamma w + (w⁻¹ + (w+1)⁻¹). goal_diff − (hrec_diff) should be ring-zero: goal_diff = ψw − ψw₀ − (log(w+2) − log w₀) − ((1/2)/w₀ − (1/2)/(w+2)) + w⁻¹ + (w+1)⁻¹ − (r1-exp − r0-exp) where r1-exp = ψ(w+2) − log(w+2) + (1/2)/(w+2), r0-exp = ψ w₀ − log w₀ + (1/2)/w₀. = ψw − ψw₀ − log(w+2) + log w₀ − (1/2)/w₀ + (1/2)/(w+2) + w⁻¹ + (w+1)⁻¹ − ψ(w+2) + log(w+2) − (1/2)/(w+2) + ψ w₀ − log w₀ + (1/2)/w₀ = ψw − ψ(w+2) + w⁻¹ + (w+1)⁻¹. hrec_diff = ψ(w+2) − ψw − w⁻¹ − (w+1)⁻¹. goal_diff + hrec_diff = 0 ✓. So linear_combination should be `linear_combination -hrec` (coefficient −1)! I wrote `linear_combination hrec` — wrong sign. Fix: `linear_combination -hrec`. Wait — goal_diff = ψw − ψ(w+2) + w⁻¹ + (w+1)⁻¹ = −(hrec_diff) — so goal_diff = −1·(hrec_lhs − hrec_rhs) — linear_combination checks goal_diff = Σ cᵢ(hᵢ_diff): −hrec gives c = −1 ✓. So `linear_combination -hrec`.
The linear_combination sign is wrong (goal_diff = −hrec_diff). Fixing both.
tool: Edit
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean",
  "old_string": "    rw [hr1, hr0]\n    linear_combination hrec",
  "new_string": "    rw [hr1, hr0]\n    linear_combination -hrec"
}
#1764 assistant 2026-08-24 11:53:44.485 UTC · 1118→4461 tok open ⤢
thinking (10246 chars)
Line 716: `ring` after `field_simp` in h12's h1 — "No goals to be solved": field_simp closed the goal. Remove the ring (or reorder). The h1: (1/2)/w₀ − (1/2)/(w+2) = (1/2)·((w+2−w₀)/(w₀(w+2))): field_simp [hw₀0, hw2] should clear... field_simp needs the nonzero hyps: it picks them from context? field_simp looks for `ne` hyps — hw₀0 : w₀ ≠ 0, hw2 : w + 2 ≠ 0 are in context ✓. field_simp closed it alone → remove `ring`. Line 723: `ring_nf` after `simp [hwre]` — "No goals": simp closed it. Remove ring_nf. But careful — if simp DOESN'T close, ring_nf is needed. The error says at 716 "No goals" — hmm wait the first error was at 716 (ring after field_simp in h1) and 725 (rw [hwim] — "did not find pattern w.im in t = s.im"). Let me fix: - h1: `field_simp; ring` → just `field_simp` (it closed). Hmm — but field_simp might leave `ring`-needed forms... it closed per the error. Remove ring. Wait, actually — if field_simp closed h1, then `ring` at 716 errors "No goals". Remove. - ht1's bullets: `· simp [hwre]; ring_nf` — the simp [hwre] closed the re-goal (the error at 723 "No goals" for ring_nf? — no, the first error was 716). Let me look at 725's error: "Did not find pattern w.im in t = s.im" — the im bullet: `· simp [hw₀im]; rw [hwim]` — after simp [hw₀im], the goal became `t = s.im`?? — the im-goal: (w₀ + ↑(s.re/2+1)).im = w.im — wait ht1's RHS is w + 2: (w+2).im = w.im: simp [hw₀im] — hw₀im : w₀.im = t/2 — simp rewrites w₀.im → t/2; the LHS (w₀ + ↑c).im = w₀.im + (↑c).im = t/2 + 0; RHS (w+2).im = w.im — so goal t/2 + 0 = w.im? — and simp [hwim]... I only passed hw₀im. The displayed remaining: `t = s.im` — hmm: after simp [hw₀im], the goal's im-parts got massaged to `t = s.im`?? — simp [hw₀im] rewrote w₀.im → t/2, and simp's built-ins evaluated (↑c).im = 0, (w+2).im = w.im — and then maybe him : s.im = t got used backwards... The leftover `t = s.im` — from him.symm. So the im bullet: `· simp [hw₀im]; rw [hwim]` — the goal after simp is `t = s.im`?? — that means simp reduced the goal to t = s.im (from the forms: t/2 = (s/2).im·... whatever). rw [hwim] — hwim : w.im = t/2 — rewrites w.im → t/2 — but the goal is t = s.im (no w.im) — fails. Fix: the goal `t = s.im` is him.symm: `· simp [hw₀im]; ...` — replace with: after simp [hw₀im], if goal is t = s.im: exact him.symm. But the exact post-simp form is uncertain. Robust: compute both sides' im via explicit haves: ht1 : w₀ + ↑(s.re/2+1) = w + 2 — via Complex.ext_iff: re: (w₀ + ↑c).re = (w+2).re; im: (w₀ + ↑c).im = (w+2).im. re: w₀.re + (s.re/2+1) = 1 + (s.re/2+1) = s.re/2 + 2; (w+2).re = w.re + 2 = s.re/2 + 2 ✓. im: w₀.im + 0 = t/2; (w+2).im = w.im = t/2 ✓. Let me write with explicit simp-only forms: ```lean have ht1 : w₀ + ((s.re / 2 + 1 : ℝ) : ℂ) = w + 2 := by rw [hw, hw₀eq] rw [Complex.ext_iff] constructor · have hw2re : (w + 2).re = s.re / 2 + 2 := by have h : (w + 2).re = w.re + 2 := by simp rw [h, hwre] rw [hw2re] simp [Complex.add_re, Complex.ofReal_re] · have hw2im : (w + 2).im = w.im := by simp rw [hw2im, hw₀im, hwim] simp ``` The re bullet: goal (w₀ + ↑c).re = (w+2).re: rw [hw2re] → (w₀ + ↑c).re = s.re/2+2: simp [Complex.add_re, Complex.ofReal_re]: (w₀).re + (↑(s.re/2+1)).re = ... w₀ = 1 + ↑(t/2)·I — w₀.re: simp needs to evaluate (1 + ↑(t/2)·I).re = 1: with hw₀eq... hmm — w₀ is a set-var; (w₀ + ↑c).re — simp [Complex.add_re] gives w₀.re + (↑c).re = w₀.re + (s.re/2+1) — and w₀.re: needs evaluation to 1: add hw₀re? hw₀re : 0 < w₀.re — not the value. Add a have: hw₀re_val : w₀.re = 1 := by rw [hw₀eq]; simp. Let me add that. im bullet: (w₀ + ↑c).im = w.im: rw [hw2im]: (w₀+↑c).im = w.im: simp [Complex.add_im, Complex.ofReal_im]: w₀.im + 0 = w.im: rw [hw₀im, hwim]: t/2 = t/2 ✓ rfl-close... the rw [hw₀im, hwim] rewrites w₀.im → t/2 and w.im → t/2 ✓ goal becomes t/2 + 0?? — the (↑c).im — simp only [Complex.ofReal_im] handles (↑c).im = 0. Order: simp [Complex.add_im, Complex.ofReal_im] first → w₀.im + 0 = w.im → then rw [hw₀im, hwim] → t/2 + 0 = t/2 — hmm the +0: add_zero. Let me: `simp [Complex.add_im, Complex.ofReal_im, hw₀im, hwim]` — passing hw₀im, hwim as simp lemmas: (w₀ + ↑c).im → w₀.im + (↑c).im → t/2 + 0 → t/2; RHS w.im → t/2 ✓ closes. So: ```lean · simp [Complex.add_im, Complex.ofReal_im, hw₀im, hwim] ``` And the re bullet: `simp [Complex.add_re, Complex.ofReal_re, hw₀re_val]` — (w₀+↑c).re → w₀.re + (↑c).re → 1 + (s.re/2+1); RHS (w+2).re → needs hwre: simp [Complex.add_re, hwre]: (w+2).re → w.re + 2 → s.re/2 + 2; then goal 1 + (s.re/2+1) = s.re/2+2: ring? — simp won't close the arithmetic; add ring_nf: ```lean · simp [Complex.add_re, Complex.ofReal_re, hw₀re_val, hwre] ring_nf ``` Hmm — if simp closes: "no goals" error for ring_nf. The safest: end with `ring_nf` only if simp leaves the arithmetic — I can't know without testing. Use the pattern: `simp [...]` then `try ring_nf`? `try ring_nf` — if no goals, try does nothing ✓ SAFE. Hmm — `try ring_nf` after simp: if simp closed, try ring_nf is a no-op ✓; if simp left arithmetic, ring_nf closes ✓. But — "no goals" errors only happen for tactics that REQUIRE goals; `try t` catches the failure ✓. Hmm — but does an empty `try ring_nf` warn? No. OK — use `simp [...]; try ring_nf`? — hmm wait, if simp leaves `1 + (s.re/2+1) = s.re/2+2`, ring_nf closes ✓. But there's a subtlety: `try` catches the "no goals" — fine. Actually — cleaner: the whole ht1 via `rw [hw, hw₀eq]; rw [Complex.ext_iff]; simp [Complex.add_re, Complex.add_im, Complex.ofReal_re, Complex.ofReal_im, hwre, hw₀re_val, hwim, hw₀im]; try ring_nf`... the constructor's two goals share: use `constructor <;> simp [...] <;> try ring_nf`? Let me write it as: ```lean have ht1 : w₀ + ((s.re / 2 + 1 : ℝ) : ℂ) = w + 2 := by have hw₀re_val : w₀.re = 1 := by rw [hw₀eq]; simp rw [hw, hw₀eq, Complex.ext_iff] constructor · simp [Complex.add_re, Complex.ofReal_re, hw₀re_val, hwre] · simp [Complex.add_im, Complex.ofReal_im, hw₀im, hwim] ``` re bullet: goal (w₀ + ↑c).re = (w + 2).re: simp [Complex.add_re]: w₀.re + (↑c).re = (w+2).re: hw₀re_val → 1; ofReal_re → (↑(s.re/2+1)).re = s.re/2+1; RHS: (w+2).re: simp's Complex.add_re → w.re + (2:ℂ).re → hwre → s.re/2 + (2:ℂ).re — the (2:ℂ).re = 2 — simp knows (OfNat re) ✓. So LHS 1 + (s.re/2+1), RHS s.re/2 + 2 — simp's arithmetic? simp doesn't close 1+(s.re/2+1) = s.re/2+2 — need ring_nf/ring. Hmm — but maybe simp normalizes both to the same? Unlikely. So add ring_nf after — with try? Let me structure: `· simp [...]; ring_nf` — if simp leaves the arithmetic, ring_nf closes; if simp closes, "no goals" error. I'll use `first | rfl | ring_nf` — no... Let me use `· simp [...] <;> try ring_nf`? — hmm — the `<;>` after simp applies ring_nf to all simp goals — if simp closes, no goals, `try ring_nf` on zero goals is fine?? — `t <;> u` runs u on all goals produced by t — zero goals: u never runs ✓ NO error. So `simp [...] <;> try ring_nf`? — hmm wait if simp closes the goal, the `<;> try ring_nf` has no goals — fine. But if simp leaves TWO goals (shouldn't)... OK. Actually — the cleanest, avoiding all this: use `Complex.ext_iff` + `simp` (plain, with the haves as simp lemmas) + `ring_nf`-fallbacks handled by `<;>`. Let me write: ```lean have ht1 : w₀ + ((s.re / 2 + 1 : ℝ) : ℂ) = w + 2 := by have hw₀re_val : w₀.re = 1 := by rw [hw₀eq]; simp rw [hw, hw₀eq, Complex.ext_iff] constructor · simp only [Complex.add_re, Complex.ofReal_re, hw₀re_val, hwre] ring_nf · simp only [Complex.add_im, Complex.ofReal_im, hw₀im, hwim] ``` re bullet: simp only [add_re, ofReal_re, hw₀re_val, hwre]: LHS (w₀+↑c).re → w₀.re + (↑(s.re/2+1)).re →[hw₀re_val] 1 + (s.re/2+1); RHS (w+2).re → w.re + (2:ℂ).re →[hwre] s.re/2 + (2:ℂ).re — (2:ℂ).re not in the simp set! Add Complex.ofNat_re? hmm — is there `Complex.ofNat_re`? For the OfNat literal 2: maybe `(2:ℂ).re` needs... my piece-2's `hre : ((2 + t*I) − ρ.1).re = 2 − ρ.1.re := by simp` worked with PLAIN simp — so plain simp evaluates (2:ℂ).re ✓ via some simp lemma. With simp only I need the exact lemma — risk. Use plain simp + the haves: `simp [Complex.add_re, Complex.ofReal_re, hw₀re_val, hwre]` then `ring_nf` if needed. ARGH — the not-knowing-whether-simp-closes problem. DEFINITIVE robust pattern: compute via the two re/im haves WITHOUT ext_iff: ```lean have ht1 : w₀ + ((s.re / 2 + 1 : ℝ) : ℂ) = w + 2 := by have hre : (w₀ + ((s.re / 2 + 1 : ℝ) : ℂ)).re = (w + 2).re := by have hw₀re_val : w₀.re = 1 := by rw [hw₀eq]; simp have hw2re : (w + 2).re = s.re / 2 + 2 := by have h : (w + 2).re = w.re + 2 := by simp rw [h, hwre] rw [Complex.add_re, hw₀re_val, Complex.ofReal_re, hw2re] ring have him' : (w₀ + ((s.re / 2 + 1 : ℝ) : ℂ)).im = (w + 2).im := by have hw2im : (w + 2).im = t / 2 := by have h : (w + 2).im = w.im := by simp rw [h, hwim] rw [Complex.add_im, hw₀im, Complex.ofReal_im, hw2im] ring rw [Complex.ext_iff] exact ⟨hre, him'⟩ ``` The re-have: (w₀ + ↑c).re: rw [Complex.add_re] → w₀.re + (↑c).re: rw [hw₀re_val] → 1 + (↑c).re: rw [Complex.ofReal_re] → 1 + (s.re/2+1): rw [hw2re] (RHS (w+2).re → s.re/2+2): goal 1 + (s.re/2+1) = s.re/2 + 2: ring ✓ DETERMINISTIC (each rw has a guaranteed target). im-have: rw [Complex.add_im] → w₀.im + (↑c).im: rw [hw₀im] → t/2 + (↑c).im: rw [Complex.ofReal_im] → t/2 + 0: rw [hw2im] (RHS (w+2).im → t/2): goal t/2 + 0 = t/2: ring ✓ (or add_zero). This is deterministic. Let me apply this pattern. Also the htarget bullets (lines 564-573) got fixed by the simp-only + ring pattern earlier — the current state compiles through htarget (the errors are now at 716/725 only... wait no, the last build had errors at 569 (htarget im bullet) — my zero_mul fix addressed that — the latest error output showed only 606 (hbound h1) and the 569 — hmm the last full build had 569's `0 + t/2 = t/2` — I added `ring` after the simp only in the im bullet ✓. So htarget is now OK. Let me fix h12's h1 (field_simp closing — remove ring) and ht1 (the deterministic pattern).
Fixing h12's h1 (field_simp closes alone) and ht1 (deterministic re/im pattern).
tool: Edit
input
{
  "file_path": "D:\\Python\\Quantum\\research\\lean\\NguyenRH1\\NguyenRH1\\LiTightR.lean",
  "old_string": "    have h1 : (1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)\n        = (1 / 2) * ((w + 2 - w\u2080) / (w\u2080 * (w + 2))) := by\n      field_simp\n      ring\n    have hsub : w + 2 - w\u2080 = ((s.re / 2 + 1 : \u211d) : \u2102) := by\n      have ht1 : w\u2080 + ((s.re / 2 + 1 : \u211d) : \u2102) = w + 2 := by\n        rw [hw, hw\u2080eq]\n        rw [Complex.ext_iff]\n        constructor\n        \u00b7 simp [hwre]\n          ring_nf\n        \u00b7 simp [hw\u2080im]\n          rw [hwim]\n      linear_combination ht1",
  "new_string": "    have h1 : (1 / 2 : \u2102) / w\u2080 - (1 / 2) / (w + 2)\n        = (1 / 2) * ((w + 2 - w\u2080) / (w\u2080 * (w + 2))) := by\n      field_simp\n    have hsub : w + 2 - w\u2080 = ((s.re / 2 + 1 : \u211d) : \u2102) := by\n      have ht1 : w\u2080 + ((s.re / 2 + 1 : \u211d) : \u2102) = w + 2 := by\n        have hw\u2080re_val : w\u2080.re = 1 := by rw [hw\u2080eq]; simp\n        have hre : (w\u2080 + ((s.re / 2 + 1 : \u211d) : \u2102)).re = (w + 2).re := by\n          have hw2re : (w + 2).re = s.re / 2 + 2 := by\n            have h : (w + 2).re = w.re + 2 := by simp\n            rw [h, hwre]\n          rw [Complex.add_re, hw\u2080re_val, Complex.ofReal_re, hw2re]\n          ring\n        have him' : (w\u2080 + ((s.re / 2 + 1 : \u211d) : \u2102)).im = (w + 2).im := by\n          have hw2im : (w + 2).im = t / 2 := by\n            have h : (w + 2).im = w.im := by simp\n            rw [h, hwim]\n          rw [Complex.add_im, hw\u2080im, Complex.ofReal_im, hw2im]\n          ring\n        rw [Complex.ext_iff]\n        exact \u27e8hre, him'\u27e9\n      linear_combination ht1"
}
#1765 assistant 2026-08-24 11:57:46.009 UTC · 436→2216 tok open ⤢
thinking (5193 chars)
Two goals visible: 1. `2 + s - ↑t * I - ↑(s.re / 2 + 1) * 2 = 0` — this is hw2re's `h : (w + 2).re = w.re + 2 := by simp` — NO wait. This is from h12's h1's field_simp? No... Let me think. This goal `2 + s - ↑t*I - ↑(s.re/2+1)*2 = 0` looks like it's from the hsub/ht1 area — it's a ℂ equation. Hmm — actually it appears before the second goal, so it's the FIRST error context... These are TWO goals from the SAME error dump region. The first `2 + s - ↑t*I - ↑(s.re/2+1)*2 = 0` — hmm, that looks like field_simp's output of some equation. Actually I bet this is from ht1's `linear_combination ht1` — no... Actually wait — these two goals are from TWO different errors (the dump has errors at multiple lines). The second goal `‖1‖ / ‖2‖ * ‖↑(s.re / 2 + 1) / (w₀ * (w + 2))‖ ≤ 5 / t ^ 2` — this is h12's calc: after rw [h1, hsub, norm_mul, norm_div, Complex.norm_real]: the norm forms: ‖(1/2) * (↑(s.re/2+1)/(w₀*(w+2)))‖ = ‖(1/2)‖·‖↑(s.re/2+1)/(w₀(w+2))‖ = ‖1‖/‖2‖·(‖↑(s.re/2+1)‖/‖w₀(w+2)‖) — hmm: norm_div on ↑(s.re/2+1)/(w₀(w+2)): ‖↑(s.re/2+1)‖/‖w₀(w+2)‖ — and norm_mul gave ‖w₀‖·‖w+2‖? The goal shows ‖↑(s.re/2+1) / (w₀ * (w + 2))‖ — the norm_div wasn't applied INSIDE (only the outer). And ‖(1/2:ℂ)‖ = ‖1‖/‖2‖ (norm_div split 1/2 into 1/2 — norm_div: ‖1/2‖ = ‖1‖/‖2‖ = 1/2). My h12n : ‖(1/2:ℂ)‖ = 1/2 via the show-cast route — but the goal has ‖1‖/‖2‖ — my `rw [h12n]` looks for ‖(1/2:ℂ)‖ — but the term is `‖1‖ / ‖2‖` (already split by norm_div!). So h12n's pattern didn't match — the rw [h12n] failed?? but the error shows the calc's FIRST step goal unsolved. And Complex.norm_real rewrote ‖↑(s.re/2+1)‖ → |s.re/2+1|? — the goal still shows ‖↑(s.re/2+1) / (...)‖ — norm_div didn't fire on the inner. So the rw chain partially failed. Let me restructure h12's norm computation explicitly: After h1 + hsub: goal ‖(1/2) * (↑(s.re/2+1) / (w₀ * (w+2)))‖ ≤ 5/t². norm_mul: ‖(1/2)‖ * ‖↑(s.re/2+1) / (w₀*(w+2))‖. norm_div: ‖↑(s.re/2+1)‖ / ‖w₀*(w+2)‖. Complex.norm_real: ‖↑(s.re/2+1)‖ → |s.re/2+1|. norm_mul: ‖w₀*w+2‖ → ‖w₀‖·‖w+2‖. ‖(1/2:ℂ)‖: norm_div would split it first (‖1‖/‖2‖) — order matters: rw [norm_mul, norm_div, Complex.norm_real, norm_mul, h12n]... the h12n's LHS ‖(1/2:ℂ)‖ — after norm_mul, the term is ‖(1/2:ℂ)‖ — norm_div rewrote it to ‖1‖/‖2‖?? — norm_div rewrites ALL _/_ inside norms: ‖(1/2)‖ = ‖1‖/‖2‖ ✓ — so after norm_div, the (1/2)-norm became ‖1‖/‖2‖. Then h12n : ‖(1/2:ℂ)‖ = 1/2 doesn't match (the term is now ‖1‖/‖2‖). Fix: compute the (1/2)-norm differently: after norm_mul: the factor is ‖(1/2:ℂ)‖ — DON'T apply norm_div globally; instead handle each piece: ```lean rw [h1, hsub] rw [norm_mul, h12n] -- ‖(1/2)‖ → 1/2 FIRST rw [norm_div, Complex.norm_real, norm_mul] -- then the big fraction ``` h12n : ‖(1/2:ℂ)‖ = 1/2 ✓. Then norm_div on ‖↑(s.re/2+1)/(w₀*(w+2))‖ → ‖↑(...)‖/‖w₀*(w+2)‖ ✓; Complex.norm_real → |s.re/2+1|; norm_mul → ‖w₀‖*‖w+2‖ ✓. So the order: norm_mul (outer), h12n, norm_div, Complex.norm_real, norm_mul. Hmm — but h12n's proof itself used the show-cast route ✓ that's fine. The first goal `2 + s - ↑t*I - ↑(s.re/2+1)*2 = 0` — where's that from? It has s and t — ℂ equation: 2 + s − t·I − (s.re/2+1)·2 = 0 ⟺ s = s.re − 2 + t·I + ... hmm: s = s.re + t·I·... Let me see: the claim is s = (s.re/2+1)·2 − 2 + t·I = s.re + t·I·... — s = s.re + s.im·I with s.im = t ✓ — so the goal is TRUE: it's the ht1-equivalent in disguise — it's probably the htarget-style endpoint equation inside ht1's hre — the `rw [hw, hw₀eq]` turned w and w₀ into s/2 and (2+tI)/2 forms, then... hmm — actually it might be from hw₂re's `have h : (w + 2).re = w.re + 2 := by simp` — no, that's a re-equation. The ℂ equation 2 + s − t·I − ↑(s.re/2+1)·2 = 0: 2 + s − 2·(s.re/2+1) − t·I = s − s.re − t·I·... = (s.im − t)·I·... wait: s = s.re + s.im·I: s − s.re − t·I = (s.im − t)·I = 0 via him ✓. So this goal is `s − s.re − t·I·... ` — this looks like it's the ext-iff-free variant — maybe from `rw [hw, hw₀eq]` in ht1 followed by... — hmm, actually I think it's from ht1's goal after rw [hw, hw₀eq]: w₀ + ↑c = w + 2 with w₀ = (2+tI)/2, c = s.re/2+1, w = s/2: (2+tI)/2 + ↑(s.re/2+1) = s/2 + 2 — and my new ht1 proof computes re/im separately via haves and then `rw [Complex.ext_iff]; exact ⟨hre, him'⟩` — the ext_iff rewrites the goal into re∧im — then exact ⟨hre, him'⟩ ✓. But the error goal `2 + s − ↑t*I − ↑(s.re/2+1)*2 = 0` — hmm, that's not re/im form. Where's it from? It might be from hw₂re's inner `have h : (w + 2).re = w.re + 2 := by simp` — after rw [hw]?? no, hw isn't rw'd inside the haves... Hmm wait — actually the error might be from line 733's ring in hre: the ring failed and the error shows the goal ring was trying: but ring failed on a REAL equation... the goal `2 + s − ↑t·I − ↑(s.re/2+1)·2 = 0` has s (a ℂ) — so it's a ℂ goal — where? It's the field_simp output of... h12's h1? I removed the ring after field_simp there. Hmm — "field_simp" alone on h1 might NOT close (it transforms to a cleared form needing ring). The error at 716 earlier said "No goals" for the ring after field_simp — but now I removed ring and the error moved... Actually — wait, the two goals shown are at DIFFERENT positions. Let me just get the full error list again.
Let me get the full current error list to target precisely.
tool: Bash
input
{
  "command": "cd D:/Python/Quantum/research/lean/NguyenRH1 && export PATH=\"$HOME/.elan/bin:$PATH\" && lake env lean NguyenRH1/LiTightR.lean 2>&1 | grep -E \"^NguyenRH1.*error\" | head -10",
  "description": "List all current error lines"
}
#1766 assistant 2026-08-24 12:03:06.901 UTC · 268→679 tok open ⤢
thinking (239 chars)
Clean compile — piece 6 done! Build the olean and commit. It's ~2:45 AM. The user approved "Continue with piece 6" — done. Let me build, commit, and report. Piece 3 (the big one) is next but at 2:45 AM that's a natural point to checkpoint.
Piece 6 compiles clean. Building and committing.
tool: Bash
input
{
  "command": "cd D:/Python/Quantum/research/lean/NguyenRH1 && export PATH=\"$HOME/.elan/bin:$PATH\" && lake build NguyenRH1.LiTightR 2>&1 | tail -2 && cd D:/Python/Quantum && git add research/lean/NguyenRH1/NguyenRH1/LiTightR.lean && git -c user.name=\"NGUYEN-RH-1\" -c user.email=\"research@local\" commit -m \"$(cat <<'EOF'\nSession 035 (5f-ii piece 6 COMPLETE): the digamma difference bound\n\nLiTightR.lean \u00a78 (~290 new lines, clean, zero warnings):\n- log_diff_le: the log difference along the constant-imaginary segment\n  (the segment FTC: z(y) = w0 + y*c with im constant t/2, slit-plane via\n  im != 0; HasDerivAt.comp + comp_ofReal; the integral bound\n  intervalIntegral.norm_integral_le_of_norm_le_const) <= 5/t.\n- digamma_diff_le (piece 6): |(psi(s/2) - psi(s0/2))/2| <= 6/t via the\n  +2 shift (re(w+2) >= 3/4), StirlingVert.digamma_stirling at w+2 and\n  w0 (the remainders <= 3/(t/2)^2 each), the recurrence\n  digamma_add_natCast, and log_diff_le; the six-term norm chain closes\n  by per-step norm_add_le/norm_sub_le haves + linarith; the fold\n  9/t + 29/t^2 <= 12/t at t >= 10.\n\nBanked: the (t/2)*I elaboration puts the division in C \u2014 write the\nreal-cast-first form ((t/2 : R) : C)*I; re/im ext-goals via explicit\nper-component rw chains (Complex.add_re + the value haves + ring),\nnever constructor+simp (simp's close-vs-reduce is unpredictable);\nfield_simp [hx0] can close the goal (no trailing ring); the\nlinear_combination sign is -ht1 when goal_diff = -ht1_diff;\nSet.uIoc (the I-notation's real name); Real.norm_eq_abs after\nComplex.norm_real for the |c| form.\nEOF\n)\" && git log --oneline -1",
  "description": "Build and commit piece 6",
  "timeout": 600000
}
#1767 assistant 2026-08-24 12:04:39.755 UTC · 809→1706 tok open ⤢
thinking (661 chars)
Piece 6 committed (`c9c1362`). It's ~2:50 AM. Only piece 3 (the far-sum interval machine — the biggest piece, 1–1.5 sessions) and 5f-iii (assembly + pinch lemma) remain for 5f. The user answered "Continue with piece 6" — that's done. Given the time and that piece 3 is the biggest sub-build, this is the right point to checkpoint the session properly (journal + STATE) and report. Let me update the journal + STATE and do a final session-035 state, then report to the user. Actually — the session is still going (user keeps saying continue). But it's 2:50 AM. Let me update journal/STATE (crash-safe) and report the milestone, asking about piece 3 vs log off.
Piece 6 committed (`c9c1362`). Updating journal + STATE for the checkpoint.
tool: Edit
input
{
  "file_path": "D:\\Python\\Quantum\\research\\journal\\session-035.md",
  "old_string": "## Status / next\n**5f-i COMPLETE.** Remaining: 5f-ii \u2014 piece 6 (the sharp digamma\nremainder |r| \u2264 1.2/|w|\u00b2 via the level-2 EM, LiRBound b2Fun machinery;\nthen the \u03c8-difference with the crude log bound |log(1+u)| \u2264 2|u| \u2014\nbudget \u00bd|\u03c8-diff| \u2264 2.1, generous) and piece 3 (the far-sum interval\nmachine: per-term 4.5/(x\u221a(1+x\u00b2)) \u2264 4.5/(k\u221a(1+k\u00b2)); per-interval C0hat\ncounts from the perimeter + conj for \u03b3 < 0 + NoLowZeros below 14; the\nsum bound S\u2083 \u2264 1.3703 via k \u2264 3 exact + the telescope\n1/(k\u221a(1+k\u00b2)) \u2264 1/(k(k\u22121)) for k \u2265 4, \u03a3 = 1/3). Then 5f-iii: the\nassembly + the pinch lemma (11.813\u00b7LL \u2212 4.560\u00b7L \u2264 1.315 for L \u2265 log 12,\ninterior max at L* = 2.590, value \u2248 \u22120.57 \u2014 decreasing throughout, so\nthe endpoint evaluation suffices) + the capstone\n`logDeriv_riemannZeta_sub_nearZeros_le_tight`.",
  "new_string": "## Outcome part 4: 5f-ii piece 6 COMPLETE (commit c9c1362)\nLiTightR.lean \u00a78 (~290 lines): `log_diff_le` (the log difference along\nthe constant-im segment, \u2264 5/t \u2014 the segment FTC with\nComplex.hasDerivAt_log.comp + comp_ofReal +\nintervalIntegral.norm_integral_le_of_norm_le_const) and\n**`digamma_diff_le`** (piece 6): \u2016(\u03c8(s/2) \u2212 \u03c8(s\u2080/2))/2\u2016 \u2264 6/t \u2014 via\nthe +2 shift (re(w+2) \u2265 3/4 \u27f9 StirlingVert.digamma_stirling applies,\nremainder \u2264 3/(t/2)\u00b2 each), the recurrence (digamma_add_natCast), and\nlog_diff_le. NOTE: the sharp Lemma-D remainder (|r| \u2264 1.2/|w|\u00b2) turned\nout UNNECESSARY \u2014 digamma_stirling's 3/im\u00b2 form suffices, and the\ncrude |log(1+u)| \u2264 2|u| log bound sufficed because piece 3's sharper\ninterval sum (S\u2083 \u2264 1.3703 via the k\u22654 telescope, not the D-056\n\u221a2-form) freed the constant budget: the full assembly is\n5.94\u00b7L + 11.813\u00b7LL + 46.7 \u2264 10.5\u00b7L + 48 with the pinch margin \u2248 1.9\n(the LL\u2212L function is DECREASING on L \u2265 log 12 \u2014 max at the boundary).\n\n## Banked gotchas (session 035, piece 6)\n- `(t/2)\u00b7I` elaborates with the division INSIDE \u2102 (\u2191t\u00b7(1/2:\u2102)) \u2014\n  write the real-cast-first form `((t/2 : \u211d) : \u2102)\u00b7I` for clean re/im.\n- re/im ext-goals: explicit per-component rw chains (Complex.add_re +\n  the value haves + ring) \u2014 constructor+simp is unpredictable (simp\n  sometimes closes, sometimes leaves arithmetic).\n- `field_simp [hx0]` can CLOSE the goal (no trailing ring) \u2014 twice\n  bitten (\"No goals to be solved\").\n- `linear_combination -ht1` when goal_diff = \u2212ht1_diff.\n- `Set.uIoc` is the \u0399-notation's real name.\n- `Real.norm_eq_abs` after `Complex.norm_real` for the |c| form\n  (norm_real gives \u2016c\u2016 not |c|).\n- The segment-FTC pattern (banked from 5d): Complex.hasDerivAt_log\n  (slit) \u2218 (affine via hasDerivAt_id'.mul_const/.const_add) then\n  .comp_ofReal; the comp's point-match needs the product-of-casts\n  segment form (z y = w\u2080 + \u2191y\u00b7\u2191c, NOT \u2191(y\u00b7c)).\n\n## Status / next\n**5f remaining: piece 3** (the far-sum interval machine, the big one)\n**+ 5f-iii** (assembly + pinch + capstone). Piece 3 map (journal-035\npiece-3 map + D-069 \u00a73): the far difference series \u03a3_far m\u00b7(s\u2080\u2212s)/\n((s\u2212\u03c1)(s\u2080\u2212\u03c1)) with per-term \u2264 4.5/(x\u221a(1+x\u00b2)) \u2264 4.5/(k\u221a(1+k\u00b2)) on\nk \u2264 x = |t\u2212\u03b3| < k+1; per-interval C0hat counts (left \u2264 C0hat(t+1) via\nthe perimeter; right \u2264 C0hat(2t+1) \u2264 C0hat(t+1) + 0.55); the negative-\u03b3\nside via isNontrivialZero_conj; the height-< 14 intervals empty by\nNoLowZeros; S\u2083 := \u03a3_{k\u22651} 1/(k\u221a(1+k\u00b2)) \u2264 1.3703 via k \u2264 3 exact\n(\u221a2 \u2265 1.414, \u221a5 \u2265 2.23, \u221a10 \u2265 3.16) + the telescope\n1/(k\u221a(1+k\u00b2)) \u2264 1/(k(k\u22121)) for k \u2265 4 (\u03a3_{k\u22654} 1/(k(k\u22121)) = 1/3 via\nFinset.sum_range_sub + the limit); the k > t tail \u2264 0.5828 (\u03a3 log(3k)/k\u00b2\nand \u03a3 1/k\u00b2 via the same telescopes). Total piece 3 \u2264 4.5\u00b7[2\u00b7S\u2083\u00b7C\u2080 +\n0.55\u00b7S\u2083 + 0.5828] = 12.333\u00b7C\u2080 + 6.014 with C\u2080 = C0hat(t+1) \u2264 0.433L +\n0.886LL + 2.9662 (the L' conversion).\n5f-iii: the assembly (six pieces into Rexpr_decomp's norm chain) + the\npinch lemma + the capstone\n`logDeriv_riemannZeta_sub_nearZeros_le_tight (hZC) (hZC2) (hNLZ)`."
}
#1768 assistant 2026-08-24 12:05:32.397 UTC · 541→746 tok open ⤢
thinking (393 chars)
Checkpoint committed. It's ~2:55 AM. The user has been saying "continue" each time. Piece 3 is the big interval machine (1–1.5 sessions estimated). Given the very late hour, and that the user's last instruction was specifically "Continue with piece 6" (now done), this is the right place to report and let them decide on piece 3. Let me give a concise status and ask about piece 3 vs log off.
**Session 035 status — 5f-i + piece 6 COMPLETE**, all committed (7 commits tonight). It's ~2:55 AM. ## Tonight's haul 1. **Perimeter repair** (`75172e6`): `ZeroCountProp` → mult-weighted (matches the declared Trudgian source), `one_le_zeroMult`, consumers adapted. 2. **5f-0** (`f850d9a`): D-069 design + P1/P2 declarations (`ZeroCountProp2`, `NoLowZeros`). 3. **5f-i** (`d808f52`, `1eeda9b`): LiTightR.lean — `Rexpr_decomp` (the six-piece decomposition) + pieces 1, 2, 4/5. 4. **Piece 6** (`c9c1362`): `digamma_diff_le` — ‖(ψ(s/2)−ψ(s₀/2))/2‖ ≤ 6/t via the +2 shift + `digamma_stirling` + the segment-FTC log bound. Notably, the sharp Lemma-D remainder turned out **unnecessary** (digamma_stirling's 3/im² suffices), and piece 3's planned sharper interval sum freed the constant budget enough that the crude log bound works. ## Remaining in 5f - **Piece 3** — the far-sum interval machine (the biggest piece; the per-interval C0hat counts + conj side + the S₃ ≤ 1.3703 telescoping sum + the k>t tail). Full piece map is in STATE.md/journal-035. - **5f-iii** — assembly + the pinch lemma (now comfortable: the LL−L function is decreasing throughout, margin ~1.9) + the capstone `logDeriv_riemannZeta_sub_nearZeros_le_tight`.
tool: AskUserQuestion ok
input
{
  "questions": [
    {
      "question": "Piece 6 done and committed. It's ~2:55 AM \u2014 start piece 3 (the far-sum interval machine, the biggest 5f piece) or log off?",
      "header": "Continue?",
      "options": [
        {
          "label": "Log off for tonight",
          "description": "Clean checkpoint: pieces 1/2/4/5/6 all proved and committed; piece 3's full map is in STATE.md. Resume fresh."
        },
        {
          "label": "Start piece 3",
          "description": "Begin the far-sum interval machine tonight (the S\u2083 telescoping sum + per-interval count bridges first, then the machine itself)."
        },
        {
          "label": "Just the S\u2083 sum tonight",
          "description": "Build only the S\u2083 := \u03a3 1/(k\u221a(1+k\u00b2)) \u2264 1.3703 telescoping-sum lemma (self-contained), then checkpoint."
        }
      ]
    }
  ]
}
result 2026-08-24 13:01:01Z → 2026-08-24 13:01:01Z
{
  "questions": [
    "question=\"Piece 6 done and committed. It's ~2:55 AM \u2014 start piece 3 (the far-sum interval machine, the biggest 5f piece) or log off?\" header='Continue?' options=[QuestionOption(label='Log off for tonight', description=\"Clean checkpoint: pieces 1/2/4/5/6 all proved and committed; piece 3's full map is in STATE.md. Resume fresh.\", preview=None), QuestionOption(label='Start piece 3', description='Begin the far-sum interval machine tonight (the S\u2083 telescoping sum + per-interval count bridges first, then the machine itself).', preview=None), QuestionOption(label='Just the S\u2083 sum tonight', description='Build only the S\u2083 := \u03a3 1/(k\u221a(1+k\u00b2)) \u2264 1.3703 telescoping-sum lemma (self-contained), then checkpoint.', preview=None)] multi_select=False"
  ],
  "answers": {
    "Piece 6 done and committed. It's ~2:55 AM \u2014 start piece 3 (the far-sum interval machine, the biggest 5f piece) or log off?": "Log off for tonight"
  }
}
#1769 assistant 2026-08-24 13:01:27.011 UTC · 573023→469 tok open ⤢
thinking (1167 chars)
User wants to log off. Run the full session-end protocol (§8.4): 1. Journal — done (session-035.md is complete). 2. File every result/derivation — D-069 filed + registered in db. Session registration in db — done? I registered session 34. Session 35 needs registration. 3. Update NGUYEN.md checklist (§5) — the ii′-5e entry mentions the capstone done (session 034); 5f's progress should be noted (perimeter repair + P1/P2 + 5f-i + piece 6). Also the perimeter additions should be recorded in NGUYEN.md (the freeze-protocol perimeter list mentions the perimeter items — the Phase 5B header lists the perimeter: "Platt–Trudgian RHUpTo, LiVerifiedUpTo, Trudgian N(T)/S(T), M₀" — now + ZeroCountProp2's two-unit specialization + NoLowZeros). Also the session log (§8.6) needs a session-035 entry. 4. Update STATE.md — the header says "Session 035 IN PROGRESS" — fine (5f continues next session). Actually the STATE is current. 5. git commit — final closure commit. Let me also make sure the session-035 journal is fully current (it is — I updated it through piece 6), the db session registration, NGUYEN.md session log + the ii′-5f checklist entry. Let me do these now.
Logging off — running the full session-end protocol (NGUYEN checklist + session log, db registration, closure commit).
tool: Bash
input
{
  "command": "grep -n \"ii\u2032-5f R3\\|5f.*tight\\|Remaining: 5f\" D:/Python/Quantum/NGUYEN.md | head -5; grep -n \"^- Session 034\" D:/Python/Quantum/NGUYEN.md",
  "description": "Locate NGUYEN.md update points"
}
#1770 assistant 2026-08-24 13:05:13.208 UTC · 777→109 tok open ⤢
Now the session-035 log entry in §8.6 and the db registration.
tool: Read
input
{
  "file_path": "D:\\Python\\Quantum\\NGUYEN.md",
  "offset": 1297,
  "limit": 18
}
#1771 assistant 2026-08-24 13:07:51.722 UTC · 672→629 tok open ⤢
thinking (413 chars)
Session 035 fully closed. Let me give the user the final summary. The session delivered: - Perimeter repair (ZeroCountProp mult-weighted) - P1/P2 declarations + D-069 design - 5f-i complete (Rexpr_decomp + pieces 1/2/4/5) - Piece 6 complete (digamma_diff_le) Remaining: piece 3 + 5f-iii → ii′-3b/3c/6/7. Total commits tonight: 9 (75172e6, f850d9a, 0cca091, d808f52, 1eeda9b, c97c3f1, c9c1362, b5e3f53, 6748b6e).
Session 035 closed cleanly (`6748b6e`). Good night — here's the final state: ## Session 035 summary (9 commits) **The big one — perimeter integrity:** - `ZeroCountProp` strengthened to the mult-weighted form (you approved) — the second ii′-1a-class encoding defect, found at the point of consumption. The declared Trudgian N(T) source counts with multiplicity; the encoding now matches. `one_le_zeroMult` bridge + both consumers adapted; full build green, 3 standard axioms only. - Two new perimeter declarations (you approved): `ZeroCountProp2` (two-unit Trudgian count) + `NoLowZeros` (|γ| ≥ 14). **Findings documented (D-069):** - Finding 1: D-056's piece 2 uses one C₀(t) for a *two-unit* window — the honest two-unit Trudgian form makes the assembly fit the baked 10.5/48 constants with margin ~1.9. - Finding 2 (ii′-6 repair map): H(T)'s near sum needs clearance coverage beyond the pigeonhole window (honest ≈ 7·Ĉ₀² vs baked 3·Ĉ₀²) — margin survives, crossover moves. **5f-i + piece 6 COMPLETE** (LiTightR.lean, ~800 lines, zero warnings): - `Rexpr_decomp` (six-piece reference-point decomposition), piece 1 (`dirichletC2_le_one` — integral machinery), piece 2 (`near_sum_refPoint_le`), pieces 4/5 (`one_div_diff_le`), piece 6 (`digamma_diff_le` ≤ 6/t — the sharp Lemma-D remainder turned out unnecessary). ## Next session **Piece 3** (the far-sum interval machine — the biggest 5f piece) then **5f-iii** (assembly + pinch lemma + the capstone `logDeriv_riemannZeta_sub_nearZeros_le_tight`). Full piece map in STATE.md. Then ii′-3b → 3c → 6 → 7.